The most abundant state of matter in the universe is also the state with the most kinetic energy. That is
Answer: The Answer is Plasma
Explanation:
Answer:
C. Plasma
Explanation:
it was blue he vented
One molecule of glucose makes 30 molecules of atp. how many molecules of glucose are needed to make 300 molecules of atp in aerobic respiration?
Answer:
10
Explanation:
The glucose molecules produce the energy currency ATP by the process of glycolysis. If one molecules of glucose makes 30 molecules of ATP, then 10 glucose molecules are needed to make 300 molecules of ATP in aerobic respiration.
What is glycolysis?Glycolysis is the process of breakdown of glucose to produce the chemical energy in the form of ATP i.e. Adenosine triphosphate. Glycolysis is called the cellular respiration where the oxygen and glucose is consumed to produce ATP and carbon dioxide.
Body stores the chemical energy in the form of glucose, when body needs energy, these glucose molecules are broken down to produce ATP.
If one molecule of ATP produces 30 ATP molecules, then, the number of glucose molecules needed to produce 300 ATP molecules is:
= (300 /30) = 10
Therefore 10 glucose molecules are needed to produce 300 ATP molecules.
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Find the force a 68.5 kg person would experience while standing on the surface of mars. mars has a mass of 6.43 x 10 23 kg and a radius of 3.43 x 10 6 m from its center to the surface.
The ratio of red to blue marbles in a bag 3:2. If there are 18 red marbles. How many blue marbles are in the bag
If the ratio of red to blue marbles in a bag is 3 : 2 . If there are 18 red marbles, then there are 12 marbles in the bag.
What is the percentage of a number?It is the relative value that represents the hundredth part of any number for example 2% of any number represents, 2 multiplied by the 1/100th of that number.
As given in the problem, the ratio of red to blue marbles in a bag is 3:2. If there are 18 red marbles, then we have to find the number of blue marbles,
The number of the blue marbles = 18 × 2 / 3
= 12
Thus, If the ratio of red to blue marbles in a bag is 3 : 2 . If there are 18 red marbles, then there are 12 marbles in the bag.
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A car with a leftward velocity and a rightward acceleration is moving where ?
Which term means to bend the foot upward at the ankle?
Dorsiflexion, as the word suggests, is the action of bending the foot upward at the ankle. In activities like walking, running, or ascending stairs, it is a typical movement. Plantar flexion is the term for the opposite motion.
Explanation:Dorsiflexion is the name given to the process of bending the foot upward at the ankle. This is a typical movement when doing a variety of activities where your foot's position changes in relation to your leg, like walking, running, or ascending stairs. Plantar flexion is the term for the motion that pushes your foot downward in the opposite direction.
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Dorsiflexion refers to bending the foot upward at the ankle. This is one of the two primary movements at the ankle joint, the other being plantar flexion which involves lifting the heel or pointing the toes downward.
Explanation:The term that refers to bending the foot upward at the ankle is called dorsiflexion. This movement is characterized by lifting the front of the foot so that the top of the foot moves toward the anterior leg. Dorsiflexion is one of two primary movements at the ankle joint. The opposite movement to dorsiflexion is plantar flexion, which involves lifting the heel of the foot from the ground or pointing the toes downward. These two movements, dorsiflexion and plantar flexion, are the only movements available at the ankle joint.
Dorsiflexion is the term that means to bend the foot upward at the ankle. It is a movement at the ankle joint where the top of the foot moves towards the anterior leg. This movement is opposite to plantar flexion, which is the bending of the foot downward at the ankle.
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what physical properties of nylon and leather make them good materials to use for shoe laces?
Nearly all physics problems will use the unit m/s squared. Why are the seconds squared?
A typical garden hose has an inner diameter of 5/8". Let's say you connect it to a faucet and the water comes out of the hose with a speed of 7.0 feet per second. If you then put your thumb over the end of the hose so the opening is only a circle 0.25" across, with what speed will the water stream out now?
The speed of the water will be "43.75 ft/sec".
