How many days does it take for mercury to orbit the sun

Answers

Answer 1

It takes approximately 88 Earth days for Mercury to orbit the sun.

Hope I helped, sorry if I'm wrong ouo.

~Potato

Copyright Potato 2019.

Answer 2

Answer:

87.96926 Days =88 days

Explanation:

Average speed 105,947 miles per hour.


Related Questions

The reflective quality of a surface is known as its

Answers

Answer: Albedo

The albedo is an amount that expresses the percentage of radiation a surface reflects with respect to the incident radiation.

In other words:

This amount allows us to know the level of radiation that reflects a surface compared to the total radiation it receives.

According to this, light surfaces such as snow covered ground or white sand will have a higher albedo than dark surfaces such as carbon covered ground. It is also important to note, the albedo will be higher on glossy surfaces than on matte surfaces.

It should be noted that the albedo of the Earth is on average about [tex]37\%[/tex], which means that part of the radiation received by the Sun is absorbed and another part reflected back to space.

Watt which is a unit of power is equal to

Answers

Answer:

A joule divided by a second

Explanation:

i googled it m8 wasnt that hard to find

Answer:   a joule divided by a second

Explanation:

A horizontal spring has one end firmly attached to a wall and the other end attached to a mass. The mass can slide freely on a smooth, horizontal surface with no friction. The mass is pulled away from the equilibrium position by a distance A in the positive x-direction and then released so that it oscillates in simple harmonic motion with frequency f. What will happen to the frequency of the oscillation if the mass is doubled?

Answers

Explanation:

The frequency of a spring is:

f = 1/(2pi) sqrt(k / m)

If m doubles, then f decreases by a factor of 1/sqrt(2).

Final answer:

Doubling the mass attached to a spring in a frictionless simple harmonic oscillator will decrease the frequency of oscillation by a factor of √2, or approximately 0.7071 times the original frequency.

Explanation:

In a simple harmonic oscillator like the mass-spring system described, the frequency of oscillation is given by f = (1/2π) * √(k/m), where k represents the spring constant and m the mass attached to the spring. If the mass is doubled, the frequency of the oscillation will decrease because the frequency is inversely proportional to the square root of the mass. Therefore, if the mass increases by a factor of two, the new frequency will be f' = (1/2π) * √(k/2m), which is f' = f/√2. This implies that the frequency will decrease by a factor of √2, or approximately 0.7071 times the original frequency.

Two forces produce equal torques on a door about the door hinge. The first force is at the midpoint of the door; the second force is applied at the doorknob. Both fortes are applied perpendicular to the door. Which force has a greater magnitude?

the first force (at the midpoint).
the second force (at the doorknob).
the two forces are equal.

Answers

Answer:

The force at the midpoint of the door.

Explanation:

The torque produced in the door will be:

              T = rFsinθ

Here θ = 90 degrees so,

               T = rF  

At the midpoint of the door the moment arm is half than that of doorknob. So, to produce same torque we have to apply two times force at the midpoint of the door than the force at doorknob.

Final answer:

The correct option is a.

In Physics, the concept of torque shows that the first force at the midpoint of the door has a greater magnitude than the second force at the doorknob, given that the torques are equal and distances from the door h-inge for both forces are different.

Explanation:

In the context of torque, the force that one applies on a door at different points creates differing results because of the concept of lever arm. Torque is calculated by multiplying the force applied by the distance from the pivot point, which in this case is the door h-inge. Therefore, if the torques are equal as proposed in the question and the distance for the second force (at the doorknob) from the h-inge is greater than the first force (at the midpoint), it must mean that the magnitude of the second force is less than the first for the torques to be equal. Thus, the first force (at the midpoint) has a greater magnitude.

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Why is it important to have a control setup in an experiment?

Answers

Explanation:

A control is important for an experiment because it allows the experiment to minimize the changes in all other variables except the one being tested.

A sample of gas initially has a volume of 859 ml at 565 k and 2.20 atm. What pressure will the sample have if the volume changes to 268 ml while the temperature is increased to 815 k?

