How do i translate (x,y) ?

One of my questions is asking me to translate , (x,y) i know the formula for translating, (a,b) x+a,y+b But a=x and b=y. How do i solve this?

Final answer:

Jupiter has 67 moons.

Explanation:

To solve this problem, let's define j as the number of moons Jupiter has. According to the given information, Jupiter has 11 more than 4 times as many moons as Neptune, which has 14 moons. So, we can set up an equation: j = 4n + 11, where n is the number of moons Neptune has. Since Neptune has 14 moons, we can substitute that value into the equation: j = 4(14) + 11. Simplifying further, we get j = 56 + 11 = 67. Therefore, Jupiter has 67 moons.

[tex]A_{\triangle}=\dfrac{1}{2}bh\\\\\text{We have}\ b=7cm,\ h=4cm\\\\\text{Substitute:}\\\\A_{\triangle}=\dfrac{1}{2}(7)(4)=\dfrac{28}{2}=\boxed{14\ cm^2}[/tex]

Answer: 60 cans in each box

Step-by-step explanation:

98+82=180

180/3=60

Answer: Exponential

$35,000(1.03)^x

Step-by-step explanation:

Answer:

The answer is exponential hope this helps mark me brainliest.

Answer:

The band members of sixth graders are 28.

The band members of seventh graders are 14.

The percentage of the  band members eighth graders are 40% .

Step-by-step explanation

Formula

[tex]Percentage = \frac{Part\ value\times 100}{Total\ value}[/tex]

As given

There are 70 students in the school band.

40% of them are sixth graders, 20% are seventh graders, and the rest are eighth graders.

Now first find out the  band members are sixth graders .

Percentage = 40%

Total value = 70

Put in the formula

[tex]40 = \frac{Number\ of\ band\ members\ are\ sixth\ graders\times 100}{70}[/tex]

[tex]Number\ of\ band\ members\ are\ sixth\ graders = \frac{40\times 70}{100}[/tex]

[tex]Number\ of\ band\ members\ are\ sixth\ graders = \frac{2800}{100}[/tex]

[tex]Number\ of\ band\ members\ are\ sixth\ graders = 28[/tex]

Therefore the number of band members are from sixth graders are 28 .

Now first find out the  band members are seventh graders .

Percentage = 20%

Total value = 70

[tex]20 = \frac{Number\ of\ band\ members\ are\ seventh\ graders\times 100}{70}[/tex]

[tex]Number\ of\ band\ members\ are\ seventh\ graders = \frac{20\times 70}{100}[/tex]

[tex]Number\ of\ band\ members\ are\ seventh\ graders = \frac{1400}{100}[/tex]

[tex]Number\ of\ band\ members\ are\ seventh\ graders = 14[/tex]

Therefore the number of band members are from seventh graders are 14.

Now find out the percentage of the eighth graders of the band members.

Total number of band members = sixth graders members + seventh grade members + eighth graders members

As  sixth graders members =  28

seventh grade members = 14

Total number of band members = 70

Put in the above

70 = 28 + 14  + eighth graders members

70 - 42 = eighth graders members

28 = eighth graders members

Put in the percentage formula

[tex]Percentage = \frac{28\times 100}{70}[/tex]

[tex]Percentage = \frac{2800}{70}[/tex]

Percentage = 40%

Therefore the percentage of the band members are eighth graders is 40 %.

Answer:

The band members of sixth graders are 28.

The band members of seventh graders are 14.

The percentage of the  band members eighth graders are 40% .

Step-by-step explanation

Formula

As given

There are 70 students in the school band.

40% of them are sixth graders, 20% are seventh graders, and the rest are eighth graders.

Now first find out the  band members are sixth graders .

Percentage = 40%

Total value = 70

Put in the formula

Therefore the number of band members are from sixth graders are 28 .

Now first find out the  band members are seventh graders .

Percentage = 20%

Total value = 70

Step-by-step explanation:

Therefore the number of band members are from seventh graders are 14.

