Answer: There are 6045 millions world population during the period of 1950 to 2000.
Step-by-step explanation:
Since we have given that
The world population in the second half of the 20 the century by the equation:
[tex]P(t)=2560e^{0.017185t}[/tex]
We need to find the average world population during the period of 1950 to 2000.
So, there are 50 years between 1950 to 2000.
So, t = 50 years.
Therefore, the average population would be
[tex]P(50)=2560e^{0.017185\times 50}\\\\P(50)=6045.15\\\\P(50)\approx 6045\ millions[/tex]
Hence, there are 6045 millions world population during the period of 1950 to 2000.
Write the Ratio 32 :42 as a Fraction in Simplest Form
Divide by 2 for both of the numbers
32/2, 42/2
16/21
Answer is 16/21
Answer:
Divide both numbers by 2
32÷2 ,42÷2
Or, 16,21
answer is 16,21
Convert ln x = y to exponential form.
How do you convert 7/2^6 to decimal please? ( seven over 2 to the power of 6)
You just put the expression in a calculator! We have
[tex]\dfrac{7}{2^6} = \dfrac{7}{64}=0.109375[/tex]
2007 Federal Income Tax Table Single: Over But not over The tax is $0 $7,825 10% of the amount over $0 $7,825 $31,850 $788 + 15% of the amount over $7,825 $31,850 $77,100 $4,386 + 25% of the amount over $31,850 $77,100 $160,850 $15,699 + 28% of the amount over $77,100 $160,850 $349,700 $39,149 + 33% of the amount over $160,850 $349,700 And Over $101,469 + 35% of the amount over $349,700 Mr. Profit had a taxable income of $35,000. He figured his tax from the table above. 1. Find his earned income level. 2. Enter the base amount. = $ 3. Find the amount over $ = $ 4. Multiply line 3 by % = $ 5. Add Lines 2 and 4 = $ 6. Compute his monthly withholding would be = $
The total tax comes to $5,173.50, with a monthly withholding of approximately $431.13.
To calculate Mr. Profit's federal income tax based on a taxable income of $35,000 in 2007, we need to find the correct tax bracket and perform a series of calculations:
Earned income level: Based on the provided information, an income of $35,000 falls into the third bracket (over $31,850 but not over $77,100).Enter the base amount: The base amount for this bracket is $4,386.Find the amount over: The amount over $31,850 is $35,000 - $31,850, which equals $3,150.Multiply line 3 by the percentage: Multiply the amount over $31,850 by the rate of 25%, which is $3,150 * 25% = $787.50.Add lines 2 and 4: Adding the base amount to the above calculation gives us the total tax: $4,386 + $787.50 = $5,173.50.Compute his monthly withholding: To find the monthly withholding amount, we divide the total tax by 12 months: $5,173.50 / 12 = $431.125.Therefore, Mr. Profit's federal income tax for 2007 would be $5,173.50, and his monthly withholding would be approximately $431.13.
Mr. Profit's earned income level is $35,000. The base tax is $4,386, with an additional tax of $787.50 for amounts over $31,850. Monthly withholding comes to approximately $431.13.
To calculate Mr. Profit's tax liability based on his taxable income, we need to identify which tax bracket his income falls into and then compute the tax accordingly.
Given that Mr. Profit has a taxable income of $35,000, he falls into the 25% tax bracket, where the taxable income is over $31,850 but not over $77,100.
The tax table for this bracket is:
Base tax for incomes from $7,825 to $31,850: $788
The marginal tax rate for income over $31,850: 25%
Let's compute the tax following the provided steps.
Earned Income Level
Mr. Profit's earned income level is his taxable income:
Earned Income Level = $35,000
Base Amount
The base tax amount for his tax bracket:
Base Amount = $4,386
Amount Over
The amount over the lower bound of his tax bracket:
Amount Over = $35,000 - $31,850 = $3,150
Multiply by Percentage
Multiply the amount over by the tax rate for his bracket (25%):
Multiply Line 3 by 25% = $3,150 \times 0.25 = $787.50
Add Base and Multiplication Result
Add the base amount and the calculated tax from step 4:
Add Lines 2 and 4 = $4,386 + $787.50 = $5,173.50
Compute Monthly Withholding
Given that there are 12 months in a year, compute the monthly withholding:
Compute monthly withholding [tex]= $5,173.50 \div 12 \approx $431.13[/tex]
Thus, rounding to two decimal places, we have :
Earned Income Level: $35,000
Base Amount: $4,386
Amount Over: $3,150
Multiply Line 3 by Percentage: $787.50
Add Lines 2 and 4: $5,173.50
Compute monthly withholding: $431.13
The complete question is : 2007 Federal Income Tax Table Single: Over But not over The tax is $0 $7,825 10% of the amount over $0 $7,825 $31,850 $788 + 15% of the amount over $7,825 $31,850 $77,100 $4,386 + 25% of the amount over $31,850 $77,100 $160,850 $15,699 + 28% of the amount over $77,100 $160,850 $349,700 $39,149 + 33% of the amount over $160,850 $349,700 And Over $101,469 + 35% of the amount over $349,700 Mr. Profit had a taxable income of $35,000. He figured his tax from the table above. 1. Find his earned income level. 2. Enter the base amount. = $ 3. Find the amount over $ = $ 4. Multiply line 3 by % = $ 5. Add Lines 2 and 4 = $ 6. Compute his monthly withholding would be = $
Evaluate the function at the given value of the independent variable. Simplify the results. (If an answer is undefined, enter UNDEFINED.) f(x) = x3 − 49 x f(x) − f(7) x − 7 =
To evaluate the function f(x) = 5x² + 7 at a given value, substitute that value into the function and simplify. The resulting answer is the function's value at that point. For the difference quotient f(x) - f(7)/(x - 7), the value is undefined if x = 7.
