In a suvey of 100 out-patients who reported at a hospital one day it was find out that 70 complained of fever, 50 complained of stomachs and 30 were injured. All 100 patients had at least one of the complains. How many patients had all three complains?

Answers

Answer 1

Final answer:

To find the number of patients who had all three complaints (fever, stomach issues, and injury), we can use a Venn diagram. From the given information, we determine that 30 patients had all three complaints.

Explanation:

To find the number of patients who had all three complaints, we can use a Venn diagram. Let's start with the information given:

Total number of patients = 100Number of patients who complained of fever = 70Number of patients who complained of stomach issues = 50Number of patients who were injured = 30All 100 patients had at least one complaint

To determine the number of patients who had all three complaints, we need to find the overlapping region in the Venn diagram. From the given information, we can determine the following:

The number of patients who complained of fever and stomach issues = 100 - 30 (injured patients) = 70The number of patients who complained of fever and were injured = 70 - 50 (patients with stomach issues) = 20The number of patients who complained of stomach issues and were injured = 50 - 20 (patients with both fever and injury) = 30The number of patients who had all three complaints = 30 (those who complained of stomach issues and were injured)

Therefore, the number of patients who had all three complaints is 30.

Answer 2

Final answer:

To find out how many patients had all three complaints of fever, stomach pain, and injury, we used the principle of inclusion-exclusion and found that 25 patients had all three complaints.

Explanation:

To determine how many patients had all three complaints (fever, stomach pain, and injury) at the hospital, we can use the principle of inclusion-exclusion from combinatorics.

First, we add the number of people with each complaint:

People with fever: 70

People with stomach pain: 50

People with injury: 30

According to the inclusion-exclusion principle:

Total with all complaints = (People with fever) + (People with stomach pain) + (People with injury) - (People with fever and stomach pain) - (People with fever and injury) - (People with stomach pain and injury) + (People with all three complaints)

Since all 100 patients had at least one complaint, and assuming the least number of people with multiple complaints, we minimize the terms (People with fever and stomach pain), (People with fever and injury), and (People with stomach pain and injury). The minimum number for all these combined categories is the sum of individual complaints minus the total number of patients, which is (70 + 50 + 30) - 100 = 50.

Therefore, if there were no people with all three complaints, the total with any two complaints would be 50. However, this number includes people with all three complaints three times (once for each pair of complaints). To correct this, we subtract twice the number of people with all three complaints to get the true number of people with exactly two complaints:

50 - 2*(People with all three complaints) = Total with exactly two complaints

If there are no people with exactly two complaints, then this means that all 50 are those with all three complaints:

50 - 2*(People with all three complaints) = 0

Solving for (People with all three complaints), we get:

(People with all three complaints) = 50 / 2

(People with all three complaints) = 25

This result suggests that 25 patients had all three complaints of fever, stomach pain, and injury.


Related Questions

The square root of 150 is between

A.10 and 11
B.11 and 12
C.12 and 13
D.13 and 14

Answers

The square of 12 is 144 and the square of 13 is 169. Since 150 is in between those, it is C.

Hope this helps!

Find the height of a door on a scale drawing if the door is 2 meters tall and the scale is 1 centimeter = 4 meters. Round to the nearest tenth.

Answers

1 cm in the drawing = 4 meters real measure
Since you want the drawing measure for a real 2 m, and 2 m is half of 4 m, then the drawing measure is 0.5 cm

If 1 cm = 4 m, then
0.5 cm = 2 m

Answer: 0.5 cm

The height of the door in the drawing will be 1/2 centimeters.

What is scale factor?

Scale factor is used to compare the size of two objects. Mathematically, we can write -

{K} = S{O1}/S{O2}

13 mg

Given is that the height of a door on a scale drawing if the door is 2 meters tall and the scale is 1 centimeter = 4 meters.

Height of the door = 2 meters

Scale :  1 centimeter = 4 meters.

So, in one meters, there will be - 1/4 centimeters.

In 2 meters, there will be -

(1/4) x 2 = 1/2 centimeters

Therefore, the height of the door in the drawing will be 1/2 centimeters.

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You deposit $5000 each year into an account earning 8% interest compounded annually. How much will you have in the account in 20 years?

Answers

is this using A=P(1+r)^t or A=Pe^rt

if the raidus of mars(3,397 km) is about 13.7% of of neptunes radius, what is the radius of neptune?

