If Sue rides 10 miles per hour on her bike, and this relationship is graphed, which ordered pair would not be on the graph?
(2, 20)
(5, 50)
(6, 60)
(8, 85)

Answers

Answer 1

Answer:

(8, 85) Would make this relationship not a function because every time you count up 1 it goes up 10 and 8 would match to 80 not 85 making 8, 85 the ordered pair would not be on the graph.


Answer 2
Final answer:

Given Sue's speed of 10 miles per hour, we're looking for an ordered pair that does not fit the relationship y = 10x. While (2,20), (5,50), and (6,60) all fit this relationship, the pair (8,85) does not, hence it won't be on the graph.

Explanation:

Sue's speed on her bike is 10 miles per hour. This relationship can be graphed as a straight line in a coordinate plane because the speed remains constant - the distance covered increases uniformly over time. So, for each hour (x), she covers a distance of 10x miles (y). Therefore, we can identify the ordered pair that does not belong on the graph by determining which one does not fit the relationship y = 10x.

(2,20): y=10*2=20, so the pair (2,20) fits the relationship.(5,50): y=10*5=50, therefore the pair (5,50) fits the relationship.(6,60): y=10*6=60, hence the pair (6,60) fits the relationship.(8,85): y=10*8=80, but the given y-value is 85, therefore the ordered pair (8,85) does not fit the relationship and would not be on the graph.

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Related Questions

The diameter at the center of the tower is_ meters. The center of the tower is _meters above the ground

Answers

Answer:

think 5 meters

Step-by-step explanation:


Answer:

The diameter at the center of the tower is 4 meters. The center of the tower is 8 meters above the ground.

Step-by-step explanation:

4x^2-y^2+16y-80=0

Completing squares in variable "y": Common factor -1:

4x^2-(y^2-16y)-80=0

4x^2-[(y-16/2)^2-(16/2)^2]-80=0

4x^2-[(y-8)^2-(8)^2]-80=0

4x^2-[(y-8)^2-64]-80=0

Eliminating the brackets:

4x^2-(y-8)^2+64-80=0

Adding like terms (constants):

4x^2-(y-8)^2-16=0

Adding 16 both sides of the equation:

4x^2-(y-8)^2-16+16=0+16

4x^2-(y-8)^2=16

Dividing all the terms by 16:

4x^2/16-(y-8)^2/16=16/16

Simplifying:

x^2/4-(y-8)^2/16=1

The hyperbola has the form:

(x-h)^2/a^2-(y-k)^2/b^2=1

Then:

h=0

k=8

a^2=4→sqrt(a^2)=sqrt(4)→a=2

The diameter (d) at the center of the tower is:

d=2a→d=2(2)→d=4 meters

The center of the tower is 8 (k) meters above the ground.

What is the solution to 4+5e^(x+2)=11?

(Answers Below)

Answers

Answer:

x = ln (7/5) - 2

Step-by-step explanation:

4+5e^(x+2)=11

Subtract 4 from each side

4-4+5e^(x+2)=11-4

5e^(x+2)=7

Divide by 5 on each side

5/5e^(x+2)=7/5

e^(x+2)=7/5

Take the natural log on each side

ln (e^(x+2))= ln (7/5)

x+2    = ln (7/5)

Subtract 2 from each side

x = ln (7/5) - 2

Answer:

option 1

Step-by-step explanation:

Given the table below, determine if the data represents a linear or an exponential function and find a possible formula for the function.

Answers

Answer:

Option a is correct

given data in the table represents an exponential function

The possible formula for the function is, [tex]y = f(x) = 12.5 (1.10)^x[/tex]

An exponential function is in the form of [tex]f(x) = ab^x[/tex] where a is the initial value and b ≠ 0 ,  b> 1.

