It is desired that 7.7 mc of charge be stored on each plate of a 5.3 mf capacitor. what potential difference is required between the plates?

Answer:

12.25 m/s

Explanation:

If a car slows down at -5 m/s2 and it comes to a stop after traveling 15 m we just have to use the next formula:

[tex]Vf^{2} =Vo^{2} +2ad[/tex]

Now we know that the final velocity is 0, so by inserting our data into the formula it would look like this:

[tex]Vf^{2} =Vo^{2} +2ad[/tex]

[tex]0 =Vo^{2} +2(-5m/s^{2})(15m)[/tex]

[tex]-Vo^{2}= -150m^{2}/s^{2}[/tex]

[tex]Vo^{2}= 150m^{2}/s^{2}[/tex]

[tex]Vo= \sqrt{150m^{2}/s^{2}}[/tex]

[tex]Vo= 12.25m/s[/tex]

Final answer:

The range of angles over which the visible m = 1 spectrum extends can be calculated using the equation θ = sin^(-1)(mλ/d), where θ is the angle, m is the order of the spectrum, λ is the wavelength of light, and d is the grating spacing. For a diffraction grating with 790 lines/mm spacing, the range of angles for the visible m = 1 spectrum is approximately 18.42° to 33.57°.

Explanation:

We are given the property of the illuminating light:

790 lines/mm

Which is also equivalent to:

790,000 lines/m

Taking the reciprocal of this value will give us the distance per line:

d = 1 m / 790,000 lines

d = 1.2658 * 10^-6 m

Now we can solve for the range of angles using the formula

λ = d * sin θ

sin θ  = λ / d

where λ is the wavelength of light and θ is the angle

Now we know that visible light ranges from 400 to 700 nm, therefore we use these values to find the range.

when λ = 400 nm = 400 * 10^-9 m

sin θ = 400 * 10^-9 m / 1.2658 * 10^-6 m

θ = 18.42°

when λ = 700 nm = 700 * 10^-9 m

sin θ = 700 * 10^-9 m / 1.2658 * 10^-6 m

θ = 33.57°

Therefore the range of angles is 18.42° to 33.57°.

Answer:

B.

Explanation:

I don't believe scientists would use a biased source to obtain credible and accurate evidence for their research, and we all should know that C. is wrong.  With A. being wrong, the best choice to me would be none other than B.

Final answer:

Light pollution is the excessive or misdirected artificial light that brightens the night sky, making it difficult to see celestial objects. It is a concern for astronomers, environmentalists, and those worried about global warming.

Explanation:

Light pollution refers to the excessive or misdirected artificial light that brightens the night sky, making it difficult to see celestial objects such as planets and stars. This phenomenon is of concern not just to astronomers, but also to environmentalists and those who are worried about global warming. It can disrupt the natural life cycle of animals and lead to unnecessary expenses and energy consumption. Light pollution can be measured and compared using citizen science projects like Globe at Night, and organizations like the International Dark-Sky Association work to address this issue.

Answer:

Stop

Explanation:

when we drive fast it will be take longer time to stop.

As  car  is moving fast  the acceleration will be to decelerate we have to apply  brake.

By applying brake the car decelerates very fast as deceleration is the change in velocity per unit time. change in velocity is very high so deceleration will be high.

when the brake is applied the distance travel by the high speed vehicle will be more than the vehicle moving at slow speed.

Answer:D

Explanation:

Answer: In a typical rear-end collision, the victim's head is accelerated faster and harder than torso.

Explanation:

When a vehicle crashes into the one in front of it then this type of collision is called rear-end collision.

The lighter part of the victim would have more acceleration than the lower heavy part of the victim. Here, the lighter part of the victim is head and the heaver part of the victim is torso.

Therefore,  in a typical rear-end collision, the victim's head is accelerated faster and harder than torso.

When backing a vehicle for maximum visibility, a driver should check all mirrors, look over their shoulder, and utilize a rear-view camera if available to maintain full awareness of their surroundings.