Answers

this is the answer check it out

You swim the 50-meter freestyle in 28.12 seconds.This is 0.14 second less than your previous fastest time. What was your previous fastest time?

Answers

if your fastest time was 0.14 seconds more before today then you previous fastest time would be 28.26

If a person swim the 50-meter freestyle in 28.12 seconds. This is 0.14 second less than persons previous fastest time is 28.26.

What is Equation?

Two or more expressions with an equal sign is called as equation.

Given that,

One swim the 50-meter freestyle in 28.12 seconds..

The previous fastest time be x.

The new fastest time is 28.12 seconds.

New fastest time is 0.14 second less than your previous fastest time.

So, 28.12+0.14=x

28.26=x

Hence the previous fastest time is 28.26 seconds.

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What is the end behavior of f(x)=5x^3-2x+5

Answers

f ( x) = 5x^3 - 2x + 5

y = 5x ^3 - 2x + 5

LEFT END = RISING &  RIGHT END = RISING 
f(x)  = 5x³-2x+5

The end behavior of a polynomial is the behavior of the graph when:
x→ + ∞  and x → - ∞

when x → + ∞, f(x) → +∞

and when x → - ∞ , f(x) → - ∞

You follow the sign of the greatest exponent , that is 3 (on 5x³)

solve for first two positive solutions sin(3x)cos (4x)+cos(3x)sin(4x)=-0.9

Answers

sin(3x)cos (4x)+cos(3x)sin(4x)=-0.9
Then sin(3x+4x) = 0.9
sin(7x) = 0,9
Arcsin(,9) = 64.158 degrees or 115.842
x = 9.165 and 16.549

At what projection angle will the range of a projectile equal to 6 times its maximum height?

Answers

i not sure but it might be 60 kilogrames
The formula for maximum height is:

H = v²sin²θ/2g

The formula for range is:

R = v²sin(2θ)/g

The relationship between the two is written as:
R = 6H
v²sin(2θ)/g = 6(v²sin²θ/2g)
v²sin(2θ)/g = 3v²sin²θ/g)
Cancelling out like terms,
sin(2θ) = 3sin²θ
Solving for θ using a scientific calculator,
θ = 33.7°

A card is randomly selected from a deck of 52 cards. Find the probability that the card is between four and eight (inclusive) or is a club.

Answers

Answer:

20/52+13/52-5/52=.538

Step-by-step explanation:

The probability that the card is between four and eight (inclusive) or is a club is 4/13.

What is Probability?

Probability helps us to know the chances of an event occurring.

[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

The number of cards can be written as,

The number of cards between 4 and 8 is 3 {4,5,6,7,8}.Number of club cards = 13Number of cards between 4 and 8 from heart, spades, and diamonds = 15

Now, the probability that the card is between four and eight (inclusive) or is a club is,

Probability

= (Number of club cards+ Number of cards between 4 and 8)/(Total number of cards)

= (13+15)/(52)

= 28/52

= 4/13

Hence, the probability that the card is between four and eight (inclusive) or is a club is 4/13.

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Find the mean median mode and range of this date 49,49,54,55,52,49,55, if necessary round to the nearest tenth

Answers

The numbers from least to greatest is (49, 49, 49, 52, 54, 55, 55) The mean is 51.8 (52 rounded), 52 is median, mode is 49, and the range is 6. :) 

identify the type of of function represented by the equation y=2x^2

Answers

I think it is a parabola
I believe this is a quadratic function.

What is the effect of decreasing the alpha level (for example, from a = .05 to a = .01)? it decreases the probability of a type i error. it decreases the size of the critical region. it decreases the probability that the sample will fall into the critical region. all of the other options are results of decreasing alpha?

Answers

The effect of decreasing the alpha level from 0.05 to 0.01. it decreases the probability that the sample will fall into the critical region, it decreases the probability of a Type I error, and it decreases the size of the critical region.
Therefore, the answer is that all of other options are results of decreasing alpha.

