If a project is handed in late you receive 8/9 of your earned points. You received 72 points on your late project. How many points did you lose

Answers

Answer 1

Final answer:

In this situation, because the project was handed in late, you lost a total of 9 points. The full score was 81, and you got 72 after a deduction.

Explanation:

The principal in this problem is understanding proportion. Given that handing in a project late results in receiving 8/9, or approximately 88.88%, of the total points, we'll figure out the total possible score by dividing the received points (72) by the portion of the full score you got for handing in the project late, which is 8/9. So, 72 ÷ 8/9 = 81. This would be the original points you could have received. You can then subtract the received points (72) from the original points (81) to ascertain the number of points lost. Therefore, 81 - 72 = 9. Consequently, you lost 9 points because the project was handed in late.

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Related Questions

The perimeter of a rectangular field is 264 yards. If the width of the field is 54 yards, what is its length?

Answers

P = 2(L + W)
P = 264
W = 54

264 = 2(L + 54)
264 = 2L + 108
264 - 108 = 2L
156 = 2L
156/2 = L
78 <=== Length is 78 yards

First, we must multiple the width by two. Then, we subtract the perimeter by that number. Next, we divide the number we have by two.

54 * 2 = 108
264 - 108 = 156
156 / 2 = 78

The perimeter is 78 yards.

What best describes the greatest height a ball will bounce off the ground after being dropped from a height of 50 centimeters? Less than 50 centimeters, as the ball transforms some of its thermal energy into sound energy Less than 50 centimeters, as the ball transforms some of its potential energy into sound energy Greater than 50 centimeters, as the ball transforms some of its thermal energy into potential energy Greater than 50 centimeters, as the ball transforms some of its potential energy into thermal energy

Answers

Answer:
Less than 50 centimeters , as the ball transforms some of its potential energy into ound energy

Explanation:
When a ball is dropped from a height of 50 cm, several factors reduce the initial potential energy (PE) of the ball.
a. Between the time the ball is dropped and when it strikes the ground, aerodynamic frictional forces consume some of the PE.
b. When the ball hits the ground, the remaining PE is converted into kinetic energy (KE) as it strikes the surface.
c. The KE is dissipated by energy required to deform the ball, some of the KE is transformed into sound energy, and some of the KE is lost by frictional forces that generate heat (thermal energy).
d. The remaining energy is stored in the ball, and it causes the ball to rebound as if it was a wound spring with stored energy. The coefficient of restitution defines how much of the PE is stored for the rebound.

Answer:

B) Less than 50 centimeters , as the ball transforms some of its potential energy into sound energy

How can you use transformations to graph this function?

y=3x[tex] 7^{-x} [/tex]+2

Answers

[tex]\bf \qquad \qquad \qquad \qquad \textit{function transformations} \\ \quad \\\\ % left side templates \begin{array}{llll} f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}} \\ \quad \\ y=&{{ A}}({{ B}}x+{{ C}})+{{ D}} \\ \quad \\ f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}} \\ \quad \\ f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}} \\ \quad \\ f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}} \end{array}\\\\ --------------------[/tex]

[tex]\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\ \bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the y-axis}[/tex]

[tex]\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by }{{ D}}\\ \left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\ \left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{{{ B}}}[/tex]

with that template in mind, let's check

[tex]\bf y=\stackrel{A}{3}(7^{\stackrel{B}{-1}x})\stackrel{D}{+2}[/tex] <---- so the parent function will then be y = 7⁻ˣ

A = 3 it shrinks, in relation the y-axis, by a factor of 3 times, so is narrower.

B=-1 well, it flips it sideways, reflection over the y-axis.

D= +2 well, that's just a vertical shift of 2 units.

Sketch the graph of Y=7^X.

Reflect the graph across the y-axis to show the function y=7^-x.

Stretch the graph vertically by a factor of 3 to show the function y=3 x 7^-x.

Shift the graph up 2 units to show the function y= 3 x 7^-x +2

A car dealer recently sold five cars for the following profits 10, 126, 9,999, 12,398, 12,007, and 4,567. What was the mean for the profits of the sales

Answers

The answer is 9,819.4 Hope this helped :)

If you want to calculate the mean of several products, there is an easy way to do it - just add all of those numbers and divide the product by the number of items.
So, here is how to do it:
10,126 + 9,999 + 12,398 + 12,007 + 4,567 = 49,097
Now divide that number by 5 (the number of numbers):
49,097 / 5 = 9,819.4

The correct answer is 9,819.4

whole numbers includes zero but natural numbers do not

Answers

That is most certainly true!

