[tex]\displaystyle\\\text{If }~~180^o<\theta<270^o~~\text{then }~~\theta\in~\text{quadrant 3}\\\\\text{In the 3rd cotangent dial is positive.}\\\\\text{We use the formula: } ~~~\boxed{1+\cot^2\theta=\csc^2\theta}[/tex]
[tex]\displaystyle\\1+\cot^2\theta=\csc^2\theta\\\\\cot^2\theta=\csc^2\theta-1\\\\\cot^2\theta=\left(-\frac{3}{2}\right)^2-1\\\\\\\cot^2\theta=\left(\frac{3}{2}\right)^2-1\\\\\\\cot^2\theta=\frac{9}{4}-\frac{4}{4}\\\\\\\cot^2\theta=\frac{5}{4}\\\\\\\cot\theta=\pm\sqrt{\frac{5}{4}}\\\\\\\text{We will eliminate the negative solution.}\\\\\\\cot\theta=+\sqrt{\frac{5}{4}}\\\\\\\boxed{\bf\cot\theta=\frac{\sqrt{5}}{2}}}[/tex]
Find the area of the sector below. Round your answer to two decimal places. PLEASE HELP PIC ATTACHED (pls explain how to solve it!!)
Answer:
88.49 units²
Step-by-step explanation:
Use the formula for the area of a sector.
A = (1/2)r²·θ
where θ is the central angle of the sector in radians, and r is the radius.
Here, the central angle of the sector is 360°-300° = 60° = π/3 radians. Then the area is ...
A = (1/2)(13)²(π/3) = 169π/6 ≈ 88.49 . . . . units²
To find the area of a sector, use the formula A = (θ/360) × πr². Plug in the provided values for the central angle and the radius. The final answer should carry the same number of significant figures as the radius provided.
Explanation:To find the area of the sector (A), we will use the formula: A = (θ/360) × πr², where θ represents the sector's central angle in degrees and r the radius of the circle. Suppose you are given that the central angle (θ) is 90° (or π/2 in radians) and the radius (r) is 0.0500 m, as suggested in the provided information.
Plugging these values into the formula, we get A = (90/360) × 3.14(0.0500 m)² = 7.85 × 10-3 m² rounded to two decimal places. Even though the output from the calculator is a number with more digits, [1.11] , we need to make sure our final answer is limited to two significant figures to match the given radius value.
If the radius of the circle was given as 0.800 m (or 80.0 cm), then going through the same process produces an area of 1.26 m² for a one meter length along the curve of the mirror, for instance.
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Consider the following factor and indicate whether it increases or decreases the equilibrium price of gasoline and the equilibrium quantity of gasoline sold. In this problem, assume that gasoline is a normal good.
When the number of sellers decreases, the
Choose one:
A. supply curve shifts to the right.
B. demand curve shifts to the right.
C. demand curve shifts to the left.
D. supply curve shifts to the left.
As a result,
Choose one:
A. price decreases and quantity decreases.
B. price decreases and quantity increases.
C. price increases and quantity decreases.
D. price increases and quantity increases.
The answer for your question is A,D.
Answer:
D. supply curve shifts to the left
C. price increases and quantity decreases
Step-by-step explanation:
Since the number of sellers decreases, the quantity available at the same price decreases. This shifts the supply curve to the left.
When the supply curve shifts to the left, the equilibrium point shifts to the left (and up the demand curve). Hence the price increases and the quantity decreases.
You find an old bathroom scale at a garage sale on your way home from getting a physical exam from your doctor. You step on the scale, and it reads 135 lb. You step off and step back on, and it reads 134 lb. You do this three more times and get readings of 135 lb, 136 lb, and 135 lb. a. What is the precision of this old bathroom scale? Would you consider this adequate precision for the type of measurement you are making? b. The much more carefully constructed and better-maintained scale at the doctor's office reads 126 lb. Assuming that you are wearing the same clothes that you wore when the doctor weighed you, do you think the accuracy of the old bathroom scale is high or low?
the scale has a persicion of 2 and it reads high.
1. 2 is the precision of this old bathroom scale.
