In triangle KLM LM = 7 and angle k equals 45 Find KL.

Answers

Answer 1
Final answer:

In this problem, the student can use the properties of a 45°-45°-90° triangle to determine that the hypotenuse KL is 7 * √2 which is approximately equal to 9.9.

Explanation:

In a triangle where you know one angle (45°) and one side (7 units) across from the right angle, it is a typical example of a situation where trigonometry can be used. In this case, you're dealing with a 45°-45°-90° triangle, also known as an isosceles right triangle. In such a triangle, the sides are in a specific ratio. The sides opposite the 45° angles are the same length (let's call it 'a'), and the hypotenuse is a√2.



Given that LM = 7 and angle K is 45°, triangle KLM is therefore an isosceles right triangle and KL (the hypotenuse) is equal to LM multiplied by √2. So, KL = 7 * √2 which approximately equals to 9.9.


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Related Questions

On a rotating turntable, how do tangential speed and rotational speed vary with distance from the center?

Answers

Tangential speed increases with distance. Rotational speed is constant.

Assume that y varies inversely with x. If y=6.4when x=4.4, find y when x=3.2

Answers

Because y varies inversely with x, let
y = k/x
where k = constant.

When x=4.4, y=6.4. Therefore
k/4.4 = 6.4
k = 6.4*4.4 = 28.16

The required relation is
y = 28.16/x

When x = 3.2, obtain
y = 28.16/3.2 = 8.8

Answer: 8.8

the answer is 8.8

that is the answer

i need help with this question

Answers

[tex]g(x)= \sqrt{x-5} , h(x)= x^{2} -6[/tex]

case (i):
the output of the first machine ([tex]\sqrt{x-5}[/tex]) is the input of the second machine, so we plug ([tex]\sqrt{x-5}[/tex]) or g(x) in function h and calculate, as follows:

[tex]h(g(x))=h(\sqrt{x-5})[/tex], now h is the function which squares whatever the input is and subtracts 6:

[tex]h(\sqrt{x-5})=(\sqrt{x-5}) ^{2}-6=x-5-6=x-11[/tex]

case (ii): we plug h in g:

[tex]g(h(x))= \sqrt{h(x)-5}= \sqrt{ x^{2} -6-5}= \sqrt{ x^{2} -11} [/tex]


a. 

case1

[tex]h(g(x))=x-11=5 [/tex]

x=16

so for x=16, h(g(x))=5

case2 

[tex]g(h(x))= \sqrt{ x^{2} -11}=5[/tex]

[tex] x^{2} -11=25[/tex]

[tex] x^{2} =36[/tex]

x=-6 or x=6

for both these values, g(h(x))=5


so since her input was 6, the order was g(h(x)), that is h(x) was the input of g(x)


b.

case1

[tex]h(g(x))=x-11=-5[/tex]

x=11-5=6, 

so for x=6, h(g(x))=-5

case2

[tex]g(h(x))= \sqrt{ x^{2} -11}=-5[/tex]

the square root cannot be a negative number



Answer: 

A. order is g(h(x))

B. yes, for h(g(x)) only

Solve 3x2 + 13x = 10
a. x = two over three and x = −5
b. x = 3 and x = −3
c. x = −2 and x = five over three
d. x = −7 and x = 13

Answers

We want to solve the quadratic equation 3x² + 13x = 10.

Write the equation as
3x² + 13x - 10 = 0

Use the quadratic formula to obtain
x = (1/6) [ -13 +/- √{13² - 4*3*(-10)} ]
   = (1/6) [-13 +/- √289]
   = (1/6) [-13 +/- 17]
x = -30/6 = -5
or
x = 4/6 = 2/3

The solution is x = 2/3 and -5.

