Answer: h = 15
Step-by-step explanation:
Volume (V) = Length (L) × width (w) × height (h)
1386 = 14 × 9 × (h - 4)
[tex]\dfrac{1386}{14\times 9}=h-4[/tex]
11 = h - 4
11 + 4 = h
15 = h
help me please asap!
Answer:
[tex](x^2-9)(x^2+9)\\(x-3)(x+3)(x^2+9)[/tex]
Step-by-step explanation:
To factor the expression, factor as a difference of squares. Find the square root of each term and write it in this form (x+a)(x-a).
[tex]x^4 - 81\\(x^2 - 9)(x^2 + 9)[/tex]
Factor x² - 9 as a difference of squares.
[tex](x^2-9)(x^2+9)\\(x-3)(x+3)(x^2+9)[/tex]
This is the most factored form because a sum of squares cannot be factored.
what is the value of x
Answer:
The answer to your question is that x is equal to 50.
A parking lot in a shape of a trapezoid has an area of 12,052.1 square meters.the lean the of one base is 82.4 meters and the length of the other base is 108.6 meters.what is the height of the parking lot?
Answer:
126.2 meters
Step-by-step explanation:
A trapezoid's area is found using the formula A = 1/2 (a+b)h where a and b are the two bases. Substitute A = 12,052.1, a = 82.4 and b=108.6. Then solve for h.
A = 0.5(a+b)h
12,052.1 = 0.5(82.4 + 108.6)*h
12,052.1 = 0.5(191)h
12,052.1 = 95.5h
126.2 = h
The student body at a high school was surveyed about sports participation. The table below shows the data by grade level.
The number of students who are in 9th grade and play two or more sports is a
'marginal frequency'
'Joint frequency'
The number of students who are in the 11th grade is a
'marginal frequency'
'joint frequency'
The percentage of the student body that plays one sport is a
'marginal relative frequency'
'joint relative frequency'
The percentage of the student body that are in 12th grade and do not play a sport is a
'marginal relative frequency'
'joint relative frequency'
Marginal frequency:
The number in the end column or row - "Total".
Joint frequency:
The ratio of the frequency in a particular category and the total number of data values.
Basically, the values that aren't in the final row or column - "Total".
The number of students who are in 9th grade and play two or more sports is a joint frequency.
This is only asking for the students in 9th grade who play two or more sports.
The number of students who are in the 11th grade is a marginal frequency.
This is asking for the total number of students in 11th grade.
The percentage of the student body that plays one sport is a marginal relative frequency'.
This is asking for the total number of students who play 1 sport.
The percentage of the student body that are in 12th grade and do not play a sport is a joint relative frequency.
This is only asking for the students in 12th grade and don't play sports.
Answer:
The answer is D on edge
The function g is defined by g(x)=ax−7, where a is a constant. Find a, if the graph of g passes through the point ( 1/3 ,−2).
Answer:
a = 15
Step-by-step explanation:
The graph of function g(x) is described by g(x)=ax−7, or y = ax−7.
y = g(x)=ax−7 passes through (1/3, -2). We can subst. -2 for y and 1/3 for x to determine the value of the coefficient a:
-2 = g(1/3) = a(1/3) - 7
Solve for a. First, add 7 to both sides: 5 = a(1/3).
Next, multiply both sides by 3: 15 = a, or a = 15.
twelve more than the quotient of a number and eight
Answer:
12+x/8
Step-by-step explanation:
Answer:
17
Step-by-step explanation:
i hope it helps if not 17 then it is ..................... 12+x/8
What number is the same as 10^-5
Answer:
0.00001
Step-by-step explanation:
1
______
100000
hope this helps
The set of ordered pairs in the mapping below can be described as which of the following?
x----y
0 - 8
3 - 2
6 - -1
(1) a relation only
(2) a function only
(3) both a relation and a function
(4) neither a relation nor a function
Answer:
"(3)"
Step-by-step explanation:
Relation is a mapping between x-values and y-values. Xs are the domain and Ys are the range.
Given x values (0,3,6) and y-values(8, 2, -1), this is a relationship, so it is a relation.
To check whether a relation is a function or not, we simply see if each unique x value is paired with a unique y value.
Is there any y value that is same for x-values? NO! All are different. So this is a function as well!
Answer choice (3) is right.
Answer: (3) both a relation and a function
Step-by-step explanation:
Relation : It is the relation established between two set of values
Function : It is a kind of relation, where only output exist for e ach input.
Generally x values presents input values and y values represents the output values.
The given table :
x - y
0 - 8
3 - 2
6 - 1
Here, each x value is related to a y-value , so its a relation.
