Answer:
400 m/s
Explanation:
From the question;
The frequency of the wave is 200 Hz Wavelength of the wave is 2 metersWe are required to calculate the speed of the wave;
We need to know that the speed of the wave is calculated by multiplying frequency by the wavelength of the wave.That is, speed = wavelength × frequency In this case;Speed of the wave = 200 Hz × 2 m
= 400 m/s
Thus, the speed of the wave is 400 m/sA 3.0-kilogram cart possesses 96 joules of kinetic
energy. Calculate the speed of the car.
Answer:
8.0 m/s
Explanation:
KE = ½ mv²
96 J = ½ (3.0 kg) v²
v = 8.0 m/s
The kinetic energy of the object is the energy conserved due to the motion of the object.
A cart of 3 kg mass has the kinetic energy of 96 joules hence the speed of the cart is 8 m/s.
How do you calculate the speed of the cart?Given that cart has a kinetic energy of 96 Joules and the mass of the cart is 3 kg.
The formula for kinetic energy is given below.
[tex]KE = \dfrac {1}{2} mv^2[/tex]
Where KE is the kinetic energy of the cart, m is the mass of the cart and v is the speed of the cart.
Substituting the given values in the above formula to calculate the speed of the cart.
[tex]96 = \dfrac {1}{2} \times 3\times v^2[/tex]
[tex]v^2 = 64[/tex]
[tex]v = 8 \;\rm m/s[/tex]
Hence we can conclude that the speed of the cart is 8 m/s.
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In a solid, the atoms are tightly locked in position and do not change position.
(B) True
(A) False
Answer:
(B) True
The answer is true.
A .005kg projectile leaves a 1500kg launcher with a velocity of 750 m/s. What is the recoil velocity of the projectile
Answer:
The recoil velocity of the projectile is 0.0025m/s
Explanation:
Given:
Mass of the projectile =0.005kg
Mass of the launcher = 1500kg
Velocity = 750 m/s.
To Find:
The recoil velocity of the projectile = ?
Solution:
The recoil velocity is the obtained by dividing the "recoil momentum" by the "mass of the recoil body". The recoil momentum is equal to the momentum of the other body. The momentum of the other body is equal to it mass times its velocity.
Lets find the recoil momentum,
Recoil momentum = mass of the projectile X velocity
Recoil momentum =[tex]0.005 \times 750[/tex]
Recoil momentum = 3.75
Now Recoil Velocity,
Recoil Velocity = [tex]\frac{\text { Recoil Momentum}}{\text {Mass of the launcher}}[/tex]
Recoil Velocity = [tex]\frac{ 3.75}{1500}[/tex]
Recoil Velocity = 0.0025m/s
Please help please help
Answer: p= m/v so 90kg/.075m^3 = 1,200
2a. .35 m 1.1 m and .015 m
2b. 35 cm x 110 cm x 1.5 cm = 5,775 cm^3 = 57.75 m^3
mass= pv
2700•57.75= 155,925 kg
mass= 155,925 kg
volume= 57.75 m^3
Explanation: physics
a ball is thrown downward with an initial speed of 7m/s. the balls velocity after 3 seconds is m/s
Answer: -36.4
Explanation:
It says that the initial speed is 7 and the time is 3. acceleration is -9.8 ( its always 9.8 but since its going downward its negative)
The equation you want to use is Vf = Vo + AT.
When you plug in the answers it is
0 = 7 + -9.8(3)
-9.8(3) = -29.4
Then add 7
and you get -36.4
The ball's velocity after 3 seconds is 24.4 m/s.
The ball is thrown downward with an initial speed of 7 m/s. The acceleration due to gravity is 9.8 m/s². So, the ball's velocity is increasing at a rate of 9.8 m/s^2.
After 3 seconds, the ball's velocity is 7 m/s + 3 * 9.8 m/s²
= 24.4 m/s.
Therefore, the ball's velocity after 3 seconds is 24.4 m/s.