2. Since 135 lbs of the old scale is higher than 126 lbs of a better-maintained scale at the doctor's office.
Given that,
An old bathroom scale,
You step on the scale, and it reads 135 lb. You step off and step back on, and it reads 134 lb. You do this three more times and get readings of 135 lb, 136 lb, and 135 lb.
In mathematics, it deals with numbers of operations according to the statements.
Here,
a). What is the precision of this old bathroom scale,
= higher reading - the lower reading
= 136 - 134
= 2
b. The much more carefully constructed and better-maintained scale at the doctor's office reads 126 lb.
Since measured weight by the old scale is 135 lbs which is higher than 126 lbs measured by the scale at the doctor's office.
Thus,
1. 2 is the precision of this old bathroom scale.
2. Since 135 lbs of the old scale is higher than 126 lbs of a better-maintained scale at the doctor's office.
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How do you find the exact value of sec θ if sin θ = -15/17 and 180 < θ < 270?
For [tex]180^\circ<\theta<270^\circ[/tex], we expect to have [tex]\cos\theta<0[/tex]. Then if [tex]\sin\theta=-\dfrac{15}{17}[/tex], we have
[tex]cos^2\theta+\sin^2\theta=1\implies\cos\theta=-\sqrt{1-\sin^2\theta}=-\dfrac8{17}[/tex]
[tex]\implies\sec\theta=\boxed{-\dfrac{17}8}[/tex]
Find the value of x in the triangle shown above PLEASE HELP ASAP! Will give 5 stars to right answer
Answer:
12
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
[tex] {9}^{2} + {x}^{2} = {15}^{2} \\ \\ 81 + {x}^{2} = 225 \\ \\ {x}^{2} = 144 \\ \\ {12}^{2} = 144 \\ \\ [/tex]
Which expression is equivalent to (r^-7)^6
A. r^42
B. 1/r^42
C. -7r^6
D. 1/r
(r^-7)^6 = r^-1 = 1/r
Therefore the answer is D. 1/r
Let me know if you have any questions.
Answer:
B. 1/r^42
Step-by-step explanation:
(r^-7)^6= r^-7*6= r^-42.
As a positive exponent: 1/r^42
Solve the equation -2=3-7 5sqrt x^2
Answer:
B. 0.43, -0.43
Step-by-step explanation:
The given equation is
[tex]-2=3-7\sqrt[5]{x^2}[/tex]
Combine similar terms to get:
[tex]-2-3=-7\sqrt[5]{x^2}[/tex]
[tex]-5=-7\sqrt[5]{x^2}[/tex]
[tex]\sqrt[5]{x^2}=\frac{5}{7}[/tex]
[tex]x^2=(\frac{5}{7})^5[/tex]
[tex]x^2=\frac{3125}{16807}[/tex]
[tex]x=\pm \sqrt{\frac{3125}{16807}}[/tex]
[tex]x=\pm 0.43[/tex]
[tex]x=0.43[/tex] or [tex]x=-0.43[/tex]
The correct answer is B.
Answer:
B
Step-by-step explanation:
First subtract 3 from the equation:
[tex]-2-3=3-7\sqrt[5]{x^2}-3\\ \\-5=-7\sqrt[5]{x^2}[/tex]
Now divide the equation by -7:
[tex]\sqrt[5]{x^2}=\dfrac{5}{7}[/tex]
Now raise the equation to the 5th power:
[tex]x^2=\left(\dfrac{5}{7}\right)^5[/tex]
Take square root:
[tex]x=\pm \sqrt{\left(\dfrac{5}{7}\right)^5} =\pm \dfrac{25}{49}\sqrt{\dfrac{5}{7}} \\ \\x_1\approx 0.43\\ \\x_2\approx -0.43[/tex]
Which of the following equations is represented by the given graph?
Answer:
A
Step-by-step explanation:
Please help last question
Answer:
75
Step-by-step explanation:
"given that it's a junior" means to only look at juniors.
