If a polygon has six sides, then it is a hexagon. true or false.

Answers

Answer 1
If a polygon does not have six sides, then it is not a hexagon.

Related Questions

The perimeter of a rectangle is 96 ft. The ratio of its length to its width is 5 : 3. What are the dimensions of the rectangle?

Answers

I hope this helps you




length/width=5/3


length=5/3width


Perimeter =2 (width+length)


96=2 (width +5/3width)


48=8/3width


width=48.3/8


width=18


length=5/3.18


length=30

Maple Grove wants to include two types of maple trees, the namesake of the city,for their parks.Two varieties of maple trees have been selected.One variety costs $80 per tree; the other more colorful variety costs $85 per tree. The tree budget must not exceed $75,000. Citizens want more of the colorful $85 trees than the others if possible.

Let x be the number of $80 trees and y the number of $85 trees. Which system of inequalities represents the situation?

Options:
80x+85y>= 75,000 x<=y
80x+85y>=75,000 x>=y
80x+85y<=75,000 x>=y
80x+85y<=75,000 x<=y ...?

Answers

If you’re on Plato Your answer will be 80x+85y <=75,000 x<=y

which equation is equivalent to
2x + 4a = 10
A. x= 5/4a
B. x= 5 + 2a
C. x= 10 - 4a
D. x=5 - 2a

Answers

In all the answers we are solving for x. That means x needs to be by itself.

2x + 4a = 10

Subtract 4a.

2x = 10 - 4a

Divide by 2.

x = 5 - 2a

Answer is....

D. x=5-2a

An equation is equivalent to 2x + 4a = 10 will be D. x=5-2a.

What are equivalent expressions?

Those expressions who might look different but their simplified forms are same expressions are called equivalent expressions.

To derive equivalent expressions of some expression, we can either make it look more complex or simple. Usually, we simplify it.

In all answers we are solving for x. That means x needs to be by itself.

2x + 4a = 10

Subtract 4a;

2x = 10 - 4a

Divide by 2;

x = 5 - 2a

D. x=5-2a

Therefore, an equation is equivalent to 2x + 4a = 10 will be D. x=5-2a.

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Find parametric equations for the tangent line at the point (cos(3pi/6),sin(3pi/6), (3pi/6))
on the curve x=cost, y= sint, z=t
x(t)=?
y(t)=?
z(t)=?

Answers

[tex]r(t)=(\cos{t},\sin{t},t) \\r'(t)=(-\sin{t},\cos{t},1) \\t= \frac{3\pi}{6} = \frac{\pi}{2} \\ r'(t)=(-\sin{\frac{\pi}{2}},\cos{\frac{\pi}{2}},1) \\ r'(t)=(-1,0,1) \\ \\x=0+t(-1)=-t \\y=1+t\times 0=1 \\z= \frac{\pi}{2} +t[/tex]

Solve (x + 2 < 5) (x - 7 > -6).
Please help

Answers

Hello :)
==========================================================
x+2<5
x<5-2
x<3
==========================================================
x-7>-6
x>-6+7
x>1
==========================================================

if AB is congruent to ED and BC is congruent to DC, how is AC congruent to EC

Answers

What shape or segments are you working with?
Pentagon?

A kite, flying 50 feet high in the air is attached by a string to a stake in the sand. How long is the string to the nearest tenth of a foot?

a) 50.0 feet
b) 70.7 feet
c) 86.6 feet
d) 100.0 feet ...?

Answers

Answer:

the answer is b) 70.7 feet

Step-by-step explanation:

thank you for amazing answers on the board.

Use one transformation to solve n-4.6=2.98

Answers

what are the options of tranformation ??/
 n = —7.58 n = 8.58. = -1.62.

Inez has 699 pennies and 198 nickels estimate how many more pennies than nickels she has.

Answers

She has 501 more pennies than nickles.
About 500 more pennies than nickels


what is point O on MN called if MO=ON

Answers

O in this case must be the midpoint.

Given that f(x) = 3x + 1 and g(x) = the quantity of 4x plus 2
divided by 3, solve for g(f(0)).

2
6
8
9

Answers

Replace x in g(x) by 3x+1 and you get:
(4(3x+1)+2)/3 = (12x+4+2)/3 replace now x by 0 and solve
(12*0+6)/3 = 6/3 = 2
So the answer is 2

Solve. 3t < –15 (1 point)
t < –5
t > –5
t < –45
t > –45

Answers

Final answer:

The solution to the inequality 3t < –15 is t < –5, attained by dividing both sides by 3.

