I want to select between 5 different 2-bit inputs and output it. How many bits do I need to specify which input?

Answer:

Touch screen

Explanation:

A computer system is an electronic device that is meant to give processed output values to input values. The computer components are categorized into three parts, namely input devices, output devices and processing unit.

Input device component of a computer are used to give commands or input data values to the computer. Examples of input devices are keyboards, mouse, joystick, light pen and most recently, touchscreens.

Touch screen are input devices on the screens on computer systems like laptops and smartphones, that uses light sensors to input data when the screen is touched with the finger or a stylus.

Answer:

Program:

#include <stdio.h> // header file

int main() // main function

{

   printf("In C, lowercase letters are significant. main() is where program execution begins. Opening and closing braces enclose program statements in a routine. All program statements must be terminated by a semicolon."); // print statement which print the text which is said by the question to print.

return 0; // return statement

}

Output:

Explanation:

Answer:

- Different route paths, due to dynamic routing in WAN.

- Local area networks have one or very few paths to destination and does not require dynamic routing.

Explanation:

A wide area network is a network that covers a large geographical area. It goes beyond the private local area network, with more routing paths and network intermediate devices. The router is an essential tool for routing packets between devices. It requires a routing path, learnt statically or dynamically to work.

There are mainly two types of route paths, they are, static routes and dynamic routes.

The dynamic routes are used mainly in WAN. Sometimes, there can be multiple path to a destination, the router determines the best path to send the packets. It sends the sequenced packets through all available path and they arrive at the destination depending on the path used, the packets arrive in an out -of-order fashion in the destination and a rearranged.

Answer:

Signed: -4 -5 +6 -1

Unsigned: 12 13 6 9

Explanation:

We are given with binary number i.e. 1100110101101001. First of all we will break this binary number into sets of 4 starting from the right side of the binary number. First set will be 1001, second will be 0110, third wil be 1101, fourth will be 1100.

Basic concept of converting binary numbers into decimal numbers:

256 128 64 32 16 8  4  2  1  

0      1      1    0    1  0  0  1  1

Add the number written above each of the binary number if its 1 and ignore if its 0. Starting from the left side 0 represents 256 so, we will ignore it. 1 represents 128 so we will consider it and so on.

128+64+16+2+1 = 211

011010011 is the binary of 211.

For signed binary, if the last number of the set is 0 the, it is a postive number. For unsigned binary, if the last number of the set is negative then, it is a negative number.

For signed binary:

1100    1101    0110   1001

-4        -5      +6       -1

Note:

We are not adding these numbers because in the question it is specified to give 4 answers.

For unsigned binary:

1100    1101    0110   1001

12        13      6       9

Note:

We are not adding these numbers because in the question it is specified to give 4 answers.

11001101 (as unsigned binary) is 205 in decimal

11001101 (as signed binary) is -51 in decimal

01101001 (as unsigned binary) is 105 in decimal

01101001 (as signed binary) is still 105 in decimal.

a.  11001101

1 => Treating as unsigned binary

Since the number is unsigned, the usual direct conversion to decimal is sufficient. i.e

11001101 = 1 x [tex]2^{7}[/tex] + 1 x [tex]2^{6}[/tex] + 0 x [tex]2^{5}[/tex] + 0 x [tex]2^{4}[/tex] + 1 x [tex]2^{3}[/tex] + 1 x [tex]2^{2}[/tex] + 0 x [tex]2^{1}[/tex] + 1 x [tex]2^{0}[/tex]

11001101 = 128 + 64 + 0 + 0 + 8 + 4 + 0 + 1

11001101 = 205 (in decimal)

Therefore 11001101 (as unsigned binary) is 205 in decimal

2 => Treating as signed binary

Signed binary using 2's complements dictates that the most significant bit (leftmost bit) in a binary number represents the sign of the bit. If the most significant bit is 0, then the number is positive. If it is 1, the number is negative.

Since the most significant bit of the number (11001101) is 1, then the number is negative.

