Answer:
601 square inches
Step-by-step explanation:
The wrapping is needed to cover a cubed gift box that is 9 inches high is 616 sq inches.
What is surface area? The surface area is the sum of the areas of all its faces.The areas of the base, top, and lateral surfaces i.e all sides of the object. It is measured using different area formulas and measured in square units and then adding all the areas. The surface area of a solid object is a measure of the total area that the surface of the object covers.Calculation:-
The area of gift wrapping needed is equal to the total surface area of the box.
area of a bow =115
∴ side of bow =[tex]\sqrt{115}[/tex]
= 10.72
total surface area = 115+115+10.72+10.72
=616 sq ft.
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Ben went to the farmer’s market with $14.00, bought 2 pounds of cherries and still had enough money left to buy 3 pounds of apples. Tom went to the farmer’s market and bought 6 pounds of apples and 4 pounds of cherries for $28.00.
14 – 2y = 3x, 6x + 4y = 28
The boys solved the equations to find the price per pound that they paid for cherries and found the solution 14 = 14. How should they interpret this result?
A: The price of 4 pounds of cherries is $14.00.
B: The price of 2 pounds of cherries is $14.00.
C: They made a math error when solving the equations, and should try a different solution method to find the price of the cherries.
D: The two equations describe the same line, so there is not enough information to determine the price per pound of cherries.
Answer:
C C C C
Step-by-step explanation:
DONT LISTEN TO THE FIRST GUY ITS C THEY MADE A MATH ERRORRR
can you help me will mark brainlyist
Answer:
see below
Step-by-step explanation:
The functions for these tables are, respectively, ...
f(x) = 5 - x
f(x) = 3x
f(x) = (x -1)² . . . . . a quadratic relation
f(x) = 4x² . . . . . . a quadratic relation
We assume the intention is that the terminology "quadratic variation" mean "proportional to the square of x". In that case, only the last function has such variation.
According to the fundamental theorem of algebra, how many roots does the polynomial f(x)=x4+3x2+7 have over the complex numbers, and counting roots with multiplicity greater than one as distinct? (i.e f(x)=x2 has two roots, both are zero).
The polynomial f(x)=x^4+3x^2+7 has four roots over the complex numbers according to the fundamental theorem of algebra, counting roots with multiplicity greater than one as distinct. This is consistent with the theorem's stipulation that a polynomial of degree n has exactly n roots.
Explanation:The subject of this question is the fundamental theorem of algebra which belongs to the domain of Mathematics, specifically the study of polynomials. As indicated in the question, we have a function, f(x), which represents a polynomial of degree 4 as shown by the highest exponent. According to the fundamental theorem of algebra, a polynomial of degree n has exactly n roots, counting multiplicity. This means a function f(x)=x4+3x2+7, which is a fourth degree polynomial, will have four roots over the complex numbers.
This is also true per the theorem when roots with multiplicity greater than one are considered distinct. For example, f(x)=x2 is a polynomial of degree 2; it has two roots, both are zero, hence the two roots are counted as two distinct roots.
While the quadratic formula is used for finding roots of second degree polynomials, it is not directly applicable here since we are dealing with a fourth degree polynomial.
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Which statement about the function f(x)=x(x – 3)(x – 2) is true?
It has no horizontal asymptote.
It does not cross the horizontal asymptote.
It crosses the horizontal asymptote at the origin.
It has one vertical asymptote.
Answer:
It has no horizontal asymptote
Step-by-step explanation:
It has no horizontal asymptote. This is a cubic function which has the end behavior of the left tail down and the right tail up, so both the domain and the range are infinity. That means that there is no horizontal asymptote to go through. Because it is not a rational function, there are no vertical asymptotes that could make the denominator go to 0 since there is no denominator (not rational).
Answer:
C,
It crosses the horizontal asymptote at the origin.
Step-by-step explanation:
Plato
What is m∠A ? Enter your answer in the box.
Answer:
The measure of angle A is 115°
Step-by-step explanation:
we know that
The sum of the internal angles of a triangle must be equal to 180 degrees
so
∠C+∠A+∠B=180°
substitute values and solve for x
x°+(3x-35)°+(x-35)°=180°
5x°=180°+70°
x=250°/5=50°
Find the measure of angle A
∠A=(3x-35)°
substitute the value of x
∠A=(3(50)-35)=115°
Answer:
[tex]m\angle A=115\degree[/tex]
Step-by-step explanation:
The sum of angles in a triangle is 180 degrees.