Consider any two points from the table as shown;

(0, 12.5) and (1, 13.75)

Substitute these in [1] we have;

For (0, 12.5)

where x = 0 and f(x) = 12.5 in [1]

[tex]12.5 = ab^0[/tex]

12.5 = a

For (1, 13.75)

[tex]13.75 = ab^1[/tex]

13.75 = ab

Substitute the value of a =12.5 we have;

13.75 = 12.5b

divide both sides by 12.5 we get;

[tex]b = \frac{13.75}{12.5} = 1.10[/tex]

since, y =f(x)

therefore, we have the following exponential function as:

[tex]y= 12.5 (1.10)^x[/tex]

Work out the area of the lawn.

Answers

Area of Flower Bed:
(b*h)/2
(3*8)/2 = 12m^2

Area of Vegetable Patch:
((b1 + b2)*h)/2
((5+7)*10)/2 = 60m^2

Area of Whole Garden:
l*w
14*10 = 140m^2

Whole Garden - Vegetable Patch - Flower Bed = Lawn
140 - 60 - 12 = 68m^2

Area of Lawn: 68m^2

Hope this helps.

Answer:

68 m^2

Step-by-step explanation:

Area of The entire enclosure ( rectangle)

Area rectangle = L * WL = 7 + 7 = 14W = 10 Area rectangle = 10*(7 + 7)Area of rectangle = 10 * 14Area of rectangle = 140 square meters.

Area of the triangle

Area of the triangle = 1/2 b*hArea of the triangle = 1/2 * 8 * 3Area of the triangle= 12 square meters.

Area of the Trapezoid

h = 10b1 = 5b2 = 7

Formula

Area = (b1 + b2)*h /2

Solution

Area = (5 + 7)*10/2Area = 12*10/2Area = 60

Area of the Lawn

Area of the Lawn = rectangle area - triangle area - trapezoid areaArea of the lawn = 140 - 12 - 60Area of the lawn = 68 m^2

Write the first five terms of the the sequence defined by the explicit formula an=72(1/3)^n-1

Answers

[tex]a_n=72\left(\dfrac{1}{3}\right)^{n-1}\\\\\text{Put}\ n=1,\ n=2,\ n=3,\ n=4,\ n=5\ \text{to the equation}:\\\\n=1\to a_1=72\left(\dfrac{1}{3}\right)^{1-1}=72\left(\dfrac{1}{3}\right)^0=72(1)=72\\\\n=2\to a_2=72\left(\dfrac{1}{3}\right)^{2-1}=72\left(\dfrac{1}{3}\right)^1=72\left(\dfrac{1}{3}\right)=\dfrac{72}{3}=24\\\\n=3\to a_3=72\left(\dfrac{1}{3}\right)^{3-1}=72\left(\dfrac{1}{3}\right)^2=72\left(\dfrac{1}{9}\right)=\dfrac{72}{9}=8\\\\n=4\to a_4=72\left(\dfrac{1}{3}\right)^{4-1}=72\left(\dfrac{1}{3}\right)^3=72\left(\dfrac{1}{27}\right)=\dfrac{72}{27}=\dfrac{8}{3}\\\\n=5\to a_5=72\left(\dfrac{1}{3}\right)^{5-1}=72\left(\dfrac{1}{3}\right)^4=72\left(\dfrac{1}{81}\right)=\dfrac{72}{81}=\dfrac{8}{9}\\\\Answer:\ \boxed{72,\ 24,\ 8,\ \dfrac{8}{3},\ \dfrac{8}{9}}[/tex]

Answer:

The first five terms are as follows:

72, 24, 8, 2.66, 0.88

Step-by-step explanation:

1) Explicit formula:

[tex]72 * 1/3^{n-1}[/tex]

2) Simply replace "n" with 2,3,4 and 5 in order to find the numbers associated with these terms.

a(1) = 72

a(2) = 24

a(3) = 8

a(4) = 2.66

a(5) = 0.88

Note:

In the explicit formula the first term is already provided, so you do not have to find the first term if it has already been given.