Now find out the percentage of the eighth graders of the band members.

Total number of band members = sixth graders members + seventh grade members + eighth graders members

As  sixth graders members =  28

seventh grade members = 14

Total number of band members = 70

Put in the above

70 = 28 + 14  + eighth graders members

70 - 42 = eighth graders members

28 = eighth graders members

Put in the percentage formula

Percentage = 40%

Therefore the percentage of the band members are eighth graders is 40 %.

Answer:  [tex]y -3 = \frac{4}{11} (x - 11)[/tex]

Step-by-step explanation:

We can use the point-slope formula to write the equation of a line given a point on the line and the slope of the line:  

Slope = m

Given point (x₁,y₁)

Formula = (y-y₁) = m(x-x₁)

Given point: (11,3); slope: 4/11

Answer : [tex]y - 3 = \frac{4}{11} (x - 11)[/tex]

[tex]\textit{\textbf{Spymore}}[/tex]​​​​​​

Answer:

4y-x

Step-by-step explanation:

Combine like-terms.

6y-2y and  -3x+2x

Do the Math

4y and -x

4y-x

Answer:

8 miles

Step-by-step explanation:

Given:

To take a taxi initial cost = $ 3.00

Per mile cost =  $ 2.00

Total spent = $20

Tip Given = $ 1

To find:

Total miles traveled=?

Solution:

Now the total cost f the ride was $ 20

As we see that initial cost for all the trips would stay the same

Let someone travels x miles

then according to the given

Initial cost + 2 * miles traveled + tip = total cost

Putting from the given values it becomes

3 + 2 * x + 1 = 20

Now we have to find x here which is the total miles traveled

solving the above equation

3+1+2x=20

4+2x=20

2x=20-4

2x=16

dividing both sides by 2

x =8 miles

so total miles travelled by the person is 8 miles

Answer: 8 miles you traveled.

Step-by-step explanation:

Hello from MrBillDoesMath!

Answer:

fourthroot(35)

Discussion:

The question is a bit unclear as to the desired answer.... but here goes!  

(35)^1/4 is the fourth root of 35, that is, symbolically,   fourthroot(35).

Note the fourth root of a number is the same as the square root of the square root of the number.

Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!

Answer:

C=25d

Step-by-step explanation:

We write an equation where C or cost is my output and d or days is my input. I should be able to put in any number of days and find the cost. Let's gather some data:

River Ramble

Day 1 $25(1)=25 cost

Day 2 $25(2)=50 cost

Day 3 $25(3)=75 cost

Day d $25(d)=C.

Our equation is C=25d.

[tex]\bf (\stackrel{x_1}{-7}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{-6}~,~\stackrel{y_2}{7}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{7-(-2)}{-6-(-7)}\implies \cfrac{7+2}{-6+7}\implies \cfrac{9}{1}\implies 9[/tex]

[tex]x^2+7x+12=x^2+4x+3x+12=x(x+4)+3(x+4)=(x+4)(x+3)\\\\-x^2-3x+4=-(x^2+3x-4)=-(x^2+4x-x-4)\\\\=-[x(x+4)-1(x+4)]=-(x+4)(x-1)\\\\f(x)=\dfrac{x^2+7x+12}{-x^2-3x+4}=\dfrac{(x+4)(x+3)}{-(x+4)(x-1)}\\\\\text{Vertical asymptotes:}\\\\(x+4)(x-1)=0\iff x+4=0\ \vee\ x-1=0\\\\\boxed{x=-4\ and\ x=1}\\\\\text{Horizontal asymptotes:}[/tex]

[tex]\lim\limits_{x\to\pm\infty}\dfrac{x^2+7x+12}{-x^2-3x+4}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\dfrac{7}{x}+\dfrac{12}{x^2}\right)}{x^2\left(-1-\dfrac{3}{x}+\dfrac{4}{x^2}\right)}=\dfrac{1}{-1}=-1\\\\\boxed{y=-1}[/tex]

