How do odd or even exponents influence polynomial exponents?

Answers

Answer 1

(x + y)^0 = 1

(x + y)^1 = x + y

(x + y)^2 = x^2 + 2x + y

(x + y)^3 = x^3 + 3x^2y + 3xy^2 + y^3

(x + y)^4 = x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4

.

.

.

1

1 + 1

1 + 2 + 1

1 + 3 + 3 + 1

1 4 6 4 1

.

.

.

I hope I helped you.

Answer 2

Odd exponents ensure at least one real root for polynomials, while even exponents may result in no real roots. Multiplying even functions together, or odd functions together, results in an even function. These properties have applications in areas like quantum mechanics.

Odd and even exponents greatly influence the behavior of polynomial functions. For polynomials with odd exponents, they will always have at least one real root. This is because polynomials of odd degree tend to positive infinity as x goes to positive infinity and negative infinity as x goes to negative infinity, therefore they must cross the x-axis at some point. A polynomial like x³ - x + 17 exemplifies this behavior.

On the other hand, polynomials with even exponents may not have any real roots, as they never need to cross the x-axis; for example, x² + 1 is always positive for any real value of x and thus has no real roots.

Even functions and odd functions also display characteristic properties when multiplied. An even function times an even function yields an even function (e.g., x² e⁻²), and an odd function times another odd function results in an even function (e.g., x sin x).

In contrast, an odd function times an even function gives an odd function. These properties are particularly useful in fields such as quantum mechanics where symmetry plays an important role in solving equations like Schrödinger's equation.


Related Questions

what is the value of x in the diagram below ?

Answers

Answer:

x = 9

Step-by-step explanation:

12^2 + a^2 = 54^2

a^2 = 54^2 - 12^2

a = sqrt (54^2 - 12^2) = 6 * sqrt(77)

Then calculate it for another triangle, where each side is 6 times shorter (as 12/2 = 6):

2^2 + (sqrt(77))^2 = x^2

x^2 = 81

x = 9

What is the missing number in the synthetic division problem below?

Answers

Answer:

D. 7

Step-by-step explanation:

In synthetic division, the first # in the division bracket (2)  is dropped, and the number outside the bracket is multiplied with it to find 4. Then, -2 and 4 are added to get 2. Again, 2 x 2=4. 3+4=7.

Simplified version: Drop, multiply, add, multiply, add till you reach the last term.


Final answer:

The synthetic division problem hasn't been stated in this query, making it impossible to ascertain the missing number. Synthetic division is a mathematical methodology used to simplify polynomial division by binomial. The correct problem should be offered for accurate guidance.

Explanation:

Unfortunately, the provided synthetic division problem was not included in your question so I'm unable to solve for the missing number. In general, synthetic division is a method used in algebra to divide a polynomial by a binomial. I would suggest you to verify the problem and restate your question providing all necessary details. Then I would gladly help you solve the missing number in the synthetic division.

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According to the real rational root theorem, what are all the potential rational roots of f(x)=5x3-7x+11

Answers

Answer:

x = -11, -11/5, -1, -1/5, 1/5, 1, 11/5,11

Step-by-step explanation:

The general formula for a third-degree polynomial is

f(x) = ax³ + bx² + cx + d

Your polynomial is  

f(x) = 5x³ + 7x + 11

a = 5; d = 11

p/q = Factors of d/Factors of a

Factors of d = ±1, ±11

Factors of a = ±1, ±5

Potential roots are x = ±1/1, ±1/5, ±11/1, ±11/5

Putting them in order, we get the potential roots

x = -11, -11/5, -1, -1/5, 1/5, 1, 11/5, 11

(There are no rational roots. There is one irrational root and two imaginary roots.)

what percent of 260 is 156?

Answers

Divide 260 and 156 to get 5/3, or 1 2/3. Multiply by 100 to get 166.(6). (6) means repeating forever. For example 1.(3)=1.333333333....


You know the slope of a line and a point on the line that is not the y-intercept. Can you use a graph to write the equation of the line in slope-intercept form? Explain.

Answers

sure you could as long as you have the point.

for example let's say the slope is 2 and the point we are given is (4,4)

we know that:
[tex]y = mx + b[/tex]
plug in the values given
x=4
y=4
m=2

[tex]4 = 2(4) + b[/tex]
b, the y intercept equals -4.

so:

[tex]y = 2x - 4[/tex]
in this case

if sin (a+b)=k sin (a-b) prove that (k-1)cotb =( k+1) cota

Answers

Answer:

Proof

Step-by-step explanation:

Recall the identity [tex]\sin(a \pm b) = \sin(a)\cos(b) \pm \cos(a)\sin(b)[/tex].

