If k pencils cost c cents what is the cost in cents of p pencils

Answers

Answer 1
the cost in cents of 1 pencil = c/k

the cost in cents of p pencils = (c/k) * p
Answer 2

If k pencils cost c cents. Then the cost in cents of p pencils will be cp / k.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

If k pencils cost c cents. Then the cost of each pencil is given as,

⇒ c / k

Then the cost in cents of p pencils is given as,

⇒ (c / k) x p

⇒ (cp) / k

If k pencils cost c cents. Then the cost in cents of p pencils will be cp / k.

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Related Questions

The measure of ∠B is (3x – 4 )° and the measure of ∠D is (2x – 6)°. What are the measures of angles B and D?

Answers

B = 110 D = 70 your welcome yall

The measures of angles B and D are 110° and 70° respectively.

What is cyclic quadrilateral?

The rule of cyclic quadrilateral states that, the sum of the opposite is supplementary i.e 180°

Therefore, applying this rule, Angle B and D are supplementary

Then, B+D=180°

Given that, B=3x-4 and D= 2x-6

Thus, (3x-4)+(2x-6)=180°

3x-4+2x-6=180°

3x+2x-4-6=180°

5x-10=180°

5x=180°+10

5x=190°

Then, x =190/5

x=38°

Then solving for B and D;

B=3x-4

B=3(38)-4

B=114-4

B=110°

Also, D=2x-6

D=2(38)-6

D=76-6

D=70°

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parallel lines r and s are cut by two transversals, parallel lines t and u

Answers

its not c or d for sure 

i believe it is b
its a <5 and <13 that is the right answer

I'm having trouble finding the answer to this question

Answers

I believe ABC is 125 degrees.
Those two angles are supplementary, so they add up to 180 degrees
180-55=125

Suppose you are thinking about buying one of two cars. Car A will cost $17,655. You can expect to pay an average of $1230 per year for fuel, maintenance and repairs. Car B will cost about $15,900. Fuel maintenance and repairs for it will average about $1425 per year. After how many years are the total costs for the cars the same? a. 5 years c. 9 years b. 7 years d. 11 years

Answers

A=17655+1230y, B=15900+1425y

We wish to know when A=B so:

15900+1425y=17655+1230y  subtract 15900 from both sides

1425y=1230y+1755  subtract 1230y from both sides

195y=1755  divide both sides by 195

y=9

So in 9 years both cars would cost the same.




After 9 years many years are the total costs for the cars the same.

What is an expression?

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division

Given that:-

Car A will cost $17,655. You can expect to pay an average of $1230 per year for fuel, maintenance and repairs. Car B will cost about $15,900. Fuel maintenance and repairs for it will average about $1425 per year. After how many years are the total costs for the cars the same?

We can form two-equation for the total cost of the two cars:-

A   =   17655  +   1230y,

B   =   15900  +   1425y

We wish to know when the cost will become the same for both the cars.

A     =     B

15900    +   1425y  =    17655  +    1230y  

Now subtract 15900 from both sides

1425y     =    1230y   +    1755  

Now subtract 1230y from both sides

195y     =    1755  

Now divide both sides by 195

y   =   9 years

Therefore After 9 years, many years are the total costs for the cars the same.

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In triangle DEF, DG = 10 cm. What is CG?

Answers

The answer is CG=5 CM

Answer:

5 cm is the correct answer it would be half of DG

Step-by-step explanation:

write an equation for a line perpendicular to the x-axis that passes through the point (5,1)

Answers

If it is perpendicular to the x-axis, it is a vertical line of the form:

x=k, since it must pass through (5,1) that vertical line is:

x=5
Final answer:

The equation of a line perpendicular to the x-axis passing through the point (5,1) is x = 5. This is because a vertical line crossing the x-axis at a specific point will have the same x-coordinate for all its points.

Explanation:

In mathematics, a line perpendicular to the x-axis is a vertical line that crosses the x-axis at a specific point. All points on this line will share the same x-coordinate. Therefore, a line that is perpendicular to the x-axis, and passes through the point (5,1) will have the equation x = 5. This equation represents a line that is vertical and intercepts the x-axis at the point where x equals 5. This is because in each point on the line, x remains constant, which is the characteristic of a vertical line in a Cartesian Coordinate System.

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Find the exact solution to the equation. Show your work for credit. (1 point) four to the power of quantity twelve minus four x equals two hundred and fifty six.