From the table, under junior, there are 2 males and 6 females. 2 + 6 = 8. The total number of juniors is 8.
p(female given junior) = 6/8 = 3/4 = 0.75 = 75%
Answer: 75
Answer:
75
Step-by-step explanation:
"given that it's a junior" means to only look at juniors.
From the table, under junior, there are 2 males and 6 females. 2 + 6 = 8. The total number of juniors is 8.
p(female given junior) = 6/8 = 3/4 = 0.75 = 75%
Answer: 75
Please help asap!!!!!!!!
ANSWER
A=16
EXPLANATION
The radius of the circle is r=4 units.
The area of a triangle is
[tex] \frac{1}{2} bh[/tex]
Both the height and the base of the triangle are radii, which is 4 units.
The area of the two isosceles right triangle is
[tex] 2(\frac{1}{2} \times 4 \times 4) = 16[/tex]
Answer:
Area of combined triangle = 2 * 8 = 16 square units
Step-by-step explanation:
Points to remember
Area of triangle = bh/2
b - Base and h - Height
From the figure we can see that a circle and two right angled triangles.
To find the combined area of triangles
Here base and height of two triangles is equals to radius of circle
Therefore b = 4 and h = 4
Area of one triangle = bh/2
= (4 * 4)/2 = 8 square units
Area of combined triangle = 2 * 8 = 16 square units
Graph the function by first finding its zeroes.
y = x3- 2x2 + x
Answer:
The zeros of the function are;
x = 0 and x = 1
Step-by-step explanation:
The zeroes of the function simply imply that we find the values of x for which the corresponding value of y is 0.
We let y be 0 in the given equation;
y = x^3 - 2x^2 + x
x^3 - 2x^2 + x = 0
We factor out x since x appears in each term on the Left Hand Side;
x ( x^2 - 2x + 1) = 0
This implies that either;
x = 0 or
x^2 - 2x + 1 = 0
We can factorize the equation on the Left Hand Side by determining two numbers whose product is 1 and whose sum is -2. The two numbers by trial and error are found to be -1 and -1. We then replace the middle term by these two numbers;
x^2 -x -x +1 = 0
x(x-1) -1(x-1) = 0
(x-1)(x-1) = 0
x-1 = 0
x = 1
Therefore, the zeros of the function are;
x = 0 and x = 1
The graph of the function is as shown in the attachment below;
Please help on puzzle #2
Answer:
(2 +4i)(5 -6i) . . . or . . . (4 -2i)(6 +5i)
Step-by-step explanation:
The product of two complex numbers is ...
(a +bi)(c +di) = (ac -bd) +(bc +ad)i
So, we're looking for pairs of numbers that can be combined in different ways to give 34 and 8. The numbers we found (by trial and error) are ...
2, 4, 5, 6
where 4*6 +2*5 = 34 and 4*5 -2*6 = 8. Because of the effect if i^2 on the sign, we need to have the imaginary parts have opposite signs.
Each of the solutions shown above is representative of 4 solutions. For example, for the first one, you could have ...
(2 +4i)(5 -6i) = (2·5 +4·6) + (4·5 +2(-6))i = 34 +8i
(5 -6i)(2 +4i) = (5·2 +6·4) + (-6·2 +5·4) = 34 +8i . . . . . order of factors swapped
(-2 -4i)(-5 +6i) = ((-2)(-5) -(-4)(6)) + ((-4)(-5) +(-2)(6))i = 34 +8i . . . . both factors in the first solution negated
(-5 +6i)(-2 -4i) = ((-5)(-2) -(6)(-4)) +(6(-2) +(-5)(-4))i = 34 +8i . . . . factors swapped and negated
___
Likewise, the second shown solution above is representative of 4 solutions.
Possible solutions are ...
(2 +4i)(5 -6i)(4 -2i)(6 +5i)with sign and order variations.
_____
Comment on trial and error
Actually, we did an exhaustive search of the 441 products of single-digit numbers [-9, 9] to see which pairs of them differed by 34. Then, among those, we looked for product pairs that added to 8. In the end, we found the 8 solutions described above.
please help me asap
afraid to fail
Answer: 311.25
Step-by-step explanation: Take 52.50 and multiply by 4.5. Then add the $75 service fee.
