Help me with the first question

Answer:

$162.97 is the exact answer.

Step-by-step explanation:

Answer:38200000 Is the correct answer

Step-by-step explanation:

Answer: The height of the stacked boxes is 31 meters.

Step-by-step explanation:

Since, the Volume of a cube = (side)³

The volume of first box = 1331 cubic meters,

⇒ (side)³ = 1331

⇒

Similarly, the side of second box = 11 meters ( Because, both boxes have the same volume )

Now, the volume of third box = 729 cubic meters

⇒ ⇒ (side)³ = 729

⇒

Thus, the height of the stacked boxes = Side of first box + side of second box + side of third box

= 11 + 11 + 9

= 31 meters.

Answer:

a) 8 : 11

b) 8:3

Step-by-step explanation:

Given: The total number of apples in the basket = 11

The number of green apples = 3

Then , the number of red apples = [tex]11-3=8[/tex]

a) The ratio of red apples to all apples in the basket will be :-

[tex]\dfrac{\text{Number of red apples}}{\text{Total apples}}=\dfrac{8}{11}=8 : 11[/tex]

b) The ratio of red apples to green apples will be :-

[tex]\dfrac{\text{Number of red apples}}{\text{Number of green apples}}=\dfrac{8}{3}=8 : 3[/tex]

Final answer:

The velocity of the ball at t = 1 second is found by taking the derivative of the position function s(t) and evaluating it at t = 1. The derived velocity function is v(t) = -32t + 20, and the velocity at t = 1 second is 8 ft/sec.

Explanation:

The student wants to find the velocity of a ball at t = 1 second when thrown vertically upward from the top of a 100-foot tower with an initial velocity of 20 ft/sec. The position function given is [tex]s(t) = -16t^2 + 20t + 100[/tex]. To find velocity, we need to take the derivative of the position function with respect to time, which represents the velocity function v(t).

The derivative of the position function is:
v(t) = −32t + 20.

To find the velocity at t = 1 second, substitute 1 for t:
v(1) = −32×1 + 20 = −12 + 20 = 8 ft/sec.

Therefore, the velocity of the ball at t = 1 second is 8 ft/sec.

[tex] \dfrac{y}{-6}+5=9\ \ \ \ |-5\\\\\dfrac{y}{-6}=4\ \ \ \ |\cdot(-6)\\\\y=-24 [/tex]

Answer:

A

Step-by-step explanation:

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To find the exact solutions of the given equation 2sec^2x-tan^4x=-1, we can simplify the equation using trigonometric identities and solve for tanx. The solutions are x = pi/3 + n*pi for tanx = sqrt(3), and x = -pi/4 + n*pi for tanx = -1.

The given equation is 2sec^2x-tan^4x=-1. To solve this equation, we need to simplify the trigonometric terms using known identities. The identity sec^2x = 1 + tan^2x can be used here. Substituting this identity into the equation gives us 2(1 + tan^2x) - tan^4x = -1. Simplifying further, we have 2 + 2tan^2x - tan^4x = -1. Rearranging the terms, we get tan^4x - 2tan^2x - 3 = 0.

Now, let's substitute tan^2x with u, giving us the equation u^2 - 2u - 3 = 0. This is a quadratic equation that can be factored as (u - 3)(u + 1) = 0. Solving for u, we have u = 3 or u = -1. Substituting back tan^2x for u, we get tan^2x = 3 or tan^2x = -1. Taking the square root of both sides, we have tanx = sqrt(3) or tanx = -1.

Finally, to find the exact solutions of x, we need to consider the periodic nature of trigonometric functions. Since tanx repeats every pi radians, the solutions are x = pi/3 + n*pi, where n is an integer, for tanx = sqrt(3), and x = -pi/4 + n*pi, for tanx = -1.

To solve this problem, what we have to do is to divide the whole equation 4 x^4 – 2 x^3 – 6 x^2 + x – 5 with the equation 2 x^2 + x – 1. Whatever remainder we get must be the value that we have to subtract from the main equation 4 x^4 – 2 x^3 – 6 x^2 + x – 5 for it to be exactly divisible by 2 x^2 + x – 1.

By using any method, I used long division we get a remainder of -6.

Therefore we have to subtract -6 from the main equation which results in:

4 x^4 – 2 x^3 – 6 x^2 + x – 5 – (-6) = 4 x^4 – 2 x^3 – 6 x^2 + x + 1

Answer:

(5,32)

Step-by-step explanation:

This question deals with the physics of projectile motion and rocket trajectories. By analyzing the given equations for acceleration and position over time, we can determine the units of constants and describe the motion of the rockets, emphasizing their parabolic paths.