Explanation:

The student's question involves solving an inequality, specifically 3t < –15. To solve for t, we need to isolate t on one side of the inequality. This can be done by dividing both sides of the inequality by 3. The solution to the inequality is:

Divide both sides by 3: t < –5

Therefore, the correct answer to the inequality 3t < –15 is t < –5. The other options such as t > –5, t < –45, and t > –45 are incorrect.  

8 is 15% of what number?
15% of 18.95 is what number?
what percent of 64 is 326?
10% of what number is 40?

Answers

Q1. The answer is 53.33

The initial number is 100%. So, make a proportion:
If 8 is 15%, what number is 100%?
8 : 15% = x : 100%
15% * x = 8 * 100%
x = 8 * 100% / 15% = 53.33


Q2. The answer is 2.8425

The initial number 18.95 and it is 100%. How much is its 15%? Make a proportion:
If 18.95 is 100%, what number is 15% of it?
18.95 : 100% = x : 15%
x * 100% = 18.95 * 15%
x = 18.95 * 15% / 100% = 2.8425


Q3. The answer is 509.375%

The initial number is 64 and it is 100%. So, what percent is 326? Make a proportion:
If 64 is 100%, 326 is what percent?
64 : 100% = 326 : x
x * 64 = 326 * 100%
x = 326 * 100% / 64 = 509.375%


Q4. The answer is 400.

The initial number is 100%. Make a proportion:
If 40 is 10%, what number is 100%?
40 : 10% = x : 100%
x * 10% = 40 * 100%
x = 40 * 100% / 10%
x = 400

During a 52 week period, a company paid overtime wages for 19 weeks and hired temp help for 11 weeks. During 5 weeks, the company paid overtime AND hired temp help. If an auditor randomly examined the payroll for only one week, whats the probability that the payroll for that week contained overtime wages or temp help wages? ...?

Answers

P(overtime wage) = 19/52 + 5/52 = 24/52
P(temp help wage) = 11/52 + 5/52 = 16/52
P(overtime or temp help) = P(overtime) + P(temp help)
= 24/52 + 16/52
= 40/52 = 10/13

The probability that the payroll for one week contained overtime wages or temporary help is [tex]\boxed{\frac{10}{13}}[/tex].

Further explanation:

It is given that during a [tex]52[/tex] week period, a company paid overtime wages for [tex]19[/tex] weeks and hired temporary help for [tex]11[/tex] weeks.

During [tex]5[/tex] weeks, the company paid overtime and hired temporary help.

Calculation:

A company paid overtime wages for [tex]19[/tex] weeks and [tex]5[/tex] weeks during the [tex]52[/tex] week period.

Therefore, the probability of overtime wages [tex]P(O)[/tex] is calculated as follows:

[tex]\begin{aligned}P(O)&=\dfrac{19}{52}+\dfrac{5}{52}\\&=\dfrac{19+5}{52}\\&=\dfrac{24}{52}\end{aligned}[/tex]

The probability of overtime wages is [tex]\frac{24}{52}[/tex].  

The same company hired temporary help for [tex]11[/tex] weeks and [tex]5[/tex] weeks during the [tex]52[/tex] week period.

Therefore, the probability of temporary help [tex]P(H)[/tex] is calculated as follows:

[tex]\begin{aligned}P(H)&=\dfrac{11}{52}+\dfrac{5}{52}\\&=\dfrac{11+5}{52}\\&=\dfrac{16}{52}\end{aligned}[/tex]  

The probability of temporary help is [tex]\frac{16}{52}[/tex].  

Now, the combined probability [tex]P[/tex] that the payroll for one week contained overtime wages or temporary help is calculated by adding the probabilities of overtime wages and temporary help as follows:

[tex]\begin{aligned}P&=\dfrac{24}{52}+\dfrac{16}{52}\\&=\dfrac{24+16}{52}\\&=\dfrac{40}{52}\\&=\dfrac{10}{13}\end{aligned}[/tex]

 

The probability that the payroll for one week contained overtime wages or temporary help is [tex]\boxed{\dfrac{10}{13}}[/tex].

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Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Probability

Keywords: Probability, events, outcome, sample, experiment, equally likely, random, complementary events, joint probability, independent events, mutually exclusive events, conditional probability.

