Answer:
D they both have rocky surfaces
The earth and mars are similar to each other because both the planets have rocky surfaces. Thus, the correct option is D.
What are the Earth and mars?Earth and Mars are similar when it comes to their basic makeups, however it has been given that they are both the terrestrial type of planets. Earth and mars, both are differentiated between a dense metallic core and an overlying mantle and crust which are composed of less dense materials like silicate rocks.
Mars is about the half the size of the Earth by diameter and has a much thinner atmosphere, with an atmospheric volume which is less than 1% of the volume of the Earth. The atmospheric composition of the two planets are also significantly different because primarily they are carbon dioxide-based, while the Earth's is rich in nitrogen and oxygen gases.
Therefore, the correct option is D.
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Psi communication refers to the transfer of information through a/an ________ process.
Answer:
unknown
Explanation:
Psi communication: The term "Psi communication" was initially originated in an article named 'Mass Communication and Para-Social Interaction' during 1956 by Donald Horton, and is also denoted as "parasocial interaction". It is described as a phenomenon that involves "one-sided interaction" between people, encompassing the viewer knowing a specific celebrity well whereas the viewer himself or herself is being completely unknown for the celebrity in return.
In the question above, the given statement represents that the Psi communication is responsible for transforming via an unknown process as one of its members are considered as unknown of the transfer, so the correct answer would be "unknown process".
In a parallel circuit, more current will take the path of LEAST RESISTANCE.
True
False
Answer:
True
Explanation:
This is because least resistance would allow more current to pass through it. Since current, I is inversely proportional to resistance, R.
В каких из перечисленных случаев тело приобретает потенциальную энергию? А) воду в реке поднимают с помощью плотины В) пуля вылетает из ружья С) недеформированную пружину сжимают D) на земле лежит камень
Answer: D) a stone lies on the ground
Explanation:
Potential energy this is defined as the mechanical energy, energy stored, or energy created by the position of an object. Example; energy possessed by a ball while hanging at the top of a steep hill when about to roll down is called a potential energy. This is same as a stone which lies in a floor.
3. To open a soda bottle, a force of 55.0 N is applied to the bottle opener. If the bottle opener
applies a force of 675 N to the cap, what is the mechanical advantage of the bottle opener?
Output Force: 55.0 N
Input Force: 675 N
Mechanical Advantage:
Answer:
0.0815
Explanation:
Mechanical advantage is output force/input force. So all you have to do is 55.0N/675N ~ 0.0815
Hope this helped!
Final answer:
The mechanical advantage of the bottle opener is the ratio of the output force to the input force, resulting in a mechanical advantage of approximately 12.27.
Explanation:
The mechanical advantage (MA) of a simple machine is the ratio of the output force to the input force. In this scenario with the soda bottle opener, you are given an output force of 675 N and an input force of 55.0 N. To calculate the mechanical advantage, you divide the output force by the input force:
MA = Output Force ÷ Input Force
MA = 675 N ÷ 55.0 N = 12.27
The bottle opener has a mechanical advantage of approximately 12.27, meaning the force exerted on the cap is about 12.27 times greater than the force applied by the user.
a rollercoaster goes down hill
a. kinetic energy is converted into potential energy
b. potential energy is converted into kinetic energy
c. electrical energy is converted into potential energy
d. potential energy is converted into electrical energy
Answer:
a. potential energy is converted into kinetic energy
Explanation:
potential energy is the energy something has when it isn't in motion, as the roller coaster goes down hill (moves) the potential energy is turned into kinetic energy
Jessica has a mass of 55kg she sleds down a hill that has a slope of 32 degrees. what is the component of her weight that is along her direction of motion ?
Answer:
W = 285.62 N
Explanation:
It is given that,
Mass of Jessica is 55 kg
Slope of the hill is 32 degrees
We need to find the component of her weight that is along her direction of motion.
The component along her direction of motion is shown in attached figure. It means
[tex]W_y=mg\sin\theta\\\\W_y=55\times 9.8\times \sin(32)\\\\W_y=285.62\ N[/tex]
So, the component of her weight that is along her direction of motion is 285.62 N.
