I NEED HELP ASAP!!! THIS IS A 30 POINT QUESTION!!!
Which statement best describes the steps leading up to protein synthesis?
( 1 )The translation of DNA to RNA occurs in the cytoplasm; then, the transcription of RNA occurs in the nucleus.
( 2 )The transcription of DNA to RNA occurs in the cytoplasm; then, the translation of RNA occurs in the nucleus.
( 3 )The translation of DNA to RNA occurs in the nucleus; then, the transcription of RNA occurs in the cytoplasm.
( 4 ) The transcription of DNA to RNA occurs in the nucleus; then, the translation of RNA occurs in the cytoplasm.

The question asks for the product structure of a reaction to be drawn using a utility. Somewhat, it isn't possible to provide a drawn response without the reaction details and the specific utility. However, in general, recognizing the reactants, the type of reaction, and consequently sketching the product guidance was given.

The current question pertains to a chemical reaction product and the drawing of its structure using a specific utility. Unfortunately, without an image of the reaction and the platform's drawing utility unattainable here, an explicit 'drawn' response isn't feasible. However, the request to not specify stereochemistry suggests that your interest is mainly in the skeletal structure.

Generally, in organic chemistry, you'd discern the reactants, identify the type of reaction (such as addition, substitution, or elimination), and consequently draw the product by connecting atoms according to the reaction rules. The stereochemistry, which refers to the three-dimensional arrangement of the atoms, isn't a concern in this case.

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Answer: The theories are such that if any chemical produce H+ ion then it is an acid and if the chemical produces OH- ion then it's a base.

Explanation:

sorry I am not that much knowledgeable like all of you

Answer:

[tex]\boxed{\text{A. } m = 2, n = 3; \text{B. } m = 2, n = 4; \text{C. } m = 2, n = 5; \text{D. } m = 2, n = 6}[/tex]

Explanation:

The Balmer equation is

[tex]\lambda = B\left(\dfrac{n^{2}}{n^{2} -m^{2}}\right)[/tex]

where B = 364.5 nm and m = 2

Thus, the Balmer equation reduces to

[tex]\lambda = 364.5\left(\dfrac{n^{2}}{n^{2} - 4}\right)[/tex]

We will be doing four separate calculations for n, so it will be convenient to solve the equation for n.

[tex]\lambda (n^{2} -4) = 364.5n^{2}\\\\\lambda n^{2} -4\lambda = 364.5n^{2}\\\\\lambda n^{2}- 364.5n^{2} = 4\lambda \\\\ n^{2}(\lambda - 364.5) = 4\lambda \\\\ n^{2}= \dfrac{4\lambda}{\lambda - 364.5}\\\\ n= \sqrt{\dfrac{4\lambda}{\lambda - 364.5}}[/tex]

A. λ = 656.5 nm

[tex]n= \sqrt{\dfrac{4 \times 656.5}{656.5 - 364.5}} = \sqrt{\dfrac{2626}{292}} =\sqrt{8.993} = 2.999 \approx \boxed{\mathbf{3}}[/tex]

B. λ = 486.3 nm

[tex]n= \sqrt{\dfrac{4 \times 486.3}{486.3 - 364.5}} = \sqrt{\dfrac{1945}{121.8}} =\sqrt{15.97} = 3.996 \approx \boxed{\mathbf{4}}[/tex]

C. λ = 434.2 nm

[tex]n= \sqrt{\dfrac{4 \times 434.2}{434.2 - 364.5}} = \sqrt{\dfrac{1737}{69.7}} =\sqrt{24.9} = 4.99 \approx \boxed{\mathbf{5}}[/tex]

D. λ = 410.3 nm

[tex]n= \sqrt{\dfrac{4 \times 410.3}{410.3 - 364.5}} = \sqrt{\dfrac{1641}{45.8}} =\sqrt{35.8} = 5.99 \approx \boxed{\mathbf{6}}[/tex]

These are two questions and two answers.