It takes Francisco 15 minutes to ride his bicycle 4km ,which is the distance from home to school . What is the average speed

Answers

Answer:

16 KMH is the correct answer

Step-by-step explanation:


Mackenzie wrote the following paragraph proof for the Vertical Angles Theorem: Line segment NT intersects line segment MR forming four angles. Angles 1 and 3 are vertical angles. Angles 2 and 4 are vertical angles. The sum of angle 1 and angle 4 and the sum of angle 3 and angle 4 are each equal to 180 degrees by the definition of supplementary angles. The sum of angle 1 and angle 4 is equal to the sum of angle 3 and angle 4 _________________. Angle 1 is equal to angle 3 by the subtraction property of equality. Which phrase completes the proof? by construction using a straightedge by the definition of a perpendicular bisector by the transitive property of equality. by the vertical angles theorem

Answers

by the transitive property of equality

Answer:

the transitive property of equality

Step-by-step explanation:


You invest $1,000 in an account at 2.5% per year simple interest. How much will you have in the account after 4 years? Round your answer to the nearest whole dollar

Answers

Answer:

1000*(1,025)=1025 $ the 1st year

After 4 years, the account will be 4* 1025=4100



Answer:

Amount after 4 years = 1000+100=$1100

Step-by-step explanation:

To solve this, we will simply use the simple interest formula;

S.I = PRT/100

where p=principal

R=rate   and   T= time

S.I = simple interest

From the question

Principal=$1000

Rate = 2.5    and time=4

We can now proceed to inert the values into the equation

S.I = 1000×2.5×4   /100

Two zeros at the numerator will cancel-out the two zeros at the denominator, Hence;

S.I = 10×2.5×4

S.I =$100

Amount after 4 years = 1000+100=$1100

Elena mixes 5 cups of apple juice with 2 cups of sparkling water to make sparkling apple juice for a party she wants to make 35 cups of sparkling apple juice. how much of each ingredient should Elena use?

Answers

Answer: 25 cups of apple juice and 10 cups of splarking water.


Step-by-step explanation:

1. You have the following information given in the problem:

- She mixes 5 cups of apple juice with 2 cups of sparklin.

- She wants to make 35 cups of sparkling apple juice.

2. Then:

[tex]5cups+2cups=7cups[/tex] (Each lot of sparkling apple juice has 7 cups).

3. As she needs 35 cups, she needs to make 5 lots of sparkling apple juice, because:

[tex]\frac{35}{7}=5lots[/tex]

4. Therefore, you must multiply 5 lots by 5 cups of apple juice and 5 lots by 2 cups of sparkling apple juice. Then, she should use:

[tex]A.juice=5*5cups=25cups\\S.water=5*2cups=10cups[/tex]

5. The answer is:

25 cups of apple juice and 10 cups of splarking water.

Final answer:

To make 35 cups of sparkling apple juice, Elena will need to mix 25 cups of apple juice with 10 cups of sparkling water. This is because the initial quantity ratio is 5:2 for apple juice to sparkling water. Thus, to make a larger quantity, these original quantities are multiplied by a common factor.

Explanation:

The goal here is to get the quantities of apple juice and sparkling water that Elena should use to prepare 35 cups of sparkling apple juice. In the original mix, Elena combines 5 cups of apple juice with 2 cups of sparkling water to make 7 cups of the juice. This mix is thus in a ratio of 5:2 in favor of apple juice to water.

Given that the total quantity she now wants to prepare is 35 cups, which is 5 times the original quantity (because 35/7 = 5), you would multiply the quantities of each of the components (apple juice and sparkling water) by 5. This implies:

Apple juice: 5 cups x 5 = 25 cupsSparkling water: 2 cups x 5 = 10 cups

Therefore, Elena will need 25 cups of apple juice and 10 cups of sparkling water to make 35 cups of sparkling apple juice.

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Based on the table of values below, find the slope between points where x = 3 and where x = 7.

x y
3 1
4 6
7 9

Answers
−4

1/4

1

2

Answers

Answer:

d) 2

Step-by-step explanation:

let's take the points (3, 1) and (7, 9)

Slope formula (m) = (y2 - y1)/(x2 - x1)

Here x1 = 3, y1 = 1 , x2 = 7 and y2 = 9

Now plug in these values in the formula, we get

slope (m) = (9 -1) / (7 -3)

= 8/4

Slope = 2

Answer: d) 2

Thank you.

