For this ionic compound, what would be the name of the anion? KMnO4 A. potassite B. potassiate C. permanganite D. permanganate

Answer:

9

Explanation:

Hello,

In this case, since the third shell of electrons has  the following 3 subshells:

[tex]3s, 3p \ and \  3d[/tex]

- The [tex]s[/tex] subsehll has one orbital for one pair of electrons: [tex]s^1 \ and \   s^2[/tex].

- The [tex]p[/tex] subsehll has three orbitals for three pairs of electrons: [tex]p^1, \ p^2,\ p^3, \ p^4,\ p^5\ and \ p^6\[/tex].

- The [tex]d[/tex] subsehll has five orbital for five pairs of electrons [tex]d^1, \ d^2,\ d^3, \ d^4,\ d^5,\ d^6,\ d^7,\ d^8,\   d^9\ and \ d^{10}\[/tex].

Therefore, the total number of orbitals when n=3 is:

[tex]1+3+5=9[/tex]

Best regards.

The third shell (n=3) of an atom contains nine orbitals, which are divided into three subshells: 3s, 3p, and 3d containing 1, 3, and 5 orbitals respectively.

The third shell (n=3) of an atom contains nine orbitals. Electron shells are divided into subshells, which are made up of orbitals. For n=3, the subshells are 3s, 3p, and 3d. The 3s subshell contains only one orbital, the 3p subshell contains three orbitals, and the 3d subshell contains five orbitals. So, if you add up the number of orbitals in each subshell (1 for 3s, 3 for 3p, and 5 for 3d), you will find that the third shell has a total of nine orbitals.

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The molar mass of styrene is 104.1 g/mol and its molecular formula is C8H8. Therefore, option B is correct.

Given information,

Molar mass = 104.1 g/mol

The molar mass of styrene (104.1 g/mol) is significantly larger than the molar mass of the empirical formula (CH). This means that there must be multiple CH units in the molecular formula.

a. C₂H₄: (2 × 12.01 g/mol) + (4 × 1.01 g/mol) = 28.06 g/mol

b. C₈H₈: (8 × 12.01 g/mol) + (8 × 1.01 g/mol) = 104.16 g/mol

c. C₁₀H₁₂: (10 × 12.01 g/mol) + (12 × 1.01 g/mol) = 132.22 g/mol

d. C₆H₆: (6 × 12.01 g/mol) + (6 × 1.01 g/mol) = 78.11 g/mol

Therefore, option B is correct.

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Answer:

K⁺ and NO₃⁻ are the spectator ions.

Explanation:

First, we will consider the molecular equation because is the easiest to balance.

K₂CrO₄(aq) + Ba(NO₃)₂(aq) → BaCrO₄(s) + 2 KNO₃(aq)

Then, we will write the full ionic equation, which includes all the ions and the molecular species.

2 K⁺(aq) + CrO₄²⁻(aq) + Ba²⁺(aq) + 2 NO₃⁻(aq) → BaCrO₄(s) + 2 K⁺(aq) + 2 NO₃⁻(aq)

Finally, we will write the net ionic equation, which includes only the ions that participate in the reaction and the molecular species. The missing ions are the spectator ones.

CrO₄²⁻(aq) + Ba²⁺(aq) → BaCrO₄(s)

Final answer:

In the reaction between potassium chromate and barium nitrate, the spectator ions are NO3- and K+, as they appear unchanged on both sides of the chemical equation.

Explanation:

The question involves identifying the spectator ion(s) in the reaction between potassium chromate (K2CrO4) and barium nitrate (Ba(NO3)2). When these two aqueous solutions are mixed, a precipitation reaction occurs, forming barium chromate (BaCrO4) as the precipitate, and potassium nitrate (KNO3) remains in solution. Given that spectator ions are those ions that do not participate in the actual chemical reaction but are present in the same form on both sides of the equation, the NO3-(aq) and K+(aq) ions are the spectator ions in this reaction. They are present on both sides of the equation and remain unchanged.

Final answer:

To find the number of excess electrons on a conducting sphere with a net charge of -4.8 × 10⁻¹⁷ C, the total charge is divided by the charge of a single electron, resulting in approximately 300 excess electrons.

Explanation:

The question asks about the number of excess electrons on a conducting sphere with a net charge of –4.8 × 10⁻¹⁷ C. To find the number of excess electrons, we need to divide the total charge by the charge of a single electron, which is approximately 1.6 × 10⁻¹⁹ C. The calculation is as follows

Number of electrons = Total charge / Charge of one electron

= (-4.8 × 10⁻¹⁷ C) / (1.6 × 10⁻¹⁹ C)

= 3 × 10² electrons.

Therefore, the sphere has approximately 300 excess electrons.