Answers

4^(12-4x)=256  realize that 256 is 4^4  so we really have:

4^(12-4x)=4^4  taking the natural log of both sides

(12-4x)ln4=4ln4  dividing both sides by ln4

12-4x=4  subtract 12 from both sides

-4x=-8  divide both sides by -4

x=2


The exact solution to the equation [tex]4^{(12 - 4x)[/tex] = 256 is x = 2. By recognizing that 256 is 4 raised to the fourth power, we equate the exponents and solve for x.

To solve this problem, we need to recognize that 256 is a power of 4. 4⁴ = 256. With this insight, the equation can be rewritten as:

[tex]4^{(12 - 4x)[/tex] = 4⁴

Since the bases are the same, we can equate the exponents:

12 - 4x = 4

Now, we'll isolate the variable x:

Subtract 12 from both sides: -4x = 4 - 12

-4x = -8

Divide both sides by -4: x = 2

Thus, the exact solution to the given equation is x = 2.

Can someone please help me with math for college readiness

Answers

6.79,7.729,31/4,7+5/6
it is best to start by converting all to decimals. so 7 5/6= 7.8333 and 31/4=7.75
o in order of least to greatest it is 6.79, 7.729, 31/4, 7 5/6.

Has 320 yards of fencing to enclose a rectangular area. find the dimensions of the rectangle that maximize the enclosed area. what is the maximum​ area

Answers

The dimensions of the rectangle that maximize the enclosed area are L = 80 yards and W = 80 yards. The maximum area is A = 80 * 80 = 6400 square yards.

To find the dimensions of the rectangle that maximize the enclosed area using 320 yards of fencing, we'll use the concept of optimization. Let's solve it step by step:

Let's assume the length of the rectangle is L and the width is W.

Perimeter constraint:

The perimeter of the rectangle is given as 2L + 2W, which must equal 320 yards:

2L + 2W = 320

Simplify the perimeter equation:

Divide both sides by 2 to get:

L + W = 160

Express one variable in terms of the other:

Solve the equation for L:

L = 160 - W

Area equation:

The area of the rectangle is given by A = L * W.

Substitute the value of L from the previous step into the area equation:

A = (160 - W) * W

A = 160W - W^2

Maximize the area:

To find the maximum area, we need to maximize the function A = 160W - W^2. This is achieved when the derivative is zero.

Take the derivative of A with respect to W:

dA/dW = 160 - 2W

Set dA/dW = 0 and solve for W:

160 - 2W = 0

2W = 160

W = 80

Substitute the value of W back into the perimeter equation to find the corresponding value of L:

L = 160 - W = 160 - 80 = 80

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Final answer:

The optimization problem involves finding the dimensions of a rectangle to maximize its area using a fixed amount of fencing. The dimensions that maximize the area are both 80 yards, making the maximum area 6400 square yards.

Explanation:

The subject of this question is Mathematics, specifically a problem about optimization in the field of Calculus. In the given problem, we wish to find a rectangular area that can be enclosed by 320 yards of fencing that maximizes the area.

Let's designate the rectangular area's width and length as x and y respectively. The problem can now be rephrased. With the total length of fencing equal to 320 yards, you can express this as 2x + 2y = 320. Simplifying this equation, we get x + y = 160, or y = 160 - x.

The area of a rectangle is computed as width times length, or in this case, x(160 - x). This is a quadratic function, and its maximum value happens at the vertex of the parabola defined by this function. For a quadratic in standard form like y = ax^2 + bx + c, the x-coordinate of the vertex is at -b/2a. In this case, the maximum area happens when x = 160/2 = 80.

Substituting this value back into the equation for the rectangle's dimensions gives y = 160 - 80 = 80. So, the dimensions that maximize the area for a rectangle with a parameter of 320 yards are both 80 yards. Therefore, the maximum area possible is 80*80 = 6400 square yards.

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Simplify the expression: -3(4a-5b)

Answers

 −3(4a−5b)=(−3)(4a+−5b)=(−3)(4a)+(−3)(−5b)=−12a+15b

how close are a meter and a yard? convert 1 meter into yards by using the fact
that there are 100 centimeters in a meter, 2.53 centimeters in a inch, 12 inches in a foot, and 3 feet in a yard.