Answer:
286 rounded, - A P E X
Explanation:
there is a bell at the top of a tower that is 45m high. the bell has a mass of 18kg. the bell has what energy
Answer:
the bell has potential energy equal to,
18 x 9.8 x 45 = 7938 joules
An object is moving forward and then gets knocked sideways, what is this force called?
Final answer:
The force that knocks an object moving forward sideways is an external force, as described by Newton's first law of motion. This could be due to a collision, friction, or other forces changing the object's direction, like the effect felt during a sharp turn in a car.
Explanation:
The force you are asking about, when an object moving forward gets knocked sideways, is typically called an external force. In accordance with Newton's first law of motion, which states that an object will maintain its state of motion unless acted upon by a net external force, this sideways force changes the object's state of motion. In real-world situations, several forces can act as this external force, such as friction, tension, normal force, or even another object colliding with the one in motion.
For example, if an object like a rolling ball is knocked sideways by another ball, the sideways force is the result of the collision between the two balls. This changes the direction of the ball's momentum, creating a new motion path. Similarly, when a car makes a sharp turn, the force exerted by the friction between the tires and the road surface is what changes the direction of the car's velocity. This is why you might feel a force pushing you sideways in the seat, often referred to as a centrifugal effect, which is in fact the inertia of your body wanting to continue in a straight line.
Do magnets stick to all metal?
Answer:
No, only metal with magnetic properties.
Explanation:
Brass, Gold, Silver, are just some examples of metal magnets cannot stick on.
~
What is the definition for Astronomy?
Answer:
Astronomy is the branch of science that deals with celestial objects and space, including the physical universe.
Explanation:
Hope this helps :)
Answer:The definition of astronomy is the scientific study of matter outside of the atmosphere of the Earth including stars, planets and what they are made of and how they move.
Explanation:
About how long ago did our solar system start to form?
About 5 million years ago
About 14 million years ago
About 5 billion years ago
About 14 billion years ago
Answer:
(C)- About 5 billion years ago
Explanation:
4.6 Billion Years rounds up to 5 Billion Years
A spring is laid horizontally on a table and a force of 62 N is required to stretch the spring 12 cm. The spring is then held vertically and an object is attached to the end of it which causes the spring to stretch 9.7 cm. What is the Mass of the object?
SHOW YOUR WORK
Answer:
5.11 kg
Explanation:
Hooke's law states that stress is directly proportional to strain. It can be represented by the equation:
F = -kx
Where x is the displacement of the spring’s end from its equilibrium position, F is the force applied to the spring, k is a constant known as spring constant.
At first a force (F) of 62 N i used to stretch a spring by 12 cm (x).
Substituting into Hooke's equation:
F = kx
k = F/x = 62 / 12 = 5.17 N/cm
The spring is then held vertically and an object. The object is acted by upon by acceleration due to gravity since it is vertically upward. Therefore the force created by the object F = mg where g = acceleration due to gravity = 9.8 m/s². It causes a stretch (x) of 9.7 cm
Therefore:
mg = 5.17 N/cm × 9.7 cm
9.81m = 50.117
m = 50.117 / 9.81 = 5.11 kg
An electric charge, A, is placed carefully between two other charges, B and C, and experiences no net electric force. Do B
and C have the same charge (positive OR negative) as one another, opposite charges from one another, or do you not have
enough information to tell?
Answer:
I do not have enough information to tell
Explanation:
This is deduced due to the fact that if the net force due to B and C on A is zero, the charges on B and C could either be positive or negative depending on the charge on A.
A student discovers that sound waves travel 1,687.5 meters in 5 seconds through air at a temperature of 10°C. Based on this information, determine the speed of sound, in m/s, through air at this temperature.