If a gambler rolls two dice and gets a sum of 10, he wins $10, and if he gets a sum of three, he wins $20. the cost to play the game is $5. what is the expectation of this game?
a. $3.06
b. -$2.78
c. -$3.06
d. $2.78

Answers

Chance to win $10 is 3/36 Chance to win $20 is 2/36 Chance to lose is 31/36 So if cost of play is $5: ((3*5) + (2*15) - (5*31))/36 = -3.06 C. $-3.06

Final answer:

The expected value of the gambling game with a cost of $5, and potential winnings of $10 for a sum of 10 or $20 for a sum 3, is −$2.78. The calculation shows the player will lose $2.78 on average per game, indicating it is not a profitable game to play long term. So, option (b) is correct.

Explanation:

The student is interested in determining the expected value of a gambling game where rolling two dice can result in either winning money or losing the cost to play. To find the expected value, we must consider the probability of each outcome and its associated payoff.

First, we calculate the chances of rolling a sum of 10 with two dice. There are three combinations that give a sum of 10: (4,6), (5,5), and (6,4). Since there are 36 possible outcomes when rolling two dice, the probability of obtaining a sum of 10 is 3/36 or 1/12.

Similarly, the only combinations that result in a sum of 3 are (1,2) and (2,1). Thus, the probability of rolling a sum of 3 is 2/36 or 1/18.

The expected value (EV) can be calculated using the formula:

EV = (−cost to play) + [P(sum of 10) × winnings for 10] + [P(sum of 3) × winnings for 3]

Substituting the given values yields:

EV = (−5) + [(1/12) × 10] + [(1/18) × 20]

After calculating, we find tha-

EV = −$2.78.

Since the expected value is negative, this implies that, on average, the player will lose $2.78 per game. Therefore, playing this game would result in an average loss over time.

which of the following was a result of prison reform during the 1800s
A. a decrease in prisons
B. a decrease in crime
C. the formation of mental hospitals
D. the formation of public schools in rural areas

Answers

Which of the following was a result of prison reform during the 1800s
A. a decrease in prisons 

Answer:

C. the formation of mental hospitals

Step-by-step explanation:

During that time the jail and asylum conditions were worse.

The inmates especially the mentally ill, were bound in chains and locked in cages.

Hence, with the reform movement, came the formation of mental hospitals. Public asylums were made for the mentally ill incarcerated people.

The 2015 senior class from puma high school raised funds for an end of the year party at club sizzle. It costs $4,000 to rent out club sizzle plus $20 per student for food and drinks. If the senior class raised 11,000, how many students can attend the end of year party ? Write an equation for the situation and solve.

Answers

4000+20x=11000
20x=11000-4000
20x=7000
20/20x=7000/20
x=350 $tudents.

Which number is 100 times greater than 6 thousandths

Answers

 6 thousandths = .006 so times that by 100
.006 * 100 = .6

Every night, Mary spends 3 hours doing homework, 30 minutes practicing the piano, and 35 minutes talking on the phone. What is the total number of minutes Mary spends doing these activities?

Answers

four hours and five minutes

Raj eats 1/11 of a pound of grapes in 1/25 of a minute. How many minutes will it take him to eat a full pound of grapes?

Answers

[tex]\bf \begin{array}{ccll} \stackrel{lbs}{grapes}&minutes\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \frac{1}{11}&\frac{1}{25}\\\\ 1&m \end{array}\implies \cfrac{\frac{1}{11}}{1}=\cfrac{\frac{1}{25}}{m}\implies \cfrac{\frac{1}{11}}{\frac{1}{1}}=\cfrac{\frac{1}{25}}{\frac{m}{1}} \\\\\\ \cfrac{1}{11}\cdot \cfrac{1}{1}=\cfrac{1}{25}\cdot \cfrac{1}{m}\implies \cfrac{1}{11}=\cfrac{1}{25m}\implies 25m=11\implies m=\cfrac{11}{25}[/tex]

find the equation to the line that is perpendicular to y=2x-3 and goes through the point (-1,2)

Answers

first off, let's see this equation     [tex]\bf y=\stackrel{slope}{2}x-3[/tex]

so, notice, since it's already in slope-intercept form, we know the slope is just 2.

a line that is perpendicular to it, will have a negative reciprocal slope to it, let's check.

[tex]\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad 2\implies \cfrac{2}{1}\\\\ slope=\cfrac{2}{{{ 1}}}\qquad negative\implies -\cfrac{2}{{{ 1}}}\qquad reciprocal\implies - \cfrac{{{ 1}}}{2}[/tex]

so, what is the equation of a line whose slope is -1/2 and goes through -1,2?