I'm currently learning about this too.

I hope this helps you! :)

This is a true statement!

The set of counting numbers {1, 2, 3, 4, 5, ...} is called the set of natural numbers. The natural numbers begin at 1 and go on indefinitely.

When we include 0 in the natural numbers, we then have a new set of numbers called the whole numbers. All the natural numbers are contained within the set of whole numbers.

What are the maximum data rates of 802.11 legacy, 802.11a, 802.11b, and 802.11g?

Answers

802.11 legacy = 2 Mbps
802.11a = 54 Mbps
802.11b = 11 Mbps
802.11g = 54 Mbps

Final answer:

The 802.11 standards designate maximum data rates: 802.11 legacy offers 2 Mbps, 802.11a and 802.11g both offer 54 Mbps, and 802.11b offers 11 Mbps. These maximum rates depend on ideal conditions and can be lower in real-world usage.

Explanation:

The 802.11 wireless standards determine the maximum achievable data rates between a wireless device and a wireless access point. Here are the maximum data rates for the 802.11 legacy, 802.11a, 802.11b, and 802.11g:

802.11 legacy: The theoretical maximum speed is 2 Mbps.802.11a: It has a maximum data rate of 54 Mbps.802.11b: This standard allows for a maximum data rate of 11 Mbps.802.11g: This offers a maximum data rate of 54 Mbps, the same as 802.11a, but it is more widely compatible with other devices as it operates on the 2.4 GHz band.

It's important to note that these are the maximum possible data rates, under ideal conditions. In real-world usage, the actual data rate can be lower due to factors such as distance from the access point, interference, and the number of devices connected to the network.

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John drives to work each morning and the trip takes an average of µ = 38 minutes. the distribution of driving times is approximately normal with a standard deviation of σ = 5 minutes. for a randomly selected morning, what is the probability that john's drive to work will take between 36 and 40 minutes?

Answers

The Answer to this is 0.2743

Choose the compound inequality that can be used to solve the original inequality |3x – 5| > 10.

A. –10 < |3x – 5| < 10

B. 3x – 5 > –10 or 3x – 5 < 10

C. 3x – 5 < –10 or 3x – 5 > 10

D. –10 < 3x – 5 < 10

Answers

C i think , look at it maybe true

Compound inequality is the combination of more than one inequality.

The compound inequality from [tex]|3x - 5| > 10[/tex] is:

Given that:

[tex]|3x - 5| > 10[/tex]

When the above inequality is split, we have the following inequalities:

[tex]3x - 5 > 10[/tex]. [tex]3x - 5 < -10[/tex]

So, the result of the split is:

[tex]3x - 5 < -10[/tex] or [tex]3x - 5 > 10[/tex]

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Which number sentence correctly solves this problem?

Mount Everest is 8,848 meters high. K2 Mountain is 8,611 meters high. How much higher is Mt. Everest than K2 Mountain?

A.
8,848 + 8,611 = 17,459

B.

8,848 – 8,611 = 1,237

C.

8,848 – 8,611 = 237

D.
8,848 + 8,611 = 16,459

Answers

its c because when you subtract the two mountains you will get 237

What are the amplitude, period, and midline of f(x) = −4 cos(2x − π) + 3?

Answers

[tex]\bf \qquad \qquad \qquad \qquad \textit{function transformations} \\ \quad \\ % function transformations for trigonometric functions \begin{array}{rllll} % left side templates f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}} \\\\ f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\ f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}} \end{array} \\\\ -------------------\\\\[/tex]

[tex]\bf \bullet \textit{ stretches or shrinks}\\ \left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\ \bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the y-axis}[/tex]

[tex]\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\ \bullet \textit{vertical shift by }{{ D}}\\ \left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\ \left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}[/tex]

[tex]\bf \bullet \textit{function period or frequency}\\ \left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\ \left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)[/tex]

with that template in mind, let's check

[tex]\bf f(x)=-\stackrel{A}{4}(\stackrel{B}{2}x\stackrel{C}{-\pi } )\stackrel{D}{+3}\\\\ -------------------------------\\\\ Amplitude\implies 4\\\\ Period\implies \cfrac{2\pi }{B}\implies \cfrac{2\pi }{2}\implies \pi [/tex]

now, the function is just the parent cos(x), shrunk some, -4, and shifted about, now D = +3, that means it has a vertical shift of 3 units up.

the parent function cos(x), has a midline of y = 0, now, if we shift it upwards by 3 units, the new midline will then be y = 3.