Answer:
The speed of sound, in m/s, through air at this temperature is 343.5 m/s
Explanation:
Given;
distance traveled by sound, d = 1,687.5 meters
time taken for the sound to travel, t = 5 seconds
air temperature, θ = 10°C
Speed of sound = distance traveled by sound / time taken for the sound to travel
Speed of sound = d / t
= 1687.5 m / 5 s
= 337.5 m/s
Speed of sound at the given temperature is calculated as;
c = 337.5 + 0.6θ
c = 337.5 + 0.6 x 10
c = 337.5 + 6
c = 343.5 m/s
Therefore, the speed of sound, in m/s, through air at this temperature is 343.5 m/s
A hydraulic press has a large circular piston of radius 0.8m and circular plunger of radius 0.1m . A force of 200N is exerted by a plunger . Find the force exerted on the piston
Answer:
[tex]F_{o}=12800 N[/tex]
Explanation:
Let's use the Pascal principle:
[tex]P_{i}=P_{o}[/tex]
[tex]\frac{F_{i}}{A_{i}}=\frac{F_{o}}{A_{o}}[/tex]
Where:
F(i) is the input force, 200 N
F(o) is force exerted on the piston
A(i) is the area of the plunger (A =πr(i)²)
A(o) is the area of the piston (A =πr(o)²)
[tex]F_{o}=\frac{A_{o}F_{i}}{A_{i}}[/tex]
[tex]F_{o}=\frac{r_{o}^{2}F_{i}}{r_{i}^{2}}[/tex]
[tex]F_{o}=\frac{0.8^{2}*200}{0.1^{2}}[/tex]
[tex]F_{o}=12800 N[/tex]
I hope it helps you!
If a 340 g ball has 2.4 J of kinetic energy, what is it's velocity?
Answer:
Explanation:
i really dont know im a 4th grader
Answer:
3.76
Explanation:
KE = 1/2 * m *v^2
v=[tex]\sqrt{2.4*2/340 *1000}[/tex]
Which cells or organs are considered to be part of both the immune and lymphatic systems? Select all that apply.
arteries
lymph nodes
capillaries
tonsils and adenoids
veins
thymus
Answer:
lymph nodes
tonsils and adenoids
thymus
Explanation:
-Arteries are the blood vessels that take the blood that contains oxygen from the heart to the tissues and are part of the circulatory system.
-Lymph nodes are glands that take care of filtering the fluid that goes through the lympathic system and are also important for the functioning of the immune system.
-Capillaries are blood vessels that connect the veins and arteries and are part of the circulatory system.
-Tonsils and adenoids are located in the throat and they help protect the body from diseases and they are part of immune system and the lympathic system.
-Veins are the vessels that take the blood to the heart and they are part of the circulatory system.
-Thymus is an organ in which the T cells develop and they help protect the body against virus and bacteria and it is part of the immune and lympathic systems.
According to this, cells or organs that are considered to be part of both the immune and lymphatic systems are:
lymph nodes
tonsils and adenoids
thymus
Answer:
B), D), & E)
Explanation:
Edge 2021
1.- Un balín de acero a 20 C tiene un volumen de 0.004 m3. ¿Cuál es la dilatación que sufre cuando su temperatura aumenta a 50 C?
Answer:
[tex]\Delta V = 1.440\times 10^{-6}\,m^{3}[/tex]
Explanation:
El coeficiente de expansión volumétrica se calcula a partir de la siguiente ecuación diferencial parcial (The volumetric expansion coefficient is computed by means of the following partial differential equation):
[tex]\alpha = \frac{1}{V} \cdot \left(\frac{\partial V}{\partial T} \right)[/tex]
Se integra la fórmula a continuación (The formula is integrated herein):
[tex]\alpha\, dT = \frac{dV}{V}[/tex]
Supóngase que el coeficiente es constante (Let suppose that coefficient is constant):
[tex]\alpha \int\limits^{T_{f}}_{T_{o}}\,dT = \int\limits^{V_{f}}_{V_{o}}\, \frac{dV}{V}[/tex]
[tex]\alpha \cdot (T_{f}-T_{o}) = \ln \frac{V_{f}}{V_{o}}[/tex]
El volumen final es (The final volume is):
[tex]V_{f} = V_{o}\cdot e^{\alpha \cdot (T_{f}-T_{o})}[/tex]
El coeficiente de expansión volumétrica del acero es [tex]12\times 10^{-6}\,^{\circ}C^{-1}[/tex] (The volumetric expansion coefficient of steel is [tex]12\times 10^{-6}\,^{\circ}C^{-1}[/tex]):
[tex]V_{f} = (0.004\,m^{3})\cdot e^{(12\times 10^{-6}\,^{\circ}C^{-1})\cdot (50^{\circ}C-20^{\circ}C)}[/tex]
[tex]V_{f} \approx 4.001\times 10^{-3}\,m^{3}[/tex]
Finalmente, la dilatación experimentada por el balín es (Lastly, the dillatation experimented by the pellet is):
[tex]\Delta V = 4.001\times 10^{-3}\,m^{3} - 4.000\times 10^{-3}\,m^{3}[/tex]
[tex]\Delta V = 1.440\times 10^{-6}\,m^{3}[/tex]
La dilatación que sufre un balín de acero al pasar de 20 C a 50 C es de 0.00000432 m^3. Esta respuesta se obtiene aplicando la formula de dilatación volumétrica y asumiendo el coeficiente de dilatación volumétrica para el acero es de aproximadamente 0.000036 1/C.
