In mrs. prosser's class there are 32 students. If 3 out of every 8 prefer to ride their bicycles to school, how many students in the entire class like to ride their bicycles to school?

Answers

Answer 1
First divide 32 by 8

32/8

=4

Then multiply the 4 by 3 to find out how many students in the class like to ride their bicycles to school

4x3

12 students is your answer

Related Questions

Barb’s class has 18 bikes .tim’s class has some rows of bikes with 5 bikes in each row. Tim’s class has more bikes than barb’s class. How many rows of bikes could tim’s class have?

Answers

Tom's class could have at least 4 rows of bikes
tim's class could have 4 row of 5 bikes and it would be more

Given the values of the derivative f′(x) in the table and that f(0)=150, find or estimate f(x) for x=0,2,4,6.

Answers

Final answer:

To find or estimate f(x) for x=0,2,4,6, integrate the given derivative f'(x) with respect to x to find the constant term. Then, add each value of f'(x) in the table to the constant term to obtain the values of f(x) for x=0,2,4,6.

Explanation:

To find or estimate f(x) for x=0,2,4,6, we need to use the values of the derivative f'(x) given in the table. Since f'(x) represents the rate of change of f(x) at different values of x, we can use the derivative to find or estimate the values of f(x). Given that f(0) = 150, we can start by finding the constant term of the function using this initial condition.

To find the constant term, we need to integrate the derivative f'(x) with respect to x. This will give us the original function f(x).Integrating f'(x) gives us f(x) = 150 + C, where C is the constant term we need to find.Next, we can use the given values of f'(x) in the table to find or estimate the corresponding values of f(x) for x=0,2,4,6.Let's assume that the third column in the table represents the values of f'(x) at different values of x. We can add each value to the constant term C to obtain the values of f(x) for x=0,2,4,6.

Therefore, by integrating f'(x) and adding the constant term, we can find or estimate the values of f(x) for x=0,2,4,6.

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Carol ate 2/5 of the cake. Dima ate 3/5 of the REMAINING CAKE, mom ate the rest.
How many times more did Carol eat compared to Dima? PLEASE EXPLAIN, GIVING BRAINLIEST, PLEASE HELP.

Answers

Well, the best explanation is that if you keep going up you will eventually get the number so 2/5 times 1 is 2/5, 2/5 times 2 is 4/5 some it between exactly so its .5 times as large

Describe or show two ways to find the following product: 1/4 x 2/3.

Answers

1/4 = 0.25
2/3 = 0.666666667
0.25(0.666666667) = 0.166666667 = [tex] \frac{1}{6} [/tex]
______________________________

[tex] \frac{1}{4} ( \frac{2}{3}) = \frac{2}{12} = \frac{1}{6} = 0.166666667[/tex]

Given that P = (-4, 11) and Q = (-5, 8), find the component form and magnitude of vector QP

Answers

The given points are
P = (-4,11)
Q = (-5,8)

The x-component of vector QP is
-4 - (-5) = 1
The y-component of vector QP is
11 - 8 = 3

The vector QP is 
(1,3) or
[tex]\vec{QP} = \hat{i} + 3\hat{j}[/tex]

The magnitude of the vector is
√(1² + 3²) = √(10)

Answer:
[tex]\vec{QP} = \hat{i}+3\hat{j} \,\, or \,\, (1,3)[/tex]
The magnitude is √(10).

Answer:

<1, 3>, square root of ten

Step-by-step explanation:

How much pure acid should be mixed with 6 gallons of a 20% acid solution in order to get a 90% acid solution?

Answers

so, how much acid is there in 6 gallons?  well is 20% acid or (20/100), so the amount of acid in it just (20/100) * 6 or 1.2, the rest is say water.

now, if we want a 90% solution, and say we add "y" gallons, how much acid is in it?  well (90/100) * y, or 0.9y.

now let's add "x" gallons of pure acid, now, pure acid is just pure acid, so is 100% acid, how much acid is there in it?  (100/100) * x, or 1x or just x.