To evaluate the function f(x) = 5x² + 7 at a given value of the independent variable and simplify the results, we simply plug in the value of the independent variable into the function. For example, if we want to evaluate f at x = 3, we would calculate f(3) = 5(3)² + 7 = 5(9) + 7 = 45 + 7 = 52. Thus, the evaluated function at x = 3 is 52.
If we were to find the difference quotient f(x) - f(7)/(x - 7), we would need to plug in a value for x that is not 7, as the expression is undefined for x = 7. For any other value of x, we substitute x into the function, subtract f(7), and divide by (x - 7). If x = 7, the result is UNDEFINED.
Calculate ∬y dA where R is the region between the disks x^2+y^2 <=1 & x^2+(y-1)^2 <=1
Show all work. (Also explain why you split up the regions)
Let's first consider converting to polar coordinates.
[tex]\begin{cases}x=r\cos\theta\\y=r\sin\theta\end{cases}\implies\begin{cases}x^2+y^2=1\iff r=1\\x^2+(y-1)^2=1\iff r=2\sin\theta\end{cases}[/tex]
We have
[tex]1=2\sin\theta\implies\sin\theta=\dfrac12\implies\theta=\dfrac\pi6\text{ or }\theta=\dfrac{5\pi}6[/tex]
Then [tex]\mathrm dA=r\,\mathrm dr\,\mathrm d\theta[/tex] and the integral is
[tex]\displaystyle\iint_Ry\,\mathrm dA=\int_{\pi/6}^{5\pi/6}\int_{2\sin\theta}^1r^2\sin\theta\,\mathrm dr\,\mathrm d\theta=\boxed{-\frac{\sqrt3}4-\frac{2\pi}3}[/tex]
Fast! Which of the following are characteristics of the graph of the square root
parent function? Check all that apply.
Answer:
Only choices B and C are correct.
Step-by-step explanation:
The square root parent function is [tex]f(x)= \sqrt{x}.[/tex]
The function [tex]f(x)[/tex] is not a linear function, therefore it's graph cannot be a straight line. This rules out choice A.
The function [tex]f(x)[/tex] is defined at [tex]x=0[/tex] because [tex]f(0)= \sqrt{0} =0[/tex]. This means that choice B is correct.
The function [tex]f(x)[/tex] is only real for values [tex]x\geq 0[/tex], because negative values of [tex]x[/tex] give complex values for [tex]f(x)[/tex]. This means that choice C is correct.
The function [tex]f(x)[/tex] can take only positive values which means it is confined to only the I quadrant, and is not defined in quadrants II, III, and IV. This rules out Choice D.
Therefore only choices B and C are correct.
Answer:
B & C
Step-by-step explanation:
B and C are the answers
when are the expressions 3x +12 and 3(x+4) equvialent
Answer:
For any value of x
Step-by-step explanation:
Solve by using system of equations!
3x+12
3(x+4)=3x+12
3x+12=3x+12
x=x
This means that any value of x would create the same answer for both equations.
Answer:
Always.
Step-by-step explanation:
Always. This is true by distributive property.
The length of time it takes to find a parking space at 9 A.M. follows a normal distribution with a mean of 5 minutes and a standard deviation of 2 minutes. Find the probability that it takes at least 8 minutes to find a parking space. (Round your answer to four decimal places.)
Answer: 0.0668
Step-by-step explanation:
Given: Mean : [tex]\mu = 5\text{ minutes}[/tex]
Standard deviation : [tex]\sigma = 2\text{ minutes}[/tex]
The formula to calculate z is given by :-
[tex]z=\dfrac{X-\mu}{\sigma}[/tex]
To check the probability it takes at least 8 minutes (X≥ 8) to find a parking space.
