Answers
mp=((x1+x2)/2, (y1+y2)/2)
Related Questions
Mrs. Patil bought 4 packs of pencils for her class. Then she bought 3 more packs of pencils. There are 12 pencils in a pack. How many pencils did she buy?
Answers
[tex]4+3 = 7[/tex] packs of pencils were bought in total
each one contains 12 pencils, so
[tex]7*12 = 84[/tex] pencils were bought
The number of pencils from 7 packs is 84.
What is the unitary method?The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
Given that, Mrs. Patil bought 4 packs of pencils for her class. Then she bought 3 more packs of pencils.
Now, 4+3 =7 packs
There are 12 pencils in a pack.
Here, number of pencils =12×7
= 84 pencils
Therefore, the number of pencils from 7 packs is 84.
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Factor: 216+8d^3
d^3 is d to the third power
Answers
6 ^3 + (2 .d ) ^3
= ( 6 + 2d ) ( 36 + 4d^2 - 12d)
= 2 (3 +d) ( 36 + 4d^2 - 12d)
hope it helped
I spent 25 Points, PLEASE HELP! In a graph, x represents the number of months since a business opened, and y represents the total amount of money the business has earned. The following three points are from the graph:
(2, 1990) (5, 4225) (9, 7205)
Find the slope and y-intercept. Explain what each represents.
Answers
m=(4225-1990)/(5-2)=745,
m is the slope, this represents the amount of money earned each month that the business operates.
so far we have:
y=745x+b, using any point we can solve for b, I'll use (2,1990)
1990=745(2)+b
1990=1490+b
500=b
b is the y-intercept which is $500, it represents the amount of moeny that the business started with.
The slope of this scenario is 745. The slope represents the profit made each month.
Assuming that the equations define x and y implicitly as differentiable functions x=f(t),y=g(t) find the slope of the curve x=f(t), y=g(t) at the given value of t x(t+1)-4tsqrt(x)=9, 2y+4y^3/2=t^3+t , t=0
Answers
[tex]x(t+1)-4t \sqrt{x} =9[/tex] (1)
[tex]2y+4y^{3/2}=t^{3}+t[/tex] (2)
When t=0, obtain
[tex]x=9 \\ 2y+4y^{3/2}=0 \,\,=\ \textgreater \ \, y(1+2 \sqrt{y} )=0 \,=\ \textgreater \ \,y=0[/tex]
Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
When t=0, obtain
x'(0) + x(0) - 4√x(0) = 0
x'(0) + 9 - 4*3 = 0
x'(0) = 3
Here, x' means [tex] \frac{dx}{dt} [/tex].
Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
When t=0, obtain
2y'(0) +6√y(0) * y'(0) = 1
2y'(0) = 1
y'(0) = 1/2.
Here, y' means [tex] \frac{dy}{dt} [/tex].
Because [tex] \frac{dy}{dx} = \frac{dy}{dt} / \frac{dx}{dt} [/tex], obtain
[tex] \frac{dy}{dx} |_{t=0}\, = \frac{1/2}{3}= \frac{1}{6} [/tex]
Answer:
The slope of the curve at t=0 is 1/6.
Final answer:
To find the slope of the curve at a given value of t, differentiate the implicit equations x=f(t) and y=g(t) with respect to t, then substitute the given t value into the derivatives to find the slopes.
Explanation:
Slope of the curve at the given value of t:
Given equations: x(t+1)-4tsqrt(x)=9 and 2y+4y^3/2=t^3+t, t=0Differentiate the equations x and y with respect to t to find dx/dt and dy/dtSubstitute t=0 into the derived dx/dt and dy/dt to find the slopes at the given value of tIf wx = XZ, then WX = YZ
Answers
hope this helps
Find the area of the circle.
Round to the nearest hundredth.
Answers
that is 28.27 to nearest 1/100.
HELP PLEASE!!
graph A
graph B
graph C
graph D
Which graph is defined by f(x) = x2 + 5|x| + 6?
(each graph is in order)
Answers
You can test this by substituting values in.
x=-2, f(x)=20
x=-1, f(x)=12
x=0, f(x)=6
x=1, f(x)=12
x=2, f(x)=20
Select all the numbers that are multiples of 9.
9
21
27
45
54
78
81
38
Answers
These are the multiples of 9.
9 *1
9 *3
9 *5
9 *6
9 *9
Answer: 9, 27, 45, 54, 81,
Hope this helps! :)
The level of detail that infants can see at 20 feet is equivalent to the level of detail that adults can see at _____ feet.
