According to the Law of Conservation of Mass, the mass of the rust should be greater than the original mass of the iron nail, because the mass of the oxygen and water that form the rust are added to the mass of the iron nail.
Explanation:The principle at play here is the Law of Conservation of Mass, which states that matter cannot be created or destroyed in a chemical reaction. In this scenario, an iron nail is reacting with oxygen and water from the environment to form rust, or iron(III) oxide.
If the nail were left to rust completely, the mass of the rust would be greater than the original mass of the nail. This is because the mass of the oxygen and water that combines with the iron is added to the mass of the nail to form the rust. The additional mass comes from the oxygen atoms in the air and in the water that combine with the iron atoms in the nail.
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Which type of energy releases greenhouse gases when used to make electricity?
A.) Nuclear
B.) Hydroelectric
C.) Geothermal
D.) Natural gas
Plz help! Apex:(
Answer:
Natural gas
Explanation:
Nuclear is from splitting atoms in a nuclear power plant and doesn't emit GHG.
Hydroelectric is a clean energy which powered by water currents in turn not emitting any GHG.
Geothermal is heat captured from underneath the surface and within Earth and doesn't have GHG once the contruction of putting pipes underground is done.
Natural gas once burned emits GHG.
I need help on 31 and 32 please !!! 30pts !!
Answer:
h = 500 meters; angle = 45°
Explanation:
Don't worry the answers are very simple. As we can see in problem 31 we have a right triangle, the right triangle always has a 90° angle. Let's also remember that all the sum of the three angles of a triangle will be equal to 180°.
Using the trigonometric function of cosinus we can find the value for h.
[tex]cos(60)=\frac{h}{1000} \\h= cos(60)*1000\\h= 500[m][/tex]
Cosinus (angle) = adjacent side / hypotenuse
Hypotenuse = longest side of the right triangle
adjacent side = side of the triangle, near to the angle that we want to find its dimension.
In problem 32 we will use also the trigonometric function. In this case we don't know the hypotenuse dimension therefore the best trigonometric fuction is "tangent"
[tex]tan (\alpha ) = \frac{125}{125}\\\alpha =tan^{-1}(1)\\\alpha =45 (deg)[/tex]
tan (angle) = opposite side / adjacent side
find the angle between the vectors |A+B|=|A-B|
Answer:
90 degrees
Explanation:
In the attached image we can see, the condition where this condition (|A+B|=|A-B|) is true.
vector A is pointing horizontally to the right, vector B (positive), points up vertically.
Now analyzing the subtraction of vectors A and B = A - B, we have that vector A continues to point to the right (positive) and vector B points down (negative). In this way the magnitudes of both operations sum and subtraction of vectors is equal.
But the angle between the two vectors (A and B) will remain the same and will be 90°.
A ball is dropped from the top of a cliff. By the time it reaches the ground, all the energy in its gravitational potential energy store has been transferred into its kinetic energy store. If the ball is travelling at 20 m/s when it hits the ground, what height was it dropped from? (Assume that the gravitational field strength is 10 N/kg.)
Answer:
20 meters.
Explanation:
mgh = 1/2mv^2
gh = 1/2v^2
10(h) = 1/2(20)^2
10h = 1/2(400)
10h = 200
(10h)/10 = 200/10
h = 20
Answer:
20 meters
Explanation:
4.
A 4800-kg truck traveling with a
velocity of +4.0 m/s collides head-on
with a 1200-kg car traveling with a
velocity of -12 m/s. The truck and car
entangle and move together after the
collision. Fill in the before- and after-
collision table below.
Momentum Bo
Before the collision, the total momentum of the system is the sum of the momentum of the truck and the car. After the collision, the truck and the car move together with a final velocity of 0.8 m/s.
Explanation:Before the collision, the total momentum of the system is the sum of the momentum of the truck and the car:
Total momentum before = (mass of truck × velocity of truck) + (mass of car × velocity of car)
Total momentum before = (4800 kg × 4.0 m/s) + (1200 kg × -12 m/s)
Total momentum before = 19200 kg·m/s - 14400 kg·m/s = 4800 kg·m/s
After the collision, the truck and the car move together. They have the same final velocity. To find this velocity, we can use the principle of conservation of momentum:
Total momentum after = (mass of the combined system × final velocity)
4800 kg·m/s = (6000 kg × final velocity)
Final velocity = 4800 kg·m/s / 6000 kg = 0.8 m/s
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The final velocity is (4800 kg ×7 m/s) ×7 (6000 kg) = 0.8 m/s.