Answer:

19.2

Step-by-step explanation:

[tex]\\\text{Consider the sum}\\\\9.327 + 5.72 + 4.132\\\\\text{To add the numbers, we add the whole parts together and the decimal parts together}\\\text{so we have}\\\\\ \ 9.327\\5.720\\4.132\\----\\19.179\\\\\text{we need to round the final answer to one decimal place.}\\\text{observe that the second digit after the decimal point is 7, which is greater than 5}\\\\\text{so we'll increase the digit before it by 1, so the sum of the numbers}\\\text{to one decimal place is }19.2[/tex]

Answer:

65

Step-by-step explanation:

Since <5 and <1 are corresponding angles and m is parallel to n

<5 = <1

<5 =65

so <1 = 65

Answer:

-1

Step-by-step explanation:

because if you put it in a equation for you get x^2-4=3x therefore you use the quadratic formula and solve the two answers you get are 4 and -1 so since its negative solution it must be -1 must be the square

The negative solution for a quadratic equation, set up to represent the expression 'When 4 is subtracted from the square of a number, the result is 3 times the number', is -1.

The subject of this question is a quadratic equation. If we let n be the number, the provided question can be rewritten as:

n² - 4 = 3n

To solve this equation for n, we rearrange terms to get a standard quadratic equation:

n² - 3n - 4 = 0

We can solve this equation using the quadratic formula:

n = [-b ± sqrt(b² - 4ac)] / (2a)

Substituting the values a = 1, b = -3, c = -4 into the formula, we obtain:

n = [3 ± sqrt((-3)² - 4 × 1 × -4)] / (2 × 1)

which simplifies to:

n = [3 ± sqrt(9 + 16)] / 2 = [3 ± sqrt(25)] / 2 = [3 ± 5] / 2

Thus we have two solutions:

n = 8/2 = 4 and n = -2/2 = -1

Since we are looking for the negative solution, the number we are looking for is -1.

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Answer:

Option D. 16

Step-by-step explanation:

Let

x ----> the number

we know that

The linear equation that represent this problem is equal to

[tex]\frac{3}{4}x-2=10[/tex]

Solve for x

Multiply by 4 both sides

[tex](4)*\frac{3}{4}x-2*4=10*4[/tex]

[tex]3x-8=40[/tex]

Adds 8 both sides

[tex]3x-8+8=40+8[/tex]

[tex]3x=48[/tex]

Divide by 3 both sides

[tex]3x/3=48/3[/tex]

[tex]x=16[/tex]

therefore

The number is 16

Answer:

B would be the answer for this question.

Step-by-step explanation:

Answer:  The fourth term is [tex]5000x^2.[/tex]

Step-by-step explanation:  We are given to find the fourth term in the expansion of the following binomial :

[tex]B=(2x+5)^5.[/tex]

We know that

the r-th term in the expansion of the binomial [tex](a+x)^n[/tex] is given by

[tex]T_r=^nC_ra^{n-(r-1)}b^{r-1}.[/tex]

For the given term, we have

n = 5  and  r = 4.

Therefore, fourth term is given by

[tex]T_4\\\\=^5C_{4-1}(2x)^{5-(4-1)}5^{4-1}\\\\=^5C_3(2x)^25^3\\\\=\dfrac{5!}{3!(5-3)!}\times4x^2\times125\\\\\\=\dfrac{5\times4}{2\times1}\times 500x^2\\\\=5000x^2.[/tex]

Thus, the fourth term is [tex]5000x^2.[/tex]

Answer:

The height of the object after 3 seconds is 45 feets.

Step-by-step explanation:

The height of an object thrown into the air with an initial upward velocity of 63 feet per second is given as

[tex]h(t)=-16t^2+63t[/tex]

Where, h(t) is height of the object in feet and t is the time in seconds.

