If two ends A and B are connected through a metallic wire. If electrons flows from point B to point A. What can you say about the potential A and B.

For this case we have by definition, that the Ampere, is the unit of electric current intensity.

For its part, the electric current is a measure of the velocity at which the electric charge flows.

The symbol of the current is A. We have that 1 Ampere is equivalent to an electric charge of a coulomb per second.

[tex]1A = \frac {1C} {s}[/tex]

Answer:

[tex]1A = \frac {1C} {s}[/tex]

The acceleration which is gained by an object because of gravitational force is called its acceleration due to gravity. Its SI unit is m/s2. Acceleration due to gravity is a vector, which means it has both a magnitude and a direction. The acceleration due to gravity at the surface of Earth is represented by the letter g. It has a standard value defined as 9.80665 m/s2.[ However, the actual acceleration of a body in free fall varies with location. (Wikipedia)

The acceleration due to gravity is  9.89 m / s2.

Explanation:

Gravity was discovered by Newton when he was sitting under a tree and was watching an apple reaching the ground instead of going upwards. He fond that there is a gravitational pull attached to the ground of the earth which makes all the objects towards the ground. It is represented by 'g' and its value is equal to 9.8 m /s2.

Due to electric current a magnetic field is generated. So when a compass is placed next to an electric field, it shows deviations.

The compass shows the direction of the North. Therefore the direction of the magnetic field can be found. This is found using the right hand rule.

Answer:

55.3 N, 223.3 N

Explanation:

First of all, we can find the angle of the inclined plane.

We have:

L = 5 m the length of the incline

h = 1.2 m is the height

We also have the relationship

[tex]h = L sin \theta[/tex]

where [tex]\theta[/tex] is the angle of the incline. Solving for the angle,

[tex]\theta= sin^{-1} (\frac{h}{L})=sin^{-1} (\frac{1.2 m}{5 m})=13.9^{\circ}[/tex]

Now we can find the components of the weight of the box, which is the force that the box exerts on the plank. Calling W = 230 N the weight of the box, we have:

- Component parallel to the incline:

[tex]W_{par} = W sin \theta = (230 N)(sin 13.9^{\circ}) =55.3 N[/tex]

- Component perpendicular to the incline:

[tex]W_{per} = W cos \theta = (230 N)(cos 13.9^{\circ}) =223.3 N[/tex]

Explanation:

Given:

v₀ = 15 m/s

a = 3.5 m/s²

t = 5.0 s

Find: v

v = at + v₀

v = (3.5 m/s²) (5.0 s) + 15 m/s

v = 32.5 m/s

The final velocity of the car, after accelerating at a rate of 3.5 m/s^2 for 5 seconds from an initial velocity of 15 m/s, is 32.5 m/s.

The car's final velocity can be calculated using the formula for acceleration: final velocity = initial velocity + (acceleration x time). Here, the initial velocity is 15 m/s, the acceleration is 3.5 m/s^2, and the time is 5.0 seconds.

Substituting these values in the formula gives: final velocity = 15 m/s + (3.5 m/s^2 x 5.0 seconds) = 15 m/s + 17.5 m/s = 32.5 m/s. So, the car's velocity after 5 seconds of accelerating at a rate of 3.5 m/s^2 is 32.5 m/s.

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Answer with Explanation:

When solving a problem in math, chemistry or physics, it is necessary to understand all the words and their definitions.  If not, start with finding out their meanings, one by one.

Here the key word to know is pascal, (P), which is a unit of measure for pressure, defined as

pressure = Force / applied area

1 pascal = 1 newton / square metre or

1 P = 1 N/sq.m.

Here, we have been given:

Force = 150 N

Area = 0.25 m^2.

Thus the pressure

= Force / Area

= 150 N / 0.25 m^2

= 150/0.25  N/m^2

= 600 pascals.

[ note that the abbreviations are written in capitals, while the full words, units of measurement,  are written without capitalization, since they are no longer proper names]

Answer:

Explanation:

As spring season is a yearly phenomenon so, Rita should organize her data on yearly basis. Firstly, she should plan the procedure of her experiment and collect the data according to it. Secondly, identify the attribute of each object of her experiment. Thirdly, she can organize and segregate her data in tabular form, graphical form or diagrammatically.

The acceleration of the skateboarder on road A, road B and road C is 7,75 m/s² , 3,87 m/s² and 9,68 m/s².

