The first step is to determine each compound's total molar mass by adding up all of its constituent parts.
What are compounds?Compounds are defined as anything made up of similar molecules with atoms from two or more different chemical elements. Chemical connections that are challenging to break are created when the elements interact with one another.
Chlorobenzene, the chemical on the left, has a mass of 112 and is composed of 5 carbons (12 g/mol), 1 chlorine (35 g/mol), and 5 hydrogens (1 g/mol). The right-hand chemical (2-chloropentane), which consists of 3 carbons, 1 chlorine, and 7 hydrogens, has a mass of 78. The mass loss for chlorobenzene is 112 - 77 = 35. The mass loss for 2-chloropropane is 78 - 77 = 1. The loss of a hydrogen ion results in a loss of one unit. This is typical and is referred to as the "M-1 peak." Therefore, the dehydrogenated molecular ion is represented by the 77 m/z fragment.
Thus, the first step is to determine each compound's total molar mass by adding up all of its constituent parts. '
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Using the table of average bond energies below, the delta h for the reaction is
To calculate ΔH for a reaction, bond energies and Hess's law are used. The sum of bond energies is equivalent to the standard enthalpy change. Energy required for bond breakage and energy released in bond formation are central to these computations.
Explanation:The calculation of delta H (ΔH) for a reaction requires the consideration of bond energies. In this case, the bond energy of a pure covalent H-H bond, for instance, is 436 kJ/mol. For reactions involving more molecules, the sum of all bond energies in the molecule equals the standard enthalpy change.
Let's consider a reaction where H-H bonds and Cl-Cl bonds form H-Cl. The energy required to break these bonds is the sum of the bond energy of the H-H bond (436 kJ/mol) and the Cl-Cl bond (243 kJ/mol). During the reaction, two moles of H-Cl bonds are formed, releasing energy. The enthalpy change can be calculated using the Hess's law.
The average C-H bond energy is another example, computed as 1660/4 = 415 kJ/mol, considering there are four moles of C-H bonds broken per mole of the reaction. Overall, determining ΔH involves understanding bond energies and applying principles such as Hess's law.
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Precipitation tends to be _______ on the _______ side of a mountain because water vapor _______ as it rises there.
a. lower; windward; expands
Precipitation is higher on the windward side of a mountain due to orographic precipitation, where rising air cools and water vapor condenses, leading to rain or snow. This creates a rain shadow effect and drier conditions on the leeward side.
Precipitation tends to be higher on the windward side of a mountain because water vapor condenses as it rises there. This phenomenon is known as orographic precipitation. As the moist air from the ocean encounters a mountain range, it rises and cools, leading to the condensation of water vapor which then precipitates as rain or snow on the windward side. This results in a rain shadow on the leeward side, where the air, now dry, descends and warms up, creating drier conditions.
Which units express heat capacity? J/°C, J/K, cal/°C, cal/K J/(gi°C), J/(giK), cal/(gi°C), cal/(giK) J, cal °C, K
The units that express heat capacity are J/ °C; J/K; and cal/ °C
Why?Heat capacity is the amount of heat required to increase the temperature of a determined amount of substance.
As the heat capacity increases, more heat will need to be given to the substance to increase its temperature.
Heat capacity is expressed mathematically as:
[tex]\lim_{\Delta T \to 0} \frac{Heat}{\Delta Temperature}[/tex]
So that means that Heat capacity will have units of Heat (in J or cal) over temperature (in °C or K).
Have a nice day!
its a or J/°C, J/K, cal/°C, cal/K
Explanation:
A mixture of propane and butane is fed into a furnace where it is mixed with air. the furnace exhaust leaves the furnace at 305°c, 763.0 mmhg and contains only n2, o2, co2, and h2o. the partial pressure of o2 in the exhaust is 100.7 mmhg and the partial pressure of co2 in the exhaust is 33.57 mmhg.
How reactive is an atom of Sodium(Na) and why?
Question 1 options:
Sodium (Na) is very reactive because it does not have a full valence shell.
Sodium (Na) is very reactive because it does not have enough protons in the nucleus.
Sodium (Na) is not very reactive because it does not have a full valence shell.
Sodium (Na) is not very reactive because it can only bond with Chlorine (Cl) to become salt.
