Answer: Option (c) is the correct answer.
Explanation:
Atomic number of carbon is 6 and its electronic configuration is [tex]1s^{2}2s^{2}2p^{2}[/tex].
Atomic number of oxygen is 8 and its electronic configuration is [tex]1s^{2}2s^{2}2p^{4}[/tex].
Atomic number of titanium is 2 and its electronic configuration is [tex][Ar]4s^{2}3d^{2}[/tex].
Atomic number of silicon is 14 and its electronic configuration is [tex][Ne]3s^{2}3p^{2}[/tex].
Therefore, we can conclude that out of the given options all the 4 elements have 2 unpaired electrons in the ground state.
Among Carbon (C), Oxygen (O), Titanium (Ti), and Silicon (Si), only Carbon (C) and Silicon (Si) have 2 unpaired electrons in their ground state.
Explanation:The question is asking how many of the following elements: Carbon (C), Oxygen (O), Titanium (Ti), and Silicon (Si) have 2 unpaired electrons in the
ground state
. In a
ground state
, an atom's electrons are all in the lowest possible energy levels. Carbon has 2 unpaired electrons, as its electron configuration ends in 2s^22p^2. Silicon, similar to carbon, also has 2 unpaired electrons with electron configuration ending in 3s^23p^2. However, Oxygen (2s^22p^4) and Titanium (3d^24s^2) do not have 2 unpaired electrons in their ground state, the answer is therefore (d) 2.
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Calculate the pH of each of following buffered solutions.?a. 0.10 M acetic acid/0.25 M sodium acetate b. 0.25 M acetic acid/0.10 M sodium acetate c. 0.080 M acetic acid/0.20 M sodium acetate d. 0.20 M acetic acid/0.080 M sodium acetate
Answer:
a. 5.10.
b. 4.35.
c. 5.10.
d. 4.35.
Explanation:
a. 0.10 M acetic acid/0.25 M sodium acetate
For acidic buffer:
∵ pH = pKa + log [salt]/[Acid]
∴ pH = - log(Ka) + log [salt]/[Acid]
Ka for acetic acid = 1.8 x 10⁻⁵.
∴ pH = - log(1.8 x 10⁻⁵) + log(0.25)/(0.10)
∴ pH = 4.744 + 0.34 = 5.084 ≅ 5.10.
b. 0.25 M acetic acid/0.10 M sodium acetate
For acidic buffer:
∵ pH = pKa + log [salt]/[Acid]
∴ pH = - log(Ka) + log [salt]/[Acid]
Ka for acetic acid = 1.8 x 10⁻⁵.
∴ pH = - log(1.8 x 10⁻⁵) + log(0.10)/(0.25)
∴ pH = 4.744 - 0.34 = 4.346 ≅ 4.35.
c. 0.080 M acetic acid/0.20 M sodium acetate
For acidic buffer:
∵ pH = pKa + log [salt]/[Acid]
∴ pH = - log(Ka) + log [salt]/[Acid]
Ka for acetic acid = 1.8 x 10⁻⁵.
∴ pH = - log(1.8 x 10⁻⁵) + log(0.20)/(0.08)
∴ pH = 4.744 + 0.34 = 5.084 ≅ 5.10.
d. 0.20 M acetic acid/0.080 M sodium acetate
For acidic buffer:
∵ pH = pKa + log [salt]/[Acid]
∴ pH = - log(Ka) + log [salt]/[Acid]
Ka for acetic acid = 1.8 x 10⁻⁵.
∴ pH = - log(1.8 x 10⁻⁵) + log(0.08)/(0.20)
∴ pH = 4.744 - 0.34 = 4.346 ≅ 4.35.
The pH of various acetic acid and sodium acetate buffered solutions can be calculated using the Henderson-Hasselbalch equation. The pH values are 5.14, 4.34, 5.04, and 4.44 respectively. A good buffer should ideally have equal concentrations of acid and base.
Explanation:To calculate the pH of each buffered solution, we will use the Henderson-Hasselbalch equation, which is pH = pKa + log([A⁻]/[HA]), where [A⁻] is the molar concentration of the base (sodium acetate) and [HA] is the molar concentration of the acid (acetic acid).
Firstly, we need to know the pKa of acetic acid. The Ka of acetic acid is 1.8 x 10⁻⁵, therefore, the pKa = -log(Ka) = 4.74.