we know whatever "x" and "y" amounts are, they -> x + 6 = y

and we also know that x + 1.2 = 0.9y

[tex]\bf \begin{array}{lccclll} &\stackrel{gallons}{acid}&\stackrel{acid~\%}{quantity}&\stackrel{acid~gallons}{quantity}\\ &------&------&------\\ \textit{pure acid}&x&1.00&x\\ \textit{20\% sol'n}&6&0.20&1.2\\ ------&------&------&------\\\ mixture&y&0.90&0.9y \end{array} \\\\\\ \begin{cases} x+6=\boxed{y}\\ x+1.2=0.9y\\ ----------\\ x+1.2=0.9\left( \boxed{x+6} \right) \end{cases} \\\\\\ x+1.2=0.9x+5.4\implies x-0.9x=5.4-1.2\implies 0.1x=4.2 \\\\\\ x=\cfrac{4.2}{0.1}\implies x=\stackrel{gallons}{42}[/tex]
Final answer:

To get a 90% acid solution, you should mix 54 gallons of pure acid with the 6 gallons of the 20% acid solution.

Explanation:

To solve this problem, we can use the formula for concentration:

Concentration = (Volume of pure acid) / (Total volume of solution)

Let x represent the volume of pure acid to be added. We know that the total volume of the solution after adding the pure acid is 6 gallons + x gallons. We also know that the concentration of the 20% acid solution is 0.2.

Using the formula, we can set up the equation:

0.9 = x / (6 + x)

Multiplying both sides of the equation by (6 + x), we get:

0.9(6 + x) = x

Simplifying the equation, we have:

5.4 + 0.9x = x

Subtracting 0.9x from both sides of the equation, we get:

5.4 = 0.1x

Dividing both sides of the equation by 0.1, we get:

54 = x

Therefore, you should mix 54 gallons of pure acid with the 6 gallons of the 20% acid solution to get a 90% acid solution.

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Find the vertex of the parabola whose equation is y = x2 - 4x + 6.

Answers

Hello Romom! To find the vertex, we can use the vertex formula to find x of the vertex and then use the equation to find the y of the vertex.

Vertex Formula: [tex]x = \frac{-b}{2a}[/tex]

[tex]y = x^2 - 4x + 6 [/tex]
b =  (-4) 
a = 1

[tex]x=\frac{-b}{2a}[/tex]
[tex]x=\frac{-(-4)}{2(1)}[/tex]
[tex]x=\frac{4}{2}[/tex]
[tex]x=2[/tex]

So the vertex x point is at 2 so (x,y) = (2,y)
Now lets find the y by inserting 2 where the x is located in the equation:
[tex]y = x^2 - 4x + 6[/tex]
[tex]y = 2^2 - 4(2) + 6[/tex]
[tex]y = 4 - 8 + 6[/tex]
[tex]y = 2[/tex]
Now that we found the y for the vertex, we have (x,y) = (2,2) and (2,2) is our vertex. We can graph the equation to and see (2,2) is correct.


The gas tank in the car holds 20 gallons of gasoline. You used up 4 gallons and 1 quart on your trip. How much gasoline is left in the tank?

Answers

There are 4 quarts in a gallon so the amount used can be shown as 4 1/4, or 4.25 so to find out how much gas is left in the tank you simply subtract 4.25 from 20.

20-4.25

=15.75

There is 15.75, or 15 3/4, gallons of gasoline left in the tank.

The correct answer is:

Total capacity of tank in quarts:

20 gallons = 20 × 4 = 80 quarts

Gasoline used in quarts:

4 gallons 1 quart = (4 × 4) + 1 = 17 quarts

Gasoline left in the tank in quarts:

80 − 17 = 63 quarts

Gasoline left in the tank in gallons and quarts:

63 quarts = 63 ÷ 4 = 15 remainder 3 = 15 gallons 3 quarts

Solve the system 2x-2y=10 4x-5y=17

Answers

multiply 2x-2y=10 by 2,
4x-4y=20,
given:4x-5y=17
y=3
pluck it in
2x-6=10
move the 6 to the right
2x=16
divide
x=8
y=3
Equation 1)  2x - 2y = 10
Equation 2)  4x - 5y = 17

Multiply ALL of equation 1 by 2.

1)  2(2x - 2y = 10)

Simplify.

1)  4x - 4y = 20
2)  4x - 5y = 17

Subtract equations from one another.

y = 3

Plug in 3 for y in the first equation.

1)  2x - 2y = 10

2x - 2(3) = 10

Simplify.