The answer would be D. 2

Johns house is 12 miles away from school he is 2/3 the way there how many miles has he walked

Answers

Basically this is asking what is 2/3 of 12. you can count by 4s to find out. 4, 8 ,12... so John has walked 8 miles so far.

If I could have help on this that would be great.

Answers

Answer: Choice C) Harold

Darren is correct because he subtracted c from both sides

Julie is correct because she multiplied both sides by H, and then divided both sides by L

Brenda is correct because she multiplied both sides by r

Harold is not correct. We can see this with a counter example. If A = 7 and h = 1, then the first equation Harold wrote leads to b = 14. Now plug those same values into the second equation and we get h = 2b/A turning into 1 = 2*14/7 and that simplifies to 1 = 4, which is a false statement. This contradiction is one example why the two equations Harold wrote aren't equivalent.

Answer:

C.

Step-by-step explanation:

Juile, Brenda, and Darren are all incorrect.

the force on an object is given by the equation f=ma. in this equation, F is the force, m is the mass, and a is the acceleration. which answer hows this equation solved for mass?
A. m=a/f
B. m=fa
C. m=f/a
D. m= m/f

Answers

Answer:

C. mass = force / accellaration


Step-by-step explanation:


Find the sum of 10x squared -x+1 and x squared-10x-7

Answers

Answer:

11x^2 - 11x - 6

Step-by-step explanation:

I'm guessing you mean:

(10x^2 - x + 1 ) + (x^2 - 10x - 7)

First you combined like terms:

Such as :

10x^2 + x^2

-x - 10x

1 - 7

There's your answer.

11x^2 - 11x - 6

NEED HELP!! 30 POINTS! HAS TO BE CORRECT AND NEED THE ANSWER NOOW!

Answers

Answer: options b and c

Step-by-step explanation:

∠ACD is supplementary to ∠ACE  given

∠ACD is supplementary to ∠BCD   given

⇒ ∠ACE is supplementary to ∠BCD   transitive property


∠ACD ≅ ∠BCE   given

⇒ ∠BCE is supplementary to ∠ACE  substitution

and ∠BCE is supplementary to ∠BCD   substitution

********************************************************************************

multiple choice options:

a) ∠ACE is supplementary to ∠BCD    False

b) ∠BCE is supplementary to ∠ACE    TRUE

c) ∠BCD is supplementary to ∠BCE    TRUE

d) ∠ACE ≅ ∠BCE                                   False

e) ∠BCD ≅ ∠ACE                                   False


The movie theater sold 56 boxes of gummy bears during the week.At this rate how many boxes of gummy bears will the movie theater sell in a 6 week period

Answers

Answer is in the picture attached.

Answer:

Step-by-step explanation:

At a sales rate of 56 boxes of gummy bears per week, the movie theater will sell

= 56 × 6

= 336 boxes

This is on the assumption that the rate is sustained.

At that rate (of 56 boxes per week), the company (movie theater) would have sold 336 boxes.

30 POINTS!!!

Select ALL of the expressions that are equivalent to 4 square root of 5.

A. 2 square root of 20.

B. 6^1/2-5^1/2

C. 3*5^1/2+5^1/2

D. 4* 5^1/2

E. 2 square root of 10

F. 3*5^1/2

Answers

Answer:

A, C, & D

Step-by-step explanation:

A square root has the form [tex]\sqrt[2]{x}  = x^{1/2}[/tex] and can be represented in exponential form. Let's convert all the expressions to [tex]\sqrt{x}[/tex] this form. 4 square root 5 is [tex]4\sqrt{25} =\sqrt{16*5}=\sqrt{80}[/tex]