Answers

Answer:

10.2 atm

Explanation:

Use ideal gas law:

PV = nRT

Initial number of moles is:

(2.20 atm) (0.859 L) = n (0.0821 atm L / mol / K) (565 K)

n = 0.0407 mol

At the new volume and temperature, the pressure is:

P (0.268 L) = (0.0407 mol) (0.0821 atm L / mol / K) (815 K)

P = 10.2 atm

We have that the pressure the sample have if the volume changes to 268 ml while the temperature is increased to 815 k is

[tex]P_2=10atm[/tex]

From the question we are told

A sample of gas initially has a volume of 859 ml at 565 k and 2.20 atm. What pressure will the sample have if the volume changes to 268 ml while the temperature is increased to 815 k

Generally the equation for the ideal gas   is mathematically given as

PV=nRT

Where

[tex]\frac{P1V1}{T1}=\frac{P2V2}{T2}[/tex]

Therefore

[tex]P_2=\frac{P1V1T2}{V2T1}\\\\P_2=\frac{2.20*859*815}{268*565}[/tex]

[tex]P_2=10atm[/tex]

THEREFORE

the pressure the sample have if the volume changes to 268 ml while the temperature is increased to 815 k is

[tex]P_2=10atm[/tex]

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What type of electron is available to form bonds?

Answers

Answer:

Valence electrons

Explanation:

The valence electrons are found in the outermost shell of an atom. They are the most loosely held electrons found within an atom. These valence electrons are involved and are used to form bonds when atoms combines together.

The energy required to remove these loosely held electrons is relatively low compared to electrons located in the inner orbitals. This is why when atoms combines, they use the outermost electrons to form bonds and mimic stable atoms like those of the noble gases.

Final answer:

Valence electrons are those in the outermost shell of an atom; they are used to form bonds such as ionic and covalent bonds to achieve stable electron configurations. Atoms generally follow the octet rule where they seek eight valence electrons, although there are exceptions like hydrogen and transition elements.

Explanation:

The type of electron that is available to form bonds is known as the valence electron. Valence electrons are those electrons found in the outermost shell of an atom and are critical in determining how an atom will chemically interact with other atoms. Typically, atoms will form bonds to achieve a stable electron configuration, often striving to have eight valence electrons, following the octet rule. However, there are exceptions such as hydrogen, which only requires two electrons to fill its valence shell, and transition elements that do not always follow the octet rule due to their d and f electrons.

There are two main types of bonds that involve valence electrons: ionic bonds and covalent bonds. Ionic bonds occur when electrons are transferred from one atom to another, creating ions that are held together by electrostatic forces. Covalent bonds occur when electrons are shared between atoms, which can be envisioned as electron density located in space-symmetric wave functions between the nuclei of the bonded atoms.

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The strength of the electric field at a certain distance from a point charge is represented by E. What is the strength of the electric field at twice the distance from the point charge?

a.) At twice the distance, the strength of the field is E/2.
b.) At twice the distance, the strength of the field is 2E.
c.)At twice the distance, the strength of the field is 4E.
d.)At twice the distance, the strength of the field remains equal to E.
e.)At twice the distance, the strength of the field is E/4.

Answers

Answer:

e.)At twice the distance, the strength of the field is E/4.

Explanation:

The strength of the electric field at a certain distance from a point charge is given by:

[tex]E=k\frac{Q}{r^2}[/tex]

where

k is the Coulomb's constant

Q is the charge

r is the distance from the point charge

In this problem, the distance from the point charge is doubled:

r' = 2r

So the new electric field strength is

[tex]E'=k\frac{Q}{(2r)^2}=k \frac{Q}{4 r^2}=\frac{1}{4} (k\frac{Q}{r^2})=\frac{E}{4}[/tex]

so, at twice the distance the strength of the field is E/4.

Final answer:

The strength of the electric field at twice the distance from a point charge is one-fourth of its original strength. So the correct option is (e).

Explanation:

The strength of the electric field at a certain distance from a point charge is generally given by the formula E = k|Q|/r², where k is Coulomb's constant, Q is the magnitude of the charge, and r is the distance from the charge to the point in question. When the distance is doubled (2r), the formula becomes E' = k|Q|/(2r)², which simplifies to E' = E/4. Therefore, the strength of the electric field at twice the distance from the point charge is one-fourth the original strength.

The binding energy of a nucleus can be found using

Answers

Answer:

converting that mass to energy by using E=mc2. Mass must be in units of kg. Once this energy, which is a quantity of joules for one nucleus, is known, it can be scaled into per-nucleon and per-mole quantities.