Put X= 8 minutes
[tex]z=\dfrac{8-5}{2}=1.5[/tex]
The P Value =[tex]P(z\geq1.5)=1-P(z\leq1.5)=1- 0.9331927=0.0668073\approx0.0668[/tex]
Hence, the probability that it takes at least 8 minutes to find a parking space = 0.0668
The probability that it takes atleast 8 minutes to find a parking space is 0.0668
Given the Parameters :
Mean = 5 minutes Standard deviation = 2 minutes X ≥ 8First we find the Zscore :
Zscore = (X - mean) / standard deviationZscore = (8 - 5) / 2 = 1.5
The probability of taking atleast 8 minutes can be expressed thus and calculated using the normal distribution table :
P(Z ≥ 1.5) = 1 - P(Z ≤ 1.5)
P(Z ≥ 1.5) = 1 - 0.9332
P(Z ≥ 1.5) = 0.0668
Therefore, the probability, P(Z ≥ 1.5) is 0.0668
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The student business club on your campus has decided to hold a pizza fund raiser. The club plans to buy 50 pizzas from Dominos and resell them in the student center. Based upon the specials advertised on the Dominos website, what will you need to charge per slice (assume 8 slices per pizza) in order to break even? Since this is a fund raiser, what would you suggest charging for each slice and, based on this, what would the net profit be to this club? Why do you feel breakeven analysis is so crucial in the development of new products for businesses?
Answer:
2.50 per slice would be okay because most people would order 2 slices and that would have them give you an even 5.00. Net profit for this would be 464.00
Step-by-step explanation:
The specials advertised on Domino's website is 5.99 for each pizza, 8 slices.
The break even price is 1.34 per slice. This is important to know because a business never wants to take a loss.
To break even, the club would need to charge $2 per slice. However, for fundraising, they might charge $3 per slice, giving a net profit of $400. Breakeven analysis is crucial in business as it helps in decision making and financial planning.
Explanation:Based on the information given, we see that the business club wants to purchase 50 pizzas from Domino's and resell them on campus. Assuming each pizza costs $16 (as per the example given for Authentic Chinese Pizza), the initial cost for the club would be $800 (50 pizzas x $16).
To calculate the break-even price per slice, we would need to divide the total cost by the total number of slices: $800 / (8 slices x 50 pizzas) = $2 per slice. However, since this is a fundraiser, the club might want to add in a margin to generate profit, so they might charge for example $3 per slice, resulting in a profit of $1 per slice, or $400 total.
The breakeven analysis is crucial in the development of new products because it helps businesses determine the minimum production and sales levels they must achieve to avoid losing money. This is useful for decision making and financial planning in any business operation.
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Factor the higher degree polynomial
5y^4 + 11y^2 + 2
[tex]5y^4 + 11y^2 + 2=\\5y^4+10y^2+y^2+2=\\5y^2(y^2+2)+1(y^2+2)=\\(5y^2+1)(y^2+2)[/tex]
For this case we must factor the following expression:
[tex]5y ^ 4 + 11y ^ 2 + 2[/tex]
We rewrite[tex]y^ 4[/tex] as[tex](y^ 2) ^ 2[/tex]:
[tex]5 (y ^ 2) ^ 2 + 11y ^ 2 + 2[/tex]
We make a change of variable:
[tex]u = y ^ 2[/tex]
So, we have:
[tex]5u ^ 2 + 11u + 2[/tex]
we rewrite the term of the medium as a sum of two terms whose product is 5 * 2 = 10 and whose sum is 11. Then:[tex]5u ^ 2 + (1 + 10) u + 2\\5u ^ 2 + u + 10u + 2[/tex]
We factor the highest common denominator of each group:
[tex]u (5u + 1) +2 (5u + 1)[/tex]
We factor [tex](5u + 1):[/tex]
[tex](5u + 1) (u + 2)[/tex]
Returning the change:
[tex](5y ^ 2 + 1) (y ^ 2 + 2)[/tex]
ANswer:
[tex](5y ^ 2 + 1) (y ^ 2 + 2)[/tex]
Two balls are drawn at random from an urn containing six white and nine red balls. Recall the equatio n for an. r) given below. C(n,r) (a) Use combinations to compute the probability that both balls are white. (b) Compute the probability that both balls are red. (a) The probability that both balls are white is (Type an integer or a decimal. Round to two decimal places as needed.)