For 0.10 M acetic acid/0.25 M sodium acetate, pH = 4.74 + log(0.25/0.10) = 5.14.For 0.25 M acetic acid/0.10 M sodium acetate, pH = 4.74 + log(0.10/0.25) = 4.34.For 0.080 M acetic acid/0.20 M sodium acetate, pH = 4.74 + log(0.20/0.080) = 5.04.For 0.20 M acetic acid/0.080 M sodium acetate, pH = 4.74 + log(0.080/0.20) = 4.44.Remember, a good buffer should have about equal concentrations of both of its components for best buffering capacity.
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Which of the following gases will have the highest velocity at a given temperature? A) Ne B) O2 C) Ar D)N2
The velocity of any gas particles is inversely proportional to the molecular mass of the the gases. Lighter gases posses higher kinetic energy than heavier gases. From the list given, Neon is the lightest of the four gases with an atomic mass of 4.03 thus it is the lightest. Velocity contributes to the Kinetic energy of the particle. Thus A) Neon is the correct answer.
Answer: The correct answer is Option A.
Explanation:
Velocity of the gas is inversely related to the molar mass of the given gas. The equation representing the relation between the two is:
[tex]\text{Velocity of the gas}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}[/tex]
From the above relation, if the molar mass of the gas is more, the velocity of the gas will be less and vice-versa.
The molar masses of the given gases are as:
Ne = 20 g/mol
[tex]O_2[/tex] = 32 g/mol
Ar = 40 g/mol
[tex]N_2[/tex] = 28 g/mol
As, the molar mass of neon is the lowest. Thus, it will have the highest velocity.
Hence, the correct answer is Option A.
One difference between first- and second-order reactions is that ________. One difference between first- and second-order reactions is that ________. the half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0 the rate of both first-order and second-order reactions do not depend on reactant concentrations the rate of a first-order reaction depends on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations a first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed None of the above are true.
Answer:
(first choice)
One difference between first- and second-order reactions is that the half-life of a first-order reaction does not depend on [Ao]; the half-life of a second-order reaction does depend on [Ao].
Explanation:
1) First order reactions' model
This is a brief deduction of the first order reactions' half-life
Equation: aA +b B → cC + dDrate: r = - d[A]/dt = k[A]Integration:- d[A]/[A] = kdt ⇒ - ln { [A]/[Ao] } = kt
Half-life:t half-life = T
[A] = (1/2) [Ao] ⇒- ln { [A]/[Ao] } = - ln (1/2) = ln(2) = kT
⇒ T = ln(2) / T
Conclusion:* The half-life of a first order reaction is a constant; it does not depend on the initial concentration of the reactants, it only depend on the rate constant.
2) Second order reaction's model:
This is a brief deduction of the second order reactions' half-life
Equation: aA +b B → cC + dDrate: r = - d[A]/dt = k[A]²Integration:- d[A]/[A]² = kdt ⇒ 1/[Ao] - 1/[A] = kt
Half-life:t half-life = T
[A] = (1/2) [Ao] ⇒ 1 / [Ao] - 1 / {2[Ao]} = 1 / {2[Ao]} = kT
⇒ T = 1 / {2k[Ao] }
Conclusion:* The half-life of a second order reaction depends on the initial concentration and the rate constant.
3) Final conclusion:
We have found that while the half life of a first order reaction is does not depend on the initial concentration, the half-life of a second order reaction does depends on the initial concentration. Hence, the correct answer to the question is:
One difference between first- and second-order reactions is that the half-life of a first-order reaction does not depend on [Ao]; the half-life of a second-order reaction does depend on [Ao].
The key distinction between first- and second-order reactions lies in the impact of initial reactant concentrations on half-life. In first-order reactions, half-life remains constant, irrespective of initial reactant concentration. For second-order reactions, half-life decreases as reactant concentration increases.
Explanation:One major difference between first- and second-order reactions is found in the relationship between reaction half-life and initial reactant concentration. In a first-order reaction, the half-life is independent of initial reactant concentration, meaning it stays consistent regardless of the amount of reactant present initially. On the other hand, in a second-order reaction, the half-life is dependent on the initial reactant concentration; specifically, the half-life decreases as the concentration increases. The relationship for a second-order reaction follows this formula: t1/2 is inversely proportional to the initial concentration [A]₀. As the reaction proceeds and the reactant concentration decreases, the half-life increases.
