Answer:
Following are the program in the Python Programming Language.
# Define the function
def Sum(tu):
# Check if the tuple contain 0
if len(tu)==0:
#Then, Return 0
return 0
#Otherwise
else:
#call the recursive function
return tu[0]+Sum(tu[1:])
#Set tuple type variable
tu=(2,5,1,8,10)
#print and call the function
print("The sum of tuple is:",Sum(tu))
Output:
The sum of tuple is: 26
Explanation:
Here, we define a function "sum()" and pass an argument "tu" which stores the tuple type value, inside the function.
Set the if conditional statement to check condition is the length of the tuple is 0 then, return 0.Otherwise, call and return the sum of the tuple which is recursively calculated and close the function.Finally, set the tuple type variable "tu" and initialize the value in it then, print and call the function sum.
Final answer:
A recursive function in Python can be written to calculate the sum of the elements of a tuple by adding the first element to the sum of the remaining elements until an empty tuple is reached, which has a sum of 0.
Explanation:
In Python, tuples are immutable sequences of elements, typically used to store collections of heterogeneous data. A recursive function for summing the elements of a tuple can be defined by considering the base case of an empty tuple having a sum of 0. If the tuple is not empty, the sum is computed by adding the first element of the tuple to the sum of the remaining tuple elements.
The recursive function defined below takes a tuple as an argument and calculates the sum of its elements:
def sum_of_elements(a_tuple):
if not a_tuple: # Base case: empty tuple
return 0
else:
return a_tuple[0] + sum_of_elements(a_tuple[1:]) # Recursive case
This recursive approach is an example of how tuples can be processed in Python. It leverages the fact that tuples can be indexed and sliced, and we are able to recursively reduce the problem size by considering the tuple without its first element.
Modern operating systems support multitasking by doing what?A) Keeping pending jobs available in memory as processesB) Sharing input and output devices between usersC) Distributing tasks as threadsD) Using hard disk space as an extension of memory
Answer:
Option A is the correct answer to the following question.
Explanation:
Because multitasking is the process of an operating system in which provides users to accomplish more than one jobs at the same time, for example, we can listen music with creating documents in word such as we can do multiple jobs at a time by which we can save much more time to do other works. So, that's why the following option is correct.
1. Please write the following code in Python 3.2. Please also show all outputs.Create a dictionary named letter_counts that contains each letter and the number of times it occurs in string1. Challenge: Letters should not be counted separately as upper-case and lower-case. Intead, all of them should be counted as lower-case.string1 = "There is a tide in the affairs of men, Which taken at the flood, leads on to fortune. Omitted, all the voyage of their life is bound in shallows and in miseries. On such a full sea are we now afloat. And we must take the current when it serves, or lose our ventures."
Answer:
string1="There is a tide in the affairs of men, Which taken at the flood, leads on to fortune. Omitted, all the voyage of their life is bound in shallows and in miseries. On such a full sea are we now afloat. And we must take the current when it serves, or lose our ventures."
string1=string1.lower() #covert whole string to lowercase
letter_counts={}
for ch in string1:
letter_counts[ch]=letter_counts.get(ch,0)+1 #updates counter for each letter
letter_counts['o']
OUTPUT :
17
Explanation:
lower() is used to change the string to lowercase characters so that uppercase and lowercase is not differentiated for the same letter. After that, letter_counts is declared as a dictionary which is empty. for loop is used in which every letter of string will be stored ch variable. Dictionary in python has a get method in which 2 arguments can be passed, first one is the key whose value to be retrieved and the other argument would be default value to be set if not found and ch in string1 will increment the value of key ch in letter_counts.
Which components can be added to a lightning app on custom object (choose 3 answers)A. Visualforce B. Standard Lightning component C. Custom lightning component D. global actions E. object specific actions on the custom object
Answer:
b. Standard Lightning component.
c. Custom Lightning component.
d. Global actions
These three components are best used in a ligthening app, for custom object i.e standard, Custom and Global Actions.
Adding Visualforce components to a Lightning Application is impossible, but one can add Lightning components into Visualforce pages.
Recall the problem of finding the number of inversions. As in the text, we are given a sequence of numbers a1, . . . , an, which we assume are all distinct, and we define an inversion to be a pair i < j such that aj < ai . We motivated the problem of counting inversions as a good measure of how different two orderings are. However, one might feel that this measure is too sensitive. Lets call a pair a significant inversion if i < j and 2aj < ai .
(a) Describe a O(n log n) algorithm to count the number of significant inversions between two orderings. Make clear how is it that your algorithm would achieve the given O(n log n) execution time bound.
Answer:
The algorithm is very similar to that of counting inversions. The only change is that here we separate the counting of significant inversions from the merge-sort process.
Explanation:
Algorithm:
Let A = (a1, a2, . . . , an).