First, we find the acceleration of the ball by multiplying the acceleration due to gravity by the time it has been falling.
Next, we add the initial velocity of the ball to the acceleration we just found to find the final velocity of the ball.
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What is the difference in light that is refracted compared to light that is reflected? Think in terms of speed of light as well as what happens to light waves when they interact with a medium.
Answer:
The refracted light wave is bent at an angle while the reflected light wave is bounced back either at 90° or at angle less than 180°.
The refracted light wave changes its speed when it moves from one medium to another based on the density of the medium.
The reflected light does not change its speed once it contacts another medium. It just bounces back with the same speed.
Explanation:
One day in second grade, Chris drank chocolate milk before recess. She then played hard during recess and got sick from the heat. That was years ago, but Chris never drank chocolate milk again because even thinking about chocolate milk makes her feel sick. Chris is most likely experiencing __________. A. food aversion B. superstition C. phobia D. learned helplessness
Answer:
A. Food Aversion
It's right on ED2020, good luck!! Stay healthy and safe!!
Final answer:
Chris is experiencing food aversion, which is an associative learning process where one learns to avoid certain tastes associated with past sickness.
Explanation:
Chris is most likely experiencing a food aversion. This type of conditioning occurs when an individual associates the taste of a certain food or drink with a negative experience, such as illness, and then avoids it in the future. The event where Chris felt sick after playing hard in heat post-drinking chocolate milk exemplifies how a single adverse incident can lead to a long-lasting aversion. This aversion is a learned response when the conditioned stimulus (in Chris's case, chocolate milk) is paired with an unconditioned stimulus (feeling sick) resulting in a conditioned aversion to the food or drink.
Similar to Chris's experience with chocolate milk, taste aversion conditioning can happen when flavors associated with stomach pain or illness become avoided and disliked, an evolutionary mechanism important for animals and humans to avoid potential toxins. An example is how cancer patients may develop aversions to certain foods right before chemotherapy since the treatment often leads to nausea or sickness, strengthening the association between the flavor and the negative reaction.
How does a fire prevention plan benefit your workplace
Answer
Explanation:
Establish a Fire Prevention Plan – A fire prevention plan provides facilities with documentation outlining the employees responsible for identifying combustible materials, fire hazards and heat-producing equipment. It also outlines the procedures necessary to prevent potential emergencies.
A fire prevention plan benefits the workplace by enhancing safety, reducing the risk of fires, and minimizing potential losses.
A workplace can benefit greatly from a well-executed fire protection plan. It primarily reduces the likelihood of fires, which can result in casualties, property damage, and business interruptions. Businesses may dramatically lower the risk of fires by recognizing potential fire dangers, developing safety procedures, and making sure that firefighting equipment is available and maintained.
A plan for fire prevention also improves workplace security in general. It increases staff members' knowledge of the dangers of fire and instructs them on how to safely exit the building in case of an emergency. In addition to saving lives, this fosters a feeling of security and well-being among the staff, raising morale and productivity. It may also result in lower insurance prices.
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A 2 000-kg sailboat experiences an eastward force of 3 000 N by the ocean tide and a wind force against its sails with a magnitude of 6 000 N directed toward the northwest (45 N of W). What is the magnitude of the resultant acceleration? with steps, please.