Given

mᴀ = mʙ = mᴄ = 62 kg

Fᴀ = 480N

Fʙ = 240 N

Fᴄ = 600 N

Asked

aᴀ, aʙ, aᴄ = ?

Solution

     Based on the question, we know that the mass of road A, road B and road C are same. And, the formula of acceleration is

             [tex]\boxed{\text{a} = \frac{\text{F}}{\text{m}}}[/tex]

so, we can calculate the acceleration of road A, road B and road C.

• for road A

[tex]\text{a}_A = \frac{\text{F}_A}{\text{m}}[/tex]

[tex]\text{a}_A = \frac{480 \text{N}}{\text{62 \text{kg}}}[/tex]

aᴀ = 7,7419 m/s²

aᴀ = 7,75 m/s²

• for road B

[tex]\text{a}_B = \frac{\text{F}_B}{\text{m}}[/tex]

[tex]\text{a}_B = \frac{240 \text{N}}{62 \text{kg}}[/tex]

aʙ = 3,8709 m/s²

aʙ = 3,87 m/s²

• for road C

[tex]\text{a}_C = \frac{\text{F}_C}{\text{m}}[/tex]

[tex]\text{a}_A = \frac{600 \text{N}}{62 \text{kg}}[/tex]

aᴄ = 9,6774 m/s²

aᴄ = 9,68 m/s²

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1. Learn More About The First Newton Law https://brainly.com/question/10454047

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Grade: Middle School

Subject: Physics

Chapter: Motion and Kinematics

Keywords: Motion, Mass, Acceleration, Newton, Newton Law, Force, Kinematics

To find the acceleration of the skateboarder, use the provided data and the equation: acceleration = (final velocity - initial velocity) / time. Plug in the values and ensure all units are consistent, then solve.

To calculate the acceleration of the skateboarder, you need to use the data given in the table and the equations of motion. Assume the data provides initial velocity (Vi), final velocity (Vf), and time (t).

The acceleration can be calculated using the formula: acceleration (a) = (Vf - Vi) / t. Make sure the velocities are in the same units and the time is in seconds to get the acceleration in meters per second squared (m/s²).

Plug in the values from the table into this equation to find the acceleration. For instance, if Vi = 2 m/s, Vf = 4 m/s, and t = 1 s, Then the acceleration would be (4 m/s - 2 m/s) / 1 s = 2 m/s².

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Answer:

2.7

Explanation:

This is because fluorine has an atomic number 9

Answer:

2, 7

Explanation:

Fluorine has 9 electrons and electronic structures are written listing the amount of electrons in each shell/energy level starting from the first one.

The first one can hold a maximum of 2 electrons and the 2nd, 3rd and 4rth can hold a maximum of 8

Answer:

202.95J

Explanation:

The formulae for the energy absorbed by the iron skillet is;

q=m*c*ΔФ   where q=energy absorbed, m is mass of iron skillet, c is specific heat capacity and ΔФ is change in temperature

Given that;

m= 41g

ΔФ=20°-9°=11°

c=0.45 J/g°C

q= 41×0.45×11

q= 202.95 J

It could speed up, change direction, come to a complete stop, or slow down without stopping.

The one thing the object could NOT do is keep moving with the same velocity. Its velocity must change.

Answer:

move at the same velocity

Explanation:

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Answer:

[tex]1.99 \times {10}^{30} [/tex]

Explanation:

Scientific notation should be in the form of

[tex]a \times {10}^{n} [/tex]

where

[tex]1 \leqslant a < 10[/tex]

The answer is the second option "watt." Watt is the unit of power measured by one joule per second. Watts are a amount of electrical power and measured by the rate of energy transfer between two things.

Hope this helps.

Hello There!

Elements are substances that are only made up of 1 type of atom.

Some examples of elements could be Carbon {C}, Hydrogen {H} and Iron {Fe}.

Compounds on the other hand are made up of two or more atoms. They are chemical substances. An example of a compound could be Water because this is made up of 2 hydrogen atoms and one oxygen atom.

Elements and compounds are both types of substances, but they have some key differences. Elements are pure substances that cannot be broken down into simpler substances by chemical means, while compounds are substances made up of two or more elements that are chemically bonded together.

Elements and compounds are both types of substances, but they have some key differences.

Elements are pure substances that cannot be broken down into simpler substances by chemical means. They consist of only one type of atom and are listed on the periodic table. Examples of elements include oxygen, carbon, and gold.

