If 5+3+2=151012, 9+2+4=183662, 8+6+3=482466, 5+4+5= 202504 , then 7+2+5= ?
a.141035
b.143510
c.143542
d.143524

Answers

Answer 1
A) is the right answer!

Related Questions

Find the product of (x − 2i)^2.

Answers

I'll show you the steps that you can follow to get the answer....

*** First of all remember that  i = √-1

(x - 2i)²
(x - 2i)(x - 2i)
(x² - 2xi - 2xi + 4i²)           ----->   i² = (√-1)² = -1
(x² - 4xi - 4)

That is your final answer!

Hope this helps you :D

The product of (x-2i)²=x²-4+i4x

What is the process of multiplication of complex numbers?

The product or multiplication of two complex numbers is also a complex number. The formula for multiplying complex numbers is: (a + ib) (c + id) = (ac - bd) + i(ad + bc).

Given here  (x-2i)² =(x-2i) (x-2i)

                              =x²-4+i4x

Hence, the product is x²-4+i4x

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The Pyramid of Giza is one of the largest pyramid structures still standing in Egypt. It is a right pyramid with a square base, a base length of 230 m, and height of 150 m. The area of the base is __________ The volume is ________

Answers

Answer:- The area of base is 52900 square meters. The volume is 2654000 cubic meters.


Explanation:-

Base length of right pyramid (square) a =230m

Height of right pyramid = 150m

Area of base of right pyramid[tex]=a^2=(230)^2=52900\ m^2[/tex]

Volume of right pyramid with square base[tex]=\frac{1}{3}a^2h\\=\frac{1}{3}\times52900\times150=2645000\ m^3[/tex]

Thus, the area of base is 52900 square meters and the volume is 2654000 cubic meters.

The area of the base of the pyramid is 52900 m²

The volume of the square base pyramid of Giza is 2645000 m³

The pyramid is a square base pyramid. Therefore,

volume of a square base pyramid;v =  1 / 3 Bh

where

B = base area

h = height

h = 150 m

Therefore,

area of the base = l²

where

l = length of side

area of the base = 230² = 52900 m²

Volume = 1  / 3 × 52900 × 150

volume = 7935000 / 3

volume = 2645000 m³

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Tablets are on sale for 15% off the original price (t), which can be expressed with the function p(t) = 0.85t. Local taxes are an additional 8% of the discounted price (p), which can be expressed with the function c(p) = 1.08p. Using this information, which of the following represents the final price of a tablet with the discount and taxes applied based on its original price? (2 points) c[p(t)] = 0.918t c(p) + p(t) = 1.93t c(p) ⋅ p(t) = 0.918pt t[c(p)] = 1.93p

Answers

c [p(t)] = 1.08p
c (0.85t) = 1.08(0.85t) = 0.918t
∴ c[p(t)] = 0.918t

The final price of the tablet is c(t) = 0.918.

What is sale price?

A sale price is the discounted price at which goods or services are being sold.

According to the given question

Tablets are on sale for 15% off the original price(t), which can be expressed with the function:

p(t) = 0.85t

The additional taxes of 8% of the discounted price(p), which can be expressed as a function:

c(p) = 1.08p

Therefore,

The final price of a tablet with the discount and taxes applied based on its original price is given by

c(p(t)) = 1.08 ×p(t)

c(p(t)) = 1.08×(0.85t)

c(p(t)) = 0.918t

c(t) =0.918t

Hence, the final price of the tablet is c(t) = 0.918.

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Write the sum using summation notation


729 + 1000 + 1331 + 1728 + ... + n^3

Answers

[tex]\displaystyle \sum_{i=9}^n n^3[/tex]

What is the correct name for this circle?

Answers

circle C
hope this helped!
The circle takes name from its center. I'd say Circle C

Given: The coordinates of iscosceles trapezoid JKLM are J(-b, c), K(b,c), L(a,0), and M(-a,0).
Prove: The diagonals of an isosceles trapezoid are congruent.
As part of the proof, find the length of KM

A) a2+b2+c2
B) (-a+b)2+c2
C) (a+b)2+c2

Answers

The answer for this question is B. Let me know

Answer with explanation:

It is given that, coordinates of Isosceles trapezoid J K L M are J(-b, c), K(b,c), L(a,0), and M(-a,0).

To Prove: The diagonals of an isosceles trapezoid are congruent.

Proof:

  Distance formula , that is distance between two points in x y plane is given by

       [tex]=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}[/tex]

Where, [tex](x_{1},y_{1}),(x_{2},y_{2})}[/tex] are coordinates of two points in the plane.