[tex]\implies (x-35)\degree+x+(3x-35)\degree=180\degree[/tex]
[tex]\implies 5x-70\degree=180\degree[/tex]
[tex]\implies 5x=180+70[/tex]
[tex]\implies 5x=250[/tex]
Divide both sides by 5.
[tex]\implies x=50[/tex]
We substitute the value of angle A to obtain:
[tex]m\angle A=3(50)-35[/tex]
[tex]m\angle A=115\degree[/tex]
PLEASE HELP!!
In isosceles △ABC, AB = BC and CH is an altitude. Find the perimeter of △ABC, if CH = 84 cm and m∠HBC = m∠BAC +m∠BCH?
Answer:
I think I could help you
Have fun and feel free to ask me something new.
Or we can prove some properities without calculating by details
Step-by-step explanation:
I think I could help you
Have fun and feel free to ask me something new.
Or we can prove some properities without calculating by details
Answer: The perimeter of triangle ABC is (112√3 + 168) cm.
Step-by-step explanation: Given that in isosceles triangle △ABC, AB = BC and CH is an altitude. Also,
CH = 84 cm and
[tex]m\angle HBC = m\angle BAC+m\angle BCH~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
We are to find the perimeter of triangle ABC
Since AB = BC, so the angles opposite to them are congruent and have equal measures.
That is, [tex]m\angle BAC=m\angle ACB~~~~~~~~~~~~~~~~~~~~~~~~(ii)[/tex]
Now, since angle HBC is an exterior angle of triangle ABC and triangles BAC and ACB are remote interior angles.
So, we have
[tex]m\angle HBC=m\angle BAC+m\angle ACB\\\\\Rightarrow m\angle BAC+m\angle BCH=m\angle BAC+m\angle ACB\\\\\Rightarrow m\angle ACB=m\angle BCH.[/tex]
Therefore, from equation (i) implies that
[tex]m\angle HBC = m\angle BAC+m\angle BCH\\\\\Rightarrow m\angle HBC=m\angle BCH+m\angle BCH~~~~~~~[\textup{applying equations (ii) and (iii)}]\\\\\Rightarrow m\angle HBC=2m\angle BCH.[/tex]
Now, from angle sum property in triangle BCH, we have
[tex]m\angle HBC+m\angle BCH+m\angle BHC=180^\circ\\\\\Rightarrow 3m\angle BCH+90^\circ=180^\circ\\\\\Rightarrow 3m\angle BCH=90^\circ\\\\\Rightarrow m\angle BCH=30^\circ.[/tex]
So, we get
[tex]m\angle BAC=m\angle ACB=m\angle BCH=30^\circ,\\\\m\angle HBC=2\times30^\circ=60^\circ.[/tex]
In right-angled triangle ACH, we have
[tex]\tan 30^\circ=\dfrac{CH}{AH}\\\\\\\Rightarrow \dfrac{1}{\sqrt3}=\dfrac{84}{AH}\\\\\\\Rightarrow AH=84\sqrt3.[/tex]
In right-angled triangle BCH, we have
[tex]\tan 60^\circ=\dfrac{CH}{BH}\\\\\\\Rightarrow \sqrt3=\dfrac{84}{BH}\\\\\\\Rightarrow BH=\dfrac{84}{\sqrt3}.[/tex]
And,
[tex]\sin 60^\circ=\dfrac{CH}{BC}\\\\\\\Rightarrow \dfrac{\sqrt3}{2}=\dfrac{84}{BC}\\\\\\\Rightarrow BC==\dfrac{168}{\sqrt3}=56\sqrt3.[/tex]
Therefore,
[tex]AB=AH-BH=84\sqrt3-\dfrac{84}{\sqrt3}=\sqrt3(84-28)=56\sqrt3.[/tex]
Now, in triangle ACH,
[tex]\sin 30^\circ=\dfrac{CH}{AC}\\\\\\\Rightarrow \dfrac{1}{2}=\dfrac{84}{AC}\\\\\Rightarrow AC=168.[/tex]
Thus, the perimeter of triangle ABC is given by
[tex]P=AB+BC+CA=56\sqrt3+56\sqrt3+168=112\sqrt3+168.[/tex]
The perimeter of triangle ABC is (112√3 + 168) cm.
What is the distance between points F and G?