Compounds, on the other hand, are substances made up of two or more elements that are chemically bonded together. They have a fixed composition and can be broken down into their constituent elements through chemical reactions. Examples of compounds include water (H2O) and carbon dioxide (CO2).

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Answer:

Input force = 100N

Explanation:

Formula

Mechanical Advantage = output force / input force.

Givens

MA = 6

Output Force = 600 N

Input Force = ??

Solution

6 = 600 / x

Multiply both sides by x

6x = (600/x)*x

6x = 600                

The xs cancel. Now Divide by 6

6x/6 = 600/6

x = 100 N

Answer:

100n

Explanation:

Answer:

Explanation:

You are going to lift and press down on the 200 N many times and move only a short distance. The reward is that slowly but surely you will lift a very heavy load -- one that cannot be managed any other way but by the hydraulic jack.

Answer:

B. Globular clusters    

are scattered throughout the galactic halo that surrounds the Milky Way.

Explanation:

Answer:

The purpose of the sun is to keep planets orbiting around it. Without the sun's gravity, the planets would not be orbiting around it, although it is impossible for a planet or a star or a planet to not have gravity. I hope you find this answer as the one you needed, please mark me as brainiest answer. Aka Answer A.)

Gravity is the property of every object that has mass. The gravity of the sun keeps the planets orbiting  around the sun in the solar system.

Therefore, the gravity of the sun keeps the planets orbiting  around the sun in the solar system.

Learn more about Gravity,

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Answer:

Inertia

Explanation:

Inertia is best defined as the ability of an object to resist a change in position or movement. That is why when an object has a higher mass, the higher the inertia. Imagine an oncoming truck that is fully loaded versus you. The tendency for the truck to change its movement would be difficult because of its its mass. It has a lot of inertia.

Answer:

A. The particles will begin to move enough

that they slide past each other.

Explanation:

When the plastic cup is heated, the Kinetic energy of its particles starts increasing. As the temperature rises, the kinetic energy keeps increasing. With the increase of K.E, the particles start moving faster and faster. When the temperature finally reaches the melting point, the K.E of the molecules is enough to break the bonds and slide past each other.

Answer:

An on-camera flash is an indispensible accessory for many photographers; it provides additional light when conditions become too dark to handhold your camera comfortably, allows you to achieve more balanced exposures in daylight conditions, permits freezing of fast-moving subjects and can also be used to control or trigger other flash light sources. Additionally, a flash can be used as a highly effective creative tool to establish an aesthetic that elevates your imagery when lighting conditions are considered less than stellar. The benefits of an external on-camera flash far outweigh those provided by a built-in camera flash, while the only drawback is keeping an additional piece of equipment.

On-Camera Flash versus Off-Camera Flash versus In-Camera Flash

The term on-camera flash simply refers to a type of strobe light (flash) that can connect directly with your camera. While it is referred to as “on-camera” this does not require the flash to be physically mounted on your camera. On-camera flashes can, and often are, used off-camera. This differs from other strobe-light sources, such as studio pack strobes and monolights in that these types of strobes are not meant to be physically connected to your camera (except under rare and unusual circumstances involving convoluted methods of adaptation). Additionally, on-camera flashes usually have a self-contained power supply, although external power sources can sometimes be used to improve performance or battery life.

On-camera external flash also refers to the type of external flash that can be used on your camera, compared to a built-in flash that is integrated into many cameras. An on-camera external flash performs better than a built-in flash in almost every regard with the one exception that it is not built into your camera. The ability to take the flash off your camera results in a significantly greater number of lighting options; far more than simply providing a blast of flat light to the scene to facilitate an adequate exposure. It is often not desirable to have your flash pointed squarely at the scene at hand; more often than not you will want to bounce the flash light off other surfaces and point in other directions to control the look of your flash. When using an in-camera flash, you are forced to use the flash at the given angle from which it extends.

Most built-in flashes are also located near the camera lens, which can often result in the red-eye effect  when photographing subjects in dimly lit conditions. Red-eye occurs because pupils dilate in dim light, the built-in flash is aligned with the lens's optical axis, its beam enters the eye and reflects back at the camera from the retina at the rear of the eye, which is quite red. Being able to use an on-camera flash source off-camera, from a different angle, will help to eliminate the red-eye effect in your photographs of people.