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what is the relationship between the kinetic energy of molecules in an object nd the objects temperature?
a. the total kinetic energy of the molecules is not affected by a change in temperature.
b. as the kinetic energy of the modules decreases the temperature increases
c. as the temperature increases the kinetic energy of the molecules increases
d. the kinetic energy always increases whether the temperature increases or decreases
It is C. An increase of temperature results in an increase in kinetic energy of the molecules of the substance. For example, in a gas the molecules will move about faster.
In a certain acidic solution at 25 ∘c, [h+] is 100 times greater than [oh −]. what is the value for [oh −] for the solution? in a certain acidic solution at 25 , [] is 100 times greater than [ ]. what is the value for [ ] for the solution? 1.0×10−8 m 1.0×10−7 m 1.0×10−6 m 1.0×10−2 m 1.0×10−9 m
Answer:
1.0 x 10⁻⁸ M.
Explanation:
∵ [H⁺][OH⁻] = 10⁻¹⁴.
∵ [H⁺] = 100 [OH⁻].
∴ 100 [OH⁻][OH⁻] = 10⁻¹⁴.
∴ 100 [OH⁻]² = 10⁻¹⁴.
[OH⁻]² = 10⁻¹⁴/ 100 = 1.0 x 10⁻¹⁶.
∴ [OH⁻] = √(1.0 x 10⁻¹⁶) = 1.0 x 10⁻⁸ M.
Given the data from the question, the value of the concentration of the hydroxide ion OH¯ is 1×10¯⁸ M
What is pH ?This is simply a measure of the acidity / alkalinity of a solution.
The pH measures the hydrogen ion, H⁺ concentration while the pOH measures the hydroxide ion, OH¯ concentration
Relationships between H⁺ and OH¯[H⁺] × [OH¯] = 10¯¹⁴
How to determine OH¯From the question given above, the following data were obtained:
Hydrogen ion concentration [H⁺] = 100[OH¯]Hydroxide ion concentration [OH¯] =?[H⁺] × [OH¯] = 10¯¹⁴
100[OH¯] × [OH¯] = 10¯¹⁴
100 × [OH¯]² = 10¯¹⁴
Divide both side by 100
[OH¯]² = 10¯¹⁴ / 100
[OH¯]² = 10¯¹⁶
Take the square root of both side
[OH¯] = √(10¯¹⁶)
[OH¯] = 1×10¯⁸ M
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Which sabatamic particle is electrically neutral and found in the nucleus of an atom
The neutron. It is neutral and found inside the nucleus with positive protons.
Which unit can be used to express the rate of a reaction? A. mL / s B. mL / g C. g / mL D. mL / mol E. s / mL
Answer:
A. mL/s.
Explanation:
The rate of the reaction is the change in the concentration of the reactants (decrease) or the products (increase) with time.Rate of the reaction = Δ[C]/Δt.
If we take the volume (mL) expressing the concentration. So, the unit of the rate of the reaction is (mL/s).
What is the approximate mass of a 100-N person on Earth?
Question options:
1 kg
10 kg
100 kg
1,000 kg
What is the equilibrium constant for the reaction
Answer:
B. Keq = [SO₃][NO]/[SO₂][NO₂].
Explanation:
For any equilibrium reaction:Keq = [products]/[reactants].
For the reaction: SO₂(g) + NO₂(g) → SO₃(g) + NO(g).
∴ Keq = [SO₃][NO]/[SO₂][NO₂].
What is a group or family on the periodic table
A group or family on the periodic table is one of the vertical sections on the table. A period is a horizontal section
The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0 °c is 4.48. what is the value of ka for hbro?
a.2.0 × 10-9
b.1.1 × 10-9
c.6.0 × 10-5
d.3.3 × 10-5
e.3.0 × 104
____________________________________________________
Answer:
Your answer would be a). 2.0 × 10-9
____________________________________________________
Work:
In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.
You would use the ph (4.48) to find the ka for "hbro"
[H+]
=
10^-4.48
=
3.31 x 10^-5 M
=
[BrO-]
or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]
Then you would find ka:
(3.31 x 10^-5)^2/0.55 =2 x 10^-9
____________________________________________________
-Julie
There are many different types of objects in the solar system. Which type of object is the Sun?
It is a star, since it glows and is very hot.