Answers
Hope this helps : )
In standard notation, 2.34 x 102 is 23,400. true or false
Answers
2.34 × 10² equals to 2.34 × 100 which gives the result of 234
Hence, the statement given is false
Arby's age is 6 years less than 7 times Anna's age. If Anna's age is x years, which expression best shows Arby's age?
x
7x − 6
x − 1
6x − 7
Answers
Answer:
A = 7x - 6
Step-by-step explanation:
The options aren't very clear, but the answer would be (assume that A is Arby's age):
A = 7x - 6
Answer:
A
Step-by-step explanation:
PLEASE HURRY!!! 30 POINTS
A rectangle has an area of 102 cm2. The length of the rectangle is 17 cm.
What is the perimeter of the rectangle?
Answers
(6*2)+(17*2) = 46
Hope this helps! :)
Answer:
(Really really really sorry if this incorrect)... ok so it's 17 cm tall in length. That would be 17 blocks high, for example. The area is 102, so 102 cm2 divided in half equals 51, so the width would be 51 cm. So the perimeter is 17 + 17 + 51 + 51 = 136 cm.
X/x+2 = 4/5. Solve for x.
Answers
5x = 4x + 8
5x - 4x = 8
x= 8
First, let's write the problem.
[tex]\frac{x}{x}+2=\frac{4}{5}[/tex]
Since the least common multiple is 5x, we are going to multiply by that.
[tex]\frac{x}{x}\cdot \:5x+2\cdot \:5x=\frac{4}{5}\cdot \:5x[/tex]
[tex]5x+10x=4x[/tex]
[tex]15x=4x[/tex]
Subtract 4x from both sides.
[tex]15x-4x=4x-4x[/tex]
[tex]11x=0[/tex]
Divide both sides by 11.
[tex]\frac{11x}{11}=\frac{0}{11}[/tex]
Our final answer would be,
[tex]x=0[/tex]
This tells us that this problem has no solution.
_________
Your problem may have been written like this,
[tex]\frac{x}{\left(x+2\right)}=\frac{4}{5}[/tex]
If so, there's a totally different solution, which is why important to include parenthesis. Let's simplify it.
Cross multiply. It would look something like this,
[tex]x\cdot \:5=\left(x+2\right)\cdot \:4[/tex]
Apply the distributive property.
[tex]x\cdot \:5=4x+8[/tex]
Subtract 4x from both sides.
[tex]x\cdot \:5-4x=4x+8-4x[/tex]
This tells us that our final answer would be,
[tex]x=8[/tex]
Thanks!
-TetraFish
p=2L+2w solve for w helppppp
Answers
Subtract 2l from both sides
P-2l=2w
Divide all terms by 2
(1/2)P-l= w
Final answer: w= (1/2)P-l
What would the answer be?
Answers
There are 24 girls and 12 boys on that bus.
Your linear equations would be:
[tex]x = girls \\ y = boys \\ 2x + y = 36 [/tex]
The diagonals of parallelogram DEFG intersect at H. What congruence statements can you make about the parallelogram?
Answers
DH=HF
EH=HG
EF=DG
DE=FG
hence;
Hence ΔDEF is congruent to ΔDGF and ΔEFG is congruent to ΔEGD by Side-side-side (SSS) postulate
Which represents the number 7,776 in exponential form? 68 36 28 65
Answers
Use a table of function values to approximate an x-value in which the exponential function exceeds the polynomial function. f(x) = 5x + 4 h(x) = x2 + 8x + 24
x = -3
x = 3
x = 4
x = 5
Answers
The polynomial function is [tex]h(x)= x^{2} +8x+24[/tex]
We want a value of x as such that [tex]f(x)\ \textgreater \ h(x)[/tex], so
[tex] 5^{x}+4 [/tex] > [tex] x^{2} +8x+24[/tex]
We are provided with four possible value of x. By process of trial and error, we will narrow down two values of x when the statement is changing from false to true
first, we try [tex]x=-3[/tex] by substituting into [tex]f(x)[/tex] and [tex]h(x)[/tex]
[tex] f(-3)=5^{-3}+4 = 4.008 [/tex] and [tex]h(-3)= (-3)^{2}+8(-3)+24=9 [/tex]
so [tex]f(x)[/tex]>[tex]h(x)[/tex] which is not the inequality wanted
We try [tex]x=3[/tex] by substituting into [tex]f(x)[/tex] and [tex]h(x)[/tex]
[tex]f(3)= 5^{3}+4=129 [/tex] and [tex]h(3)= (3)^{2}+8(3)+24=57 [/tex],
so [tex]f(x)[/tex] > [tex]h(x)[/tex] as wanted
We know that any values of [tex]x[/tex] greater than three will give [tex]f(x)[/tex] greater than [tex]h(x)[/tex], so we narrow down to two values that make the statement changes from false to true.