Therefore to convert it to its decimal counterpart;

i. flip all its bits by changing all 1s to 0s and all 0s to 1s as follows

=> 11001101 = 00110010

ii. add 1 to the result above as follows

=> 00110010 + 1 = 00110011

iii. now convert the result to the decimal representation as follows

00110011 = 0 x [tex]2^{7}[/tex] + 0 x [tex]2^{6}[/tex] + 1 x [tex]2^{5}[/tex] + 1 x [tex]2^{4}[/tex] + 0 x [tex]2^{3}[/tex] + 0 x [tex]2^{2}[/tex] + 1 x [tex]2^{1}[/tex] + 1 x [tex]2^{0}[/tex]

00110011 = 0 + 0 + 32 + 16 + 0 + 0 + 2 + 1

00110011 = 51 (in decimal)

Therefore, 11001101 (as signed binary) is -51 in decimal

b.  01101001

1 => Treating as unsigned binary

Since the number is unsigned, the usual direct conversion to decimal is sufficient. i.e

01101001 = 0 x [tex]2^{7}[/tex] + 1 x [tex]2^{6}[/tex] + 1 x [tex]2^{5}[/tex] + 0 x [tex]2^{4}[/tex] + 1 x [tex]2^{3}[/tex] + 0 x [tex]2^{2}[/tex] + 0 x [tex]2^{1}[/tex] + 1 x [tex]2^{0}[/tex]

01101001 = 0 + 64 + 32 + 0 + 8 + 0 + 0 + 1

01101001 = 105 (in decimal)

Therefore 01101001 (as unsigned binary) is 105 in decimal

2 => Treating as signed binary

Signed binary using 2's complements dictates that the most significant bit (leftmost bit) in a binary number represents the sign of the bit. If the most significant bit is 0, then the number is positive. If it is 1, the number is negative.

Since the most significant bit of the number (01101001) is 0, then the number is positive and the usual conversion to decimal will suffice. i.e

01101001 = 0 x [tex]2^{7}[/tex] + 1 x [tex]2^{6}[/tex] + 1 x [tex]2^{5}[/tex] + 0 x [tex]2^{4}[/tex] + 1 x [tex]2^{3}[/tex] + 0 x [tex]2^{2}[/tex] + 0 x [tex]2^{1}[/tex] + 1 x [tex]2^{0}[/tex]

01101001 = 0 + 64 + 32 + 0 + 8 + 0 + 0 + 1

01101001 = 105 (in decimal)

Therefore 01101001 (as signed binary) is still 105 in decimal.

Note: A positive binary number will have the same value (in decimal) whether it is treated as signed or unsigned.

Answer:

A. label, mnemonic, operand(s), comment.

Explanation:

Assembly language is a low level programming language. There are four parts of the assembly language syntax, they are, from left to right, label, mnemonic, operands, comments.

The label points to a specific location in the program, it is used to segment codes and ends with a colon. The mnemonic is also called an opcode, it is the operation carried out on the operands. The operands are the values in memory being resolved. A comment is a statement that describes a line of code, it is not executed by the assembler.

Answer:

Port 3389 is used for remote desktop access to graphical interfaces.

The syntax used to track ping traffic is " tcp.port eq 25 or icmp".

Explanation:

Wireshark is a network packet sniffer tool used to analysing and troubleshooting packet transmission in a network.

The ping command is used in a network to check or confirm connectivity between two devices in the network. It sends ICMP message echos to the specified IP address and receives it back if there is connection. To get the ping traffic in wireshark the command syntax " tcp.port eq 25 or icmp" is used.

The port 3389 is a TCP and UDP listening port for the Microsoft proprietary protocol called remote desktop protocol or connection used to remotely connect to the graphical interface of other system running the RDP server.

Answer:

collaboration diagram

Explanation:

Collaboration diagram -

It refers to the diagram , which showcase the link between the unified modeling language with the software object , is referred to as the collaboration diagram.

It is also called the communication diagram .

These diagram are very important for a company as it is the  pictorial representation.

Various software are used to make these diagrams.

Answer: - availability

Explanation: disconnecting a cable connection to the company server shuts you out from having access to files contained in that server until reconnection and probably authentication and login.

Answer: FALSE

Explanation:-N-tier application architecture is a system by which developers can make flexible and reusable applications. By separating an application into tiers developers can easily modifying or add particular layer, instead of working on already existing application.