PLz plz plz plz help
When cool, dense air from over the water flows inland, it's called a ____. a. land breeze c. jet stream b. polar easterly d. sea breeze
Answer: Option (d) is the correct answer.
Explanation:
When cool, dense air from over the water flows inland, it's called a sea breeze.
Any wind that travels from large body of water towards the inland is known as sea breeze. Land absorbs heat from the sun more readily as compared to water in the sea.
Therefore, the wind above the land is warm whereas the wind above the sea is cooler and dense.
The substance gray tin is found to crystallize in a cubic lattice, with an edge length of 646.0 pm. if the density of solid gray tin is 5.850 g/cm3, how many sn atoms are there per unit cell?
First find the volume of the cubic lattice given edge length of 646 pm or 6.46x10^-8 cm.
volume = (6.46x10^-8 cm)^3
volume = 2.7x10^-22 cm^3
The total mass of the lattice is:
mass = (5.850 g/cm^3) * 2.7x10^-22 cm^3
mass = 1.577x10^-21 grams
The molar mass of tin is 118.71 g/mol and the Avogadros number is 6.022 x 10^23 atoms/mol, hence:
Sn atoms = [1.577x10^-21 g / (118.71 g/mol)] * 6.022 x 10^23 atoms/mol
Sn atoms = 8 atoms
The number of Sn atoms in the unit cell of grey tin depends on the type of cubic cell structure (simple, body-centered, or face-centered). The question does not provide sufficient information to determine this. With full information, one can use the density and molar mass of Sn to calculate the number of atoms per unit cell.
Explanation:To determine the number of Sn atoms per unit cell, we must first determine the type of cubic cell structure. Metals typically crystallize in one of three types of cubic unit cells: simple cubic (sc), face-centered cubic (fcc), or body-centered cubic (bcc). Unfortunately, information is not provided regarding the specific type of gray tin, so we can't definitively answer your question.
However, here's a brief explanation of how you would calculate this if the necessary details were given:
For a simple cubic lattice, there is one atom per unit cell. For a body-centered cubic lattice, there are two atoms per unit cell. For a face-centered cubic lattice, there are four atoms per unit cell.
The density, given that it's in g/cm³, can be converted to atoms per cm³ using the molar mass of Sn (118.7 g/mol), from which we can calculate atoms per unit cell, providing the structure type of the unit cell is known.
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Why is the demand for environmental scientists and specialists expected to increase?
Environmental scientists and specialists are expected to be in demand as public awareness of environmental threats grows. These professionals will still be required to analyze environmental issues and create solutions that protect community health.
What is the demand for environmental scientists?Due to the increased effects of climate change we have witnessed over the past ten years, employment opportunities in environmental science are more in demand than ever. Environmental scientists study problems like pollution and deforestation that concern us all.
Environmental scientists are expected to be in greater demand due to the growing need for environmental protection and responsible land and water resource management.
In their research, environmental scientists frequently employ scientific techniques and data analysis. Their conclusions are based on a careful examination of scientific evidence. In their analyses, they must take into account all potential strategies, interactions, and solutions.
Thus, Environmental scientists and specialists are expected to be in demand as public awareness of environmental threats grows.
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Classify these alcohols as primary (1°), secondary (2°), or tertiary (3°). g
The alcohols are classified as primary, secondary, or tertiary based on the number of carbon atoms directly bonded to the hydroxyl-bearing carbon. Examples include CH3-CH3CHOH (1°), OH-CH3CCH3-CH3 (2°), and OH-CH2CHCH3-CH3 (3°), indicating their respective structural arrangements.
The classification of alcohols as primary (1°), secondary (2°), or tertiary (3°) is based on the number of carbon atoms directly bonded to the carbon atom bearing the hydroxyl group. Here's the classification for the given alcohols:
a. CH3-CH3CHOH
- This alcohol has one carbon directly bonded to the carbon with the hydroxyl group. Therefore, it is a primary alcohol (1°).
b. OH-CH3CCH3-CH3
- This alcohol has two carbons directly bonded to the carbon with the hydroxyl group. Therefore, it is a secondary alcohol (2°).
c. OH-CH2CHCH3-CH3
- This alcohol has three carbons directly bonded to the carbon with the hydroxyl group. Therefore, it is a tertiary alcohol (3°).
