If p(x) = x2 – 1 and q(x)=5(x-1), which expression is equivalent to (p – q)(x)?

5(x – 1) – x2 – 1
(5x – 1) – (x2 – 1)
(x2 – 1) – 5(x – 1)
(x2 – 1) – 5x – 1

Answer:

553.64 rounded to the nearest cent

or

553.65

Step-by-step explanation:

Answer

Find out the  what is the clearance price .

To prove

As given

The gift shop at manatee mall was having a clearance sale.

everything was marked down 30%.

The original price of a manatee hat was $18.

30% is written in the decimal form

[tex]= \frac{30}{100}[/tex]

= 0.30

Than

The clearance price = 18 - 0.30 × 18

                                  = 18 - 5.4

                                  = $12.6

Therefore the clearance price be  $12.6 .

Answer:

5n

Step-by-step explanation:

group of answer chances below

A. n - 5

B. 5n

C. 5 + n

D. 5/n

Answer: x=-4 + or - i square root of 6

Answer: Hi!

in a probability table, the x represents a given event, and p is the probability of such event.

There are two rules if you have n events; then p₁ + p₂ + ... + pₙ = 1, this is because the probability is normalized.

whit this info you can discard the third option, because there is a probability bigger than 1, and then the addition of al the probabilities is bigger than 1.

The second rule is that there do not exist negative probabilities (because they don't have sense) then you can also discard the second option.

Now we need to check the first and the fourth options, we need to add the 4 probabilites in each and see if the result is 1.

for the first options we have :  

0.2 + 0.35 + 0.15 + 0.25 = 0.95

this is not normalized, this is not a probability distribution table.

for the fourth option we have:

0.4 + 0.15 + 0.25 + 0.2 = 1

this is normalized, then this is a probability distribution table.

Then the only right answer is option 4.

Answer:

Graph 2 :)

Step-by-step explanation:

Answer: Option A) [tex]729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}[/tex] is the correct expansion.

Explanation:

on applying binomial theorem,  [tex](a+b)^n=\sum_{r=0}^{n} \frac{n!}{r!(n-r)!} a^{n-r} b^r[/tex]

Here a=3c, [tex]b=d^2[/tex] and n=6,

Thus, [tex](3c+d^2)^6=\sum_{r=0}^{6} \frac{6!}{r!(6-r)!} (3c)^{n-r} (d^2)^r[/tex]

⇒ [tex](3c+d^2)^6= \frac{6!}{(6-0)!0!} (3c)^{6-0}.(d^2)^0+\frac{6!}{(6-1)!1!} (3c)^{6-1}.(d^2)^1+\frac{6!}{(6-2)!2!} (3c)^{6-2}.(d^2)^2+\frac{6!}{(6-3)!3!} (3c)^{6-3}.(d^2)^3+\frac{6!}{(6-4)!4!} (3c)^{6-4}.(d^2)^4+\frac{6!}{(6-5)!5!} (3c)^{6-5}.(d^2)^5+\frac{6!}{(6-6)!6!} (3c)^{6-6}.(d^2)^6[/tex]

⇒[tex](3c+d^2)^6= \frac{6!}{(6-)!0!} (3c)^6.d^0+\frac{6!}{(5)!1!} (3c)^5.d^2+\frac{6!}{(4)!2!} (3c)^4.d^4+\frac{6!}{(6-3)!3!} (3c)^3.d^6+\frac{6!}{(2)!4!} (3c)^2.d^8+\frac{6!}{(1)!5!} (3c).d^{10}+\frac{6!}{(0)!6!} (3c)^0.d^{12}[/tex]

⇒[tex](3c+d^2)^6=(3c)^6.d^0+\frac{720}{120} (3c)^5.d^2+\frac{720}{48} (3c)^4.d^4+\frac{720}{36} (3c)^3.d^6+\frac{720}{48} (3c)^2.d^8+\frac{720}{120} (3c).d^{10}+.d^{12}[/tex]

⇒[tex](3c+d^2)^6=729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}[/tex]

Answer:

Option (a) is correct.

[tex](3c+d^2)^6=729c^6+1458c^5d^2+1215c^4d^4+540c^3d^6+135c^2d^8+18cd^{10}+d^{12}[/tex]

Step-by-step explanation:

Given :  [tex]\left(3c+d^2\right)^6[/tex]

We have to expand the given expression and choose the correct from the given options.