There is one value between -3 and three that makes [tex]f(x)[/tex] greater than [tex]h(x)[/tex]. From here we use the method of trial and error.
We can start with the mid value between -3 and three which is 0
[tex]f(0)= 5^{0}+4=5 [/tex]
[tex]h(0)= 0^{2}+8(0)+24=24 [/tex]
[tex]f(x)[/tex] is less than [tex]h(x)[/tex] which isn't the inequality we want so here we narrow down the value of x must be between 0 and 3
We can try mid-value between 0 and three which is 1.5
[tex]f(1.5)= 5^{1.5}+4=15.18 [/tex]
[tex]h(1.5)= (1.5)^{2}+8(1.5)+24=38.25 [/tex]
[tex]f(x)[/tex] is still less than [tex]h(x)[/tex], so we now narrow down the value of x between 1.5 and 3
We try again using the mid-value between 1.5 and three which is 2.25
[tex]f(2.25)= 5^{2.25}+4=41.38 [/tex]
[tex]h(2.25)= 2.25^{2}+8(2.25)+24=47.0625 [/tex]
We still have [tex]f(x)[/tex] less than [tex]h(x)[/tex] so we can narrow down further the value of x between 2.25 and 3 (which is quite a short interval already)
We can keep trying by choosing a value of x says x=2.6
[tex]f(2.6)= 5^{2.6}+4=69.66 [/tex]
[tex]h(2.6)= 2.6^{2}+8(2.6)+24=51.56 [/tex]
We have [tex]f(x)[/tex] greater then [tex]h(x)[/tex]
The narrowing down process continues where we now have the interval of x between 2.25 and 2.6. Keeping to one decimal place we can find the
value of x=2.4 is the approximate value where [tex]f(x)[/tex] is greater than [tex]h(x)[/tex].
Answer: x=2.4
The correct answer is x = 5.
Trust me, I just did the quiz.
what's the exact circumference of the circle
a. 7p cm
b. 5p cm
c. 10p cm
d. 4p cm
Answers
Answer:
B
Step-by-step explanation:
not sure
To solve the system of linear equations 3x+5y=2 and 6x+10y=8 by using the linear combination method, Laura correctly multiplied the first equation by –2 to get -6x-10y=-4 and then correctly added the equations -6x-10y=-4 and and then correctly added the equations -6x-10y=-4 and 6x+10y=8 to get 0 = 4. How many solutions are there to the system of equations?
A. 0
B. 1
C. 2
D. 4
Answers
Answer:
The two linear equation are
1. 3 x + 5 y =2
2. 6 x + 10 y = 8
If you will multiply equation (1), by number ,2 you will get
6 x + 10 y=4
or, if you will divide equation 2,by 2 you will get ,line
2 × (3 x + 5 y)=2 × 4
3 x + 5 y=4
→Slope of line 1
[tex]=\frac{-3}{5}[/tex]
→Slope of line 2
[tex]=\frac{-6}{10}=\frac{-3}{5}[/tex]
→→Slope of two lines are equal , so they are parallel.
Parallel lines never intersect. So,there is no solution.
Option A: 0
Help please! The grades received by 200 students follow a normal distribution. The mean of the grades is 70%, and the standard deviation is 7%. The number of students who received a grade greater than 70% is about? and the number of students who got a grade higher than 84% is about?
Answers
The number of students who received a grade greater than 70% is about 100, because 50% of the data is above the mean.
100% - 95% = 5%
(%5)2 = 2.5%
2.5 of 200 people is 5 people.
A square has sides 5.3cm long. Work out the area of the square
Answers
Answer:
Area of square = 28.09 square cm.
Step-by-step explanation:
Given : A square has sides 5.3 cm long.
To find : Work out the area of the square.
Solution : We have given
Side of square = 5 .3 cm .
Area of square = side * side .
Area of square = 5.3 * 5.3 .
Area of square = 28.09 square cm.
Therefore, Area of square = 28.09 square cm.
WILL GIVE A BRAINLIEST!! PLEASE HELP
Determine whether the sequence below is a geometric sequence and, if so, find a formula that describes the sequence.
3, 1, 1/3, 1/9, …
A.
a(n)=3x(1/3)n-1
B.
a(n)=1/3(3)n-1
C.
a(n)=3x(n-1)^3
D.
The sequence is not a geometric sequence.