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The probable question may be:
Classify these alcohols as primary (1°), secondary (2°), or tertiary (3°).
a. CH3-CH3CHOH b. OH-CH3CCH3-CH3 c. OH-CH2CHCH3-CH3
Which particles that make up an atom are involved in nuclear reactions?
protons only
protons and neutrons
electrons only
electrons and neutrons
According to research, protons and neutrons are the particles that make up an atom involved in nuclear reactions.
What are nuclear reactions?It is a procedure that leads to combine and modify the nuclei of atoms and subatomic particles.
Protons and neutrons are concentrated in the atomic nucleus, in response to the absorption of these particles, many types of nuclear reactions take place.
Therefore, we can conclude that according to research, protons and neutrons are the particles that make up an atom involved in nuclear reactions.
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Peter is 5 ft, 11 inches tall. Paul is 176 cm tall. Who is taller?
Final answer:
To compare the heights of Peter and Paul, we convert their heights to the same unit. Peter is taller with a height of 71 inches compared to Paul's height of approximately 69.29 inches.
Explanation:
In order to compare the heights of Peter and Paul, we need to convert their heights to the same unit. Peter's height is given in feet and inches, so we need to convert it to inches. Since there are 12 inches in a foot, Peter's height is 5 ft * 12 inches/ft + 11 inches = 60 inches + 11 inches = 71 inches.
Now we can compare Peter's height of 71 inches with Paul's height of 176 cm. In order to convert centimeters to inches, we need to know that 1 inch is approximately equal to 2.54 centimeters. So, Paul's height is 176 cm * 1 inch/2.54 cm = 69.29 inches (approximately).
Comparing the heights, we can see that Peter is taller with a height of 71 inches compared to Paul's height of approximately 69.29 inches.
When metals bond with nonmetals, electrons are transferred from the metal to the nonmetal, resulting in the formation of an ionic compound?
Metals lose electrons to become cations, and nonmetals gain those electrons to become anions, with the electrostatic attraction between these oppositely charged ions forming an ionic compound.
When metals bond with nonmetals, electrons are indeed transferred from the metal to the nonmetal, resulting in the formation of an ionic compound. This process involves a metal atom losing electrons to become a cation, which is a positively charged ion, while a nonmetal atom gains those electrons to become an anion, which is a negatively charged ion. The electrostatic attraction between the opposite charges of these ions holds the compound together.
For example, in the formation of sodium fluoride (NaF), sodium (Na) loses one electron to form a Na+ cation while fluorine (F) gains one electron to form an F- anion. The resulting compound, NaF, is stabilized by the strong attractions between the positively charged sodium ions and the negatively charged fluoride ions.
Which element in Period 3 is the most active nonmetal?
In Period 3 of the Periodic Table, the most active nonmetal is Chlorine, due to its high electronegativity and electron affinity which results from its electron configuration.
Explanation:The most active nonmetal in Period 3 (third period) of the Periodic Table is Chlorine (Cl). Period 3 includes the elements Sodium (Na) to Argon (Ar). Among these, the nonmetals are Silicon (Si), Phosphorus (P), Sulfur (S), and Chlorine (Cl). Among these nonmetals, Chlorine is the most active because it has the highest electronegativity and affinity for electrons. Its high reactivity is due to its electron configuration, with it needing just one more electron to achieve a stable, full outer shell.
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Write the balanced chemical equation for the neutralization reaction that occurs when an aqueous solution of nitric acid (HNO3) is mixed with an aqueous solution of sodium hydroxide (NaOH). Indicate the physical states of the reactants and products using the abbreviations (s), (l), (g), or (aq) for solids, liquids, gases, or aqueous solutions, respectively.
Answer: [tex]HNO_3(aq)+NaOH(aq)\rightarrow NaNO_3(aq)+H_2O(l)[/tex]
Explanation:
Neutralization is a chemical reaction in which an acid and a base reacts to form salt and water.
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas. Liquids are represented by (l) and gases are represented by (g).