Also, there only one unique y-value for each x-values, thus its a function.
Hence, the set of ordered pairs in the mapping below can be described as both a relation and a function.
The product of 17 and 1.27
Answer:
1.27 x 17 = 21.59 Product means multiply
Step-by-step explanation:
Answer:
21.59
Step-by-step explanation:
17 x 1.27 = 21.59
21.59/17=1.27
What is the mode of the data set?
Fifth Grade Jump Distance
2|0
3|2 4 6
4|0 2 4 8
5|5
6|5
2|0 = 20 inches
The data set is
20
32, 34, 36
40, 42, 44, 48
55
65
We can see that each value only shows up one time. Therefore there is no mode. To have a mode, we need to have a value show up more than once, and it must be the most frequent value. For example, the set {1,2,3,3,4} has a mode of 3 since it shows up twice, the most of any value in that set. However we don't have that occur for the data set your teacher gave you.
Final Answer: There is no mode for this data setAnswer:
no mode i just got it right
Step-by-step explanation:
A rectangle prism has a length of 3 1/2 inches a width of 5 inches and height of 1 1/2 inches what is the volume
Answer:
Step-by-step explanation: I hope that helps you.
Analyze the sequence 243, 162, 108, 72,…
Answer: You multiply 1.5 each time.
Step-by-step explanation:
72*1.5=108
108*1.5=162
162*1.5=243
And so on and so forth.... Hope it helped!
243 = 3x3x3x3x3
162 = 3x3x3x3x2
108 = 3x3x3x2x2
72 = 3x3x2x2x2
The next two numbers in the sequence would be
48 = 3x2x2x2x2
32 = 2x2x2x2x2
The sum of 1 and 3 times a number is 22
A. X= 4
B. X= 6
C. X= 7
D. X= 9
12 = g - 56
(Solve for g)
Answer:
G=68
Step-by-step explanation:
First get G by it's self
By adding 56 on both sides
12 plus 56 equals 68
G=68
I Hope this helps you
I need help with 9 please
Answer:
12
Step-by-step explanation:
Treat the less than or equal too sign as you would a normal equal sign.
Add 27 to -15 so that x is less than or equal to 12
what is 4 radical sign 5 equivalent to
Answer:
1.31950791
Step-by-step explanation:
I don't actually know if this is correct
Hey guys please help, thanks so much
12) D'(3, 1) E'(1, -2) F'(5, 0)
13) Vertex E
14) D'(3, 1)
15) D'(1, 3) E'(3, 0) F'(-1, -2)
16) D'(-11, 11) E'(13, 8) F'(-9, 6)
P'(-9, 10) Q'(-7, 12) R'(-5, 10)
17) Translate 4 units down; (x, y) ---- (x, y - 4)
18) P'(-1, 2) Q'(-3, 4) R'(-5, 2)
19) P'(-2, 1) Q'(-4, 3) R'(-2, 5)
20) P'(-1, -2) Q'(-3, -4) R'(-5, -2); Rotated 180° about the origin
21) P'(3, 6) Q'(9, 12) R'(15, 6)
22) A'(-9, 0) B'(0, 12) C'(9, 0) D'(0, -12)
23) Image (yes, the answer is actually Image)
24) (x, y) → (1.5x, 1.5y)
This took me 45 mins to do, lol.
You're welcome? :) <3
help subtract (xsquared +43x10)-(10xsquared-5x+10 express the answer in standard form
Answer:
[tex]\large\boxed{(x^2+43x+10)-(10x^2-5x+10)=-9x^2+48x}[/tex]
Step-by-step explanation:
[tex](x^2+43x+10)-(10x^2-5x+10)\\\\=x^2+43x+10-10x^2-(-5x)-10\\\\=x^2+43x+10-10x^2+5x-10\qquad\text{combine like terms}\\\\=(x^2-10x^2)+(43x+5x)+(10-10)\\\\=-9x^2+48x[/tex]
if f={(2,3),(5,7),(3,3),(5,4),(9,1)} what is the range
[tex]\bf \stackrel{\textit{range is always the set of y-coordinates}}{f=\{(2,\stackrel{\downarrow }{3}),(5,\stackrel{\downarrow }{7}),(3,\stackrel{\downarrow }{3}),(5,\stackrel{\downarrow }{4}),(9,\stackrel{\downarrow }{1})\}}\qquad \qquad \{3,7,3,4,1\}\implies \{3,7,4,1\}[/tex]
Answer:
{3, 7, 3, 4, 1}
Step-by-step explanation:
Match the functions with their inverse functions.