Answer:
$311.25
Step-by-step explanation:
This is your correct answer because 52.50 x 4.5 plus 75 equals 311.25.
Suppose that the lifetimes of light bulbs are approximately normally distributed, with a mean of 56 hours and a standard deviation of 3.3 hours. With this information, answer the following questions. (a) What proportion of light bulbs will last more than 61 hours? (b) What proportion of light bulbs will last 53 hours or less? (c) What proportion of light bulbs will last between 57 and 62 hours? (d) What is the probability that a randomly selected light bulb lasts less than 46 hours?
To solve this problem, we need to use the z-score formula to standardize the values and then look up the corresponding probabilities in the standard normal distribution table.
Explanation:To solve this problem, we need to use the z-score formula to standardize the values and then look up the corresponding probabilities in the standard normal distribution table. The z-score formula is given by (X - μ) / σ, where X is the given value, μ is the mean, and σ is the standard deviation. Here are the calculations for each question:
(a) What proportion of light bulbs will last more than 61 hours?First, we need to calculate the z-score for 61 hours:
z = (61 - 56) / 3.3 = 1.52
Next, we can look up the probability corresponding to a z-score of 1.52 in the standard normal distribution table. The probability of getting a value greater than 1.52 is approximately 0.0655, or 6.55%.
(b) What proportion of light bulbs will last 53 hours or less?First, we need to calculate the z-score for 53 hours:
z = (53 - 56) / 3.3 = -0.9091
Next, we can look up the probability corresponding to a z-score of -0.9091 in the standard normal distribution table. The probability of getting a value less than or equal to -0.9091 is approximately 0.1814, or 18.14%.
(c) What proportion of light bulbs will last between 57 and 62 hours?First, we need to calculate the z-scores for 57 hours and 62 hours:
z1 = (57 - 56) / 3.3 = 0.303
z2 = (62 - 56) / 3.3 = 1.82
Next, we can look up the probabilities corresponding to z1 and z2 in the standard normal distribution table. The probability of getting a value between z1 and z2 is approximately 0.1988, or 19.88%.
(d) What is the probability that a randomly selected light bulb lasts less than 46 hours?First, we need to calculate the z-score for 46 hours:
z = (46 - 56) / 3.3 = -3.03
Next, we can look up the probability corresponding to a z-score of -3.03 in the standard normal distribution table. The probability of getting a value less than -3.03 is approximately 0.00123, or 0.123%.
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The question involves the computation and interpretation of Z-scores in a normally distributed data, which in this case is the lifetime of light bulbs. The probabilities are found by calculating the Z-scores and then looking up these scores in a Z-table or using a calculator. About 6.4% of bulbs will last more than 61 hours, 18.1% will last 53 hours or less, approximately 34.1% will last between 57 and 62 hours, and only about 0.1% will last less than 46 hours.
Explanation:The question is about using the properties of a normal distribution to find probabilities related to the lifetime of light bulbs. To do this, we use the mean and standard deviation to compute Z-scores, which give us the number of standard deviations away from the mean a certain value is.
(a) To find the proportion of light bulbs that will last more than 61 hours, we calculate the Z-score for 61 hours: Z = (61 - 56)/3.3 = 1.52. We look this Z-score up in a Z-score table or use a calculator to find that the probability of getting a Z-score of 1.52 is about 0.064. Therefore, about 6.4% of light bulbs will last more than 61 hours.
(b) For finding the proportion of light bulbs that will last 53 hours or less, we calculate the Z-score for 53 hours: Z = (53 - 56)/3.3 = -0.91. Looking this up, we find that about 18.1% of light bulbs will last less than or equal to 53 hours.
(c) To find the proportion of light bulbs that will last between 57 and 62 hours, we calculate the Z-scores and find the probabilities for both, then subtract the smaller from the larger. The Z-score for 57 hours is 0.30 (probability about 37.5%) and for 62 hours is 1.82 (probability about 3.4%). Thus, about 34.1% of all light bulbs will last between 57 and 62 hours.