Length of Diagonal J L

                  [tex]=\sqrt{(a+b)^2+(0-c)^2}\\\\=\sqrt{(a+b)^2+c^2}[/tex]

Length of Diagonal K M

           [tex]=\sqrt{(a+b)^2+(0-c)^2}\\\\=\sqrt{(a+b)^2+c^2}[/tex]

So, we can see that,

  J L = KM  [tex]=\sqrt{(a+b)^2+(c)^2}[/tex]

Hence,The diagonals of an isosceles trapezoid are congruent.

So ,

  [tex]KM=\sqrt{(a+b)^2+c^2}[/tex]

Option C

Find all values of $x$ such that $6= \dfrac{35}{x} -\dfrac{49}{x^2}$. If you find more than one value, then list your solutions in increasing order, separated by commas.

Answers

x=7/3 and x=7/2

if you want the step-by-step then you just try to isolate x and it is pretty self-explanatory from there on. Hope this helped! 

:P

Answer:

[tex]x=\frac{7}{3} , \frac{7}{2}[/tex]

Step-by-step explanation:

[tex]6= \frac{35}{x} - \frac{49}{x^2}[/tex]

Now we need to solve for x

To get 'x' alone we make the denominators same

LCD = x^2

WE multiply the whole equation by x^2

[tex]6x^2 = 35x - 49[/tex]

Now we the equation =0, move all the terms to left hand side

[tex]6x^2-35x + 49=0[/tex]

Now we apply quadratic formula to solve for x

a= 6, b= -35 , c= 49

[tex]x= \frac{-b+-\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x= \frac{-(-35)+-\sqrt{(-35)^2-4(6)(49)}}{2*6}[/tex]

[tex]x= \frac{35+-\sqrt{49}}{12}[/tex]

[tex]x= \frac{35+-7}{12}[/tex]

Now frame two equations , one with +  and another with -

[tex]x= \frac{35+7}{12}[/tex]                                  [tex]x= \frac{35-7}{12}[/tex]

[tex]x= \frac{42}{12}[/tex]                                       [tex]x= \frac{28}{12}[/tex]  

[tex]x= \frac{7}{2}[/tex]                                           [tex]x= \frac{7}{3}[/tex]  

So value of x= {7/3, 7/2}

How many sixteenth notes would be needed to have the same duration as 3 quarter notes? Represent this as a fraction

Answers

1 quarter note=2 eighth notes
1 eight note=2 sixteenth notes
so

1 quarter note=4 sixteenth note
so
times 3 both sides
3 quarter notes=12 sixteenth notes

What is the median of 36, 14, 21, 56, and 10?

Answers

The median is the middle number which is 21
The median is going to be the middle number in a sequence when the sequence is written from smallest value to latest value:

10, 14, 21, 36, 56

So, as the above person said, the median is 21 but it is still important to remember the aforementioned rule above.

Use ABC to find the value of sin A. See picture below. Thanks!

Answers

sin is equal 35 divided 37

Explain how you would use a number line to find the absolute value of –12.

Answers

The absolute value is 12. I don't know how you would use the number line to your advantage but that's because that's not how they taught me in school.
This is kind of hard to explain, but I'm going to try. Feel free to comment questions if what I'm going to say doesn't make sense.

Absolute Value
 # of spaces away from zero
∞ how far away a number is from zero

1). Draw a number line.
2). Label it from -12 to 0.
3). Count on the number line from -12 to 0 and see how many units to the right you have to go to reach zero. The answer is 12, so that is the absolute value.
 |-12| = 12

∠EFG and ∠GFH are a linear​ pair, m∠EFG=3n+19, and m∠GFH=55+33 What are m∠EFG and m∠​GFH?

Answers

a linear pair is a pair of angles that form a straight line and are therefore, equal to 180 degrees

3n + 19 + 55 + 33 = 180
3n + 107 = 180
3n = 180 - 107
3n = 73
n = 73/3 


so < EFG = 3n + 19 = 3(73/3) + 19 = 73 + 19 = 92
and < GFH = 55 + 33 = 88

can someone help me please

Answers

The correct answer is C) Graph A. We can find this remembering our rules about graphing lines such as parabolas. You could also use a graphing tool, such as Desmos, to input the equation and see the outcome. I would also recommend purchasing a graphing calculator (TI-84 Plus) which would let you put this equation in and show you the line.