Answer:
The magnitude of the resultant acceleration is 2.2 [tex]m/s^2[/tex]
Explanation:
Mass (m) of the sailboat = 2000 kg
Force acting on the sailboat due to ocean tide is [tex]F_1[/tex] = 3000N
Eastwards means takes place along the positive x direction
Then[tex]F_{1x}[/tex] = 3000N and [tex]F_{1y}[/tex]= 0
Wind Force acting on the Sailboat is[tex]F_2[/tex] = 6000N directed towards the northwest that means at an angle 45 degree above the negative x axis
Then
[tex]F_{2x}[/tex] = -(6000N) cos 45 degree = -4242.6 N
[tex]F_{2y}[/tex] = (6000N) cos 45 degree = 4242.6 N
Hence , the net force acting on the sailboat in x direction is
[tex]F_x = F_{1x}+ F_{2x}[/tex]
= - 3000 N + 4242.6 N
= - 3000 N +4242.6 N
= 1242.6N
Net Force acting on the sailboat in y direction is
[tex]F_y = F_{1y}+ F_{2y}[/tex]
= 0+ 4242.6N
= 4242.6N
The magnitude of the resultant force =
Using pythagorean theorm of 1243 N and 4243 N
[tex]\sqrt{(1242.6)^2 + (4242.6)^2[/tex]
[tex]\sqrt{(1544054.76) + (17999654.8)}[/tex]
[tex]\sqrt{(19543709.5)^2}[/tex]
4420.8 N
F = ma
[tex]a = \frac{F}{m}[/tex]
[tex]a =\frac{4420.8}{ 2000}[/tex]
=2.2 [tex]m/s^2[/tex]
9. The most important member of the convention was a ___-year-old scholarly lawyer from
Virginia, James Madison
A. 46
B. 26
C. 36
D. None of the above
An airplane takes off from Boston for
the 980 km trip to Detroit. The plane
lands two hours later. Which of the
following best describes the average
speed and direction of the airplane's
flight?
A. 325 km/h W
B. 490 km/h W
C. 980 km/h W
D. 1960 km/h W
Answer:B
Explanation:
Calculate speed using equation:V=S/t
S=980 km ------------ distance Boston-Detroit
t=2h --------------------- time
v=?
------------------------
V=S/t
V=980km/2h
V=490km/h
Final answer:
The average speed of the airplane for the trip from Boston to Detroit, covering a distance of 980 km in two hours, is 490 km/h. The direction of flight is westward.
Explanation:
The subject of this question is Physics, and it would typically be encountered by students at the High School level. The question involves calculating the average speed and direction of an airplane's flight from Boston to Detroit, which is a 980 km trip that the airplane completes in two hours. To find the average speed, we divide the total distance traveled by the total time of the trip.
The calculation would be Average speed = Total distance / Total time = 980 km / 2 hours = 490 km/h. Since the plane is flying from Boston to Detroit, the general direction is westward. Therefore, the best description of the airplane's average speed and direction is 490 km/h West.
__________ is the process of separating one’s identity from a particular aspect of performance or group. A. Stereotyping B. Perception C. Motivation D. Disidentification
Answer:
The answer is dis identification.
Explanation:
Answer:
D
Explanation:
D.
Disidentification
A trio of students push a 65 kg crate. The first student pushes 31 N [e], the second student pushes 28 N [s] and the third student pushes 39 N [w]. draw the FBD for the crate.
Answer:
The free body diagram is attached.
Explanation:
A force of 31[N] to the east, the second force goes to the south and it is equal to 28[N], the third force goes to the west and it is equal to 39 [N].
We can consider the crate as a particle. And all the forces are acting over the particle.
When an object rolls over a surface, the kind of friction that occurs is called
round friction
A. True
B. False
Answer:
False, When an object rolls over a surface, the kind of friction that occurs is called ROLLING FRICTION
Explanation:
The correct term for the kind of friction that occurs when an object rolls over a surface is rolling friction, not round friction, making the statement False. Rolling friction, which is different from sliding friction, is weaker and allows a rolling object to travel farther.
The kind of friction that occurs when an object rolls over a surface is not called round friction, making the statement False. When an object rolls over a surface, the friction is correctly called rolling friction. Rolling friction is a force that resists the motion of an object rolling on a surface. It happens due to deformations at the contact area between the rolling object and the surface. Unlike sliding friction, which occurs when there is relative motion between two surfaces in contact without rolling, rolling friction generally requires less force to overcome due to the reduced contact area and the nature of the motion.