Answers:

Explanation:

1) Balanced chemical equation (given):

2) Part A: How many moles of methane are produced when 59.6 moles of carbon dioxide gas react with excess hydrogen gas?

a) Mole ratios:

b) Proportion:

         ⇒ x = 59.6 mol CH₄ ← answer

3) Part B How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 42.1 moles of water vapor?

a) Mole ratios:

b) Proportion:

         ⇒ x = 42.1 × 4 / 2 moles CH₄ = 84.2 mol H₂ (g) ← answer

Answer: since it has a very reactive sulfhydryl group at its side chain. This puts cysteine in special position that cannot be replaced or substituted by any other amino acid. Because disulfide bridges formed by cysteine residues are permanent component of protein primary structure.

Explanation:

hydrogen is the most

Hydrogen is the most abundant element in the universe, making up about 90% of atoms. Helium is the second most abundant. These two elements dwarf the prevalence of all other elements combined.

The most abundant chemical element in the universe is hydrogen. Accounting for approximately 90% of atoms, hydrogen's prevalence surpasses all other elements. This elemental dominance extends to the composition of stars, including our sun, where hydrogen serves as a primary fuel for stellar processes. Following hydrogen, helium constitutes most of the remaining 10%, and all other elements appear in far lesser quantities. Hydrogen plays a significant role on Earth as well, being a part of countless compounds such as water, which is the most widespread compound of hydrogen on our planet.

Answer:

40.73 L.

Explanation:

where, P is the pressure of the gas in atm (P = 121.59 kPa/101.325 = 1.2 atm).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = 2.0 mol).

R  is the general gas constant (R = 0.082 L.atm/mol.K),

T is the temperature of the gas in K (T = 25°C + 273 = 298 K).

∴ V = nRT/P = (2.0 mol)(0.082 L.atm/mol.K)(298 K)/(1.2 atm) = 40.73 L.

Answer:I believe your answer would be option B) dilute. Hope this helps.

Explanation:

The correct answer is B) Dilute

Explanation:

In a solution, the proportions of the solute vs the solvent determine the type of solution that includes dilute/concentrated or unsaturated, saturated and supersaturated. In the case of a dilute solution, this occurs if there is a small amount of the solute in comparison to the amount of solvent, which makes it possible to add more solute as this can be dissolved. This type of solution applies to the case presented because one gram of salt (solute or substance dissolved) is a small quantity of solute in comparison to the amount of solvent (the substance that dissolves) that in this case is 100 liters of water. Thus, in this case, there is a dilute solution.

Answer:

0.60 L.

Explanation:

How many moles of [tex]\rm H_2SO_4[/tex]?

[tex]n(\mathrm{H_2SO_4}) = c\cdot V = 4.0\times 0.30 = \rm 1.2\; mol[/tex].

How many moles of [tex]\rm NaOH[/tex] will react with all that 1.2 moles of [tex]\rm H_2SO_4[/tex]?

Balance the equation:

[tex]\rm H_2SO_4 + 2\; NaOH \to Na_2SO_4 + 2\;H_2O[/tex].

The coefficient in front of [tex]\rm H_2SO_4[/tex] is 1. The coefficient in front of [tex]\rm NaOH[/tex] is 2. Hence the ratio:

[tex]\displaystyle \frac{n(\mathrm{NaOH})}{n(\mathrm{H_2SO_4})} = \frac{2}{1} = 2[/tex].

Therefore

[tex]\displaystyle n(\mathrm{NaOH}) = \frac{n(\mathrm{NaOH})}{n(\mathrm{H_2SO_4})} \cdot n(\mathrm{H_2SO_4}) = 2\times 1.2 = \rm 2.4\;mol[/tex].

What will be the volume of the [tex]\rm NaOH[/tex] solution?

[tex]\displaystyle V(\mathrm{NaOH}) = \frac{n}{c} = \frac{2.4}{4.0} = \rm 0.60\;L[/tex].

Answer:

Lithium

Explanation:

An ionic bond requires one metal and one nonmetal. Out of all the choices given, Lithium is the only one that is a metal.

Answer:

0.1589 mol ≅ 0.16 mol.

Explanation:

no. of moles (n) = mass/molar mass

mass of Al(OH)₃ = 12.4 g & molar mass of Al(OH)₃ = 78.01 g/mol.

∴ n = mass/molar mass = (12.4 g)/(78.01 g/mol) = 0.1589 mol ≅ 0.16 mol.