Function CountSigInv(A[1...n])
if n = 1 return 0; //base case
Let L := A[1...floor(n/2)]; // Get the first half of A
Let R := A[floor(n/2)+1...n]; // Get the second half of A
//Recurse on L. Return B, the sorted L,
//and x, the number of significant inversions in $L$
Let B, x := CountSigInv(L);
Let C, y := CountSigInv(R); //Do the counting of significant split inversions
Let i := 1;
Let j := 1;
Let z := 0;
// to count the number of significant split inversions while(i <= length(B) and j <= length(C)) if(B[i] > 2*C[j]) z += length(B)-i+1; j += 1; else i += 1;
//the normal merge-sort process i := 1; j := 1;
//the sorted A to be output Let D[1...n] be an array of length n, and every entry is initialized with 0; for k = 1 to n if B[i] < C[j] D[k] = B[i]; i += 1; else D[k] = C[j]; j += 1; return D, (x + y + z);
Runtime Analysis: At each level, both the counting of significant split inversions and the normal merge-sort process take O(n) time, because we take a linear scan in both cases. Also, at each level, we break the problem into two subproblems and the size of each subproblem is n/2. Hence, the recurrence relation is T(n) = 2T(n/2) + O(n). So in total, the time complexity is O(n log n).
Correctness Proof: We will prove a stronger statement that on any input A our algorithm produces correctly the sorted version of A and the number of significant inversions in A. And, we will prove it by induction. Base Case: When n = 1, the algorithm returns 0, which is obviously correct.
Inductive Case: Suppose that the algorithm works correctly for 1, 2, . . . , n − 1. We have to show that the algorithm also works for n. By the induction hypothesis, B, x, C, y are correct. We need to show that the counting of significant split inversions and the normal merge-sort process are both correct. In other words, we are to show that z is the correct number of significant split inversions, and that D is correctly sorted.
First, we prove that z is correct. Due to the fact that B and C are both sorted by the induction hypothesis, for every C[j], where j = 1, . . . , length(C), we can always find the smallest i such that B[i] > 2C[j]. Therefore, B[1], B[2], . . . , B[i − 1] are all smaller than or equal to 2C[j], and B[i], B[i + 1], . . . , B[length(B)] are all greater than 2C[j]. Thus, length(B) − i + 1 is the correct significant split inversion count for pairs involving C[j]. After counting the number of correct significant split inversions for all C[j], where j = 1, . . . , length(C), z is the correct number of significant split inversions. Second, we show that D is the sorted version of A.
This is actually the proof of merge-sort. Each time, we append one element from B or C to D. At each iteration k, since B and C are both sorted by the induction hypothesis, min(B[i], C[j]), the one to be appended to D, is also the smallest number among all the numbers that have not been added to D yet.
As a result, every time we append the smallest remaining element (of B and C) to D, which makes D a sorted array
Design and code a program including the following classes, as well as a client class to test all the methods coded:A Passenger class, encapsulating a passenger. A passenger has two attributes: a name, and a class of service, which will be 1 or 2.A Train class, encapsulating a train of passengers. A train of passengers has one attribute: a list of passengers, which must be represented with an ArrayList. Your constructor will build the list of passengers by reading data from a file called passengers.txt. You can assume that passengers.txt has the following format:...For instance, the file could contain:James 1Ben 2Suri 1Sarah 1Jane 2...You should include the following methods in your Train class:
a method returning the percentage of passengers traveling in first class
a method taking two parameters representing the price of traveling in first and second class and returning the total revenue for the train
a method checking if a certain person is on the train; if he/she is, the method returns true; otherwise, it returns false
Answer:
Code given below
Explanation:
/*
* Class to hold the Passenger data
* Stores the name and classOfService
* */
public class Passenger {
String name;
int classOfService;
public Passenger(String string, int classOfService) {
this.name = string;
this.classOfService = classOfService;
}
@Override
public String toString() {
return "Passenger [name=" + name + ", classOfService=" + classOfService
+ "]";
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + classOfService;
result = prime * result + ((name == null) ? 0 : name.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Passenger other = (Passenger) obj;
if (classOfService != other.classOfService)
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
return true;
}
public String getName() {
return name;
}
public int getClassOfService() {
return classOfService;
}
}
----
import java.util.ArrayList;
import java.util.List;
/* Train class for holding the
* passengerList.