For maximum visibility when backing a vehicle, a driver is required to regularly check all mirrors, turn their head to look over their shoulder, and use the vehicle's rear-view camera if one is available. Maintaining a full awareness of their surroundings is essential. For example, looking over the right shoulder will help spot any pedestrians, obstacles, or approaching vehicles from that direction. Similarly, the mirrors and rear-view camera enable a driver to monitor the areas behind and to the sides of the vehicle, ensuring a safe and smooth backing maneuver.

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For maximum visibility while backing a vehicle, the driver should use all mirrors, check blind spots, ensure rear visibility is unobstructed, and back slowly. It is also crucial that the vehicle is well-maintained with functioning lights and signals.

For maximum visibility when backing a vehicle, a driver needs to be highly alert and use all available visual aids. This includes checking all mirrors, turning to look over each shoulder for blind spots, and using the rear-view camera if the vehicle is equipped with one. It's important to have a clear view of the path behind the vehicle, which means ensuring that the rear windshield is free of obstructions like stickers, dirt, and snow. Furthermore, it's essential for the driver to move slowly and smoothly, allowing more time to react if an obstacle appears. A step-by-step approach includes:

It's also crucial that the vehicle is in good condition, as noted in 'KNOW YOUR HIGHWAYS and BE SURE TO HAVE YOUR CAR IN GOOD CONDITION', including functioning lights and reverse signals to alert nearby pedestrians and motorists. Being aware of the surrounding environment, such as obeying unknown speed limits as inferred from the scenario with the test car, increases safety while maneuvering.

The force of gravity on planet x is equal to 8.4 m/s². Therefore, option (B) is correct.

The weight of a body can be defined as the force acting on the body due to the gravity of the earth or any planet. Weight can be described as a vector parameter if the gravitational force is exerted on the object.

The measurement unit for weight is similar to that of force, which (SI) is the newton (N). A body with a mass of 1 Kg has a weight of 9.8 N on Earth's surface, and about 1/6th as much on the Moon.

The mathematical expression to determine the weight of an object is written as follows:

W = mg

Given the mass of the given object, m = 15 Kg

The weight of the object, W = 126N

The  force of gravity on planet x will be equal to:

126 N = 15 Kg × g

g = 126/15

g = 8.4 m/s²

Therefore, the force of gravity on planet x is equal to 8.4 m/s².

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Answer:

C. Gravity = air resistance

Explanation:

An object falling down has two forces acting on him:

- Gravity, which acts downward --> the magnitude of this force is constant (equal to [tex]mg[/tex], where m is the mass of the object and g is the gravitational acceleration)

- Air resistance, which acts upward --> the magnitude of this force is directly proportional to v, the speed of the object

When the object starts its fall, the speed is zero (v=0) so only gravity acts and it accelerates the object downward. Therefore, the speed of the object increases, and so does the air resistance, until a point where the air resistance becomes equal to gravity (which is constant): when this occurs, the acceleration of the object becomes zero (because forces are balanced), so the object continues its fall at constant velocity, called terminal velocity.

The second shell in the ground state of atomic argon contains 8 electrons.

Therefore, we can say that the atomic argon has 8 electrons in the second shell.

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The displacement of a plane that is uniformly accelerated is equal to 925.7 m.

The equations of motion can be described as the relationship of the motion of any physical system as the function of time and set up the relationship between the acceleration, velocity, time, and displacement of a moving system.

Given, the initial velocity of the plane, u = 66 m/s

The final velocity of the plane, v = 88 m/s

The time taken by the plane, t = 12 sec

From the first equation of motion we can calculate the acceleration:

v = u + at

88 = 66 + a(12)

a = 1.83 m/s²

From the second equation of motion we can calculate the displacement of the plane:

S = ut + (1/2)gt²

S = 66 × 12 + (1/2)× 9.8× (12)²

S = 925.7 m

Therefore, the displacement of the plane is 925.7 m.

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Answer:

3.72!!!