Identify the brønsted-lowry acid, the brønsted-lowry base, the conjugate acid, and the conjugate base in each reaction: (a) c5h5n(aq)+h2o(l)⇌c5h5nh+(aq)+oh−(aq) (b) hno3(aq)+h2o(l)⇌h3o+(aq)+no3−(aq) drag the appropriate items to their respective bins.
acids give away protons (H+), bases accept protons, conjugate bases are what u get when when you take the protons from the acid, and conjugate acids are what u get when you add the protons to the base.
so for (a) the C5H5N is the base, water is the acid, C5H5NH+ is the conj acid, OH- is the conj base
(b) HNO3 is the acid, H2O is the base, hydronium ion is the conj. acid, NO3- is the conj base.
Answer: a) [tex]C_5H_5N(aq.)+H_2O(l)\rightarrow C_5H_5NH^+(aq.)+OH(aq.)[/tex]
bronsted- lowry acid : [tex]H_2O[/tex]
conjugate base : [tex]OH^-[/tex]
bronsted- lowry base : [tex]C_5H_5N[/tex]
conjugate acid : [tex]C_5H_5NH^+[/tex]
b) [tex]HNO_3(aq)+H_2O(l)\rightarrow H_3O^+(aq.)+NO_3^-(aq.)[/tex]
bronsted-lowry acid : [tex]HNO_3[/tex]
conjugate base : [tex]NO_3^-[/tex]
bronsted- lowry base : [tex]H_2O[/tex]
conjugate acid : [tex]H_3O^+[/tex]
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
For the given chemical equation:
a) [tex]C_5H_5N(aq.)+H_2O(l)\rightarrow C_5H_5NH^+(aq.)+OH(aq.)[/tex]
Here, [tex]H_2O[/tex] is loosing a proton, thus it is considered as a brønsted-lowry acid and after losing a proton, it forms [tex]OH^-[/tex] which is a conjugate base.
And, [tex]C_5H_5N[/tex] is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms [tex]C_5H_5NH^+[/tex] which is a conjugate acid.
b) [tex]HNO_3(aq)+H_2O(l)\rightarrow H_3O^+(aq.)+NO_3^-(aq.)[/tex]
Here, [tex]HNO_3[/tex] is loosing a proton, thus it is considered as a brønsted-lowry acid and after losing a proton, it forms [tex]NO_3^-[/tex] which is a conjugate base.
And, [tex]H_2O[/tex] is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms [tex]H_3O^+[/tex] which is a conjugate acid.
Laura adds 50ml of boiling water to 100ml of ice water. if the 150ml of water is then put into a freezer, at what temperature will the water freeze?
According to what I know, if the water is pure, it always freezes at 0°C.
- Lee Hae :) Have a great day!
If 50 mL of boiling water is added to 100 mL of ice water and the entire mixture is put in a freezer, the water will freeze at 0 [tex]^oC[/tex].
Irrespective of the initial temperature, water always freezes when its temperature drops to zero degrees Celsius, 32 degrees Fahrenheit, or 273 Kelvin.
The freezing happens at the quoted temperature under standard atmospheric pressure and if the water is pure. At higher pressure, the freezing point is lower and at lower pressure, the freezing point increases.
Impurities also lower the freezing point of water
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Help!!!!!!!!!!!!!!!!!!
rate = k{A}^2{B}^2
When having a reaction both need to be included, so we know that D wouldn't work for us. But since they are being combined they would both be squared with 2. Then they would form compounds of C and D.
The electron configuration of an element is 1s^22s^1. How many valence electrons does the element have?
1
2
3
4
Answer : The number of valence electron present in an element is, 1
Explanation :
Electronic configuration : It is defined as the representation of electrons around the nucleus of an atom.
Number of electrons in an atom are determined by the electronic configuration.
Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.
The given electronic configuration of an element is,
[tex]1s^22s^1[/tex]
That means, the element has 1 valence electrons.
The element has 1 valence electron.
Explanation:The electron configuration of an element is 1s22s1. To determine the number of valence electrons, we look at the highest energy level, which is indicated by the last number in the electron configuration. In this case, the highest energy level is the 2s level. Therefore, the element has 1 valence electron.