* The passengerList is the list of Passenger Object
*/
public class Train {
List<Passenger> passengerList;
public Train() {
passengerList = new ArrayList<Passenger>();
}
public Passenger getPassenger(int index) {
if (index <= 0 && getTotalNumberOfPassengersOnBoard() < index) {
return null;
} else {
return passengerList.get(index - 1);
}
}
public void addPassenger(Passenger p) {
passengerList.add(p);
}
public int getTotalNumberOfPassengersOnBoard() {
return passengerList.size();
}
public boolean isPassengerOnBoard(String name) {
boolean flag= false;
for (Passenger p : passengerList) {
if (p.getName().equalsIgnoreCase(name)) {
flag = true;
break;
} else {
flag = false;
}
}
return flag;
}
public double getRevenue(double priceFirstClass, double priceSecondClass) {
double total = 0.0;
for (Passenger p : passengerList) {
if (p.getClassOfService() == 1) {
total += priceFirstClass;
} else {
total += priceSecondClass;
}
}
return total;
}
public double getPercentageFirstClassTravellers() {
double count = 0.0;
for (Passenger p : passengerList) {
if (p.getClassOfService() == 1) {
count++;
}
}
return count / getTotalNumberOfPassengersOnBoard() * 100;
}
@Override
public String toString() {
return "Train [passengerList=" + passengerList + "]";
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result
+ ((passengerList == null) ? 0 : passengerList.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Train other = (Train) obj;
if (passengerList == null) {
if (other.passengerList != null)
return false;
} else if (!passengerList.equals(other.passengerList))
return false;
return true;
}
}
-----------
public class TrainTest {
public static void main(String[] args) {
Train t = new Train();
Passenger p1 = new Passenger("James", 1);
Passenger p2 = new Passenger("Sarah", 2);
Passenger p3 = new Passenger("Jhon", 1);
Passenger p4 = new Passenger("Test", 2);
// add other passengers Test1 .. Test6
for (int j = 1; j < 7; j++) {
t.addPassenger(new Passenger("Test" + j, j % 2));
}
t.addPassenger(p1);
t.addPassenger(p2);
t.addPassenger(p3);
t.addPassenger(p4);
System.out.println("total revenue $" + t.getRevenue(10.0, 25.0));
System.out.println("total number of passengers on Board .. "
+ t.getTotalNumberOfPassengersOnBoard());
System.out.println("percentage of first class traveller .. "
+ t.getPercentageFirstClassTravellers());
System.out.println("getPassenger number # 2 .. " + t.getPassenger(2));
System.out.println("is passenger Jhon on board ? "
+ t.isPassengerOnBoard("Jhon"));
System.out.println("is passenger Dummy on board ? "
+ t.isPassengerOnBoard("Dummy"));
System.out.println("Printing all the Passengers on Board ...");
for (int i = 1; i <= t.getTotalNumberOfPassengersOnBoard(); i++) {
System.out.println("" + t.getPassenger(i));
}
// using the the Train toString to print all the passengers from Train
System.out.println(t.toString());
}
}
Universal containers wants to rollout new product bundles with several pricing options. Pricing options include product-price bundles, account specific pricing and more. Which product satisfies the needs:
A. Custom AppExchange-app for product-pricingB. Workflow on Opportunity/Opportunity ProductC. Formula fields on Opportunity/Opportunity ProductD. Lightning process builder
Answer:
a) Custom AppExchange-app for product-pricing
Explanation:
We can find a solution in AppExchange for this product-pricing, surfing in the option, we could get solutions like BoonPlus, and easy pricing Opportunity, this App has a free trial.
With this option is easy to choose a book price, add new products, select pricing rule, we can get an order's product, and calculate pricing, just we must download the app and install it.
To direct a style rule to specific elements, __________ can be used to match only those page elements that correspond to a specified pattern.
Question 2 options:
a)
web fonts
b)
pseudo-classes
c)
descendant elements
d)
selector patterns
Answer:
d) selector patterns
Explanation:
To apply and create rules to elements in the same class, selector patterns are a simple solution to make the task easier.
Selector patterns allow you to have a set of rules, tools already tested, which allow you to solve most problems directly.
To direct a style rule to specific elements, selector patterns are used. Selectors can be a tag, class, or ID and are specified at the start of a CSS rule followed by curly braces containing the style declarations.
Using Selectors in CSS
To direct a style rule to specific elements, selector patterns can be used to match only those page elements that correspond to a specified pattern. The selector is the first part of a CSS rule that identifies the HTML elements the subsequent styles will apply. It can reference an HTML tag directly, or it can be a custom class, ID or even a combination of selectors for more specificity. Once you specify a selector, you can define styles inside the curly braces {} that follow.
For example, using a descendant selector like .completed ul, you can target all <ul> elements within an element with the class .completed, and apply a specific style such as text-decoration: line-through; to them. This type of specificity ensures that styles are applied precisely to the elements intended. The colon (:) is used in CSS to assign values rather than an equal sign, which is typical in many programming languages.
When defining classes in our CSS file, we precede the name with a period to indicate it is a class and use the class attribute within the HTML document to apply it to elements. Classes allow us to apply different styles to the same type of elements, enhancing the page's design and user experience.
UC is importing 1000 records and want to avoid duplicate, how can they do it?
Answer:
By unchecking the 'allow duplicate' box and checking the 'Block duplicate' box in the SalesForce user interface. More also, including a column in the import file that has other record name(SF ID) will ensure no duplicate during import.
Explanation:
importing 1000 records is quiet lengthy and to avoid duplicate it is important to include in the import file that has other record name(SF ID). By including a column that has another file ID every record will be referenced uniquely thereby easily identifying any duplicate.