Consider [tex]\sin(a + b) = k\sin(a - b)[/tex]. We firstly apply the above identity to reach

[tex]\sin(a)\cos(b) + \cos(a)\sin(b) = k(\sin(a)\cos(b) - \cos(a)\sin(b))[/tex].

By expanding the bracket on the right we obtain

[tex]\sin(a)\cos(b) + \cos(a)\sin(b) = k\sin(a)\cos(b) - k\cos(a)\sin(b)[/tex] and so

[tex]\cos(a)\sin(b) + k\cos(a)\sin(b) = k\sin(a)\cos(b) - \sin(a)\cos(b)[/tex] and so

[tex](1+k)\cos(a)\sin(b) = (k-1)\sin(a)\cos(b)[/tex] and so

[tex](k+1)\frac{\cos(a)}{\sin(a)}= (k-1)\frac{\cos(b)}{\sin(b)}[/tex] and finally

[tex](k+1)\cot(a)= (k-1)\cot(b)[/tex].

Final answer:

Using the sum and difference identities for sine, we can manipulate the equation sin(a+b) = k sin(a-b) to prove the trigonometric identity (k-1)cotb = (k+1)cota as required.

Explanation:

To solve the given trigonometric identity, we must show that if sin(a+b) = k sin(a-b), then (k-1)cotb = (k+1)cota. First, let's utilize the sum and difference identities for sine:

sin(a+b) = sin(a)cos(b) + cos(a)sin(b)

sin(a-b) = sin(a)cos(b) - cos(a)sin(b)

Substitute these into the original equation:

sin(a)cos(b) + cos(a)sin(b) = k(sin(a)cos(b) - cos(a)sin(b))

Now, distribute the k on the right side and arrange terms:

sin(a)cos(b)(1-k) = cos(a)sin(b)(1+k)

Divide both sides by sin(b)cos(b) to isolate cot(a) and cot(b):

(1-k) cot(b) = (1+k) cot(a)

This proves the identity as required. Notice that the cotangent function is the reciprocal of the tangent function, which is the ratio of sine to cosine.

At first, the ratio of Dave's savings to Sam's savings was 5:4. After each of them donated $40 to charity, the ratio of Dave's savings to Sam's savings became 13:10. What was Dave's savings at first?

Answers

Let the initial savings at first be = x

Given ratio is [tex]\frac{5}{4}[/tex] and after donating $40 to charity, the ratio becomes [tex]\frac{13}{10}[/tex]

Hence, the relation becomes:

[tex]\frac{5x-40}{4x-40}=\frac{13}{10}[/tex]

[tex]10(5x-40)=13(4x-40)[/tex]

= [tex]50x-400=52x-520[/tex]

[tex]-2x=-120[/tex] or

[tex]2x=120[/tex]

[tex]x=60[/tex]

So , Dave's saving at first was 5x = 5*60 = $300

and Sam's saving at first was 4x = 4*60= $240

1. A researcher believes that university students weigh more than the population. The researcher reasons that more time spent on studying for exams means having less time to exercise. The researcher selects an alpha level of 0.10 (or CL = 90%). Upon looking at census data, the average American weighs 170lbs with a standard deviation of 35lbs.

The researcher takes a random sample of 225 CSU students and finds that the mean weight of CSU students is 180lbs with a sample standard deviation of 45.

Is there enough evidence to reject the null hypothesis?

Answers

Answer:

The null and alternative hypotheses are:

[tex]H_{0}: \mu = 170[/tex]

[tex]H_{a}: \mu >170[/tex]

Under the null hypothesis, the test statistic is:

[tex]z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}} }[/tex]

         [tex]=\frac{180-170}{\frac{35}{\sqrt{225}} }[/tex]

         [tex]=\frac{10}{2.33}[/tex]

         [tex]=4.29[/tex]

Now, we have to find the right tailed z critical value at 0.10 significance level. Using the standard normal table, we have:

[tex]z_{critical} = 1.28[/tex]

Since the test statistic is greater than the z critical value, we therefore, reject the null hypothesis and conclude that there is sufficient evidence to support the claim that the university students weigh more than the population.


Solve A = a + b /2 for b

Answers

Answer:

b=2A-2a

Step-by-step explanation:

First you subtract a to the other side.

Then you divide by 2.