Answer: (a) [tex]\dfrac{1}{7}[/tex] (b) [tex]\dfrac{12}{35}[/tex]
Step-by-step explanation:
Given: Number of white balls : 6
Number of red balls = 9
Total balls = 15
(a) The probability that both balls are white is given by :-
[tex]\dfrac{^6C_2}{^{15}{C_2}}\\\\=\dfrac{\dfrac{6!}{2!(6-2)!}}{\dfrac{15!}{2!(15-2)!}}=\dfrac{1}{7}[/tex]
∴ The probability that both balls are white is [tex]\dfrac{1}{7}[/tex] .
(b) The probability that both balls are red is given by :-
[tex]\dfrac{^9C_2}{^{15}C_2}\\\\=\dfrac{\dfrac{9!}{2!(9-2)!}}{\dfrac{15!}{2!(15-2)!}}=\dfrac{12}{35}[/tex]
∴ The probability that both balls are red is [tex]\dfrac{12}{35}[/tex] .
Find the absolute maximum and minimum values of f(x.y)=x^2+y^2-2x-2y on the closed region bounded by the triangle with vertices (0,0), (2,0), and (0,2)
Try this suggested solution, note, 'D' means the region bounded by the triangle according to the condition. It consists of 6 steps.
Answers are underlined with red colour.
Which number is irrational?
A. 0.14
B.1/3
C. Square root 4
D. Square root 6
Answer:
[tex]\sqrt{6}[/tex]
Step-by-step explanation:
Let's define irrational by stating what rational means first, and the use the process of elimination.
A rational number is one that can be expressed as a ratio. When dividing the numerator of this ratio by the denominator, we will either get a whole number, a decimal that repeats a pattern, or we will get a decimal that terminates.
.14 terminates, so it is rational
1/3 divides to .333333333333333333333333333333333333333 indefinitely, so it is rational
square root of 4 is 2, a whole number, so it is rational
the square root of 6, to 9 decimal places, is 2.449489743... and it goes on without ending and without repeating. So this is the only irrational number of the bunch.
Answer:
D
Step-by-step explanation:
in what form is the following linear equation written y=9x+2
The linear equation can be written as; 9x - y = -2
What is a linear equation?A linear equation is an equation that has the variable of the highest power of 1. The standard form of a linear equation is of the form Ax + B = 0.
We are given the linear equation as;
y = 9x + 2
-9x + y = 2
A cannot be a negative:
-1(-9x + y = 2)
9x - y = -2
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The 5 hour energy drink should keep a person feeling awake while driving for 5 hours, regardless of their age. Stacy just doesn't believe it. So she has 50 twenty year olds, 50 thirty year olds, 50 forty year olds, and 50 fifty year olds consume a 5 hour energy drink, and then Stacy measured participants' awakeness after 5 hours of driving. What test should she use to analyze her results?
Answer:
a. Single-sample Z-Test
b. Single-sample t-test
c. Independent-measures t-test
d. Repeated-measures t-test (Paired-samples t-test)
e. Independent-measures ANOVA
Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. lim x → (π/2)+ cos(x) 1 − sin(x)
Answer:
The limit of the function at x approaches to [tex]\frac{\pi}{2}[/tex] is [tex]-\infty[/tex].
Step-by-step explanation:
Consider the information:
[tex]\lim_{x \to \frac{\pi}{2}}\frac{cos(x)}{1-sin(x)}[/tex]
If we try to find the value at [tex]\frac{\pi}{2}[/tex] we will obtained a [tex]\frac{0}{0}[/tex] form. this means that L'Hôpital's rule applies.
To apply the rule, take the derivative of the numerator:
[tex]\frac{d}{dx}cos(x)=-sin(x)[/tex]
Now, take the derivative of the denominator:
[tex]\frac{d}{dx}1-sin(x)=-cos(x)[/tex]
Therefore,
[tex]\lim_{x \to \frac{\pi}{2}}\frac{-sin(x)}{-cos(x)}[/tex]
[tex]\lim_{x \to \frac{\pi}{2}}\frac{sin(x)}{cos(x)}[/tex]
[tex]\lim_{x \to \frac{\pi}{2}}tan(x)}[/tex]
Since, tangent function approaches -∞ as x approaches to [tex]\frac{\pi}{2}[/tex]
, therefore, the original expression does the same thing.
Hence, the limit of the function at x approaches to [tex]\frac{\pi}{2}[/tex] is [tex]-\infty[/tex].
The function cos(x)/(1-sin(x)) approaches an indeterminate form as x approaches π/2 from the right. By applying L'Hopital's Rule, we find that the limit is equivalent to the limit of tan(x) as x approaches π/2 from the right. However, tan(π/2) is undefined, so the limit does not exist.
Explanation:In this question, we are asked to find the limit of the function cos(x)/(1-sin(x)) as x approaches π/2 from the right. We can't directly substitute x = π/2 because it makes the denominator zero, yielding an indeterminate form of '0/0'.