It is also important to check the ''Block duplicate' box in the salesForce user interface to ensure that records are imported without duplicate.
A company purchased a high-quality color laser printer to print color brochures and sales proposals. The printer is connected to a marketing PC via USB and is configured as a shared local printer for use by the sales and marketing teams. The manager is concerned about the cost of consumables for the printer and does not want users to unintentionally print to the printer. What can be done to ensure that only authorized users can send print jobs to the printer?
Answer:
In order to ensure that only authorized users can send print jobs to the printer, the option of enabling the user authentication on shared printer can be used.
Explanation:
The manager can create user Id and password only for those people who have the permission to send the printer jobs to the printer. In this way, whenever a command is given to the printer, it will ask the user credentials before doing the printing job. If the person is unable to give the credentials then the printing will not start. Moreover, it will decrease the probability of the printing unintentionally so it will save the resources from wastage.Describe how your leadership and service has made a positive difference in your school, inyour community, in your family and/or on the job, and how it will continue to make adifference in college and beyond.
I could describe my leadership and service as being motivational and more a credit-giver.
I do not own the credit for every successful task that my team has accomplished. In fact, I am giving them all the recognitions they deserved. In times of struggling and great pressure, I would motivate them. Most of their complaints about my leadership method is I do not give importance to time. I normally tend to finish everything before deadlines. With these attitudes, my family learn to adapt to this behavior. They value ideas and teamworks in their respective workplace and like me, they would also hate to submit their works late. They would sometimes get positive feedback from clients for finishing their assigned tasks on time.
A penetration tester has been tasked with reconnaissance to determine which ports are open on the network. Which of the following tasks should be done FIRST? (Choose two)
A. Network scan
B. Banner grab
C. Tracert
D. DHCP server check
E. Brute-force attack
Network scan and banner grab are the following tasks should be done FIRST.
A. Network scan
B. Banner grab
Explanation:
The penetration tester has been assigned a task to determine which ports are open on the given network.
To kick start the process, the tester should give a network scan in order to gather information about the various elements of the network and their details.
To follow up, the tester should proceed with banner grab. Banner grabbing is the process through which he/she would gain information about a computer system on the network and services running on its open ports.
Enter a formula in cell E4 to calculate how long each item has been on sale. This is calculated by subtracting the launch date in cell D4 from the Data Updated date in cell C20. To show the time in years, divide that result by 365. Use an absolute reference to the date in cell C20. Copy the formula from cell E4 to cells E5:E14.
In D4 is 3/17/2013
In C20 is 10/14/2016
Any help? I have no idea what function is needed for this.
Final answer:
In Excel, to calculate the time an item has been on sale, use the formula =($C$20-D4)/365 in cell E4 and copy it down to E5:E14. This formula subtracts the launch date from the Data Updated date and converts the result to years using an absolute reference for the Data Updated date.
Explanation:
To calculate how long each item has been on sale in an Excel spreadsheet, you would subtract the launch date in cell D4 from the Data Updated date in cell C20 and then divide by 365 to convert the difference to years. Since cell C20 should not change when you copy the formula, you need to use an absolute reference for this cell.
The formula in cell E4 will be =($C$20-D4)/365. This formula uses the absolute reference $C$20 to ensure that as you copy the formula from cell E4 to cells E5:E14, the reference to C20 remains constant.
After entering the formula in E4, you would then copy it down to the cells E5 through E14. The result will show you the time each item has been on sale in years.
Which two security measures must an engineer follow then implementing Layer 2 and Layer 3 network design?
A.Utilize the native VLAN only on trunk ports to reduce the risk of an Double-Tagged 802.1q VLAN hopping attack
B.Utilize an access list to prevent the use of ARP to modify entries to the table
C.Utilize DHCP snooping on a per VLAN basis an apply ip dhcp snooping untrusted on all ports
D.Utilize the ARP inspection feature to help prevent the misuse of gARPE.Utilize private VLANs an ensure that all ports are part of the isolated port group
Answer:
A. Utilize the native VLAN only on trunk ports to reduce the risk of a Double-Tagged 802 1q VLAN hopping attack
C. Utilize DHCP snooping on a per VLAN basis an apply IP DHCP snooping entrusted on all ports.
D. Utilize the ARP inspection feature to help prevent the misuse of garpe Utilize private VLANs an ensure that all ports are part of the isolated port group.
Explanation:
We must configure the native VLAN only on trunk ports because in this way we are not to receive fake VLAN, and can steal information.
We can use DHCP snooping to configure trusted ports and entrusted ports, in this case, the trusted port can accept trust messages, only with those messages we can connect with the server.
We could ask the MAC address with ARP inspections, MAC address is unique value for a physical hardware in the world.
A physical switch port is part of an EtherChannel group. What happens while the same port is configured as a SPAN destination?