SO it will be b=2A-2a which is your answer

A = a+b/2

*subtract a from both sides*

A-a =b/2

*multiply both sides by 2*

2(A-a)=b

*distribute*

b=2A-2a

plz help look at the Picture thanks so much for the Help

Answers

The amount of the markup is 20% of 25.15

EQUATION 1: 20/100 * 25.15

ANSWER TO EQUATION 1: 503/100

Then we have divide 503 and 100

EQUATION 2: 503/100

FINAL ANSWER: $5.03

The amount of the markup is $5.03

Use a common denominator to write an equivalent fraction for each fraction 1/6 , 1/9

Answers

Answer:

1/6 = 3/18

1/9 = 2/18

Step-by-step explanation:

The common denominator for 6 and 9 is the smallest number that they both go into, which is 18.  We need to multiply 6 by 3 to get 18 and multiply 9 by 2 to get 18

1/6 *3/3 = 3/18

1/9 *2/2 = 2/18

Answer:

the pair would be 3/18 and 2/18

What is BC?
Enter your answer in the box?

Answers

Answer:

18

Step-by-step explanation:

Since this is an isosceles triangle, sides AB and sides AC are equal

AB=AC

8x-4 = 5x+11

Subtract 5x from each side

8x-5x-4 = 5x-5x+11

3x-4 = 11

Add 4 to each side

3x-4+4 = 11+4

3x=15

Divide by 3

3x/3 =15/3

x=5


We want to find BC

BC= 4x-2

Since x=5

BC = 4(5) -2

BC = 20-2

BC =18

List the first 5 multiples,and find ALL the factors of 13.

Answers

13, 26, 39, 52, 65

1,13 (because its a prime number)

0.1406250 to the nearest 10th

Answers

Answer:

0.1

Step-by-step explanation:


0.1 will be the right answer because If the number is in between 0-4 you don’t add anything but if the number is in between 5-9 you add 1 to it

What is a positive number that equals 30 when added to it squared

Answers

Answer: 5

Step-by-step explanation:

Let x represent the number, then

x² + x = 30

x² + x - 30 = 0      

(x + 6) (x - 5) = 0

x + 6 = 0   x - 5 = 0

 x = -6        x = 5

    ↓

not valid since the restriction is that x > 0 (a positive number)

So, x = 5

how can you tell which quadrant a point is in by looking at the signs of its coordinates

Answers

Answer:

In quadrant I   x is positive , y is positive

In quadrant II   x is negative , y is positive

In quadrant III   x is negative , y is negative

In quadrant IV  x is positive , y is negative

Step-by-step explanation:

In quadrant I   x is positive , y is positive

In quadrant II   x is negative , y is positive

In quadrant III   x is negative , y is negative

In quadrant IV  x is positive , y is negative


How I remember, I and II quads have a positive y

                             I and IV quads have a positive x

Dan borrowed $750.00 from his brother with a 5% simple interest. If Dan pays his brother back in 6 months, how much does he have to pay back including the interest?

Answers

Answer:

$780

Step-by-step explanation:

The initial sum of money borrowed was $750


at a simple interest rate of 8%


Dan pays the money back in 6 months



The amount of money Dan has to pay back his brother including the interest in 6 months' time.



The total amount accrued, principal plus interest, from simple interest on a principal of $750 at a rate of 8% per year for 6 months is $780.



The total interest that is to be paid back can be calculated using the formula



where P is the prinicipal amount of money we begin with (in this case $750), r is the rate of interest (in this case 8%) and t is the time period (in this case, 6 months or 1/2 of a year).


(Note that we must take the value of t in years if the interest is annual interest and that is why we use t = 1/2 = 0.5 instead of t = 6).


So, by simple calculation we can find interest to be paid as



the interest accrued is $30


To find the total sum to be paid back, we add the initial sum or pricipal amount to the interest we have calculated above i.e.,



the total amount accrued, principal plus interest, from simple interest on a principal of $750 at a rate of 8% per year for 6 months is $780.



Apply distributive property to factor out the GCF

27+18r=

Answers

Answer: 9(3 + 2r)

Step-by-step explanation:

      27                     18r

       ∧                       ∧

    3  9                    2  9r

         ∧                         ∧

        3  3                     3 3r

27: 3 * 3 * 3

18r: 2 * 3 * 3 * r

Common Factors are 3 * 3 = 9

27: 9 * 3

18: 9 * 2r

27 + 18r  =  9(3 + 2r)

Can anyone place the numbers 1-9 (in any of the nine circles ) making the sum of each of the Columns 23... please and thanks

Answers

ANSWER:

The solution for this problem is displayed in the image attached.