The balanced chemical equation for the neutralization reaction:
[tex]HNO_3(aq)+NaOH(aq)\rightarrow NaNO_3(aq)+H_2O(l)[/tex]
Among the intermolecular forces, which forces are typically the weakest?
dipole-dipole interactions
hydrogen bonds
dipole-induced dipole interactions
London dispersion forces
The strength of intermolecular forces from the strongest to the weakest is:-
Hydrogen Bonds > Dipole-Dipole interactions > Dipole-induced dipole > London dispersion forces
Hence, London dispersion forces are the weakest. This arises due to the unsymmetrical distribution of electrons around the nucleus which tends to create an instantaneous temporary dipole. When a second molecule come in contact, the dipole from the first distorts the charge distribution in the later which leads to weak electrostatic attraction between the two atoms/molecules.
A certain alcohol contains only three elements, carbon, hydrogen, and oxygen. Combustion of a 30.00 gram sample of the alcohol produced 57.30 grams of CO2 and 35.22 grams of H2O. What is the empirical formula of the alcohol?
first we calculate the mass percent composition
of three elements carbon hydrogen and oxygen.
Mass of CO₂ = 44.0096 g/mol
Mass of H₂O = 8.0153 g/mol
percent composition of carbon = (57.30 g CO2) / (44.0096 g CO2/mol) x
(1/1) x (12.0108 g C/mol) / (30.00 g) = 0.521264 = 52.1264% C
Percent composition of hydrogen = (35.22 g H2O) / (18.0153 g H2O/mol) x (2/1) x
(1.0079 g H/mol) / (30.00 g) = 0.131363 = 13.1363% H
percent composition of oxygen = 100% - 52.1264% C 13.1363% H = 34.7373% O
Now calculate the number of moles in the compound;
(52.1264 g C) / (12.0108 g C/mol) = 4.33996 mol C
(13.1363 g H) / (1.0079 g H/mol) = 13.0333 mol H
(34.7373 g O) / (15.9994 g O/mol) = 2.17116 mol O
Now divide by the smallest number of moles:
(4.33996 mol C) / (2.17116 mol) = 1.999 = 2
(13.0333 mol H) / (2.17116 mol) = 6.003 = 6
(2.17116 mol O)/ (2.17116 mol) = 1.000 = 1
So, the empirical formula is :
C₂H₆O
The empirical formula of the alcohol cannot be determined with the given information.
Explanation:The empirical formula of the alcohol can be determined by analyzing the masses of carbon dioxide (CO₂) and water (H₂O) produced during combustion. From the given information, 57.30 grams of CO₂ and 35.22 grams of H₂O were produced. To find the empirical formula, we need to calculate the moles of carbon, hydrogen, and oxygen in the sample.
First, calculate the moles of CO₂ and H₂O produced:
CO₂: 57.30 g * (1 mol CO₂ / 44.01 g) = 1.30 mol CO₂H₂O: 35.22 g * (1 mol H₂O / 18.02 g) = 1.95 mol H₂ONext, calculate the moles of carbon and hydrogen:
Carbon: 1.30 mol CO₂ * (1 mol C / 1 mol CO₂) = 1.30 mol CHydrogen: 1.95 mol H₂O * (2 mol H / 1 mol H₂O) = 3.90 mol HFinally, divide the moles of each element by the smallest number of moles to get the mole ratio:
Carbon: 1.30 mol C / 1.30 mol C = 1Hydrogen: 3.90 mol H / 1.30 mol C = 3Oxygen: Since we don't have the mass of oxygen, we can assume it's the leftover mass from the sample. Oxygen = Total mass - (mass of carbon + mass of hydrogen) = 30.00 g - (57.30 g + 35.22 g) = -62.52 g (which is not physically possible)Based on these calculations, it is not possible to determine the empirical formula of the alcohol using the given information. Further information is needed to calculate the empirical formula.
A student titrates 25.0 ml of vinegar with 0.317 m naoh. the initial naoh burret reading is 0.15 ml and the final reading is 19.35 ml. what is the molarity of hoac in the vinegar sample?
Final answer:
The molarity of acetic acid in the vinegar sample is determined by calculating the moles of NaOH used in the titration, which are equivalent to the moles of acetic acid, and then dividing by the volume of the vinegar sample.