Answer:  a

Answer:

A. x = two over three and x = -5

The equation 3x^2 + 13x = 10 can be solved using the quadratic formula. The solutions are given by:

[tex]$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$[/tex]

Substituting the values from the equation (where a = 3, b = 13, and c = -10), we get:

[tex]$$x = \frac{-13 \pm \sqrt{13^2 - 4*3*(-10)}}{2*3}$$[/tex]

This simplifies to:

[tex]$$x = \frac{-13 \pm \sqrt{289}}{6}$$[/tex]

So, the solutions are:

[tex]$$x = \frac{-13 + \sqrt{289}}{6} = \frac{2}{3}$$[/tex]

and

[tex]$$x = \frac{-13 - \sqrt{289}}{6} = -5$$[/tex]

So, the correct answer is A. x = two over three and x = −5.

A rectangular room is 4 4 times as long as it is wide, and its perimeter is 60 60 meters. find the dimension of the room.

Answers

L = 4w
4w + w + w + 4w = 60
10w = 60
w = 6
4w = 24
L = 24

(just to check the answer, 24 + 24 + 6 + 6 = 60 :)

What is the formula for finding the area of a regular polygon with perimeter P and apothem length a?

Answers

Answer:

[tex]A=\frac{1}{2}Pa[/tex]

Step-by-step explanation:

Let

P------> the perimeter of a regular polygon

a-----> the apothen

A-----> the area of a regular polygon

we know that

The formula to calculate the area of a regular polygon is equal to

[tex]A=\frac{1}{2}Pa[/tex]

The formula for finding the area of a regular polygon with

perimeter P and apothem length a is 1/2Pa.

What is a Polygon?

This is referred to as a plane figure which has a finite number of

straight line segments connected to form a closed polygonal

chain.

The formula for calculating the area of a regular polygon is

1/2Pa where P is the perimeter of a regular polygon and a is the

apothem.

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what is the maximum value of the function y = −3x2 − 15x + 9?

Answers

y = -3x² - 15x + 9
The graph of this equation is an n-shape. It will go up to a maximum point and then arc back downwards.
In order to find this point, there are two ways I can think of, I will show the one I prefer:
First, take out the coefficient of the x² terms:
y = -3(x² + 5x - 3)
Now, CTS (complete the square):
y = -3((x + 5/2)² - 25/4 - 3)
y = -3(x + 5/2)² + 111/4
Maximum Point: (-5/2, 111/4) or (-2.5, 27.75)

There are 10 pots exposed in the shop, 2 of which have hidden defects. the customer buys two pieces. what is the probability that at least one of them has a hidden bug ?

Answers

check the tree diagram, of all the possible scenarios and the probabilities.

All the possible scenarios are: 

1st.non defective,  2nd.non defective
1st.non defective,  2nd. defective
1st. defective,  2nd. non defective
1st. defective,  2nd. defective

consider the case 1st.non defective,  2nd.non defective

the probability that the first one is non defective is 8/10, since 8 out of 10 are non defective.

In this scenario, the second one is non defective as well. The probability for this to happen is 7/9, since now we have 7 non defective pots, and 9 in total.

This means that the probability of the first to be non defective, and the second non-defective is (8/10) * (7/9)=0.622

similarly we calculate the other cases, as shown in the picture.

P(at least one is defective)=
P(1st.non defective,  2nd. defective)+P(1st. defective,  2nd. non defective)+P(1st. defective,  2nd. defective)=
0.178+0.178+0.022=0.378


Answer: 0.378

Choose the answer that best represents the situation described below. Kurt is buying a new cell phone. He knows that the more features the cell phone has, the more expensive it will be. A. The cost of the cell phone is a function of the number of features. B. The size of the cell phone is a function of the number of features. C. The number of features is a function of the cell phone company Kurt chooses.

Answers

Final answer:

The cost of the cell phone is a function of the number of features.

Explanation:

The answer that best represents the situation described is option A. The cost of the cell phone is a function of the number of features.

In this case, as Kurt is buying a new cell phone, he knows that the more features the cell phone has, the more expensive it will be. This implies that the cost of the cell phone is dependent on the number of features it has.

For example, if a cell phone with basic features costs $200, a cell phone with additional features like a better camera, more storage, and waterproof capabilities may cost $400 or more.