El problema nos pide encontrar la dilatación del acero cuando su temperatura sube de 20 C a 50 C. La dilatación es un fenómeno físico donde los objetos cambian de tamaño debido a los cambios de temperatura. Para entender esto mejor, supongamos que es necesario calcular la dilatación volumétrica de un objeto hecho de acero cuando su temperatura cambia.
La fórmula general para el cálculo de la dilatación volumétrica es: ΔV = β·V0·ΔT, donde ΔV es la dilatación, β es el coeficiente de dilatación volumétrica (acero tiene un valor de aproximadamente 0.000036 1/C), V0 es el volumen inicial ( en este caso 0.004 m3) y ΔT es el cambio de temperatura en grados Celsius (50 C - 20 C = 30 C).
Entonces, sustituimos los valores en la fórmula: ΔV = 0.000036 1/C * 0.004 m3 * 30 C = 0.00000432 m3
Por lo tanto, cuando la temperatura del balín de acero aumenta de 20 C a 50 C, sufre una dilatación de 0.00000432 m3.
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what are the two forces involved in an interaction called
Answer:These two forces are called action and reaction forces and are the subject of Newton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects.
Explanation:
Final answer:
The two forces involved in an interaction are contact forces and field forces; contact forces require physical contact, like the Coulomb force resulting in friction, while field forces, such as gravitational and electromagnetic forces, act at a distance.
Explanation:
The two forces involved in an interaction are commonly referred to as contact forces and field forces. Contact forces occur due to direct physical contact between two objects. An example of this is the Coulomb force, which occurs between the charges in atoms and molecules in close proximity, such as when a baseball hits a bat. On a larger scale, these forces are experienced as the force of friction and the normal force.
In contrast, field forces act without the necessity of physical contact; they occur because of the presence of a field in the space around an object. Examples of field forces include the gravitational force, which is due to mass, and the electromagnetic force, which occurs between charged particles and can manifest as either electrostatic or magnetic forces. Both of these types of forces, contact and field forces, are essential for understanding the interactions between objects in physics.
On Earth, Yancy hits a golf ball as hard as he can. The golf ball flies 150 meters before hitting the ground. About how far would the golf ball fly if Yancy hit it on the surface of Mercury with exactly the same amount of force and in the same direction? (Ignore the air resistance on both planets.) A. 150 yards B. more than 150 meters C. 150 meters D. less than 150 meters
Answer:
More than 150 meters
Explanation:
Answer:
more than 150 meters
Explanation:
Question 1
A student makes the claim that the space around a charged particle will exert a force on any other charged particle that is placed within this space If an object is placed between two charged metal plates, one
plate that is positively charged and one plate that is negatively charged, which argumentBEST supports the student's claim?
A
An object with a positive charge will move toward the negative plate
B
An object with a negative charge will remain stationary between the plates
A neutrally-charged object will move toward the positive plate
A neutrally-charged object will move toward the negative plate
Answer:
Its A
Explanation:
I took the test
The claim of the student that supported should be an object along with the positive charge along with will the movement towards the negative plate.
What is a charged particle?In terms of physics, the charged particle refer to the particle along with an electric charge. It should be ion like molecule or atom along with a surplus or deficit of electrons with respect to the b. In the case when the object should be considered as the positive charge should be movement towards the negative plate so the same should be considered as the student claim.
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Guadalupe and her family fly to Disney world, 450 miles away, in 3 hours. At what
speed was the plane traveling?
Suppose an automobile has a kinetic energy
of 2300 J.