Answer:

sp3 hybridization

Explanation:

Hello,

Based on the Lewis structure Nitrogen has 3 valence electrons with a lone pair of non-bonded electrons, thus, the hybridization calculation rule,

[tex]Hybridization=\#Attached.Atoms+\# lone.pairs\\[/tex]

Allows us to identify that the [tex]NF_3[/tex] has three attached atoms and one lone pair. Now, by considering the convention: sp3=4, sp2=3  and sp=2 , one finds that:

[tex]Hybridization=3+1=4[/tex]

Therefore, [tex]NF_3[/tex] has sp3 hybridization.

Best regards.

In NF3 (nitrogen trifluoride), the nitrogen (N) atom undergoes hybridization to form its bonding orbitals. So, the hybridization of the nitrogen atom in NF3 is sp3.

The nitrogen atom in NF3 has five valence electrons, with one being paired and three unpaired. To form four bonding orbitals and accommodate the three fluorine (F) atoms, the nitrogen atom undergoes sp3 hybridization.

In sp3 hybridization, one 2s orbital and three 2p orbitals of the nitrogen atom combine to form four new hybrid orbitals called sp3 orbitals. These sp3 orbitals are arranged in a tetrahedral geometry around the nitrogen atom, with the three fluorine atoms occupying three of the sp3 orbitals, and the remaining sp3 orbital containing a lone pair of electrons.

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Answer: C. They have small difference in electronegativity.

Explanation:

got it correct on text !

Answer:

-contain hydroxide ion or produce it in a solution

-taste sour

Explanation:

Answer: Mantle

Explanation:

The boiling point of the compound is 914.32°C.

Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.

Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:

1)Molecular compounds where in atoms are joined by covalent bonds.

2) ionic compounds where atoms are joined by ionic bond.

3)Inter-metallic compounds where atoms are held by metallic bonds

4) co-ordination complexes where atoms are held by co-ordinate bonds.

1 j - 0.001 kj

53.69 j -Kj

Kj = 53.69 ×0.001

=>  0.05369 Kj

T = ΔH / ΔS

T = 49.09 / 0.05369

T = 914.32 º C

Hence, the boiling point of the compound is 914.32°C.

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The mass percent of aluminum in aluminum chlorohydrate, Al2(OH)5Cl, is calculated by dividing the mass of aluminum in the compound by the compound's total molar mass and then multiplying by 100, which results in approximately 30.94%.

To calculate the mass percent of aluminum in aluminum chlorohydrate, Al2(OH)5Cl, we first need to find the molar mass of aluminum and the molar mass of the entire compound. The molar mass of aluminum is approximately 26.98 g/mol and there are two aluminum atoms in the compound. Next, calculate the total molar mass of Al2(OH)5Cl using the molar masses of all the atoms involved.

For Al2(OH)5Cl:

Total molar mass of Al2(OH)5Cl = 53.96 + 80.00 + 5.05 + 35.45 = 174.46 g/mol

Mass percent of Aluminium in the compound = (Mass of Al in the formula / Molar mass of the compound) × 100 = (53.96 / 174.46) × 100 = 30.94%

A covalent bond results when two electrons occupy a bonding molecular orbital, shared between two atoms due to the overlap of their atomic orbitals, creating a lower energy state.

When two electrons occupy the bonding molecular orbital, a covalent bond results. This bond occurs when atomic orbitals from two atoms overlap in a way that their electron clouds are in phase, allowing the electrons to be shared between the atoms and creating a lower energy state than the original separate atomic orbitals. The type of covalent bond (single, double, triple) depends on the number of electron pairs shared and the orbitals involved, as described by the valence bond theory.

For instance, a single bond (σ bond) arises from end-to-end overlap and involves one electron pair, whereas double and triple bonds involve, respectively, one or more additional side-by-side π bonds created by the overlap of p orbitals. These concepts are also in line with the molecular orbital theory, where the filled bonding orbitals contribute to the bond strength of a molecule. The bond order, calculated from an energy level diagram showing the net number of bonding electrons, determines the strength and type of bond.

The isotope with 8 protons (atomic number), 8 electrons, and 11 neutrons is Oxygen. The symbolic notation of this isotope would be represented as 19\8O, where 'O' is the symbol for Oxygen, '19' is the mass number (protons + neutrons), and '8' is the atomic number (protons).

The element with 8 protons and 8 electrons is Oxygen. Therefore, the element you're asking about is an isotope of Oxygen. Isotopes are distinguished by the number of neutrons. In this specific case, we have 11 neutrons.

The symbolic notation of an isotope is represented as follows: The symbol for the isotope is the element's symbol (X), the mass number (A) is written as a superscript, and the atomic number (Z) is written as a subscript. In your case:

Z = 8 (number of protons)

X = O (symbol for Oxygen)

A = Z + N = 8 + 11 = 19 (Sum of protons plus neutrons)

Therefore, the symbolic notation of the isotope would be 19\8O.