So, we use L'Hopital's Rule, which states that the limit of a ratio of two functions as x approaches a particular value is equal to the limit of their derivatives.
The derivative of cos(x) is -sin(x) and the derivative of (1-sin(x)) is -cos(x). Using L'Hopital's Rule, we can now re-evaluate our limit substituting these derivatives.
lim [x → (π/2)+] (-sin(x)/-cos(x)) = lim [x → (π/2)+] tan(x)
When substituting x = π/2 into tan(x), we realize that the tan(π/2) is undefined, so the answer is the limit does not exist.
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Which of the following is a solution of 4x + 5y ≤ 20?
A. (5, 7)
B. (1, 1)
C. (0, 5)
D. (8, 0)
Answer:
B.
Step-by-step explanation:
Plug in and see:
Let's try the first (x,y)=(5,7)
4(5)+5(7) <=20
20+35<=20 not true so not A
Let's try (1,1) for (x,y)
4(1)+5(1)<=20
4+5<=20 that is true so choice B looks good
For this case we must replace each of the points and verify if the inequality is met:
Point: (5,7)
[tex]4 (5) +5 (7) \leq20\\20 + 35 \leq20[/tex]
It is not fulfilled!
Point: (1,1)
[tex]4 (1) +5 (1) \leq20\\9 \leq20[/tex]
Is fulfilled!
Point: (0,5)
[tex]4 (0) +5 (5) \leq20\\0 + 25 \leq20[/tex]
It is not fulfilled!
Point: (8,0)
[tex]4 (8) +5 (0) \leq20\\32 \leq20[/tex]
It is not fulfilled!
Answer:
(1,1)
The Pew Internet and American Life Project finds that 95% of teenagers (12–17) use the Internet and that 81% of online teens use some kind of social media. Of online teens who use some kind of social media, 91% have posted a photo of themselves. STATE: What percent of all teens are online, use social media, and have posted a photo of themselves?
The percent of all teens are online, use social media, and have posted a photo of themselves are:
70% (approx)
Step-by-step explanation:It is given that:
95% of teenagers use the Internet this means that the teens are online.
This means that 95%=0.95.
and 81% of online teens use some kind of social media.
i.e. 81%=0.81
and Of online teens who use some kind of social media, 91% have posted a photo of themselves.
i.e. 91%=0.91
Now we are asked to find the percent of teens who are online, use social media, and have posted a photo of themselves
i.e. The percent is: (0.95×0.81×0.91)×100
= 70.0245%
which is approximately equal to 70%
Answer:
The percent of all teens are online, use social media, and have posted a photo of themselves 70% (approx)
Step-by-step explanation:
Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a standard deviation of 1800 hours and a mean life span of 20,000 hours. If a monitor is selected at random, find the probability that the life span of the monitor will be more than 17,659 hours. Round your answer to four decimal places.
Answer: 0.9032
Step-by-step explanation:
Given: Mean : [tex]\mu = 20,000\text{ hours}[/tex]
Standard deviation : [tex]\sigma = 1800 \text{ hours}[/tex]
The formula to calculate z is given by :-
[tex]z=\dfrac{x-\mu}{\sigma}[/tex]
For x= 17659
[tex]z=\dfrac{17659-20000}{1800}=−1.30055555556\approx-1.3[/tex]
The P Value =[tex]P(z>-1.5)=1-P(z<1.3)=1- 0.0968005\approx0.9031995\approx 0.9032[/tex]
Hence, the probability that the life span of the monitor will be more than 17,659 hours = 0.9032
To find the probability that the life span of the monitor will be more than 17,659 hours, use the z-score formula and the standard normal distribution table. The probability is approximately 0.0968.
Explanation:To find the probability that the life span of the monitor will be more than 17,659 hours, we need to calculate the z-score and use the standard normal distribution table. The z-score is calculated as:
z = (x - μ) / σ
Where x is the value we want to find the probability for, μ is the mean, and σ is the standard deviation. In this case, x = 17,659, μ = 20,000, and σ = 1800. Plugging these values into the formula, we get:
z = (17659 - 20000) / 1800 = -1.3
Now, we can look up the probability corresponding to the z-score -1.3 in the standard normal distribution table. The probability is approximately 0.0968. Therefore, the probability that the life span of the monitor will be more than 17,659 hours is approximately 0.0968.
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i need geometry help pleas will give brainliest
Area of the shaded segment=
6π-9√3un^2
12π-9√3un^2
9π-9√3un^2
Answer:
6π - 9√3 unit^2
Step-by-step explanation:
Area of sector
= 1/6(π (6)^2
= 6π
Area of triangle = √3/4 (6)^2 = 9√3
Area of the shaded segment = Area of sector - Area of triangle
= 6π - 9√3 unit^2
to the risk of sounding redundant.