2x - 6 = 10

Add 6 to both side.s

2x = 16

Divide both sides by 2.

x = 8

------------------------------------
Check your work by plugging in 8 for x, and 3 for y into the original equations.

2x - 2y = 10 & 4x - 5y = 17

1)  2x - 2y = 10

2(8) - 2(3) = 10

Simplify.

16 - 6 = 10

10 = 10 

2)  4x - 5y = 17

4(8) - 5(3) = 17

Simplify.

32 - 15 = 17

17 = 17

Therefore, x = 8, y = 3

~Hope I helped!~

Carlos has 5/8 pound of pumpkin seeds. He puts the seeds evenly into 20 envelopes. How much pumpkin seed is in each envelope?

Answers

Hello there! The answer would be 32. Here's how I solved it:
20/1 divided by 5/8:
20 x 8 = 160
1 x 5 = 5 = 160/5
Simplify: 32

Hope this helps you!

The answer would be 32.I got 32 because 20/1 is supposed to be divided by 5/8.I got 20/1 because when you don’t have a fraction and you want to make I a fraction it’ll be 20/1 in this case for example.So then you multiply 20 and 8 equals 160.Then 1 times 5 equals 5 which also equals 160/5.Lastly you simplify it to 32.

I hope this helps.Good Luck!

Solve for x.y = mx+b

Answers

x=   b      y
     - _ +  _
       m     m
this is the answer

y = mx + b

Solve for x means to isolate x.

y - b = mx

We now divide both sides by m to isolate x.

(y - b)/m = x

There are 24 student's in a science class. Mr. Sato will give each pair of student's 3 magnets. So far, Mr. Sato has given 9 pairs of students their 3 magnets. How many more magnets does Mr. Sato need zo.that each pair of student's habe exactly 3 magnets?

Answers

well, a pair of students means two. if there are 24 students then there are: 24/2 = 12 pairs of students.

9 pairs already got their magnets. 12 - 9 = 3 pairs still need magnets.

each pair gets 3 magnets. So he needs 3*3 = 9 more magnets
2 students equal a pair, 9 pairs equal 18 students, which leave 6 students left. that remains 3 pairs, which need 3 magnets each pair. (3*3=9) Mr. Sato needs 9 magnets.

A customer pays $3.27 for oranges and $4.76 for pears. How many pounds of fruit does the customer buy?

Answers

take 3.27 and divide that by 1.09  (for the oranges)
3.27/1.09=3lbs. of oranges
then take 4.76 and divide that by 1.19       (for the pears)
4.76/1.19=4lbs. of pears
add 4+3 to get how many lbs. in all
4+3=7

A total of 7 pounds of fruit does the customer buy.

Given that, a customer pays $3.27 for oranges and $4.76 for pears.

The cost of 1 pound orages=$1.09 and the cost of 1 pound pears=$1.19

What is a unitary method?

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Now, the number of pounds of oranges =3.27/1.09=3 pounds

The number of pounds of pears =4.76/1.19=4 pounds

Total weight=3+4=7 pounds

Therefore, a total of 7 pounds of fruit does the customer buy.

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What percentage of 3000 is 330

Answers

The answer to this is 11 percent

Answer:

11

Step-by-step explanation:

The table of values below represents a linear function and shows the height of a tree since it was transplanted. What was the height of the tree when it was transplanted?

Answers

4 feet is the answer
Answer:

The height of the tree when it was transplanted was:

                              4 feet

Step-by-step explanation:

As we could observe that the given table represents a linear function.

The table is given as follows:

Year since it was      4        4.5        5      

transplanted

Height  (Feet)            12       13          14

We will find the linear function.

Let y denotes height and x denote year since it was transplanted.

We know that any linear function passing through two points (a,b) and (c,d) is given by:

[tex]y-b=\dfrac{d-b}{c-a}\times (x-a)[/tex]

Here let (a,b)=(4,12) and (c,d)=(5,14)

Hence, the linear function is calculated as follows:

[tex]y-12=\dfrac{14-12}{5-4}\times (x-4)\\\\\\y-12=2(x-4)\\\\\\y-12=2x-8\\\\\\y=2x-8+12\\\\\\y=2x+4[/tex]

Now the height of tree when it was transplanted is the value of y when x=0

Hence, when x=0 we have:

y=4

    Hence, the height was:

               4 feet

spiders can walk on walls write the statement in if then form

Answers

If a spider can walk, then it can walk on walls.