The question at hand involves understanding the motion of two rockets using principles of physics and applying mathematical functions to describe their trajectories. For rocket A, the given quadratic function A(t) = −(t − 8)2 + 535, describes its height as a function of time, indicating a parabolic trajectory, which is typical for projectiles under gravity's influence.

In rocket motion, the acceleration can sometimes be described by an equation of the form a(t) = A - Bt1/2. Here, A and B are constants that determine the rocket's changing acceleration over time. The units of A would be meters per second squared (m/s2), since it represents acceleration, and the units of B would have to be meters per second to the power of five halves (m/s5/2) to ensure the units of time (t) cancel out correctly. When a rocket starts from rest, its velocity changes over time, initially increasing but then possibly decreasing if the acceleration is negative due to the subtraction of the term involving Bt1/2.

If the initial position is set to zero, the rocket's position as a function of time can be found by integrating the velocity function, which is the integral of the acceleration function with respect to time. This integration process accounts for the initial conditions and gives a complete description of the rocket's motion.

In the context of projectile motion, the trajectory is indeed parabolic, represented by the equation y = ax + bx2. To prove this, we use the kinematic equations that separately describe the horizontal and vertical motions (x = Voxt for horizontal and y = Voyt - (1/2)gt2 for vertical motion) and eliminate the time variable to find y as a function of x.

Answer:

The value of given expression is 49.

Step-by-step explanation:

The given expression is

[tex](3+4)^2[/tex]

On solving the parenthesis, we get

[tex](3+4)^2=7^2[/tex]

It can written as

[tex](3+4)^2=7\times 7[/tex]

On multiplication, we get

[tex](3+4)^2=49[/tex]

The simplified value of given expression is 49.

Therefore the required value is 49.

The mathematical rule (x,y) to (x-2, y-7) signifies a transformation in the coordinate plane shifting points 2 units to the left and 7 units down. To apply this rule to any point, subtract 2 from the x-coordinate and 7 from the y-coordinate.

The rule (x,y) to (x-2,y-7) in Mathematics signifies a specific transformation in a coordinate plane. This is essentially a rule used in graph transformations to shift a point in the coordinate plane. In this specific rule, every point (x, y) is shifted 2 units to the left and 7 units down to get the new point (x-2, y-7). For example, if we take a point, (5,10), applying this rule means we subtract 2 from the x-coordinate and 7 from the y-coordinate resulting in a new point (3,3). Therefore, simplifying this process, to apply the rule (x,y) to (x-2,y-7) to any point, all you need to do is subtract 2 from the x-coordinate and 7 from the y-coordinate of the point.

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C(n,r)=C(7,6) 

Final answer:

There are 7 different ways to select a committee of 6 people from a group of 7 candidates, calculated using the combinations formula C(7, 6) = 7! / (6! * (7 - 6)!) = 7.

Explanation:

The question is asking to determine the number of different ways a committee can be selected from a group of candidates, which is a common problem in combinatorics, a branch of mathematics. To find the number of different ways a committee of 6 people can be selected from a group of 7 candidates, you can use combinations. Since the order in which the committee is chosen does not matter, you calculate combinations and not permutations. The formula for combinations is:

C(n, k) = n! / (k! * (n - k)!)

Applying the formula:

C(7, 6) = 7! / (6! * (7 - 6)!) = 7 / 1 = 7

Therefore, there are 7 different ways to select a committee of 6 people from a group of 7 candidates.

To find the number of students in the larger class, set up a system of equations using the given information. Solve the system to find the value of x, which represents the number of students in the larger class. The larger class has 28 students.

To find the number of students in the larger class, we can set up a system of equations. Let's call the number of students in the larger class x, and the number of students in the smaller class y. The problem states that one class has 6 more students than the other, so we can write the equation x = y + 6.

We also know that the two classes have a total of 50 students, so x + y = 50. We can solve this system of equations to find the value of x, which represents the number of students in the larger class.

Using the second equation, we can substitute the value of x from the first equation into the second equation: (y + 6) + y = 50. Simplifying this equation, we get 2y + 6 = 50. Next, subtract 6 from both sides to isolate the variable: 2y = 44. Finally, divide both sides by 2 to solve for y: y = 22. Now, we can substitute this value of y back into the first equation to find x: x = 22 + 6 = 28. Therefore, there are 28 students in the larger class.

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Answer:

50.24 square units

Step-by-step explanation:

Hope this helps.