[tex]\bf \textit{area of a segment of a circle}\\\\ A=\cfrac{r^2}{2}\left(\cfrac{\pi \theta }{180}-sin(\theta ) \right)~~ \begin{cases} r=&radius\\ \theta =&angle~in\\ °rees\\ \cline{1-2} r=&6\\ \theta =&60 \end{cases}\implies A=\cfrac{6^2}{2}\left(\cfrac{\pi 60}{180}-sin(60^o ) \right) \\\\\\ A=18\left( \cfrac{\pi }{3}-\cfrac{\sqrt{3}}{2} \right)\implies \boxed{A=6\pi -9\sqrt{3}}\implies \implies A\approx 3.26[/tex]
How to integrate with steps:
(4x2-6)/(x+5)(x-2)(3x-1)
[tex]\displaystyle\int\frac{4x^2-6}{(x+5)(x-2)(3x-1)}\,\mathrm dx[/tex]
You have a rational expression whose numerator's degree is smaller than the denominator's. This tells you you should consider a partial fraction decomposition. We want to rewrite the integrand in the form
[tex]\dfrac{4x^2-6}{(x+5)(x-2)(3x-1)}=\dfrac a{x+5}+\dfrac b{x-2}+\dfrac c{3x-1}[/tex]
[tex]\implies4x^2-6=a(x-2)(3x-1)+b(x+5)(3x-1)+c(x+5)(x-2)[/tex]
You can use the "cover-up" method here to easily solve for [tex]a,b,c[/tex]. It involves fixing a value of [tex]x[/tex] to make 2 of the 3 terms on the right side disappear and leaving a simple algebraic equation to solve for the remaining one.
If [tex]x=-5[/tex], then [tex]94=112a\implies a=\dfrac{47}{56}[/tex]If [tex]x=2[/tex], then [tex]10=35b\implies b=\dfrac27[/tex]If [tex]x=\dfrac13[/tex], then [tex]-\dfrac{50}9=-\dfrac{80}9c\implies c=\dfrac58[/tex]So the integral we want to compute is the same as
[tex]\displaystyle\frac{47}{56}\int\frac{\mathrm dx}{x+5}+\frac{10}{35}\int\frac{\mathrm dx}{x-2}+\frac58\int\frac{\mathrm dx}{3x-1}[/tex]
and each integral here is trivial. We end up with
[tex]\displaystyle\int\frac{4x^2-6}{(x+5)(x-2)(3x-1)}\,\mathrm dx=\frac{47}{56}\ln|x+5|+\frac27\ln|x-2|+\frac5{24}\ln|3x-1|+C[/tex]
which can be condensed as
[tex]\ln\left|(x+5)^{47/56}(x-2)^{2/7}(3x-1)^{5/24}\right|+C[/tex]
Solve the following problem. PV=$24,122; n = 70; i = 0.024; PMT ?; PMT = $ (Round to two decimal places.)
Answer:
The payment per period is $714.82.
Step-by-step explanation:
Given information: PV=$24,122; n = 70; i = 0.024
The formula for payment per period is
[tex]PMT=\frac{PV\times i}{1-(1+i)^{-n}}[/tex]
Substitute PV=$24,122; n = 70; i = 0.024 in the above formula.
[tex]PMT=\frac{24122\times 0.024}{1-(1+0.024)^{-70}}[/tex]
[tex]PMT=\frac{578.928}{0.80989084337}[/tex]
[tex]PMT=714.822256282[/tex]
[tex]PMT\approx 714.82[/tex]
Therefore the payment per period is $714.82.
You want to endow a scholarship that will pay $10,000 per year forever, starting one year from now. If the school’s endowment discount rate is 7%, what amount must you donate to endow the scholarship? 13. How would your answer to Problem 12 change if you endow it now, but it makes the first award to a student 10 years from today?
Answer:
12. $142,857.14
13. $77,704.82 . . . it is changed by the accumulated interest on the amount
Step-by-step explanation:
12. You want one year's interest on the endowment to be equal to $10,000. The principal (P) can be found by ...
I = Prt
10,000 = P·0.07·1
10,000/0.07 = P ≈ 142,857.14
The endowment must be $142,857.14 to pay $10,000 in interest annually forever.
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13. If the first award is in 10 years, we want the above amount to be the value of an account that has paid 7% interest compounded annually for 9 years. (The first award is 1 year after this amount is achieved.) Then we want the principal (P) to be ...
142,857.14 = P·(1 +0.07)^9
142,57.14/1.07^9 = P = 77,704.82
The endowment needs to be only $77,704.82 if the first award is made 10 years after the endowment date.
The initial amount required for endowment yielding $10,000 annually in perpetuity with a discount rate of 7% is $142,857.14. If the first payment is postponed to 10 years later, the present value of this amount is $72,975.85.