Consider the given expression  [tex]\left(3c+d^2\right)^6[/tex]

Using binomial  theorem ,

[tex]\left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i[/tex]

We have  [tex]a=3c,\:\:b=d^2[/tex]

[tex]=\sum _{i=0}^6\binom{6}{i}\left(3c\right)^{\left(6-i\right)}\left(d^2\right)^i[/tex]

also, [tex]\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}[/tex]

for i = 0 , we have,

[tex]\frac{6!}{0!\left(6-0\right)!}\left(3c\right)^6d^2^0=729c^6[/tex]

for i = 1 , we have,

[tex]\frac{6!}{1!\left(6-1\right)!}\left(3c\right)^5d^2^1=1458c^5d^2[/tex]

for i = 2 , we have,

[tex]\frac{6!}{2!\left(6-2\right)!}\left(3c\right)^4d^2^2=1215c^4d^4[/tex]

for i = 3 , we have,

[tex]\frac{6!}{3!\left(6-3\right)!}\left(3c\right)^3d^2^3=540c^3d^6[/tex]

for i = 4 , we have,

[tex]\frac{6!}{4!\left(6-4\right)!}\left(3c\right)^2d^2^4=135c^2d^8[/tex]

for i = 5 , we have,

[tex]\frac{6!}{4!\left(6-4\right)!}\left(3c\right)^2d^2^4=18cd^{10}[/tex]

for i = 6 , we have,

[tex]\frac{6!}{6!\left(6-6\right)!}\left(3c\right)^0d^2^6=d^{12}[/tex]

Thus, adding all term together, we have,

[tex](3c+d^2)^6=729c^6+1458c^5d^2+1215c^4d^4+540c^3d^6+135c^2d^8+18cd^{10}+d^{12}[/tex]

Thus, Option (a) is correct.

we have

[tex]f(x)=\sqrt{x}+12[/tex]

[tex]g(x)=2\sqrt{x}[/tex]

we know that

[tex](f-g)(144)=f(144)-g(144)[/tex] -------> equation A

Step 1

Find the value of [tex]f(144)[/tex]

For [tex]x=144[/tex]

substitute in f(x)

[tex]f(144)=\sqrt{144}+12[/tex]

[tex]f(144)=12+12[/tex]

[tex]f(144)=24[/tex]

Step 2

Find the value of [tex]g(144)[/tex]

For [tex]x=144[/tex]

substitute in g(x)

[tex]g(144)=2\sqrt{144}[/tex]

[tex]g(144)=2(12)[/tex]

[tex]g(144)=24[/tex]

Step 3

Find [tex](f-g)(144)[/tex]

Substitute the values in the equation A

[tex]24-24=0[/tex]

therefore

the answer is the option

[tex]0[/tex]

Answer:

The answer is 63.

Step-by-step explanation:

50-12=38       38/.6 is equal to 63.333 you can't buy .333 of a bracelet so she will be able to buy 63 and have little money left.

The greatest number of bracelets she could buy will be 63.

Inequality is a sort of equation in which the equal sign is missing. As we will see, inequality is defined as a statement regarding the relative magnitude of two claims.

Given data;

The total amount of money in my wallet =  $50.00

Cost of shirt = $12.00

Price of bracelet per piece = $0.60

Let x is the no of the bracelet;

The equation obtained as;

⇒The total amount of money in my wallet = Cost of the shirt + Price of the bracelet per piece × No of the bracelet

⇒50 = 12 + 0.60 x

⇒0.60 x = 50-12

⇒x = 38/0.60

⇒x= 63.333 ≈ 63 bracelet

Hence the greatest number of bracelets she could buy will be 63.

To learn more about inequility, refer to https://brainly.com/question/20383699.

#SPJ2

p=3h + 3u  subtract 3u from both sides

p-3u=3h   now divide both sides by 3

h = p/3 - u

Two triangles with the same corresponding side lengths will be congruent - False

False. Two triangles with the same corresponding side lengths are not guaranteed to be congruent. They may still be similar triangles with equal corresponding angles but different sizes.

To turn 4√5 into an entire radical, the expression is rewritten as a single radical expression, √80, by identifying that 4 is a perfect square (4²), and multiplying it by the number inside the original radical (5) to get the product under one radical sign.

