*help please* What is the amplitude of the function graphed?

*help Please* What Is The Amplitude Of The Function Graphed?

Answers

Answer 1

So amplitude is the length from the highest (or lowest) point from the mid-line of the function

In this case the mid-line is y = 1

The highest point, which has a y of 3 is 2 units away from the mid-line. This means that the amplitude is 2!

Hope this helped!

Answer 2

The amplitude of the function graphed will be 2.

What is amplitude ?

The amplitude of a function is the amount by which the graph of the function travels above and below its midline, i.e. it is the height from the mean value of the function to its maximum or minimum.

We have,

A graph,

The highest value = 3,

Lowest value = -1

So,

From the definition mentioned above,

Amplitude [tex]=\frac{3+|-1|}{2}[/tex]

We get,

Amplitude = 2

Hence, we can say that the amplitude of the function graphed will be 2.

To know more about amplitude click here

https://brainly.com/question/17942624

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Related Questions

Given: AB ≅ BC BD − median of ΔABC, m∠ABD = 40° Find: m∠ABC, m∠BDC

Answers

Answer:

m∠ABC= 80°, m∠BDC= 90°

Step-by-step explanation:

If m∠ABD = 40°, then add 40°+40° to get m∠ABC because AB ≅ BC, meaning their angles would be congruent.

For m∠BDC, just look at the picture and deduce that it's a 90 degree angle.

Answer:

m∠ABC=80° and m∠BDC=90°

Step-by-step explanation:

Given the ΔABC in which AB ≅ BC, m∠ABD = 40° and BD is median of ΔABC.

we have to find the measure of angle ∠ABC and ∠BDC.

As the median of isosceles triangle split the angle at the vertex into two equal parts i.e ∠ABC is twice the angle ∠ABD

[tex]\angle ABC=2\angle ABD[/tex]

[tex]\angle ABC=2\times 40=80^{\circ}[/tex]

Also the median of isosceles triangle is perpendicular to the opposite side i.e to the base. Here, BD is perpendicular to AC

⇒  ∠BDC=90°

Therefore, the measure of angle ABC and BDC is 80° and 90° respectively.

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