Explanation:The question pertains to figuring out the initial amount needed to fund an endowment that would yield $10,000 annually, indefinitely, given a discount rate of 7%. This is a case for the use of perpetuity, a financial concept in which an infinite amount of identical cash flows occur continually. The formula for perpetuity is: Perpetuity = Cash flow / Discount rate. Thus, in this case, the amount to endow is $10,000 / 0.07 = $142,857.14.
For the second part of the question, if the first award will be given 10 years from today, the present value of the perpetuity needs to be factored in. The present value of a perpetuity starting at a future point is: Present Value of Perpetuity = Perpetuity / (1 + r)^n where 'r' is the discount rate and 'n' is the number of periods before the perpetuity starts. Here, it will be $142,857.14 / (1 + 7%)^10 = $72,975.85
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A test consists of 10 multiple choice questions, each with 5 possible answers, one of which is correct. To pass the test a student must get 60% or better on the test. If a student randomly guesses, what is the probability that the student will pass the test?
Try this option:
if only one answer of five is correct, it means, the probability to choose it P=1/5=0.2.
If the student guesses randomly, it means, using the probability 0.2, he(she) can choose only 10*0.2=2 correct answers. To pass the test, the student must get 0.6*10=6 correct answers or more.
Use the ratio test to determine whether ∑n=14∞n+2n! converges or diverges. (a) Find the ratio of successive terms. Write your answer as a fully simplified fraction. For n≥14, limn→∞∣∣∣an+1an∣∣∣=limn→∞.
Answer:
The sum [tex]\displaystyle \sum^{\infty}_{n = 14} n + 2n![/tex] diverges ∵ of the Ratio Test.
General Formulas and Concepts:
Calculus
Limits
Limit Rule [Variable Direct Substitution]: [tex]\displaystyle \lim_{x \to c} x = c[/tex]Special Limit Rule [Coefficient Power Method]: [tex]\displaystyle \lim_{x \to \pm \infty} \frac{ax^n}{bx^n} = \frac{a}{b}[/tex]Series Convergence Tests
Ratio Test: [tex]\displaystyle \lim_{n \to \infty} \bigg| \frac{a_{n + 1}}{a_n} \bigg|[/tex]Step-by-step explanation:
Step 1: Define
Identify.
[tex]\displaystyle \sum^{\infty}_{n = 14} n + 2n![/tex]
Step 2: Find Convergence
[Series] Define: [tex]\displaystyle a_n = n + 2n![/tex][Series] Set up [Ratio Test]: [tex]\displaystyle \sum^{\infty}_{n = 14} n + 2n! \rightarrow \lim_{n \to \infty} \bigg| \frac{n + 1 + 2(n + 1)!}{n + 2n!} \bigg|[/tex][Ratio Test] Evaluate Limit [Coefficient Power Method]: [tex]\displaystyle \lim_{n \to \infty} \bigg| \frac{n + 1 + 2(n + 1)!}{n + 2n!} \bigg| = \infty[/tex][Ratio Test] Define conclusiveness: [tex]\displaystyle \infty > 1[/tex]Since infinity is greater than 1, the Ratio Test defines the sum [tex]\displaystyle \sum^{\infty}_{n = 14} n + 2n![/tex] to be divergent.
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Topic: AP Calculus BC (Calculus I + II)
Unit: Taylor Series
Which is an equation of a circle with center ( -5, -7) that passes through the point ( 0, 0 ) brainly
Answer:
(x+5)^2+(y+7)^2=74
Step-by-step explanation:
So we are given this (x+5)^2+(y+7)^2=r^2
We need to find r so just plug in your point (0,0) for (x,y) and solve for r :)
(0+5)^2+(0+7)^2=r^2
25+49=r^2
74=r^2
So the answer is (x+5)^2+(y+7)^2=74
Answer:
(x+5)^2+(y+7)^2=74
Step-by-step explanation:
Find a parametrization for the curve「and determine the work done on a particle moving along Γ in R3 through the force field F:R^3--R^3'where F(x,y,z) = (1,-x,z) and (a) Im (Γ) is the line segment from (0,0,0) to (1,2,1) (b) Im (Γ) is the polygonal curve with successive vertices (1,0,0), (0,1,1), and (2,2,2) (c) Im (Γ) is the unit circle in the plane z = 1 with center (0,0,1) beginning and ending at (1,0,1), and starting towards (0,1,1)
a. Parameterize [tex]\Gamma[/tex] by
[tex]\vec r(t)=(t,2t,t)[/tex]
with [tex]0\le t\le1[/tex]. The work done by [tex]\vec F[/tex] along [tex]\Gamma[/tex] is
[tex]\displaystyle\int_\Gamma\vec F\cdot\mathrm d\vec r=\int_0^1(1,-t,t)\cdot(1,2,1)\,\mathrm dt=\int_0^1(1-t)\,\mathrm dt=\boxed{\frac12}[/tex]
b. Break up [tex]\Gamma[/tex] into each component line segment, denoting them by [tex]\Gamma_1[/tex] and [tex]\Gamma_2[/tex], and parameterize each respectively by
[tex]\vec r_1(t)=(1-t,t,t)[/tex] and[tex]\vec r_2(t)=(2t,1+t,1+t)[/tex]both with [tex]0\le t\le1[/tex]. Then the work done by [tex]\vec F[/tex] along each component path is
[tex]\displaystyle\int_{\Gamma_1}\vec F\cdot\mathrm d\vec r_1=\int_0^1(1,t-1,t)\cdot(-1,1,1)\,\mathrm dt=\int_0^1(2t-2)\,\mathrm dt=-1[/tex]
[tex]\displaystyle\int_{\Gamma_2}\vec F\cdot\mathrm d\vec r_2=\int_0^1(1,-2t,1+t)\cdot(2,1,1)\,\mathrm dt=\int_0^1(3-t)\,\mathrm dt=\frac52[/tex]
giving a total work done of [tex]-1+\dfrac52=\boxed{\dfrac32}[/tex].