A. The port forwards traffic in the EtherChannel group and acts as a SPAN source simultaneously
B. The operation is not allowed as an EtherChannel member cannot be a SPAN source port
C. The port is put in the errdisabled state and can only be reenabled manually
D. The port is removed from the EtherChannel group
Answer:
D. The port is removed from the EtherChannel group.
Explanation:
The configuration SPAN is when we copy traffic, and we transfer that traffic to another port, in this case, we can analyze that traffic in our benefit.
If a physical port belongs to the EtherChannel group, it can be configured as a SPAN source port and still be a part of the EtherChannel.
But a physical port cannot be configured as a SPAN destination and belong to the EtherChannel group.
This means we can be the SPAN source but not the SPAN destination.
This assignment is to code a simple hangman game. The game should choose a random word out of a list of words that are coded into the program and ask for guesses. You should include a total of 20 words, lengths ranging from 4 to 12 letters long . Each time a person guesses wrong, it should decrement the total number of guesses (5 incorrect guesses allowed, on the 6th incorrect guess the game ends with a loss). When the user guesses the word or if they lose, they have the option of playing again. The expected output should be text based.
Answer:
Programming language not stated.
I'll use python for this question
Explanation:
import random
# library that we use in order to choose
# on random words from a list of words
words = ['rain, 'computer', 'science', 'program, 'python', 'mathematics', 'player', 'condition','reverse', 'water', 'board', 'geeks','learn','school','days','scholar','collar','flood','house','flies']
# Function will choose one random word from this list of words
word = random.choice(words)
print("Guess the word")
guesses = ''"
# 5 turns
turns = 5
while turns > 0:
# counts the number of times a user fails
failed = 0
# all characters from the input word taking one at a time.
for char in word:
# comparing that character with the character in guesses
if char in guesses:
print(char)
else:
print("_")
# for every failure 1 will be incremented in failure
failed += 1
if failed == 0:
# user will win the game if failure is 0 and 'You Win' will be given as output
print("You Win")
# this print the correct word
print("The word is: ", word)
break
# if user has input the wrong alphabet then it will ask user to enter another alphabet
guess = input("guess a character:")
# every input character will be stored in guesses
guesses += guess
# check input with the character in word
if guess not in word:
turns -= 1
# if the character doesn’t match the word then “Wrong” will be given as output
print("Wrong")
# this will print the number of turns left for the user
print("You have", + turns, 'more guesses')
if turns == 0:
print("You Loose")
1. True/False:
Mark either T (true) or F (false) for each statement in below. Write in one short sentence why you chose that answer, if necessary. You may lose points if your answer is very long.
a. Adjacency lists are more space efficient than adjacency matrices for sparse graphs. A sparse graph G = (V,E) has |E| = O(|V|).
b. The maximum number of edges in a graph with n vertices is n (n +1) / 2 .
c. A spanning tree of a graph with n vertices contains n edges.
d. Dijkstra’s algorithm does not work on directed graphs.
e. A dynamic programming algorithm makes short-sighted choices that are locally optimal.
f. Dynamic programming is an appropriate choice to solve merge sort.
g. Prim’s and Kruskal’s algorithms are examples of greedy algorithms.
h. In a flow network, the capacity of an edge must be less than or equal to the flow on the edge.
i. Dynamic programming uses memoization to avoid solving the same subproblem more than once.
j. Choice of data structures do not impact the time complexity of graph algorithms.
Answer:
(a) - True
(b)- False
(c)- False
(d) - False
(e) - False
(f) - False
(g)- True
(h)- False
(i) - False
(j) - False
Explanation:
(a)- In an adjacency list the usage of space depends upon the number of edges and vertices in the graph while in the case of the matrix efficiency depends upon the square of the vertices.
(b) The maximum number of edges is n*(n-1).
(c) The number of edges with a spanning tree of n vertices contains n-1 edges.
(d) Dijkstra's Theorem simply refers the adjacent vertices of a vertex and is independent of the fact that a graph is directed or in directed.
(e) Greedy Algorithm makes short sighted choices
(f) Consider the term overlapping sub-problems which is the technique used in Dynamic programming it uses previous calculations to find optimal solutions however in case of merge sort the idea is to break down array into smaller pieces that don't overlap unlike dynamic programming.
(g) Prim and Kruskal's algorithm are examples of greedy algorithm because the use the idea to pick the minimum weight edges at every step which is the approach of a greedy algorithm.
(h) the amount of flow on an edge cannot exceed its capacity.
(i) Dynamic Programming can be implemented using tabulation too.
(j) Different data structures have different time complexity.
In one to two sentences, describe how to change your home page.
Answer:
The main page of a website a visitor see while navigating, known as Home page.
Explanation:
The steps by which we can easily change our home page of Google Chrome, are as follows:
Step 1 :- Open Google Chrome.
Step 2 :- Click on the three vertical dots which appears next to the icon (profile).
Step 3 :- Click on settings, turn 'Show home button' to ON.
Step 4 :- Choose the new tab page you had like to use.