(Picture below)
Answer:
18
Step-by-step explanation:
The distance is 12 - (-6) = 12 + 6 = 18
-6+x=12 it’s obviously 18 units apart
Find an equation for the nth term of the arithmetic sequence.
a19 = -92, a20 = 6
a. an = -1856 + 98(n - 1)
b. an = -1856 - 98(n - 1)
c. an = -1856 - 98(n + 1)
d. an = -1856 + 98(n + 1)
d = 92+6 = 98
an = a1 + 98 (n-1)
a1=a19-98 (n-1)
a1=-92 -98 * 18
=-1856
It’s A ( an = -1856+98(n-1) )
Find the value of x, rounded to the nearest tenth
Answer:
x=12.5
Step-by-step explanation:
The given triangle is a right angle triangle.
We cannot use the Pythagoras theorem as the lengths of all sides are not known. We will use triangular ratios here to solve the given problem.
As it is clear from the diagram that x is the hypotenuse of the triangle and 11 is the length of the base. We will use a ratio in which base and hypotenuse are used.
So,
cos θ= base/hypotenuse
cos 28=11/x
x=11/cos28
x=11/0.8829
x=12.45
Rounding off to nearest 10
x=12.5
In every right triangle, a leg is given by the multiplication between the hypothenuse and the sine of the opposite angle, or the cosine of the adjacent one.
So, in this case, we have
[tex]11 = x\cos(28)[/tex]
Solving for x, we have
[tex]x = \dfrac{11}{\cos(28)}\approx 12.5[/tex]
A grocery clerk sets up a display of oranges in the form of a triangle using 14 oranges at the base and 1 at the top how many oranges were used by the clerk to make the arrangement?
Answer:
105
Step-by-step explanation:
The numbers that can be used to form triangles are collectively called "triangle numbers." The n-th triangle number is the sum of all numbers less than or equal to n. It is ...
n(n+1)/2
For n=14, the number is 14(15)/2 = 7·15 = 105.
The clerk used 105 oranges to make the arrangement.
The grocery clerk used 105 oranges to set up a triangular display. This is calculated with the formula for triangular numbers sequence (n*(n+1))/2 where n is the base of the triangle.
Explanation:To solve the problem, we need to use the approach for calculating the number of items in a triangular number sequence. Triangular numbers are used to form equilateral triangles. The nth term of a triangular number sequence is given by the formula (n*(n+1))/2. In this case, the base of the triangle contains 14 oranges, so n=14.
Using the formula, the total number of oranges used to form triangle by the grocery clerk is (14*(14+1))/2 = 105 oranges. So, the clerk used 105 oranges to set up the display.
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PLSSS HELPPP A football quarterback goes for a two-point conversion when the ball is within 10 yards of the end zone. During the game, he has two opportunities for a two-point conversion. He misses the first attempt 50% of the time. When he misses the first attempt, he misses the second attempt 15% of the time. What is the probability of missing both two-point conversion attempts?
Answer:
The probability of missing both two-point conversion attempts is 7.5%
Step-by-step explanation:
We are informed that the probability of missing the first attempt is 50% of the time. Furthermore, the probability of missing on the second attempt given that he missed the first attempt is 15% of the time
Now,the probability of missing on both the two-point conversion attempts will simply be given by the product of these two probabilities since the events are independent;
50%*15% = 0.5 * 0.15 = 7.5%
Therefore, the probability of missing both two-point conversion attempts is 7.5%
Answer:
The probability of missing both two-point conversion attempts is 7.5%
Step-by-step explanation:
^^
In this figure, AB ||CD and m<1=135. What is m<7
Answer:
135
Step-by-step explanation:
Angles 1 and 3 are vertical angles, so they are congruent.
Since angle 1 measures 135 deg, angle 3 also measures 135 deg.
Angles 3 and 7 are corresponding angles of parallel lines cut by a transversal, so they are congruent.
Since angle 3 measures 135 deg, angle 7 also measures 135 deg.
Answer: m<7 = 135 deg
congruence, in mathematics, the term employed in several senses, each connoting harmonious relation, or agreement, and correspondence. so 2 triangles are congruent if 2 sides and their included angle in the 1 are = to 2 sides and their included angle in the other.
Angles one and three are vertical angles, so they are congruent.
Since angle one measures 135 degree, angle three also measures 135 degree.
Angles 3 or 7 are corresponding angles to the parallel lines cut by the transversal, so they are congruent.
Since angle 3 measures 135 deg, angle 7 also measures 135 deg.
Answer: m<7 = 135 degree
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Use what you know about translations of functions to analyze the graph of the function f(x) = (0.5)x−5 + 8. You may wish to graph it and its parent function, y = 0.5x, on the same axes. The parent function y = 0.5x is across its domain because its base, b, is such that . The function, f, shifts the parent function 8 units . The function, f, shifts the parent function 5 units .