(d) Finally, to find the probability that a light bulb lasts less than 46 hours, we again calculate the Z-score: Z = (46 - 56)/3.3 = -3.03. This Z-score is quite small, suggesting this is unlikely: indeed, only about 0.1% of all light bulbs last less than 46 hours.
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Write the equation 9y = 12x + 0.2 in standard form. Identify A, B, and C.
Question 19 options:
45x – 60y = 1 where A = 45, B = –60, and C = –1
45x – 1y = 1 where A = 45, B = –60, and C = 1
60x + 45y = –1 where A = 60, B = 45, and C = 1
60x – 45y = –1 where A = 60, B = –45, and C = –1
Answer: D) 60x-45y = - 1 where A = 60 , B = -45 , and c = - 1
Step-by-step explanation: Clear it : 45y=60x+1
Step 2: Isolate the constant on one side: ( -1 = -45y +60x)
step 3: A= 60 , B= - 45 , C= - 1
Answer:
60x-45y = - 1 where A = 60 , B = -45 , and c = - 1
Step-by-step explanation:
what is the additive inverse of the expression below, where are a and b real numbers?
2a+b
A. -1
B. 0
C. 2a-b
D. -2a-b
Answer:
D. -2a-b
Step-by-step explanation:
The additive inverse is found by multiplying the expression by -1.
-1(2a+b) = -2a -b . . . . matches selection D
For which intervals is the function positive?
(−∞,−2)
(0,4)
(4,∞)
(−1.5,−1)
(2,2.5)
(−2, 0)
Answer:
(−∞,−2) and (0,4)
Step-by-step explanation:
The function is positive when it is above the x-axis. This is when x is less than -2 and when x is between 0 and 4.
This question is asking about the intervals in which a given function is positive. Without knowing the exact function, one would typically evaluate the function in the given intervals to decide whether the result is positive or negative.
Explanation:The question is asking in which intervals a given mathematical function is positive. Without more specific information about the function, it is impossible to definitively say which of the intervals the function is positive in. Normally, you would evaluate the function at multiple points within the given intervals and analyze the output to determine if the function is positive or negative within those ranges.
For example, if you had the function f(x) = x^2 - 3x + 2, you could plug in a couple of values in the intervals (−∞,−2), (0,4), (4,∞), (−1.5,−1), (2,2.5), (−2, 0) and see whether the output is positive.
Again, without the specific function this exercise is theoretical and is based on your understanding of intervals and their relationship with function values.
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Find the value of x.
log 3 x=4
Answer:
The correct answer option is D. 81.
Step-by-step explanation:
We are given the following expression and we are to find the value of x:
[tex] log _ 3 x = 4 [/tex]
We can inverse [tex] log _ 3 x [/tex] and re-write it as [tex]3^x[/tex].
Doing that, we will raise both the sides of the equation to the power of 3 to get:
[tex] 3 ^ { log 3 x } = 3 ^ 4 [/tex]
x = 81
Please help me last question
As you can see there are two triangles but it can be done calculating just for one. First we must understand how formula for area of triangle works.
[tex]A=\frac{1}{2}bh[/tex]
Where [tex]b[/tex] represents base (hypotenuse) and [tex]h[/tex] as height of the triangle.
We know that:
[tex]
b=13cm \\
h=4cm
[/tex]
Using this data we fill the formula.
[tex]A=\frac{1}{2}\cdot13\cdot4=\frac{13\cdot4}{2}=13\cdot2=\boxed{26cm^2}[/tex]
Hope this helps.
r3t40
Answer:
Area of the triangle = 26 cm²
Step-by-step explanation:
The given triangle has the measure of height h = 4 cm
and base of the triangle = 13 cm
We know the formula of the area of a triangle = [tex]\frac{1}{2}(Base)(height)[/tex]
By putting the values in the formula
Area of the triangle = [tex]\frac{1}{2}(4)(13)[/tex]
= 2×13
= 26 cm²
Therefore, area of the given triangle is 26 cm².
A foam material has a density of 175 g/l. what is its density in units of lb/ft3? How do you get 1 gram/liter = 0.06242796 pound/cubic foot?