Answer:
First you would want to search in the bottom left search bar "settings", once you're there you would want to go to the top of the settings search bar and search up home page. Once you're there you can do whatever you want to do with your homepage.
Explanation:
got it right on edg.
What type of malicious software masquerades as legitimate software to entice the user to run it?
Answer:
Trojan horse
Explanation:
A Trojan horse is malicious software that masquerades as a legitimate computer program such as a video game, image file, utility program, or even an antivirus so as to entice the user to run it, thereby allowing an attackers (the developer of the malicious program) to gain access to the data on the computer in an illegal manner.
Modify the function to return true if the given decimal is even when it is rounded to the nearest integer, and false otherwise 1 function isRoundedNumberEven(decimal) t 5 * Do not modify code below this line 6 7 console.log(İsRoundedNumberEven(2.2),'<-- console.logCisRoundedNumberEven(2.8), should should be be true'); false;
Answer:
The function solution is in JavaScript
Explanation:
function isRoundedNumberEven(decimal) {
return Math.round(decimal) % 2 === 0;
/* the modulus 2 operation is used for numbers divisible by 2 */
/* This indicates even numbers */
}
console.log(isRoundedNumberEven(2.2));
console.log(isRoundedNumberEven(2.8));
When admitting digital evidence at trial, the issue of ________ comes up when the evidence involves computer-generated records.
Answer:
When admitting digital evidence at trial, the issue of Authenticity comes up when the evidence involves computer-generated records.
Explanation:
The digital evidence such as video, audio or some pictures have been presented before court as evidence. The first question that may arise is related to "authenticity of the material". To authenticate that evidence court may order the forensic audit of that particular evidence.
So, the issue of authenticity of evidence will arise, in case of digital evidence.
Write a SELECT statement that returns an XML document that contains all of the invoices in the Invoices table that have more than one line item. This document should include one element for each of the following columns:InvoiceNumberInvoiceDateInvoiceTotalInvoiceLineItemDescriptionInvoiceLineItemAmountHint: Below is the SQL part of the query that you should use so that all you have to add is the XML partSELECT InvoiceNumber, InvoiceDate, InvoiceTotal, InvoiceLineItemDescription AS ItemDescription, InvoiceLineItemAmount AS ItemAmountFROM Invoices AS Invoice JOIN InvoiceLineItems AS LineItemON Invoice.InvoiceID = LineItem.InvoiceIDWHERE Invoice.InvoiceID IN (SELECT InvoiceIDFROM InvoiceLineItemsGROUP BY InvoiceID HAVING COUNT(*) > 1)ORDER BY InvoiceDateSave the XML document that is returned in a file named MultipleLineItems.xmlGenerate an XML schema for the file and save it in a file named MultipleLineItems.xsd
Answer:
The code is given, paying attention to every column details
Explanation:
columns:
InvoiceNumber
InvoiceDate
InvoiceTotal
InvoiceLineItemDescription
InvoiceLineItemAmount
SELECT InvoiceNumber, InvoiceDate, InvoiceTotal, InvoiceLineItemDescription AS ItemDescription, InvoiceLineItemAmount AS ItemAmount
FROM Invoices AS Invoice JOIN InvoiceLineItems AS LineItem
ON Invoice.InvoiceID = LineItem.InvoiceID
WHERE Invoice.InvoiceID IN (
SELECT InvoiceID
FROM InvoiceLineItems
GROUP BY InvoiceID
HAVING COUNT(*) > 1)
ORDER BY InvoiceDate
FOR XML RAW, ELEMENTS;
Fill in the blanks:
a. __________ is based on travelling datagrams through internetworks one hop at a time. The entire route is unknown at the beginning of the journey.
b. __________ is group-based communication. It can be one-to-many or many-to-many distribution.
c. The most important requirement of a _______ network is the ability to treat different data types differently.
d. _______ process transmits telephone calls (voice) over the internet. 2
e. _______ is the standard recommended by the ITU for low bit-rate voice transmission over the Internet.
f. ________ is an unencrypted message data.
Answer:
(a). IP routing.
(b). Multicasting.
(c). converged.
(d). VoIP.
(e). VoIP.
(f). Plain text.
Explanation:
Ip routing is the method of transfer data from the one destination to another destination and it also send data from host to host across the network.
Multicasting is the type of distribution from one host to many hosts and also many hosts to many of them, it is used for the Internet Protocol Routing protocol in which the data is distributed to many receivers.
VoIP is that type of routing through which folks can use the internet services as the transmission mode.
Final answer:
Packet switching is based on travelling datagrams one hop at a time through internetworks. Multicast is group-based communication. A QoS network treats different data types differently.
Explanation:
a. **Packet switching** is based on travelling datagrams through internetworks one hop at a time. The entire route is unknown at the beginning of the journey.
b. **Multicast** is group-based communication. It can be one-to-many or many-to-many distribution.
c. The most important requirement of a **Quality of Service (QoS)** network is the ability to treat different data types differently.
d. **VoIP (Voice over IP)** process transmits telephone calls (voice) over the internet.
e. **G.729** is the standard recommended by the ITU for low bit-rate voice transmission over the Internet.
f. **Clear text** is an unencrypted message data.