Explanation:
The student's question pertains to the calculation of the molarity of acetic acid (HOAc) in a vinegar sample based on a titration experiment with sodium hydroxide (NaOH). To determine the molarity, we use the volume of NaOH added and the molarity of NaOH to calculate the moles of NaOH, which equals the moles of acetic acid due to the 1:1 stoichiometry in the reaction. The equation is:
VNaOH (L) × MNaOH = moles of NaOH = moles of HOAcMolarity of HOAc = moles of HOAc / Volume of vinegar sample (L)Given that the volume of NaOH used is (19.35 mL - 0.15 mL) and the molarity of NaOH is 0.317 M, the calculation is as follows:
Moles of NaOH = (19.35 mL - 0.15 mL) × 0.317 M × (1 L / 1000 mL)
Moles of HOAc = Moles of NaOH
Molarity of HOAc = Moles of HOAc / 0.025 L
NaOH = 19.35 - 0.15 = 19.2 mL 19.2 mL x 0.317 M = 6.086 millimoles NaOH 6.086 mmol NaOH neutralized 6.086 mmol acetic acid 6.086 mmol acetic acid / 25.0 mL = 0.2435 mmol/mL = 0.2435 mol/L Acetic acid was 0.2435 M
Shoe companies imbed unique designs on the bottoms of the sneakers they manufacture. What is the main purpose of the designs on the bottoms of sneakers?
A. to increase potential energy
B. to decrease friction
C. to increase friction
D. to decrease potential energy
Calculate the number of grams of silane gas, SiH4, formed when 34.9 g of Mg2Si reacts with excess H2O.
To calculate the grams of silane gas, SiH4, formed when 34.9 g of Mg2Si reacts with excess H2O, you need to use the balanced chemical equation and molar ratios. Determine the moles of Mg2Si, then use the molar ratio to find the moles of SiH4. Finally, convert the moles of SiH4 to grams using its molar mass.
Explanation:To calculate the number of grams of silane gas (SiH4) formed when 34.9 g of Mg2Si reacts with excess H2O, we need to consider the molar ratios between Mg2Si and SiH4 in the balanced chemical equation:
2Mg2Si + 4H2O → 4Mg(OH)2 + SiH4
From the balanced equation, we can see that 2 moles of Mg2Si react to produce 1 mole of SiH4. First, calculate the number of moles of Mg2Si:
Moles of Mg2Si = 34.9 g / (2 * molar mass of Mg2Si)
Then, use the molar ratio to calculate the moles of SiH4 produced:
Moles of SiH4 = Moles of Mg2Si * (1 mole of SiH4 / 2 moles of Mg2Si)
Finally, convert the moles of SiH4 to grams using its molar mass:
Grams of SiH4 = Moles of SiH4 * molar mass of SiH4
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G vinegar is a solution of acetic acid in water. if a 165 ml bottle of distilled vinegar contains 28.2 ml of acetic acid, what is the volume percent (v/v) of the solution?
When marco is sick, he tests the ph of his saliva and finds that it is 6.1. what is the hydrogen ion concentration of his saliva? (round your answer to seven decimal places.)?
The pH of Marco's saliva indicates its acidity, and with a pH of 6.1, the hydrogen ion concentration, [H3O+], is approximately 0.0000008 M.
Explanation:The subject of your question is related to the concentration of hydrogen ions in a solution, which comes under the field of chemistry. The pH of a solution is a way to measure the acidity or alkalinity of a liquid and is calculated by the formula pH = -log[H3O+]. If Marco's saliva has a pH of 6.1, we can use this formula to calculate the concentration of hydrogen ions, or [H3O+], in his saliva.
To find [H3O+], simply reverse the formula: [H3O+] = 10^-pH. So for Marco's saliva with a pH of 6.1, [H3O+] = 10^-6.1. This gives a hydrogen ion concentration of approximately 0.0000001 M or to seven decimal places, 0.0000008 M.
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The hydrogen ion concentration of Marco's saliva, determined from its pH of 6.1 using the formula [H+] = 10^(-pH), is approximately 7.943 × 10^(-7) Molar. This implies a relatively low concentration of hydrogen ions, indicative of a slightly acidic environment.
The pH of a solution is a measure of its acidity or alkalinity and is defined as the negative logarithm (base 10) of the hydrogen ion concentration. The formula for pH is given by pH = -log[H+], where [H+] is the hydrogen ion concentration.