According to the question,
Initially inner diameter,
5/8 inch or 0.052 ftFinal diameter,
0.25 inch or 0.0208 ftBy continuity equation, we get
→ [tex]Area1\times Velocity1=Area2\times Velocity2[/tex]
By substituting the values, we get
→ [tex]pi\times (\frac{0.052}{2} )^2\times 7= pi\times (\frac{0.0208}{2} )^2\times Velocity[/tex]
→ [tex]Velocity = 43.75 \ ft/sec[/tex] (speed)
Thus the above answer is correct.
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While traveling south on an expressway, a car traveling 60 mph (miles per hour) slows down to 30 mph in 12 minutes due to traffic conditions. Calculate the acceleration.
To calculate the car's acceleration, we convert the initial speed of 60 mph to 26.8 m/s and the final speed of 30 mph to 13.4 m/s. Using the acceleration formula (final velocity minus initial velocity divided by time), the acceleration is found to be [tex]-0.0186 m/s^2[/tex] over the 720 seconds (12 minutes), indicating that the car is decelerating.
To calculate the acceleration of the car, we first need to convert the speeds from miles per hour to meters per second (m/s). Since the car slows down, the acceleration will be negative. The initial speed is 60 mph, which is equivalent to 60 imes 1609/3600 m/s or approximately 26.8 m/s. The final speed is 30 mph, which is equivalent to 30 1609/3600 m/s or approximately 13.4 m/s. The time taken to slow down is 12 minutes, which is 12 60 seconds or 720 seconds. Now we use the formula for acceleration, which is a = (v_f - v_i) / t, where v_f is the final velocity, v_i is the initial velocity, and t is the time taken. Thus, the acceleration a is (13.4 m/s - 26.8 m/s) / 720 s = [tex]-0.0186 m/s^2[/tex]. The negative sign indicates that the car is decelerating.
You answer your phone at home several times a day, but it is always a telemarketer. Finally you stop answering it. This is an example of
A. Passive avoidance
B. Extinction
C. Negative reinforcement
D. A variable ratio schedule
Which is a better conductor of thermal energy a plastic foam cup or window glass?
Window glass is a better conductor of thermal energy than a plastic foam cup which acts as a good thermal insulator, slowing down the transfer of heat. The foam cup is better at keeping the heat in, while the window glass allows more heat to pass through.
Explanation:In the comparison between window glass and a plastic foam cup, the better conductor of thermal energy is window glass. Some materials conduct thermal energy faster than others. Materials like glass and metals are generally good heat conductors, whereas materials such as plastic and rubber are poor heat conductors. Plastic foam like polystyrene foam seen in disposable cups is actually a good thermal insulator, meaning it slows down the transfer of heat. As such, it's great for keeping your coffee hot by reducing heat transfer from the coffee to the environment.
On the other hand, window glass, while not as conductive as metals, still conducts heat at a much faster rate than plastic foam. It is therefore less effective as a thermal insulator, which is why you may feel the cold through a window on a chilly day. Window glass is seen as a major region of heat transfer in buildings, as it allows heat to escape from the interior to the exterior.
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How many different values of ml are possible in the 5d sublevel?
Which is the ability to move a joint through its entire range of motion?
What is the total distance between the diving board and the diver's stopping point underwater?
A 72 kg skydiver can be modeled as a rectangular "box" with dimensions 21 cm × 41 cm × 170 cm . if he falls feet first, his drag coefficient is 0.80. part a what is his terminal speed if he falls feet first? use ρ = 1.2 kg/m3 for the density of air at room temperature.
The terminal speed of the skydiver falling feet first is 53.2 m/s.
Explanation:To find the terminal speed of the skydiver, we can use the formula:
vt = sqrt((2 * m * g) / (ρ * A * Cd))
where:
vt is the terminal speedm is the mass of the skydiverg is the acceleration due to gravityρ is the density of airA is the frontal area of the skydiverCd is the drag coefficientUsing the given values, we can plug them into the formula:
vt = sqrt((2 * 72 kg * 9.8 m/s2) / (1.2 kg/m3 * (0.21 m * 0.41 m) * 0.80))
vt = 53.2 m/s
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The terminal speed of a 72 kg skydiver falling feet first is approximately 189.25 m/s. This is calculated using the formula for terminal velocity, with given values for mass, air density, cross-sectional area, and drag coefficient. The cross-sectional area was determined based on the dimensions of the skydiver.