Answer:
Given: 175 g/L
1 gram/liter = 0.06242796 pound/cubic foot
175 g/L * 0.06242796 pound/cubic foot= 10.924893 lb/ft3
So, a foam material has a density of 10.924893 lb/ft3 in units of lb/ft3
Step-by-step explanation:
Find the points on the curve where the tangent is horizontal or vertical. If you have a graphing device, graph the curve to check your work. (Enter your answers as a comma-separated list of ordered pairs.)x = t^3 - 3t, y = t^2 - 4
To find the points where the tangent is horizontal or vertical on the given curve, we find the slope, set it equal to zero or undefined, and solve for t. Then substitute the values of t in the equations to find the corresponding points on the curve.
Explanation:To find the points on the curve where the tangent is horizontal or vertical, we need to find the slope of the curve and determine when it is zero or undefined. For the given curve x = t^3 - 3t, y = t^2 - 4, we can find the slope dy/dx, set it equal to zero or undefined, and solve for t. Once we have the values of t, we can substitute them back into the equations x = t^3 - 3t and y = t^2 - 4 to find the corresponding points on the curve.
To find the horizontal tangent, we set dy/dx equal to zero:
dy/dx = (dy/dt) / (dx/dt) = (2t) / (3t^2 - 3) = 0
Setting the numerator equal to zero, 2t = 0, we find t = 0. Substituting t = 0 back into the equations x = t^3 - 3t and y = t^2 - 4, we get the point (0, -4).
To find the vertical tangent, we set dx/dt equal to zero:
dx/dt = 3t^2 - 3 = 0
Solving for t, we find t = ±1. Substituting t = 1 and t = -1 back into the equations x = t^3 - 3t and y = t^2 - 4, we get the points (2, -3) and (-2, -3) respectively.
Therefore, the points on the curve where the tangent is horizontal or vertical are (0, -4), (2, -3), and (-2, -3).
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The points on the curve defined by x = t^3 - 3t and y = t^2 - 4 where the tangent is horizontal or vertical are (-2, 3), (0, -4), and (2, 3).
Explanation:In the subject of Mathematics, specifically calculus, the question is seeking the points on the curve defined by the parametric equations x = t^3 - 3t and y = t^2 - 4 where the tangent is horizontal or vertical. This means we are looking for the values of t where the derivative dy/dx equals 0 (horizontal tangent) or is undefined (vertical tangent).
First, we need to calculate the derivatives dx/dt and dy/dt. dx/dt = 3t^2 - 3 and dy/dt = 2t. Then we can find the overall derivative dy/dx = (dy/dt)/(dx/dt).
For a horizontal tangent, dy/dx = 0, meaning the numerator of our derivative equation must be zero: dy/dt = 2t = 0. This gives us t = 0.
For a vertical tangent, dy/dx is undefined, meaning the denominator of our derivative equation must be zero: dx/dt = 3t^2 - 3 =0. Solving this equation gives us t = -1, 1.
Substitute t = -1, 0, and 1 into x = t^3 - 3t and y = t^2 - 4 to get the points in the (x, y) format. This results in the points: (-2, 3), (0, -4), and (2, 3).
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Tatiana wants to give friendship bracelets to her 32 classmates. She already has 5 bracelets, and she can buy more bracelets in packages of 4.
Will Tatiana have enough bracelets if she buys 5 packages?
PLEASE ANSWER ASAP!
TWENTY POINTS!!
THANKSSS
Answer:
No.
Step-by-step explanation:
First, subtract 32-5= 27
Then multiply 5 * 4=20
since 20 is less than 27, she will not have enough.
Answer:
No
Step-by-step explanation:
She already has 5 and the total is 32 so she has to make 28 friendship bracelets.
Bracelets in packages of 4 and she buys 5 packages which is 20 so no, she doesn't have enough bracelets if she buys 5 packages.
I need help with Precal asap !!!! I’ll mark u as brainliest, please if you don’t know the correct answer don’t write down.