Answers

1 meter= 100cm

2.53cm=1 inch

12 inches= 1 foot

3 feet= 1 yard

2.53*12*3=91.08

1 yard=91.08cm
1 meter=100cm

1 meter is 8.92cm longer than 1 yard

I hope this helps, if you need more elaboration, just ask

Find the difference- (ab+3a+7)- (-5ab-2)

Answers

(ab+3a+7)- (-5ab-2)
=ab+ 3a+ 7+ 5ab + 2
=3a + 6ab + 9

Joe gave the following argument: Since lim x→0 0 = 0,
(A) and since 0 = −1 x + 1 x ,
(B) we know that lim x→0 ( −1 x + 1 x ) = 0.
(C) But then, since lim x→0 ( −1 x + 1 x ) = lim x→0 ( −1 x ) + lim x→0 ( 1 x ),
(D) we can say that lim x→0 ( −1 x ) + lim x→0 ( 1 x ) = 0, which means that lim x→0 ( −1 x ) = − lim x→0 ( 1 x ).
(E) no error
In which line, if any, has joe made an error?

Answers

No error - A and B are completely right, and using the subtraction law D is right

Miss broom invested $10,000 into an account with an interest rate of 6% compounded annually which equation models the time it will take for his money to double?

A- logbase2 1.06= T

B- log2 =T

C-log1.06 =T

D= logbase1.06 2=t

Answers

The answer is
D= logbase1.06 2=t

If you compute it, you will will get 11.89 years which rounded to 12 years

Find the surface area of the cone to the nearest tenth.


A. 203 cm2
B. 1341.5 cm2
C. 747.7 cm2
D. 213.5 cm2

Answers

So i also need closure on this question actualy taking the geometry examen rn... and i figured i had to do (pi)* 7^2 = 152.938......
soooo like this is what you gone do....
(pi) * 7^2+ (pi) *7 *27
=747.6990.....
hope this helps 
THE STRUGGLE IS REAL

The surface area of the given cone is 747.32.

What is area of a cone?

"The total surface area of a cone is defined as the total area of the cone occupied in a three-dimensional area. It is equal to the sum of the curved surface and the base of the cone. "

Surface area of the cone is [tex]\pi*r(l+r )[/tex]

[tex](22/7)*7*(27+7)[/tex]

= 747.32

The surface area of the cone is 747.32

Hence, option C is correct.

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Which graph represents the function f(x) = x2 + 3x + 2?

graph 1

graph 2

graph 3

graph 4

Answers

Graph 1 obviously because it states x^2 meaning it is a quadratic function. This one requires very little explanation and it is instinctive given the parabola. The other graphs are linear or to the x power.

Answer:

Graph 1

Step-by-step explanation:

Here, the given equation is,

[tex]f(x)=x^2+3x+2-----(1)[/tex]

For x-intercept, f(x) = 0

[tex]x^2+3x+2=0[/tex]

[tex]x^2+2x+x+2=0[/tex]

[tex]x(x+2)+1(x+2)=0[/tex]

[tex](x+1)(x+2)=0[/tex]

[tex]\implies x=-1\text{ or } -2[/tex]

So, the x-intercept of the function are (-1,0) and (-2,0)

Since, the line must has at least one x-intercept.

Graph 2 and Graph 4 can not be the graph of the given function,

Also, for y-intercept,

Put x = 0 in equation (1),

We get, f(x) = 2,

Hence, the y-intercept of the given function is (0,2),

But in Graph 3 the y-intercept of the function = (0,1)

⇒ Graph 3 can not be the graph of the given function,

Therefore, Graph 1 is the correct graph of the given function.

Karen is trying to determine how long her 4-year-old daughter should sit in time-out for deliberately pouring her juice on the floor. if she uses the suggested estimate, her daughter will be in time-out for:

Answers

A good rule of thumb is one minute per year of your child's age. So Karen’s child is 4 years old, she would get four minutes of time-out. If you find that the shorter time-outs aren't having the wanted result, increase the length by half the time (so your 4-year-old would get an extra two minutes, for a total of six minutes).

What is the equation of the line perpendicular to 5x − 2y = −18 that contains the point (10, 4)?

y=-2/5x
y=-2/5x+8
y=-5/2x+29
y=5/2x-29

Answers

To find the slope of the line perpendicular to 5x-2y=-18. I would suggest changing the equation to point slope form or y=(5x/2)+9. The slope of the line perpendicular is the negative reciprocal. To find the reciprocal flip the slope of 5/2 to 2/5 and add a negative sign to -2/5. Now to find the constant of the equation solve the point slope form of y-4=-2/5(x-10) this simlifies to y=-2/5x+8. Your answer is the y=-2/5x+8.

Rita made $221 for 17 hours of work.At the same rate, how much would she make for 12
hours of work?