The subject question is concerned with momentum conservation in a collision between a truck and a car, a fundamental concept in physics. To fill in the before-and-after collision table, we calculate the initial momentum of each vehicle and use conservation of momentum to find the final velocity of the entangled masses.
The initial momentum of the truck is the product of its mass and velocity, which is (4800 kg) ×(4.0 m/s) = 19200 kg ×7 m/s directed 'positive'. For the car, it is (1200 kg) ×(-12 m/s) = -14400 kg ×7 m/s directed 'negative'. The total initial momentum of the system is the sum of the individual momenta: 19200 kg ×7 m/s - 14400 kg ×7 m/s = 4800 kg ×7 m/s.
After the collision, since the truck and car move together, we must find their combined mass and solve for the final velocity using the equation: (Total Initial Momentum) = (Total Mass) ×(Final Velocity). The total mass is (4800 kg + 1200 kg) = 6000 kg.
Studies have shown that viewing violent actions in the media __________ the inhibition against performing those actions, especially if the behavior is rewarded or results in positive benefits. A. increases B. decreases C. does not affect D. intensifies
Answer:
Decreases
Explanation:
Answer:
B. Decreases
Explanation:
According to differential reinforcement theory, one of the social learning theories, when behaviors are rewarded with the certain positive actions or positive outcomes then it is called positive enforcement. Positive enforcement increases the criminal actions. On the other hand, negative enforcement increases the actions which reduce the criminal activities.
According to theory explained above Studies have shown that viewing violent actions in the media decreases the inhibition against performing those actions when behavior is rewarded with the positive enforcement.
The motion of roller coasters depends upon the conversion of potential and kinetic energy. A 100-kg car starts from rest at the top of a hill with a height of 50 m. Which of the following is this car's kinetic energy at the bottom of the hill? 150 J 5000 J 49,000 J 98,000 J
Answer:
The kinetic energy will be 49000[J]
Explanation:
This problem is the common use of energy conservation when the body is at the top at the point where its elevation is the highest (usually the lowest point is taken as the reference level) at that point the body will have the highest potential energy, then as the body descends its potential energy decreases but its kinetic energy begins to increase. By the time the body reaches the lowest point or reference point, its potential energy will be zero, but its maximum kinetic energy, as all potential energy has become kinetic energy.
Therefore:
[tex]Ep=m*g*h\\where\\m =100 [kg]\\g= 9.81 [m/s^2] gravity\\h = 50 [m]\\\\Ep= 100*9.81*50\\Ep=49000 [J][/tex]
This energy will be transformed into kinetic energy at the bottom of the hill.
The kinetic energy of the roller coaster car at the bottom of the hill is 49,000 J, which equals the potential energy at the top of the hill assuming no energy loss to friction.
The motion of roller coasters relies on the conversion between potential and kinetic energy.
At the top of a hill, a roller coaster car has maximum gravitational potential energy, which is given by the equation:
PE = mgh,where
m is the mass (100 kg), g is the acceleration due to gravity (9.8 m/s²), and h is the height (50 m)Thus,
PE = 100 kg * 9.8 m/s² * 50 m PE = 49,000 J.Assuming no energy loss due to friction, this potential energy is entirely converted to kinetic energy at the bottom of the hill.
Hence, the kinetic energy of the car at the bottom is: 49,000 J.
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Reflection refers to light _____.
A. bending in a medium
B. bouncing off a surface
C. passing through an object
D. being stopped at an object
Answer:
B
Explanation:
Reflect: (of a surface or body) throw back (heat, light, or sound) without absorbing it.
Answer:
bouncing off a surface
Explanation:
definition of reflection: the throwing back by a body or surface of light, heat, or sound without absorbing it.
A new ride being built at an amusement park includes a vertical drop of 126.5 meters. Starting from rest, the ride vertically drops that distance before the track curves forward. If the velocity at the bottom of the drop is 10.0 m/s and the mass of the cart and passengers is 3.5 x 104 kg, how much potential energy was converted into thermal energy (heat)?
3.7 x 107 J
4.2 x 107 J
4.5 x 107 J
8.0 x 107 J
Answer:
Potential energy converted = 4.2*10^7 [J]
Explanation:
This problem has to be analysed under the principle of energy conservation. For this case potential energy that is transformed into kinetic energy, but however not all potential energy is transformed into kinetic energy, as we are told that some of this energy dissipates in the form of heat. We must first find the potential energy.