In the case of Marco's saliva with a pH of 6.1, we can use the formula to find the hydrogen ion concentration.
pH = -log[H+]
6.1 = -log[H+]
To find [H+], we can rewrite the equation as:
[H+] = 10^(-pH)
Substituting the pH value:
[H+] = 10^(-6.1)
Calculating this gives the hydrogen ion concentration:
[H+] = 7.943 × 10^(-7)
Rounded to seven decimal places, the hydrogen ion concentration of Marco's saliva is approximately 0.0000008. Therefore, the hydrogen ion concentration is 7.943 × 10^(-7).
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The scientific method helps scientists avoid injecting which of the following into their experiments? a. information b. conclusions c. hypotheses d. bias
The total pressure of gases a, b, and c in a closed container is 4.1 atm. if the mixture is 36% a, 42% b, and 22% c by volume, what is the partial pressure of gas c?
The partial pressure of gas C is 0.902 atm
calculation
partial pressure of gas c =[( percent by volume of gas C / total percent) x total pressure]
percent by volume of gas C= 22%
Total percent = 36% +42% + 22% = 100 %
Total pressure = 4.1 atm
partial pressure of gas C is therefore = 22/100 x 4.1 atm = 0.902 atm
"If I have seen further it is by standing on the shoulders of giants." This is an old quote, one that Isaac Newton used to describe his own scientific efforts. It was his way of saying that the advances he contributed to science were only possible because A) he had exceptional vision. B) of divine guidance from heaven above. C) of the scientists and ideas that came before him. D) of the extremely large individuals who lifted him up.
The correct answer is C) of the scientists and ideas that came before him.
Explanation:
Isaac Newton was a prominent physicist mainly known for his theories and ideas regarding gravity, motion, mechanics, among others that are still used today due to their relevance and accuracy. Despite this, Newton recognized in a letter "If I have seen further it is by standing on the shoulders of giants" which suggests Newton felt his theories and ideas were only possible due to previous theories and scientists that build the basis Newton used. Indeed, Newton's predecessors such as Kepler or Galilei were necessary for Newton and also he had the support of contemporary scientists. Thus, in this quote, Newton said that his advances were only possible because of the scientists and ideas that came before him.
the use of high-pressure chambers to control disease processes is known as
what is the importance of the collagen in the human body?
It strengthens tendons and supports the skin and internal organs.
Collagen makes up about 25 percent of protein in the body. Bones and teeth are made by adding minerals to it.
The rate of change of atmospheric pressure p with respect to altitude h is proportional to p, provided that the temperature is constant. at a specific temperature the pressure is 102.2 kpa at sea level and 87.9 kpa at h = 1,000 m. (round your answers to one decimal place.) (a) what is the pressure at an altitude of 2500 m?
Final answer:
To find the pressure at an altitude of 2500 m, set up a proportion using the given pressures at sea level and 1000 m altitude.
Explanation:
The question asks for the pressure at an altitude of 2500 m. We are given that the pressure at sea level is 102.2 kPa and 87.9 kPa at h = 1000 m. Since the rate of change of pressure with respect to altitude is proportional to the pressure itself, we can set up a proportion. Let p be the pressure at 2500 m:
(102.2 kPa - 87.9 kPa) / (0 m - 1000 m) = (p - 87.9 kPa) / (2500 m - 1000 m)
Find the value of p, which gives the pressure at an altitude of 2500 m.
How many milliliters of 0.260 m na2s are needed to react with 35.00 ml of 0.315 m agno3?
The complete balanced chemical reaction is:
2 AgNO3 + Na2S --> 2 NaNO3 + Ag2S
First let us calculate the number of moles of AgNO3.