Explanation:

Answer:

1.09

Explanation:

Motorola connecter or a Motorola antenna plug is a connector used on a car radio antenna. It is a common coaxial cable RF connector used mainly in the locomotive trade for linking coaxial feed line from the antenna to the radio receiver. The pin of the connector is fused to the middle of the conductor of the coaxial cable starting the antenna. Its adjacent ground forms a 1.5inch long sleeve all over the coax. By rubbing the male plug alongside the female socket, the sleeve contains one or more longitudinal spring that offer sufficient electrical contact.

The connector on a car radio antenna is typically attached to the base of the antenna rod, facilitating the transmission and reception of radio waves.

The connector on a car radio antenna is typically attached to the base of the antenna rod.

The rod of the antenna is fed by a coaxial cable, where the center conductor is connected to the base of the rod, and the sheath is attached to the car body.

Antennas on cars, such as the commonly seen whip antenna, are important for converting electric power into radio waves for transmission and reception.

Final answer:

To determine the height above a window a flowerpot reached, we use kinematic equations for motion under gravity. By dividing the time the pot was in view by 2, and knowing the window's height, we calculate the initial velocity and then the additional height the pot reached above the window.

Explanation:

The question concerns a flowerpot moving past a window and how high it goes above the window after being in view for 0.49 seconds. To solve this, we can use kinematic equations of motion under constant acceleration due to gravity. We assume the pot goes up and then comes down passing the window twice, once going up and once going down. The time it takes to pass the window should be the same in both directions.

Divide the total time in view by 2 to find the time for one pass: 0.49 s / 2 = 0.245 s. Next, use the kinematic equation s = ut + 1/2at^2, where s is the distance, u is the initial velocity (0 m/s at the top of the window for the upward direction), a is the acceleration (gravity, which is -9.8 m/s^2 here), and t is the time the pot is in view. We can calculate the initial velocity needed to reach the top of the window in 0.245 s and then use that to find how high above the window top the flowerpot went.

Since the flowerpot was seen passing the entire height of the window (1.80 m), we use this distance to find the initial velocity it had when it first appeared at the bottom of the window. Using the kinematic formula u = (s - 1/2at^2) / t, we can solve for u. Then, apply this as the final velocity in the equation for its journey starting from the top of the window on its way up. With the final velocity at the top being zero (at the peak of its trajectory), we can now find the displacement above the window using the kinematic formula s = ut - 1/2at^2, and solve for s, where this time u is our previously calculated initial velocity and a is -9.8 m/s^2 (upward direction).

When set something is set down on the ground, negative work is said to be done by the body.

This is the type of work which is characterized by the force and displacement being in opposite direction.

This type of work occurs when the arm set down something on the ground which makes it the most appropriate choice.

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Answer: B or

A solid is like the tray being shaken slowly and all the marbles moving in their positions, a liquid is like the tray being shaken and the marbles moving around it, and a gas is like the tray being shaken hard and the marbles moving vigorously around it.

Explanation:

i did the test

X-rays are high energy electrons that can cause damage when exposed under extreme conditions. The best technology that can block it is using a lightweight type of metal foam. It can take in high energy collisions which also exhibits high forces. it does not only block x-rays but also, neutron radiation and gamma rays.

The second collision in this scenario is likely to be when the boy's body hits some interior part of the car after he initially impacts with the car. This is because of the conservation of momentum which needs to go somewhere after the initial collision, often resulting in a further collision.

In the scenario you explained, a young boy was riding his bicycle and hit a parked car. This is referred to as the first collision. The second collision in this context would be the boy's body hitting some interior part of the car (like the car door or windshield) after the initial impact with the car.

This is an application of the physics principle of conservation of momentum. Initially, the bike and the boy have some momentum, and after hitting the parked car, that momentum needs to go somewhere - which often results in a second collision. However, the exact nature of the second collision could depend on a few factors such as the speed of the bicycle and the angle at which the bicycle hit the car.

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