Jade wants to buy a $200,000 term life insurance policy. She is 34 years old. Using the premium table, what is her annual premium for a 10 year policy?

Answer:

3 months

Step-by-step explanation:

Let after m months they saved same amount of money.

Given,

Saving of Jaclyn = $ 120,

Amount earned by him/her per month = $ 40,

So, the total amount contained by him/her in m months = Saving + earning for m months

= 120 + 40m,

Similarly, saving of Pedro = $ 180,

Amount earned by him/her per month = $ 20,

So, the total amount contained by him/her in m months = 180 + 20m

Thus, we can write,

120 + 40m = 180 + 20m

40m = 180 + 20m - 120

40m - 20m = 60

20m = 60

⇒ m = [tex]\frac{60}{20}[/tex] = 3.

Hence, it will take 3 months before which Jaclyn and Pedro have saved the same amount of money.

Linear equations can be solved by applying arithmetic operations separately for variables and constants. If they both save their entire allowances, 3 months will it take before Jaclyn and Pedro have saved the same amount of money

Let us assumed that the saving of Jaclyn and Pedro will be the same after n months.

Now, from the given data.

Saving of Jaclyn = $ 120

Amount earned by Jaclyn per month = $ 40

Total amount in hand of Jaclyn after work for n months will be the addition of current saving and the amount earned by Jaclyn after n months.

Thus,

[tex]\rm{Amount \;after \;n \;months}= 120 + 40n[/tex],

Similarly, the saving of Pedro = $ 180

Amount earned by Pedro per month = $ 20

Total amount in hand of Pedro after work for n months will be the addition of current saving and the amount earned by Pedro after n months.

Thus,

[tex]\rm{Amount \;after \;n \;months}= 180 + 20n[/tex]

According to the question,

[tex]\begin{aligned}&120 + 40n = 180 + 20n\\&40n = 180 + 20n - 120\\&40n - 20n = 60\\&20n = 60\\&n=\dfrac{60}{20}\\&n=3\end{aligned}[/tex]

Hence, If they both save their entire allowances, 3 months will it take before Jaclyn and Pedro have saved the same amount of money.

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Answer:  " w = (all real numbers) " —as explained below.

_________

Step-by-step explanation:

_________

Given the following "inequality":

_________

 " -3(w – 3) ≥ 9 – 3w " ;   Solve for "w" ;

                                         and see if the answer ["value for "w"]; is:

                                           "all real numbers."

_________  

  →  " -3(w – 3) ≥ 9 – 3w " ;  

_________

Method 1):

_________

On the "right-hand side" of the "inequality";

  Factor out a "(-3)" ;

_________

  " -3(w – 3) ≥  ( -3 * ? = 9?) – (-3 * ? = 3w? ) " ;

_________

                        1)   " -3 * (what value?) = 9 "?

                          Let "x" be the 'unknown value' :

                             →  " -3x = 9 " ;

                                Divide each side of the equation by "(-3)"  ;

                                  to isolate "x"  on one of the equation;

                                 & to solve for "x" ;

                                  -3x / -3 = 9 / -3 ;

                              to get:  " x = -3 " ;  

                               _________

                        2)   " -3 * (what value?) = 3w " ?

                        Let "x" be the 'unknown value' :                      

                           →   " -3x = 3w " ? ;

                         → Divide each side or the equation by ("-3").

                             → to isolate "x" on one side of the equation;

                                →  & to solve for "x" ;

                                    -3x / 3 = 3w / -3 ;

                                    to get:  x = -1w ;

_________

So:    " -3(w – 3) ≥  -3* (? = 9?) – (-3 * ? = 3w?) " ;

_________

Rewrite as:  

         " -3(w – 3) ≥  -3* [(-3 – (-1w)] " ;

_________

Now, let us consider the Following Portion of the "right-hand side" of the inequality:;

                            " (-3 – (-1w)]  =  " (-3 + 1w) " ;  

                    → {since:  "subtracting a "negative value is the equivalent of adding that particular value's positive value"} ;

         and bring down the "(-3)" on the "right-hand side" of the inequality; and rewrite the inequality as:

_________

           " -3(w – 3) ≥ -3(-3 + 1w) "  ;

        →  Now, divide EACH SIDE of the inequality by "(-3)" :

 {Note: Each time when one multiplies or divides an inequality by a "negative value"—the inequality sign flips to the other direction.}.

          →  [ -3(w – 3)]  / -3  ≥ [-3(-3 + 1w ] / -3 ;  

                 to get:

             →  " (w – 3) ≤ (-3 + 1w) " ;

_________

Note: " (-3 + 1w) " ; ↔ " [(1w + (-3)]  =  " 1w – 3 " =  "w – 3 " ;

_________

Rewrite the inequality:

_________

             →  " (w – 3) ≤ (w – 3 ) " ;

             ↔ "  w – 3  ≤  w – 3  "  ;

        The same value is equal to each other: not less than or equal to each other:   For instance:

              →  " w – 3  ≤  w – 3 " ;

If we add "3" to each side of the equation:

              →  " w – 3 + 3  ≤  w – 3 + 3 " ;

  We get:    " w  ≤ w " .   "w = w".  "w is not "less than" itself.  So all real numbers apply!

_________

Method 2)

_________

Given the following "inequality":

_________

 " -3(w – 3) ≥ 9 – 3w " ;   Solve for "w" ;

                                         and see if the answer ["value for "w"]; is:

                                           "all real numbers."