HELP WILL GIVE BRAINLIEST (08.01)
Line Q is represented by the following equation: 2x + y = 11

Which equation completes the system that is satisfied by the solution (3, 5)?
x + 2y = 15
x + y = 15
x + y = 8
x − y = 2

Answers

Plug in x and y into the available choices.
3+2(5)=13 not 15
3+5=8 not 15
3-5 p=-2 not 2
The only logical answer is C

Answer:

C  (1, 1) is the solution to line K but not to line J..

The ratio of the number of girls to the number of boys was 3 to 5 . of 2,520 were presented, how many were girls and how many were boys

Answers

girls to boys...3 to 5.....added = 8

3/8(2520) = 7560/8 = 945 girls <==
5/8(2520) = 12600/8 = 1575 boys <==

There were 945 girls and 1575 boys respectively.

What is the ratio of two quantities?

Suppose that we've got two quantities with measurements as 'a' and 'b'

Then, their ratio(ratio of a to b) a:b or a/b

We usually cancel out the common factors from both the numerator and the denominator of the fraction we obtained. The numerator is the upper quantity in the fraction and the denominator is the lower quantity in the fraction). Remember that the ratio should always be taken of quantities with the same unit of measurement. Also, the ratio is a unitless(no units) quantity.

We have been given that the ratio of the number of girls to the number of boys was 3 to 5.

The ratio girls to boys;

3 to 5

The Total = 8

The number of boys was 3 to 5 . of 2,520, Then;

3/8(2520) = 7560/8

girls = 945  

5/8(2520) = 12600/8

boys = 1575

Therefore, there were 945 girls and 1575 boys respectively.

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ASAP WILL MARK BRAINIEST ANSWER FOR FIRST CORRECT ANSWER Find the image of A(4, -2) after it is reflected over the line y = 2, then reflected over the line x = 2. (-8, 6) (0, -2) (0, 6) (-8, -2)

Answers

0,6.....thx for the Brainliest!

Answer:

(0, 6)

Step-by-step explanation:

Since, when a points is reflected through the line y = 2,

Then, the rule will be,

[tex](x,y)\rightarrow (x, -(y-4))[/tex]

While, the points is reflected through the line x = 2,

Then, the rule will be,

[tex](x,y)\rightarrow (x-4, y)[/tex]

So, when (4,-2) is reflected over the line y = 2 is,

[tex](4,-2)\rightarrow (4, -(-2-4))[/tex]

Hence, the position of (4,-2) after reflection through line y = 2 is (4,6),

Now,  when (4,6) is reflected over the line x=2 is,

[tex](4,6)\rightarrow (4-4, 6)[/tex]

Hence, the position of (4,6) after reflection through line x = 2 is (0,6),

Third option is correct.

On Saturday Mike ran 5.5 kilometers swam 300M and invite 23 hectometers how many kilometers did he travel in total

Answers

Mike traveled 8.1 kilometers

F leonard bought 2 packs of batteries for x amount of dollars, how many packs of batteries could he purchase for $5.00 at the same rate

Answers

1.
The rate at which Leonard bought was 2 packs per x dollars, 

that is his buying rate was (2 packs)/(x dollars)=2/x (p/$)

2.

with 1 $ Leonard buys 2/x packs
then
with 5 $ Leonard buys (2/x)*5 = 10/x packs.

Answer: 10/x packs

Scientists are studying the temperature on a distant planet. Let y represent the temperature (in degrees Celsius).
Let x represent the height above the surface (in kilometers). Suppose that x and y are related by the equation =y−235x .
Answer the questions below. Note that a change can be an increase or a decrease.

For an increase, use a positive number. For a decrease, use a negative number.

What is the temperature change for each kilometer we go up from the surface?

Answers

wouldn't this be science because it's dealing with temperature?

Final answer:

For each kilometer increase in altitude, the temperature on the distant planet decreases by 235 degrees Celsius, according to the given equation y = -235x.

Explanation:

The question pertains to the relationship between altitude and temperature on a distant planet. Given the equation y = -235x, where y represents the temperature in degrees Celsius and x represents the height above the surface in kilometers, we are asked to determine the temperature change for each kilometer as we increase elevation from the surface.