A pyramid-shaped building is 340 ft tall and has a square base with sides of 567 ft. The sides of the building are made from reflective glass. What is the surface area of the reflective glass?

Answers

check the picture below.

now, notice, the reflective glass part of the building, is just the triangular faces, it has four of those.

now, notice that each triangular face has a base of 567 and a height or altitude of 442.69.

so the surface area with the reflective glass will be, the area of those four triangles, get the area of each and add them up.

The picture shows a triangular island Which expression shows the value of Q?

Answers

In trigonometric ratios, the cos (x) = adjacent over hypotenuse.

Therefore, in the diagram, cos (55°) = s/q
To isolate q, divide both sides by s
cos (55°) / s = 1/ q
Then flip both numerators and denominators (raise both sides to the power of -1)
q = s / cos (55°)

Answer is D

S/cos 55• the answer D

Six hikers shared 4 1/2 lbs of trail mix. How much trail mix did each hiker receive?

Answers

6 hikers = 4.5 lbs of trail mix

4.5 divided by 6= .75 lbs each hiker.

Divide 4 1/2 lb by 6 to determine the share given to each of the 6 hikers:

4 1/2 divided by 6 is the same as 9/2 divided by 6, or

9 1 9
--- * ---- = ------- = 3/4 lb. (answer)
2 6 12

Check by mult. 3/4 lb by 6: 18/4 = 9/2 = 4 1/2 lb. This is correct.

A quotient of 8.4×10^9 and a number n results in 5.6×10^27 what is the value of n

Answers

Translated to notation, this question is asking you to solve for n when:

[tex] \frac{8.4\times10^9}{n}=5.6\times10^{27} [/tex]

A good first step would be to multiply both sides by n, cancelling out the n in the denominator on the left side and leaving you with:

[tex]8.4\times10^9=(5.6\times10^{27})n[/tex]

And of course, to get n by itself from here, you simply divide both sides by [tex]5.6\times10^{27}[/tex]:

[tex]n= \frac{8.4\times10^9}{5.6\times10^{27}} [/tex]

If the variance of a probability was computed to be 3.6 grams, what is the standard deviation

Answers

the standard deviation is the square root of the variance
so if the variance is 3.6, the standard deviation is the sqrt 3.6...
sqrt 3.6 = 1.897 <= if u need it rounded, it is 1.9 grams

Final answer:

The standard deviation is the square root of the variance, which is about 1.897 grams when the variance is 3.6 grams.

Explanation:

If the variance of a probability was computed to be 3.6 grams, the standard deviation is the square root of the variance. To calculate the standard deviation, you perform the following steps:

First, recognize that variance (σ²) is the square of the standard deviation (σ).To find the standard deviation, take the square root of the variance.Therefore, the standard deviation is √3.6 g.

By using a calculator, we find that the standard deviation is approximately 1.897 grams.

Which statements about the sum of the interior angle measures of a triangle in Euclidean and non-Euclidean geometries are true?
A) In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in elliptical or spherical geometry the sum is less than 180 degrees.
B) In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in elliptical or spherical geometry the sum is greater than 180 degrees.
C) In Euclidian geometry the sum of the interior angle measures of a triangle is less than 180 degrees, but in hyperbolic geometry the sum is equal to 180 degrees.
D) In Euclidian geometry the sum of the interior angle measures of a triangle is greater than 180 degrees, but in hyperbolic geometry the sum is less than 180 degrees.
In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in hyperbolic geometry the sum is less than 180 degrees.

Answers

In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in elliptical or spherical geometry the sum is greater than 180 degrees. As well as In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in hyperbolic geometry the sum is less than 180 degrees. Are the answers.

The statements that are true about the information given will be:

In Euclidian geometry, the sum of the interior angle measures of a triangle is 180 degrees, but in elliptical or spherical geometry the sum is greater than 180 degrees.In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in hyperbolic geometry the sum is less than 180 degrees.

