In how many ways can 50 cards be chosen from a standard deck of 52 cards?

Answers

Answer 1
The answer must take into account that the order is irrelevant, that is that it is the same J, Q, K that Q, K, J, and K, J, Q and all the variations of those the three cards.

The number of ways you can draw 50 cards from 52 is 52*51*50*49*48*47*...4*3 (it ends in 3).
,
But the number of ways that those 50 cards form the same set repeats is 50! = 50*49*49*47*....3*2*1

So, the answer is (52*51*50*49*48*....*3) / (50*49*48*...*3*2*1) =  (52*51) / 2 = 1,326.

Note that you obtain that same result when you use the formula for combinations of 50 cards taken from a set of 52 cards:

C(52,50) = 52! / [(50)! (52-50)!] = (52*51*50!) / [50! * 2!] = (52*51) / (2) = 1,326.

Answer: 1,326

Related Questions

Which of the following are pairs of congruent segments?
Check all that apply.

Answers

A. BC and PO
C. AB and AP
E. IJ and LM
According to how close the segments are relative to the center, corners, ad each other, I believe the answer is A, C and E.

A cab ride from your home to the airport cost $23.47. If you want to tip the cab driver close to 10 percent of the fare, how much should you tip?

$0.24
$1
$3
$8

Answers

You would tip 8 dollars bc that's 10%

Answer:

Step-by-step explanation:

For all Plato users.

The function y=-2+5sin(pi/12(x-2)), what is the minimum value?

Answers

Answer:

-7

Step-by-step explanation:

bla bla bla 20 characters

Answer:

-7

Step-by-step explanation:

We are given that   a function

[tex]y=-2+5 sin(\frac{\pi}{12}(x-2))[/tex]

We have to find the minimum value of y.

We know that range of sin x is [-1,1].

[tex]-1\leq sin(\frac{\pi}{12}(x-2))\leq 1[/tex]

[tex]-5\leq 5sin(\frac{\pi}{12}(x-2))\leq 5[/tex]

[tex]-5-2\leq -2+5sin(\frac{\pi}{12}(x-2))\leq 5-2[/tex]

[tex]-7\leq -2+5sin(\frac{\pi}{12}(x-2))\leq 3[/tex]

[tex]-7\leq y\leq 3[/tex]

Maximum value of y=3

Minimum value of y=-7

Hence, the minimum value of given function =-7

A=1/2(a+b)h solve for h

Answers

A=1/2(a+b)h ↔ A= [(a+b).h]/2

Cross multiplication:→2A = (a+b).h.

Divide both sides by (a+b):

2A/(a+b) =h

Cross multiply then divide

The following set of coordinates most specifically represents which figure?

(−5, 6), (−1, 8), (3, 6), (−1, 4)

Answers

I drew it roughly  

All 4 sides are = sqrt20
Looks like a rhombus

The correct answer is C: Rhombus. This is how you find your answer: desmos.com because you just plant in the ordered pair into the program and it plots out the shape for you. The only thing you need to know is your shapes and you should be set.

A traffic light is needed at each intersection. How many traffic lights are needed if there are 6 streets in the town.

Answers

Final answer:

To calculate the number of traffic lights needed for a town with 6 streets intersecting each other, you can use the formula Number of traffic lights = Number of intersections. In this case, 15 traffic lights are needed.

Explanation:

A traffic light is needed at each intersection. How many traffic lights are needed if there are 6 streets in the town?

To determine the number of traffic lights needed for 6 streets, we use the formula: Number of traffic lights = Number of intersections. In a town with 6 streets, each street intersects with every other street, resulting in 15 intersections. Therefore, 15 traffic lights are needed for the 6 streets.

which of the following correctly describes the end behavior of the polynomial function, f(x)=3x^4+2x^2-x

Answers

Answer:

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow -\infty[/tex]

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow +\infty[/tex]

Step-by-step explanation:

Given polynomial function is,

[tex]f(x)=3x^4+2x^2-x[/tex]

Since, the end behavior of a polynomial is same as the end behavior of leading term,

Here, the leading term = [tex]3x^4[/tex]

[tex]\text{As }x\rightarrow -\infty[/tex]

The leading term is positive,

[tex]\text{While, as }x\rightarrow +\infty[/tex]

The leading term is positive,

Hence, the end behavior of the given polynomial is,

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow -\infty[/tex]

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow +\infty[/tex]

⇒ In the graph of f(x), both ends will go upward.

Answer:both ends go down !

Step-by-step explanation:

Help on this please show my work ?

Answers

Factor the denominator
x^2+3x-10
(x+5)(x-2)

(x-2)/((x+5)(x-2))

The x-2 in the numerator and denominator cancel out.