To find the temperature change per kilometer, we examine the coefficient of x in the equation. Since the coefficient is -235, it signifies that for every kilometer increase in altitude, the temperature on this planet decreases by 235 degrees Celsius.

Some facts about powers of ten are shown.

Use what you know about powers of ten to enter numbers that make the equation true

Enter numbers to write 256,000 in scientific notation.

Answers

10^5 is a 1 followed by 5 zeros, so it is 100,000.
Multiply 2.56 and 100,000 and you get 256,000.

First box is 100,000 and the second box is 5

The number 256,000 can be written as 2.56 x [tex]10^5[/tex]  in scientific notation

How does scientific notations work?

The number is written in the form [tex]a \times 10^b[/tex]

The number b shows the order, which is the most important figure for which scientific notation is used. It tells us how much order large or small a value is in powers of 10. We can for a time, ignore the value of 'a' for two comparable quantities and only compare their orders(this type of comparison is useful when difference is too big, like size of human to size of a star etc sort of comparisons).

Scientific notations value in terms of power of 10 is known, which helps in easy comparison of quantities differing by a large value.

To write 256,000 in scientific notation.

[tex]10^5[/tex] is followed by 5 zeros, so, it is 100,000.

Now Multiply 2.56 and 100,000 we get

2.56 x 100,000 = 256,000.

Therefore, First box is 100,000 and the second box is 5

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Solve the inequality. Check your solutions.

7−(2/b)<(5/b)

im not surehow to answer this, it's supposedly in a number form but I'mcompetely lost. Maybe a _

Answers

The inequality is 

[tex]7- \frac{2}{b}\ \textless \ \frac{5}{b}[/tex]

write 7 as 7b/b to have all the expressions in common denominator:

[tex] \frac{7b}{b} - \frac{2}{b}\ \textless \ \frac{5}{b}[/tex]

[tex]\frac{7b-2}{b} \ \textless \ \frac{5}{b}[/tex]

[tex]\frac{7b-2}{b}- \frac{5}{b}\ \textless \ 0[/tex]

[tex]\frac{7b-2-5}{b}\ \textless \ 0[/tex]

[tex]\frac{7b-7}{b}\ \textless \ 0[/tex]

[tex]\frac{7(b-1)}{b}\ \textless \ 0[/tex]

here b=1 is a root and b=0 is not in the domain of the expression, but it still has an effect in the sign of the expression.

the sign table of [tex]\frac{7(b-1)}{b} [/tex] is :

+++++++[0] --------[1] +++++

this means that for values of b to the left of 0 and to the right of 1, the expression is positive, and for values of b in (0, 1), the expression is negative.

that is [tex]\frac{7(b-1)}{b}\ \textless \ 0 [/tex] for b∈(0, 1)

Answer: (0, 1)

Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2). Find the coordinates of the center of the circle.

Answers

Since we are given three points on the circle, and we know that each point is a distance equal to the radius to some point (x,y), we can set up a system of equations to solve for the center...

Knowing that the distance between any two points is:

d^2=(x2-x1)^2+(y2-y1)^2 and these distances are all equal we can say

d^2=(x-0)^2+(y-0)^2, (x+3)^2+(y-0)^2, (x-1)^2+(y-2)^2

d^2=x^2+y^2,  x^2+6x+9+y^2,  x^2-2x+1+y^2-4y+4  now getting differences

0=-6x-9,  8x+4+4y  

Since both of the equations above are equal to zero we can see that:

-6x-9=0

-6x=9

x=-9/6

x=-1.5, making 8x+4+4y=0 become:

8(-1.5)+4+4y=0

-12+4+4y=0

-8+4y=0

4y=8

y=2

So the center of this circle is at the point (-1.5, 2)

Suppose three out of every five people said they would prefer a television over a computer. If we surveyed 5,000 people, how many would prefer a television? A. 1,875 B. 5,000 C. 3,125 D. 3,000

Answers

3/5 people means 60% prefer televisions.
60% of 5000 is equal to 0.6*5000=3000
Final answer: D

Evaluate the determinant for the following matrix: [1 4 4 5 2 2 1 5 5]

(This is a 3x3 matrix)

Answers

I would assume the order of the 3×3 matrix to be in this manner:

  1    4    4
  5    2    2
  1    5    5

To determine the determinant of the matrix, you must multiply the number diagonally. For a 3×3 matrix, you must also form 3 diagonals up and 3 diagonals down. To do this, you copy the the first two columns and place it next to the third column.

