the largest negative number would be the coldest, so -14 would be the coldest.
Chicago is the coldest city
whats the answer to z−4/9−1/3=5/9
A company’s profits (P) are related to increases in a worker’s average pay (x) by a linear equation. If the company’s profits drop by $1,500 per month for every increase of $450 per year in the worker’s average pay, what is the slope of the graph of the equation?
which of these numbers are square numbers 25 36 48
Need help on my math homework
200 +6m = 500-6m
add 6m to each side
200+12m = 500
subtract 200 from each side
12m = 300
divide both sides by 12
m = 300/12 = 25
25 minutes
check:
200+ 25*6 = 200 +150 = 350
500 - 25*6 = 500-150 = 350
Write 0.12*10-3 as a decimal
what is 15%, 0.015, and 1/5 from least to greatest
Approximate the square root of 18 to the nearest tenth and plot the number on a number line SHOW ALL WORK
Please explain how to do this
What is 23.66 times 2.03
What's 755,082 rounded to the nearest 10,000
Would you be more or less likely to take a job in which the type of work is enjoyable to you? Why?
Answer:
yes if i enjoy the job i would not give it up
Step-by-step explanation:
(1, -1) parallel to y= 2/5x-3
What is the midpoint of AB if A = (−2, 2) and B = (3, −1)? Enter your answer in the boxes below.
Answer:
[tex](\frac{1}{2}, \frac{1}{2})[/tex]
Step-by-step explanation:
Since, the coordinates of the midpoint of a line segment having the endpoints [tex](x_1,y_1)[/tex] and [tex](x_2, y_2)[/tex] are,
[tex](\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})[/tex]
Here,
[tex]x_1=-2, y_1=2, x_2 = 3, y_2=-1[/tex]
Hence, the coordinates of the midpoint of segment AB are,
[tex](\frac{-2+3}{2},\frac{2-1}{2})[/tex]
[tex](\frac{1}{2}, \frac{1}{2})[/tex]
Okay So I just a question that I don't even know what it means, So if someone could help that would be awesome!
see attached picture for solution:
the table shows amounts earned for washing dogs. how much can be earned by washing 8 dogs
dogs,x. dollars,y
1. 18
2. 36
3. 54
4. 72
a.) $144
b.)$324
c.)$64
d.)$126
How do you turn -13 into an improper fraction
52 thousandths in scientific notation
Help me plz math (picture)
Daniel Plays Videogames for 2/3 (Fraction) of an hour every night before dinner. hos many hours if videogames does he play altogether after 5 days.
-2/3×1/2×-6/7=
please help
use distributive property to find the product of (m+3)(m+7)
Answer:
m² + 10m + 21
Step-by-step explanation:
(m + 3)(m + 7)
m(m + 7) + 3(m + 7)
m² + 7m + 3m + 21
m² + 10m + 21
38 points!
Please do #11 and #12
In return:
Brainliest
Special Thanks
5^2-11 over 6(3). Evaluate the expression. A. 7. B. 2/9. C.-1/63. D. 7/9
What is the value of y in the equation 3(3y – 12) = 0? (5 points)
4
5
6
9
4.
How many solutions does the equation 5p – 4p – 8 = –2 + 3 have? (5 points)
One
Two
None
Infinitely many
What is 2.085×106 in standard form?
208,500
285,000
2,085,000
2,850,000
2.085 x 10^6 =
move the decimal 6 places to the right: 2,085,000
The following table shows the data collected from a random sample of 100 middle school students on the number of hours they do household chores every week
There are 1,500 students in the school. Based on the sample proportion, how many students in the school would be expected to do household chores for at least two hours every week?
A: 480 B: 960 C: 1,020 D: 1,440
There will be 1020 students in the school doing household chores for at least two hours every week.
What is a ratio?A ratio is a comparison of two attributes of a similar kind.
Based on the random sample, the number of students doing household chores for at least two hours every week =64+3+1 =68
Out of 100, the number of students doing household chores for at least two hours every week = 68
So, out of 1, the number of students doing household chores for at least two hours every week = 68/100
So, out of 1500, the number of students doing household chores for at least two hours every week = (68/100)*1500 =1020
Thus, there will be 1020 students in the school doing household chores for at least two hours every week.
To get more about ratios visit:
https://brainly.com/question/2328454
Maryann is testing the effectiveness of a new acne medication. There are 100 people with acne in the study. Fifty-five patients received the acne medication, and 45 other patients did not receive treatment. Thirty of the patients who received the medication reported clearer skin at the end of the study. Twenty-two of the patients who did not receive medication reported clearer skin at the end of the study. What is the probability that a patient chosen at random from this study took the medication, given that they reported clearer skin?
Answer: 58 %
Step-by-step explanation:
Let M represents the event of taking medicine, M' represents the event of not taking medicine and C represents the event of clearing skin,
Thus, according to the question,
n(M) = 55,
n(M') = 45,
n(M∩C) = 30,
n(M'∩C)= 22,
⇒ n(C) = n(M∩C) + n(M'∩C) = 30 + 22 = 52
Let S shows the total number of people,
⇒ n(S) = 100
Hence, the probability of cleared skin,
[tex]P(C)=\frac{n(C)}{n(S)}=\frac{52}{100}=0.52[/tex]
And, the probability of cleared skin of that people who took the medicines,
[tex]P(M\cap C)=\frac{n(M\cap C)}{n(S)}=\frac{30}{100}=0.3[/tex]
Thus, the probability that a patient chosen at random from this study took the medication, given that they reported clearer skin,
[tex]P(\frac{M}{C})=\frac{P(M\cap C)}{n(C)}=\frac{0.3}{0.52}=0.57692307692\approx 0.58 = 58\%[/tex]
Answer: 0.58
Step-by-step explanation:
Let A = Event that the patients received the acne medication.
B = Event that the patients did not receive the acne medication.
C = Patient reported reported clearer skin.
Now,
[tex]P(A)=\dfrac{55}{100}=0.55\ \ ,P(B)=\dfrac{45}{100}=0.45[/tex]
[tex]P(C|A)=\dfrac{30}{55}\ \ , P(C|B)=\dfrac{22}{45}[/tex]
Using Bayes theorem, The probability that a patient chosen at random from this study took the medication, given that they reported clearer skin:
[tex]P(A|C)=\dfrac{P(A)\cdot P(C|A)}{P(A)\cdot P(C|A)+P(B)\cdot P(C|B)}\\\\=\dfrac{0.55\cdot\dfrac{30}{55}}{0.55\cdot\dfrac{30}{55}+0.45\cdot\dfrac{22}{45}}=0.576923076923\approx0.58[/tex]
Hence, the required probability : 0.58
The greatest common factor of a number n and 6 is 3. What are all of he possible whole-number values for n?
Answer: Odd multiple of 3.
[tex]3,\ 9,\ 15,\ 21, \ 27, \ 33, \ 39,\ 45,...........[/tex]
Step-by-step explanation:
Given : The greatest common factor of a number n and 6 is 3.
Then, it is clear that n should be a multiple of 3.
Prime factorization of 6 :
[tex]6=2\times3[/tex]
So for n a even number then the greatest common factor will be 6.
Thus , the possible choice for n is a odd multiple of 3.
Hence, the possible whole-number values for n are :
[tex]3,\ 9,\ 15,\ 21, \ 27, \ 33, \ 39,\ 45,...........[/tex]
Solve for b.
d = 3a + 3b
A)b=d−3a
B)b=d−3a/3
C)b=3a−d/3
D)b=d−3a/a
Alex spend 3/4 of his money. He gave 1/4 of the remainder to his sister. He had $120 left. How much did have in the beginning?