Final answer: x+5

Implify the expression. write your answer using decimals. 22.5 + 7(n−3.4

Answers

An algebraic expression consists of variables which are represented with letters like for this case we have n, a coefficient which is indicated by numbers (e.g. 22.5, 7 and 3.4 ) and  sometimes exponents Oftentimes expressions contains a number of terms which consists of those elements. To simplify an expression, we need to remember that we can only add and subtract terms that have the same base of the variable. As for multiplying and dividing, we can proceed with these operations accordingly. We simplify as follows:

22.5 + 7(n−3.4)
22.5 + 7n - 23.8
7n - 1.3

The simplified expression would be written as 7n - 1.3.


Find the midpoint of C and E. Simplify completely.



1. (–4,–3)
2. (0,–3)
3. (–4,–1)
4. (0,–1)
5. none of these

Answers

C=(-4,-4)

E = (4,-2)

-4 +4 = 0/2 =0

-4+-2 = -6/2 = -3

(0,-3)

Find the possible value or values of n in the quadratic equation 2n^2-7n+6=0

Answers

Using the quadratic formula:
n = [-b +- sq root (b^2 -4*a*c)] / 2a
n = [--7 +- sq root (49 -4*2*6)] / 4
n = [--7 +- sq root (49 -48)] / 4
n = [--7 +- sq root (1)] / 4
n1 = (7 + 1) / 4
n1 = 2

n2 = (7 -1) / 4
n2 = 1.5


For the ordered pair, give three other ordered pairs with θ between −360° and 360° that name the same point. (3, 135°)

Answers

Final answer:

Three other ordered pairs with θ between −360° and 360° that name the same point as (3, 135°) are (−243, −45°), (−177, −15°), and (315, 495°).

Explanation:

The ordered pairs (−243, −45°), (−177, −15°) and (315, 495°) all name the same point as (3, 135°) with θ between −360° and 360°.

To find these ordered pairs, you can add or subtract 360° to the given angle of 135° while keeping the x-coordinate constant at 3.

For example, you could subtract 360° from 135° to get −225° and combine it with the x-coordinate of 3 to get the ordered pair (3, −225°).

(08.06)The following data show the height, in inches, of 11 different garden gnomes:
2 9 1 23 3 7 10 2 10 9 7
After removing the outlier, what does the mean absolute deviation of this data set represent?
On average, the height of a garden gnome varies 3.2 inches from the mean of 7 inches.
On average, the height of a garden gnome varies 3.6 inches from the mean of 6 inches.
On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.
On average, the height of a garden gnome varies 3.6 inches from the mean of 7 inches.

Answers

Answer:

The correct statement is:

On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.

Step-by-step explanation:

We are given a data of 11 gardens as:

2   9    1    23    3    7    10    2    10    9     7

Now on removing the outlier i.e. 23 (since it is the very large value as compared to other data points) the entries are as follows:

x         |x-x'|        

2          4              

9          3              

1           5              

3          3              

7           1                

10         4              

2           4              

10          4              

9           3              

7            1              

Now mean of the data is denoted by x' and is calculated as:

[tex]x'=\dfrac{2+9+1+3+7+10+2+10+9+7}{10}\\\\x'=\dfrac{60}{10}\\\\x'=6[/tex]

Hence, Mean(x')=6

Now,

∑ |x-x'|=32

Now mean of the absolute deviation is:

[tex]\dfrac{32}{10}=3.2[/tex]

This means that , On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.

Answer: Please don’t judge me but I agree with the other guy, it’s (C.
Credits to him ♥️

What is the value of x 20 35 60 70

Answers

x+40 =3x (vertical angles)
2x = 40
x = 20

answer  is A. 20 (first choice)
TRS and VRW are vertical angles, therefore they're congruent

x + 40 = 3x
40 = 2x
20 = x

x is 20

You are helping a partner in your group with their problem. What mistake did they make solving the system?
3x+y-9
-2x+y=4

Students work when solving the second equation for y:
Y=2x+4
-2x+(2x+4)=4
-2x+2x+4=4
4=4

The students response is there are indefinitely many solutions and this is not correct. Explain the mistake.

Answers

The answer is supposed to be that there is no solution

Rewrite the equation in vertex form and then give the vertex of the quadratic equation

Answers

hello :

: f(x) = a(x-h)²+k is the equation in vertex form  of the quadratic equation
when  the vertex is ( h , k)

Find the length of arc xpy with a radius of 12m. leave in terms of pi./Users/alymcclellan/Desktop/Screen Shot 2017-07-31 at 10.25.17 PM.png

Answers

If you have the measure of the central angle, you use the formula 2pi r where r is the radius by the fraction value of the arc length

Find f'(x) for f(x) = −7x2 + 4x − 10.