The ka of benzoic acid is 6.30 ⋅ 10-5. The ph of a buffer prepared by combining 50.0 ml of 1.00 m potassium benzoate and 50.0 ml of 1.00 m benzoic acid is ________.
pH = 4.20
Explanation;pKa = -log(6.30 × 10^-5)
pKa = 4.20
Moles of Benzoic acid = volume × molarity
= 0.050L × 1.00M
= 0.050moles benzoic acid
Moles of the salt = 0.050L × 1.00M
= 0.050 moles salt
Therefore;
0.050mols / 0.1 L = 0.50M
0.050mols / 0.1 L = 0.50M
Thus;
pH = 4.20 + log(0.50/0.50)
pH = 4.20
From the calculations, the pH of the solution is 4.20
What is pH?The pH is defined as the degree of acidity or alkalinity of a solution. We have to find the pH of the buffer using the Henderson–Hasselbalch equation.
Since, Ka = 6.30 × 10^-5
then pKa = -log(6.30 × 10^-5)
pKa = 4.20
Number of moles of Benzoic acid = volume × molarity
= 0.050L × 1.00M = 0.050moles benzoic acid
Number of moles of benzoate = 0.050L × 1.00M = 0.050 moles
Total volume of solution = 50 mL + 50 mL = 100 mL or 0.1 L
Molarity of acid
0.050mols / 0.1 L = 0.50M
Molarity of conjugate base
0.050mols / 0.1 L = 0.50M
Hence;
pH = 4.20 + log(0.50/0.50)
pH = 4.20
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URGENT!!!
Calculate how many grams of Zinc Chloride are produced if 6.5 of Zn is used to react in the chemical reaction below. Be sure to show all of your work.
Zn + 2HCl —> ZnCl2 + H2
= 13.629 g of ZnCl2
Explanation;The equation for the reaction.
Zn(s)+2HCL(aq)=>ZnCl2(aq)+H2(g)
Number of moles of Zinc;
Moles = mass/RAM
= 6.5 g/65g/mol
= 0.1 moles
The mole ration of Zn : ZnCl2 is 1 : 1
Therefore, number of moles of ZnCl2 is 0.1 moles
Mass = moles × Molar mass
= 0.1 ×136.286 g/mol
= 13.629 g
Using the balanced equation Zn + 2HCl —> ZnCl₂ + H₂, we find that 6.5 g of Zinc produces 13.55 grams of Zinc Chloride.
First, let's write the balanced equation:
Zn + 2HCl → ZnCl₂ + H₂The molar mass of Zn is 65.38 g/mol.The number of moles of Zn is:
n(Zn) = 6.5 g / 65.38 g/mol = 0.099 molFrom the balanced equation, we know that 1 mole of Zn reacts to form 1 mole of ZnCl₂. Therefore, the number of moles of ZnCl₂ produced is:
n(ZnCl₂) = 0.099 mol (Zn) × (1 mol ZnCl₂ / 1 mol Zn) = 0.099 molThe molar mass of ZnCl₂ is 136.29 g/mol.Now, let's calculate the mass of ZnCl₂ produced:
m(ZnCl₂) = 0.099 mol × 136.29 g/mol = 13.5 gTherefore, if 6.5 g of Zn is used, the mass of ZnCl₂ produced is 13.55 g.
Identify which of the following molecules can exhibit hydrogen bonding as a pure liquid.
The following molecules can exhibit hydrogen bonding as a pure liquid is NH3 (amonia), HC3 -- O -- OH (methanol), CH3CO2H (acetic acid)
Further explanation
Hydrogen bonding is directly connected to Nitrogen, Oxygen, and Fluoride and it (N, O, F) represents the hydrogen bonding. Whereas molecule is the smallest particle in a chemical element or compound that has the chemical properties of that element or compound
Identify which of the following molecules can exhibit hydrogen bonding as a pure liquid.
NH3 (amonia) : Yes, because ammonia has 3 bonds, each between Nitrogen and a Hydrogen.HC3 -- O -- OH (methanol) : Yes, because oxygen and hydrogen in the hydroxyl group that branching off of the carbon share a hydrogen bond.CH2F2 (difluoromethane) : No, because the carbon bonds with two hydrogens and two fluorines, but hydrogen and fluorine never bond with each other.CF4 (tetrafluoromethane) : No, because the carbon bonds with four fluorine atoms, hence no hydrogen involved.HI (hydroiodic acid) : No, because F, O, N involved.CH3CO2H (acetic acid) : Yes, because hydrogen bonds with oxygen directly in the hydroxyl substituent group that forms off of the second carbonC7H6O (benzaldehyde): No, because this is a benzene ring with oxygen and hydrogen branching off of one of the carbons.Learn moreLearn more about hydrogen bonding https://brainly.com/question/1814257Learn more about molecules https://brainly.com/question/1462404Learn more about benzaldehyde https://brainly.com/question/12631576Answer detailsGrade: 9
Subject: chemistry
Chapter: hydrogen bonding
Keywords: hydrogen bonding, molecules, amonia, tetrafluoromethane, benzaldehyde
The molecules that exhibit hydrogen bonding are ammonia NH3, acetic acid CH3CO2H and H2C20H
What is hydrogen bonding?Hydrogen bonding refer to am electrostatic force of attraction that exist between a hydrogen atom which is covalently bonded together to an atom that is more electronegative and another electronegative atom that have a lone pair of electrons. the hydrogen bond is the acceptor.