N-tier architectures can be classified into three tiers known as

PRESENTATION TIER(main function is to receive and transfer data to the logic tier and in turn recieve information from the logic tierand transfer to the user).

LOGIC TIER( it does all the calculations and through logic process data accordingly).

DATA TIER( information are stored and retrieved to the logic tier for processing and transfer). Generation of information happens in the third tier(Data tier).

Answer:

Secure Sockets Layer (SSL)            

Explanation:

Answer:

Answer is explained below

Explanation:

The running time is measured in terms of complexity classes generally expressed in an upper bound notation called the big-Oh ( "O" ) notation. We need to find the upper bound to the running time of both the algorithms and then we may compare the worst case complexities, it is also important to note that the complexity analysis holds true (and valid) for large input sizes, so, for inputs with smaller sizes, an algorithm with higher complexity class may outperform the one with lower complexity class i.e, efficiency of an algorithm may vary in cases where input sizes are smaller & more efficient algorithm might be outperformed by the lesser efficient algorithms in those cases.

That's the reason why we consider inputs of larger sizes when comparing the complexity classes of the respective algorithms under consideration.

Now coming to our question for algorithm A, we have,

let F(n) = 1/4x² + 1300

So, we can tell the upper bound to the function O(F(x)) = g(x) = x2

Also for algorithm B, we have,

let F(x) = 112x - 8

So, we can tell the upper bound to the function O(F(x)) = g(x) = x

Clearly, algorithmic complexity of algorithm A > algorithmic complexity of algorithm B

Hence we can say that for sufficiently large inputs , algorithm B will be a better choice.

Now to find the exact location of the graph in which algorithmic complexity for algorithm B becomes lesser than

algorithm A.

We need to find the intersection point of the given two equations by solving them:

We have the 2 equations as follows:

y = F(x) = 1/4x² + 1300 __(1)

y = F(X) = 112x - 8 __(2)

Let's put the value of from (2) in (1)

=> 112x - 8 = 1/4x² + 1300

=> 112x - 0.25x² = 1308

=> 0.25x² - 112x + 1308 = 0

Solving, we have

=> x = (112 ± 106) / 0.5

=> x = 436, 12

We can obtain the value for y by putting x in any of the equation:

At x=12 , y= 1336

At x = 436 , y = 48824

So we have two intersections at point (12,1336) & (436, 48824)

So before first intersection, the

Function F(x) = 112x - 8 takes lower value before x=12

& F(x) = 1/4x² + 1300 takes lower value between (12, 436)

& F(x) = 112x - 8 again takes lower value after (436,∞)

Hence,

We should choose Algorithm B for input sizes lesser than 12

& Algorithm A for input sizes between (12,436)

& Algorithm B for input sizes greater than (436,∞)

To determine at which input size one would prefer Algorithm A over B, their running times must be set equal and the resulting quadratic equation solved for 'n'. Algorithm A is quadratic (O(n^2)), while Algorithm B is linear (O(n)), indicating Algorithm B is better for large inputs. The exact crossover point is found by solving the quadratic equation formed by equating the two running times.

The question asks at what input size one would prefer Algorithm A ((1/4)n2 + 1300) over Algorithm B (112n
- 8) or vice versa, assuming all other factors equal. When analyzing the running time of algorithms, we focus on the highest-order terms, also known as Big-O notation. The running time of Algorithm A, in Big-O notation, is O(n2), while the running time for Algorithm B is O(n). Therefore, Algorithm B is more efficient for large input sizes due to its linear time complexity compared to Algorithm A's quadratic time complexity.

To determine the exact point where one algorithm becomes preferable over the other, we have to set their running times equal to each other and solve for n:

After solving the quadratic equation, we will get the values of n at which the running time of both algorithms is the same. For values lower than this n, Algorithm A would be preferred, and for values higher, Algorithm B would be more efficient.

To determine at which input size one would prefer Algorithm A over B, their running times must be set equal and the resulting quadratic equation solved for 'n'. Algorithm A is quadratic (O(n^2)), while Algorithm B is linear (O(n)), indicating Algorithm B is better for large inputs. The exact crossover point is found by solving the quadratic equation formed by equating the two running times.