Guide Numbers, Manual Usage, Controlling Flash Power and Sync Speeds

Before delving into the automatic technology that is contained within most contemporary flashes, it is best to understand how to manually control and grasp a flash’s power. This is directly related to having an understanding of exposure ratios—how shutter speeds and apertures affect and balance each other—even though auto-exposure metering is available and often utilized for determining the best exposure settings.

Explanation:

Answer:

The answer would be drug use, addiction, dependence, tolerance, and withdrawal.

Answer:

D. drug use, tolerance, dependence, addiction, and then withdrawal

Explanation: took the test rn on edge 2020

Answer:

Before I answer I want to say this Calibri is the superior font and green is the only highlight color.

The correct answer is C: Electrons are transferred → Ions form → Ions are attracted to each other

Explanation:

Generally, an ionic compound is formed between electropositive and electronegative elements.

Normally every element wants to occupy the inert gas configuration in order to be stable. During the ionic bond formation the electropositive metal will lose the electrons and forms cation. The electronegative metal will gain electrons and forms anion.

The cation is positively charged and the ion is negatively charged. Due to the coulombic force of attraction, the ions will be attracted to each other and forms an ionic compound.

One can take the example of NaCl where Na will lose one electron and form. Chlorine will take one electron and form. These ions are attracted and sodium chloride is formed.

Hence the formation of an ionic compound follows these steps-

1- First electrons are transferred.

2-The ions are formed

3-The ions are attracted to form the compound

Answer: skeletal only

Explanation: Cardiac muscle (also called heart muscle or myocardium) is one of three types of vertebrate muscles, with the other two being skeletal and smooth muscles. It is an involuntary, striated muscle that constitutes the main tissue of the walls of the heart.

Smooth muscle is responsible for muscle tissue in which the contractile fibrils are not highly ordered, occurring in the gut and other internal organs and not under voluntary control.

Hope this helps

Good conductors can give us more electrical energy. Advanced batteries today use ion charges for the batteries.

knowledge of the relationship between the molecular structure of metals and their conductivity is invaluable for engineers developing more powerful batteries.

In many battery designs, the electrodes are made of metal materials such as lithium, copper, or aluminum. These metals have a crystalline structure that allows for the efficient flow of electrons. Understanding the molecular structure of these metals helps engineers select the best materials for the electrodes to ensure optimal electrical conductivity, which, in turn, leads to better battery performance.

Engineers need to consider the corrosion resistance of metal components in batteries. Some metals form protective oxide layers that prevent corrosion, extending the lifespan of the battery. A detailed understanding of the molecular structure and corrosion behavior of metals helps in selecting the most durable materials for battery components.

Learn more about electrical conductivity at:

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Answer:

D

Explanation:

The correct answer is D

How does the thickness of the wire affect the strength of an electromagnet?

Answer:

How does the thickness of the wire affect the strength of an electromagnet

Explanation:

Generally, electromagnet strength increases with an increase in wire thickness. From the theory of electric circuit, the resistance of an electric wire is inversely proportional to the cross sectional area of the electric wire. Mathematically, we have:

R ∝ 1/A

Where:

R is the resistance of the electric wire; A is the cross sectional area of the wire. Therefore, for a large cross sectional area, the resistance will be very low, and the electric current passing through the electromagnet will be high. This will create a very high magnetic field. Thus, the question that Maya will most likely answer is: How does the thickness of the wire affect the strength of an electromagnet.

Elastic potential energy stored in bungee cord is 20.0 J.

Answer: Option B

Explanation:

The elastic potential energy is a form of potential energy stored in elastic materials. Generally potential energy is the energy of any object when it is at rest. But in materials possessing elastic properties, they store these potential energy in the form of elastic potential energy and it is used when the elastic materials undergoes elastic deformation.

For example, if we consider a spring, the elastic potential energy of the spring will be zero, when it is not deformed elastically i.e., when the spring is not stretched or compressed. But the same spring will be exhibiting elastic potential energy when the spring is stretched or compressed. So, the formula for elastic potential energy is

      [tex]\text { Elastic potential energy }=\frac{1}{2} \times \text { spring constant } \times\left(\frac{\text {stretching}}{\text {compressing distance}}\right)^{2}[/tex]

In this case, as the spring constant of cord is given as 10 N/m and the stretching distance of the cord is given as 2 m, so the elastic potential energy stored in the cord will be

       [tex]\text { Elastic potential energy }=\frac{1}{2} \times 10 \times(2)^{2}=\frac{1}{2} \times 10 \times 4 = 20 J[/tex]