Yen calculates the product 5/8 times 24/25. before he multiples he

Answers

the ans is u divide before u multiply
it just BODMAS rule f u kno t (brackets of division multiplication addition and subtraction one comes before the other 

Answer:

[tex]\frac{1}{1} \times \frac{3}{5}[/tex]

Step-by-step explanation:

The complete question is

Yen calculates the product 5/8 x 24/25. before he multiplies, he simplifies all the factors. what does the problem look like after he simplifies the factors?

The given product is

[tex]\frac{5}{8} \times \frac{24}{25}[/tex]

Then, Yen simplifies and the problem looks like

[tex]\frac{1}{1} \times \frac{3}{5}[/tex]

Because, we simplified 5 with 25 and 8 with 24.

Therefore, the result of the product is

[tex]\frac{3}{5}[/tex]

lottie needs a driver. Drive A is offering his services for an initial $200 in addition to $80 per hour. Driver B is offering this service for an intal $230 and an addition of $70 per hour When will the two drivers charge the same amount

Answers

200 + 80h = 230 + 70h
80h - 70h = 230 - 200
10h = 30
h = 30/10
h = 3...they will charge the same rate at 3 hrs
Final answer:

Driver A and Driver B will charge the same amount after 3 hours of service.

Explanation:

The subject of this question is a problem involving linear equations, a topic in mathematics. Specifically, it pertains to the intersection point of two linear functions, representing the costs charged by the two drivers over time. Let's denote the driving time as 't' (in hours) and the total cost as 'C' to solve it.

Driver A's cost function could be formulated as C = 200 + 80t, while Driver B's as C = 230 + 70t.

To find out when both drivers will charge the same amount, set these two equations equal to each other:

200 + 80t = 230 + 70t

This simplifies to 10t = 30 after subtracting 200 from both sides and 70t from both sides. Finally, dividing by 10 gives us t = 3.

Therefore, both drivers would charge the same amount after 3 hours of service.

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Pleasee help x.x 1. Solve the system by elimination-
-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5
2.Solve using substitution-
x-y-z=-8
-4x+4y+5z=7
2x+2z=4

Thanks for any help :o

Answers

Q1. The answer is x = 1, y = 1, z = 0

(i) -2x+2y+3z=0
(ii) -2x-y+z=-3 
(iii) 2x+3y+3z=5
_________
Sum up the first and the third equation:
(i) -2x+2y+3z=0
(iii) 2x+3y+3z=5
_________
5y + 6z = 5

Sum up the second and the third equation:
(ii) -2x-y+z=-3 
(iii) 2x+3y+3z=5
_________
2y + 4z = 2


(iv) 5y + 6z = 5
(v) 2y + 4z = 2
________
Divide the fifth equation by 2
(iv) 5y + 6z = 5
(v) y + 2z = 1
________
Multiple the second equation by -3 and sum the equation
(iv) 5y + 6z = 5
(v) -3y - 6z = -3
________
2y = 2
y = 2/2 = 1


y + 2z = 1
1 + 2z = 1
2z = 1 - 1
2z = 0
z = 0


-2x-y+z=-3
-2x - 1 + 0 = -3
-2x = -3 + 1
-2x = -2
x = -2/-2 = 1



Q2. The answer is x = -37, y = -84, z = -35

(i) x-y-z=-8 
(ii) -4x+4y+5z=7 
(iii) 2x+2z=4
______
Divide the third equation by 2 and rewrite z in the term of x:
(iii) x+z=2
z = 2 - x
______
Substitute z from the third equation and express y in the term of x:
x-y-(2-x)=-8 
x - y - 2 + x = 8
2x - y = 10
y = 2x - 10
______
Substitute z from the third equation and y from the first equation into the second equation:
-4x + 4y + 5z = 7 
-4x + 4(2x - 10) + 5(2 - x) = 7
-4x + 8x - 40 + 10 - 5x = 7
-x -30 = 7
-x = 30 + 7
x = -37
y = 2x - 10 = 2*(-37) - 10 = -74 - 10 = -84
z = 2 - x = 2 - 37 = -35

Juan charges $3.50 per hour for babysitting. Write a rule to describe the amount of money (M) earned is a function of the number of hours (h) spent baby-sitting. HELP PLEASE

Answers

M(earned money)=h(worked hours)*$3.50

What is 110.079 to the nearest hunderdths?

Answers

110.08 

hope this is what youre looking for

A horizontal pull A pulls two wagons over a horizontal frictionless floor, the first wagon is 500N, the second is 2000 N. The tension in the light horizontal rope connecting the wagons is.

the options are:
a) equal to A, by Newton’s third law.
b) equal to 2000 N.
c) greater than A.
d) less than A.