A. [tex]2\sqrt{20} =\sqrt{4*20}=\sqrt{80}[/tex]

B. [tex]6^{1/2}-5^{1/2} =\sqrt{6}-\sqrt{5}[/tex]

C. [tex]3*5^{1/2}+5^{1/2} =3\sqrt{5}+\sqrt{5}=4\sqrt{5}=\sqrt{16*5}=\sqrt{80}[/tex]

D. [tex]4*5^{1/2}=4\sqrt{5}=\sqrt{16*5}=\sqrt{80}[/tex]

E.[tex]2\sqrt{10} =\sqrt{4*10}=\sqrt{40}[/tex]

F.  [tex]3*5^{1/2}=3\sqrt{5}=\sqrt{9*5}=\sqrt{45}[/tex]

If leo is 6 years old and max is 12 years, how many years would it be until max is 3 times as old as leo

Answers

Answer:

Step-by-step explanation: max is already 3 times older than max. 6*3=18 and 6+12=18

Final answer:

Max cannot be 3 times as old as Leo based on the given information.

Explanation:

To find out how many years it will be until Max is 3 times as old as Leo, we can set up an equation.

Let's assume that it takes x years for Max to be 3 times as old as Leo.

So, Max's age in x years will be 12 + x, and Leo's age in x years will be 6 + x. According to the problem, Max will be 3 times as old as Leo, so we can write the equation as: 12 + x = 3(6 + x).

To solve for x, we can start by simplifying the equation: 12 + x = 18 + 3x. Now, let's isolate the variable x by moving all the x terms to one side and the constant terms to the other side. Subtracting x from both sides gives us: 12 = 18 + 2x. Subtracting 18 from both sides gives us: -6 = 2x. Finally, dividing both sides by 2 gives us: -3 = x.

This means that it will take -3 years for Max to be 3 times as old as Leo. However, since time cannot be negative, we can conclude that it is not possible for Max to be 3 times as old as Leo based on the given information.

What is the solution set of the equation j+4/j+2=2−1/j ? Note: j≠0, −2

Answers

Answer:

values of j are: 2 , -1

Step-by-step explanation:

In the given case, The solutions are j = -4 and j = 1, and the solution set is  {-4, 1}.

The given equation is:

j+4/j+2=2−1/j

We can solve for j by cross-multiplying:

(j+4)(j) = (j+2)(2-1/j)

Expanding the left side and right side, we get:

[tex]j^2 + 4j = 2j + 4 - 2/j[/tex]

Moving all the terms to the left side of the equation, we get:

[tex]j^2 + 2j - 4 = 0[/tex]

We can factor the left side of the equation as:

(j+4)(j-1) = 0

Therefore, the solutions are j = -4 and j = 1.

Note that the given equation is defined when j ≠ 0 and j ≠ -2. Therefore, the solutions are j = -4 and j = 1, and the solution set is  {-4, 1}.

Here is a step-by-step solution:

n first move the constant term to the right side of the equation.

j² + 2j = 4

We can then factor the left side of the equation.

(j+4)(j-1) = 0

The solutions are j = -4 and j = 1.

We check that these solutions are valid by substituting them back into the original equation.

j+4/j+2=2−1/j

When j = -4, the left side of the equation is 0/-2 = 0, and the right side of the equation is 2 - 1/-4 = 2 + 0.5 = 2.5.

The equation is satisfied.

When j = 1, the left side of the equation is 5/3, and the right side of the equation is 2 - 1/1 = 2 - 1 = 1. The equation is satisfied.

Therefore, the solutions are j = -4 and j = 1, and the solution set is  {-4, 1}.

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A standard deck of cards has 52 cards divided into 4 suits, each of which has 13 cards. Two of the suits ( and , called 'hearts' and 'diamonds') are red, the other two ( and , called 'spades' and 'clubs') are black. The cards in the deck are placed in random order (usually by a process called 'shuffling'). In how many ways can we pick two different cards? (Order matters, thus ace of spades followed by jack of diamonds is different than jack of diamonds followed by ace of spades.)

Answers


When the order of something happens it is a permutation.


There are a total of 52 cards and you want to pick 2 different cards.

The equation for this is:

52! / (52 - 2!)

Simplified becomes 52! / 50!

Answer = 2,652 ways.