Answers
Find z so that 6% of the standard normal curve lies to the left of z. remember that this means you are looking for the area (which means you need to find the 4 digit number in the area portion of table 3 that is closet to 6%).
Answers
We can solve this problem by referring to the standard normal probabilities table for z statistic.
At P = 0.06 to the left of z, this corresponds to a value of approximately z = -1.55
Answer: z = - 1.55 (P = 0.0606 ~ 0.06)
3 dice of different colors are rolled, and the number coming up on each die is recorded. how many different outcomes are possible?
Answers
When rolling three different dice, the number of possible outcomes can be calculated by performing 6*6*6, which equals 216, as there are 6 possible results on each die.
Explanation:The question pertains to the count of distinct outcomes when rolling three differently colored dice. Each die has 6 possible outcomes (numbered 1 to 6). Since these are independent events, you multiply the number of outcomes of each event (or the number of outcomes of each die's roll) to get the total number of different outcomes for all the events combined. Hence, the total different outcomes would be 6*6*6 = 216
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Order these decimals form greatest to least 3.6; 0.36; 36; 0.036
Answers
Is your answer.
in an isosceles trapezoid, how do you prove the base angles are congruent?
Answers
Find the critical value of t for a sample size of 23 and a 99% confidence level. choose the correct value from below:
Answers
For using t - table we need degree of freedom and alpha either for two tailed test or one tailed test.
We can determine degree of freedom by subtracting sample size from one.
So in given question sample size is 23. So we can say degree of freedom(df) for sample size 23 is
df = 23 - 1= 22
Now we have to go on row for degree of freedom 22.
After that we need to find alpha either for two tailed test or one tailedl test.
Confidence level is 99%. We can convert it into decimal as 0.99.
So alpha for two tailed test is 100 - 0.99 = 0.01
Alpha for one tailed test is 0.01/2 = 0.005.
So we will go on column for 0.01 for two tailed test alpha or 0.005 for one tailed test alpha.
SO the critical value 22 degree of freedom and 0.01 two tailed alpha is 2.819 from t - table.
To find the critical t-value for a sample size of 23 at a 99% confidence level, you need to use the degrees of freedom (df=22) and locate the t-value that corresponds to the 0.995 area in the t-distribution, which can be found using tables or a calculator's invT() function.
Explanation:The question pertains to finding the critical t-value for a sample size of 23 at a 99% confidence level. To determine this, you need to take into account the degrees of freedom (df), which is the sample size minus one (n-1). In this case, df = 23 - 1 = 22. Since the confidence level is 99%, there is 1% left for the two tails combined in a two-tailed test. This means that for each tail, the area is 0.5%. Therefore, you look for the t-value that corresponds to the area to the left, which is 1 - 0.005 = 0.995. Using a t-distribution table or a calculator function such as invT(), you find the critical t-value that would place an area of 0.995 to the left of it.
Remember that you might not directly find the exact degrees of freedom in some t-distribution tables, and you may need to interpolate between the provided values. The exact critical value would typically be found using statistical software or a graphing calculator that can output precise t-values for non-standard degrees of freedom and confidence levels.
Line segment SU is dilated to create S'U' using point Q as the center of dilation.
The scale factor of the dilation is:
Answers
QS : QS' = 4 : 8 = QU : QU' = 5 : 10 = 1 : 2
Then the scale factor is of the dilation is 2 (magnification)
I hope that helps!
If a point divides any line segment into two equal parts, then the point is the mid-point of that line. The ratio of the whole line segment and the distance from mid-point to any end point of the line segment is always 2:1, hence the scale factor of the dilation is 2.
To find the scale factor of the dilation, we need to find the ratio from initial point of the line segment to the distance from the point that is lie on that line segment.
Following points can be concluded from the given conditions.
It is shown in the figure that the distance from Q to S is 4 unit, and the distance from Q to S' is 8 unit.The distance from Q to U is 5 unit and the distance from Q to U' is 10 unit.U and S both are the mid-points of the line segment QU' and QS' respectively.The ratio of the whole line segment and the distance from mid-point to any end point of the line segment is always 2:1, hence the scale factor of the dilation is 2.
To know more about the scale factor, please refer to the link:
https://brainly.com/question/20449840
Given a soda can with a volume of 15 and a diameter of 2, what is the volume of a cone that fits perfectly inside the soda can?
Answers
so, a cone, that fits inside the cylinder, will have the same height "h" and radius "r". Thus
[tex]\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h\qquad \boxed{\pi r^2 h}=15 \\\\\\ \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}\implies V=\cfrac{\boxed{15}}{3}[/tex]