   1   4   4   1   4
   5   2   2   5   2 
   1   5   5   1   5

The sum of the products of the diagonals down is subtracted to the sum of the products of the diagonals up. In other words, 
Determinant = ∑(products of diagonal down) - ∑(products of diagonal up)
Determinant = [(1*2*5)+(4*2*1)+(4*5*5)]-[(1*2*4)+(5*2*1)+(5*5*4)]
Determinant = 0

The determinant of the matrix is zero.

Final answer:

The determinant of the given 3x3 matrix [1 4 4 5 2 2 1 5 5] is calculated by expanding across the first row and is found to be -60.

Explanation:

To evaluate the determinant of a 3x3 matrix, you can use the method of expansion across any row or any column. Given the matrix [1 4 4 5 2 2 1 5 5], let's expand across the first row:

The determinant of the matrix is the sum of the products of each element in the chosen row or column and the determinant of the 2x2 matrix that remains after removing the row and column of that element.

Multiply the first element of the first row by the determinant of the remaining 2x2 matrix, then subtract the product of the second element and its associated 2x2 matrix, and add the product of the third element and its 2x2 matrix.

Calculating the values, we get: 1*(2*5 - 2*5) - 4*(5*5 - 2*1) + 4*(5*2 - 2*1) = 1*0 - 4*23 + 4*8 = 0 - 92 + 32.

Therefore, the determinant of the given matrix is -60.

Can square root of 27 be simplified

Answers

Yes, square root of 27 can be simplified

[tex] \sqrt{27}= \sqrt{9*3}=3 \sqrt{3} [/tex]


The roots up to 27 are 1 4 9 16 and 25. 9 is a factor of 27 so the answer is yes.
To take 9 out, write the root on the left side (3) and write what is left on the right (3 since 9 times 3 is 27) The answer to root 27 simplified is 3 root 3

Find an equation in standard form for the hyperbola with vertices at (0, ±3) and foci at (0, ±7)

Answers

The equation of a hyperbola is:

(x – h)^2 / a^2 - (y – k)^2 / b^2 = 1

 

So what we have to do is to look for the values of the variables:

For the given hyperbola : center (h, k) = (0, 0)
a = 3(distance from center to vertices)
a^2 = 9


c = 7 (distance from center to vertices; given from the foci)
c^2 = 49

 

By the hypotenuse formula:
c^2 = a^2 + b^2
b^2 = c^2 - a^2

b^2 =  49 – 9

b^2  = 40

Therefore the equation of the hyperbola is:

(x^2 / 9) – (y^2 / 40) = 1

Answer:

Hope this helps :)

Step-by-step explanation:

Find the length of the hypotenuse of a right triangle whose legs measure 6 and 5

Answers

A right triangle is a type of triangle which contains a right triangle. To be a right triangle, it should satisfy the Pythagorean Theorem which relates the three sides of the triangle. In this triangle, the longest side is called as the hypotenuse. To determine the hypotenuse, we use the Pythagorean Theorem which is expressed as follows:

c^2 = a^2 + b^2

where c is the hypotenuse

We calculate as follows:

c^2 = a^2 + b^2
c^2 = 6^2 + 5^2
c^2 = 61
c = √61

Therefore, the hypotenuse of the right triangle with sides 6 and 5 would be √61 which, clearly, is longer than the two sides.

The length of the hypotenuse is: [tex]\[ c = \sqrt{61} \][/tex]

To find the length of the hypotenuse of a right triangle with legs measuring 6 and 5, we use the Pythagorean theorem, which states:

[tex]\[ a^2 + b^2 = c^2 \][/tex]

where a  and b  are the lengths of the legs, and c is the length of the hypotenuse.

