How do you solve -5+-3?

Answer:

[tex](4x+9)[/tex]

Step-by-step explanation:

we know that

The perimeter of triangle is equal to the sum of the three length sides

therefore

[tex]P=(x+4)+(x+8)+(2x-3)\\ \\P=(x+x+2x)+(4+8-3)\\ \\P=(4x+9)\ units[/tex]

To find the length of cable remaining on the spool, subtract the weight of the empty spool from the total weight, and then divide the result by the weight of cable per metre.

The question involves the process of subtracting, conversion and division. First, we need to subtract the weight of the empty spool from the total weight of the partly-used spool and the remaining cable to find the weight of the remaining cable alone. This means 1540 grams - 260 grams = 1280 grams. Then, we convert the weight of the remaining cable (which is in grams) to metres by dividing it by the weight of one metre of cable (which is 85 grams). So, 1280 grams ÷ 85 grams/metre = approximately 15 metres. Therefore, this is the quantity of cable that Ted has left on the spool.

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The number of different coloured crayons is 76.

Given that, Henry wants to see how many different coloured crayons are in the crayons box. There are 4 rows of 19 crayons.

We need to find how many different coloured crayons are there, assuming no duplicate colours.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Let the number of different coloured crayons be x.

Now, x=4×19

⇒x=76

Therefore, the number of different coloured crayons is 76.

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The value of the solution of expression is, r = 7

We have to give that,

An expression to simplify,

r + 15 = 4r - 6

Now, Simplify the expression by combining like terms as,

r + 15 = 4r - 6

Subtract r on both sides,

r + 15 - r = 4r - r - 6

15 = 3r - 6

Add 6 into both sides,

15 + 6 = 3r

21 = 3r

Divide 3 on both sides,

r = 21/3

r = 7

Therefore, the solution is, r = 7

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I am sure the answer is |10.5−(−6.1)| hope this helps and if correct give me the brainliest please

the correct answer is

|10.5-(6.1)|

I took the test

Answer:

The simplified product has a degree of 2.

The simplified product, in standard form has exactly 2 negative terms.

Step-by-step explanation:

[tex](b - 2c)(-3b + c)[/tex]

LEts multiply it using FOIL method

[tex]b* -3b= -3b^2[/tex]

[tex]b*c= bc[/tex]

[tex](-2c) * (-3b)= 6bc[/tex]

[tex](-2c) * c= -2c^2[/tex]

The product is [tex]-3b^2 +bc+6bc-2c^2[/tex]

[tex]-3b^2+7bc-2c^2[/tex]

The simplified product has a degree of 2.

It has two negative terms

Answer: The correct options are,

The simplified product has a degree of 2,

The simplified product, in standard form, has exactly 2 negative terms.

Step-by-step explanation:

Here, the given expression,

[tex](b-2c)(-3b+c)[/tex]

By distributive property,

[tex]=(b-2c)(-3b)+(b-2c)(c)[/tex]

Again by distributive property,

[tex]=b(-3b)-2c(-3b)+bc-2c(c)[/tex]

[tex]=-3b^2+6bc+bc-2c^2[/tex]

[tex]=-3b^2+7bc-2c^2[/tex]

Which is the simplified form of the given expression,

That having three terms in which two terms are negative and the degree ( The highest sum of the exponents of the variables) is 2,

Hence, the correct options are,

The simplified product has a degree of 2,

The simplified product, in standard form, has exactly 2 negative terms.

Maria and her family drove 885 miles, and the first '8' in this number represents the hundreds place, meaning it has a value of 800 miles.

The student's question is related to place value in numbers. Maria and her family drove 885 miles on their summer vacation, and the query specifically asks about the value represented by the first digit '8' on the left side of this three-digit number. In this case, the digit '8' is in the hundreds place, which means it represents the hundreds component of the overall number. Therefore, the first '8' has a value of 800. This is because in the number 885, the first '8' represents 8 hundreds, the second '8' represents 8 tens (or eighty), and the '5' represents 5 ones.