Explanation:

Answer:

An elephants balls

Explanation:

which of the following represents thermal energy transfer through radiation
A)a thermometer sitting on top of a heat lamp
B)a person trying to unscrew a hot light bulb
C)a child sitting in front of a space heater
D)swimming in the pool and noticing that the deeper end of the pool is colder than the shallow end

Answers

C. since the the heat from the heater is going to the child in waves, it’s radiating

The transfer of thermal energy through radiation is exemplified by a thermometer sitting on top of a heat lamp, representing energy transferred through electromagnetic waves without direct contact.

The answer which represents thermal energy transfer through radiation is A) a thermometer sitting on top of a heat lamp. This is because radiation is a method of heat transfer that does not rely on any contact between the heat source and the heated object, as in the case of a thermometer receiving infrared radiation from a heat lamp.

Radiation is the transfer of energy by electromagnetic waves, and it can occur even through a vacuum. For example, the glow of the sun or a candle flame is heat transfer by radiation; the energy is transferred in the form of visible light and other electromagnetic waves. The amount of power radiated is proportional to the surface area of the radiating object and increases significantly with the absolute temperature of the object, adhering to the relationship P ≈ T4, where P represents the radiated power and T is the absolute temperature in Kelvin.

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a soccer ball sits still on the ground until someone applies a force by kicking it. this scenario is best described by which law of motion?

Answers

Answer:

Newton’s first law

Explanation:

An object at rest will stay at rest until moved on by a different object. And a object at motion will stay in motion until acted on by another object. There technically could be 2 that apply because the force could be Newton’s second law. Hope this helped :)

Final answer:

Newton's First Law of Motion, which states that a body at rest remains at rest unless acted upon by an external force, best describes the scenario of a stationary soccer ball being kicked into motion.

Explanation:

The scenario described in the question, where a soccer ball remains still until it is kicked, is best explained by Newton's First Law of Motion. This law, also sometimes referred to as the law of inertia, states that a body at rest will remain at rest unless acted upon by a net external force. In the case of the soccer ball, it remains stationary until the soccer player applies a force with their foot. Additionally, once in motion, the ball continues to move and only stops or changes direction due to external forces like gravity, air friction, or being caught by a goalkeeper. These forces are considered external as they are not part of the ball's internal structure.

The escape speed from Planet X is 20,000 m/s. Planet Y has the same radius as Planet X but is twice as dense. What is the escape speed from Planet Y?

Answers

Answer:

the escape speed from planet Y is [tex]\sqrt{2}[/tex] times the escape speed from planet X.

Explanation:

The escape speed from a surface of a planet is given by:

[tex]v=\sqrt{\frac{GM}{R}}[/tex]

where

G is the gravitational constant

M is the mass of the planet

R is the radius of the planet

Let's call M the mass of planet X and R its radius. So the speed

[tex]v_x=\sqrt{\frac{GM}{R}}[/tex]

corresponds to the escape speed from planet X.

Now we now that planet Y has:

- same radius of planet X: R' = R

- twice the density of planet X: d' = 2d

The mass of planet Y is given by

[tex]M' = d' V'[/tex]

where V' is the volume of the planet. However, since the two planets have same radius, they also have same volume, so we can write

[tex]M' = d' V= (2d)V = 2M[/tex]

which means that planet Y has twice the mass of planet X. So, the escape speed of planet Y is

[tex]v'=\sqrt{\frac{GM'}{R}}=\sqrt{\frac{G(2M)}{R}}=\sqrt{2}(\sqrt{\frac{GM}{R}})=\sqrt{2} v[/tex]

so, the escape speed from planet Y is [tex]\sqrt{2}[/tex] times the escape speed from planet X.

Final answer:

The escape speed from Planet Y, which has the same radius but twice the density as Planet X, would be approximately 28,300 m/s.

Explanation:

The escape speed, or escape velocity, from a planet is dependent on the mass and the radius of the planet, and it's calculated using the formula:

v = sqrt((2*G*M)/R)

Where v is the escape speed, G is the gravitational constant, M is the mass of the planet, and R is the radius of the planet. If Planet Y has the same radius as Planet X but is twice as dense, its mass will be twice that of Planet X because mass is density times volume. Thus, the escape speed from Planet Y will be sqrt(2) or approximately 1.414 times the escape speed from Planet X. So, v_Y = 1.414 * 20,000 m/s, or about 28,300 m/s.