Therefore, The molecules that exhibit hydrogen bonding are ammonia NH3, acetic acid CH3CO2H and H2C20H.
The question is incomplete bit the options are gotten from another website. here are the options below.
N2H4CF2H2HClCF4*H3CO2H*C2H2O4H2C2OHLearn more about hydrogen bonding here.
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WILL MARK BRAINLIEST !! HELP ASAP
Which of the following is an example of a combustion reaction?
A.Photosynthesis in plants
B.Cellular respiration in humans
C.Mixing of vinegar and baking soda
D. Release of carbon dioxide on heating limestone
I am almost positive that the answer is D
Answer : The correct option is, (B) Cellular respiration in humans
Explanation :
Combustion reaction : It is defined as the hydrocarbon react with the oxygen then it react to give carbon dioxide and water as a product.
A. Photosynthesis in plants
Photosynthesis : It is a chemical process or a reaction which takes place in the green plants or the living organisms.
During this process, the carbon dioxide reacts with the water in the presence of sunlight to gives glucose and oxygen as a product.
The balanced chemical reaction will be,
[tex]6CO_2+6H_2O\overset{sunlight}\rightarrow C_6H_{12}O_6+6O_2[/tex]
B. Cellular respiration in humans
Cellular respiration : In this process, the hydrocarbon react with the oxygen to give carbon dioxide and water as a product. This reaction is a combustion reaction.
Cellular respiration is directly opposite of photosynthesis.
The balanced chemical reaction will be,
[tex]C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O[/tex]
C. Mixing of vinegar and baking soda
When vinegar is react with baking soda then it gives sodium acetate, carbon dioxide and water as a product. This reaction is an acid-base reaction.
The balanced chemical reaction will be,
[tex]CH_3COOH+NaHCO_3\rightarrow CH_3COONa+H_2O+CO_2[/tex]
D. Release of carbon dioxide on heating limestone
When limestone (calcium carbonate) is heated then it decomposes to give calcium oxide and carbon dioxide as a product. This reaction is a decomposition reaction.
The balanced chemical reaction will be,
[tex]CaCO_3\rightarrow CaO+CO_2[/tex]
Hence, from this we conclude that the example of combustion reaction is, (B) Cellular respiration in humans
Inside the combustion chamber of a coal-fired power plant
Burning fossil fuels release energy in the form of heat.
How do we account for the great variety of substances in the world? how do we account for the great variety of substances in the world? most of these substances are organic compounds. atoms are incredibly small. the earth is 4.5 billion years old. there are many possible combinations of atoms?
Answer:
There are many possible combinations of atoms
Explanation:
Atoms in the periodic table can combine in a myriad of ways – sometimes quoted to approximately 10^78 combinations. To understand the enormity, carbon (and its ability to form numbers combination with other elements) is the main element significant in the variations of organic life on earth.
Answer:
There are many possible combinations of atoms
Explanation:
This is based on the Law of Multiple Proportion. Two different elements can combine in different ratio to create multiple compounds. Let’s take the example of CO and CO₂. In carbon monoxide there is 1:1 ratio of C:O and in carbon dioxide the ration of C:O is 1:2. Because of the difference in combination ratios of the individual elements the two compounds have different physical and chemical property.
What is different about a reversible reaction
A reversible reaction is a chemical reaction where the reactants form products that, in turn, react together to give the reactants back. Reversible reactions will reach an equilibrium point where the concentrations of the reactants and products will no longer change.
A reversible reaction is a chemical reaction where the reactants form products that, in turn, react together to give the reactants back. Reversible reactions will reach an equilibrium point where the concentrations of the reactants and products will no longer change
The term _____ describes a substance that can act as both an acid and a base.
The term amphoteric describes a substance that can act as both an acid and a base.
The compound sb4o5cl2(s), which has been investigated because of its interesting electrical properties, can be prepared by warming a mixture of antimony(iii) oxide and antimony(iii) chloride, both of which are solids. What is the coefficient of antimony(iii) oxide in the balanced equation for the reaction?
5Sb2O3 + 2SbCl3 -> 3Sb4O5Cl2
The coefficient of Sb2O3 in the equation is 5.
Final answer:
The coefficient of antimony(III) oxide in the balanced chemical equation for the reaction to produce Sb4O5Cl2(s) is 4.
Explanation:
The student is asking for the coefficient of antimony(III) oxide in the balanced chemical equation for the reaction to produce Sb4O5Cl2(s). This substance can be prepared by reacting antimony(III) oxide (Sb2O3) with antimony(III) chloride (SbCl3).
To find the coefficient, we need to balance the equation. Let's consider 'a' as the coefficient for Sb2O3 and 'b' for SbCl3. The possible reaction would be:
a Sb2O3(s) + b SbCl3(s) → Sb4O5Cl2(s)
By examining the stoichiometry, we find that for every 4 atoms of antimony, we should have 5 oxygen and 2 chlorine atoms on the reactant side as well. After balancing, we get:
4 Sb2O3(s) + 2 SbCl3(s) → Sb4O5Cl2(s)
Therefore, the coefficient of antimony(III) oxide is 4.
If you combine 370.0 mL of water at 25.00 °C and 110.0 mL of water at 95.00 °C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water.
The final temperature of a mixture of two volumes of water at different temperatures can be found using the principle of heat transfer. The heat lost by the hotter water will be equal to the heat gained by the cooler water. The final temperature is computed using the formula for heat, q = mcΔT.
Explanation:The exercise in question involves the concept of heat transfer, a fundamental concept in Physics. When two bodies of different temperatures are combined, the heat will flow from the hotter to the cooler body until thermal equilibrium is reached, and both bodies have the same temperature.
Using the principle of heat transfer, we consider that the heat lost by the hotter water will be equal to the heat gained by the cooler water. The formula for heat is q = mcΔT where m is mass, c is specific heat, and ΔT is the change in temperature. Using the density of water as 1 g/mL, we calculate the mass of both volumes of water (370.0 g for the cooler water and 110.0 g for the hotter water). The specific heat of water is 4.184 J/g °C. With this, we set up the equation (370.0 g * 4.184 J/g °C * (Tfinal - 25.00 °C)) = (110.0 g * 4.184 J/g °C * (95.00 °C - Tfinal)), and solve for Tfinal, which represents the final temperature of the mixture.
Learn more about Heat Transfer here:https://brainly.com/question/13433948
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What is the percent yield if the actual yield is 25 g and 100 g should have formed?
It is 25%. 25g ÷ 100g × 100% = 25%
An ion is created when __________ are added or removed. A. protons B. neutrons C. electrons D. protons and neutrons
C. electrons
An ion is formed when electrons are gained or lost.
Which of the following is a property of an ionic compound?
A.low boiling point
B.low melting point
C.high melting point
C, ionic compounds have high boiling and melting points as the bonds are very strong and require tons of energy to break.
Answer:
C. High Melting PointExplanation:
I just did this question on my quiz and C was correct.
Which of these substances has the lowest pH? 0.5 M HBr, pOH = 13.5 0.05 M HCl, pOH = 12.7 0.005 M KOH, pOH = 2.3
0.5 M HBr, pOH = 13.5 ; Has the lowest pH
Explanation;From the question;
pH = -Log [OH]
or pH = 14 - pOH
Therefore;
For 0.5 M HBr
[H+] = 0.5 M
pH = - Log [0.5]
= 0.30
For; pOH = 13.5
pH = 14 - pOH
= 14 -13.5
= 0.5
For; 0.05 M HCl
pH = - log [H+]
[H+] = 0.05
pH = - Log [0.05]
= 1.30
For; pOH = 12.7
pH = 14 -pOH
= 14 -12.7
= 1.30
For; 0.005 M KOH,
pOH = - log [OH]
[OH-] = 0.005
pOH = - Log 0.005
= 2.30
pH = 14 - 2.30
= 11.7
For; pOH = 2.3
pH = 14 -pOH
= 14- 2.3
= 11.7
Answer:
solution A, pOH = 1.5
0.5 M HBr, pOH = 13.5
Explanation:
I got it correct on e d g e n u i t y
Have a good day :D