During rolling motion, especially without slipping, a kinetic friction force can also arise if there is relative motion between the surfaces. However, rolling friction is primarily responsible for slowing down a rolling object over time, even in the absence of air resistance. It is significantly weaker than sliding friction, allowing a rolling object to travel much farther than it could slide on the same surface. The force of rolling friction is necessary for rolling motion, as it provides the torque needed to change the object’s angular momentum.
What is the force required to accelerate a 4 kg rock from 3 m/s to 15 m/s in seconds?
Answer:
16 Newtons
Explanation:
We will use the equation F=ma
First, find the acceleration using the givens.
a=∆v/∆t
a=15-3/3
a=12/3
a=4 m/s^2
Next, plug the acceleration and mass into the equation.
F=ma
F=4kg(4m/s^2)
F=16 Newtons
Which information is necessary to determine an object's speed?
1. distance and period of time.
2. distance and direction
3. period of time and direction
4. distance and change in position
Answer:
1. distance and period of time.
Explanation:
The speed is calculated using the formula [tex]k = \frac{d}{t}[/tex]
"k" is the speed, "d" is the distance and "t" is the time.
You need distance and time to calculate the speed.
Speed is how fast an object is going. The direction is irrelevant to speed, not to be confused with velocity, which is speed in a given direction.
Answer: 1. distance and period of time.
Explanation:
The initial kinetic energy imparted to a 0.020 kg bullet is 1200 J. (a) Assuming it
accelerated down a 1.00 m rifle barrel, estimate the average power delivered to it during
the firing. (b) Neglecting air resistance, find the range of this projectile when it is fired
at an angle such that the range equals the maximum height attained.
Answer:
(a) Power= 207.97 kW
(b) Range= 5768.6 meter
Explanation:
Given,
Mass of bullet, [tex]m=0.02 kg[/tex]
Kinetic energy imparted, [tex]K=1200 J[/tex]
Length of rifle barrel, [tex]d=1 m[/tex]
(a)
Let the speed of bullet when it leaves the barrel is [tex]v[/tex].
Kinetic energy, [tex]K=\frac{1}{2} mv^{2}[/tex]
[tex]v=\sqrt{\frac{2K}{m} }[/tex]
[tex]=\sqrt{\frac{2\times1200}{0.02} }[/tex]
[tex]=346.4m/s[/tex]
Initial speed of bullet, [tex]u=0[/tex]
The average speed in the barrel, [tex]v_a_v_g=\frac{u+v}{2}[/tex]
[tex]=\frac{0+346.4}{2} \\=173.2 m/s[/tex]
Time taken by bullet to cross the barrel, [tex]t=\frac{d}{v} [/tex]
[tex]=\frac{1}{173.2}\\ =0.00577 second[/tex]
Power, [tex]P_a_v_g=\frac{W}{t}[/tex]
[tex]=\frac{1200}{0.00577} \\=207.97kW[/tex]
(b)
In projectile motion,
Maximum height, [tex]H_m=\frac{v^2\sin^2\theta}{2g} \\[/tex]
Range, [tex]R=\frac{v^2\sin2\theta}{g}[/tex]
given that, [tex]H_m=R[/tex]
then, [tex]\frac{v^2\sin^2\theta}{2g}=\frac{v^2\sin2\theta}{g}\\\sin^2\theta=2\sin\theta\cos\theta\\\\\tan\theta=4\\\theta=\tan^-^14\\\theta=75.96^0\\R=\frac{v^2\sin2\theta}{g}\\=\frac{346.4^2\times\sin(2\times75.96)}{9.8}\\5768.6 meter[/tex]
SP: Describe what moment is,
give the formula and unit for it.
Rearrange the equation to make
a force as a subject
Answer:
Moment of force (often just moment) is a measure of its tendency to cause a body to rotate about a specific point or axis.ORA force that tends to cause rotation.Explanation:
The unit for moment is N/m(newton per meter).