To find the terminal speed ([tex]v_t[/tex]) of the skydiver, we use the formula for terminal velocity:
[tex]v_t[/tex] = √(2mg / ρA[tex]C_d[/tex])
Where:
m = 72 kg (mass of the skydiver)
g = 9.8 m/s² (acceleration due to gravity)
ρ = 1.2 kg/m³ (density of air)
A = 0.041 m² (cross-sectional area in meters squared, which is 0.21 m * 0.41 m)
[tex]C_d[/tex] = 0.80 (drag coefficient)
Putting the values into the formula:
[tex]v_t[/tex] = √((2 * 72 kg * 9.8 m/s²) / (1.2 kg/m³ * 0.041 m² * 0.80))
[tex]v_t[/tex] = √(1411.2 / 0.03936)
[tex]v_t[/tex] = √(35848.78)
[tex]v_t[/tex] ≈ 189.25 m/s
Therefore, the terminal speed of the skydiver falling feet first is approximately 189.25 m/s.
What will be the acceleration of a skydiver when air resistance builds up to 86% of her weight? assume the acceleration due to gravity is 10 m/s 2 . answer in units of m/s 2 ?
The acceleration of a skydiver when air resistance is 86% of her weight is calculated by finding the net force on her (weight minus air resistance), then dividing this by her mass. The result is 1.4 m/s^2, reflecting the balance of forces and the concept of terminal velocity.
Explanation:To calculate the acceleration of a skydiver when the air resistance is 86% of her weight, we must first understand that the net force on the skydiver is her weight minus the force of air resistance. If the air resistance is 86% of the skydiver's weight, then only 14% of her weight is acting downwards. Considering the weight (force) is the mass (m) times the acceleration due to gravity (g), or F=mg. We then have, a = Fnet / m = 0.14 * weight / m = 0.14 * g (as weight = mg).
Given g (acceleration due to gravity) is 10 m/s2, substituting this into our equation gives an acceleration of a = 0.14 * 10 m/s2, which is 1.4 m/s2. Therefore, the acceleration of the skydiver when air resistance builds up to 86% of her weight is 1.4 m/s2.
It's important not only to understand formulae in physics but also the concepts they express. In this situation, that concept is the balance of forces and how they affect an object's movement. In the case of a skydiver, as they fall, air resistance builds up until it equals their weight, causing their acceleration to decrease until they reach a constant velocity, known as 'terminal velocity'.
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i do not know why but the answer is 684 please let me know why. A light with a second-order dark band forms a diffraction angle of 20.0°. The diffraction grating has 200.0 lines per mm.
The wavelength of the light, to the nearest whole number, is nm.
Final answer
The wavelength of the light, to the nearest whole number, is 684 nm.
The formula for the diffraction grating is given by d sin( heta) = m extlambda, where d is the distance between adjacent gratings, heta is the angle of diffraction, m represents the order of the maximum, and extlambda is the wavelength of the light. For a grating with 200.0 lines per mm, the distance d is the inverse of the number of lines per meter, which is 1/(200,000) meters or 5 x 10^-6 m. The given second-order dark band (m=2) forms at a 20.0°(diffraction angle). Using these values in the diffraction grating equation, solving for extlambda yields a wavelength of approximately 684 nm. This can be calculated as follows: 5 x 10^-6 m * sin(20.0°) = 2 extlambda, leading to extlambda approximately equals 684 nm after computation.
If an object is moving at a constant speed in one direction, what is needed to change its speed or direction?
A. a balanced force
B. an unbalanced force
C. a long period of time
D. a short period of time
An unbalanced force is needed to change its speed or direction. So, option B.
What is Newton's first law ?Newton's first law states that, an object will continue its state of rest or uniform motion, unless it is acted upon by an external force.