Answer:
The parent function y = 0.5x is DECREASING across its domain because its base, b, is such that 0<b<1.
The function, f, shifts the parent function 8 units UP .
The function, f, shifts the parent function 5 units RIGHT .
Translation involves moving a function vertically or horizontally.
The function [tex]\mathbf{y = 0.5^{x- 5} + 8}[/tex] shifts the parent function 5 units right, and 8 units up.
The parent function is given as:
[tex]\mathbf{y = 0.5^x}[/tex]
Move the function right, by 5 units
[tex]\mathbf{y = 0.5^{x- 5}}[/tex]
Move the function up by 8 units
[tex]\mathbf{y = 0.5^{x- 5} + 8}[/tex]
So, the function [tex]\mathbf{y = 0.5^{x- 5} + 8}[/tex] shifts the parent function 5 units right, and 8 units up.
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A model rocket is launched into the sky. The distance the rocket flies is 25 feet the first second, 75 feet the next second, 125 feet the third second, and so on in an arithmetic sequence. What is the total distance the rocket flies in 6 seconds? A) 275 B) 550 C) 900 D) 1200
A is the correct answer
Please help me out with this
Answer:
y=6x-2
Step-by-step explanation:
to find the 6 you have to see the difference in the y values and the y values are going up by 6 each time. the -2 comes from the y intercept. to find the y intercept you have to see when x=0 which in this table is -2
hope i helped
y = 6x - 2. The equation that describes how x and y are related is given by y = 6x - 2.
If we look the table of the image, we can see that the graph that describes the relation between x and y is a straight line.
The set of infinite points aligned in the same direction is known as straight line and its main equation has the form y = mx + b, where m is the slope, and b the y-intercept.
In order to solve this problem, we need to find the slope which is [tex]m = \frac{y_{2}-y_{1} }{x_{2}- x_{1}}[/tex]
Solving m for two points of the straight line, Let's take (0, -2) and (1, 4):
[tex]m = \frac{4-(-2)}{1 - (0)}=\frac{6}{1} \\m = 6[/tex]
We can see if we take two points in order from the table always obtain the value m = 6, which means for each unit of x, y increase 6 units.
To find the y- intercept (0, y), from the table of the image we can see when x = 0, y = -2.
Writing the equation y = mx + b, with m = 6 and b = -2:
y = 6x -2
Please HELP ASAP I really need help
Answer:
[tex]f(g(x)) = 16x ^ 4-32x ^ 2 + 18[/tex]
Step-by-step explanation:
we have two functions
[tex]f (x) = x ^ 2 -2x + 3\\\\g (x) = 4x ^ 2-3[/tex]
We wish to find the compound function f(g(x))
To find f(g(x)) you must introduce the function g(x) within the function f(x). This is change the variable x, in the function f(x), by g(x).
[tex]f (g (x)) = (4x ^ 2-3) ^ 2 - 2 (4x ^ 2-3) +3[/tex]
Now simplify the expression:
[tex]f (g (x)) = 16x ^ 4-24x ^ 2 + 9 - 8x ^ 2+6 +3\\\\f(g(x)) = 16x ^ 4-32x ^ 2 + 18[/tex]
ANSWER
[tex]f(g(x)) = 16 {x}^{4} -3 2{x}^{2} +18[/tex]
EXPLANATION
The given functions are:
[tex]f(x)={x}^{2} - 2x + 3[/tex]
and
[tex]g(x) = 4 {x}^{2} - 3[/tex]
We want to find
[tex]f(g(x)) = f(4 {x}^{2} - 3)[/tex]
This implies that;
[tex]f(g(x)) = ( 4 {x}^{2} - 3)^{2} - 2(4 {x}^{2} - 3) + 3[/tex]
We expand to get,
[tex]f(g(x)) = 16 {x}^{4} - 24 {x}^{2} + 9- 8 {x}^{2} + 6+ 3[/tex]
[tex]f(g(x)) = 16 {x}^{4} -3 2{x}^{2} +18[/tex]
Karl participated in a two-day charity walk. His parents donated money for each mile he walked. Karl walked 2 1 4 miles on the first day and 5 1 2 miles on the second day. His parents donated $62. How much money did his parents pay for each mile?