The formula for moment of force(also known as torque) is:
T= r.F sinθ
To make force as a subject,
T = r.F sinθ
T/r = F sinθ
F = T / r sinθ
Just after vertical launch from Earth surface, the space shuttle takes 8.0 s to reach a speed of 160 km/h. During this phase, what is the apparent weight of an 84 kg astronaut?
Answer:
1291.08 N
Explanation:
acceleration=change in speed per unit time
[tex]a=\frac {v-u}{t}[/tex] where v and u are final and initial velocities respectively.
u is zero and v=160 km/h converted to m/s becomes[tex]160\times \frac {1000m}{3600s}\approx 44.44 m/s[/tex]
acceleration=[tex]\frac {44.44-0}{8}\approx 5.56 m/s^{2}[/tex]
Apparent weight, [tex]F_N=m(g+a)[/tex]
Taking g as 9.81 and m as 84 Kg then
[tex]F_N=84(9.81+5.56)\approx 1291.08 N[/tex]
The astronaut's apparent weight just after launch is about 467.04 N. This is calculated using the equation F = ma, where m is the astronaut's mass and a is the shuttle's acceleration (derived from the given final velocity and time).
Explanation:To calculate the apparent weight of the astronaut, we need to find the acceleration of the shuttle first. We'll use the formula v = u + at, where v is the final velocity, u is the initial velocity (zero in this case as it's a vertical launch), a is the acceleration, and t is the time. We're given that v = 160 km/h which is equivalent to 44.44 meters per second (160000 m / 3600 seconds) and t = 8 seconds.
Calculating for a = (v - u) / t, we get a = 5.56 m/s². Then we calculate the apparent weight using the equation F = ma, where F is the force (apparent weight) and m is the mass. Using m = 84 kg and a = 5.56 m/s², we find that F (the apparent weight) = 467.04 N (rounded to the nearest hundredths place).
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A train is moving with the speed of light(c=3*10^8m/s) around the Earth. How much time will it take to complete one round trip along the equator on the surface of the Earth if it's radius is 6400km
Answer:
t = 0.13 [s]
Explanation:
We know that the speed of light is equal to c = 3 * 10^8m/ s, equivalent to 300000000 [m / s] and the radius of the Earth equal to 6400 [km] or 6400000 [m].
The speed definition is given as:
[tex]c = \frac{x}{t} \\where:\\c = velocity or speed light [m/s]\\t = time [s]\\x = distance [m][/tex]
But we need to know the value of x.
We know that the Earth's equator resembles a circumference, and we need to know the length of the circumference that will be the value of x.
[tex]x =2*\pi *r\\where:\\r = Earth radius [m]\\replacing:\\x = 2*\pi *6400000 = 40212385.97[m][/tex]
Then we can find the time.
[tex]t=\frac{40212385.97}{300000000} \\t=0.13[s][/tex]
An astronaut weighs 700 N on Earth what is the astronaut's Mass on Earth?
Answer:
70 kg
Explanation:
On earth, g = 9.8 m/s².
W = mg
700 N = m (9.8 m/s²)
m ≈ 71 kg
Rounded to 1 significant figure, the astronaut's mass is 70 kg.
Convert the following units
4.8 g/cm^3 to kg/m^3
Final answer:
To convert 4.8 g/cm³ to kg/m³, multiply by the conversion factors (0.001 kg/g) and (1,000,000 cm³/m³) to obtain 4800 kg/m³.
Explanation:
To convert the density from grams per cubic centimeter (g/cm³) to kilograms per cubic meter (kg/m³), we use the conversion factors: 1 g = 0.001 kg and 1 cm³ = 0.000001 m³. Therefore, to convert 4.8 g/cm³ to kg/m³, multiply by the conversion factors:
4.8 g/cm³ × (0.001 kg/g) × (1,000,000 cm³/m³) = 4.8 × 1000 kg/m³ = 4800 kg/m³.