When it moves with six times the speed,
what will be its kinetic energy?
Answer in units of J.
Answer:
Explanation:
Given that,
Kinetic energy of an automobile is 2300J
K.E = 2300J
The formula for kinetic energy is
K.E = ½mv²
So, if the speed of the automobile is increased by 6, what is the kinetic energy
Now v' = 6v.
The mass of the automobile is constant.
Therefore, the kinetic energy is
K.E' = ½mv'²
Where v' = 6v
K.E' = ½m(6v)²
K.E' = ½m × 36v²
K.E' = 36 × ½mv²
Where, from above ½mv² = 2300J
Then,
K.E' = 36 × 2300 = 82,800J
The kinetic energy of the automobile when it increase it's speed is 82,800J
When the automobile moves with six times the initial speed, its kinetic energy will be 82800 J.
The kinetic energy (KE) of an automobile is given by the formula:
[tex]\[ KE = \frac{1}{2}mv^2 \][/tex]
where[tex]\( m \)[/tex]is the mass of the automobile and [tex]\( v \)[/tex] is its velocity.
If the automobile's kinetic energy is 2300 J at a certain speed, then we can denote this initial kinetic energy as [tex]\( KE_{initial} \)[/tex]and the initial speed as[tex]\( v_{initial} \)[/tex]. We have:
[tex]\[ KE_{initial} = \frac{1}{2}mv_{initial}^2 = 2300 \, \text{J} \][/tex]
When the automobile moves with six times the initial speed, its new speed is [tex]\( v_{new} = 6v_{initial} \).[/tex] The new kinetic energy[tex]\( KE_{new} \)[/tex]can be calculated using the same formula:
[tex]\[ KE_{new} = \frac{1}{2}m(6v_{initial})^2 \] \[ KE_{new} = \frac{1}{2}m \cdot 36v_{initial}^2 \] \[ KE_{new} = 36 \cdot \frac{1}{2}mv_{initial}^2 \] \[ KE_{new} = 36 \cdot KE_{initial} \][/tex]
Since [tex]\( KE_{initial} = 2300 \, \text{J} \)[/tex], we substitute this value into the equation:
[tex]\[ KE_{new} = 36 \cdot 2300 \, \text{J} \] \[ KE_{new} = 82800 \, \text{J} \][/tex]
The answer is: 82800.
A uniform electric field with a magnitude of 250 N/C is directed in the positive x direction. A 12 μC charge moves from the origin to the point (20.0 cm, 50.0 cm). What is the change in the electrical potential ener- gy of the system as a result of the change in position of this charge?
The change in electrical potential energy of the system can be calculated using the equation: ΔPE = q * ΔV, where ΔPE is the change in potential energy, q is the charge, and ΔV is the change in electric potential. In this case, the change in electrical potential energy of the system is 0.060 J.
Explanation:The change in electrical potential energy of the system can be calculated using the equation:
ΔPE = q * ΔV
Where ΔPE is the change in potential energy, q is the charge, and ΔV is the change in electric potential.
In this case, the charge q is 12 μC and the change in electric potential is given by ΔV = E * d, where E is the electric field strength and d is the displacement.
Plugging in the values, we get:
ΔPE = (12 μC) * (250 N/C) * (20.0 cm) * (1 m/100 cm)
Simplifying the units and the calculation, the change in electrical potential energy of the system is 0.060 J.
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To find the change in electrical potential energy, calculate the work done by the electric field as the charge moves along the x-axis. The work done equals 6 × 10⁻⁴ J, which is the change in electrical potential energy.
Change in Electrical Potential Energy
To determine the change in electrical potential energy of the system, we need to consider the direction and magnitude of the electric field and the charge's movement.
The electric field extbf(E) is directed along the positive x-axis with a magnitude of 250 N/C. The charge q is 12 μC (microcoulombs), or 12 × 10-6 C.
The initial position of the charge is at the origin (0,0), and the final position is (20.0 cm, 50.0 cm). Convert these to meters: (0.2 m, 0.5 m). The electric field works only along the x-axis, so we only need the change in the x-coordinate.
Work done by the electric field is defined as:
W = qEΔx
Here, Δx = xfinal - xinitial = 0.2 m - 0 m = 0.2 m.