Answer:
Equation 1: r = -5 * cos theta
Equation 2: r = 1 – ( 4 * sin theta )
Step-by-step explanation:
Graph 1:
This graph is a circle along negative x- axis.
General equation for graph:
R = a cos theta ∴ a = diameter of circle
From given graph, it is included that:
a = -5
a/2 = -2.5 (center of circle)
Equation 1: r = -5 cos theta
Graph 2:
This graph is an inner-loop limacon.
The inner-loop limacon is in the downward direction along the negative y-axis
The general equation for the graph will be :
r = a – b sin theta
a will represent x – intercept, from graph it is included that:
a = { +1, -1 }
For inner-loop on y-axis, b - a = 3 ………….1
For outer-loop on y-axis, a + b = 5 …………2
Adding both 1 and 2 to find values of a and b
b – a = 3
a + b = 5
2b = 8 ⇒ b = 4
Putting value of b in 2
a + 4 = 5 ⇒ a = 1
substituting values of a and b in general equation:
Equation 2: r = 1 – 4 sin theta
WH
A cylinder measures 10 inches in
diameter and has a height of 6
inches. What is its volume?
Answer:
150π in³ ≈ 471.24 in³
Step-by-step explanation:
The formula for the volume of a cylinder is ...
V = πr²h
The radius is half the diameter, so you have a volume of ...
V = π(5 in)²(6 in) = 150π in³ ≈ 471.24 in³
A ball is launched from a sling shot. Its height, h(x), can be represented by a quadratic function in terms of time, x, in seconds.
After 1 second, the ball is 121 feet in the air; after 2 seconds, it is 224 feet in the air.
Find the height, in feet, of the ball after 3 seconds in the air.
Answer:
309 ft
Step-by-step explanation:
In order to solve this I have to assume that the sling shot is ground level. Since you did not provide an initial height, without making the assumption that it is 0, we cannot solve the problem at all.
The standard form of a quadratic function is
[tex]f(x)=ax^2+bx+c[/tex]
c is the initial height for which we are going to sub in a 0. Given 2 points, we are going to plug in the y and the x, one point each into 2 quadratic functions, to find the model. The first coordinate is (1, 121):
[tex]121=a(1)^2+b(1)+0[/tex] and 121 = a + b
The second coordinate is (2, 224):
[tex]224=a(2)^2+b(2)+0[/tex] and 224 = 4a + 2b
Solve the first equation for a:
a = 121 - b
and sub it in for a in the second equation:
224 = 4(121 - b) + 2b and
224 = 484 - 4b + 2b and
-260 = -2b so b = 130.
Now we can sub that in for b and solve for a:
a = 121 - 130 so a = -9.
The equation then that models the motion is
[tex]f(x)=-9x^2+130x[/tex]
Now that we know that, all we have to do now is to find f(3):
[tex]f(3)=-9(3)^2+130(3)[/tex] and
f(3) = 309 ft
Can someone please help me with this problem
30 points!!!!
Answer:
29.4
Step-by-step explanation:
29.4444 rounded to the nearest tenth is 29.4
the other answerer forgot to round to the tenths place
Which expression is equivalent to sec2xcot2x?
A.
sin2x
B.
csc2x
C.
`(1)/(cos^2x)`
D.
`(1)/(tan^2x)`
Answer:
Option B is correct answer.
Step-by-step explanation:
We need to solve the expression sec2xcot2x.
We know sec x = 1/ cos x and cot x = 1/ tan x and tan x = sin x/cos x and 1/tanx = cosx /sinx
Since in question we 2x instead of x so, replacing x with 2x and Putting values:
[tex]sec2x\,\, cot2x\\=\frac{1}{cos 2x} * \frac{1}{tan 2x} \\=\frac{1}{cos 2x} * \frac{cos2x}{sin2x}\\=\frac{1}{sin 2x}\\=csc2x[/tex]
So, Option B is correct answer.