It should be noted that Euclidian geometry is simply about understanding the geometry of flat, two-dimensional spaces while non-Euclidian geometry is about curved surfaces.

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Explain why the hypotenuses of the triangles below have the same slope.

Answers

They have the same slope because they are similar. The smaller one is 1/2 the size of the bigger one and they have a ratio of 1:2 which makes them similar.

The hypotenuses are the same because they fall on the same line.

write the equation for a line that intersects points (1,3) and (2,5)

Answers

y=2x+1 is your answer

y=2x+1 is the correct answer

How many grains of sand in a 10kg bag if one grain weighs 10 to the negative third gram

Answers

If one grain of sand weighs 10^-3 gram, it is one thousandths of a gram. A kilogram (kg), is 1000 times the mass of a gram. So, you take the 10 kg and multiply by a conversion factor of 1 kg equaling 1000g. This results in you having 10000 grams. Multiply that by another thousand, seeing as each grain of sand weighs one thousandth of a gram. This should result in you getting 10000000, or 1.0 x 10^7 grains of sand.

Final answer:

To determine the number of grains of sand in a 10kg bag with each grain weighing 10 to the negative third gram, convert the weight to grams and then divide by the weight of one grain. The answer is 10 million grains.

Explanation:

Grains of sand in a 10kg bag can be calculated by converting the weight to grams first: 10kg = 10,000g. Then, since each grain weighs 10-3g, we divide the total weight by the weight of one grain: 10,000g / 10-3g = 10,000,000 grains. So, there are 10 million grains of sand in a 10kg bag.

An elevator descends 1500 feet in 60 seconds. Find the change in height per second.

Answers

1500ft/60s = 25seconds

The answers is height=25

Find the LCM of 8 and 12.

Answers

✨24✨

the least common multiple is 24, the greatest common diviser is 4

You need to write out the 8 and the 12 times table and you then find the lowest number that is the same:

8:
8,16,24,32

12:
12,24,36,48

As you can see the lowest number that is the same for both of them is 24, thus the lowest common multiple is 24.

Hope this helps! :)

HURRY

At the grocery store checkout, you watch at the register as it rings up your purchases and coupons. The prices are as follows: $2.95 $1.19 $4.61 $1.74 $3.04 $8.83 $1.16 − $0.75 (coupon) − $1.00 (coupon) The register gives your total bill as $21.77. Round each price and coupon to the nearest dollar and then estimate the total amount of the bill. Using your estimate, determine whether the total on the register is reasonable. Justify your answer.

Answers

$3, $1, $5, $2, $3, $9, $1 = $24 - $1 = $23 - $1 = $22.

$22 is the estimation of the bill when all of the amounts are rounded to the nearest dollar. The estimation is greater than the total bill which is 23 cents less than the estimation. The total on the register is reasonable and accurate.

Valerie earns $24 per hour. Which expression can be used to show how much money she earns in 7 hours?

A. ( 7 + 20 ) + ( 7 + 4 )

B. ( 7 x 20 ) + ( 7 x 4 )

C. ( 7 + 20 ) x ( 7 + 4 )

D. ( 7 x 20 ) x ( 7 x 4 )

Who ever answers the best gets brainliest!

Answers

The answer is B) (7x20) + (7x4)

The answer is B (7•20)•(7+4)

At a rate of 4%, you paid $144.00 in interest over a two-year period. What was the original amount of your loan?

A. $2,000.00
B. $2,550.00
C. $2,250.00
D. $1,800.00

Answers

Simple interest - not compounded you got $ 1,800
Formula

I= P x r x t
where:
I= Interest
P is the principal amount, $1800.00.
r is the interest rate, 4% per year, or in decimal form, 4/100=0.04.
t is the time involved, 2 year(s) time periods.

So, t is 2 year time periods.
To find the simple interest, we multiply 1800 × 0.04 × 2 to get that: $144.00

The formula that will be used here is: I = PRT,
Where I = interest = $144.00
P = principal = ?
R = rate = 4% = 0.04
T = time = 2 years
I = PRT
P = I / RT
P = 144 / [0.04 * 2] = 144 / 0.08
P = 1800.
Therefore, the principal is $1,800.00.
The correct answer is D.

write an addition problem that has sum of 8/5

Answers

3/5 + 5/5 = 8/5

4/5 + 4/5 = 8/5

7/5 + 1/5 = 8/5

8/10 + 8/10 = 8/5

These are just a few examples

hope this helps

Hey guys, I need help answering this question for my Algebra 2 class.