If then because statements are much like they seem.

The perimeter of a square is 26.46 inches. What is the side length of the square?

Answers

A square has 4 equal sides.  Perimeter is calculated by adding all the sides
Normally it would be:
P=s1+s2+s3+s4
for a square its simply
P=4s
26.46=4S
6.615=S
Each side is 6.615 inches
Final answer:

The side length of a square whose perimeter is 26.46 inches can be calculated by dividing the given perimeter by 4 (the number of sides in a square), resulting in a side length of approximately 6.615 inches.

Explanation:

The subject of this question is Mathematics, with the specific topic being measurement and geometry. This question is applicable to Middle School grade levels. The student seeks to determine the side length of a square, knowing the perimeter is 26.46 inches.

To find the side length, we need to recall the formula for the perimeter of a square: P = 4s, where P represents the perimeter and s represents the length of a side. The student's square has a perimeter of 26.46 inches, so the equation would be 26.46 = 4s.

To isolate the value of s, we divide both sides of the equation by 4. This gives us: s = 26.46/4. Upon doing the division, we find that each side of the square is approximately 6.615 inches.

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A​ salesperson's commission rate is 5 ​%. What is the commission from the sale of $ 44,000 worth of​ furnaces? Use pencil and paper. Suppose sales would double. What would be true about the​ commission? Explain without using any calculations.

Answers

So, for the first question, you just want to multiply 5% by 44,000 to find how much is 5% of 44,000.

5% = 0.05

0.05 * 44,000 = 2,200

So the salesperson makes 2,200 dollars from the sale of 44,000.

If sales doubled, then she would make the double amount.

a. The commission from the sale of $ 44,000 worth of​ furnaces is $1,800

b. Commission would double as well.

What is the percentage?

A percentage is a minimum number or ratio that is measured by a fraction of 100.

We are given that salesperson's commission rate is 5 ​%

Then Commission paid on $36,000 worth of furnaces with a rate of 5% is:

= Amount of sales x commission rate

= 36,000 x 5%

= $1,800

If the sales were to double, the commission would be based on double the amount so it would double;

= 36,000 x 2

= $72,000

Commission = 72,000 x 5%

= $3,600

therefore Commission is doubled.

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Cody filled a container with 7 3/16 quarts of iced tea. how many 1/4 quart glasses can be served from the container

Answers

simply do a division on both.

[tex]\bf \stackrel{mixed}{7\frac{3}{16}}\implies \cfrac{7\cdot 16+3}{16}\implies \stackrel{improper}{\cfrac{115}{16}} \\\\\\ \textit{how many times does }\frac{1}{4}\textit{ go into }\frac{115}{16}? \\\\\\ \cfrac{\quad \frac{115}{16}\quad }{\frac{1}{4}}\implies \cfrac{115}{16}\cdot \cfrac{4}{1}\implies \cfrac{115}{4}\implies 28\frac{3}{4}[/tex]

If the circular opening of the pipe has a diameter of 21 inches and the oil was estimated to be flowing at 30 inches/second, how many cubic feet of oil were leaving the pipe each second? Each day?

Answers

This is a matter of Amount = Rate  times  time.

First, find the area of the circular opening.  A = pi (r^2).  Here,

A = pi(10.5 inches)^2.

To obtain the volume of water that flows out of the pipe per second, multiply this area by the 30 inches per second rate.

That comes out to a volume per second of  Volume rate = pi*(10.5 inches)^2 * 30 inches per second:

Volume rate = 3.14(110.25 in^2)(30 inches/sec)
                     = 10390.8 cubic inches per second

Convert this result to cubic feet per second.  Recall that 1 cubic foot = (12 inches)^3, or 1728 cubic inches / 1 cubic foot.