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The definition of parallel lines requires the undefined terms line and plane

Answers

Answer:

True

Explanation:

Answer:

Parallel lines never intersect, but they must be in the same plane. The definition does not require the undefined term point, but it does require plane. Because they intersect, perpendicular lines must be coplanar; consequently, plane is not required in the definition.

What did you include in your response? Check all that apply.

Parallel lines do not intersect.

Parallel lines must be coplanar.

Perpendicular lines intersect at one point.

Perpendicular lines intersect  so plane is not required in the definition.

Determine the wavelength of light having energy of 2.25 × 10−19 j.

Answers

Answer:

[tex]8.84\cdot 10^{-7} m[/tex]

Explanation:

The energy a single photon of an electromagnetic wave is given by

[tex]E=\frac{hc}{\lambda}[/tex]

where

h is the Planck constant

c is the speed of light

[tex]\lambda[/tex] is the wavelength of the photon

In this problem, we have

[tex]E=2.25\cdot 10^{-19} J[/tex] is the energy of the photon

So we can re-arrange the equation to find the wavelength:

[tex]\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{2.25\cdot 10^{-19} J}=8.84\cdot 10^{-7} m[/tex]

please help on this one?

Answers

Answer:

A

Explanation:

a cell phone tower provides 1e+13 waves per second

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By what mechanism is a person injured when he or she falls from a significant height? Select one: a. Kinetic energy is converted to potential energy; the potential energy is then converted into the work of bringing the body to a stop. b. As the person falls, the amount of kinetic energy is converted into work; work is then converted to kinetic energy upon impact. c. Potential energy is created as the person is falling; the potential energy is then converted into kinetic energy upon impact. d. Potential energy is converted to kinetic energy; the kinetic energy is then converted into the work of bringing the body to a stop.

Answers

Answer:

d. Potential energy is converted to kinetic energy; the kinetic energy is then converted into the work of bringing the body to a stop

Explanation:

- When the person starts his/her fall from a certain height h, he/she possesses gravitational potential energy:

[tex]U=mgh[/tex]

where m is the mass of the person, g is the acceleration due to gravity, h is the height.

- During the fall, the height h decreases, while the speed of the person increases, so gravitational potential energy is converted into kinetic energy:

[tex]K=\frac{1}{2}mv^2[/tex]

where

m is the mass of the person

v is the speed

- Just a moment before hitting the ground, h=0, so all the potential energy has been converted into kinetic energy

- When the person hits the ground, he/she comes a stop: this means that now the speed is zero (v=0), so the kinetic energy is zero as well. This occurs because all the kinetic energy has been converted into the work of bringing the body to a stop. (the work has been done by the ground on the person)

What is the process of evaporation through plant leaves called

Answers

Answer: Transpiration

Vegetal transpiration is the loss of water in the form of vapor, in the plant through its different parts, especially its leaves.

In this process, soil water is absorbed by the roots of the plant and transported in liquid form to the leaves to be converted into water vapor, while a part is used in photosynthesis. That is why vegetal transpiration is considered a vital function in the photosynthesis process.

This is possible because the leaves have small pores that allow water to escape into the atmosphere in the form of vapor and absorb carbon dioxide. Then, most of the water in the plants is used in the process of transpiration and only a small percentage is retained in liquid state and used for its growth and storage.

A car of 1000 kg with good tires on a dry road can decelerate (slow down) at a steady rate of about 5.0 m/s2 when braking. If a car is initially traveling at 20 m/s (45 mi/h), (a) How much time does it take the car to stop? (b) What is its stopping distance? (c) What is the deacceleration? (d) How big is the net force to be applied to stop this car? (e) Calculate the work done by this force (Work = Force * distance). (f) During the stopping process, what happens to the car's kinetic energy?

Answers

(a) 4.0 s

The acceleration of the car is given by

[tex]a=\frac{v-u}{t}[/tex]

where

v is the final velocity

u is the initial velocity

t is the time interval

For this car, we have

v = 0 (the final speed is zero since the car comes to a stop)

u = 20 m/s is the initial velocity

[tex]a=-5.0 m/s^2[/tex] is the deceleration of the car

Solving the equation for t, we find the time needed to stop the car:

[tex]t=\frac{v-u}{a}=\frac{0-(20 m/s)}{-5.0 m/s^2}=4 s[/tex]

(b) 40 m

The stopping distance of the car can be calculated by using the equation

[tex]v^2 - u^2 = 2ad[/tex]

where

v = 0 is the final velocity

u = 20 m/s is the initial velocity

a = -5.0 m/s^2 is the acceleration of the car

d is the stopping distance

Solving the equation for d, we find

[tex]d=\frac{v^2-u^2}{2a}=\frac{0^2-(20 m/s)^2}{2(-5.0 m/s^2)}=40 m[/tex]

(c) [tex]-5.0 m/s^2[/tex]

The deceleration is given by the problem, and its value is [tex]-5.0 m/s^2[/tex].