The question asks at what input size one would prefer Algorithm A ((1/4)n2 + 1300) over Algorithm B (112n
- 8) or vice versa, assuming all other factors equal. When analyzing the running time of algorithms, we focus on the highest-order terms, also known as Big-O notation. The running time of Algorithm A, in Big-O notation, is O(n2), while the running time for Algorithm B is O(n). Therefore, Algorithm B is more efficient for large input sizes due to its linear time complexity compared to Algorithm A's quadratic time complexity.

To determine the exact point where one algorithm becomes preferable over the other, we have to set their running times equal to each other and solve for n:

After solving the quadratic equation, we will get the values of n at which the running time of both algorithms is the same. For values lower than this n, Algorithm A would be preferred, and for values higher, Algorithm B would be more efficient.

To determine at which input size one would prefer Algorithm A over B, their running times must be set equal and the resulting quadratic equation solved for 'n'. Algorithm A is quadratic (O(n^2)), while Algorithm B is linear (O(n)), indicating Algorithm B is better for large inputs. The exact crossover point is found by solving the quadratic equation formed by equating the two running times.

The question asks at what input size one would prefer Algorithm A ((1/4)n2 + 1300) over Algorithm B (112n
- 8) or vice versa, assuming all other factors equal. When analyzing the running time of algorithms, we focus on the highest-order terms, also known as Big-O notation. The running time of Algorithm A, in Big-O notation, is O(n2), while the running time for Algorithm B is O(n). Therefore, Algorithm B is more efficient for large input sizes due to its linear time complexity compared to Algorithm A's quadratic time complexity.

To determine the exact point where one algorithm becomes preferable over the other, we have to set their running times equal to each other and solve for n:

After solving the quadratic equation, we will get the values of n at which the running time of both algorithms is the same. For values lower than this n, Algorithm A would be preferred, and for values higher, Algorithm B would be more efficient.

Answer:

There are 7 layers in linux.

Explanation:

As networking is difficult and complex.

Imagine if every application had to know how to communicate on every step that would be more than just complex. So, rather than reinvent something which will help it to communicate let’s just make something that will automatically controls the communication and for that protocols came in to live.

As for the linux operating system, it is not exceptional from other operating systems.

There are 7 layers on network protocol stack use to communicate with other network protocol stack.

1. Application layer

2. System call interface

3. Protocol agnostic interface

4. Network protocol

5. Device agnostic interface

6. Device drivers

7. Physical hardware

All the layers vary in their functionality.

One more important thing to remember is that the network protocol stack layers is not one way its 2 way communication. First, when a client request to a network and second, when the request is full filled.

The top most layer is a part of user space, the next five layers comes in the kernel space and the final layer is the physical layer.

Application layer:

When a client or user request to  a network the request initially comes to this layer.

On this layer we use tcp/ip protocol.

System call interface(SCI):

When application layer make a call to the kernel this layer handles that call. And take the request to the next layer.

Protocol agnostic interface:

This layer has two functions “talking” or “listening”. There is a thing called sockets which perform these functions and each socket has an id which is used specifically for an application.

Network protocol:

This layer is used for how the data is sent or received.

Device agnostic interface:

It is used to connect data from/to kernel user space and the network device drivers which allows the data to prepare itself for transmission over the medium from the network device.

Physical hardware :

This layer is responsible for the data packets transmission and received from the network medium being used whether cable or wireless.

Answer:

The correct answer to the following question will be "KVM".

Explanation:

Therefore, if a customer requests to use a single set of devices (input) to control multiple computers then we must have them as a KVM.

Answer:

c. Surveillance-specific design.

Explanation:

Surveillance-specific design is a kind of design done by a data center designer that focuses on all factors that need to be considered before siting a surveillance device.

Answer:

C. . Surveillance-specific design

Explanation:

Designing and managing the operations of an effective surveillance system rely on two key principles:

Clear prioritization: What are the most critical data and analyses needed for the epidemiological zones with the highest epidemic potential? How can financial and technical resources be deployed most efficiently?

Flexibility: Do you have the ability to adjust where and when data are collected and analysed based on new information about the epidemic? Incorporating flexibility into your national surveillance plan design will help the programme be responsive and stay ahead of the epidemic.