We have to find the height of the object after 3 seconds. So, substitute t=3.

[tex]h(3)=-16(3)^2+63(3)[/tex]

[tex]h(3)=-16(9)+189[/tex]

[tex]h(3)=-144+189[/tex]

[tex]h(3)=45[/tex]

Therefore height of the object after 3 seconds is 45 feets.

To calculate the height of an object after 3 seconds using the equation h(t) = -16t^2 + 63t, substitute t with 3 and solve. This results in a height of 45 feet.

To find the height after 3 seconds, we substitute t with 3 into the equation, getting h(3) = -16(3)2 + 63(3). Calculating this step-by-step, we first find the square of 3, which is 9, and then multiply it by -16 to get -144. Next, we multiply 63 by 3 to get 189. Adding these two results together, we end up with 45 feet. Therefore, the height of the object after 3 seconds is 45 feet.

Answer:

4 and 32

Step-by-step explanation:

We are given paired values for two variables x and y and we are to fill in the missing values such that they are in a proportional relationship.

For x, we have the following paired values:

[tex]1, 3, ___, 5, 8[/tex]

So from the given options, 4 fits the best here which is greater than 3 and lesser than 5.

And for y, we have:

[tex]4, 12, 16, 20, ___[/tex]

Here, 32 fits the best from all the options as it is the next (available) number after 20.

Assuming this is for a programming language like c++, then the expression might look like

c = sqrt(a*a + b*b)

or you can use the pow function (short for power function)

c = sqrt( pow(a,2) + pow(b,2) )

writing "pow(a,2)" means "a^2"; similarly for b as well.

the length of hypotenuse can be found using the formula [tex]c = \sqrt{a^2+b^2}[/tex]

The pytharogas theorem states that:

[tex]hypotenuse^2 = perpendicular^2+ base^2[/tex]

The Pythagorean Theorem relates the length of the legs of a right triangle, labeled a and b, with the hypotenuse, labeled c. The relationship is given by:

[tex]a^2 + b^2 = c^2[/tex]

This can be rewritten, solving for c:

[tex]c = \sqrt{a^2+b^2}\\\\[/tex]

Thus, the length of hypotenuse can be found using the formula [tex]c = \sqrt{a^2+b^2}[/tex]

Answer:

C

Step-by-step explanation:

The slope intercept of a line is y=mx +b where

This graph crosses the y-axis (the vertical line) halfway between -1 and -2. This  is -3/2. This means only answers a, c, and d are options.

The graph moves up from -3/2 to its next point at (-4,0). We calculate the slope using:

Slope:[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

We substitute [tex]x_1=0\\y_1=-1.5[/tex] and [tex]x_2=-4\\y_2=2[/tex]

[tex]m=\frac{2-(-1.5)}{-4-0}[/tex]

[tex]m=\frac{2+1.5}{-4}=\frac{3.5}{-4} =-0.875[/tex]

This decimal is equivalent to -7/8. This means C is the answer.

This equation represents a line with a slope of [tex]\( -\frac{7}{8} \)[/tex](meaning the line slopes downward from left to right) and a y-intercept of [tex]\( -\frac{3}{2} \)[/tex](where the line crosses the y-axis). The correct answer is option c

The slope-intercept form of the equation of a line is [tex]\( y = mx + b \),[/tex] where m represents the slope of the line, and b represents the y-intercept (where the line crosses the y-axis).