Which point satisfies both f(x)=2^x and g(x)=3^x (0,1) (0,-1) (1,0) (-1,0)

Answers

The only solution for [tex]2^x=3^x[/tex] is [tex]x=0[/tex], so it's either [tex](0,1)[/tex] or [tex](0,-1)[/tex].
Both [tex]2^0[/tex] and [tex]3^0[/tex] are equal to 1, so the answer is [tex](0,1)[/tex].

note that 2^0 = 1  and 3^0 = 1

so  the point must be (0,1)

Which Graph correctly represents x+2y≤4?

Answers

It's graph B, remember you can use desmos

Answer with Step-by-step explanation:

We are given an inequality:

x+2y≤4

We have to determine its correct graph

In graph A and graph C (0,4) lies in shaded region but (0,4) does not satisfy the inequality

(since, 0+2×4=8 which is not less than or equal to 4)

Hence, A and C are not the graph of this inequality

In graph D (0,2) does not lie in shaded area but it satisfies the inequality

Hence, D is also not the graph of this inequality

Hence, correct graph of x+2y≤4 is:

Graph B

In the following triangle, find the values of the angles B and B', which are the best approximations to the solutions of this ambiguous case.

Answers

the answer is B because the bottom has to be supplementary to 180 degrees because their supplementary angles

Answer:

Option B. B = 70.05° B' = 109.95°

Step-by-step explanation:

By the sine rule in a given triangle

sin 45°/16.5 = sinB/22

1/(1.414×16.5) = sinB/22

sinB = 22/(1.414×16.5) = 0.94

[tex]B = sin^{-1}(0.94)[/tex]

B = 70.05°

Now we know B' = 180 - Supplementary angle of B'

and B = B' ( opposite angles of equal sides are equal)

B' = 180 - B = 180 - 70.05 = 109.95°

Therefore option B is the answer.

Five students visiting the student health center for a free dental examination during national dental hygiene month were asked how many months had passed since their last visit to a dentist. their responses were as follows. 5 18 12 24 28 assuming that these five students can be considered a random sample of all students participating in the free checkup program, construct a 95% confidence interval for the mean number of months elapsed since the last visit to a dentist for the population of students participating in the program. (give the answer to two decimal places.)

Answers

To find for the value of the confidence interval, let us first calculate for the values of x and s, the mean and standard deviation respectively.

x = (5 + 18 + 12 + 24 + 28) / 5

x = 17.4 months

 

s = sqrt{[(5 – 17.4)^2 + (18 – 17.4)^2 + (12 – 17.4)^2 + (24 – 17.4)^2 + (28 – 17.4)^2]/(5-1)}

s = 9.21

 

The formula for the confidence interval is given as:

Confidence Interval = x ± t s / sqrt(n)

Where t can be taken from standard distribution tables at 95% level at degrees of freedom = n – 1 = 4, t = 2.132. Therefore:

Confidence Interval = 17.4 ± 2.132 * 9.21 / sqrt(5)

Confidence Interval = 17.4 ± 8.78

Confidence Interval = 8.62 months, 26.18 months

Final answer:

To construct a 95% confidence interval for the mean number of months elapsed since the last visit to a dentist, use the sample mean and sample standard deviation. Calculate the confidence interval using the formula and given data.

Explanation:

In order to construct a confidence interval for the mean number of months elapsed since the last visit to a dentist for the population of students participating in the program, we can use the sample mean and sample standard deviation. The formula for constructing a confidence interval for the mean is:

Confidence Interval = sample mean ± (critical value) × (sample standard deviation / √sample size)

Using the given data, the sample mean is 17.4 months and the sample standard deviation is 9.18 months. With a confidence level of 95%, the critical value is 2.776. Plugging these values into the formula, we get:

Confidence Interval = 17.4 ± (2.776) × (9.18 / √5)

Calculating this, we find that the 95% confidence interval for the mean number of months elapsed since the last visit to a dentist is approximately 4.81 to 29.99 months.

On monday eliza read her book. on tuesday she read three times as long as she read on monday. on wednesday she read 20 minutes less than tuesday. on thursday she read for 20 minutes which was half as long as she read on wednesday. how many minutes did eliza read over the 4-day period

Answers

monday : x
tuesday : 3x
wednesday : 3x - 20 = 40
thursday: 20

3x - 20 = 40
3x = 40 + 20
3x = 60
x = 60/3
x = 20

monday : 20 minutes
tuesday : 3x....3(20) = 60 minutes
wednesday : 40 minutes
thursday: 20
for a total of : 140 minutes <===

bacterial colonies can triple in size every 4 days. if you start with 150 bacteria microorganisms, how large would the colony be after 16 days?