moles AgNO3 = 0.315 M * 0.035 L
moles AgNO3 = 0.011025 mol
From the reaction, 1 mole of Na2S is needed for every 2 moles of AgNO3 hence:
moles Na2S required = 0.011025 mol AgNO3 * (1 mol Na2S / 2 mol AgNO3)
moles Na2S required = 5.5125 x 10^-3 mol
Therefore volume required is:
volume Na2S = 5.5125 x 10^-3 mol / 0.260 M
volume Na2S = 0.0212 L = 21.2 mL
21.20 mL of 0.260 M [tex]\(\text{Na}_2\text{S}\)[/tex] is needed to react with 35.00 mL of 0.315 M [tex]\(\text{AgNO}_3\).[/tex]
To determine the volume of 0.260 M [tex]\(\text{Na}_2\text{S}\)[/tex] needed to react with 35.00 mL of 0.315 M [tex]\(\text{AgNO}_3\)[/tex], we need to use the stoichiometry of the reaction between [tex]\(\text{Na}_2\text{S}\) and \(\text{AgNO}_3\).[/tex]
The balanced chemical equation for the reaction is:
[tex]\[ \text{Na}_2\text{S} + 2\text{AgNO}_3 \rightarrow \text{Ag}_2\text{S} + 2\text{NaNO}_3 \][/tex]
From the balanced equation, we see that 1 mole of [tex]\(\text{Na}_2\text{S}\)[/tex] reacts with 2 moles of [tex]\(\text{AgNO}_3\).[/tex]
Step 1: Calculate moles of [tex]\(\text{AgNO}_3\)[/tex]
First, we calculate the moles of [tex]\(\text{AgNO}_3\)[/tex] in the 35.00 mL solution.
[tex]\[ \text{Moles of AgNO}_3 = \text{Molarity} \times \text{Volume (in L)} \][/tex]
[tex]\[ \text{Moles of AgNO}_3 = 0.315 \, \text{M} \times 0.03500 \, \text{L} \][/tex]
[tex]\[ \text{Moles of AgNO}_3 = 0.011025 \, \text{moles} \][/tex]
Step 2: Determine moles of [tex]\(\text{Na}_2\text{S}\)[/tex] needed
From the balanced equation, 1 mole of [tex]\(\text{Na}_2\text{S}\)[/tex] reacts with 2 moles of [tex]\(\text{AgNO}_3\).[/tex]
[tex]\[ \text{Moles of Na}_2\text{S} = \frac{\text{Moles of AgNO}_3}{2} \][/tex]
[tex]\[ \text{Moles of Na}_2\text{S} = \frac{0.011025 \, \text{moles}}{2} \][/tex]
[tex]\[ \text{Moles of Na}_2\text{S} = 0.0055125 \, \text{moles} \][/tex]
Step 3: Calculate the volume of 0.260 M [tex]\(\text{Na}_2\text{S}\)[/tex] solution needed
Now, we need to find the volume of 0.260 M [tex]\(\text{Na}_2\text{S}\)[/tex] that contains 0.0055125 moles of [tex]\(\text{Na}_2\text{S}\).[/tex]
[tex]\[ \text{Volume (in L)} = \frac{\text{Moles of Na}_2\text{S}}{\text{Molarity}} \][/tex]
[tex]\[ \text{Volume (in L)} = \frac{0.0055125 \, \text{moles}}{0.260 \, \text{M}} \][/tex]
[tex]\[ \text{Volume (in L)} = 0.0212019 \, \text{L} \][/tex]
Convert the volume from liters to milliliters:
[tex]\[ \text{Volume (in mL)} = 0.0212019 \, \text{L} \times 1000 \, \text{mL/L} \][/tex]
[tex]\[ \text{Volume (in mL)} = 21.20 \, \text{mL} \][/tex]
Therefore, 21.20 mL of 0.260 M [tex]\(\text{Na}_2\text{S}\)[/tex] is needed to react with 35.00 mL of 0.315 M [tex]\(\text{AgNO}_3\).[/tex]
Calculate the ph of a 0.10 m solution of hypochlorous acid, hocl. ka of hocl is 3.5Ã10â8 at 25 âc. express your answer numerically using two decimal places.
The oxidation of magnesium to form magnesium oxide is shown by which balanced chemical equation?
Answer : The balanced chemical reaction will be,
[tex]2Mg(s)+O_2(g)\rightarrow 2MgO[/tex]
Explanation :
Balanced chemical reaction : It is the reaction in which the number of atoms of an individual elements present on reactant side must be equal to the product side.
As per question, when 2 moles of magnesium react with 1 mole of oxygen the it reacts to give 2 moles of magnesium oxide as a product.
The balanced chemical reaction will be,
[tex]2Mg(s)+O_2(g)\rightarrow 2MgO[/tex]