Given:

a = 6

b = 5

We need to find  c . Plugging the values into the Pythagorean theorem, we get:

[tex]\[ 6^2 + 5^2 = c^2 \][/tex]

Calculating the squares:

[tex]\[ 36 + 25 = c^2 \][/tex]

Adding the numbers:

[tex]\[ 61 = c^2 \][/tex]

To find c , we take the square root of both sides:

[tex]\[ c = \sqrt{61} \][/tex]

Therefore, the length of the hypotenuse is:

[tex]\[ c = \sqrt{61} \][/tex]

If there are x teams in a sports​ league, and all the teams play each other​ twice, a total of​ n(x) games are​ played, where ​n(x)equals

Answers

1.
Consider a group of n objects. Assume we want to form groups of r, from these n objects.

There are in total [tex]C(n, r)= \frac{n!}{r!(n-r)!} [/tex] many ways of doing so.

where, r! is "r factorial", calculated as 1*2*3*...*(r-1)*r

2.

C(x, 2) is the total number of pairs out of x objects, that we can form.

so let the x objects represent the x teams, and 2, represent a group of 2, which means a game.

The total number of games is:

n(x)=2*C(x, 2) = [tex]2* \frac{x!}{2!(x-2)!}= \frac{x!}{(x-2)!}= \frac{x(x-1)(x-2)!}{(x-2)!}=x(x-1)= x^{2} -x [/tex]

Remark, we multiplied by 2, since there will be 2 matches for each pair of teams.


Answer: [tex] x^{2} -x[/tex]

How do we do this ? is it c or a? 15 points!!!!

Answers

The answer you're looking for is b.  I and III.  II would be [tex]-a ^{5} [/tex] and IV would be [tex]- a^{-5} [/tex]

ROUND 47342.6653106 TO 1 DECIMAL PLACE HELP!

Answers

this is the answer 473242.7
I got 47343. The number after the original number (2) is a 6, which is bigger than a 5, so you round up

I'm studying for a test and i seriously can't figure this out. I took a screenshot. Please help and thanks. :) :P :D

Answers

Hello there!

What we are dealing with is called "Pythagorean Theorum", also known as the famous equation "A^2 + B^2 = C^2." The side length "A" is usually the side length opposite of the hypotenuse, which is the side length "C" that is directly across from the right angle of the triangle. The side length "B" is adjacent to the hypotenuse.

Let's apply this to our current triangle.

We have the side length "A", which is 12 in., and our side length "B", which is 6 in.

Now, let's plug in our numbers to our variables in order to solve for C.

A^2 + B^2 = C^2
Replace A with 12 and B with 6.

12^2 + 6^2 = C^2
Simplify the exponents.

144 + 36 = C^2
Simplify the left side.
180 = C^2.

Now, we must solve for C. As C is being squared, we must apply the opposite mathematical term, which is square rooting.

C^2 = 180.
Square root both sides to solve for C.

C = [tex] \sqrt{180} [/tex] in.

Your answer is (C).

I hope this helps!

Given g(x) = 2x2 − 9x − 18 and f(x) = x − 6, identify (g/f)(x).

Answers

answer is 2x+3, x not equal to 6

 see attached pic for steps

Answer:

2x + 3, x ≠ 6

Step-by-step explanation:

If x and y are not both equal to zero 1/x+y = 1/x + 1/y

Look at the picture provided below

  |
 V

Answers

Answer:

True

Step-by-step explanation:

All work is shown and pictured

Pretty sure this is super easy I'm just an idiot pls help!

Answers

Hello there!

7x + 3x - x
Combine like-terms first.
10x - x
9x

This is equivalent to 9x^1, or 9x to the degree of 1. This is known as a monomial.
monomial is a number/product of numbers and variables with whole number exponents. 

Some examples are as follows:

I hope this helps!
The correct answer is B. monomial because all of the terms are combine-able. 
Other Questions
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