Hexagon DEFGHI is translated 8 units down and 3 units to the right. If the coordinates of the pre-image of point F are
(–9, 2), what are the coordinates of F'?

(–17, 5)
(–6, –6)
(–17, –1)
(–12, –6)

In this mathematical problem involving weight reduction over time, Keith's dog has to lose 15 pounds to reach a healthy weight. If the dog can lose an average of 1.25 pounds per week, it would take the dog 12 weeks to achieve the desired weight.

The subject of the question is Mathematics, specifically a problem concerning weight loss over time, which is a real-world application of arithmetic and rate problems. In the given scenario, Keith's dog weighs 90 pounds, and the desired healthy weight is less than 75 pounds. Therefore, the dog needs to lose a total of 15 pounds. Given the dog can lose an average of 1.25 pounds per week, we can calculate the number of weeks it would take for the dog to reach a healthy weight.

Step 1: Identify the total amount of weight to be lost, which is the difference between the current weight and desired weight. This is calculated as 90 pounds - 75 pounds = 15 pounds.

Step 2: Divide the total weight to be lost by the average weight loss per week. This is calculated as 15 pounds ÷ 1.25 pounds per week = 12 weeks.

Therefore, it would take the dog 12 weeks to reach a healthy weight if he loses an average of 1.25 pounds per week.

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Answer: red sus tbh

Step-by-step explanation:

Answer: y (x)= 125 x

input :  number of visits "x"

output  :total cost "y"

Step-by-step explanation:

Hi, to answer this question we have to write an equation with the information given:

So, to obtain the total cost (y) we have to multiply the cost per visit by the number of visits (x)

y (x)= 125 x

Where the input is the number of visits "x" and the output is the total cost "y"

Feel free to ask for more if needed or if you did not understand something.

Answer:  They work for 2.5 hours to gift wrap  65 boxes.

Step-by-step explanation:

Since we have given that

Number of boxes Jack can wrap = 28

Time taken by him = 2 hours

Number of boxes Walter can wrap = 36

Time taken by him = 3 hours

Work done by Jack in  1 hour is given by

[tex]\frac{2}{28}\\\\=\frac{1}{14}[/tex]

Work done by Walter in 1 hour is given by

[tex]\frac{3}{36}\\\\=\frac{1}{12}[/tex]

So, Work done by both Jack and Walter in 1 hour is given by

L.C.M. of [tex](\frac{1}{14},\frac{1}{12})[/tex] is [tex]=\frac{l.c.m.\ of \ numerator}{h.c.f\ of\ denominator}=\frac{1}{2}[/tex]

Number of units done by Jack is given by

[tex]\frac{\frac{1}{2}}{\frac{1}{14}}\\\\=\frac{14}{2}\\\\=7\ units[/tex]

Number of units done by Walter is given by

[tex]\frac{\frac{1}{2}}{\frac{1}{12}}\\\\=\frac{12}{2}\\\\=6\ units[/tex]

So, Let the number of hours be 't' .

[tex]7t+6t=\frac{1}{2}\times 65\\\\13t=\frac{1}{2}\times 65\\\\t=\frac{1}{2}\times \frac{65}{13}\\\\t=\frac{5}{2}\\\\t=2.5\ hours[/tex]

So, They work for 2.5 hours to gift wrap  65 boxes.

Answer:

Step-by-step explanation:

A straight line can either have 1 y-intercept or infinitely many y intercepts. The only case in which there are infinitely many y-intercepts is when the line represents the y-axis itself. On y-axis, x is always 0. So the line that represents the y-axis is the line x=0. However, it is not a linear equation. In short, only the line representing y-axis has more than 1 y-intercepts. There cannot be such a linear equation(function).

A linear equation cannot have more than one y-intercept. Having multiple y-intercepts would violate the definition of a function as each input (x-value) should only be associated with one output (y-value). Therefore, a linear equation with multiple y-intercepts suggests an error.

In the field of mathematics, specifically in algebra and graphing, a linear equation cannot have more than one y-intercept. The y-intercept of a linear equation is the point at which the line crosses the y-axis on a coordinate plane. Linear equations are represented by the formula y = mx + b, where 'm' is the slope of the line and 'b' is the y-intercept. If an equation were to have more than one y-intercept, it would violate the definition of a function, which states that each input (or x-value) is only associated with one output (or y-value). Hence, if a linear equation was portrayed as having more than one y-intercept, it would imply an error in the equation or in the graph itself.

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When a trail branches off from a path with a 10° slope at a 45° angle, the angle of ascent of the branch trail is still 10° if the steepness remains constant.

If you are climbing a mountain by the steepest route at a slope of 10° and then encounter a trail that branches off at a 45° angle from your current path, we can calculate the angle of ascent of the branch trail using geometric relationships. To do this, we must comprehend that slopes can also be represented in percentages and are related to angles. For instance, a 100% slope corresponds to a 45° angle.

The steepest route you are initially taking has a 10° slope. When the branch trail diverts at a 45° angle from your path, this is not the angle of ascent but rather the angle between the two paths. If we consider a straight climb as a slope of 90°, your ascent angle would not change as it is still 10°. The branch trail effectively shifts direction but not necessarily the steepness of the path. Hence, the angle of ascent for the branch trail would also be 10°, assuming it maintains the same steepness as your original path.