Now, substitute the values:
W = (12 × 10⁻⁶ C) * (250 N/C) * (0.2 m)
W = 12 × 10⁻⁶ * 250 * 0.2
W = 12 × 10⁻⁶ * 50
W = 600 × 10⁻⁶ J
W = 6 × 10⁻⁴ J
This work is equal to the change in electrical potential energy (old{ΔU}) of the system.
The change in electrical potential energy of the system is 6 × 10⁻⁴ Joules.
Question 20
5 pts
A 3.00-cm tall light bulb is placed at a distance of 50 cm from a thin convex lens having a focal length of
13 cm. What is the image distance?
Answer:
The image distance is 17.56 cm
Explanation:
We have,
Height of light bulb is 3 cm.
The light bulb is placed at a distance of 50 cm. It means object distance is, u =-50 cm
Focal length of the lens, f = +13 cm
Let v is distance between image and the lens. Using lens formula :
[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{13}+\dfrac{1}{(-50)}\\\\v=17.56\ cm[/tex]
So, the image distance is 17.56 cm.
Final answer:
Explanation on how to calculate the image distance for a light bulb placed 50 cm away from a thin convex lens with a 13 cm focal length.
Explanation:
The image distance for the light bulb placed 50 cm away from a thin convex lens with a focal length of 13 cm can be calculated using the lens formula:
1/f = 1/do + 1/di
Where:
f = focal length of the lens (13 cm)
do = object distance from the lens (50 cm)
Solving for di, the image distance would be around 15.62 cm.
A cyclical motion occurs because of density differences in the mantle. Heated, less dense lower regions of the fluid mantle rise, and denser, cooler regions sink due to gravity. The combined motions serve as the engine for crustal plate movement.
A. convection currents
B. subduction
C. density circles
D. seafloor spreading
What is power, and what is its relationship to voltage and amperage?
A scooter has a mass of 250. Kg. A constant force is exerted on it for 60.0 S. during the time the force is exerted, the scooter increases its speed from 6.00 m/s to 28.0 m/s. What is the change in momentum? What is the magnitude of the force exerted on the scooter?
Answer:
Explanation:
change in momentum = m ( v - u ) ; m is mass , V is final velocity and u is initial velocity .
= 250 ( 28 - 6 )
= 5500. N.s
for calculating magnitude of force we shall apply the concept of impulse
Impulse = F X t = m( v-u ) ; F is force applied for time t .
F x 60 = 5500
F = 91.67 N .
force exerted = 91.67 N .
Change in momentum is 5500 N/S
The magnitude of the force exerted on the Scooter is 91.67 N
The calculation can be done as follows
The formula for change in momentum is;
m(v-u)
250(28-6)
250(22)
5500 N/S
The formula for magnitude of the force is
F ˣ 60= 5500
F= 5500/60
F= 91.67 N
Hence the magnitude of force is 91.67 N and the change in momentum is 5500 N/S
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A 90g ball, initially at rest, is dropped from a height of 2.1m.
a. Calculate the net force acting on the ball.
b. Calculate the acceleration of the ball.
c. Calculate the final velocity of the ball just before it hit the ground.
Answer:
a. 0.882 N b. 9.8 m/s² c. 6.42 m/s
Explanation:
a. The net force acting on the ball is its weight W = mg were m = mass of ball = 90 g = 0.090 kg and g = acceleration due to gravity = 9.8 m/s²
W = mg = 0.090 kg × 9.8 m/s² = 0.882 N
b. The acceleration = g = acceleration due to gravity = 9.8 m/s² since it is falling freely
c. Using v² = u² + 2as where v = final velocity of ball, u = initial velocity of ball = 0 m/s, a = acceleration of ball = 9.8 m/s² and s = height = 2.1 m. Substituting the values of the variables, we ave
v² = u² + 2as = 0² + 2(9.8 m/s²) × 2.1 m = 41.16
v = √41.16 = 6.42 m/s
What type of clouds usually accompany cold fronts?
a.
cumulus
c.
cirrus
b.
stratus
d.
none of the above
Please select the best answer from the choices provided
A
B
C
D
Answer: Cumulus
Explanation: Most large cloud fronts are made up of cumulus clouds, large storm clouds are cumulonimbus clouds.