_________

On the "left-hand side of the inequality;

we have:

_________

 " -3(w – 3) " ;

_________

Take note of the "distributive property of multiplication" :

   → " a(b + c) = ab + ac " ;

_________

As such:

_________

We can expand:

     " -3(w – 3) = (-3*w) + (-3*-3) " ;

                     =  -3w + (9) ;

_________

Now, we can rewrite the original inequality:

_________

     " -3w + 9 ≥ 9 – 3w " ;

_________

Note: " -3w + 9 = 9 + (-3w) = 9 – 3w " ;  

                                      → {since: adding a "negative value" gets the same value as subtracting that value's "positive equivalent"};

       And we can rewrite our inequality as:

_________

     " 9 – 3w  ≥ 9 – 3w " ;

_________

Note: We have the same value on each side.

 "(9 – 3w)" is not greater than itself; it is "equal to itself".

 Any and all real numbers as values for "w" will result in the same value for any particular expression's Exact Same Expression!

_________

 So:  "w = (all real numbers)" .

_________

Hope this is helpful to you!

 Best wishes!

_________

Answer:  The correct option is (C) 2√34.

Step-by-step explanation:  We are given to find the distance between the points (-2, 4) and (4, -6).

We have the distance formula as follows :

DISTANCE FORMULA :

The distance between the points (a, b) and (c, d) is given as

[tex]D=\sqrt{(c-a)^2+(d-b)^2}.[/tex]

Therefore, the distance between the points (-2, 4) and (4, -6) is given by

[tex]D\\\\=\sqrt{(4-(-2))^2+(-6-4)^2}\\\\=\sqrt{6^2+10^2}\\\\=\sqrt{36+100}\\\\=\sqrt{136}\\\\=\sqrt{4\times34}\\\\=2\sqrt{34}.[/tex]

Thus, the required distance between the given points is 2√34 units.

Option (C) is CORRECT.

[tex]\text{Use}\\\\(ab)^n=a^nb^n\\\\(a^m)^n=a^{n\cdot m}\\---------------------\\\\\left(4a^5b^6\right)^4=4^4(a^5)^4(b^6)^4=256a^{5\cdot4}b^{6\cdot4}=256a^{20}b^{24}[/tex]

Answer:

its 1300

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

Answer: g=7

Step-by-step explanation:

The balance in two separate bank accounts grows each month at different rates. the growth rates for both accounts are represented by the functions f(x) = 2x and g(x) = 4x 12. in what month is the f(x) balance greater than the g(x) balance?

Answer:

6 months

If growth rates for both accounts are represented by the functions f(x) = 2x and g(x) = 4x 12 thn in  6 months the f(x) balance is greater than the g(x) balance.

excessive-yield financial savings accounts stand out from conventional financial savings bills in that they praise you with a better interest rate, permitting your cash to grow even quicker as it sits on your account. The interest charge that these debts provide is noted as APY or annual percentage yield.

fees and minimal balance: CDs tend to pay the very best hobby prices of the 3 varieties of savings bills. They commonly require around $1,000 to open, but there are CDs without a minimum beginning balance requirement. CDs typically don't rate a month-to-month rate.

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The total present money in his account after all the $400 withdrawals is $1875.01.

Arithmetic operators are four basic mathematical operations in which summation, subtraction, division, and multiplication involve.,

Summation = addition of two or more numbers or variable

For example = 2 + 8 + 9

Subtraction = Minus of any two or more numbers with each other called subtraction.

For example = 4 - 8

Division = divide any two numbers or variable called division.

For example 4/8

Multiplication = to multiply any two or more numbers or variables called multiplication.

For example 5 × 7.

Total present money initially = $1200

Deposits check = 387.89 + 437.12 + 250 = $1075.01

Total money after deposit = 1200 + 1075.01 = $2275.01

Money remains after withdrawals of $400

⇒ $2275.01 - $400  = $1875.01.

Hence "The total present money in his account after all the $400 withdrawals is $1875.01".

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The sum of two complex numbers resulting in a real or imaginary number depends on the cancellation of their real or imaginary components upon addition.

When the sum of two complex numbers is a real number: For the sum of two complex numbers to be a real number, their imaginary parts must cancel each other out. This happens when the imaginary parts have equal magnitude but opposite signs, resulting in the cancellation upon addition.

When the sum of two complex numbers is an imaginary number: The sum of two complex numbers is an imaginary number when the real parts cancel each other out. This occurs when the real parts have equal magnitude but opposite signs, leading to the elimination of the real components.

BN =6n

n = chandeliers

 you have 15 chandeliers so n = 15

so BN = 6(15)

BN = 90

you will need 90 light bulbs

To find Joe's total sales when one-eleventh are cash sales amounting to $380, multiply the cash sales by 11, which results in a total of $4180.

To find Joe's total sales, one would apply the concept of proportions in mathematics. Here is a step-by-step breakdown of the problem:

Identify the fraction of total sales that are cash, which is one-eleventh.

Understand that $380 equals this fraction of the total sales.

To find the total sales, divide the cash sales by the fraction that represents cash sales 1/11

Calculate the total sales by using the following equation: Total Sales = Cash Sales / (1/11) = $380 / (1/11).

Perform the division: Total Sales = $380 * 11 = $4180.

Hence, Joe's total sales for the week were $4180.

Answer:

Option B. 25 ft

Step-by-step explanation:

we know that

The circumference of a circle is equal to

[tex]C=2\pi r[/tex]

we have

[tex]C=157\ ft[/tex]

assume

[tex]\pi =3.14[/tex]

substitute in the formula

[tex]157=2(3.14)r[/tex]

Solve for r

Divide by 2(3.14) both sides

[tex]r=157\(2(3.14))[/tex]

[tex]r=25\ ft[/tex]