Answers

This is the concept of exponential growth, the size of the colony after 16 days will be calculated as follows;
Exponential growth will be given by:
f(t)=ae^(kt)
where:
a=initial number=150
k=constant of proportionality=3/4=0.75
t=time=16
thus;
f(16)=150e^(0.75*16)
=24,413,218.71 bacteria

Rationalize the denominator. write it in simplest terms.

1
- ------------
√18x

yes it is a negative

Answers

let's do the same here.

[tex]\bf -\cfrac{1}{\sqrt{18x}}\cdot \cfrac{\sqrt{18x}}{\sqrt{18x}}\implies -\cfrac{\sqrt{18x}}{\sqrt{(18x)^2}}\implies -\cfrac{\sqrt{18x}}{18x}\implies -\cfrac{\sqrt{9\cdot 2\cdot x}}{18x} \\\\\\ -\cfrac{\sqrt{3^2\cdot 2\cdot x}}{18x}\implies -\cfrac{3\sqrt{ 2\cdot x}}{18x}\implies -\cfrac{\sqrt{2x}}{6x}[/tex]

a bell tolls every 10 minutes. another bell tolls every 15 minutes. both bells toll at 6:00pm. they will toll together at what time

Answers

basically, we need to find the lowest common multiple of 10 and 15.

that multiply would be 30. That means that the bells will ring together in 30 minutes.
So 30 minutes from 6 p.m. is 6:30 p.m. <==

Both the bells will ring after 30 minutes at 6:30 pm.

What is the lowest common multiple?

The smallest common positive number that is a multiple of two or more numbers.

Given that, a bell tolls every 10 minutes. another bell tolls every 15 minutes. both bells toll at 6:00pm.

To find the time for which both will ring together, we will find LCM of 10and 15

10 = 5x2

15 = 5x3

LCM = 5x2x3 = 30

The LCM of 15 and 10 is 30

So, both will ring after 30 minutes.

Right now the time is 6:00 pm, so after 30 minutes it will be 6:30 pm

Hence, Both the bells will ring after 30 minutes at 6:30 pm.

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how much would $500 invested at 6% interest compounded annually be worth after 4 years

Answers

A = P(1 + r)^t
A = 500(1 + .06)^4
A = $631.24
Remember your formula for compound interest, then just plug the numbers in and calculate. The formula is A=P(1+r)^t where A is the new amount or in this case, your answer. P is the principle you invested. r is the interest rate divided by 100 so you will have a decimal. t is the time in years. This means your formula is A=500(1+.06)^4 Now get out your handy, dandy calculator and you got it!!

A cold front moved in last weekend. In 8 hours overnight, the temperature outside dropped from 14 degrees to -10. What was the average temperature change for each hour?

I need the answer as quick as I can and I put it at max points!

Answers

Alright, so we have 14 degrees and -10 degrees. The difference between 14 and 0 is 14, and the difference between 0 and -10 is 10. 14+10=24 for total change. For the average over 8 hours, we have 24/8=3 degrees

Answer:


Step-by-step explanation:

The difference between 14 and 0 is 14, and the difference between 0 and -10 is 10. 14+10=24 for total change. For the average over 8 hours, we have 24/8=3 degrees

The party store has a special on greetings cards. It charges $14 for 4 greeting cards and $1.50 for each additional card. Write an equation for the total cost of greeting cards in terms of the number of cards. Define your variables. What is the total cost of 9 greeting cards?

Answers

C=14 +1.5(x-4)

 c= total cost

x = number of cards

cost for 9 cards:

x=9

c=14+1.5(9-4)

14+1.5(5) = 21.50

 total cost = $21.50


Julio just bought a $267,900 house. He had a 20 year mortgage with a fixed rate of 5.875%. Julio's monthly payments are $1558.09. What percent of the purchase price was Julio's down payment?