Here,
The object is said to be moving at a constant speed in one direction. So, a force is required to change the speed or direction of its movement.
Depending upon the mass, an object can be slowed down or accelerated by a force. A force has the power to alter the motion of an object. An object will move differently when subjected to a greater force. In order to experience the same change in motion, a heavier item needs to be subjected to a greater force than a lighter object.
The velocity of an object will alter as a result of unbalanced forces. The object has the ability to alter its speed, direction, or both. An object's velocity changes as a result of unbalanced forces acting on it, which provide a net force.
Hence,
An unbalanced force is needed to change its speed or direction. So, option B.
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In which range is the peak wavelength of a star that is much hotter than the sun most likely to be?
Answer:
D. Ultraviolet light
Explanation:
Edge 2021
What happens to lava as its temperature increases?
Increasing temperature in lava leads to an increase in its thermal energy, causing more vigorous molecular motion and keeping the lava in a liquid state for a longer period. Cooling of the lava involves energy transfer to its surroundings by radiation and conduction, with notable effects such as steam production when lava encounters colder matter.
Explanation:As the temperature of lava increases, the thermal energy content of the lava also increases. This increase in thermal energy causes the vibrational motions within the material to become more vigorous. As a result, when we consider the formation of igneous rock, lava that has a higher temperature will remain in a liquid state for a longer period before it cools and freezes into solid rock. The physical processes associated with a large body of cooling lava involve the transfer of energy through radiation and conduction. Specifically, the rate of energy transfer by radiation from the surface of lava into the surroundings can be calculated using the difference in temperature between the lava's surface, its interior, and the surrounding environment.
The scenario detailed here, with lava cooling from 1200°C in the interior to 450°C at the surface, highlights how heat dissipates from the hotter to the colder areas. The process is analogous to when lava flows into cold ocean water, transferring heat so rapidly that steam is produced. Therefore, as lava temperatures increase, the lava will continue to behave as a hotter substance, capable of transferring high amounts of energy to cooler surrounding areas until an equilibrium is reached.
Imagine standing on a bathroom scale and reading your weight. now lift one foot and read your weight again. does the scale read more, less or the same weight when you are standing on one foot?
Answer:B
Explanation: Because the weight will be greater with one leg lifted up in the air, it will make the weight more.
Which telecommunications device is ideal for communication during natural disasters when regular telecommunication modes might not be functional?
Answer:
satphone
Explanation:
plato users
Answer:
Explanation:
sat phone
common knowledge mate
Which statement is correct? Theories are accepted as true when a single experiment yields similar results to another one. When a scientist finds a new way to test a hypothesis, experimental methods do not change. Theories may be revised over time as information is discovered or technology is developed. When a scientist finds a new way to test a hypothesis, the original theory is made into a law.
Answer:
Theories may be revised over time as information is discovered or technology is developed.
Explanation:
A scientific theory is a set of knowledge related to a particular problem of interest, be it academic or practical. The structure of a theory is formed by the following main elements: problem, evidence, postulates, axioms, questions, hypotheses, predictions, theses, rules and laws. Theory seeks to explain a particular phenomenon or problem of society, so theories can be revised and change as society changes and new technologies and new information are discovered.
A rock is dropped from the top of a building. after 4 seconds it is moving at 40 m/s. what was the acceleration of the rock
- an object is thrown upwards with a speed of 16 m/s. how long does it take it to reach a height of 7.0 m on the way up?
Final answer:
Calculate the time for an object thrown upwards at 16 m/s to reach a height of 7.0 m.The time it takes the object to reach 7.0 m on the way up is approximately 1.63 seconds.
Explanation:
To find the time it takes for the object to reach a height of 7.0 m on the way up:
Identify the known quantities: Initial velocity (u) = 16 m/s, final velocity (v) = 0 m/s (at the top of its flight), acceleration (a) = -9.8 m/s² (acceleration due to gravity).
Use the kinematic equation: v = u + at and solve for time (t).
Calculate the time taken: t = (v - u) / a.