(d) 5000 N

The net force applied on the car is given by

[tex]F=ma[/tex]

where

m is the mass of the car

a is the magnitude of the acceleration

For this car, we have

m = 1000 kg is the mass

[tex]a=5.0 m/s^2[/tex] is the magnitude of the acceleration

Solving the formula, we find

[tex]F=(1000 kg)(5.0 m/s^2)=5000 N[/tex]

(e) [tex]2.0\cdot 10^5 J[/tex]

The work done by the force applied by the car is

[tex]W=Fd[/tex]

where

F is the force applied

d is the total distance covered

Here we have

F = 5000 N

d = 40 m (stopping distance)

So, the work done is

[tex]W=(5000 N)(40 m)=2.0\cdot 10^5 J[/tex]

(f) The kinetic energy is converted into thermal energy

Explanation:

when the breaks are applied, the wheels stop rotating. The car slows down, as a result of the frictional forces between the brakes and the tires and between the tires and the road. Due to the presence of these frictional forces, the kinetic energy is converted into thermal energy/heat, until the kinetic energy of the car becomes zero (this occurs when the car comes to a stop, when v = 0).

Unpolarized light passes through two polarizers whose transmission axes are at an angle of 30.0 degrees with respect to each other. What fraction of the incident intensity is transmitted through the polarizers?a.) 0.750b.) 0.866c.) 0.375d.) 0.627

Answers

Answer:

a) 0.750

Explanation:

When the unpolarized light passes through the first polarizer, it becomes polarized along the axis of transmission of the polarizer itself.

Then, the light passes through the second polarizer, whose axis of transmission is inclined by an angle [tex]\theta[/tex] with respect to the direction of polarization of the light.

Calling [tex]I_0[/tex] the initial intensity of the light, the intensity of light passing through the second filter is

[tex]I=I_0 cos^2 \theta[/tex]

where

[tex]\theta=30^{\circ}[/tex]

Solving the formula for [tex]\frac{I}{I_0}[/tex], which is the fraction of the incident intensity transmitted through the second polarizer, we find

[tex]\frac{I}{I_0}=cos^2 \theta = cos^2 30^{\circ}=0.750[/tex]

Final answer:

When unpolarized light passes through two polarizers whose transmission axes are at an angle of 30.0 degrees with respect to each other, the fraction of the incident intensity transmitted through the polarizers is 0.75.

Explanation:

When unpolarized light passes through two polarizers whose transmission axes are at an angle of 30.0 degrees with respect to each other, the fraction of the incident intensity transmitted through the polarizers can be calculated using Malus' Law.

Malus' Law states that the intensity of the transmitted light is equal to the initial intensity multiplied by the square of the cosine of the angle between the transmission axes of the polarizers.

In this case, the angle between the transmission axes is 30.0 degrees, so the fraction of the incident intensity transmitted through the polarizers is (cos(30.0))² = 0.75.

By what mechanism is a person injured when he or she falls from a significant height? Select one: a. Kinetic energy is converted to potential energy; the potential energy is then converted into the work of bringing the body to a stop. b. As the person falls, the amount of kinetic energy is converted into work; work is then converted to kinetic energy upon impact. c. Potential energy is created as the person is falling; the potential energy is then converted into kinetic energy upon impact. d. Potential energy is converted to kinetic energy; the kinetic energy is then converted into the work of bringing the body to a stop.

Answers

Answer:

d. Potential energy is converted to kinetic energy; the kinetic energy is then converted into the work of bringing the body to a stop.

Explanation:

- At the beginning of the falls, when the person is still at a certain height h, the person has gravitational potential energy:

U = mgh

where m is the mass of the person, g the acceleration due to gravity, h the height above the ground.

- As the person falls down, h decreases, so the potential energy decreases; according to the law of conservation of energy, potential energy is converted into kinetic energy, since the speed of the person increases:

[tex]K=\frac{1}{2}mv^2[/tex]

where v is the speed.