Answers

First find the present value using the formula of the present value of an annuity ordinary.
The formula is
Pv=pmt [(1-(1+r/k)^(-kn))÷(r/k)]
Pv present value?
PMT monthly payment 1558.09
R interest rate 0.05875
K compounded monthly 12 because the payment is monthly
N time 20 years
Pv=1,558.09×((1−(1+0.05875
÷12)^(−12×20))÷(0.05875÷12))
=219,684.92

Subtract the amount of the present value from the purchase price of the house to get the amount of the down payment
267,900−219,684.92=48,215.08

So the percent of the purchase price was Julio's down payment is
48,215.08÷267,900
=0.17997×100=17.997% round your answer to get 18%

Answer: c

Step-by-step explanation:

(6.3 × 1011) ÷ (7 × 105)

Answers

First multiply within the parantheses
(6.3 * 1011)/(7 * 105)
6369.3/735
8.666 or 8.67

type the slope-intercept equation of the line that passes through the points (0,2) and (2,0) y={?]x+{ }

Answers

slope = (0-2)/(2 - 0) = -2/2 = -1
b = 2

equation
y = -x + 2

hope it helps

Perform the operation(s) and write the answer in simplest form.
( 1/2 + 1/3) / 15/4
A.) 3 1/8
B.) 53/90
C.) 2/9
D.) 8/75

Answers

First add the fractions in the parenthesis: 1/2+1/3.. In order to do this find the common denominator, which in this case is 6.  So 3/6+2/6=5/6.  Now you have 5/6/15/4.  Divide the fractions and then simplify to get 2/9.

Hope the explanation helped!

Mr. calloway is an algebra teacher. every class period he draws a piece of paper out of a hat without looking to determine the number of homework problems he will assign. each different color of paper represents a different number of homework problems. the hat contains 2 blue, 6 red, 10 yellow, and 7 purple pieces of paper.what is the probability that mr. calloway draws a purple piece of paper during the first class period and a blue piece of paper during the second class period if he replaces all pieces of paper before each drawing?

Answers

The probability of drawing a purple piece during the first class is 7/25 because 7 pieces of paper are purple out of a total of 25 pieces of paper

Since all pieces of paper are returned, the probability of drawing a blue piece during the second class is 2/25 since there are 2 blue pieces out of a total of 25 pieces of paper

The wording is meant to trick you here. If the purple paper from the morning was not replaced before drawing the probability of drawing a blue piece in the second class would increase. 

Always remember to reduce fractions where you can 

The probability that Mr. Calloway will draw a purple piece of paper during the first class period and a blue piece during the second class period with replacement is [tex]\frac{14}{25}[/tex].

The question involves calculating the probability of drawing a purple piece of paper during the first class period and a blue piece of paper during the second class period with replacement. To find this probability, we first calculate the probability of each event separately since the events are independent. Mr. Calloway's hat contains a total of 25 pieces of paper (2 blue, 6 red, 10 yellow, and 7 purple).

The probability of drawing a purple piece of paper in the first class period is the number of purple papers divided by the total number of papers:

P(purple) = Number of purple pieces / Total pieces = [tex]\frac{7}{25}[/tex]

Since the pieces are replaced, the probabilities in the second class period are the same as in the first. Thus, the probability of drawing a blue piece of paper in the second class is:

P(blue) = Number of blue pieces / Total pieces = [tex]\frac{2}{25}[/tex]

Because these events are independent, we multiply the probabilities of each event happening:

Total probability = P(purple)  times P(blue) = ([tex]\frac{7}{25}[/tex])  times ([tex]\frac{2}{25}[/tex]) = [tex]\frac{14}{25}[/tex].

Therefore, the probability that Mr. Calloway draws a purple piece of paper during the first class period and a blue piece of paper during the second class period with replacement is [tex]\frac{14}{25}[/tex].

The number of significant figures in 0.01500 is

Answers

four significant is an answer 
because if 0 is the extreme right of decimal place it is significant
and if 0 lies between two significant figure than it is significant like 1.020 is 4 sifnificant and 100 is 1 significant figure

The number of significant figures in 0.01500 is 4.

What are significant figures?

Significant figures (or significant digits) are the number of digits in a given value or a measurement, necessary to decide the accuracy and precision of measurement.

The given decimal number is 0.01500.

Certain rules help us determine the number of significant figures. These rules are as follows:

(1) All non-zero digits are significant.

(2) All zeros in between non-zero digits are significant.

(3) Zeros on the right of a decimal point and before (or to the left of) the first non-zero digit are not significant. They only represent the position of the decimal point.

(4) Zeros on the right of a decimal point are significant, provided there is no non-zero digit after them.

(5) Zeros on the right of the last non-zero digit after a decimal point are significant. So, final zeros or trailing zeros in the decimal part are significant.

(6) In a measurement value, zeros that occur on the right of the last non-zero digit are significant.

In the given decimal 0.01500, two non zero digits and two leading zeros are significant

So, number of significant figures are 4

Therefore, the number of significant figures in 0.01500 is 4.

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