To find the number of ways to pick two different cards from a deck where order matters, we calculate the permutations, resulting in 52 times 51, which equals 2652 ways.

The question asks for the number of ways to pick two different cards from a standard deck of 52 cards considering that the order of selection matters. To calculate this, we use permutations. For the first card, there are 52 options; for the second card, since one card has already been picked, there are 51 options left. The number of permutations for two cards from a deck of 52 is therefore calculated as 52 × 51. This results in 2652 different permutations or ways to select two different cards where order is significant.

Which input value produces the same output value for the two functions on the graph?

X= -3
X= -1
X= 1
X= 3

Answers

x=-1 because it would give you a straight line across -1 and it goes thru the point

Answer:

D. [tex]x=3[/tex]

Step-by-step explanation:

We have been graph of two functions on coordinate plane. We are asked to find the input value that produces the same output value for the two functions.

To find the input value that produces the same output value for the two functions, we need to find x-value for which both functions has same y-value.

Upon looking at our given graph, we can see that at [tex]x=3[/tex], the value of both functions is [tex]-1[/tex].

Therefore, our required input value is [tex]x=3[/tex] and option D is the correct choice.

Please help & explain 4th grade math

Answers

Answer:2/9


Step-by-step explanation:

If you count the lines form zero like 0/9 1/9 2/9 3/9 4/9 5/9 6/9 7/9 8/9 then 1 is the whole so that would be 9/9


Answer:

2/9 is the answer



Find a polynomial f(×) with leading coefficient 1 such that the equation f(×)=0 has The given roots and no others . Root 1, -5 multiplicity 2,1

Answers

Answer:

[tex]x^{3} +3x^{2}-9x+5 = 0[/tex]

Step-by-step explanation:

We are given that the only roots of the given polynomial f(x) are 1 and -5 with multiplicity (the number of times the roots are repeating) 2 and 1 respectively.

Also, it is provided that the function satisfy that f(x)=0.

So, comparing the two information we have that,

f(x) = 0 and 1, -5 are the roots of f(x),

i.e [tex](x-1)^{2} \times (x+5) = 0[/tex]

i.e. [tex](x^{2} +1-2x) \times (x+5) = 0[/tex]

i.e. [tex]x^{3} +3x^{2}-9x+5 = 0[/tex]

Also, we can see that ths polynomial has leading co-efficient 1 i.e. the co-efficient of highest degree variable i.e. x^{3}.

Hence, the polynomial having leading co-efficient 1 and roots 1, -5 is [tex]x^{3} +3x^{2}-9x+5 = 0[/tex].

in 2 years i will be twice as old as i was 20 years ago how old am I?

Answers

You are going to be 40 years old.
Twice = 2
2 times 20 is 40.

Answer:

I am 42 years old

Step-by-step explanation:

Given : In 2 years i will be twice as old as i was 20 years ago.

To Find : Current age

Solution :

Let the current age be x years.

After two years i will be (x+2) years

20 years ago i was (x-20)years

Since we are given that in 2 years i will be twice as old as i was 20 years ago.


⇒[tex]x+2 = 2 (x-20)[/tex]


⇒[tex]x+2 = 2x-40[/tex]


⇒[tex]40+2 = 2x-x[/tex]


⇒[tex]42 = x[/tex]


Thus my current age 'x' = 42 years.

Hence i am 42 years old


The probability that a student at certain high school likes art is 36%. The probability that a student who likes art also likes science is 21%. Find the probability that a student chosen at random likes science given that he or she likes art. Round to the nearest tenth of a percent.

Answers

Answer: Probability that a student chose at random likes science given that he or she likes art is 58%.

Step-by-step explanation:

Since we have given that

Probability that a student at certain high school likes art =[tex]P(A)[/tex] = 36%

Probability that a student who likes art also likes science= [tex]P(A\cap S)[/tex]  = 21%

We need to find the value of probability that a student chosen at random likes science given that he or she likes art.