Answer:
$8/mile
Step-by-step explanation:
Total distance walked was 2 1/4 mi + 5 1/2 mi = 7 3/4 mi. Please note: you must use the " / " symbol to indicate division; "2 1 4" is unclear.
$62
Unit rate = $ per mile = --------------- = $8/mile
7 3/4 mi
90 POINTS!!!!! Given: KLIJ inscr. in k(O),m∠K = 64°, measure of arc LI = 69°, measure of arc IJ = 59°, measure of arc KJ =97°
Find: All angles of KLIJ
In any cyclic quadrilateral, angles opposite one another are supplementary, meaning
[tex]m\angle K+m\angle I=m\angle L+m\angle J=180^\circ[/tex]
and given that [tex]\boxed{m\angle K=64^\circ}[/tex], we have [tex]\boxed{m\angle I=116^\circ}[/tex].
By the inscribed angle theorem,
[tex]m\angle JLK=\dfrac12m\widehat{KJ}[/tex]
[tex]m\angle ILJ=\dfrac12m\widehat{IJ}[/tex]
and since
[tex]m\angle L=m\angle JLK+m\angle ILJ[/tex]
we have
[tex]m\angle L=\dfrac{97^\circ+59^\circ}2\implies\boxed{m\angle L=78^\circ}[/tex]
and it follows that
[tex]m\angle J=180^\circ-m\angle L\implies\boxed{m\angle J=102^\circ}[/tex]
What horizontal distance has she covered?
ANSWER
169.1m
EXPLANATION
From the diagram, the horizontal distance traveled is x meters.
This is the side adjacent to the 6° angle.
Since we know the hypotenuse to be 170m, we use the cosine ratio to find the value of x.
[tex]\cos(6 \degree) = \frac{opposite}{hypotenuse} [/tex]
[tex] \cos(6 \degree) = \frac{x}{170} [/tex]
.
This implies that
x=170cos(6°)
x=169.0687222
To the nearest tenth, the horizontal disance travelled is 169.1m
Please please help me
use pythagorean theorem
Answer:
x = 3.6
Step-by-step explanation:
Using the tangent ratio in the right triangle
tan20° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{x}{10}[/tex]
Multiply both sides by 10
10 × tan20° = x, hence
x ≈ 3.6
What is the value of x if 15 = 5x + 45 ?
Answer:
x=6
Step-by-step explanation:
15 = 5x + 45
/5 /5
15 = x + 9
-9 -9
6 = x
The value of x = 6
PLEASE HELP!!!!!! 10 POINTS
A highway speed monitor is located on the side of the road that has a speed limit of 45 mph. The system records the speeds of passing vehicles. The data below shows the speeds of the first 9 cars that pass.
46 56 45 44 45 61 55 53 39
What is the standard deviation, to the nearest tenth, based on the posted speed limit, 45 mph? ___________.
The tenth car traveling on this road breaks down and is being pushed by its owners as it passes the speed monitor. A speed of 1.5 mph is recorded. The measure of central tendency most affected by this tenth speed is the ____________.
What is the new standard deviation, to the nearest tenth, after the tenth speed is recorded? __________.
you need to find the mean on these numbers that is step one in finding standard deviation. so this is 44.2. now you need to subtract the mean from each number and square the result. after that step you now have these numbers.... 3.24, 139.24, .64, .4,.64,282.24,116.64,77.44,27.04. now the next step is to find the mean of these numbers. you get 71.9 appx.. now all you do is square root this number you get 8.5 when you round to the nearest thenth
What is the cosine ratio for angle F?
hope this answer your question :)
ANSWER
[tex]\cos( \angle \: F) = \frac{5}{13}[/tex]
EXPLANATION
The side length adjacent to <F is 5 units.
The length of the hypotenuse is 13 units.
The cosine ratio is
[tex] \cos( \angle \: F) = \frac{adjacent}{hypotenuse} [/tex]
This implies that:
[tex] \cos( \angle \: F) = \frac{5}{13}[/tex]
The fourth choice is correct.
Hot air ballon 280 feet away as it rises up into the sky. At first, the balloon is at an angle of elevation of 12 degrees. A few minutes later, the balloon rises to angle of elevation of 60 degrees. What is the change in altitudes between Steve's two observations?
Answer:
Step-by-step explanation:
This is right triangle trig. The reference angle is 12 in one case and 60 in the other, but the horizontal distance doesn't change in either one, and neither does what you are looking for, which is the height of the balloon in both cases of the angle differences. And if you're looking for the difference in the height, you'll find both and subtract the smaller from the larger.