An over-target baseline (OTB) is a comprehensive rebaselining effort that is best categorized as an internal replanning effort.
A. True
B. False
Answer:
The answer is "option B".
Explanation:
An OTB stands for an over-target baseline, it is a new management benchmark when an original target can't have coincided and new goals for management purposes are required.
It is also known as a reference to the foundation for calculating or constructing. It is an understanding between the client and the contractor that the cost base, which is not part of the original contract budget, should include an extra budgetDefine a function below called nested_list_string. The function should take a single argument, a list of lists of numbers. Complete the function so that it returns a string representation of the 2D grid of numbers. The representation should put each nested list on its own row. For example, given the input [[1,2,3], [4,5,6]] your function should produce the following string: "1 2 3 \n4 5 6 \n" Hint: You will likely need two for loops.
Answer:
The solution code is written in Python:
def nested_list_string(list2D): output = "" for i in range(0, len(list2D)): for j in range(0, len(list2D[i])): output += str(list2D[i][j]) + " " return outputExplanation:
Let's create a function and name it as nested_list_string() with one input parameter, list2D (Line 1).
Since our expected final output is a string of number and therefore we define a variable, output, to hold the string (Line 2).
Next use two for loops to traverse every number in the list and convert each of the number to string using str() method. Join each of individual string number to the output (Line 3-5).
At the end, we return the output (Line 7)
The 'nested_list_string' function converts a list of lists of numbers into a string that visually represents a 2D grid, with each sublist converted to a row of numbers separated by spaces, and rows separated by newlines.
The function called nested_list_string should be defined to take a list of lists of numbers as its argument and return a string representation of the 2D grid. To achieve this, you will need to use a nested for loop. The outer loop will iterate over each sublist (which represents a row of the grid), and the inner loop will iterate over each number in the sublist, converting it to a string and appending it to a string variable along with spaces. The \n character is used to move to the next line after each sublist is processed, thus simulating rows.
Here's an example code:
def nested_list_string(list_of_lists):Given an input like [[1,2,3], [4,5,6]], the nested_list_string function would return '1 2 3 \n4 5 6 \n'.
John is runnig his Database application on a single server with 24 Gigabytes of memory and 4 processors. The system is running slow during peak hours and the diagnostic logs indicated that the system is running low on memory. John requested for additional memory of 8 Gigabytes to be added to the server to address the problem. What is the resultant type of scaling that John is expecting?
Answer:
Vertical Scaling
Explanation:
Vertical scaling means the ability to increase the capacity of existing hardware or software by adding resources. In this case, more GB is added (8GB) to the server to address the problem. So vertical scaling is the resultant type john is expecting.
As the network engineer, you are asks to design an IP subnet plan that calls for 5 subnets, with the largest subnet needing a minimum of 5000 hosts. Management requires that a single mask must be used throughout the Class B network. Which of the following is a public IP network and mask that would meet the requirements?a. 152.77.0.0/21b. 152.77.0.0/17c. 152.77.0.0/18d. 152.77.0.0/19
Answer:
d) 152.77.0.0/19 (255.255.224.0)
Explanation:
If it is required to use a single mask throughout a Class B network, this means that by default, we have 16 bits as network ID, and the remaining 16 bits as host ID.
If we need to set up 5 subnets and we need that the largest subnet can support a minimum of 5000 hosts, we need to divide these 16 bits from the Host ID part, as follows:
Number of hosts = 5000
We need to find the minimum power of 2 that meet this requirement:
2ˣ - 2 = 5,000 ⇒ x = 13
We have left only 3 bits from the original 16, and repeating the process, we find that we need to use the 3 bits in order to accommodate the 5 subnets,
due to with 2 bits we could only support 4.
So, we need that the address mask be, using the CIDR notation, /19, as we need that the first three bits from the third byte to be part of the network ID.
In decimal notation, it would be as follows:
255.255.224.0
The correct IP subnet plan that can support at least 5000 hosts in the largest subnet while using a Class B network and a single mask throughout is 152.77.0.0/19.
Explanation:You are asked to provide an IP subnet plan for a scenario that requires 5 subnets, with the largest subnet supporting at least 5000 hosts, while using a single mask throughout a Class B network. To determine the correct subnet mask, you need to consider the number of hosts required for the largest subnet. Given that each subnet needs to accommodate at least 5000 hosts, the subnet must allow for more than 5000 host addresses. Calculating the number of bits for the host part, 2n - 2 must be greater than 5000 (where n is the number of host bits). This calculation gives us at least 13 bits for the host part (213 - 2 = 8190). Therefore, considering a Class B address starts with 16 network bits, adding 13 bits for the host part totals 29 bits for the network and host. Therefore, the subnet mask should be /19 (32 - 13 = 19) to meet the requirements.