Answer:

0.47dm³

Explanation

Given parameters :

Molarity of NaCl = 6.67M

Number of moles = 3.12mol

Volume of NaCl =?

Volume of NaCl = number of moles/Molarity

Volume of NaCl = 3.12mol/6.67M

Volume of NaCl = 0.47dm³

Answer:

0.468

Explanation: got it right on edge

Hi there,

Your answer is given in the image attached above

Answer:

Option B. 20 oC

Explanation:

Thinking process:

The initial reaction takes place at: 0.01840 M/s at 25 oC.

However, the rate must be reduced to 0.0046 M/s.

It is most likely that a temperature of 20 °C is used her. This is because it offers sufficient kinetic energy to effect the reaction rate of the reaction substances.

Answer:

PATHOGEN.

Explanation:

In biology, pathogen refers to any organism or particle that is capable of causing infectious diseases. Thus, all the microbes that cause diseases such as bacteria, virus, fungi, viroid,  etc are collectively known as pathogen. The entrance of pathogen into the human body usually stimulate the immune system. The immune system functions by recognizing pathogens and by capturing and destroying them.

Answer:

Bromine.

Explanation:

That is bromine which is a dark red vaporous liquid with a bad smell. There are only 2 elements which are liquid at room temperature, bromine and mercury.

Cholesterol is an example of a lipid.

Cholesterol is an example of a(n) lipid. Hence, option C is correct.

A lipid is any of various organic compounds that are insoluble in water.

Cholesterol is one of several types of fats (lipids) that play an important role in your body.

Cholesterol is a waxy substance found in all cells of the body.

The body needs it to make hormones, Vitamin D, and substances that aid in digestion.

The liver makes all the cholesterol needed for these functions.

Hence, option C is correct.

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Answer:

1.5 mol.

Explanation:

Using cross multiplication:

1.0 mole of H₂ contains → 6.022 x 10²³ molecules.

??? mole of H₂ contains → 9.03 x 10²³ molecules.

∴ The no. of moles of H₂ contains (9.03 x 10²³ molecules) = (1.0 mol)(9.03 x 10²³ atoms)/(6.022 x 10²³ atoms) = 1.5 mol.

To find the total number of moles of hydrogen gas in 9.03 × 10²³ molecules, you divide the number of molecules by Avogadro's number (6.022 × 10²³ molecules/mole), resulting in approximately 1.5 moles of hydrogen gas.

To calculate the total number of moles of hydrogen gas (H₂) from the given number of molecules, we use Avogadro's number, which is 6.022 × 10²³ molecules per mole. The number of moles (n) is given by the formula:

n = {Number of molecules} ÷ {Avogadro's number}

Substituting our values, we get:

n = (9.03× 10²³ molecules ÷ 6.022 × 10²³ molecules/mole) ≈ 1.5 moles

Therefore, there are approximately 1.5 moles of hydrogen gas contained in 9.03 × 10²³ molecules of hydrogen gas.

Answer:

f

Explanation:

pressure

The degree of certainty is high.

Answer:

The correct answer is "high".

Explanation:

Taphonomy is the science that studies how organic matter decays and becomes fossilized. Forensic taphonomy is used to estimate the characteristics of a person's death, with tests with levels of certainty depending on multiple factors. If a sample has a short PMI (Postmortem Interval), warm and humid conditions, the degree of certainty is probably high because the conditions are ideal to preserve an organic sample.

Final answer:

The greatest amount of ammonium carbonate is produced when reactants NH3, CO2, and H2O are used in the mole ratio of 2:1:1, ensuring an excess of water.

Explanation:

To determine the reactant quantities that would result in the greatest amount of ammonium carbonate being formed, we must look at the stoichiometry of the balanced chemical equation provided:

2NH3(g) + CO2(g) + H2O(l) → (NH4)2CO3

According to this equation, therefore, the greatest amount of ammonium carbonate will be produced when reactants are supplied in the mole ratio of 2:1:1 for NH3:CO2:H2O, respectively. Choosing reactant quantities that provide ammonia and carbon dioxide in at least this ratio, while ensuring an excess of water, would maximize production of ammonium carbonate.