Answers

$221 / 17 = $13

$13 per hour

so if 12 hours then 12 x $13 = $156

answer

$156 

Using the concept of proportion, Rita would make $156 for 12 hours of work at the same rate.

We have,

We can use proportions to solve this problem.

Let x be the amount of money Rita would make for 12 hours of work.

We know that Rita made $221 for 17 hours of work,

which can be written as:

221/17 = x/12

To solve for x, we can cross-multiply and simplify:

221(12) = 17x

2652 = 17x

x = 156

Therefore,

Rita would make $156 for 12 hours of work at the same rate.

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Find the 4th term if the sequend in which a1 = 2 and a n+1 = -4a n + 2



***PLEASE HELP**

Answers

Given that
[tex]a_{n+1}=-4a_{n+2}[/tex] and [tex]a_1=2[/tex]

For n = 0,
[tex]a_1=-4a_2 \\ \\ 2=-4a_2 \\ \\ \Rightarrow a_2=-\frac{1}{2}[/tex]

common ratio = [tex]\frac{a_2}{a_1}=\frac{-\frac{1}{2}}{2}=-\frac{1}{4}[/tex]

4th term = [tex]a_4=a_1r^{4-1}=2(-\frac{1}{4})^3=2(-\frac{1}{64})=-\frac{1}{32}[/tex]

what is 15 square root to the nearest tenth

Answers

mathematically the answer would be a never ending decimal (3.87298...) but in this case it would be 3.9

a farmer needs to enclose a section of land in the shape of a parallelogram by using one side of a barn for one side the barn in the side opposite of the barn will be 10 ft long one of the other sides will be 6 feet long what is the length of the last side?

A) 6 feet
B) 16 feet
C) 4 feet
D) 10 feet

Answers

The geometric properties of the parallelogram show that each to opposite side of a parallelogram are parallel and equal in length.
Thus, for this problem:
The first two opposite sides will be 10 ft long and they are also parallel
The third side is 6 ft long
This means that the fourth side will definitely be equal to the third one and parallel to it.
The answer is : A) 6 ft

Answer: C:6

Step-by-step explanation:

I just got it right on the quiz

Simplify:

6( [tex]4/3 \f[/tex] ( 14 ÷ [tex] \frac{1}{7} [/tex] ) ) ÷ [tex] \frac{13}{10} [/tex]

-
I got 603 [tex] \frac{1}{12} [/tex] , but i'm not completely sure it's correct..

Answers

[tex]\bf 6\left[\cfrac{4}{3}\left(14 \div \cfrac{1}{7} \right) \right]\div \cfrac{13}{10}\impliedby recall~\mathbb{PEMDAS} \\\\\\ 6\left[\cfrac{4}{3}\left(\cfrac{14}{1} \cdot \cfrac{7}{1} \right) \right]\div \cfrac{13}{10}\implies 6\left[\cfrac{4}{3}\left(98\right) \right]\div \cfrac{13}{10}\implies 6\left[\cfrac{392}{3} \right]\div \cfrac{13}{10} \\\\\\ \cfrac{6\cdot 392}{3}\cdot \cfrac{10}{13}\implies 784\cdot \cfrac{10}{13}\implies \cfrac{7840}{13}\implies 603\frac{1}{13}[/tex]

Where does the normal line to the parabola, given below, at the given point, intersect the parabola a second time? illustrate with a sketch. (round the answers to three decimal places.) y = 4 x - 2 x^ 2 p = (2, 0)?

Answers

The graph of the parabola when sketched is shown in the picture illustrated as the blue curve. If you want to find the normal line to the parabola at point (2,0), you want to find the line perpendicular to the curve at that certain point. Note that two equations are perpendicular to each other when the product of their slopes is equal to -1. With that, let's find the slope of the parabola at point (2,0). The slope can be determined by finding the first derivative of the equation and substituting the x-coordinate of the point.

y' = 4 - 4x = 4-4(2) = -4
Thus, the slope of the normal line is 1/4 (negative reciprocal of -4). Its equation would be y = 1/4 x + b. To find b (y-intercept), substitute the coordinates of point (2,0):

0 = 1/4 (2) + b
b = -0.5

Therefore, the equation of the normal line is y = 1/4 x - 0.5. This is illustrated as the orange line in the picture.

Which system is the only inconsistent system?
Select one:
a.
y
y
=
=
x+4
2x+4
y=x+4y=2x+4

b.
y
y
=
=
x
−x
y=xy=−x

c.
y
y
=4
=
x−3
4x+3
y=4x−3y=4x+3

d.
y
2y
=2
=
x−3
4x−6
y=2x−32y=4x−6

Answers

Final answer:

Option (c) represents an inconsistent system of equations, as the constant terms are not proportional, while the coefficients of x are. This system (y=4x-3, y=4x+3) has no solutions.