Thus, 10390.8 cubic inches per second comes out to

           10390.8 cubic inches
           ----------------------------   =   Just over 6 cubic feet per sec.
               1728 cu. inches
                ---------------------
                  1 cu. ft

How many sec in 1 day?    1 day = 24 hours
                                             1 hour = 60 minutes
                                             60 seconds = 1 minute

Figure out how many seconds there are in 1 day, and then multiply your result by 6 cu. ft. / sec. 
Final answer:

To find the flow rate of oil, first calculate the cross-sectional area of the pipe using the formula for the area of a circle, A=πr². Then, multiply the area by the given oil speed to find the volume of oil flowing every second. Multiply this by the number of seconds in a day to find the amount of oil leaving the pipe each day, and remember to convert from cubic inches to cubic feet.

Explanation:

The question is asking us to find the volume of oil leaving the pipe per second and per day. To calculate the flow rate of oil, we first find the cross-sectional area of the pipe by using the formula for the area of a circle A=πr², where r is the radius of the pipe (half the diameter). Since the diameter given is 21 inches, the radius is 10.5 inches.

Next, use the given flow rate of 30 inches/second to calculate the volume of oil flowing every second. This is done by multiplying the area by the oil speed V = A * oil speed.

To find the amount of oil leaving the pipe each day, we multiply the volume per second by the number of seconds in a day .

Note: To convert cubic inches to cubic feet (since the question asks for cubic feet), remember there are 1728 cubic inches in 1 cubic foot.

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a 9 pound bag of sugar is being split into containers that hold 2/3 of a pound. how many containers of sugar will the 9 pound bag create?

Answers

namely, how many times does 2/3 go into 9?

well

[tex]\bf 9 \div \frac{2}{3}\implies \cfrac{9}{\frac{2}{3}}\implies \cfrac{\quad \frac{9}{1}\quad }{\frac{2}{3}}\implies \cfrac{9}{1}\cdot \cfrac{3}{2}\implies \cfrac{27}{2} \\\\\\ \textit{2 goes \underline{13 times} into 27, with a \underline{remainder of 1}}\implies 13\frac{1}{2}[/tex]

Answer:

13 1/2

Step-by-step explanation:

The formula s= sa/6 gives the length of the side, s, of a cube with the surface area, sa. How much longer is the side of the cube with a surface area of 180 square meters than a cube with the surface area of 120 square meters ?

Answers

[tex]\bf s=\cfrac{sa}{6}\qquad \cfrac{\stackrel{larger}{side}}{\stackrel{smaller}{side}}\implies \cfrac{\quad \frac{180}{6}\quad }{\frac{120}{6}}\implies \cfrac{180}{6}\cdot \cfrac{6}{120}\implies \cfrac{180}{120}\implies \cfrac{3}{2}[/tex]

they're on a ratio of 3:2, so if the small is 2, the large one is 3, and if the small one is 120, the large one is 180.

on a 3:2 ratio, 3 is larger than 2 by 1 unit, 1 is 50% of 2, or half, so the longer side is 50% larger.

Answer with explanation:

Side of cube = S

Surface Area of Cube = S.A

Relation between Side of a cube and surface area

   [tex]S=\frac{S.A}{6}[/tex]

→If surface area of cube =180 Square meters

Side of cube (S)

                     [tex]S_{1}=\frac{180}{6}\\\\=30[/tex] meters

→  If surface area of cube =120 Square meters

Side of cube (S)

                     [tex]S_{2}=\frac{120}{6}\\\\=20[/tex] meters

[tex]S_{1}-S_{2}=30 -20=10\\\\S_{1}=S_{2}+10[/tex]

Side of cubic having surface area 180 square meters is greater by 10 meters, than a cube with the surface area of 120 square meters.

 

how to round 254 to the nearest hundred

Answers

One way is using the rules.

To round 254 to the nearest hundred, look at 254. 
If the tens place is 5 or above round it to 300, if it is 4 or below round it down to 200.
The tens value is 5 so you would round 254 to 300.

help!! me asap!! please!!

Answers

D is the correct answer and is highlighted in the figure.
Your reponse is the correct one.  What kind of help were you hoping for?

If m and n are two positive real numbers whose product is 10, what is the minimum value of m + 2n

Answers

If m and n are two positive real numbers whose product is 10, what is the minimum value of m + 2n

2 + 2(4)

The minimum value of (m + 2n) is 8.95 and this can be determined by using the arithmetic operations.

Given :

If m and n are two positive real numbers whose product is 10.