Answer:

[tex]\boxed{\rm \text{[ClO$_{2}^{-}$] increases}}[/tex]

Explanation:

At the beginning, you have two reactions happening:

[tex]\rm HCl + H$_{2}$O$ $\, \longrightarrow \,$ H$_{3}$O$^{+}$ + Cl$^{-}$\\\rm HClO$_{2}$ + H$_{2}$O$ $\, \rightleftharpoons \,$ H$_{3}$O$^{+}$ + ClO$_{2}^{-}$[/tex]

As you add KOH(aq), it does two things:

A) The HCl is completely ionized. The Cl⁻ does not react, but it is diluted when the volume of the solution increases. [Cl⁻] decreases.

B) The KOH reacts with the H⁺ and removes it from the solution. [H⁺] decreases.

C) When all the H⁺ from the HCl has been neutralized, the KOH starts neutralizing the H⁺ from the HClO₂. According to Le Châtelier's Principle, more HClO₂ will dissociate to replace the decreased H⁺. [HClO₂] decreases.

D) As HClO₂ reacts, it forms ClO₂⁻. [tex]\boxed{\rm \textbf{[ClO$_{2}^{-}$] increases}}[/tex]

The amount of ClO2- increases as aqueous KOH is added.

Strong acids ionize completely in solution to produce hydrogen ions.

Weak acids only ionize partially in solution to produce hydrogen ions.

When aqueous KOH is added to a mixture of HCl and HClO2, the follow occurs:

Therefore, the amount of ClO2- increases as aqueous KOH is added.

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To balance the equation Fe2O3 + 3CO → 2Fe + 3CO2, we need to ensure that the number and type of atoms are the same on both sides. Using the balanced equation, we can determine that when 40.0 mol of CO reacts with Fe2O3, 1,760 g of CO2 will be produced.

To balance the equation Fe2O3 + 3CO → 2Fe + 3CO2, we need to ensure that the number and type of atoms are the same on both sides.
Fe2O3 + 3CO → 2Fe + 3CO2

Now, to determine how many grams of CO2 will be produced when 40.0 mol of CO reacts with Fe2O3, we use the balanced equation to set up a conversion factor. The stoichiometric ratio for CO2 to CO is 3:3. So, for every 3 moles of CO, 3 moles of CO2 are produced.

Therefore, using the conversion factor:
40.0 mol CO × (3 mol CO2/3 mol CO) = 40.0 mol CO2

Converting moles to grams, we can use the molar mass of CO2:
40.0 mol CO2 × (44.01 g CO2/1 mol CO2) = 1,760 g CO2

Answer:

C. the last one

Explanation:

Cysteine's unique characteristic is its ability to form disulfide bridges, covalent bonds that provide structural stability to proteins. The formation of these bridges is a unique property of cysteine among the amino acids, even though it, like others, can form hydrogen bonds.

The unique characteristic of the amino acid cysteine is its ability to form disulfide bridges. These bridges are covalent bonds that provide structural stability to proteins. While cysteine is capable of forming hydrogen bonds like other amino acids, its special characteristic is indeed the formation of these disulfide bridges. Two cysteine residues can come together to form a disulfide bridge, helping to stabilize the three-dimensional structure of the protein. It is notable that hydrogen bonds are weak interactions that occur broadly between many different molecules, but the covalent bonding of disulfide bridges is a unique property of cysteine within the amino acid series.

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Answer:

Explanation:

Alkenes and alkynes are unsaturated molecules, because they have, at least, two adjacent carbon atoms bonded together by either a doubler or a triple bond: - C = C -  or - C ≡ C -.

Hence, at least two carbon atoms are needed to form those double or triple bonds, while alkanes have only single bonds. The example of alkane with only one carbon atom is methane: CH₄, which is the most simple alkane.

The most simple alkene is CH₂ = CH₂, and the most simple alkyne is CH≡CH.

As you see, the very definition of alkenes and alkynes forces that those molecules must have at least two carbon atoms.

Answer:

Explanation:

1) Word reaction:

This is a single replacement reaction, in which aluminum, a more acitve metal than iron, replaces the iron in the ferrous oxide to form aluminum oxide and iron.