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Final answer:

When a neutrally charged atom loses an electron to another atom, the result is the creation of an ion.

Explanation:

When a neutrally charged atom loses an electron to another atom, the result is the creation of an ion. An ion is a charged atom that has gained or lost electrons, so it has more or fewer electrons than protons and a negative or positive charge. For example, a neutral sodium atom can lose one electron to become a positively charged sodium atom (Na+), while a neutral chlorine atom can gain one electron to become a negatively charged chlorine ion (Cl-).

Answer:

0.045 L × 2.0 M = 0.09 mol

0.09 mol × 1 mol H2O/1 mol HCl = 0.09 mol H2O

0.09 mol H2O × 18 g/1 mol = 1.62 g

Solution: 1.62 grams of H2O

Explanation:

Answer from edmentum

Answer:

1.6 atm

Explanation:

A P E X!

The formula for freezing point depression is:

ΔT = Kf * m         --->1

Where,

ΔT = change in temperature = 2.88 degrees Celcius

Kf = freezing point molar constant of solvent

m = molality (moles solute/mass solvent)

First we calculate for molality since we are given the mass of solute and solvent.

Molar mass of pentane = 72.15 g / mol

molality m= (0.123 g / 72.15 g / mol) / (2.493 x 10^-3 kg)

m = 0.684 molal

Going back to equation 1:

ΔT = Kf * m

2.88 = Kf * 0.684

Kf = 4.21 degC / molal

Value for Kf in question 1 given that m = 0. 829 mol/kg:

2.88 = Kf * 0.829

Kf = 3.47 degC / molal

Final answer:

The oxidation state of chlorine in HClO4 is +7, determined by assigning known oxidation states to hydrogen and oxygen and using the rule that the sum of oxidation states in a molecule must equal its overall charge.

Explanation:

The student has asked to determine the oxidation state of chlorine in HClO4. To find this, we will use the available rules for assigning oxidation numbers.

The sum of the oxidation states in a molecule must equal the overall charge of the molecule. For HClO4, the molecule is neutral, so the sum must be zero.

Oxygen usually has an oxidation state of -2, so with four oxygen atoms, we have a total of -8.

Hydrogen generally has an oxidation state of +1.

With these values, we can set up the equation x + 1 + 4(-2) = 0, where x is the unknown oxidation state of chlorine. Solving for x gives us x = +7.

Therefore, the oxidation state of chlorine in HClO4 is +7.

Final answer:

To find the remaining mass of the isotope after 5.5 days, calculate the number of half-lives that have elapsed and then use the formula for radioactive decay. Approximately 0.445 grams of the isotope remain after the calculated time period.

Explanation:

To find out what mass of the radioactive isotope remains after 5.5 days given its half-life of 3.8 days, we use the concept of radioactive decay and half-life calculations. The number of half-lives that have passed can be calculated by dividing the elapsed time by the half-life time of the isotope.

Number of half-lives = Time elapsed / Half-life = 5.5 days / 3.8 days = 1.447

Next, we determine the fraction of the original sample that remains after 1.447 half-lives. The remaining fraction is given by (1/2) raised to the power of the number of half-lives. In this case:

Remaining fraction = (1/2)^1.447

Now, we can calculate the mass of the isotope that remains:

Remaining mass = Initial mass × Remaining fraction = 1.55 g × (1/2)^1.447

To find the exact value, we need a calculator to raise (1/2) to the power of 1.447. After calculating, if we assume that (1/2)^1.447 equals approximately 0.287, then the remaining mass is:

Remaining mass = 1.55 g × 0.287 ≈ 0.445 g

Therefore, approximately 0.445 grams of the isotope would remain after 5.5 days.

At 21.5 °C and 1.00 atm, the molar volume of helium gas is expected to be slightly higher than 22.41 L, the molar volume of an ideal gas at STP due to the increase in temperature and the behavior of helium closely resembling an ideal gas.

If you experiment to generate helium gas at 21.5 °C (which is 294.65 K) and 1.00 atm, you would expect the molar volume of the helium to be close to the value for an ideal gas under standard temperature and pressure conditions. This is because helium behaves relatively closely to an ideal gas due to its small, non-polar, monatomic nature. At standard temperature (0 °C or 273.15 K) and pressure (1 atm), the molar volume of an ideal gas is 22.41 L. However, because the experiment is carried out at a slightly higher temperature, the molar volume will be slightly higher than 22.41 L due to the direct relationship between temperature and volume described by Charles's law.

To calculate the molar volume at the given conditions, you would use the ideal gas law equation: PV = nRT. You can rearrange this equation to solve for molar volume (V/n) and find that V/n = RT/P. With R as the ideal gas constant (0.0821 L·atm/(K·mol)), T as the absolute temperature in Kelvin, and P as the pressure in atm, you can calculate the molar volume of helium at 21.5 °C and 1.00 atm.