Answers

The answer is D, none of these

if you roll a normal dice 120 times. How many odd numbers would you expect to get

Answers

1,3,5 out of 1,2,3,4,5,6.
This means there's a 50% chance of an odd number, so 120/2 = 60

Answer:

60 odd numbers

Step-by-step explanation:

A normal dice has 6 different sides numbered from 1 to 6, each side has the same probability of appearing when you roll the dice, i.e., in the long run each number will appear 1/6 of the times. We have three different odd numbers in a normal dice each will appear 1/6 of the times in the long run. Therefore, in the long run we hope to get 3/6 = 1/2 of the times an odd number and rolling the dice 120 times will produce about 120(1/2) = 60 odd numbers.

What is the solution to the following system of equations? X-2y=2, x-2y=-2

Answers

x + 2y = 2
x - 2y = -2
-------------add
2x = 0
x = 0

x + 2y = 2
0 + 2y = 2
2y = 2
y = 2/2
y = 1

solution is (0,1)
Final answer:

The given system of equations, x - 2y = 2 and x - 2y = -2, are parallel lines and do not intersect, thus there is no common solution to the system.

Explanation:

In mathematics, to find the solution to a system of equations, we generally try to find the values of variables that satisfy all the equations in the system. When looking at the given equations: x - 2y = 2 and x - 2y = -2, we can see that there is something strange. These two equations are equivalent to each other, meaning they represent the same line. This is due to the fact that both equations have the same coefficients for the x and y variables (1 and -2 respectively). So, if two lines are equivalent, they are essentially the same line. This means there are infinitely many solutions which satisfy this system of equations, since all points on the line satisfy both equations. However, if two lines have the same coefficients but different constants (the numbers without the variables), as in our case, then they are parallel and do not intersect, indicating that there's no solution for the system of equations. Therefore, this system of equations has no solution.

Learn more about System of Equations here:

https://brainly.com/question/35467992

#SPJ2

The proof that ΔQPT ≅ ΔQRT is shown. Given: SP ≅ SR Prove: ΔQPT ≅ ΔQRT What is the missing reason in the proof? Statements Reasons 1. SP ≅ SR 1. given 2. ST ⊥ PR 2. converse of the perpendicular bisector theorem 3. PT ≅ RT 3. ? 4. QT ⊥ PR 4. ST and QT name the same line. 5. QP ≅ QR 5. perpendicular bisector theorem 6. ΔQPT ≅ ΔQRT 6. HL theorem definition of perpendicular bisector definition of congruence reflexive property substitution property

Answers

Answer:

A. definition of perpendicular bisector

Step-by-step explanation:

I JUST TOOK THE TEST!!!!!!

Answer:

The correct option is a) perpendicular bisector definition.

Step-by-step explanation:

Given :

Triangle QPT is similar to triangle QRT.

[tex]\rm SP \cong SR[/tex]

To find : Why [tex]\rm PT \cong RT[/tex]

Solution :

According to perpendicular bisector definition -

Perpendicular Bisector is a line or a segment perpendicular to a segment that passes through the midpoint of the segment. Any point on the perpendicular bisector is equidistant from the endpoints of the line segment.

Therefore, [tex]\rm PT \cong RT[/tex]

Hence option a) is correct.

For more information, refer the link given below

https://brainly.com/question/24753075?referrer=searchResults

What number must you add to complete the square x^2+12x=-5
A 12
B 36
C 144
D 6

Answers

The general form of a quadratic equation is,

                         Ax² + Bx + C = 0

A, B, and C are all numerical coefficients of the terms in the equation. 

In order to complete the square, we divide all numerical coefficients by 2 and A. Then, square the value of B/2A. Performing this operation for this item,

                         n = (B/2A)²

Substituting the known values,

                         n = (12/2(1))² = 36

Thus, the missing number in this item is 36 and the final expression becomes,

                    x² + 12x + 36 = -5 + 36

Answer: B. 36

Step-by-step explanation: Trust me!

How many permutations are possible for 11 objects taken 7 at a time?

Answers

There are 330 combinations and 1,663,200 individual permutations.
11P7   =   11!           11*10*9*8*7*6*5*4*3*2*1
              --------  =   ------------------------------------  =    1,663,200
              (11-7)!                   4*3*2*1

BC is tangent to circle A at B and to circle D at C. What is AD to the nearest tenth? Look at image attached.

Answers

A tangent line to a circle is perpendicular to the radius drawn to the tangent point   ⇒
AB ⊥ BC and CD ⊥ BC  ⇒ ABCD is a right trapezoid. 