Answers

Put into standard form: y^2 - 20x - 6y - 51 = 0
We can see immediately that this is a horiz. parabola, because y is squared, not x. Because y^2 and x are both positive, we know that the parabola opens to the right. Where is the vertex?

y^2 - 6y + 9 - 9 -51 = 20 x (after completing the square)
Then (y-3)^2 - 60 = 20x, or (1/20)(y-3)^2 -3 = x, or (1/20)(y-3)^2=x+3
The vertex is at (-3,3).

Comparing (1/20)(y-3)^2=x+3 to x-h = 4p(y-3)^2, we see that p = 1/80

The focus is p units to the right of the vertex, at (-3+1/80, 3).

The directrix, a vertical line, is p units to the left of the vertex, at x = -3-1/80.

Please ask questions if need be.

Services provided by public-service companies, such as water, electricity, and gas, are all known as

Answers

Public Utility or Public Services

Answer:

Step-by-step explanation:

A. UTILITIES

rewrite 19/30 and 13/20 so that they have a common denominator then Then, use
<
,
=
, or
>

Answers

Must determine the LCD. Think: what is the smallest (least) number divisible by both 30 and 20? You could, of course, just multiply 30 and 20, obtaining 600, but that would not be the LCD.

Note that 30 and 20 share the common factor 10. Multiplying 3 and 2 together produces 6. The LCD is 10*6 = 60. Note that both 30 and 20 divide into 60 with no remainder.

Then 19/30 = 2(19) / 2[30] = 38/60, and

13/20 = 3(13) / 3[20] = 39/60.

Which is larger, 38/60 or 39/60?

Write the relationship between these 2 numbers using the appropriate inequality operator.

Answer: [tex]\dfrac{38}{60}<\dfrac{39}{60}[/tex]

Step-by-step explanation:

The given fractions : [tex]\dfrac{19}{30}\text{ and }\dfrac{13}{20}[/tex]

The denominators of the above fraction : [tex]30, 20[/tex]

Least common multiple (LCM) of (30,20)=[tex]3\times2\times5\times2=60[/tex]

Multiply 2 to the numerator and denominator of [tex]\dfrac{19}{30}[/tex] and 3 to the numerator and denominator of [tex]\dfrac{13}{20}[/tex], we get

[tex]\dfrac{19\times2}{30\times2}=\dfrac{38}{60}[/tex]

[tex]\dfrac{13\times3}{20\times}=\dfrac{39}{60}[/tex]

Clearly , [tex]\dfrac{38}{60}<\dfrac{39}{60}[/tex]

At each turn, a gambler bets a certain amount, wins it with probability p and loses it with probability q = 1−p. when he begins playing, he has $k for some integer k > 0 and his goal is to reach $n for some integer n > k, after which he stops playing. he also stops playing if he loses all his money. the gambler has the option of betting $1 at each turn and the option of betting $0.5 at each turn. show that betting $0.5 is a better option if p > 1/2 and that betting $1 is a better option if p < 1/2.

Answers

Here two cases of the probability,
p > 1/2 or p <1/2

Here, q = 1 - p
So, When p > 1/2 the q < 1/2 &
When p < 1/2 the q > 1/2

So, in first case (p > 1/2 the q < 1/2) Winning chances is more compare to Loosing, So put the Bet maximum and is of $1

Another case (p < 1/2 the q > 1/2) Winning chances is less compare to Loosing, So put the Bet minimum and is of $0.5

Which property is demonstrated below?

17/3 * 3/17=1

associative property of multiplication
inverse property of multiplication
identity property of multiplication
commutative property of multiplication

Answers

we know that

The Inverse Property of Multiplication states that the product of any number and its multiplicative inverse is one

[tex]\frac{a}{b}* \frac{b}{a}=1[/tex]

in this problem we have

[tex]\frac{a}{b}=\frac{17}{3}[/tex]

[tex]\frac{b}{a}=\frac{3}{17}[/tex] -----> multiplicative inverse of [tex]\frac{a}{b}[/tex]

substitute

[tex]\frac{17}{3}*\frac{3}{17}=1[/tex]

therefore

the answer is

inverse property of multiplication

Answer:

inverse property of multiplication or b on edg 2021

Step-by-step explanation:

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