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -1}}\quad ,&{{ 2}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies -\cfrac{1}{2} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-2=-\cfrac{1}{2}[x-(-1)] \\\\\\ y-2=-\cfrac{1}{2}(x+1)\implies y-2=-\cfrac{1}{2}x-\cfrac{1}{2}\implies y=-\cfrac{1}{2}x-\cfrac{1}{2}+2 \\\\\\ y=-\cfrac{1}{2}x+\cfrac{3}{2}[/tex]

There are three highways in the county. the number of daily accidents that occur on these highways are poisson random variables with respective parameters .3, .5, and .7. find the expected number of accidents that will happen on any of these highways today.

Answers

There is a theorem that we can use to find the expected value of a random variable that is a sum of other random variables as follows.

If [tex]X=X_1 + X_2 + ...+X_k[/tex], then [tex]E(X)=E(X_1)+E(X_2)+...+E(X_k)[/tex].

In this case, let X = the number of accidents that will happen on any of those highways today,
[tex]X_1,X_2,X_3[/tex] are the numbers of accidents on each highway, respectively.

Then  [tex]X = X_1+X_2+X_3[/tex].

Since [tex]X_1,X_2,X_3[/tex] are Poisson variates, their expected values are the parameters given, .3, .5 and .7.

So [tex]E(X_1)=.3, E(X_2) = .5, E(X_3) = .7[/tex]
Thus, [tex]E(X)=E(X_1)+E(X_2)+E(X_3) = .3 + .5 + .7 = 1.5[/tex]

The answer is 1.5.

Final answer:

To find the expected number of accidents on three highways with Poisson distributions, sum the individual expectations: 0.3, 0.5, and 0.7, resulting in an expected 1.5 accidents per day.

Explanation:

The student asked how to find the expected number of accidents that will happen on any of the three highways in a day, given that the number of daily accidents on these highways are Poisson random variables with parameters 0.3, 0.5, and 0.7 respectively. To solve this, we shall sum the parameters of the Poisson distributions because the expectation of the sum of independent random variables is the sum of their expectations.

Therefore, we calculate the expected number of accidents as follows:

For the first highway with parameter 0.3, the expected number of accidents is 0.3.

For the second highway with parameter 0.5, the expected number of accidents is 0.5.

For the third highway with parameter 0.7, the expected number of accidents is 0.7.

Adding these together, we get:

Expected number = 0.3 + 0.5 + 0.7 = 1.5 accidents per day.

Alyssa is building a brick mailbox. She is going to stack bricks that are each \dfrac23 \text{ft}
​3

​2
​​ ftstart fraction, 2, divided by, 3, end fraction, f, t tall, and the finished stack of bricks needs to be 4\dfrac23 \text{ft}4
​3

​2
​​ ft4, start fraction, 2, divided by, 3, end fraction, f, t tall.
How many bricks will go in the stack?

Answers

Given that each of the brick is [tex]\frac{2}{3}[/tex] ft tall and the finished stack of bricks is [tex]4\frac{2}{3}[/tex] ft tall.

Let the number of bricks in the stack be x, then

[tex] \frac{2}{3} x=4 \frac{2}{3} = \frac{14}{3} \\ \\ \Rightarrow x= \frac{ \frac{14}{3} }{ \frac{2}{3} } = \frac{14}{3} \times \frac{3}{2} \\ \\ = \frac{14}{2} =7[/tex]

Therefore, 7 bricks will go in the stack.

Find the percent of tip: Cost of meal: $28.00 Tip: $3.36 The percent of the tip was ___%.

Answers

12% because 28.00 divided by 3.36

Answer:

12.00%

Step-by-step explanation:

[tex]$3.36\\[/tex] ÷ [tex]$28.00\\[/tex] = [tex]0.12\\[/tex]

[tex]100 *0.12=12%\\[/tex] %

248mph equals how many meters per second

Answers

keeping in mind there are 1.609 kilometers in 1 mile, and 1000 meters in 1 kilometer, and 60 minutes in an hour and 60 seconds in a minute, therefore 60*60 seconds in an hour, or 3600 seconds, then