Answer:
b
Step-by-step explanation:
mean absolute deviation of 23,28,16,25,18,31,14,37
Answer:
6.25
Step-by-step explanation:
I find it convenient to use technology to compute the mean absolute deviation. (see below)
Answer:
(MAD) Mean Absolute Deviation: 6.25
Step-by-step explanation:
Mean: 23 + 28 + 16 + 25 + 18 + 31 + 14 + 37 = 192/8 = 24
24 - 23 = 1
24 - 28 = 4
24 - 16 = 8
24 - 25 = 1
24 - 18 = 6
24 - 31 = 7
24 - 14 = 10
24 - 37 = 13
Mean Absolute Deviation (MAD): 1 + 4 + 8 + 1 + 6 + 7 + 10 + 13 = 50/8 = 6.25
Find a parametric representation for the surface. The part of the sphere x2 + y2 + z2 = 16 that lies between the planes z = −2 and z = 2. (Enter your answer as a comma-separated list of equations. Let x, y, and z be in terms of θ and/or ϕ.)
To answer this question, we should make use of spherical coordinates.
Solution is:
S = ( 4×cosθ ×sinΦ , 4 ×sinθ× sinΦ, 4 × cosΦ)
0 ≤ θ ≤ 2×π ; π/2 ≤ Ф ≤ (3/2)×π
In Analitic Geometry we have different way of determine, and identify the position of objects, we have rectangular coordinates, cylindrical coordinates and spherical coordinates. The use of each of these system depends on de geometry of the problem.
In this particular case and according to the problem statement we should use spherical coordinates
x = ρ×cosθ ×sinΦ y = ρ ×sinθ× sinΦ z = ρ× cosΦ
In our particular case
ρ = 4 then x = 4×cosθ ×sinΦ y = 4 ×sinθ× sinΦ z = 4 × cosΦ
0 ≤ θ ≤ 2×π ; π/2 ≤ Ф ≤ ( 3/2)×π
So the solution in terms of θ and/or Φ
S = ( 4×cosθ ×sinΦ , 4 ×sinθ× sinΦ, 4 × cosΦ)
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To find a parametric representation for the surface of the part of the sphere x² + y² + z² = 16 between the planes z = -2 and z = 2, use spherical coordinates with r = 4, θ ranging from 0 to π, and ϕ ranging from 0 to 2π.
Explanation:To find a parametric representation for the surface of the part of the sphere x² + y² + z² = 16 that lies between the planes z = -2 and z = 2, we can use spherical coordinates.
Letting x = r sinθ cosϕ, y = r sinθ sinϕ, and z = r cosθ, where r is the radius of the sphere, θ is the polar angle, and ϕ is the azimuthal angle, we can rewrite the equation of the sphere as r² = 16.
Simplifying, we have r = 4.
Now we can write the parametric equations as x = 4 sinθ cosϕ, y = 4 sinθ sinϕ, and z = 4 cosθ, where θ ranges from 0 to π, and ϕ ranges from 0 to 2π.
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Find the value of f(–3) and g(3) if f(x) = –6x + 3 and g(x) = 3x + 21x–3.
f(–3) = 21
g(3) = 9.78
f(–3) = –18
g(3) = –9.78
f(–3) = –3
g(3) = 30.04
f(–3) = 15
g(3) = 8.22
The value of f(-3) for the function f(x) = -6x + 3 is 21. The value of g(3) for the function g(x) = 3x + 21x - 3 is 66.
Explanation:To find the value of f(-3), you substitute -3 in place of x in the function f(x) = -6x + 3. You get f(-3) = -6(-3) + 3 = 18 + 3 = 21.
To find the value of g(3), we substitute 3 in place of x in the function g(x) = 3x + 21x - 3. This gives g(3)= 3(3) + 21*(3)-3 = 9 + 57 = 66.
So, f(-3) = 21 and g(3) = 66.
To find the value of f(–3) and g(3), we need to substitute the given values into the respective functions.
For f(x) = –6x + 3, substituting x = –3 into the function, we get:
f(–3) = –6(–3) + 3 = 18 + 3 = 21
For g(x) = 3x + 21x – 3, substituting x = 3 into the function, we get:
g(3) = 3(3) + 21(3) – 3 = 9 + 63 – 3 = 69
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