You can find the AD using formula:

[tex]AD= \sqrt{BC^2+(AB-CD)^2} \\ \\ AD= \sqrt{19^2+(10-7)^2} = \sqrt{361+9}= \sqrt{370} \approx 19.2[/tex]

Answer:

1. 19.2

Step-by-step explanation:    

Please find the attachment.

Since we know that radius is perpendicular to tangent of a circle. So AB will be perpendicular to BC at c and DC is perpendicular to CB at C.

Now we will construct a perpendicular line to radius AB at point E from the center of our small circle. Since we have two right angles at point B and C so we will also have right angles at point E and D as well.    

Length of CD is is 7 so length of BE will be 7 as well and length of EA will be 10-7=3. Length of DE will be equal to length BC that is 19.

Now we have formed a right triangle and now we will use Pythagoras theorem to find the length of AD.  

[tex](AD)^{2}=(DE)^{2}+(EA)^{2}[/tex]    

Upon substituting our values in above formula we will get,

[tex](AD)^{2}=(19)^{2}+(3)^{2}[/tex]

[tex](AD)^{2}=361+9[/tex]

[tex](AD)^{2}=370[/tex]

Upon taking square root of both sides of our equation we will get,

[tex]AD=\sqrt{370}[/tex]  

[tex]AD=19.2353840616713448\approx 19.2[/tex]

Therefore, the length of AD will be 19.2 and 1st option is the correct choice.

When students have a perfect math test score, the teacher gives them 5 fake dollars to spend in the class store. If one student already has 25 fake dollars and 4 perfect math test scores, how many total fake dollars does the student have to spend?

Answers

Answer:

45 Fake Dollars

Step-by-step explanation:

4x5=20

d=20+25

d=45 Fake Dollars

Answer:

45

Step-by-step explanation:

explain why the diagram displqyed on the right cannot represents a real object

Answers

Notice how the frontmost corner is the only corner stacked. Then, notice how the shape comes together without bending at all. This is impossible because the only way this could be a real shape is if the two angles on the left and right bend upward. Because this doesn't happen, the shape is impossible

What is the solution to the system that is created by the equation y=-x+6 and the graph shown below?

Answers

the graph graphed is y=1/2x

so
y=1/2x and y=-x+6
y=y so
1/2x=-x+6
times 2 both sides
x=-2x+12
add 2x both sides
3x=12
x=4

sub back
y=1/2x
y=1/2(4)
y=2

(4,2) is the solution
1st let/s find the equation of the graph shown. It has te form of y₁ =mx since it oases by the origin. Moreover we notice that the slope m = rise/run = 1/2. hence the equation IS y₁ = (1/2)x.
To find the solution of y₁ = 1/2 x and y= -x + 6, let's y=y₁

-x + 6 = 1/2 x ↔ -2x +12 = x ↔ -3x= -12  and x = 4. For x = 4 , y =2.

And the solution is the intersection point between y and y₁ which is nothing but the solution or te coordinate of this point that is (4,2)

Use the information about the bakery to explain how a manager can use a system of equations to plan employee time. Include a demonstration of how to solve the system of equations given in the problem and an explanation of how a restaurant manager would schedule oven and employee time.

Answers

Good Morning. okay?  To solve this problem is very simple, it is only using a system.

20c + 10b = 800
10c + 30b = 900

Multiply the second equation by -2.

20c + 10b = 800
-20c - 60b = -1800

Now it is only to add the two equations.

0 - 50b = -1000
b = -1000/-50
b = 20

Now that we have discovered the 'b' we will substitue in the equation.

10c + 30 . 20 = 900
10c + 600 = 900
10c = 300
c = 300/10
c = 30

b=20    c=30

ok? thanks, i hope i have helped.

Pablo plans to both run and swim. let r be the number of laps he runs and let s be the number of laps he swims. each lap he runs takes him 5 minutes, and each lap he swims takes him 2 minutes. he wants to exercise for at least 45 minutes today write an inequality

Answers

5r=time he runs
2s=time he swims

total must be at least 45

5r+2s≥45

The box plot shows the number of years during which 24 colleges have participated in a local college fair

At least how many schools have participated for 2 years or fewer?

A.2 kids

B.4 kids

C.6 kids

D.7 kid

Answers

The boxplot provides the following information:
Minimum = 0
First quartile = 2
Median = 4
Third quartile = 7
Maximum = 9

The sum is 2+4+7+9 = 22
The unaccounted for participants is 24 - 22 = 2 (outliers).
Those who participated for 2 years or less is 2.

Answer: A. 2 kids
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