Answer:

The required code is given below with appropriate comments for better understanding

Explanation:

public class Population

{

  public static void main(String[] args)

  {

      int currentPopulation=312032486;

      int numSecInyear=24*60*60*365;//for one day 24 hours,60 min,60 sec

      System.out.println("current population:"+currentPopulation);

      int numBirths=numSecInyear/7;

      int numDeaths=numSecInyear/13;

      int numImmigrant=numSecInyear/45;

      //print the result using for loop

      for(int i=1;i<=5;i++){

          currentPopulation=currentPopulation+numBirths-numDeaths+numImmigrant;//add up births and immigrants, remove deaths

          System.out.println("Population After year-"+i+":"+currentPopulation);

      }

  }

}

Sure! Here's a Python program to calculate and display the population for each of the next five years based on the provided assumptions:

#constants

BIRTH_RATE = 1 / 7

DEATH_RATE = 1 / 13

IMMIGRANT_RATE = 1 / 45

SECONDS_PER_YEAR = 365 * 24 * 60 * 60

# Initial population

population = 312032486

# Calculate population for each of the next five years

for year in range(1, 6):

   # Calculate the change in population for one year

   births = SECONDS_PER_YEAR // 7

   deaths = SECONDS_PER_YEAR // 13

   immigrants = SECONDS_PER_YEAR // 45

   population_change = births - deaths + immigrants

   # Update the population

   population += population_change

   # Display the population for the current year

   print(f"Population after {year} year(s): {population}")

This program first defines constants for birth rate, death rate, immigrant rate, and the number of seconds in a year. Then, it initializes the population variable with the current population. It calculates the population change for each of the next five years based on the provided rates, updates the population accordingly, and prints the population for each year.

Answer:

Explanation:

Yes we could find microprocessors almost everything even in ourself because this technology revolution is stronger day to day, and smart thing is the future, there are smartphones, watch, even houses, nowadays there are houses and hotels with smart technology even in the curtains, with a voice command we can program activities like wash or clean, and all these products have microprocessors.

Final answer:

The effective CPI, MIPS rate, and execution time for each machine are calculated. Both machines have similar performance with minor variations.

Explanation:

(a) Effective CPI:

For Machine A:

Effective CPI = (Cycles per Instruction * Instruction Count) / 106

Effective CPI = ((1*8) + (3*4) + (4*2) + (3*4)) / 106

Effective CPI = 0.000058

For Machine B:

Effective CPI = ((1*10) + (2*8) + (4*2) + (3*4)) / 106

Effective CPI = 0.000062

MIPS rate:

MIPS = Clock rate (Hz) / (Cycles per Instruction * 106)

MIPS for Machine A = 200 MHz / (0.000058 * 106)

MIPS for Machine A = 3.4482

MIPS for Machine B = 200 MHz / (0.000062 * 106)

MIPS for Machine B = 3.2258

Execution time:

Execution time = (Instruction Count * Cycles per Instruction) / Clock rate

Execution time for Machine A = (18 * 106) / (200 * 106)

Execution time for Machine A = 0.09 seconds

Execution time for Machine B = (24 * 106) / (200 * 106)

Execution time for Machine B = 0.12 seconds

(b) Comment: Machine A has a slightly lower effective CPI and a slightly higher MIPS rate than Machine B. However, Machine B has a slightly longer execution time compared to Machine A. Overall, both machines have similar performance with minor variations.

Answer: all of the above

Explanation:

Answer:

C. Post-incident activity.

Explanation:

An incident is a event of intrusion or attack or violation of an attempt of an attack. An incident response is an opposing response to an attack or violation.

An incident response life cycle are stages followed to mitigate a current attack or violation. The stages of the incident response life cycle are, preparation, detection and analysis, containing and eradicating and recovery, and post incident activity.

Answer:

c. decimal, encoded

Explanation:

Decimal: in this type of real number constant, it consists of not more than 63 digits and either includes a decimal point or not within the range of binary integers e.g 37.5

Encoded: in this type of real number constant, it is used to put number, letter into a specialized format for efficient transmission or for storage e.g code used for text by most computers is (ASCII).

Explanation:

The "Room to think" defined by the author can mean the proposal that each individual must obtain knowledge on a certain subject through research and self-study, inspiring the reading of the book.