The answers are:
[tex]f(x)=\frac{5x+3}{2}[/tex]
[tex]f(x)=2x-8[/tex]
[tex]f(x)=7x-2[/tex]
[tex]f(x)=\frac{1}{x+2}[/tex]
Why?To find the inverse function of a function, we need to replace the variable (x for this case) for the function itself (f(x)), where we see "x" we must rewrite with "y" or "f(x) and then, isolate "y" or "f(x). If we have the inverse function and we want to find the function, we need to reverse the process.
Let's find each function of the given inverse functions in order to match each one with its inverse.
First inverse function,
[tex]f^{-1}(x)=\frac{2x-3}{5}[/tex]
Replacing "x" with "f(x)" and "f-1(x)" with "x" we have:
[tex]x=\frac{2f(x)-3}{5}\\\\5x=2f(x)-3\\\\5x+3=2f(x)\\\\f(x)=\frac{5x+3}{2}[/tex]
Therefore, the function that matches with the first inverse function is:
[tex]f(x)=\frac{5x+3}{2}[/tex]
Second inverse function,
[tex]f^{-1}(x)=\frac{x+8}{2}[/tex]
Replacing "x" with "f(x)" and "f-1(x)" with "x" we have:
[tex]x=\frac{f(x)+8}{2}\\\\2x=f(x)+8\\\\2x-8=f(x)\\\\f(x)=2x-8[/tex]
Hence, the function that matches with the second inverse function is:
[tex]f(x)=2x-8[/tex]
Third inverse function,
[tex]f^{-1}(x)=\frac{x+2}{7}[/tex]
Replacing "x" with "f(x)" and "f-1(x)" with "x" we have:
[tex]x=\frac{f(x)+2}{7}\\\\7x=f(x)+2\\\\7x-2=f(x)\\\\f(x)=7x-2[/tex]
So, the function that matches with the third inverse function is:
[tex]f(x)=7x-2[/tex]
Fourth inverse function,
[tex]f^{-1}(x)=\frac{1-2x}{x}[/tex]
Replacing "x" with "f(x)" and "f-1(x)" with "x" we have:
[tex]x=\frac{1-2f(x)}{f(x)}\\\\xf(x)=1-2f(x)\\\\f(x)x+2f(x)=1\\\\f(x)(x+2)=1\\\\f(x)=\frac{1}{x+2}[/tex]
So, the function that matches with the fourth inverse function is:
[tex]f(x)=\frac{1}{x+2}[/tex]
Have a nice day!
One angle is 36 degrees. What is the measure of its complement?
Answer:
54
Step-by-step explanation:
90-36=54 degrees. The complement of an angle is 90- the angle
7 square root of 75 simplify
7√75 = 7√25√3 = 35√3.
The simplification of the expression 7 * square root of 75 is 35 * square root of 3. This is achieved by factoring 75 into prime factors and finding pairs of those factors to take out from under the square root.
Explanation:To simplify the expression 7 * square root of 75, we first need to break down 75 into a product of prime factors:
75 = 5*5*3.
Since the square root of a number is the factor that, when squared, equals the original number, we can take out a pair of 5s from the square root:
Square root of 75 = 5 * square root of 3.
Finally, multiply this by 7 to get:
7* square root of 75 = 7 * 5 * square root of 3 = 35 * square root of 3.
Learn more about Square Root here:https://brainly.com/question/1540542
#SPJ2
Which equations could be used to find the length of a side in a right triangle with legs a and b and hypotenuse of c?
The Pythagorean Theorem says for a right triangle with legs a,b and hypotenuse c,
[tex]c^2 = a^2+b^2[/tex]
Solving for each in turn,
[tex] c= \sqrt{a^2+b^2}[/tex]
[tex]a^2=c^2 - b^2[/tex]
[tex]a = \sqrt{c^2-b^2}[/tex]
[tex]b = \sqrt{c^2-a^2}[/tex]
Looking at our choices, we select the third and fourth.
The pythagorean theorem states that, in every right triangle, the following formula holds:
[tex]a^2+b^2=c^2[/tex]
where a and b are the legs, and c is the hypotenuse.
We can deduce the following expressions for a,b and c:
[tex]a = \sqrt{c^2-b^2},\quad b=\sqrt{c^2-a^2},\quad c=\sqrt{a^2+b^2}[/tex]
Does anyone know how to tell whether a number in bold is a solution? 35 points
The teacher passed out math books.The length is 10 inches and the width is 8 inches.What is the perimeter of each book?
Answer: The perimeter of each book is: " 36 in. " .
__________________________________________________
Step-by-step explanation:
__________________________________________________
Note that the given units are all in "inches (in.)" .
Use the formula for the "perimeter of a rectangle" ;
{which happens to work for a "square" as well;
since a "square" is a rectangle.}.