With this in mind, among the given options, 152.77.0.0/19 is the correct network and mask that would meet the requirements as it provides up to 8190 possible host addresses in each subnet, which is more than sufficient for the largest subnet that requires 5000 hosts.
A radiologist’s computer monitor has higher resolution than most computer screens. Resolution refers to the:______
A radiologist’s computer monitor has higher resolution than most computer screens. Resolution refers to the: number of horizontal and vertical pixels on the screen.
Explanation:
The resolution of a screen refers to the size and number of pixels that are displayed on a screen. The more pixels a screen has, the more information is displayed on it without the user having to scroll for it.
More pixels also define and enhance the clarity of the pictures and content displayed on the screen. Pixels combine in different ratios to provide different viewing experiences for users.
Answer:
.
Explanation:
Which one of the following characteristics or skills of a ScrumMaster are closelyaligned with coaching?Select one:
a. Questioning
b. Protective
c. Transparent
d. Knowledgable
Answer:
A. Questioning
Explanation:
Questioning is the skill of a scrummaster that is most closely alligned with coaching, inspite of others.
Final answer:
The correct answer is "Questioning". The ScrumMaster's skill of questioning is closely aligned with coaching, as it encourages discussion, reflection, and problem-solving within the team.
Explanation:
The role of a ScrumMaster in the Scrum methodology of Agile software development includes various responsibilities that contribute to the success of the project. When considering which characteristics or skills are closely aligned with coaching within the ScrumMaster's role, the most relevant option among those provided would be questioning. A ScrumMaster utilizes questioning to facilitate discussion, encourage team reflection, and promote problem-solving abilities, all of which are essential coaching techniques. This helps the team find solutions to their impediments and continuously improve their processes, aligning with the ScrumMaster's goal of coaching the team towards self-organization and leveraging their full potential.
Which of the following class definitions is correct in Java?(i)public class Student{private String name;private double gpa;private int id;public void Student(){name = "";gpa = 0;id = 0;}public void Student(String s, double g, int i){set(s, g, i);}public void set(String s, double g, int i){name = s;gpa = g;id = i;}public void print(){System.out.println(name + " " + id + " " + gpa);}}(ii)public class Student{private String name;private double gpa;private int id;public Student(){name = "";gpa = 0;id = 0;}public Student(String s, double g, int i){set(s, g, i);}public void set(String s, double g, int i){name = s;gpa = g;id = i;}public void print(){System.out.println(name + " " + id + " " + gpa);}}1. Both (i) and (ii)2. None of these3. Only (ii)4. Only (i)
Answer:
The answer is "Option 3".
Explanation:
In the given question the code (ii) is correct because in the class definition class "Student" defines a constructor that does not use any return type. and code (i) class definition the class "Student" defines a constructor that uses return type void which is not allowed in the constructor. and other options are not correct that can be described as follows:
In option 1, only code (ii) is correct.In option 2, code (ii) is correct that's why it is not correct. In option 4, it is not correct, because it uses void return type.
Discuss in 500 words, why institutions might be reluctant to move there IT to the cloud. Consider specific industries like education, medicine, military, etc.
Answer:
1. Performance and uptime: In mission critical IT systems like those in the military performance and uptime are so important that the institutions might be reluctant to surrender their local infrastructure for cloud based systems, even if the cloud systems advertise better performance than what the institution's deployment can boast of. Even many corporates are still worried about this aspect of cloud computing. It’s no secret that a fraction of a second on load time can lead to loss of customers.
2. Security: Along with loss of control, security is arguably the biggest concern many large organizations like the military, academic institutions and hospitals have. Can other customers access our data? Have all the security patches been kept up to date? These question create a reluctance to migrate to the cloud among executives and IT directors in these institutions.
3. Data Protection: Closely tied in with security, institutions are concerned about data protection. Many governments place strict data protection requirements on large companies and standards audit schemes such as ISO-9001 place additional restrictions on firms.
For example, the UK’s Data Protection Act requires that personal data not to be transferred to any country outside the EU, unless that country “ensures an adequate level of protection for the rights and freedoms of data subjects in relation to the processing of personal data.” Practically, that means it’s often easier for servers to be physically located in the EU for many European institutions.
4. Losing control: When systems go down, it’s invariably the IT Director who takes the blame, so it’s no surprise that they are nervous about handing over responsibility for infrastructure to somebody they don’t even know.
Traditionally, if a hard drive fails or a CPU overheats, it’s the IT department who get the 3am call to fix it. It’s up to them to order the replacement hardware, power down the machine and get it back into production as soon as possible.
Even if you’re renting space in a hosting centre and paying for support, chances are you are physically allowed into the building and have the peace of mind that comes from knowing that, if all else fails, you can go in and fix the hardware yourself.
By moving to cloud computing, the IT Director or CIO can feel like they’re handing over control to a 3rd-party. What happens if one of the drives goes or there’s a networking issue? Who decides what hardware to buy?