Thus, the density is 4800 kg/m³ when converted from 4.8 g/cm³.
HELP FAST You should visit a sporting goods store so that you can see the products and try them out in person before you make a purchase Question 3 options: True False
Answer:
true
Explanation:
if you purchase something online, it often times gets damaged or mixed up with a different product.
Answer:
False
Explanation:
You can purchase online without seeing or trying the goods you want.
If you trust in the store in which you are purchasing (because it has a good online reputation or it was recommended by a friend), an online bought is a good option, it is faster, it is done without leaving your home and many times it is even cheaper than bought in person.
Infrared waves from the sun are what make our skin feel warm on a sunny day. If an infrared wave has a frequency of 3.0 x 1012 Hz, what is its wavelength?
Answer:
The wavelength of the infrared wave is 0.0001 m.
Explanation:
Given:
Frequency of an infrared wave is, [tex]f=3.0\times 10^{12}\ Hz[/tex]
We know that, infrared waves are electromagnetic waves. All electromagnetic waves travel with the same speed and their magnitude is equal to the speed of light in air.
So, speed of infrared waves coming from the Sun travels with the speed of light and thus its magnitude is given as:
[tex]v=c=3.0\times 10^8\ m/s[/tex]
Where, 'v' is the speed of infrared waves and 'c' is the speed of light.
Now, we have a formula for the speed of any wave and is given as:
[tex]v=f\lambda[/tex]
Where, [tex]\lambda \to \textrm{Wavelength of infrared wave}[/tex]
Now, rewriting the above formula in terms of wavelength, [tex]\lambda[/tex], we get:
[tex]\lambda=\dfrac{v}{f}[/tex]
Now, plug in [tex]3.0\times 10^8[/tex] for 'v', [tex]3.0\times 10^{12}[/tex] for 'f' and solve for [tex]\lambda[/tex]. This gives,
[tex]\lambda=\frac{3.0\times 10^8}{3.0\times 10^{12}}\\\\\lambda=0.0001\ m[/tex]
Therefore, the wavelength of the infrared wave is 0.0001 m.
To find the wavelength of an infrared wave with a frequency of 3.0 x 10¹² Hz, use the formula λ = c / f. Substituting the speed of light and the given frequency, we get a wavelength of 1.0 x 10⁻⁴ meters.
Infrared waves are part of the electromagnetic spectrum and have longer wavelengths than visible light. To find the wavelength of an infrared wave given its frequency, we use the formula:
λ = c / f
where:
λ (lambda) is the wavelengthc is the speed of light in a vacuum (approximately 3.00 x 10⁸ meters per second)f is the frequencyGiven the frequency f = 3.0 x 10¹² Hz, we can substitute the values into the equation:
λ = 3.00 x 10⁸ m/s / 3.0 x 10¹² Hz
λ = 1.0 x 10⁻⁴ meters
Thus, the wavelength of the infrared wave is 1.0 x 10⁻⁴ meters.
Which of the following is the equation used to calculate power?
Answer:
Power = Force x Velocity
Explanation:
Mathematically, it is computed using the following equation. The standard metric unit of power is the Watt. As is implied by the equation for power, a unit of power is equivalent to a unit of work divided by a unit of time. Thus, a Watt is equivalent to a Joule/second.
The equation used to calculate Power is Force multiplied velocity.
What is Power?This is defined as the amount of energy conversion which takes place per unit time and the unit is Watts.
Power = Force × Velocity
We cab however calculate Power by multiplying the applied force with the velocity of the object in order to arrive as the answer.
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Why Apparent weight of substance is less than it Real weight?
Answer:
The apparent weight is less than that of the real weight because of buoyancy.
Explanation:
Buoyancy is the upward thrust that is experienced by the object that is either fully or partially immersed in the object. The weight of the immersed object will be equal to the mass of the liquid that is displaced by the object. Buoyancy can be calculate based on Archimedes's Principle. Buoyancy also acts in the air, the normal force is reduced than the force of gravity. Buoyancy is the ability to float in liquid as well as in air. This floating happens when various forces acts on the opposite direction. The direction of the force will always remain upwards.
Urgently!
Crickets perceive sounds with a frequency of 300 - 8000 Hz. What is the period of sound vibrations and the length of the sound wave perceived by an insect?
Answer:
0.003333 s to 0.000125s or from 3.33ms to 0.125ms wher m is for milli
1.1m to 0.04125 m
Explanation:
T= 1/f=
if f= 300Hz then T = 1/300 =0.003333 s
if f= 8000 then T= 1/8000 = 0.000125s
now v=f×wave length
or wavelength = speed/ frequency
when f = 300 Hz
wavelength = 330/300=1.1 m
wavelength = 330/8000 = 0.04125m
note : i have taken speed of sound as 330 m/s you can take any value given in between 330m/s to 340m/s
what is the acceleration of a 0.50 kilogram ball that hit with a force of 21.5
Answer:
43m/s^2
It's derived from the equation F=ma.
Assuming that the force is in SI units which is Newtons, the answer is as such. The working is attached
btw,next time put all the units down when asking
Applying Newton's second law of motion, the relation between force and mass is given as F = m * a. The acceleration of a 0.50-kilogram ball hit with a force of 21.5 newtons is 43.0 m/s².
To calculate the acceleration of a 0.50-kilogram ball that is hit with a force of 21.5 newtons, we use Newton's second law of motion, which states that the force applied to an object equals mass times acceleration (F = ma). To find the acceleration (a), rearranging this equation the acceleration (a) would be:
a = F / m
a = 21.5 N / 0.50 kg
a = 43.0 m/s²
Therefore, the acceleration of the ball would be 43.0 meters per second squared (m/s²).
As water moves down through the ground, what force is acting against it?
A. Capillary action
B. Saturation
C. Gravity
D. Permeability
As water moves down through the ground, the force that is acting against it is gravity, which is in option c, as gravity pulls the water down through the soil and towards the water table or the nearest body of water.
What is capillary action?Gravity is a force that pulls objects towards each other, and it is what causes water to move downward through soil and rock. When it rains or when water is added to the soil, the force of gravity causes the water to percolate or move down through the soil and towards the water table or the nearest body of water. Capillary action refers to the ability of water to move upward through small spaces or pores, such as in soil or rock. It is caused by the surface tension of water and the adhesion of water molecules to surfaces.
Hence, as water moves down through the ground, the force that is acting against it is gravity, which is option c.
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The force acting against water as it moves down through the ground is Gravity(C). It pulls the water downwards, and this motion is resisted by the earth's material, which is referred to as permeability.
Explanation:As water moves down through the ground, the force that is acting against it is Gravity(C). Gravity is the force of attraction that pulls two masses towards each other, in this case, the mass of the earth and the mass of water. This downward pull of water is resisted by the earth's material leading to the permeability of soil and rocks, that is the ability for water to flow through them. However, the answer to your actual question is Gravity as it’s the primary force pulling the water downwards.
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A spring has a spring constant of 115 N/m. How much energy is stored in the
spring when it is compressed 0.15 m past its natural length?
O A. 1.33
OB. 0.82
O C. 17.30
O D. 8.6J
Explanation:
Elastic energy stored in a spring is:
EE = ½ kx²
EE = ½ (115 N/m) (0.15 m)²
EE = 1.3 J
Answer: The energy stored in the spring is 1.33 J
Explanation:
To calculate the energy stored in the spring, we use the equation:
[tex]E=\frac{1}{2}kx^2[/tex]
where,
E = energy stored in the spring
k = spring constant = 115 N/m
x = compression of the spring = 0.15 m
Putting values in above equation, we get:
[tex]E=\frac{1}{2}\times 115\times (0.15)^2\\\\E=1.33J[/tex]
Hence, the energy stored in the spring is 1.33 J