[tex]\bf \cfrac{248~\underline{mile}}{\underline{hr}}\cdot \cfrac{1.609~\underline{km}}{\underline{mile}}\cdot \cfrac{1000~m}{\underline{km}}\cdot \cfrac{\underline{hr}}{3600~sec}\implies \cfrac{248\cdot 1.609\cdot 1000~m}{3600~sec} \\\\\\ \cfrac{399032~m}{3600~sec}\approx 110.84\frac{m}{sec}[/tex]

A customer has six (6) $1 bills, three (3) $5 bills, four (4) $10 bills, seven (7) quarters, ten (10) dimes, seven (7) nickels, and nine (9) pennies. The customer buys a pair of shoes for $49.86. Based on the combination of bills and coins the customer has, what are the least number of bills and coins the customer can give the cashier in order to buy the shoes for the exact amount and not require any change back?

Answers

4 $10
1 $5
4 $1
3 $.25
1 $.10
1 $.01
4 tens 1 five 4 ones 3 quarters 1 dime and one penny

The Lombardo family went out to dinner and their full mean costed $62. If they left a 20% tip, how much did they tip?

Answers

their total would be $74.40 :)

Can someone please help?

Answers

3(b-4)+5b=44
distribute
3b-12+5b=44
combine number with numbers and variables with variables
8b=56
decide by 8 on both sides
b=7
We need to solve the equation: 
3(b-4)+5b=44
There is only one unknown in the equation. The unknown is b. 
We must isolate the unknown b on one side of the equation.
According the law of multiplication we can write the following:
3b-3*4+5b=44
3b-12+5b=44
(3b+5b)-12=44
8b-12=44

We shift a number from one side of an equation 
to the other by writing it on the other side with the inverse operation,so we obtain:
8b=44+12
8b=56
b=56/8
b=7

An observer (O) spots a plane flying at a 35° angle to his horizontal line of sight. If the plane is flying at an altitude of 17,000 ft., what is the distance (x) from the plane (P) to the observer (O)?
20,757 feet
24,251 feet
29,639 feet
31,262 feet

Answers

Answer:

here are numerous information's already given in the question. Based on those information's, the answer to the question can be easily deduced.

Angle at which the plane is flying in respect to the observer = 35 degree

Altitude at which the plane is flying = 17000 feet

The distance at which the plane is flying from the observer = x 

Then

x = 17000/sin 35

 = 17000/0.57357

 = 29638.93 feet

 = 29639 feet

From the above deduction, we can conclude that the correct option among all the options given in the question is the third option.

 

GIVE BRainliest plz

The distance between the plane and the observer is 29,638 feet.

Data;

Angle = 35 degreesheight of the plane = 17,000ftdistance from the plane to the observer = x

Trigonometric Ratio

This is the use of SOHCAHTOA which is the relationship between sides of a right angle triangle and it's angle.

In this case, we have the value of opposite and angle and we need to find the hypothenuse.

Using sine of the angle,

[tex]sin\theta = \frac{opposite}{hypothenuse} \\sin 35 = \frac{17000}{x}\\ x = \frac{17000}{sin35}\\ x = 29,638 feet[/tex]

The distance between the plane and the observer is 29,638 feet.

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ANSWER FAST
Marshall bought some pet supplies for $15. The sales tax was 6%. He wrote the expression 1.06(15) to find his total cost.

Which equivalent expression could he also use to find the total cost?

A. 15+0.6(15)
B. (1+0.06)15
C. 1+0.06(15)
D.15 + 0.06









Answers

A. 15+0.6(15)
You posted this question twice, hah.
Do you need work to show it?

A pooled proportion is calculated by giving each sample proportion an equal weight.
a. True
b. False

Answers

the answer is B False

Tasha earns $400 per week plus a commission of 10% on her weekly sales. Each week she saves of her earnings. In the expression , what does the expression 400 + 0.1s represent in this situation?

Answers

Final answer:

In this situation, the expression 400 + 0.1s represents Tasha's total earnings for the week, including her base salary and commission.

Explanation:

In this situation, the expression 400 + 0.1s represents Tasha's total earnings for the week. The $400 represents her base salary, and the 0.1s represents the commission she earns on her sales. The value of s represents Tasha's total sales for the week.

For example, if Tasha's total sales for the week are $2000, then her commission would be 0.1($2000) = $200. Adding this to her base salary of $400, her total earnings for the week would be $400 + $200 = $600.

Therefore, the expression 400 + 0.1s represents Tasha's total earnings for the week, including her base salary and commission.

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