- Just before hitting the ground, all the potential energy has been converted into kinetic energy

- When the person hits the ground, he/she comes to a stop: so work is done by the ground on the person, because the ground applied a force required to stop the person, and the kinetic energy "lost" by the person is equal to the work done by the ground to bring the body to a stop.

Two Physics quick help

Answers

Answer:

21.3 V, 1.2 A

Explanation:

1.

These resistors are in series, so the net resistance is:

R = R₁ + R₂ + R₃

R = 20 + 30 + 45

R = 95

So the current is:

V = IR

45 = I (95)

I = 9/19

So the voltage drop across R₃ is:

V = IR

V = (9/19) (45)

V ≈ 21.3 V

2.

First, we need to find the equivalent resistance of R₂ and R₃, which are in parallel:

1/R₂₃ = 1/R₂ + 1/R₃

1/R₂₃ = 1/10 + 1/10

R₂₃ = 5

Now we find the overall resistance by adding the resistors in series:

R = R₁ + R₂₃ + R₄

R = 10 + 5 + 10

R = 25

So the current through R₁ is:

V = IR

30 = I (25)

I = 1.2 A

During a phase change, the temperature of a substance _____.

A)decreases


B)increases


C)stays the same

Answers

During a phase change, the temperature of a substance (c). stays the same.

The temperature remains same during the phase change.

Answer: Option C

Explanation:

The term “change of phase” is similar to “change of state”. When there is a change of substance from a state to the other state or phase, it is known as changes in its state. This change of state occurs due to the change of heat.

When a substance changes the phase, either the heat comes out or goes in the substance. Although there occur a change in the content of heat present in the substance, the temperature will not change. It remains constant.  When ice melts it becomes water and the water vaporizes which becomes water vapour.

A Carnot Engine operates between a hot reservoir temperature of 215 degrees C and a cold reservoir temperature of 20 degrees C. If the engine draws 1000 J from the hot reservoir per cycle, how much work will it do per cycle?

a, 1000 J
b, 100 J
c, 400 J
d, 600 J
e, 900 J

Answers

Answer:

c. 400 J

Explanation:

The efficiency of a Carnot Engine is given by:

[tex]\eta = 1 - \frac{T_C}{T_H}[/tex]

where in this case we have

[tex]T_C = 20^{\circ} +273 =293 K[/tex] is the temperature of the cold reservoir

[tex]T_H = 215^{\circ} +273 =488 K[/tex] is the temperature of the hot reservoir

Substituting into the equation,

[tex]\eta = 1 - \frac{293 K}{488 K}=0.40[/tex]

But the efficiency can also be written as

[tex]\eta = \frac{W_{out}}{Q_{in}}[/tex]

where

[tex]W_{out}[/tex] is the useful work in output

[tex]Q_{in}[/tex] is the heat absorbed by the hot reservoir

Here,

[tex]Q_{in} = 1000 J[/tex]

So solving the formula for [tex]W_{out}[/tex] we find

[tex]W_{out} = \eta Q_{in} = (0.40)(1000 J)=400 J[/tex]

Final answer:

The Carnot Engine absorbs 1000 Joules from the hot reservoir and has an efficiency of 0.4. The work done by the engine per cycle is the product of the absorbed heat and the efficiency, which equates to 400 Joules.

Explanation:

The efficiency of a Carnot Engine is determined by the temperatures of the hot and cold reservoirs. Specifically, efficiency (η) = 1 - (Tc/Th), where Tc is the temperature of the cold reservoir and Th is the temperature of the hot reservoir. Note that these temperatures must be in Kelvin for the formula to work properly.

In this case, we need to convert the temperatures from degrees Celsius to Kelvin: Th = 215°C + 273.15 = 488.15 K and Tc = 20°C + 273.15 = 293.15 K. We then substitute these values into the formula to get the efficiency: η = 1 - (293.15 K /488.15 K) ≈ 0.4

The work done by the engine (W) is the product of the heat (Q) absorbed from the hot reservoir and the efficiency: W = η x Q. Substituting the given heat of 1000 Joules and the calculated efficiency, we get W = 0.4 x 1000 Joules = 400 Joules. Therefore, the amount of work done per cycle by the engine is 400 Joules (Option c).