Therefore, it is considered that the space to think is important, as it motivates the individual improvement to obtain more learning and knowledge on a subject, according to their own analyzes and studies.

The author means providing an environment for critical reflection when he says 'Room to think.'

The author, Andy Kirk, in his book Data Visualisation: A Handbook for Data Driven Design refers to 'Room to think' as the allowance of space and time to process information and ideas critically.

This concept means providing an environment where one can reflect deeply on the data, consider different perspectives, and reach meaningful conclusions. According to researchers, allowing time to think is an important part of learning because it enables higher-order thinking skills like critical and analytical reasoning.

This is particularly crucial in our current era of rapid technological change, as noted by Lee (2020), who emphasizes the need for critical thinking.

Answer:

Here is the C++ program

#include <iostream>  

using namespace std;  

int main(){

 double tonne = 2205;  

 double container_capacity;      

  cout << "Enter amount of wheat in pounds that a contained can hold: ";

  cin >> container_capacity;    

  cout << "Number of containers needed to store one metric ton of wheat: " << tonne / container_capacity ; }        

Explanation:

                      tonne / container_capacity = 2205/500 = 4.41

To answer the question, a simple program can be outlined in pseudo-code that takes the capacity of a container in pounds and calculates how many such containers are needed to hold one metric ton of wheat, which equals approximately 2,205 pounds.

The question requires creating a program to calculate the number of containers needed to store one metric ton of wheat, given the capacity of a container in pounds. A metric ton is approximately 2,205 pounds.

Example Program

For simplicity, we'll outline a program in a pseudo-code format:

To implement this code, you would need to handle division and possibly rounding up, as you cannot have a fraction of a container.

Answer:

intNum = int(input("Enter an Integer "))

for i in range(1,intNum):

   print(i)

Explanation:

Firstly and integer variable intNum is declared. Using Python's input function, we prompt the user to enter a value and assign it to intNum

Then we use the range function to iterate from the integer 1 up to but not including intNum and print out the values.

see sample code and output attached

The code for printing the one number per line is,

#Prompt the user to enter the input.

num_str = input ("Input an int: ")

#Run the loop from 1 to (num_str - 1).

for k in range(1, num_str):

#Display the value of k.

 print k

Learn More:https://brainly.com/question/17172273

Answer:

Assembler

Explanation:

Assembler is a type of utility program that is used to change the assembly language to machine code. it utilized the commands from assembly code to change them to binary code.

it used to change 2 types of symbols like assembler symbol and programmer symbols.

it makes the work easily by converting the language code into a readable form to the operating system.

The utility program which reads an assembly language source file and produces an object file is; Choice C: Assembler

Assemblers are share quite some similarities to compilers in that they produce executable code.

However, An assembler is a utility program which converts assembly language into machine code. This is done by taking the basic commands and operations from assembly code and converts them into binary code that can be recognized by a specific type of processor.

Read more on Assemblers;

https://brainly.in/question/1586603

The Python script calculates and displays the total bill for a customer's vehicle rental based on their classification code, rental duration, and odometer readings. The program considers specific pricing rules for each classification.

Here's a Python script that computes and displays the amount charged for a customer's vehicle rental based on the provided information:

python

def calculate_rental_cost(classification, days_rented, start_odometer, end_odometer):

   # Constants for mileage charges

   B_MILEAGE_CHARGE = 0.25

   D_MILEAGE_CHARGE = 0.25

   W_BASE_CHARGE = 350.00

   W_DAILY_CHARGE = 70.00

   # Convert classification code to uppercase

   classification = classification.upper()

   # Calculate base charge

   if classification == 'B':

       base_charge = 40.00 * days_rented

       mileage_charge = B_MILEAGE_CHARGE * (end_odometer - start_odometer)

   elif classification == 'D':

       base_charge = 60.00 * days_rented

       average_miles_per_day = (end_odometer - start_odometer) / days_rented

       mileage_charge = 0.00 if average_miles_per_day <= 100 else D_MILEAGE_CHARGE * (end_odometer - start_odometer - 100 * days_rented)

   elif classification == 'W':

       weeks_rented = days_rented // 7

       days_over_weeks = days_rented % 7

       base_charge = W_BASE_CHARGE * weeks_rented + W_DAILY_CHARGE * days_over_weeks

       mileage_charge = 0.00  # Unlimited miles for weekly rental

   # Calculate total bill

   total_bill = base_charge + mileage_charge

   # Display the total bill with 2 decimal places

   print(f"Total bill for the customer: ${total_bill:.2f}")