The height is across from the reference angle and the horizontal distance is adjacent to the reference angle, so the trig identity you want is tangent. Set up according to the angle measure of 12 degrees:
[tex]tan(12)=\frac{x}{280}[/tex] and
280 tan(12) = x
x = 59.5 ft
Now for the angle measuring 60 degrees:
[tex]tan(60)=\frac{x}{280}[/tex] and
280 tan(60) = x
x = 484.9
The difference between the two heights is 425.5 feet.
when dealing with two rational expressions that have different denominators, how would you find a common denominator. What effect would that have on the numerators of the expression
Answer:
you mulitple the two bottomz by the other number
example 3/4 and 2/8
8 is a common mulitple so 3/4 becomes 6/8 and now they have common denominators
Step-by-step explanation:
example 3/4 and 2/8
8 is a common mulitple so 3/4 becomes 6/8 and now they have common denominators
and the numerator gets multipled with the same number as the denominator
Sylvia is going on vacation and she has to drive 393 miles.If she has already gone 45miles in one hour and her current speed is 58miles per hour ,how much longer will it take Sylvie to reach her destination
Answer:
6 hours.
Step-by-step explanation:
She has already travelled 45 miles so there's another 393-45 = 348 miles to travel. So if she continues at 58 mph she will take 348 / 58 = 6 hours.
There are 14 students making sculptures with craft sticks. There are 644 craft sticks in a box. Each student gets an equal number of craft sticks. Explain each step needed to determine the maximum number of craft sticks that each student can get.
Answer:
46 craft sticks per student
Step-by-step explanation:
The simplest situation would be that in which the available 644 craft sticks are evenly divisible by the number of students receiving them. If that's the case, all we have to do is to divide:
644 craft sticks
----------------------- = 46 craft sticks per student
14 students
Identify the graph of the equation x^2+y^2=9. PLEASE HELP!!
The correct graph of the circle [tex]\rm x^2+y^2=9[/tex] is graph D, the corrcet option is D.
What is the equation of the circle?A circle can be represented as;
[tex]\rm (x-h)^2+(y-k)^2=r^2[/tex]
Where h and k are the centers of the circle and r is the radius of the circle.
The given equation of the circle is;
[tex]\rm x^2+y^2=9[/tex]
Here the center of the circle h = 0 and k = 0 so the circle passes through the origin.
The radius of the circle is;
[tex]\rm r^2=9\\\\r^2=3^2\\\\r=3[/tex]
Hence, the correct graph of the circle [tex]\rm x^2+y^2=9[/tex] is graph D, the correct option is D.
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HELP !!! | 20 Points.
Joshua has a ladder that is 17 ft long. He wants to lean the ladder against a vertical wall so that the top of the ladder is 16.5 ft above the ground. For safety reasons, he wants the angle the ladder makes with the ground to be no greater than 70°. Will the ladder be safe at this height? Show your work.
Answer:
No. The ladder is too steep.
Step-by-step explanation:
Length of ladder = 17 feet. This is the hypotenuse.
Side a of a right triangle = 16.6
To answer this, you need one of the trigonometric functions.
Opposite = 16.5
hypotenuse = 17
The function you need is the sine function.
Sin(theta) = opposite / hypotenuse
sin(theta) = 16.5 / 17
Sin(theta) = 0.97059
theta = sin-1(0.07059)
theta = 76.07
No the ladder is too steep.
Answer:
The ladder will not be safe.
Step-by-step explanation:
The ladder is 17 ft long
The top of the ladder is 16.5 ft above the ground
The ladder makes a right triangle of height = 16.5 ft and hypotenuse = 17 ft
To find the angle the ladder makes with the ground,
Height ÷ hypotenuse = sin angle
i.e [tex]\frac{16.5}{17}[/tex] = sin angle
[tex]sin^{-1}[/tex] angle = 76.1°
So the ladder is not safe since the angle it makes with the ground is greater than 70°.
Question 78 find the value of x
For this case we have that by definition, the volume of a parallelepiped is given by:
[tex]V = l * w * h[/tex]
Where:
l: It's the long
w: It is the width
h: It's the height
From the figure we have the following data:
[tex]V = 975 \ ft ^ 3\\h = 9 \ ft\\w = 4ft\\x =?[/tex]
We must find the value of the length of the parallelepiped:
[tex]975 = x * 4 * 9\\975 = 36x\\x = \frac {975} {36}\\x = 27.083[/tex]
Answer:
[tex]x = 27.1 \ ft[/tex]