Answer:

Inverse function, [tex]f^{-1}=2^x[/tex]

Step-by-step explanation:

We are given a function [tex]f(x)=\log_2x[/tex]

We need to find the inverse of f(x)

Step 1: Set f(x)=y

[tex]y=\log_2x[/tex]

Step 2: Switch x and y

[tex]x=\log_2y[/tex]

Step 3: Solve for y (isolate y)

[tex]y=2^x[/tex]              [tex]\because \log_ab=x\Rightarrow b=a^x[/tex]

Inverse of function [tex]f(x)\rightarrow f^{-1}(x)=2^x[/tex]

The inverse of the logarithmic function is [tex]f^{-1}(x) = 2^x[/tex]

The logarithmic expression is given as:

[tex]f(x) = \log_2(x)[/tex]

Replace f(x) with y

[tex]y = \log_2(x)[/tex]

Swap the positions of x and y

[tex]x = \log_2(y)[/tex]

Apply the change of base rule of logarithm

[tex]2^x = y[/tex]

Rewrite as:

[tex]y = 2^x[/tex]

Express y as an inverse function

[tex]f^{-1}(x) = 2^x[/tex]

Hence, the inverse of the logarithmic function is [tex]f^{-1}(x) = 2^x[/tex]

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Final answer:

To find (g x h)(5), calculate h(5) first, then substitute the result into g(x) and calculate. The equivalent expression is (5)^2 - 7.

Explanation:

To solve (g x h)(5), we need to find g(h(5)). Given h(x) = x - 7 and g(x) = x^2, we first find h(5) = 5 - 7 = -2. Then, we evaluate g(-2) = (-2)^2 = 4. So, (g x h)(5) = g(h(5)) = g(-2) = 4, which corresponds to the option (5)^2 - 7.

Final answer:

To find where the tangent line is horizontal on the curve y = 2x^3 + 3x^2 - 12x + 8, set its derivative to zero and solve for x, resulting in points (-2, 8) and (1, 1) where the tangent lines are horizontal.

Explanation:

To find the points on the curve y = 2x^3 + 3x^2 − 12x + 8 where the tangent line is horizontal, we look for where the derivative of the curve equals zero because horizontal tangent lines have a slope of zero. The derivative of the given function is y' = 6x^2 + 6x - 12. This derivative represents the slope of the tangent at any point on the curve.

Setting the derivative equal to zero gives us the quadratic equation 6x^2 + 6x - 12 = 0, which can be simplified to x^2 + x - 2 = 0. Factoring this quadratic equation, we get (x + 2)(x - 1) = 0, leading to two solutions for x: x = -2 and x = 1. Substituting these x-values back into the original equation gives us the y-coordinates and therefore the points on the curve where the tangent line is horizontal: (-2, 8) and (1, 1).

The cost of producing one more item is 4 if 50 are currently being produced.

A linear equation is defined as an equation in which the highest power of the variable is always one.

The slope-intercept form is y = mx+c, where the slope is m and the y-intercept is c.

We have been given that linear cost function is C(x) = 4x + 300.

Here, the slope (4) is the cost per unit,

We have to determine the cost of producing one more item

Since 50 are currently being produced, so substitute the value of x = 51,

So the cost of producing one more item as

⇒ C(51) - C(50) = 4(51) +300 - (4(50) + 300) = 504 - 500 = 4

Therefore, the cost of producing one more item is 4 if 50 are currently being produced.

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To solve the equation 67 times a number minus 58 is equal to 36 less than the number, we can use algebraic manipulation to isolate the variable x. The solution is x = 1/3.

To solve the equation, we can set up the equation as follows:

67x - 58 = x - 36

Next, we can simplify the equation by combining like terms:

67x - x = 58 - 36

66x = 22

Finally, we can solve for x by dividing both sides of the equation by 66:

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Answer:

3.50p>(or equal to) 140; p>(or equal to)40

Step-by-step explanation: