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1. Let f(p) be the average number of days a house stays on the market before being sold for price p in $1,000s. Which statement best describes the meaning of f(250)?

The house sold for $250,000.
The house stayed on the market for an average of 250 days before being sold.
This is the average number of days the house stayed on the market before being sold for $250,000.
The house sold on the market for $250,000 and stayed on the market for an average of 250 days before being sold.

2. Laura rents a movie for a flat fee of $2.00 plus an additional $0.50 for each night she keeps the movie. Choose the cost function that represents this scenario if x equals the number of nights Laura has the movie.

c(x) = 2.00x + 0.50
c(x) = 2.00 + 0.50x
c(x) = 2.50x
c(x) = (2.00 + 0.50)x

The correct formula for [tex]\( r \)[/tex] rearranged from [tex]\( v = \frac{GM}{r} \) is \( r = \frac{GM}{v} \)[/tex].

To rearrange the formula [tex]\( v = \frac{GM}{r} \)[/tex] to solve for [tex]\( r \)[/tex], follow these steps:

1. Start with the given formula:

[tex]\[ v = \frac{GM}{r} \][/tex]

2. Multiply both sides of the equation by [tex]\( r \)[/tex] to get rid of the denominator:

[tex]\[ vr = GM \][/tex]

3. Divide both sides of the equation by [tex]\( v \)[/tex] to isolate [tex]\( r \)[/tex]:

[tex]\[ r = \frac{GM}{v} \][/tex]

This gives us the rearranged formula for [tex]\( r \)[/tex] in terms of [tex]\( G \), \( M \), and \( v \)[/tex]

The greatest common factor of [tex]\(15x^2y^3\)[/tex] and [tex]\(-20x^3yz\)[/tex] is [tex]\(5x^2y\)[/tex].

To find the greatest common factor (GCF) of [tex]\(15x^2y^3\)[/tex] and [tex]\(-20x^3yz\)[/tex], we need to identify the highest power of each common factor that both terms share.

List the prime factors of each term:

[tex]\(15x^2y^3 = 3 \times 5 \times x^2 \times y^3\)[/tex]

[tex]\(-20x^3yz = -1 \times 2 \times 2 \times 5 \times x^3 \times y \times z\)[/tex]

Identify the common factors:

Common factors: [tex]\(5\), \(x^2\), \(y\)[/tex]

Find the lowest exponent for each common factor:

For (5), it appears in both terms, so we use the smaller exponent, which is [tex]\(5^1\)[/tex].

For [tex]\(x^2\)[/tex], it appears in both terms, so we use the smaller exponent, which is [tex]\(x^2\)[/tex].

For (y), it appears in both terms, so we use the smaller exponent, which is [tex]\(y^1\)[/tex].

Multiply the common factors:

[tex]\(GCF = 5 \times x^2 \times y = 5x^2y\).[/tex]

So, the greatest common factor of [tex]\(15x^2y^3\)[/tex] and [tex]\(-20x^3yz\)[/tex] is [tex]\(5x^2y\)[/tex].

Let us say that m is the number of months. So that the equations for option 1 (O1) and option 2 (O2) are:

O1 = 30 m + 100

O2  = 25 m + 150

TO determine this, we equate O1 and O2 so that:

30 m + 100 = 25 m + 150

5 m = 50

m = 10

So at the 10th month, the cost for both options are equal. So we select month 11.

Answer:

D) month 11

Final answer:

The proportion of a normal distribution for z scores greater than 1.04 is 0.1492, which is found by subtracting the area to the left (0.8508) from the total area under the curve (1).

Explanation:

To find the proportion of a normal distribution that corresponds to z scores greater than 1.04, we must look up the area to the left of the z-score using a z-table or a standard normal distribution table. Once we have the area to the left, we can calculate the area to the right by subtracting this value from 1 (since the total area under the curve is 1). For a z-score of 1.04, the z-table shows that the area to the left is approximately 0.8508. Therefore, the proportion that is greater than a z-score of 1.04 is 1 - 0.8508, which equals 0.1492.

The standard normal distribution (Z~N(0,1)) has a total area of 1 under the curve, and it is symmetric about the mean, which is 0. Z-scores give us a way to determine how many standard deviations an observation is from the mean. Additionally, common z-scores used to determine confidence intervals or the proportion of observations within a certain range are tied to the percentage areas under the curve. For example, a z-score of ±1 encompasses approximately 68% of the data, ±2 about 95%, and ±3 approximately 99.7%.

Mac's mass can be found by setting up the equation 3m + 5kg - 2m = 60kg, simplifying to m + 5kg = 60kg, and solving for m to get m = 55kg. Therefore, Mac's mass is 55kg.

The equation, according to the problem statement, is: 3m + 5kg - 2m = 60kg. This simplifies to m + 5kg = 60kg, from which we can subtract 5kg from both sides resulting in m = 55kg. So, Mac's mass is 55kg.

Steps to solve the problem:

Let m represent Mac's mass.

Write the equation according to the problem statement: 3m + 5kg - 2m = 60kg.

Simplify the equation: m + 5kg = 60kg.

Subtract 5kg from both sides: m = 55kg.

Conclude that Mac's mass is 55kg.

Answer:

[tex]x=-\dfrac{11}{6},\dfrac{8}{7}[/tex]

Step-by-step explanation:

Given: [tex](7x-8)(6x+11)[/tex]

Set the expression to 0 to solve for x

[tex](7x-8)(6x+11)=0[/tex]

Set each factor to 0 and solve for x

7x-8 = 0    or    6x+11 = 0

7x = 8      or    6x = -11

[tex]x=\dfrac{8}{7}[/tex]    or   [tex]x=-\dfrac{11}{6}[/tex]

hence, The values of x are [tex]x=-\dfrac{11}{6},\dfrac{8}{7}[/tex]

Answer: 21 quarts

Step-by-step explanation: In this problem, we are asked to convert 5.25 gallons into quarts. To convert gallons into quarts, we use the conversion factor for gallons and quarts.

Conversion factor ⇒ 4 quarts = 1 gallon

Next, notice that we are going from a larger unit "gallons" to a smaller unit "quarts" and when we go from a larger unit to a smaller unit we multiply.

We will multiply 5.25 by the conversion factor which is 4 to get 21 quarts.

Therefore, 5.25 gallons is equal to 21 quarts.

Answer:

67,600

Step-by-step explanation:

The 95% confidence interval for the mean wrist circumference for all men is 18.91 to 19.69 centimeters.

To calculate the confidence interval for the mean wrist circumference, we can use the formula: CI = x ± t(s/√n), where CI is the confidence interval, x is the sample mean, t is the t-value corresponding to the desired confidence level, s is the sample standard deviation, and n is the sample size.

In this case, the sample mean is 19.3 centimeters, the sample standard deviation is 1.2 centimeters, and the sample size is 48. We can find the t-value for a 95% confidence level using a t-table or calculator. Assuming a normal distribution, the t-value is approximately 1.96. Plugging in these values into the formula, we get:

CI = 19.3 ± 1.96(1.2/√48) = 19.3 ± 0.3956

Therefore, the 95% confidence interval for the mean wrist circumference is approximately 18.91 to 19.69 centimeters.

To find when the building will be completely depreciated, you solve for x in the equation y = 360,000 - 1,500x by setting y to 0. The solution is x = 240, meaning the building will be totally depreciated after 240 months or 20 years.

In this case, you are looking to find the value of x (the number of months) when the value of the building (y) becomes 0. The equation given is y = 360,000 - 1,500x. Set y = 0 and solve for x

So, the building will be completely depreciated after 240 months or 20 years.

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Ria will need 2677920 Rupees to pay her tuition fees

Data;

We need to convert the currency from dollars to rupees

From the data given in the question, $1 is equivalent to 63.7 Rupees.

This information can further be used to determine how many Rupees she needs to pay her Tuition fees.

[tex]\$1 = 63.76 Rupees\\\$42,000 = x\\x = 42000 * 63.76\\x = 2677920[/tex]

Ria will need 2677920 Rupees to pay her tuition fees

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10 gallons of 30% juice was mixed with 90 gallons of 10% juice to make 100 gallons of 12% juice.

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the amount of 30% juice and y represent the amount of 10% juice, hence:

x + y = 100         (1)

Also:

0.3x + 0.1y = 0.12(100)         (2)

From eqn 1 and 2:

x = 10, y = 90

10 gallons of 30% juice was mixed with 90 gallons of 10% juice to make 100 gallons of 12% juice.

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This problem is simply a multiplication problem. All we have to do in this case is to multiply 0.24 by 13, or the other way around multiply 13 by 0.24. We can do this in the calculator which gives us:

13 x 0.24 = 3.12

Answer:

A. 3.12

For each postcard person gets $14/60 or $0.2333.

Ratio is basically compares quantities, that means it show value of one quantity with respect to other quantity.

If a and b are two values, there ratio will be a:b .

Given that,

Wage for 1 hour = $14,

Since,

The person mailed 300 postcards in 5 hours,

therefore, in 1 hour 60 postcards will be mailed.

Person gets $14 for 60 postcards ,

So for 1 postcard person will get $14/60 or $0.2333 .

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