To find out what number 125% is equal to 264, one should set up the equation 1.25x = 264 and solve for x, which gives x = 211.2.

The question asks to find a number such that 125% of it equals 264. To solve for the original number, we set up the equation 1.25x = 264, where 1.25 represents 125% in decimal form, and x is the unknown number we are solving for. We divide both sides of the equation by 1.25 to isolate x, giving us x = 264 / 1.25.

By performing this division, we get:

x = 211.2

Therefore, 125% of 211.2 is 264.

The Answer is B.

I took the unit review, as well as did the math myself,

Answer:

Average velocity is 32 miles/hr.

Step-by-step explanation:

Given that a particle moves on a line away from its initial position so that after t hours it is  [tex]s=6t^2+2t[/tex] miles from its initial position.

We have to find the average velocity of the particle over the interval [1, 4].

As, average velocity is the change is position over the change in time.

[tex]s(4)=6(4)^2+2(4)=104[/tex]

[tex]s(1)=6(1)^2+2(1)=8[/tex]

∴ [tex]\text{Average Velocity=}\frac{s(4)-s(1)}{4-1}[/tex]

                            =[tex]\frac{104-8}{3}=\frac{96}{3}=32miles/hr[/tex]

Hence, average velocity is 32 miles/hr.

The average velocity of the particle is [tex]\boxed{{\mathbf{21 units}}}[/tex] .

Further explanation:  

Velocity is the speed of an object in a given direction. Velocity is the vector quantity.

The average velocity can be calculated as,

[tex]{\text{average velocity}}=\frac{{{\text{distance travelled}}}}{{{\text{time taken}}}}[/tex]

Given:

The position of the particle after [tex]t[/tex]  hours is [tex]s\left(t\right)=4{t^2}+t[/tex] . The given interval is [tex]\left[{1,4}\right][/tex] .

Step by step explanation:

Step 1:  

The position of the particle after [tex]t[/tex]  hours is [tex]s\left(t\right)=4{t^2}+t[/tex]  

First we need to find the distance travelled in the interval of [tex]\left[{1,4}\right][/tex] .

The distance travelled by the particle at [tex]t=1[/tex]  is as follows,

[tex]\begin{gathered}s\left(t\right)=4{\left(t\right)^2}+t\hfill\\s\left(1\right)=4{\left(1\right)^2}+1\hfill\\s\left( 1 \right)=5\hfill\\\end{gathered}[/tex]

The distance travelled by the particle at [tex]t=4[/tex]  is as follows,

[tex]\begin{gathered}s\left(t\right)=4{\left(t\right)^2}+t\hfill\\s\left(4\right)=4{\left(4\right)^2}+1\hfill\\s\left( 1 \right)=68\hfill\\\end{gathered}[/tex]

Now find the distance travelled by the particle in the interval of [tex]\left[{1,4}\right][/tex]  .

[tex]\begin{aligned}{\text{distance travelled}}&=s\left(4\right)-s\left(1\right)\\&=68-5\\&=63\\\end{aligned}[/tex]

Step 2:  

The given interval is [tex]\left[{1,4}\right][/tex] .

Now we need to find the time as,

[tex]\begin{aligned}{\text{time elapsed}}&=4-1\\&=3\\\end{aligned}[/tex]

Step 3:  

Now we find the average velocity of the particle.

The average velocity can be calculated as,

[tex]\begin{aligned}{\text{average velocity}}&=\frac{{{\text{distance travelled}}}}{{{\text{time taken}}}}\\&=\frac{{63}}{3}\\&=21{\text{units}}\\\end{aligned}[/tex]

Therefore, the average velocity of the particle is [tex]21{\text{ units}}[/tex] .

Learn more:  

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Speed, distance and time

Keywords: velocity, initial position, particle, moves, interval, distance travelled, time elapsed, position, average velocity, units, vector quantity, speed, direction, hours.

Answer:

200 texts = same costs

Step-by-step explanation:

Plan A:   20 + (.05 x 200)

              20 +  10 =30

Plan B  10 + (.10 x 200)

            10 + 20 = 30

Answer:

f(x) = (x - 3)²

Step-by-step explanation:

If the function given below is g(x) = x²

Then we have to find the function f(x) which is same as g(x) but shifted 3 units left.

As we know in the given equation f(x) = (a + x)²+ k, x defines the shift of the function and and k defines the shift of a graph on y-axis upwards or downwards.

Here the graph is shifted left so the value of x will be (-3) which defines the shifting of 3 left on x-axis.

Therefore the new function will be f(x) = (x - 3)²

Answer:

F(x)=(x+3)^2

Step-by-step explanation:

Answer:

the answer is b.63

Step-by-step explanation:

Hello, I can help you with this

Step 1

to solve this you must divide the money Mr Smith has by the price of a stock per share, it is

Money Mr smith has = $200

The price of a stock is $3.17

[tex]\frac{200 usd}{3.17\frac{usd}{share} }\\ =63.09\ shares\\\\[/tex]

he cand by  whole shares, so he can buy exactly 63 shares

so, the answer is b.63

I really hope it helps, Have a great day.