Potential energy
[tex]E_{p} =m*g*h\\where:\\m = mass =3.5*10^4[kg]\\g = gravity = 9.81[m/s^2]\\h = elevation = 126.5 [m]\\therefore\\E_{k} = 3.5*10^4*9.81*126.5\\E_{k} = 43433775 [J][/tex]
Kinetic Energy
[tex]E_{k}=\frac{1}{2} * m*v^{2}\\ where:\\v = velocity = 10[m/s]\\therefore:\\E_{k}=\frac{1}{2} * 3.5*10^4*10^{2}\\\\E_{k}=1750000[J][/tex]
As we can see, not all potential energy has been transformed into kinetic energy. That is, part of this energy dissipates as thermal energy, so this difference of energies will be equal to the loss of energy represented as dissipated energy.
[tex]Thermal Energy\\T_{e} = 43433775-1750000\\T_{e} =41683775[J][/tex]
The previous value can be approximated to 4.2 * 10^7 [J]
Answer:
4.2 x 10^7
I hope this helps!
a girl pushes a cart with a force of 10 N. if the cart has a mass of 5 kg, what is its acceleration?
Explanation:
Force=Mass*acceleration or F=MA. To find acceleration can be rewritten as A=F/M. If you input the numbers ypu can rewrite as A= 10N/5kg, A=2
The acceleration is 2 meters per sec.
An area where the water table is at, near, or above the land surface long enough during the year to support adapted plant growth is called a(n)
An area where the water table is at, near, or above the land surface long enough during the year to support adapted plant growth is called a wetland.
Explanation:
Wetland is a private water body, which gets fed permanently or seasonally. Wetland is not purely a water body, because it allows some aquatic plants to grow which have adapted to its hydric soil. They have their place in almost every continent. They have some types too, namely swamp, marsh, bog, etc.
Mangrove forests are also a type of wetlands because the roots of the mangrove trees store a huge amount of water, which can be used for different purposes. And also, the wetland is at sea-level, which means it is near to the water table also. Its spatial flow is identical to that of the flow of groundwater.
Describe an experiment that tests whether all metals are magnetic and identify the independent and dependent variable in your experiment.
Answer and Explanation:
NOTE: Magnetism means the magnetic property of a material that causes it to create a magnetic field, hence getting it attracted to a magnet.
EXPERIMENTAL PROCEDURE
1. Use a tape to attach a permanent magnet to the end of a ruler so that the magnet is facing away from the ruler. Don't cover the magnetic surface with the tape. ( Leave the magnet in its decorative casing.)
2. Place your metal objects in a row, and make predictions of which one of them will be attracted to the magnet and which will not.
3. Hold the magnet over each metals, and record which metals are attracted to the magnet. Go back over the
objects that were not affected by the magnet at least one more time to be sure you didn't miss any.
In this experiment, the independent variable is the magnetism of the magnet used. This is the independent variable because it remained unchanged and unaffected by the metals' magnetic properties all through the experiment.
While the dependent variable is the magnetism of the metals used. This is so because the magnetism of these metals varied and also because it is what is been measured in the experiment. Some were attracted to the magnet from very close range while others were attracted even at some centimeters away from the magnet which indicates that those metals have strong metallic properties.
Answer:
The aim of this experiment is to determine the magnetism and magnetic properties of objects.
Magnetism can be defined as the phenomenon that is a result of the movement of the free electron that produces an electric charge which in turn results in attractive and repulsive force between objects.
Explanation:
Aim: Determining which objects are magnetic.Material Required: Different kinds of objects such as eraser, wood cuttings, plastic balls, pins, glass, wires, coins, paper clip, screw, nut, and bolt.A magnet.Procedure:Scatter the various objects as mentioned above on the floor.Once scattered, take the piece of magnet and slowly hold it on top of each object.Observe carefully which of these objects slightly moves in the direction of magnet or simply which of these objects are attracted to the magnet.Inference: The objects that move in the direction of the magnets are attracted towards magnets, they're also called ferromagnetic. These include metals like Iron, Cobalt, Nickle, and their alloys.The objects that show no movement in the direction of the magnet are not attracted to a magnet.Independent variable: Such variables whose values don't depend on others. Here, the independent variable is the magnetism of the magnet.Dependent variable: Such variables whose value values depend on others or other factors. Here, the magnetic properties of the objects used in the experiment are dependent variables because the degree of attraction is different for different objects. Objects made of wood, glass, and plastic will have no magnetic properties while the alloys of Iron, Nickle, and Cobalt will have slight magnetic properties and objects made purely of the these metals will show strong magnetic properties.For more information:
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What is the relationship between the strength of an
electromagnet and the number of turns in the coil?
As the number of turns in the coil increases, the strength
of the electromagnet increases.
The number of turns in the coil has no impact on the
strength of the electromagnet.
As the number of turns in the coil decreases, the
strength of the electromagnet increases.
Answer:
As the number of turns in the coil increases, the strength of the electromagnet increases.
Explanation:
When current flows through a coil the coil behaves as an electromagnet. The strength of electromagnet depend the amount of current, no of turns of coil and the core of coil.
B=μ₀ N I
μ₀ = permeability of the core
N = Number of turns of the coil
I = Current flowing through the coil
Increasing the current and number of coils increase the strength of electromagnet.
8. In what family would each of these elements be classified?
Radium -
Tin -
Iodine -
Cesium -
Answer: Radium is a member of the alkaline metals group.
Tin is classified in the 'Other Metals' section which can be located in groups 13, 14, and 15 of the Periodic Table.
Iodine is classified as a halogen — a subset of very chemically reactive elements (Group 17 on the periodic table) that exist in the environment as compounds rather than as pure elements. The other halogens include fluorine (F), chlorine (Cl), bromine (Br) and astatine (At).
Cesium is classified as an "Alkali Metal" and located in Group 1 elements of the Periodic Table. An Element classified as an Alkali Metal is a very reactive metal that does not occur freely in nature. Alkali metals are soft, malleable, ductile, and are good conductors of heat and electricity.
Radium belongs to Alkaline Earth Metals, Tin to Post-transition Metals, Iodine to Halogens, and Cesium to Alkali Metals.
Explanation:The elements in question belong to different families on the Periodic Table.
Radium belongs to the Alkaline Earth Metals family. Tin belongs to the Post-transition Metals family. Iodine belongs to the Halogens family. Cesium belongs to the Alkali Metals family.
The elements Radium, Tin, Iodine, and Cesium belong to different families in the Periodic Table of Elements. Radium is classified in the Alkaline Earth Metals family, Tin is classified in the Carbon Group family, Iodine is classified in the Halogens family, and Cesium is classified in the Alkali Metals family.
Each family is grouped together because of similarities in chemical properties, as well as their shared valence electron structure.
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In your own words, what was the purpose of the field study?
Procedure
Write a short summary of how you completed your field study and how you classified the organisms.
Data
Use the following key to help you complete the field study.
New Fabula Creatures Taxonomic Key
Step Physical Feature Classification
1 Smooth skin Go to 2
Fur Go to 3
2 One eye Go to 4
Two eyes Go to 5
3 One eye Go to 7
Two eyes Go to 8
4 Arms and legs Silkus monowrestle
Legs only Silkus monosquirmus
5 Arms and legs Go to 6
Legs only Silkus duosquirmus
6 Tail Silkus tallyhas
No tail Silkus stretchilus
7 Tail Fuzzus tallywag
No tail Fuzzus feelzalot
8 Two teeth Go to 9
More than two teeth Fuzzus chompilus
9 Pointy Fuzzus pointilus
Square Fuzzus squarilus
Fill in the chart with each creature's scientific name based on your field study observations.
Creature Scientific Name
1
2
3
4
5
6
7
8
9
10
Conclusion
Now that you have classified the organisms on planet Fabula, answer the following questions:
1. How many different species are there?
2. How many different genus groups are there? List them.
3. Do you think all of these creatures would belong in the same Kingdom? Why or why not?
4. Explain in your own words the order in which the creature's traits may have evolved, starting from the first likely trait. (Hint: Which trait is most common across the creatures?)
Answer:
Hi there! I have only the procedure and the scientific names of the creatures. Hope this helps!
Procedure
I studied the physical features of ten creatures and classified them using the key. I completed each section below and recorded the creature's scientific name in the data section.
The Creatures Scientific Names:
1
Fuzzus tallywag
2
Fuzzus pointilus
3
Silkus duosquirmus
4
Fuzzus chompilus
5
Silkus stretchilus
6
Silkus tallyhas
7
Fuzzus feelzalot
8
Silkus monosquirmus
9
Fuzzus squarilus
10
Silkus monowrestle
Have a thrilling Thursday!
~Lola
Answer:
Creature
Scientific Name
1.
Fuzzus tallywag
2.
Fuzzus pointilis
3.
Silkus duosquirmus
4.
Fuzzus chompilus
5.
Silkus stretchilus
6.
Silkus tallyhas
7.
Fuzzus feelzalot
8.
Silkus monosquirmus
9.
Fuzzus squarilus
10.
Silkus monowrestle
Conclusion (10 points)
Now that you have classified the organisms on planet Fabula answer the following questions:
Skilled Scientist level from Rubric: Student used critical thinking skills and evidence to establish a possible relationship among organisms and a possible evolutionary history of traits.
How many different species are there?
THere are 10 different species.
How many different genus groups are there?
There are 10 different genus groups.
List the different genus groups:
Fuzzus Tallywag
Fuzzus pointilus
Silkus duosquirmus
Fuzzus chompilus
Silkus stretchilus
Silkus tallyhas
Fuzzus feelzalot
Silkus monosquirmu
Fuzzus squarilus
Silkus monowrestle
Do you think all of these creatures would be long to the same Kingdom? Why or why not?
Yes, because they all look the same, but also look different. It's kind of like cats and lions or dogs and wolves.
Explanation:
Which of the following is speed? a. the time at which a bicycle slows down b. the length of a racetrack c. the path of an elevator d. the rate at which a person slides down a rope
D. the rate at which a person slides down a rope.
This indicates speed because the person is timing people on how fast they will slide down a rope.
A 59.3 kg diver jumps off a board
and reaches the water with 1450 J
of KE. How high was the board?
(Unit = m)
The board is 2.50m high.
Why?
We can calculate how high was the board applying the Law of Conservation of Mechanical Energy. This Law states that the mechanical energy (kinematic and potential) will be conserved during the motion.
It can be described with the following formula:
[tex]E_{M_{1}}=E_{M_{2}}\\\\PE_{1}+KE_{1}=PE_{2}+KE_{2}[/tex]
[tex]PE=m*g*h\\KE=\frac{1}{2}m*v^{2}[/tex]
At the top of the boar, the kinetic energy is equal to 0.
At the water, the potential energy is equal to 0.
So,
[tex]PE_{1}=KE_{2}\\\\m*g*h=1450J\\\\59.3kg*9.8\frac{m}{s^{2}}*h=1450J\\ \\h=\frac{1450J}{59.3kg*9.8\frac{m}{s^{2}}}=2.50m[/tex]
Hence, we have that the board is 2.50m high.
Have a nice day!
Match the lithification processes.
1 . recrystallization
contact pressure causing grains to "fuse" together
2 . cementation
precipitation of bonding agents between grains
3 . compaction
increase in density due to weight of overburden
Answer:
Cementation---precipitation of bonding agents between grains.
Recrystallization---contact pressure causing grains to "fuse" together.
Compaction---increase in density due to weight of overburden.
Explanation:
I hope this helps you! Good luck and have a great day. ❤️✨
Find the resultant of two components, 3km west and 4 km south. How do I solve this using the Pythagorean theorem?
Answer:5
Explanation:
a=3
b=4
c=√(a²+b²)
c=√9+16
c=√25
c=5
Final answer:
To find the resultant of two components, 3km west and 4 km south, using the Pythagorean theorem, treat the components as the legs of a right triangle and apply the formula d = √(3² + 4²). The magnitude of the resultant of the two components, 3 km west and 4 km south, is 5 km.
Explanation:
To find the resultant of two components using the Pythagorean theorem, you need to consider the components as the legs of a right triangle. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In this scenario, the two components are 3 km west and 4 km south. These can be considered as the legs of a right triangle.
Let's denote:
- a = 3 km (west component)
- b = 4 km (south component)
The resultant, which represents the magnitude of the total displacement, can be found using the Pythagorean theorem:
[tex]\[ \text{Resultant}^2 = a^2 + b^2 \][/tex]
[tex]\[ \text{Resultant}^2 = (3 \, \text{km})^2 + (4 \, \text{km})^2 \][/tex]
[tex]\[ \text{Resultant}^2 = 9 \, \text{km}^2 + 16 \, \text{km}^2 \][/tex]
[tex]\[ \text{Resultant}^2 = 25 \, \text{km}^2 \][/tex]
Now, to find the magnitude of the resultant, we take the square root of both sides:
[tex]\[ \text{Resultant} = \sqrt{25 \, \text{km}^2} \][/tex]
[tex]\[ \text{Resultant} = 5 \, \text{km} \][/tex]
So, the magnitude of the resultant of the two components, 3 km west and 4 km south, is 5 km.
4. How far does a car travel in 90 seconds if it is traveling at a speed of 55 m/s?
Answer:90×55=4950km
Explanation:d=s×t
Answer:
4950 miles
Explanation:
You breathe in more oxygen than you breathe out. And you breathe out more carbon dioxide than you breathe in.
What type of change is oxygen turning into carbon dioxide?
A. physical only
B. chemical only
C. physical and chemical
Answer:
B. chemical only.
Explanation:
In the process of respiration which is a chemical process where organic compound is released. In this process exergonic reaction takes place in which compound changes into different ones.
Following are the two types of respiration:-
1] Aerobic respiration:- In this type of respiration requirement of oxygen is more and energy released is more.