c. Parameterize [tex]\Gamma[/tex] by
[tex]\vec r(t)=(\cos t,\sin t,1)[/tex]
with [tex]0\le t\le2\pi[/tex]. Then the work done by [tex]\vec F[/tex] is
[tex]\displaystyle\int_\Gamma\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}(1,-\cos t,1)\cdot(-\sin t,\cos t,0)\,\mathrm dr=-\int_0^{2\pi}(\sin t+\cos^2t)\,\mathrm dt=\boxed{-\pi}[/tex]
Solve the following system of equations
3x - 2y =55
-2x - 3y = 14
Answer:
The solution is:
[tex](\frac{137}{13}, -\frac{152}{13})[/tex]
Step-by-step explanation:
We have the following equations
[tex]3x - 2y =55[/tex]
[tex]-2x - 3y = 14[/tex]
To solve the system multiply by [tex]\frac{3}{2}[/tex] the second equation and add it to the first equation
[tex]-2*\frac{3}{2}x - 3\frac{3}{2}y = 14\frac{3}{2}[/tex]
[tex]-3x - \frac{9}{2}y = 21[/tex]
[tex]3x - 2y =55[/tex]
---------------------------------------
[tex]-\frac{13}{2}y=76[/tex]
[tex]y=-76*\frac{2}{13}[/tex]
[tex]y=-\frac{152}{13}[/tex]
Now substitute the value of y in any of the two equations and solve for x
[tex]-2x - 3(-\frac{152}{13}) = 14[/tex]
[tex]-2x +\frac{456}{13} = 14[/tex]
[tex]-2x= 14-\frac{456}{13}[/tex]
[tex]-2x=-\frac{274}{13}[/tex]
[tex]x=\frac{137}{13}[/tex]
The solution is:
[tex](\frac{137}{13}, -\frac{152}{13})[/tex]
Answer:
x = 411/39 and y = -152/13
Step-by-step explanation:
It is given that,
3x - 2y = 55 ----(1)
-2x - 3y = 14 ---(2)
To find the solution of given equations
eq(1) * 2 ⇒
6x - 4y = 110 ---(3)
eq(2) * 3 ⇒
-6x - 9y = 42 ---(4)
eq(3) + eq(4) ⇒
6x - 4y = 110 ---(3)
-6x - 9y = 42 ---(4)
0 - 13y = 152
y = -152/13
Substitute the value of y in eq (1)
3x - 2y = 55 ----(1)
3x - 2*(-152/13) = 55
3x + 304/13 = 55
3x = 411/13
x = 411/39
Therefore x = 411/39 and y = -152/13
1) Find the lump that must be deposited today to have a future value of $ 25,000 in 5 years if funds earn 6 % componded annually.
Answer: $ 18681.45
Step-by-step explanation:
Given: Future value : [tex]FV=\$25,000[/tex]
The rate of interest : [tex]r=0.06[/tex]
The number of time period : [tex]t=5[/tex]
The formula to calculate the future value is given by :-
[tex]\text{Future value}=P(1+i)^n[/tex], where P is the initial amount deposited.
[tex]\Rightarrow\ 25000=P(1+0.06)^5\\\\\Rightarrow\ P=\dfrac{25000}{(1.06)^5}\\\\\Rightarrow\ P=18681.4543217\approx=18681.45[/tex]
Hence, the lump that must be deposit today : $ 18681.45