The method I used to solve this problem was trial and error. I tested different combinations of 2 sets of 5 numbers each where no number is repeated except for one number in either of the two sets and the sum of each combination was 23.

The working out for the correction combination of numbers is as follows:

Column No. 1:

2 + 3 + 1 + 8 + 9 = 23
23 = 23
Therefore, this equation is correct.

Column No. 2:

4 + 5 + 1 + 6 + 7 = 23
23 = 23
Therefore, this equation is correct.

As both equations are correct and both columns add to 23 while abiding to the conditions of the problem, the combination of numbers ( answers ) for this problem must be correct.

Can you help me solve that

Answers

Answer:2.6



Step-by-step explanation:

Use your graphing calculator of you have one and if you don't you can find one online and plug in the equation and find the intersection . If you get 2.5571 round it to the nearest tenth and you should get 2.6


Answer:2.6



Step-by-step explanation:

Use your graphing calculator of you have one and if you don't you can find one online and plug in the equation and find the intersection . If you get 2.5571 round it to the nearest tenth and you should get 2.6


What does a formula do in a spreadsheet program?

A. It directs users to external resources that will help them analyze the data.

B. It instructs users how to use the data in the spreadsheet to calculate other important values for analysis.

C. It directs users where to enter important data and what ranges the values of those pieces of data should fall within.

D. It uses data entered in certain cells to calculate values for other cells.

please help.

Answers

The answer is D. Think back to the quadratic formula
You would plug in values of a, b, and c to find the zeros of the equations. It would the same way in a spreadsheet program where the cells contain the a, b, and c values but you can have more values and a different equation.

Answer:

D - it uses data entered in certain cells to calculate values for other cells

Step-by-step explanation:

A-p-e-x approved

A jogger is going running in a rectangular park that is 28 meters by 96 meters. Starting from where jogger's car is parked in the southeast corner, the jogger runs west along the width of the park and then north along the length. When the jogger reaches the northwest corner, she takes a shortcut straight back to her car. How far does the jogger run in all?

Answers

Final answer:

The jogger runs a total distance of 224 meters, which includes running along the width and length of the park and taking a shortcut diagonally across the park.

Explanation:

To calculate the total distance the jogger runs, we must add the distances from each leg of the jogger's path. Starting from the southeast corner, the jogger runs the width of the park (28 meters) to the west, and then the length of the park (96 meters) to the north, reaching the northwest corner. The shortcut from the northwest corner directly back to the southeast corner, where her car is parked, is the hypotenuse of the resulting right-angled triangle. To find the length of this hypotenuse, we use the Pythagorean theorem (a² + b² = c²), where the sides of the rectangle serve as 'a' and 'b'.

Let's calculate the hypotenuse:

a = 28 m (width)

b = 96 m (length)

c = √(a² + b²) = √(28² + 96²)

c = √(784 + 9216)

c = √10000

c = 100 m

Now, we sum up all the distances:

28 m (west along the width)

96 m (north along the length)

100 m (shortcut diagonally)

Total distance = 28 m + 96 m + 100 m = 224 meters

Kyle has entered into a 5k marathon (5 kilometers). He wanted to figure out how many miles are in the marathon. If there are 1000 meters in 1 kilometer, and 1 mile equals approximately 1609.34 meters, how many miles will Kyle run in the marathon? Round your answer to the nearest hundredth place.

Answers

Answer:

3.10 miles

Step-by-step explanation:

1k = 0.62 miles

5x.62= 3.10



Final answer:

Kyle will run approximately 3.11 miles in a 5K marathon. This calculation is performed by first converting the 5K race distance into meters and then into miles, rounding the result to the nearest hundredth place.

Explanation:

The subject of this question is conversions between different units of distance, specifically kilometers to miles. To help Kyle with this, first, we need to convert the kilometers into meters. Since 1 kilometer equals 1000 meters, therefore, 5 kilometers will be 5000 meters.

Then, remembering that 1 mile is approximately 1609.34 meters, we can divide the total meters by the conversion factor for meters to miles. Therefore, the conversion from meters to miles is as follows: 5000 meters / 1609.34 meters/mile = 3.11 miles.

So, if Kyle is running a 5K marathon, he will be running approximately 3.11 miles. This answer has been rounded to the nearest hundredth place as per your instructions.

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determine two numbers that have a sum of 12 but a difference of 12

Answers

Answer:

0 And 12

Step-by-step explanation:

0 + 12 = 12

But 0 is 12 away from 12. hope i helped :)

Answer:

0 and 12

Step-by-step explanation:

0+12=12

12-0=12

5 lb. 10 oz. − 3 lb. 1 oz. = lb. oz.