2] Anaerobic respiration:- In this type of respiration oxygen requirement is less and energy released is also less.
A horizontal string tied at both ends is vibrating in its fundamental mode. The traveling waves have speed v, frequency v, amplitude A, and wavelength λ. Calculate the maximum transverse velocity and maximum transverse acceleration of points located at (i) x= λ /2, (ii) x= λ /4 and (iii) x= λ /8 from the left-hand end of the string.
Answer:
1) both velocity and acceleration at x = λ /2 are 0
2)maximum velocity at x=λ /4 is -2Aω
maximum acceleration at x=λ /4 is Aω²
3)maximum velocity at x=λ /8 is √2Aω
maximum acceleration at x=λ /8 is (-Aω²/√2)
Explanation:
When a string is tied at both ends and vibrated, we get standing waves.
The general form of standing wave is,
y(x,t) = 2A×sin(kx)×cos(ωt) (displacement of string at x and at time t)
where, A = amplitude of wave
ω = 2πv , v = frequency of the wave
k = 2π/λ ; λ = wavelength of wave
Speed V = ω/k.
Now, differentiating y(x,t) by once with t gives velocity
⇒V(x,t) = -2Aω×sin(kx)×sin(ωt)
And differentiating once again gives acceleration
a(x,t) = -Aω²×sin(kx)×cos(ωt)
1) x= λ/2
⇒V(x,t) = -2Aω×sin(k(λ /2))×sin(ωt)
= -2Aω×sin(π)×sin(ωt)
= 0
a(x,t) = -Aω²×sin(kx)×cos(ωt)
⇒ a(x,t) = -Aω²×sin(k(λ /2))×cos(ωt)
= -Aω²×sin(π)×cos(ωt)
= 0
2) x= λ /4
⇒V(x,t) = -2Aω×sin(kx)×sin(ωt)
= -2Aω×sin(k(λ /4))×sin(ωt)
= -2Aω×sin(π/2)×sin(ωt)
= -2Aω sin(ωt)
⇒ maximum velocity at x=λ /4 is -2Aω (minimum sin value is -1)
a(x,t) = -Aω²×sin(kx)×cos(ωt)
= -Aω²×cos(ωt)
⇒ maximum acceleration at x=λ /4 is Aω² (minimum cos value is -1)
3) x= λ /8
⇒V(x,t) = -2Aω×sin(kx)×sin(ωt)
= -√2Aω×sin(ωt)
⇒ maximum velocity at x=λ /8 is √2Aω (minimum sin value is -1)
a(x,t) = -Aω²×sin(kx)×cos(ωt)
= (-Aω²/√2) × cos(ωt)
⇒ maximum acceleration at x=λ /8 is (-Aω²/√2) (minimum cos value is -1)
The velocity perpendicular to the radius vector is called the transverse velocity. The transverse acceleration is the acceleration produced by an inertial force acting across the body. The expression for the maximum transverse velocity and acceleration has been obtained for given values of x.
Given information-A horizontal string tied at both ends is vibrating in its fundamental mode.
Transverse velocityVelocity perpendicular to the radius vector is called the transverse velocity.
The formula for the maximum transverse velocity can be given as,
[tex]V_m=-2A\omega\sin(kx)\times \sin(\omega t)[/tex]
Transverse accelerationTransverse acceleration is the acceleration produced by an inertial force acting across the body.
[tex]a_m=-A\omega^2 \sin(kx)\times \cos(\omega t)[/tex]
1) Maximum transverse velocity and maximum transverse acceleration when x is equal to the [tex]\lambda/2 [/tex] -[tex]V_m=-2A\omega\sin(k\dfrac{\lambda}{y} )\times \sin(\omega t)\\ V_m=-2A\omega\sin(\pi )\times \sin(\omega t)\\ V_m=0[/tex]
[tex]a_m=-A\omega^2 \sin(k\dfrac{\lambda}{2} )\times \cos(\omega t)\\ a_m=-A\omega^2 \sin(\pi )\times \cos(\omega t)\\ a_m=0[/tex]
2) Maximum transverse velocity and maximum transverse acceleration when x is equal to the [tex]\lambda/4 [/tex] -[tex]V_m=-2A\omega\sin(k\dfrac{\lambda}{4} )\times \sin(\omega t)\\ V_m=-2A\omega\sin(\dfrac{\pi}{2} )\times \sin(\omega t)\\ V_m=-2A\omega \times \sin(\omega t)\\ [/tex]
[tex]a_m=-A\omega^2 \sin(k\dfrac{\lambda}{4} )\times \cos(\omega t)\\ a_m=-A\omega^2 \sin(\dfrac{\pi}{2} )\times \cos(\omega t)\\ a_m=-A\omega^2 \times \cos(\omega t)\\[/tex]
3) Maximum transverse velocity and maximum transverse acceleration when x is equal to the [tex]\lambda/3 [/tex] -[tex]V_m=-2A\omega\sin(k\dfrac{\lambda}{8} )\times \sin(\omega t)\\ V_m=-{\sqrt{2} }{A\omega\times \sin(\omega t)} \\ [/tex]
[tex]a_m=-A\omega^2 \sin(k\dfrac{\lambda}{4} )\times \cos(\omega t)\\ a_m=\dfrac{-A\omega^2\times \cos(\omega t)}{\sqrt{2} } \\ [/tex]
Thus the maximum transverse velocity and maximum transverse acceleration at given points has been obtained.