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A car traveling along the highway needs a certain amount of force exerted on it to stop it in a
certain distance. More stopping force is required when the car has
A) more mass.
B) more momentum.
C) less stopping distance.
D) all of these
E) none of these

Answers

A car traveling along the highway needs a certain amount of force exerted on it to stop it in a  certain distance.

More stopping force is required when the car has  more mass, or more momentum, or less stopping distance.  (D)

Answer:

More stopping force is required when the car has D) all of these.

Explanation:

Let's explain some equations and concepts in order to answer the question:

The second law of Newton states that a force exerted on an object is directly proportional to the mass of the object and the acceleration of the object. Mathematically, we can write the following equation :

[tex][/tex]

[tex]F=m.a[/tex] (I)

Where ''F'' is the force

Where ''m'' is the mass

And where ''a'' is the acceleration.

Now, we can define the momentum as :

[tex]p=m.v[/tex] (II)

The momentum ''p'' is a vector magnitude.

''m'' is the mass of the object

And ''v'' is the velocity vector.

Finally, let's explain the following motion equation :

[tex]Vf=Vi-a.t[/tex] (III)

Vf is final speed

Vi is initial speed

''a'' is the acceleration of the object.

Notice that we write a ''-'' in the ''a.t'' term because we assume that the object is stopping. Therefore, its acceleration is negative. ''t'' is the time in which the object will stop.

Let's proceed analyzing each option :

A) more mass

If the car has more mass, therefore by looking at the equation (I), the stopping force will be greater.

B) more momentum

By looking the equation (II), if the car has more momentum therefore it has more mass or more speed (or both).

If it has more mass the stopping force required must be greater.

Otherwise, if it has more speed, by looking at the equation (III) and assuming that Vf = 0 (because we need the car to stop)

[tex]0=Vi-a.t[/tex]

[tex]Vi=a.t[/tex]

If  [tex]Vi[/tex] is greater and assuming that time must be the same, therefore the acceleration will be greater. So, if acceleration increases, the stopping force increases (looking at equation (I) ).

Finally, C) less stopping distance

If the car has less stopping distance, therefore the magnitude of the acceleration vector must be greater (in order to stop the car faster). By looking the equation (I) we conclude that the stopping force will be greater.

The correct option is D) all of these

A Ping-Pong ball moving East at a speed of 4 m/s collides with a stationary bowling ball. The Ping-Pong ball bounces back to the West, and the bowling ball moves very slowly to the East. Which object experiences the greater magnitude impulse during the collision?

Answers

Answer:

They experience the same magnitude impulse

Explanation:

We have a ping-pong ball colliding with a stationary bowling ball. According to the law of conservation of momentum, we have that the total momentum before and after the collision must be conserved:

[tex]p_i = p_f\\p_p + p_b = p'_p+p'_b[/tex]

where

[tex]p_p[/tex] is the initial momentum of the ping-poll ball

[tex]p_b[/tex] is the initial momentum of the bowling ball (which is zero, since the ball is stationary)

[tex]p'_p[/tex] is the final momentum of the ping-poll ball

[tex]p'_f[/tex] is the final momentum of the bowling ball

We can re-arrange the equation as follows

[tex]p_p - p'_p = p_b'-p_b[/tex]

or

[tex]-\Delta p_p = \Delta p_b[/tex]

which means

[tex]|\Delta p_p | = |\Delta p_b|[/tex] (1)

so the magnitude of the change in momentum of the ping-pong ball is equal to the magnitude of the change in momentum of the bowling ball.

However, we also know that the magnitude of the impulse on an object is equal to the change of momentum of the object:

[tex]I=\Delta p[/tex] (2)

Therefore, (1)+(2) tells us that the ping-pong ball and the bowling ball experiences the same magnitude impulse:

[tex]|I_p| = |I_b|[/tex]

1. Provide one example of an area with high ecosystem diversity and one example of an area with low ecosystem diversity.

Answers

Explanation:

An example of a high ecosystem diversity is a rainforest or seashore.

An example of a low ecosystem diversity is a desert or farmland.

The rainforests are considered as an example of high ecosystem diversity and on the other hand, typical deserts and farmlands are considered as low ecosystem diversity.

What is an ecosystem?

A geographical area where one can observe plants, animals, and other living organisms to reside, forming a part of a complete landscape, is known as an ecosystem.

An example of a high ecosystem diversity is a rainforest or seashore. As one in the Amazon basin in South America, rainforests provide varieties of biodiversity like coral reefs, species of snakes, fishes, monkeys, and many others.