# Get input from the user

classification_code = input("Enter customer's classification code (B, D, or W): ")

days_rented = int(input("Enter the number of days the vehicle was rented: "))

start_odometer_reading = int(input("Enter the vehicle's odometer reading at the start: "))

end_odometer_reading = int(input("Enter the vehicle's odometer reading at the end: "))

# Calculate and display the total bill

calculate_rental_cost(classification_code, days_rented, start_odometer_reading, end_odometer_reading)

This script prompts the user for customer information and calculates the total bill based on the specified rules. It then displays the total bill with 2 decimal places.

Answer:

David can apply filter to the data in order to show only records that meet the criteria.

Explanation:

Answer: attached below

Explanation:

Final answer:

The MinStack class implements a stack that enables O(1) push, pop, and findMin operations by storing the minimum element alongside each node's value.

Explanation:

To support stack push, pop operations, and a findMin operation all in O(1) worst-case time, we can use a data structure design that keeps track of the current minimum element each time an element is added. This can be achieved by having each stack node not only contain the value of the element but also the minimum value at the time of its insertion into the stack. Below is a Java implementation of the proposed data structure:

/*
* Implements a stack with push, pop, and findMin operations running in O(1) time.
* Each stack node stores an element and the minimum value when this element was inserted.
*/
public class MinStack {
   private static class StackNode {
       int value;
       int min;
       StackNode next;

       public StackNode(int value, int min) {
           this.value = value;
           this.min = min;
           this.next = null;
       }
   }
   private StackNode top;
   public MinStack() {
       top = null;
   }
   public void push(int element) {
       if (top == null) {
           top = new StackNode(element, element);
       } else {
           top = new StackNode(element, Math.min(element, top.min));
           top.next = oldTop;
       }
   }
   public int pop() {
       if (top == null) throw new IllegalStateException("Stack is empty.");
       int element = top.value;
       top = top.next;
       return element;
   }
   public int findMin() {
       if (top == null) throw new IllegalStateException("Stack is empty.");
       return top.min;
   }
}

Answer:

False

Explanation:

Whenever a class implements an interface, it has to define all the functions which are declared in the interface because in the interfaces, methods are only declared and not defined, so, if a method is left undefined, it leads to compilation error, that is why, all methods of an interface has to be defined by the class which is implemented that method.

A class that implements an interface may only implement a few of that interface's method declarations: False.

A class can be defined as a user-defined blueprint (prototype) or template that is typically used by programmers to create objects and define the data types, categories, and methods that should be associated with these objects.

In object-oriented programming (OOP) language, a class that implements an interface would implement all of that interface's method declarations.

In conclusion, an object class represents the superclass of every other classes when an object-oriented programming (OOP) language such as Java is used.

Read more on class here: brainly.com/question/20264183

Answer:

The solution code is written in Python:

Explanation:

Presume that there is existence of Rectangle class as given in the question, Carpet class is written. The Carpet constructor is defined that take Rectangle object, rect, and cost as parameter (Line 2). To create data member of Carpet class, keyword "self" is used to precede with the name of the data members, size and costPerSqFoot (Line 3-4). The data members are initialized with the parameter rect and cost, respectively.

Next, cost method is defined (Line6 - 8). Within the cost method, the area method of Rectangle object is invoked by expression, self.size.area() and this will return the area value and multiplied with the costPerSqFoot to get the carpet cost and return it as output (Line 8).

Answer:

Today technology is increased much and fast-growing industry. What we purchased or opt, computer architect is outdated within the day

Explanation:

If we purchase any computer and opt for a computer architect. Such as processor or core technology still will be outdated, moreover, nowadays operating system depends on processor speed. If end-user he or her as to keep in mind that hardware investment such a period of 1 year only. Once a one-year end-user has to opt for new technology otherwise exist software and application are outdated.