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An object has a kinetic energy of 249 J and a momentum of magnitude 24.6 kg · m/s.(a) Find the speed of the object.
Answer:
The speed of the object is 20.24 m/s.
Explanation:
For a body of mass 'm' travelling with velocity 'v' , its kinetic energy is gievn by -
[tex]KE = \frac{1}{2}mv^{2}[/tex] --- 1
The momentum of body is given by -
[tex]p = mv[/tex] ---- 2
Dividing equation 1 and 2 , we get -
[tex]\frac{KE}{p} = \frac{v}{2}[/tex]
Given that ,
KE = 249 J
p = 24.6 kg.m/s
Substituting the 2 values in the above equation , we get -
v = 20.24 m/s.
When are tides lowest? What causes these tides to be lowest?
Tides are lowest when:
Tides are lowest when the earth, sun and moon come’s in a right angle. It occurs when the greatest pint in the wave or can called the crest arrives at the coast, the coast can feel the high tide, but when the smallest point i.e. trough arrives at the coast feels the low tide. The tidal force present makes the earth also the water to swell out of side which is often nearer to moon and the side farthest to that of moon, when no swelling can be seen low tides occurs.
Neap tides, which are the lowest tides, occur when the Sun and Moon's gravitational forces are at right angles to each other, typically during the first and third quarter moon phases.
Explanation:The lowest tides, known as neap tides, occur approximately twice a month when the Sun is at a 90° angle to the Earth-Moon alignment. During these periods, the gravitational forces of the Sun and the Moon act at right angles to each other, which reduces the overall tidal effect. Neap tides happen during the first and third quarters of the Moon’s phase, also referred to as the half-moon. Conversely, the highest tides, called spring tides, happen when the Earth, the Moon, and the Sun are aligned, typically during a new or full moon when their gravitational forces combine to create stronger tides.
If one horsepower is equal to 746 watts, how much horsepower does a highly trained athlete generate by doing 340 joules of work per second for an hourOne
746 joules per second = 746 watts = 1 horsepower
340 joules per second = 340 watts = (340/746) = 0.456 horsepower
Power is a RATE or a SPEED of doing work.
How long you do it doesn't matter.
Just like 30 miles per hour doesn't change whether you do it for an hour or for 10 minutes.
If one horsepower is equal to 746 watts, and a highly trained athlete generate by doing 340 joules of work per second for an hour is 0.456 horsepower.
What is Horsepower?Horsepower unit was first time used by James Watt in 1782. The story refers that James Watt uses worked with pony to charge coal from the mines. According to that story, he have the need of a unit to measure the force from one of this animals. He founds that they can move 22.000 lbs per minute, so he (arbitrarily) increase this measure in 50% been the unit Horsepower in 33.000 lb/feet per minute.This measure unit can measure "work" or "force". In the SI correspond to move up 75 Kg, to 1 meter high, in one second.
1 HP = (330 lb) x (100 feet)/1min = 33000 lb x feet/min
Is a practical unit, because reduce the amount of digits in a specific value. Also, it is more used specially in mechanical applications.
1 HP= 746 W (0,746 kW)
746 joules per second = 746 watts = 1 horsepower
340 joules per second = 340 watts = (340/746) = 0.456 horsepower
Thus, For a trained athlete, the value is 0.456 horsepower.
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WILL GIVE BRAINLIEST AND 50 POINTS!
Use the graph to answer the questions.
1. Based on the graph, what happens to current as resistance increases?
A. Increase
B. Decreases
C. Stays the same
2. This type of graph shows which type of relationship between the two variables?
A. Direct proportionally
B. Indirect proportionally
C. Inverse proportionally
3. What would be a reasonable estimate for current at a resistance of 50 Ω?
A. 0.5 A
B. 1 A
C. 5 A
D. 2 A
Answer:
1) Current decreases; 2) Inverse proportionally; 3) 1[A]
Explanation:
1)
As we can see as the resistance increases the current decreases, if we take two points as an example, when the resistance is equal to 50 [ohms] the current is equal to 1[amp] and when the resistance is equal to 200 [ohms] the current tends to have a value below 0.5 [amp]. Thus demonstrating the decrease in current.