As we know the formula for "Conditional Probability" :

[tex]P(S\mid A)=\frac{P(A\cap S)}{P(A)}\\\\P(S\mid A)=\frac{21}{36}\\\\P(S\mid A)=0.58\\\\P(S\mid A)=58\%[/tex]

Hence, Probability that a student chose at random likes science given that he or she likes art is 58%.


Answer with explanation:

A= Art

S= Science

P(A)= 36%

P (A ∩ S)=21%

We have to find ,[tex]P(\frac{S}{A})[/tex].

[tex]P(\frac{S}{A})=\frac{P(S\cap A)}{P(A)}\\\\P(\frac{S}{A})=\frac{\frac{21}{100}}{\frac{36}{100}}\\\\P(\frac{S}{A})=\frac{21}{36}=\frac{7}{12}[/tex]

In terms of Percentage , Required Probability

  [tex]=\frac{7}{12}\times 100\\\\=58.34[/tex]

= 58.34 %

 

the center of a circle is at (-2, - 7) and its radius is 36 what is equation of the circle

A, (x-2)^2 +(y, - 7)^2 = 6

B, (x+2)^2 +(y, + 7)^2 = 6

C, (x-2)^2 +(y, - 7)^2 = 1296

D, (x+2)^2 +(y, + 7)^2 = 1296

Answers

ANSWER

The required equation is,

[tex] {(x + 2)}^{2} + {(y + 7)}^{2} = 1296[/tex]

EXPLANATION

We want to find the equation of the circle given center [tex](-2,-7) [/tex]

and radius [tex]36[/tex] units.


The equation of a circle given the radius,
[tex]r[/tex]
and center
[tex](a,b) [/tex]

is given by the formula,

[tex] {(x - a)}^{2} + {(y - b)}^{2} = {r}^{2} [/tex]

We substitute,

[tex]a=-2,b=-7, r=36 [/tex]

to obtain,

[tex] {(x - - 2)}^{2} + {(y - - 7)}^{2} = {(36)}^{2} [/tex]

This will simplify to give us,

[tex] {(x + 2)}^{2} + {(y + 7)}^{2} = 1296[/tex]

The correct answer is D.



A geometric sequence is shown below.

2, – 6, 18, – 54, 162, ...

Part A:
Write a recursive relationship for this sequence. Explain how you determined your answer.

Part B:
Write an explicit formula for this sequence.

Answers

To find the recursive rule u have to find r so first so u have to divide the 2nd term by the 1st term to get r so it would be -6 divided by 2 which equals -3 then u have to plug in r with -3 so this is how it’s done so f(n)= f(n-1)•r then plug in r with -3 so then to find the explicit rule u have to plug in f(1) with your 1st term which is 2 and plug in r with -3 so f(n)= 2•(-3)n-1

The length of a rectangle is three times its width. The perimeter of the rectangle is at most 112cm. Which inequality models the relationship between the width and the perimeter of the rectangle.

Answers

Answer: w ≤ 14 cm , L ≤ 42 cm

Step-by-step explanation:

width (w): w

Length(L): 3w

Perimeter (P) = 2w + 2L

P ≤ 112

 2w +   2L   ≤ 112

2(w) + 2(3w) ≤ 112

 2w +   6w   ≤ 112

       8w        ≤ 112

         w        ≤ 14

The point located (3,-1) is reflected across the y-axis.What are the coordinates of the reflected point?

Answers

Answer:

(3,1)

Step-by-step explanation

All you have to do is change the y-coordinate to its opposite. Ex- (-2,3) coordinates of reflection. (-2,-3)

A recursive rule for a geometric sequence is a1=3;an=1/2an−1.

What is the explicit rule for this sequence?



Enter your answer in the box.

Answers

[tex]\text{The explicit rule of geometric sequence}\\\\a_n=a_1 r^{n-1}\\------------------------------\\\text{We have the recursive form}\ a_1=3,\ a_n=\dfrac{1}{2}\cdot a_{n-1}.\\\\\text{Therefore}\ r=\dfrac{1}{2}.\ \text{Substitute:}\\\\\boxed{a_n=3\left(\dfrac{1}{2}\right)^{n-1}}[/tex]

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