The time it takes the object to reach 7.0 m on the way up is approximately 1.63 seconds.
How do I work these out and what is the answer
The density of a gas is 3.16 g/l at stp. what is the gas?
The gas is chlorine gas
Explanation and solution;Density at STP = 3.16 g per L
1 mole of a gas at STP occupies, 22.4 L
Therefore, it means mass of the gas in 22.4 L that is 1 mol gas will be;
= 3.16 g × 22.4 L
= 70.8 g/mol
≈ 71 g/mol
The identity of the gas would be Chlorine gas, whose molar mass is 71 g/mol
Given the density of the gas at standard temperature and pressure, we can use the molar volume of a gas at STP to determine the molar mass. Using this process, the gas is likely to be Bromine (Br2).
Explanation:The density given is a key factor to determine the gas. Because the question refers to standard temperature and pressure (stp), we can use the known molar volume of a gas at stp, which is 22.4 L/mol. Based on the given density and the molar volume, we can calculate the molar mass of the unknown gas:
Density = Molar mass / molar volume,
so Molar mass = Density x molar volume = 3.16 g/L x 22.4 L/mol = 70.784 g/mol.
Based on common molar masses, this results indicates that the unknown gas is most likely Bromine (Br2), as its molar mass is approximately 79.9 g/mol, the closest common molar mass to 70.784 g/mol.
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A device for training astronauts and jet fighter pilots is designed to rotate the trainee in a horizontal circle of radius 11.0 m .if the force felt by the trainee is 7.80 times her own weight, how fast is she rotating? express your answer in both (a)m/s and (b)rev/s.
The velocity of the trainee is 29 m/s or 0.42 rev/s
Further explanationAcceleration is rate of change of velocity.
[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]
[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]
a = acceleration (m / s²)v = final velocity (m / s)
u = initial velocity (m / s)
t = time taken (s)
d = distance (m)
Centripetal Acceleration of circular motion could be calculated using following formula:
[tex]\large {\boxed {a_s = v^2 / R} }[/tex]
a = centripetal acceleration ( m/s² )
v = velocity ( m/s )
R = radius of circle ( m )
Let us now tackle the problem!
Given:
Radius of horizontal circle = R = 11.0 m
Force Felt by the Trainee = F = 7.80w
Unknown:
Velocity of Rotation = v = ?
Solution:
[tex]F = ma[/tex]
[tex]F = m\frac{v^2}{R}[/tex]
[tex]7.80w = m\frac{v^2}{R}[/tex]
[tex]7.80mg = m\frac{v^2}{R}[/tex]
[tex]7.80g = \frac{v^2}{R}[/tex]
[tex]7.80 \times 9.8 = \frac{v^2}{11.0}[/tex]
[tex]v^2 = 840.84[/tex]
[tex]v \approx 29 ~m/s[/tex]
[tex]\omega = \frac{v}{R}[/tex] → in rad/s
[tex]\omega = \frac{v}{2 \pi R}[/tex] → in rev/s
[tex]\omega = \frac{29}{2 \pi \times 11.0}[/tex]
[tex]\omega \approx 0.42 ~ rev/s[/tex]
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Subject: Physics
Chapter: Circular Motion
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Circular , Ball , Centripetal
The speed of trainee in [tex]{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] is [tex]\boxed{29{\text{ }}{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] and in [tex]{{{\text{rev}}}\mathord{\left/{\vphantom{{{\text{rev}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] is [tex]\boxed{0.42{\text{ }}{{{\text{rev}}}\mathord{\left/{\vphantom{{{\text{rev}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] .
Explanation:
The radius of horizontal circle is [tex]11{\text{ m}}[/tex] .and the force is equal to [tex]7.8[/tex] times the weight of trainee.
Our aim is to obtain the velocity or speed of trainee in both [tex]{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] and [tex]{{{\text{rev}}}\mathord{\left/{\vphantom{{{\text{rev}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] .
The weight of the trainee is calculated as,
[tex]W=mg[/tex]
The force is equal to 7.8 times the weight of trainee and is shown below.