Let's analyze each option:

a.[tex]\( y = -\frac{8}{7}x - \frac{3}{2} \):[/tex]

  - Slope [tex]\( m = -\frac{8}{7} \)[/tex]

  - y-intercept [tex]\( b = -\frac{3}{2} \)[/tex]

b. [tex]\( y = -\frac{3}{2}x + \frac{7}{8} \):[/tex]

  - Slope [tex]\( m = -\frac{3}{2} \)[/tex]

  - y-intercept[tex]\( b = \frac{7}{8} \)[/tex]

c.[tex]\( y = -\frac{7}{8}x - \frac{3}{2} \):[/tex]

  - Slope [tex]\( m = -\frac{7}{8} \)[/tex]

  - y-intercept [tex]\( b = -\frac{3}{2} \)[/tex]

d.[tex]\( y = \frac{7}{8}x - \frac{3}{2} \):[/tex]

  - Slope[tex]\( m = \frac{7}{8} \)[/tex]

  - y-intercept[tex]\( b = -\frac{3}{2} \)[/tex]

Among the given options, the correct slope-intercept form is option c:

[tex]\[ \boxed{y = -\frac{7}{8}x - \frac{3}{2}} \][/tex]

Answer: (3x-5)

Step-by-step explanation:

first we set it up x+3[tex]\sqrt{3x^2 +4x-15}[/tex]

we want to get rid of 3x^2 first so, x*3x= 3x^2

then we subtract x+3[tex]\sqrt{3x^2 +4x-15}[/tex]

distribute :3x*3=9x                 - (3x^2 +9x)

                                                   0 -5x

now we want to get rid of -5x, we use -5

-5(x+3)=-5x-15                x+3[tex]\sqrt{-5x-15}[/tex]

                                                           -(-5x-15)

                                                                  0, so reminder of 0

Answer:

[tex]I=12.5[/tex] amp

Step-by-step explanation:

The formula is,

[tex]E=\dfrac{P}{I}[/tex]

where,

E = Electromotive force in volts,

P = Power in watts,

I = Current in amps.

Given values are,

E = 3.6 volts,

P = 45 watts,

I = ??

Putting the values,

[tex]\Rightarrow 3.6=\dfrac{45}{I}[/tex]

[tex]\Rightarrow I=\dfrac{45}{3.6}=12.5[/tex] amp

Answer:

It would equal 98.14

Step-by-step explanation:

The greatest common factor of [tex]x^5y^2[/tex] and [tex]x^2y^7z[/tex]is [tex]x^2y^2[/tex].

To find the greatest common factor (GCF) of two or more terms, we need to identify the largest possible number that divides both terms evenly. In this case, we have two terms,[tex]x^5y²[/tex]and [tex]x²y^7z.[/tex]

Firstly, let's simplify the terms by removing any common factors. Here, we can see that both terms have 'x' and 'y' in common. So, let's remove them from both terms to simplify them.

[tex]x^5y²[/tex]becomes [tex]x^3y²[/tex]

[tex]x^2y^7z[/tex]becomes [tex]x^2y^5z[/tex]

Now, let's look for any common factors between these simplified terms. We can see that both terms have 'x' raised to the power of 2 in common. So, let's remove this factor from both terms.

[tex]x^3y²[/tex] becomes xy²

[tex]x^2y^5z[/tex] becomes [tex]xy^3z[/tex]

Now, let's look for any further common factors between these simplified terms. We can see that both terms have 'y' raised to the power of 2 in common. So, let's remove this factor from both terms.

xy² becomes xy

[tex]xy^3z[/tex] becomes xyz

Finally, we can see that both simplified terms now share a common factor of 'xy'. Therefore, 'xy' is the greatest common factor (GCF) of our original two terms, which is x²y² when we replace 'x' and 'y' with their original powers.

Answer:

A difference of squares has the following form [tex]a^2-b^2[/tex]. Any two perfect squares connected by subtraction can be factored.

It factors to (a+b)(a-b).

Step-by-step explanation:

A binomial is an expression with only terms where at least one is a term with a variable. When we can factor for difference of squares, we can have two variable terms or just one with a constant.

A difference of squares has the following form [tex]a^2-b^2[/tex]. Any two perfect squares connected by subtraction can be factored.

It factors to (a+b)(a-b).

Two supplementary angle when added together need to equal 180 degrees.

Answer:

Two supplementary angle when added together need to equal 180 degrees.

Step-by-step explanation: