In the case of a one-dimensional elastic collision where half the kinetic energy is transferred from one object to another initially at rest, the mass ratio between the moving and stationary objects is 3:1, derived from principles of kinetic energy and momentum conservation.
Explanation:The question relates to finding the mass ratio of two objects in a one-dimensional elastic collision where half of the kinetic energy of the moving object is transferred to the initially stationary object. To arrive at the solution, we need to consider the principles of conservation of momentum and conservation of kinetic energy.
For elastic collisions, the total kinetic energy before collision is equal to the total kinetic energy after collision. If half of the kinetic energy of object 1 is transferred to object 2, and given that kinetic energy is proportional to the mass of the object and the square of its velocity (KE = 1/2 mv2), we can deduce that the kinetic energy ratio post-collision influences the mass ratio.
Here, the conservation of kinetic energy and the given condition imply a specific relationship between the masses, leading us to the conclusion that for half the kinetic energy to be transferred, the mass of the moving object must be three times that of the stationary object, yielding a mass ratio of 3:1. This result is derived from manipulating the formulas for kinetic energy and conservation of momentum to reflect the energy transfer condition.
Describe the circumstances for which the output work would equal the input work in a machine
A container of gas is at a pressure of 1.3x10^5 Pa and a volume of 6 m^3. How much work is done by the gas if it expands at a constant pressure to twice its initial volume.
The work done by the gas is 7.8x10^5 J.
Explanation:To determine the work done by the gas as it expands at a constant pressure, we can use the formula:
Work = Pressure x Change in Volume
Given that the initial volume is 6 m^3 and the gas expands to twice its initial volume (12 m^3), the change in volume is 12 m^3 - 6 m^3 = 6 m^3. The given pressure is 1.3x10^5 Pa. Plugging these values into the formula:
Work = (1.3x10^5 Pa) x (6 m^3) = 7.8x10^5 J
t (sec) 0.0 - 0.5 - 1.0 - 1.5 - 2.0 - 2.5 - 3.0 - 3.5 - 4.0
s (ft) 12.5 - 26 - 36.5 - 44 - 48.5 - 50 - 48.5 - 44 - 36.5
Assuming that this smooth curve represents the motion of the body, estimate the velocity at t = 1.0, t = 2.5, and t = 3.5.
Which of the following is true about melting and freezing points?
Choices:
A. The melting point is always the same as the freezing point.
B. The melting point is achieved at a higher temperature than the freezing point.
C. The freezing point is applied to liquids, whereas the melting point is applied only to gases.
Which of the following is true about melting and freezing points?
Choices:
A. The melting point is always the same as the freezing point.
B. The melting point is achieved at a higher temperature than the freezing point.
C. The freezing point is applied to liquids, whereas the melting point is applied only to gases.
Answer:
Explanation:
I agree with what the first person said
Final answer:
The correct answer is that the melting point and freezing point of a substance are always the same, illustrating the equilibrium between the solid and liquid states of that substance at a specific temperature, such as 0°C for water.
Explanation:
The correct answer to which of the following is true about melting and freezing points is: The melting point is always the same as the freezing point. This principle is crucial in understanding the thermal properties of substances. The temperature at which a substance changes from solid to liquid (melting point) is the same temperature at which it changes from liquid to solid (freezing point) when the process is reversible and under the same pressure conditions. For instance, with water (H₂O), this equilibrium occurs at 0°C, illustrating that at this temperature, the solid and liquid states of H₂O are in equilibrium (H₂O (s) = H₂O (l)).
It's essential to refute common misconceptions like the melting point being higher than the freezing point or that these concepts apply differently to liquids and gases. All materials, whether solid, liquid, or gas at room temperature, have characteristic melting/freezing points that do not depend on their state at room temperature but rather on their inherent thermal properties.
What is the direction of the force that acts on clothes in the spin cycle of a washing machine?
a. outward
b. inward
c. up
d. down
The answer is option a.
During a washing machine's spin cycle, the force that acts on the clothes is directed outward, which is a result of the centrifugal force.
Explanation:In the context of a washing machine's spin cycle, the force that acts on the clothes is directed outward. This is due to the principle of centrifugal force, a type of inertial force that acts on an object moving in a circular path. The centrifugal force pushes the clothes against the wall of the washing machine drum when it rotates, effectively helping to draw water out of the clothes.
This centrifugal force pushes the clothes away from the center of rotation, causing them to stick to the drum's inner surface during the spin cycle.
Therefore, the answer is option a.
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As the time required to run up the stairs increases, the power developed by that person
Increases, decreases, or remains the same. Is the answer decreases?
As the time to run up the stairs increases, the power developed decreases..
When analyzing the relationship between time and power, it's essential to consider the fundamental definition of power as the rate at which work is done.
In the context of running up stairs, the work done involves overcoming the gravitational force acting against the person's ascent.As time increases while climbing the stairs, it indicates a slower pace, meaning the person is taking longer to cover the same vertical distance. Since the work done (ascending against gravity) remains constant, the longer time translates to a lower rate of work done, leading to a decrease in power output.This can also be understood using the formula for power -
Power (P) = Work (W) / Time (t)
When the time (t) increases and the work (W) remains constant, the power output (P) decreases.
Thus, as the time required to run up the stairs increases, the power developed by that person decreases.
Why magnetic monopole does not exist? ...?
Which heavenly bodies are involved in causing the earths tides?
only the moon and earth.
only the earth.
the earth, moon, and sun.
all the planets plus the moon.
PLEASE HELP The rotating light on a lighthouse is 400 feet from a cliff. It completes one rotation every 10 seconds. The equation representing the distance, d, in feet that the center of the circle of light is from the lighthouse is d(t) = 400sec (πt/5). What is the period of d(t)? (Enter only the number.) ...?
what connects neurons and what chemicals help neurons communicate
Answer:
synapses
The chemical that helps them to communicate is neurotransmitters
Explanation: synapses have a receiving end and a sending end that helps them receive signal transmitted through the neurotransmitters
A 50.0-kg wolf is running at 10.0 m/sec. What is the wolfs kinetic energy
The kinetic energy of the wolf is 2500J.
Explanation:The kinetic energy of the wolf can be calculated using the formula: Kinetic Energy = 0.5 x mass x velocity^2. Plugging in the given values, we have: Kinetic Energy = 0.5 x 50.0 kg x (10.0 m/sec)^2. Solving this equation will give us the wolf's kinetic energy.
Given values:
- Mass (m) = 50.0 kg
- Velocity (v) = 10.0 m/s
Using the formula for kinetic energy:
Kinetic Energy (KE) = 0.5 x mass x velocity^2
Plugging in the values:
KE = 0.5 x 50.0 kg x (10.0 m/s)^2
Calculating the square of the velocity:
KE = 0.5 x 50.0 kg x 100.0 m^2/s^2
Now, calculate the product:
KE = 2500.0 kg m^2/s^2
The unit of kinetic energy is joules (J), so we can rewrite it as:
KE = 2500.0 J
Therefore, the wolf's kinetic energy is 2500.0 joules (J).
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The pull of the moon on Earth's tidal bulge is causing
What is depth perception?
Explanation:
Depth perception is the ability that humans have to perceive depth. With depth perception animals are able to see something in three dimensions. The configuration of the eyes allows animals to see depth.
Having two eyes that is having binocular vision gives animals an accurate sense of depth. Animals have evolved in such a way that gives us depth perception. In order for animals to survive in a three dimensional world depth perception is vital.
I'LL GIVE ONE OF YOU BRAINLIEST ANSWER. PLEASE HELP ME
a) The electric field between two equally but oppositely charged parallel plates is 2.35 N/C [south]. If a charge of –2.00 C was placed at the midway point between the plates, what force (magnitude and direction) would act on the charge?
Give the direction as acting north or south. b) For another set of parallel plates, a charge of –4.00 C experiences a force of 6.00 x 10–3 N [east]. Determine the magnitude and direction of the electric field between these plates. Give the direction as east or west. (continued) 58 G r a d e 1 2 P h y s i c s Assignment 7.4: Electric Field between the Plates of a Parallel Plate Capacitor (continued) d) Label each plate in the diagram below with the appropriate polarity according to the information from part (c) above
How long is a pendulum with a period of 1.0 S on the moon which has 1/6 of the earths gravity
Final answer:
To find the length of a pendulum with 1.0 seconds on the Moon, we use the formula for a pendulum's period, adjust the acceleration due to gravity to the Moon's 1.63 m/s², and solve for the pendulum's length.
Explanation:
The subject question inquires about the length of a pendulum on the Moon that has a period of 1.0 seconds, taking into consideration that the Moon's gravity is 1/6th that of Earth's. The formula for the period of a simple pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
On Earth, assuming the acceleration due to gravity (g) is approximately 9.81 m/s², the length (L) for a pendulum with a period (T) of 1.0 seconds can be calculated using this formula. However, since we are interested in the situation on the Moon where g is 1/6th that of Earth's, we would have to adjust the acceleration due to gravity in our formula to be 1.63 m/s² (since 9.81 m/s² divided by 6 equals approximately 1.63 m/s²).
Accordingly, by rearranging the formula to L = T²g/(4π²), and substituting T with 1.0 second, and g with 1.63 m/s², one can compute the appropriate length of the pendulum on the Moon that would have a period of 1.0 second.
Final answer:
The length of a pendulum with a period of 1.0 second on the Moon can be calculated by rearranging the period formula for a simple pendulum, T = 2π√(L/g), and substituting in the Moon's gravity of 1.63 m/s².
Explanation:
The length of a pendulum that has a period of 1.0 second on the Moon, where gravity is 1/6th of Earth's gravity, can be found using the formula for the period of a simple pendulum, T = 2π√(L/g). On Earth, where the standard acceleration due to gravity, g, is approximately 9.81 m/s², a 1.0-second period requires a certain pendulum length. However, on the Moon, the acceleration due to gravity is only 1.63 m/s².
We can rearrange this formula to solve for the length (L) of the pendulum on the Moon: L = (T² * g) / (4π²). By substituting T for 1.0 second and g for 1.63 m/s², the length of the pendulum on the Moon can be calculated.
Using the provided formula, we get L = (1.0² seconds² * 1.63 m/s²) / (4π²) which gives us the length of the pendulum on the Moon. You would then perform the calculation to find the exact value for L.
Identify which sets of Quantum Numbers are valid for an electron. Each set is ordered (n,ℓ,mℓ,ms).
3,2,0,1/2
2,2,-1, 1/2
4,3,-4,1/2
1,0,0,1/2
2,2,1,-1/2
3,2,1,1
0,1,1,-1/2
3,3,1,1/2
2,-2,-2,-1/2
3,2,2,1/2
4,2,1,1/2
2,1,-1,-1/2
The height of a sinusoidal wave is called its
a. phase.
b. amplitude.
c. period.
d. frequency.
Answer:
The height of a sinusoidal wave is called its amplitude.
Explanation:
The height of a sinusoidal wave is called its amplitude. It is also defined as the maximum displacement of the particles of the waves. It the distance between the rest position to the crest or the rest position to the trough of the wave. The amplitude of a wave measures its intensity.
The intensity of a wave is directly proportional to the square of its amplitude.
So, the height of a sinusoidal wave is called wave's amplitude. So, the correct option is (b) "amplitude".
10 kg cart and a 5 kg cart are placed on identical surfaces. The 10 kg cart experiences a net force of 12 N to the left, while the 5 kg cart experiences a net force of 8 N to the left. Compare and contrast the motion of the two carts.
The 10 kg cart and 5 kg cart under different net forces will move to the left but with different accelerations. Despite the larger force acting on the 10 kg cart, the lighter 5 kg cart will actually accelerate at a greater rate.
Explanation:Comparing the motion of a 10 kg cart experiencing a net force of 12 N to the left and a 5 kg cart experiencing a net force of 8 N to the left involves the principles of Newton's second law of motion, F=ma. For the 10 kg cart, the acceleration is found by dividing the force by mass(12 N / 10 kg), which equals 1.2 m/s² to the left. For the 5 kg cart, the acceleration is (8 N / 5 kg), which equals 1.6 m/s² to the left.
Therefore, despite the 10 kg cart experiencing a larger force, the 5 kg cart actually accelerates at a greater rate due to its lighter mass. This illustrates the principle that net force not only depends on the magnitude of the force but also on the mass of the object it is acting on.
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Which statement best describes how the period and frequency of electromagnetic waves change between gamma rays and microwaves?
A) The period and the frequency stay the same.
B) The period increases and the frequency decreases.
C) The period decreases and the frequency increases.
D) The period increases and the frequency increases.
Answer:
B) The period increases and the frequency decreases.
Explanation:
Gamma rays are high energy rays which means these rays have high frequency. Microwaves have low energy and low frequency. For electromagnetic wave change between gamma rays to microwaves, the frequency decreases and period increases.
[tex]T= \frac{1}{f}[/tex]
Thus, option B is correct.
During an investigation, a student determines that a copper sample has a density of 8.10 g/ml. What is the students percent error of the accepted density for copper is 8.96 g/ml
You have 9 stones that are identical in appearance. One of these stones weighs just a bit more than the other 8. These other 8 stones are exactly the same in weight. Using a balance scale only TWICE, how can you determine exactly which stone is the heavier?
a particle moving along the x axis has the position x(t) at time t with the velocity of the particle given by v(t)=5sin(t^2). At time t=6, the particles position is (4,0). Find the position of the particle when t=7...
please and thank you :) ...?
Final answer:
To find the position of the particle when t=7, integrate the velocity function to obtain the position function. Substitute a given position value to determine the constant of integration. Finally, plug in t=7 into the position function and evaluate to find the position of the particle.
Explanation:
To find the position of the particle when t=7, we need to integrate the velocity function from t=6 to t=7. The velocity function v(t) = 5sin(t^2) represents the rate of change of position with respect to time. Integrating this function gives us the position function x(t) = -5cos(t^2) + C, where C is a constant of integration.
We can find the value of C by substituting the given position x(6) = 4.0 into the position function. Plugging in t=6 and x=4.0, we get 4.0 = -5cos(6^2) + C. Solving for C, we find C = 4.0 + 5cos(6^2).
Now we can find the position of the particle when t=7 by plugging in t=7 into the position function x(t) = -5cos(t^2) + C, where C is the value we obtained earlier. Evaluating the expression, we find x(7) = -5cos(7^2) + (4.0 + 5cos(6^2)). Therefore, the position of the particle when t=7 is approximately (0.609, 0).
Final answer:
The position of the particle at t=7 can be determined by integrating the given velocity function v(t) = 5sin(t^2) from t=6 to t=7 and adding the result to the known position at t=6. The integral does not have an elementary antiderivative, so numerical methods are needed for evaluation.
Explanation:
The position of the particle, while it moves along the x-axis, can be found by integrating the velocity function. Since the velocity is given by v(t) = 5sin([tex]t^2[/tex]), we will integrate this with respect to time to find the position function x(t). Given that the particle's position at time t=6 is (4,0), we can use this information to find the constant of integration after integrating the velocity function.
To find the position x(t) at any time t after t=6, we would calculate the integral of the velocity function from 6 to t, and add this to the initial position at t=6:
∫6t 5sin(τ2)dτ + 4
To find the position at t=7, we would evaluate this integral from 6 to 7, which requires a numerical method since the integral of sin(t2) is not an elementary function. Once the integral is evaluated, this value is added to 4 (the position at t=6) to determine the final position of the particle at t=7.
What is the magnitude of the acceleration of a speck of clay on the edge of a potter’s wheel turning at 45 rpm (revolutions per minute) if the wheel’s diameter is 35 cm?
The temperature of water in a beaker is 45°C. What does this measurement represent?
Answer:
the average kinetic energy of water particles
Explanation:
This part of the electromagnetic spectrum can be used to generate power.
a. gamma rays
b. radio waves
c. microwaves
d. infrared rays
Answer
a. gamma rays
Explanation
Gamma rays are the electromagnetic waves with the highest frequency. They are the waves with the smallest wavelength.
Due to their high frequency they can produce more energy. They are the most energetic waves or the most powerful.
Please help!
Find the tension in each cord in the figure if the weight of the suspended object is w = 210N
A) Find the tension in the cord A for system (b).
B) Find the tension in the cord B for system (b).
A) Tension in the cord A ≈ 570 Newton
B) Tension in the cord B ≈ 700 Newton
[tex]\texttt{ }[/tex]
Further explanationNewton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.
[tex]\large {\boxed {F = ma }[/tex]
F = Force ( Newton )
m = Object's Mass ( kg )
a = Acceleration ( m )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
weight of the suspended object = w = 210 N
Asked:
tension in the cord A = T_A = ?
tension in the cord B = T_B = ?
Solution:
Let:
γ = 360° - 60° - 45° - 90° = 165°
α = 90° + 45° = 135°
β = 60°
[tex]\texttt{ }[/tex]
We will use Lami's Theorem in this question.
If the system is in equilibrium , then:
[tex]\large {\boxed{\frac{T_A}{\sin \alpha} = \frac{w}{\sin \gamma}}}[/tex]
[tex]T_A = w \times \frac{\sin \alpha}{sin \gamma}[/tex]
[tex]T_A = 210 \times \frac{\sin 135^o}{sin 165^o}[/tex]
[tex]T_A = 210 \times ( 1 + \sqrt{3} )[/tex]
[tex]T_A \approx 570 \texttt{ Newton}[/tex]
[tex]\texttt{ }[/tex]
[tex]\large {\boxed {\frac{T_B}{\sin \beta} = \frac{w}{\sin \gamma}}}[/tex]
[tex]T_B = w \times \frac{\sin \beta}{sin \gamma}[/tex]
[tex]T_B = 210 \times \frac{\sin 60^o}{sin 165^o}[/tex]
[tex]T_B = 210 \times \frac{1}{2}( 6 + 3\sqrt{2} )[/tex]
[tex]T_B \approx 700 \texttt{ Newton}[/tex]
[tex]\texttt{ }[/tex]
Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441Newton's Law of Motion: https://brainly.com/question/10431582Example of Newton's Law: https://brainly.com/question/498822[tex]\texttt{ }[/tex]
Answer detailsGrade: High School
Subject: Physics
Chapter: Dynamics
[tex]\texttt{ }[/tex]
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant
What do telescopes detect that assists astronomers making discoveries in space
Telescopes assist astronomers by detecting and analyzing light from celestial objects in great detail, enabling scientists to view distant objects and investigate their properties, including the chemistry of their atmospheres. They provide insight into the deep time and space of the universe.
Explanation:Telescopes play an integral role in astronomical discoveries as they allow us to detect and analyze light and other forms of electromagnetic radiation from celestial objects. The key components in telescopes that make this possible are their light-gathering power and high-resolution imaging capabilities.
Telescopes gather more light than the human eye, allowing them to observe dim and distant objects in more detail. They can detect images and spectra of planets and galaxies, some of which are so distant that their light has traveled for billions of years to reach us. This provides profound insight into the structure of the universe and the life cycles of celestial bodies.
Moreover, by observing the chemistry of these planets' atmospheres, telescopes enable astronomers to search for signs of extraterrestrial life. Advanced telescopes such as the Hubble Space Telescope and the Very Large Telescope in Chile provide views of deep space and deep time – periods of time deep in the past – at an unrivaled resolution.
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Which three statements about electromagnetic radiation are true?
1)Light is a kind of electromagnetic radiation.
2)Electromagnetic radiation can travel only short distances.
3)Electromagnetic radiation has no mass.
4)Electromagnetic radiation can travel through a vacuum.
5)All kinds of electromagnetic radiation are invisible.
Answers
1)Light is a kind of electromagnetic radiation.
3)Electromagnetic radiation has no mass.
4)Electromagnetic radiation can travel through a vacuum.
Explanations
Electromagnetic waves are waves that can travel through vacuum. that is they do not require material medium for propagation.
Light is in the electromagnetic spectrum.
Electromagnetic waves can travel through a long distance. For instance, radio waves are electromagnetic radiations that travel long distances.
Electromagnetic radiations carry energy with it but no mass.
Some of the electromagnetic radiations are visible such as visible light.
How much force is needed to stop a 90-kg soccer player if he decelerates at 15 m/s²? A. 6 N B. 15 N C. 135 N D. 1350 N
The answer is 1350 N
Which statement is true concerning the evidence for black holes?
Scientists can see black holes with powerful telescopes.
Scientists can see the effect of black holes on nearby stars.
Scientists can see trails left in space by black holes.
There is no evidence for black holes.