Given that m and n are two positive real numbers whose product is 10 that is:

mn = 10

[tex]\rm m= \dfrac{10}{n}[/tex]   ---- (1)

The minimum value of (m + 2n) can be determined by using the following calculation.

Put the value of m in the given expression.

[tex]\rm = \dfrac{10}{n}+2n[/tex]  ---- (2)

Now for minimum value differentiate the above expression with respect to n.

[tex]\rm =-\dfrac{10}{n^2}+2[/tex]  

Now equate the above equation to zero.

[tex]\rm \dfrac{10}{n^2}=2[/tex]

[tex]\rm n = \sqrt{5}[/tex]

Now, put the value of n in equation (2).

[tex]\rm Minimum \;Value = \dfrac{10}{\sqrt{5} }+2\sqrt{5}[/tex]

                          = 8.95

The minimum value of (m + 2n) is 8.95.

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Find the area of the following circle. Use = 3.14

r = 5 yd.

Answers

78.5 yd² is your answer.

write all names that apply to each number 121/121

Answers

121/121



one

etc

hope this helps
1/1, 2/2, 3/3, and so on.

How many kilometers could the red car travel in 12 hours?

Answers

Cars usually on the freeway drive at 60 miles per hour or 96.56064 kilometers per hour. Speed x distance = result of kilometers or miles. In this case it is 96.56064 times 12 equals 1158.72768 kilometers per 12 hours.

10 x 6 tens-unit form and standard form

Answers

Answer:

Standard form: 600

Unit form: 6 hundreds.

Step-by-step explanation:

We have been given a number [tex]10\times 6[/tex]-tens. We are asked to write our given number in unit form and standard form.  

To write our given number in standard form, we will expand our given number as shown below:

6-tens [tex]6\times 10=60[/tex]

[tex]10\times 6[/tex]-tens would be  [tex]10\times 60=600[/tex]

Therefore, our given number in standard form would be 600.

We know that unit form is writing a number using place value units.

We can see that our given number has 0 ones, 0 tens and 6 hundreds.

Therefore, our given number in unit form would be 6 hundreds.

We have that  the Tens unit form of 10 x 6 and  Standard form is mathematically

[tex]6*10^1[/tex]

6tens

From the question we are told that

10 x 6

10 x 6=60

Standard form is a number, between 1 and 10 multiplied by a power of 10

Generally the equation for the Standard form   is mathematically given as

x*10^y

Therefore

the Standard form  of 10 x 6  is mathematically given as

[tex]6*10^1[/tex]

And

Generally the equation for the Tens unit form of 10 x 6  is mathematically given as

x*tens(10)

Tens-unit form is mathematically given as

6tens

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if a ball is thrown directly upward with a velocity of 40 ft/s, its height (in feet) after t seconds is represented by 40t-16t^2. what is the maximum height attained by the ball?

Answers

check the picture below.

[tex]\bf h(t)=40t-16t^2\implies h(t)=-16t^2+40t+0 \\\\\\ \begin{array}{llll} \qquad \textit{in feet}\\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\textit{initial velocity of the object}\\ \qquad 40\\ h_o=\textit{initial height of the object}\\ \qquad 0\\ h=\textit{height of the object at "t" seconds} \end{cases}[/tex]

[tex]\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\ \begin{array}{llll} y = &{{ -16}}x^2&{{ +40}}x&{{ +0}}\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array}\qquad \left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right) \\\\\\ \left( \stackrel{\textit{it took this long}}{-\cfrac{40}{2(-16)}}~~,~~\stackrel{\textit{to get this high}}{0-\cfrac{40^2}{4(-16)}} \right)\qquad \stackrel{\textit{maximum height}}{0-\cfrac{40^2}{4(-16)}}[/tex]
Final answer:

The maximum height attained by the ball is 25 feet.

Explanation:

The maximum height attained by the ball can be found by determining the vertex of the quadratic equation representing the height of the ball. In the given equation 40t - 16t^2, the coefficient of t^2 is negative, indicating a parabolic shape with a maximum point. The formula for the x-coordinate of the vertex is -b/2a, which in this case is -40/(2*(-16)) = 1.25 seconds. Substituting this value into the equation gives the maximum height: 40(1.25) - 16(1.25^2) = 25 feet.

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