Answers

The best option is (d) i.e;  less than A.

A cab charges $1.45 for the flat fee and $0.55 for each mile. Write and solve an inequality to determine how many miles Ariel can travel if she has $35 to spend. please help!

Answers

The answer is 1.45 + 0.55x ≤ $35; x ≤ 61

x - a number of miles

T - the total amount
T ≤ $35
T = 1.45 + 0.55x

1.45 + 0.55x ≤ 35
0.55x ≤ 35 - 1.45
0.55x ≤ 33.55
x ≤ 33.55 : 0.55
x ≤ 61 miles

Solve log11 (y + 8) + log11 4 = log11 60. what is y?

Answers

y = 7 You have to condense the left side using properties of logs.

Answer:

The value of y is 7.

Step-by-step explanation:

The given equation is

[tex]log_{11}(y+8)+log_{11}4=log_{11}60[/tex]

[tex]log_{11}[(y+8)4]=log_{11}60[/tex]               [tex][\because log_ax+log_ay=log_axy][/tex]

[tex]log_{11}(4y+32)=log_{11}60[/tex]

Equating both sides.

[tex]4y+32=60[/tex]

[tex]4y=60-32[/tex]

[tex]4y=28[/tex]

Divide both sides by 4.

[tex]y=7[/tex]

Therefore the value of y is 7.

The amount of weight that Sam loses is directly proportional to the number of hours he spends exercising. If Sam loses a pound of weight for each 3 hrs of exercise, how many hours must he spend exercising to lose 25 lbs?
A) 25 hrs
B) 50 hrs
C) 75 hrs
D) 80 hrs

Answers

It should be C, 75 hours. To explain why this is, if there is one pound loss for each three hours of exercise, then multiplying you multiply 3 hours of exercise to 75 pounds to get the total number of how many hours is needed to lose 25 pounds.

Answer:

The answer is C. 75 hours.

Step-by-step explanation:

In order to determine the hours, we have to know about direct proportionality.

The direct proportionality happens when two variables increase at the same time and their rate is a constant. It means that if one variable is increased, so the other variable will be increased too.

I have attached an image that shows a graph of two variables with direct proportionality.

In this case, we can get the constant of both variables: losing weight and the spending time.

[tex]k=\frac{Weight}{Time}=\frac{1}{3} =0.33[/tex]

Then we need to know how many hours Sam will spend to lose 25 lbs:

[tex]\frac{25}{T}=k=0.33\\ T=\frac{25}{0.33}\\ T=75.76[/tex] hours.

Finally, Sam needs to spend 75 hours to lose 25 lbs.

Which of the following relations are functions?

A. {(a,b),(b,a),(c,c),(e,d)}
B. {(c,e),(c,d),(c,b)}
C. {(b,b),(c,d),(d,c),(c,a)}
D. {(a,b),(b,c),(c,d),(d,e)}

Answers

{(c,e),(c,d),(c,b)} is NOT a function since the input c has multiple outputs (e,d,b). So choice B is out

{(b,b),(c,d),(d,c),(c,a)} is NOT a function either. The input 'c' corresponds to the output 'd' and 'a' at the same time. So choice C is out too

Choices A and D are the answer. They are functions since any given input corresponds to exactly one output. 

At first public inquiry showed there were 637000 women motorcyclists in the US up from 437000 just 8 years ago before it. Find the percent of increase in the number of women motorcyclists during these 8 years

Answers

I would say to do 637000-437000, which is 200000, and then do 200000/637000. You get 0.314, and the percentage of that in hundreds is 31%. 
Final answer:

The percent of increase in the number of women motorcyclists over the 8-year period is approximately 45.77%, calculated by finding the difference between the final and initial number of motorcyclists, dividing by the initial number, and converting the ratio to a percentage.

Explanation:

To calculate the percent of increase in the number of women motorcyclists over the 8-year period provided, follow these steps:

Determine the initial and final values. Initial value: 437,000; Final value: 637,000.

Calculate the increase by subtracting the initial value from the final value: 637,000 - 437,000 = 200,000.

Divide the increase by the initial value to find the increase ratio: 200,000 / 437,000 ≈ 0.4577.

Multiply the increase ratio by 100 to convert it to a percentage: 0.4577 * 100 ≈ 45.77%.

Therefore, the percent of increase in the number of women motorcyclists during these 8 years is approximately 45.77%.

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Identify the expression as a numerical expression or a variable expression. For a variable expression, name the variable.

1 × 12

A. numerical expression

B. variable expression; a is the variable.

C. variable expression; there is no variable.

D. variable expression; l is the variable.

Answers

The best and most correct answer among the choices provided by the first question is the first choice or letter A.

The expression above is an example of a numerical expression.


I hope my answer has come to your help. God bless and have a nice day ahead!

1. The figure attached is a regular octagon with radii and an apothem drawn. What is the measure of angle 1?
A. 22.5 degrees
B. 45 degrees
C. 60 degrees
D. 67.5 degrees

Answers

Angle on a point = 360°
Angle 1 = 360/8 = 45°

example of why division is not associative.

Answers

2÷(1÷2)=4≠1=(2÷1)÷2

Division is not associative, as if you look at one of the operands to a nest of divisions, the result will vary either in proportion to it or inversely to it depending on whether it's to the right of an odd or even number of divisions. And the basic associative law changes the number of operations the rightmost operand is to the right of by 1.

The order of division determines the numerator and the denominator and this can effect the value. And example of this:
3/2 = 1.5
2/3 = 0.6667
Whereas, multiplication is not affected by the order:
2 x 3 = 6
3 x 2 = 6

Scientists are studying the temperature on a distant planet. Let
y
represent the temperature (in degrees Celsius). Let
x
represent the height above the surface (in kilometers). Suppose that
x
and
y
are related by the equation
y=41-3x
.

Answer the questions below.
Note that a change can be an increase or a decrease.
For an increase, use a positive number. For a decrease, use a negative number.


what is the temperature on the surface of the planet?

what is the temperature change for each kilometer we go up from the surface?

Answers

41 degrees Celsius
3 less degrees Celsius

Answer:

The temperature on the surface of the planet is 41 °C.The tempearture decreases 3 °C when the height increases 1 km.

Step-by-step explanation:

The given equation is

[tex]y=41-3x[/tex]

Where [tex]x[/tex] is the height above the surface and [tex]y[/tex] is the temperature in degrees Celsius.

Now, the temperature on the surface can be find when the height above the surface is zero, that is [tex]x=0[/tex]. So, we replace this value and solve for [tex]y[/tex]

[tex]y=41-3x=41-3(0)\\y=41[/tex]

Therefore, the temperature on the surface of the planet is 41 °C.

The second question is about the constant rate of change of the given relation, which is also the slope of the linear expression. That constant rate of change is always the coefficient of variable [tex]x[/tex]. Therefore, the ratio of change is   [tex]r=-3[/tex]. Which means the tempearture decreases 3 °C when the height increases 1 km.

The decreasing behaviour is deduct from the ratio of change, when it's negative, that means the function decreases, like in this case.

x^2-14x-4=0, solve by completing the square

Answers

The answer is: x = 7 - √53      or      x = 7 + √53

The general quadratic equation is: ax² + bx + c  = 0.
But, by completing the square we turn it into: a(x + d)² + e = 0, where:
d = b/2a
e = c - b²/4a
Our quadratic equation is x² - 14x -4 = 0, which is after rearrangement:
So, a = 1, b = -14, c = -4
Let's first calculate d and e:
d = b/2a = -14/2*1 = -14/2 = -7
e = c - b²/4a = -4 - (-14)²/4*1 = -4 - 196/4 = -4 - 49 = -53
By completing the square we have:
a(x + d)² + e = 0

1(x + (-7))² + (-53) = 0
(x - 7)² - 53 = 0
(x - 7)² = 53
x - 7 = +/-√53
x = 7 +/- √53

Therefore, the solutions are:
x = 7 - √53
or
x = 7 + √53

The solution of the equation found by completing the square are;

x = 7 - √(53) and 7 + √(53)

What is the completing the square method?

Completing the square method involves writing the quadratic expression of the form a·x² + b·x + c as (x + d)²  + e, where d and e are constants.

Moving the constant to one side of the equation, we get;

x² - 14·x = 4

We complete the square on the left side of the equation by adding and subtracting the square of the half the coefficient of x term inside the parenthesis. Therefore, we add and subtract (-14/2)² = 49, as follows;

(x² - 14·x + 49) - 49 = 4

Therefore; (x - 7)² - 49 = 4

The -49 is moved to the right side of the equation to get;

(x - 7)² = 4 + 49 = 53

Taking the square root of both sides, we get;

x - 7 = ± √(53)

Therefore; x = 7 ± √(53)

The solution is; x = 7 + √(53) and 7 - √(53)

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