2) Skeleton chemical equation:

3) Balanced chemical equation:

Add the coeffcients to comply with the law of conservation of mass:

4) Mole ratio of Al and FeO:

5) Set a proportion with the unkown and solve:

Answer:

ions

Explanation:

An atom that has gained or lost an electron is called an ion. Ions are charged particles that have lost or added an electron to their outermost shell. Ions are the basis of any chemical reaction. The combination of ions leads to the formation of bonds between atoms and this results in molecules and compounds.

When atoms are in their ground state, they are otherwise neutral and such would not combine chemically. It is difficult to find elements in such form naturally. Atoms that have ionized by losing or gaining electrons would freely combine with one another in order to establish a more stable configuration.

Answer:

A saturated solution

Explanation:

A saturated solution is a solution which has dissolved as much solute as it can dissolve at a given temperature. If more solutes are added, a saturated solution would not dissolve it. Such solution has reached its carrying capacity.

If the temperature changes, the solution might be able to dissolve more solutes in it.

An undersaturated solution is one in which does not contain enough dissolved solutes in it at a given temperature.

To determine the mass of SO₃ that can react with 3.59 mol of Fe₂O₃, we use the molar ratio from the balanced equation and the molar mass of SO₃ to find that 862 g of SO₃ are needed.

To find out how many grams of SO₃ can react with 3.59 mol of Fe₂O₃, we follow a two-step mole-mass calculation process. The balanced chemical equation Fe₂O₃ +3SO₃
ightarrow Fe₂(SO₄)₃ provides us with the molar ratio needed for this calculation. For every mole of Fe₂O₃, three moles of SO₃ are required. So, we multiply the number of moles of Fe₂O₃ (3.59 mol) by three to find the moles of SO₃needed.

Once we have the number of moles of SO₃, we then use the molar mass of SO₃ to find the mass. The molar mass of SO₃ is 80.066 g/mol. After calculating the number of moles of SO3, we can then multiply by this molar mass to get the final weight of SO₃ that can react with 3.59 mol of Fe₂O₃. Applying this method, we calculate that 862 g of SO₃ will react with 3.59 mol of Fe₂O₃.

Answer:

12.5 atm.

Explanation:

Ptotal = P1 + P2 + … + Pn.

∴ Ptotal = P of gas 1 + P of gas 2 + P of gas 3 + P of gas 4 + P of gas 5.

∴ Ptotal = 5(2.5 atm) = 12.5 atm.

Answer:

Rate 1 => 1.2E-3 M/s, Rate 2 => 1.05E-3 M/s, Rate 3 => 8.9E-4 M/s

Explanation:

Rate = Δ[N₂O₅]/Δtime

Rate 1 = (1.86556 - 2310195)M/(195 - 0)s = -1.2 x 10⁻³ M/s

Same for Rates 2 & 3.

The rate of reaction can be calculated in terms of the consumption of the reactants in the reaction.

In the given equation [tex]\rm N_2O_5[/tex] has been the reactant that has been used 2 moles.

The rate of the reaction has been = [tex]\rm -\dfrac{1}{2}\;\times\;\dfrac{dN_2O_5}{dt}[/tex]

Reaction rate = [tex]\rm -\dfrac{1}{2}\;\times\;\dfrac{1.86556\;-\;2.10195}{195\;s\;-\;0\;s}[/tex]

= [tex]\rm -\dfrac{1}{2}\;\times\;\dfrac{-0.23639}{195\;s}[/tex]

= 0.0006 M/s.

Reaction rate = [tex]\rm -\dfrac{1}{2}\;\times\;\dfrac{1.48825\;-\;1.86556}{556\;s\;-\;195\;s}[/tex]

= [tex]\rm -\dfrac{1}{2}\;\times\;\dfrac{-0.416735}{361\;s}[/tex]

= 0.0005 M/s

= [tex]\rm -\dfrac{1}{2}\;\times\;\dfrac{1.25\;-\;1.48825}{825\;s\;-\;556\;s}[/tex]

= [tex]\rm -\dfrac{1}{2}\;\times\;\dfrac{-0.23825}{269\;s}[/tex]

= 0.0004 M/s.

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