[tex]F=7.8mg[/tex]
The expression for centripetal force is shown below.
[tex]{F_{{\text{centripetal}}}}=\frac{{m{v^2}}}{r}[/tex] ......(1)
The radius of circle is [tex]11{\text{ m}}[/tex] .
The centripetal force is equal to the force exerted by trainee.
So, substitute [tex]7.8mg[/tex] for [tex]{F_{{\text{centripetal}}}}[/tex] and [tex]11[/tex] for [tex]r[/tex] in equation (1) to obtain the value of velocity in [tex]{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] .
[tex]\begin{aligned}7.8mg&=\frac{{m{v^2}}}{{11}}\\7.8g&=\frac{{{v^2}}}{{11}}\\{v^2}&=85.8g\\\end{aligned}[/tex]
The acceleration due to gravity is [tex]9.8{{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}^{\text{2}}}[/tex] .
Now, the velocity is calculated as,
[tex]\begin{gathered}{v^2}=85.8\left({9.8}\right)\\=840.84\\v=\sqrt{840.84}\\=28.99\\\approx29{\text{ }}{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}\\\end{gathered}[/tex]
Therefore, the velocity of trainee in [tex]{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] is approximately [tex]29{\text{ }}{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] .
The expression for angular velocity in [tex]{{{\text{rev}}}\mathord{\left/{\vphantom{{{\text{rev}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] is shown below.
[tex]\begin{aligned}\omega&=\frac{v}{2\pi r}\end{aligned}[/tex] ... (2)
The obtained velocity is [tex]29{\text{ }}{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] , so substitute [tex]29[/tex] for [tex]v[/tex] and [tex]11[/tex] for [tex]r[/tex] in equation (2) to obtain the angular velocity.
[tex]\begin{aligned}\omega&=\frac{29}{2\pi(11)}\\&=0.419\\&\approx0.42\text{ rev/s}\end{aligned}[/tex]
Therefore, the angular velocity in [tex]{{{\text{rev}}}\mathord{\left/{\vphantom{{{\text{rev}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] is [tex]0.42{\text{ }}{{{\text{rev}}}\mathord{\left/{\vphantom{{{\text{rev}}}{\text{s}}}}\right.\kern-\nulldelimiterspace} {\text{s}}}[/tex] .
Thus, the speed of trainee in [tex]{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] is [tex]\boxed{29{\text{ }}{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] and in [tex]{{{\text{rev}}}\mathord{\left/{\vphantom{{{\text{rev}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] is [tex]\boxed{0.42{\text{ }}{{{\text{rev}}}\mathord{\left/{\vphantom{{{\text{rev}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] .
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Answer Details:
Grade: High School
Subject: Physics
Chapter: Circular Motion
Keywords:
Device, astronauts, jet, pilots, rotation, trainee, horizontal, force, weight, fast, m/s, rev/s, tangential, velocity, speed, angular, centripetal.
How was the formation of the outer planets affected by their distance from the sun?
The formation of the outer planets are affected by their distance from the sun with having them to maintain the lighter elements that they are composed of such as the hydrogen and helium, having them far away will also make their planet more cooler as the sun is distant from them.
The formation of the outer planets, like Uranus and Neptune, was affected by their distance from the Sun as they likely formed closer to where Jupiter and Saturn are now. The low density of matter in the disk surrounding the Sun outside the orbit of Saturn made it difficult for Uranus and Neptune to form at their present distances. Computer models show that gravitational interactions with neighboring planets could have caused Uranus and Neptune to move to their current locations.
Explanation:The formation of the outer planets, such as Uranus and Neptune, was affected by their distance from the Sun. According to astronomers, these planets likely did not form at their present distances but closer to where Jupiter and Saturn are now. This is because the density of matter in the disk around the Sun at the time of planet formation was too low outside the orbit of Saturn to build up Uranus and Neptune in a reasonable amount of time. Computer models suggest that Uranus and Neptune could have formed near Jupiter and Saturn and then moved to their current locations through gravitational interactions with their neighboring planets.