Answers

Answer:

2 lbs  9 oz

Step-by-step explanation:

Lets line up the ounces and pounds and subtract

  5 lb. 10 oz.

− 3 lb. 1 oz.

------------------------

2 lbs  9 oz


The result of subtraction of 5 lb. 10 oz. − 3 lb. 1 oz.  is: 2 lbs  9 oz.

Here, we have,

given that,

5 lb. 10 oz. − 3 lb. 1 oz.

so, we have to subtract them.

Lets line up the ounces and pounds and subtract

 5 lb. 10 oz.

− 3 lb. 1 oz.

------------------------

2 lbs  9 oz

Hence, The result of subtraction of 5 lb. 10 oz. − 3 lb. 1 oz.  is: 2 lbs  9 oz.

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State the domain and range of the following function. {(2,3), (7,9), (4,-7), (6,2), (3,-5)}

Answers

Answer:

Domain: {2,3,4,6,7}

Range: { -7,-5,2,3,9}

Step-by-step explanation:

The domain is the input, or x, values.

The range is the output, or y, values.

They are normally written from least to greatest.

Answer:

Domain: 2,3,4,6,7

Range: -7,-5,2,3,9

Step-by-step explanation:

hope this helps :)

FIRST TO ANSWER CORRECTLY IS BEING MARKED BRAINLIEST.Tanner has 30 stickers .he puts 6 stickers on each page.on how many pages does he put stickers on?

Answers

Answer:

5 pages

Step-by-step explanation:

30 sticker and 6 stickers on each page

30 divided by 6 = 5

Answer:

He puts stickers on 5 pages.


Select one of the factors of 5x^2 + 7x + 2.

A) (5x − 2)
B) (x + 2)
C) (5x + 1)
D) None of the above

Answers

Answer:

Correct choice is D

Step-by-step explanation:

Consider the quadratic expression [tex]5x^2 + 7x + 2.[/tex]

First, find the discriminant:

[tex]D=7^2-4\cdot 5\cdot 2=49-40=9.[/tex]

Now find the roots of the quadratic expression [tex]5x^2 + 7x + 2:[/tex]

[tex]x_{1,2}=\dfrac{-7\pm \sqrt{9}}{2\cdot 5}=\dfrac{-7\pm 3}{10}=-1,\ -0.4.[/tex]

Then

[tex]5x^2 + 7x + 2=5(x-(-1))(x-(-0.4))=5(x+1)(x+0.4)=(x+1)(5x+2).[/tex]

Joe's gas tank is 1/4 full. After he buys 6 gallons of gas, it is 5/8 full. How many gallons can Joe's tank hold?

Answers

Answer:

Amount of gas that can be hold by Joe's tank = 16 gallons.

Step-by-step explanation:

Given that Joe's gas tank is 1/4 full. After he buys 6 gallons of gas, it is 5/8 full. Now we need to find about how many gallons can Joe's tank hold.

So let's find change that happened after filling the gas.

Change = (5/8 full) - (1/4 full)

Change = (5/8 - 1/4)  full

Change = (5/8 - 2/8)  full

Change = (5 - 2)/8  full

Change = 3/8  full

So that means 3/8 full happens in 6 gallons

then 1 full will happen in 6/(3/8) gallons = 6*(8/3) gallons = 48/3 gallons = 16 gallons

So the amount of gas that can be hold by Joe's tank = 16 gallons.

Why is partitioning a directed line segment into a ratio of 1:3 not the same as finding the length of the directed line segment?

The ratio given is part to whole, but fractions compare part to part.
The ratio given is part to part. The total number of parts in the whole is 3 – 1 = 2.
The ratio given is part to part. The total number of parts in the whole is 1 + 3 = 4.
The ratio given is part to whole, but the associated fraction is .

Answers

Answer:

Third choice "The ratio given is part to part. The total number of parts in the whole is 1 + 3 = 4." is the correct answer.

Step-by-step explanation:

We know that partitioning a directed line segment into a ratio of 1:3 means that we are dividing the given line segment into two parts whose first part is 1 times the of some quantity while the another part is 3 times of the same quantity. So basically we are comparing part to part in by ratio. And total number of parts in the whole will be just sum of both so we get 1+3=4

Hence choice (3) is correct answer.

"The ratio given is part to part. The total number of parts in the whole is 1 + 3 = 4."

Answer:

it is C

The ratio given is part to part. The total number of parts in the whole is 1 + 3 = 4." is the correct answer.

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