2)
Inverse proportionally, by definition we know that the law of ohm determines the voltage according to resistance and amperage. This is the voltage will be equal to the product of the voltage by the resistance.
[tex]V=I*R\\V = voltage [volts]\\I = current[amp]\\R = resistance [ohms][/tex]
where:
[tex]R =\frac{V}{I} \\or\\I=\frac{V}{R}[/tex]
And whenever we have in a fractional number the denominator the variable we are interested in, we can say that this is inversely proportional to the value we are interested in determining. In this case, we can see from the two previous expressions that both the current and the resistance appear in the denominator, therefore they are inversely proportional to each other.
3)
If we place ourselves on the graph on the resistance axis, we see that at 50 [ohm] will correspond a current value equal to 1 [A].
Answer:
1. A. decrease
2. C. Inverse proportionally
3. B. 1 A
Explanation:
Talia is on a road trip with some friends. In the first 2 hours, they travel 100 miles. Then they hit traffic and go only 30 miles in the next hour. The last hour of their trip, they drive 75 miles. Calculate the average speed of Talia’s car during the trip. Give your answer to the nearest whole number. mph
Answer:
51.25 mph
Explanation:
[tex]Speed=\frac {Distance}{Time}[/tex]
Total distance= 100 miles + 30 miles + 75 miles=205 miles
Total time=2 hours+1 hour+1 hour= 4 hours
Average speed, [tex]s=\frac {205 m}{4 h}=51.25 mph[/tex]
The answer is 51
Explanation: Edg2020
NEED HELP!
Drift nets are huge nets that fishing boats use to catch fish. Drift nets can be several kilometers long and catch many more fish than do smaller, more traditional nets. How does the widespread use of drift nets affect the ocean ecosystem? A. It reduces pollution in the ocean. B. It increases the biodiversity of the ocean. C. It increases the populations of marine mammals that feed on fish. D. It reduces populations of fish and other marine organisms.
Answer:
Its D these nets have long been destroying the ecosystem
Answer: D.) It reduces populations of fish and other marine organisms.
Explanation: It was on study Island
how many grams of NO2 are in 3 moles of a nitrogen dioxide???
90.2g
138.2g
160g
0.07g
Answer:
138.0165
Explanation:
look up nitrogen dioxide to grams for stuff like this
A worker lifts a load of 200 N with the help of a lever by applying an effort of 50 N. The load is
kept at a distance of 20 cm and the effort is applied at a distance of im from the fulcram. Find the
mechanical advantage, velocity ratio, and efficiency of the lever used.
a) The mechanical advantage is 4
b) The velocity ratio is 5
c) The efficiency is 80%
Explanation:
a)
The mechanical advantage of a lever (or any other machine) is given by
[tex]MA=\frac{Load}{Effort}[/tex]
Where
[tex]Eff[/tex] is the effort (the force applied in input)
[tex]Load[/tex] is the load (the force in output to the lever)
For the lever in this problem, we have:
[tex]Eff = 50 N[/tex]
[tex]Load = 200 N[/tex]
Substituting into the equation, we find the mechanical advantage of the lever:
[tex]MA=\frac{200}{50}=4[/tex]
b)
The velocity ratio of a lever (or any other machine) is given by the equation
[tex]vr=\frac{d_{res}}{d_{eff}}[/tex]
where
[tex]d_{res}[/tex] is the length of the resistance arm
[tex]d_{eff}[/tex] is the length of the effort arm
For the lever in this problem, we have
[tex]d_{res} = 20 cm[/tex]
[tex]d_{eff}=1 m = 100 cm[/tex]
Therefore, the velocity ratio is
[tex]vr=\frac{100}{20}=5[/tex]
The velocity ratio represents the ideal mechanical advantage of the machine, i.e. the mechanical advantage in absence of friction, or the maximum theoretical mechanical advantage.
c)
The efficiency of the lever is given by the following ratio:
[tex]\eta = \frac{MA}{vr}[/tex]
where
MA is the mechanical advantage
vr is the velocity ratio
For the lever in this problem, we have
MA = 4 (calculated in part a)
vr = 5 (calculated in part b)
Therefore, the efficiency of the lever is
[tex]\eta = \frac{4}{5}=0.80[/tex]
Which means an efficiency of 80%.
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