Explanation:

In mathematics, specifically in algebra, an inconsistent system is a system of equations that has no solutions. To check which system is inconsistent from the options you've given, we need to compare the coefficients of each equation within a system. An inconsistent system will have proportional coefficients of x and y between the two equations, but the constant terms will not be proportional.

Looking at each option:

Option (a): y=x+4 and y=2x+4
Option (b): y=x and y=−x
Option (c): y=4x−3 and y=4x+3
Option (d): y=2x−3 and 2y=4x−6

From here, we can see that option (c): y=4x-3, y=4x+3 is inconsistent. In this system, the coefficients of x are proportional (4), but the constant terms (-3 and +3) are not proportional.

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whats the normal arm span for these heights? : 4'10,4'11,5'0,5'4,5'5,5,'7,5'8,5'9,5'10,5'11,6'0

Answers

 

In adults, the arm span is approximately 5 cm greater than the height in adult males and 1.2 cm in adult females. To calculate the arm span for the heights given, we add 5cm to their height. The following are the results:

 

Height                   Arm Span Length (in cm)

4’10                        152.32

4’11                        154.86

5’0                          157.4

5’4                          167.56

5’5                          170.10

5’7                          175.18

5’8                          177.72

5’9                          180.26

5’10                        182.80

5’11                        185.34

6’0                          187.88

 

To add, the total measurement of the length from the furthermost part of an individual's arms to the other end when raised equidistant to the ground at shoulder height at a 90º angle is called the arm span or wingspan.

A country population in 1991 was 231 million in 1999 it was 233 million . Estimate the population in 2003 using the exponential growth formula. Round you answer to the nearest million

Answers

p(y)=ir^t

233=231r^(1999-1991)

(233/231)^(1/8)=r

p(y)=231(233/231)^((y-1991)/8)  so in 2003

p(2003)=231(233/231)^((2003-1991)/8)

p(2003)=231(233/231)^(1.5)

p(2003)=234

So 234 million (to the nearest million people)


Answer:

population in 2003 is 234 million.

Step-by-step explanation:

A country's population in 1991 was 231 million

In 1999 it was 233 million.

We have to calculate the population in 2003.

Since population growth is always represented by exponential function.

It is represented by [tex]P(t)=P_{0}e^{kt}[/tex]

Here t is time in years, k is the growth constant, and  is initial population.

For year 1991 ⇒

233 = [tex]P_{0}e^{8k}[/tex] = 231 [tex]e^{8k}[/tex]

[tex]\frac{231}{233}= e^{8k}[/tex]

Taking ln on both the sides ⇒

[tex]ln(\frac{233}{231})=lne^{8k}[/tex]

ln 233 - ln 231 = 8k  [since ln e = 1 ]

5.451 - 5.4424 = 8k

k = [tex]\frac{0.0086}{8}=0.001075[/tex]

For year 2003 ⇒

[tex]P(t)=P_{0}e^{kt}[/tex]

P (t) = 231 × [tex]e^{(0.001075)(12)}[/tex]

     = 231 × [tex]e^{0.0129}[/tex]

     = 231 × 1.0129

     = 233.9 ≈ 234 million

Therefore, population in 2003 is 234 million.

17. Evaluate. Show your work.
a. 6!

b. 6P5


c. 12C3

Answers

[tex]6!=1\cdot2\cdot3\cdot4\cdot5\cdot6=720\\\\ 6P5=\dfrac{6!}{1!}=6!=720\\\\ 12C3=\dfrac{12!}{3!9!}=\dfrac{10\cdot11\cdot12}{2\cdot3}=220[/tex]

What is the area for this problem?

Answers

It's 324pi since the circumference is 2 pi r, you can divide 36 by 2 to find the radius, after finding the radius plug it into the area equation which is pi r^2

C = 2* pi *r = 36 pi

 r = 36pi/2pi = 18

We know that A= r^2 * pi

A = 18^2 * pi = 324 pi

the area would be 324PI square units



Please help me to do this one

Answers

Answer is 4

1. Multiple 29 by both side to get N by itself

2. solve 29/7.25 on a calculator, because it's easier

3. answer is 4.

4. Check your answer.  Plug in 4 to see if you get the same answer on both sides.  You should get .138 aprox. on both side. 

Answer is 4 cross multiply and divide
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