To turn 4√5 into an entire radical, we need to rewrite it as a single radical expression, effectively reversing the process of simplifying radicals. Let's start by recognizing that 4 is a perfect square and can be written as 4². So, we have 4 (the square root of 5), which can be expressed as √(4² × 5).

Here are the steps to convert 4√5 into an entire radical:

Identify the square of the number outside the radical: 4² = 16.

Multiply the square by the number inside the radical: 16 × 5 = 80.

Write the product under a single radical sign: √80.

Now, the expression 4√5 has been turned into an entire radical, √80.

1) 2x + 35 = 180° so x= 180 - 35 / 2 =73°

the answer is 73°

2)

3) In geometry, "Corresponding parts of congruent triangles are congruent" (CPCTC) is a succinct statement of a theorem regarding congruent trigonometry, defined as triangles either of which is an isometry of the other. CPCTC states that if two or more triangles are congruent, then all of their corresponding angles and sides are congruent as well. CPCTC is useful in proving various theorems about triangles and other polygons.

If triangles ABC and DEF are congruent, denoted as

Final answer:

Each congruent side of the A-frame house forms a 73° angle with the ground, and the statement that all right triangles are isosceles is false. CPCTC is a geometric theorem that states corresponding parts of congruent triangles are congruent.

Explanation:

Angles in an A-frame house

The given A-frame house forms an isosceles triangle with a peak angle of 34°. Using the theorem that the sum of angles in a triangle is 180°, we can calculate the angles each side forms with the ground. Since the two congruent sides are equal, the angles they form with the ground are also equal. There are two steps to solve this:

Subtract the peak angle from 180° to find the sum of the two base angles: 180° - 34° = 146°.

Divide the sum of the base angles by 2 (since they are equal in an isosceles triangle): 146° / 2 = 73°.

Therefore, each side forms a 73° angle with the ground.

All right triangles are isosceles - True or False?

This statement is false. Not all right triangles are isosceles. A right triangle is defined as having one 90° angle, but it doesn't necessarily have two sides of equal length, which would make it isosceles.

What does CPCTC represent?

CPCTC stands for Corresponding Parts of Congruent Triangles are Congruent. It is a theorem used in geometry to conclude that the corresponding parts (angles or sides) of two triangles are congruent, given that the triangles themselves are proven to be congruent based on certain criteria like side-angle-side (SAS) or angle-side-angle (ASA).

Final answer:

The probability that it will rain today or tomorrow, given the individual probabilities and the joint probability for both days, is calculated using the addition rule of probability, resulting in a probability of 0.5 or 50%.

Explanation:

The student is asking how to calculate the probability that it will rain today or tomorrow given the individual probabilities for rain on each day and the joint probability that it will rain on both days. This is a typical question involving the addition rule of probability.

To find the probability of either event A (rain today) or event B (rain tomorrow) occurring, we use the formula:

P(A or B) = P(A) + P(B) - P(A and B)

Where:

P(A) is the probability that it will rain today, which is 0.4,

P(B) is the probability that it will rain tomorrow, which is 0.3, and

P(A and B) is the probability that it will rain on both days, which is 0.2.

Substituting the given values, we get:

P(A or B) = 0.4 + 0.3 - 0.2

P(A or B) = 0.5

Therefore, the probability that it will rain today or tomorrow is 0.5, or 50%.

Final answer:

The simplified expression is [tex]-2a^2 + 4ab - 5a - 2b + b^2[/tex]

Explanation:

The expression -2a (a + b - 5) + 3 (-5a + 2b) + b (6a + b - 8) needs to be rewritten by expanding and combining like terms using the distributive property. To expand the expression, multiply each term inside the parentheses by the term outside the parentheses. Then, combine the like terms to simplify the expression.

Let's expand each term as follows:

-2a * a = -2a²

-2a * b = -2ab

-2a * (-5) = +10a

3 * (-5a) = -15a

3 * 2b = +6b

b * 6a = +6ab

b * b = b²

b * (-8) = -8b

Now, combine the like terms:

[tex]-2a^2 - 2ab + 10a - 15a + 6b + 6ab + b^2 - 8b[/tex]

The simplified expression is -

[tex]-2a^2 + 4ab - 5a - 2b + b^2[/tex]