__________________________________________________
This is based on the assumption that the book is shaped like a
"rectangle" (or "square" —which is a rectangle).
__________________________________________________
The formula for the Perimeter of a rectangle is:
P = 2 L + 2 w ;
in which:
P = the perimeter of the rectangle;
for which we shall solve; [in "inches (in.)" ] ;
L = the length of the rectangle = 10 in. (given) ;
w = the width of the rectangle = 8 in. (given) .
___________________________________________________
Now, plug the given values for the "length (L)" and the "width (w)" ;
as follows:
___________________________________________________
P = (2 * 10 in.) + (2 * 8 in.) ;
P = (20 in.) + (16 in.) ;
P = 36 in.
___________________________________________________
Answer: The perimeter of each book is: " 36 in. " .
___________________________________________________
Hope this helps!
Best wishes in your academic pursuits
— and within the "Brainly" community!
___________________________________________________
evaluate i^31 please help
ANSWER
[tex] {i}^{31} = - i[/tex]
EXPLANATION
We want to evaluate
[tex] {i}^{31} [/tex]
Use indices to rewrite the expression as:
[tex] = {i}^{30} \times i[/tex]
We know that
[tex] {i}^{2} = - 1[/tex]
So we rewrite the expression to obtain;
[tex] = ({ {i}^{2}) }^{15} \times i[/tex]
This gives us;
[tex]= {( - 1) }^{15} \times i[/tex]
This simplifies to
[tex] = - 1 \times i[/tex]
[tex] = - i[/tex]
Plz help!!!!!!!!!!!!!
Answer:
the third one
Step-by-step explanation:
-b to start is -(-6) which is 6
needs the plus and minus
the first expression is the whole numerator
Answer: [tex]\bold{c)\quad x=\dfrac{6\pm \sqrt{(-6)^2-4(3)(8)}}{2(3)}}[/tex]
Step-by-step explanation:
[tex]3x^2-6x+8=0\quad \rightarrow \quad a=3,\ b=-6,\ c=8\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-6)\pm \sqrt{(-6)^2-4(3)(8)}}{2(3)}}\\\\\\x=\dfrac{6\pm \sqrt{(-6)^2-4(3)(8)}}{2(3)}[/tex]
Jeremiah has a batting average of 0.312 this baseball season. Express his average as a fraction in lowest terms.
312/1,000
39/125
13/50
13/42
There is not much that can be done to figure out how to write 0.312 as a fraction, except to literally use what the decimal portion of your number, the .312, means. Since there are 3 digits in 312, the very last digit is the "1000th" decimal place. So we can just say that .312 is the same as 312/1000.
Jeremiah's batting average of 0.312 can be expressed as the fraction 312/1,000, which can be further reduced to its simplest form 39/125 by dividing by their greatest common divisor, which is 8.
Explanation:To express Jeremiah's batting average of 0.312 as a fraction in lowest terms, we need to start by expressing it as a fraction out of 1,000, which gives 312/1,000. From there, we divide both the numerator (the top number) and the denominator (the bottom number) by their greatest common divisor to reduce it to its simplest form. The greatest common divisor of 312 and 1,000 is 8. If we divide 312 by 8, we get 39, and if we divide 1,000 by 8, we get 125. Therefore, the fraction in its simplest terms is 39/125.
Expressing decimals as fractions is a common task in Mathematics and it's a handy skill for dealing with real-world data, like a baseball player's batting average.
Learn more about Converting Decimals to Fractions here:https://brainly.com/question/2362378
#SPJ3
Plz help
simplify (2x+1) (3x+4)
[tex](2x + 1)(3x + 4) \\ = 2x(3x + 4) + 1(3x + 4) \\ = 6 {x}^{2} + 8x + 3x + 4 \\ = 6 {x }^{2} + 11x + 4[/tex]
Out of 6700 students of a school only 90% passed. Find how many students passed?
Answer:
6030 students passed.
Step-by-step explanation:
First: We must convert all percentages to decimals:
So, why do we need to convert all percentages to decimals. Well, you don't have to. It's just that it's easier to work with decimals than percentages. So I'll bold out all of the percents in this problem:
Out of 6700 students of a school only 90% passed. Find how many students passed?
So how do we convert that to a decimal. Well...
A: We have to take out the percent sign:
90
B: We have to move the decimal point 2 spaces to the left:
0.90
Now that we have our percent displayed as a decimal, we need to multiply it by the total number of students to find the fraction of people that passed.
So 0.90 [or 0.9] multiplied by 6700
[tex]0.9*6700 = 6030[/tex]
So, out of the 6700 students, 6030 passed.
Topic: Percentages