An example of a low ecosystem diversity is a desert or farmland. These parts of land generally have only two to three varieties of grasses, some dandelion flowers, and few inhabitants.

Thus, we can conclude that the rainforests are considered as an example of high ecosystem diversity and on the other hand typical deserts and farmlands are considered as low ecosystem diversity.

Learn more about the ecosystem here:

https://brainly.com/question/1673533

What is the name for the imaginary parallel lines that run east to west around the world and never meet?

Answers

Answer: Latitude (Parallels)

Actually, latitude is defined as the angular distance between the equatorial line and a specific point on the Earth. Dividing the planet in the northern hemisphere and the southern hemisphere, depending on the location of the geographical point with respect to the equator.

Now, imaginary horizontal lines that never touch (that is why they are parallel) that travel across the Earth globe from East to West, forming circles that become smaller and smaller as they get closer to the poles, are called parallels. Where the equator line is known as parallel [tex]0\°[/tex], and the degrees of latitude reach up to [tex]90\°[/tex]North or [tex]90\°[/tex]South.

So, the parallels allow us to determine the latitude of a point, in other words, they help to know if the position of a point is North or South of the Equator's parallel.

Check all that apply. The magnetic force on the current-carrying wire is strongest when the current is parallel to the magnetic field lines. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current. The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.

Answers

Answer:

The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.

The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.

The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.

Explanation:

The magnitude of the magnetic force exerted on a current-carrying wire due to a magnetic field is given by

[tex]F=ILB sin \theta[/tex] (1)

where I is the current, L the length of the wire, B the strength of the magnetic field, [tex]\theta[/tex] the angle between the direction of the field and the direction of the current.

Also, B, I and F in the formula are all perpendicular to each other. (2)

According to eq.(1), we see that the statement:

"The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines."

is correct, because when the current is perpendicular to the magnetic field, [tex]\theta=90^{\circ}, sin \theta = 1[/tex] and the force is maximum.

Moreover, according to (2), we also see that the statements

"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field. "

"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current. "

because F (the force) is perpendicular to both the magnetic field and the current.

Final answer:

The magnetic force on a current-carrying wire in a uniform magnetic field is perpendicular to both the magnetic field lines and the direction of the current. The force is strongest when the current is perpendicular to the magnetic field lines, and is zero when the current runs parallel to the magnetic field lines.

Explanation:

According to the principles of magnetism and the right-hand rule, the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to both the magnetic field and to the current direction. The strength of the magnetic force on the wire is dictated by the equation F = I x B, where F is the force, I represents the current, and B is the strength of the magnetic field.

When the current flows parallel to the magnetic field lines, the force experienced by the wire is actually zero due to the nature of the cross product in the force formula. However, the magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines. This is because the effect of the magnetic force is most significant when these two quantities are at right angles to each other.

In terms of the direction of the force, you can use the right-hand rule. If you point your thumb in the direction of the current, and your fingers in the direction of the magnetic field, your palm will point in the direction of the force on the wire.

Learn more about Magnetic Force on Current-Carrying Wire here:

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A step up transformer used on a 120v line has 95 turns on the primary and 2850 turns on the secondary.what is the emf across the secondary

Answers

Answer:

3600 V

Explanation:

The transformer equation states that:

[tex]\frac{V_p}{N_p}=\frac{V_s}{N_s}[/tex]

where

[tex]V_p = 120 V[/tex] is the voltage in the primary coil

[tex]N_p = 95[/tex] is the number of turns in the primary coil

[tex]V_s[/tex] is the voltage in the secondary coil

[tex]N_s = 2850[/tex] is the number of turns in the secondary coil

Slving the equation for Vs, we find the emf induced in the secondary coil:

[tex]V_s = \frac{V_p N_s}{N_p}=\frac{(120 V)(2850)}{95}=3600 V[/tex]

A car is traveling at an initial velocity of 25 m/s slows to a stop in 10 seconds. What is the acceleration of the car?

Answers

Answer:

2.5 m/s^2

Explanation:

the formula for acceleration (or the one you use in this case) is a=vf-vi/t

where vf is equal to final velocity, vi is equal to initial velocity, and t is equal to time.

vf= 25 m/s

vi= 0m/s

t=10s       25-0=25, 25/10=2.5 therefore it is 2.5m/s^2

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