Find the mass of the cone using the triple beam balance. a. 543.0 g b. 542.0 g c. 504.28 g d. 502.8 g Please select the best answer from the choices provided

Answer:

(See sketch attached.)

Explanation:

The molecular formula of dibromoethene is [tex]\rm C_2H_2Br_2[/tex].

Consider the structure of this compound. A carbon-carbon double bond connects two carbon atoms. There are two hydrogen atoms and two bromine atoms attached to the two carbon atoms. The two bromine atoms might be on the same side of the double bond. Alternatively, they may be on opposite sides of the double bond. There are thus two structural isomers with this molecular formula:

The C-Br bond is polar. There's no way that the dipole due to these bonds will balance each other in 1,1-dibromoethene.

However, these dipoles might indeed balance each other in 1,2-dibromoethene. The two bromine atoms might be either on the same side of the molecule (structure 2) or on opposite sides along the diagonal (structure 1). Besides, unlike groups on two ends of a single bond, groups on the two ends of a C=C double bond cannot rotate freely along the bonding axis. As a result, structure 1 and 2 cannot interconvert without breaking bonds. Structures 1 and 2 are configurational geometric isomers.

The dipoles due to the two C-Br bond balance each other along the diagonal in structure. Thus there's no net dipole in structure 1.

The dipoles due to the two C-Br bonds will not balance each other in structure 2. As a result, there will be net dipole in structure 2.

A Lewis structure is a graphic representation of a molecule's valence electrons and the chemical bonds holding its atoms together. It is sometimes referred to as an electron dot diagram or Lewis electron dot structure.

The Lewis structures for the three dibromoethene isomers are shown here. [tex](C_2H_2Br_2):[/tex]

1,1-Dibromoethene

H H

| |

C=C

| |

Br Br

Due to the dipole moments of the two Br-C bonds canceling one other out, this isomer has no net dipole moment.

1,2-Dibromoethene

H Br

| |

C=C

| |

Br H

Because the dipole moments of the two Br-C bonds do not cancel one other out, this isomer has a net dipole moment. From the Br atoms to the H atoms, the dipole moment is directed.

trans-1,2-Dibromoethene

Br H

| \

C=C

| /

Br H

Because the dipole moments of the two Br-C bonds do not cancel one other out, this isomer likewise possesses a net dipole moment. From the Br atoms to the H atoms, the dipole moment is directed.

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Answer:

An oxidation-reduction reaction  

Explanation:

[tex]\stackrel{\hbox{-2}}{\hbox{C}}\text{$_{6}$H$_{12}$O$_{6}$} + 6\stackrel{\hbox{0}}{\hbox{O}\text{$_{2}$}} \longrightarrow 6\stackrel{\hbox{+4}}{\hbox{C}}\text{O$_{2}$}} + 6\text{H$_{2}$}\stackrel{\hbox{-2}}{\hbox{O}}[/tex]

Look at the oxidation numbers of the atoms.

Each carbon atom in glucose loses four electrons (oxidation), and each oxygen atom in O₂ gains two electrons (reduction).

The answer is C). Good luck.

If the solubility of potassium nitrate (KNO3) is 320 g/dm3,  potassium nitrate can be dissolved in 16 cm3 of water is 5.12 g. The correct option is C.

The solubility is the ability of a solute to gets dissolved in the solvent and form a solution.

The solubility for (KNO3) is 320 g/dm3.

Volume of water to be dissolved is

16cm³ = 0.016 dm³

Then the solubility for the given volume will be

320 g/dm³ x 0.016 dm³ = 5.12 g

Thus, if the solubility of potassium nitrate (KNO3) is 320 g/dm3,  potassium nitrate can be dissolved in 16 cm3 of water is 5.12 g. The correct option is C.

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Answer:

7,72Е24

Explanation:

if one mole is 6.022*10²³, then 6.41 moles are: 6.41*6.022*10²³*2=2*3.86*10²⁴=7.72E24 (atoms).

PS/ Formula of Br is Br₂.

The statement for, "endothermic reaction has high energy for breaking bonds" has been true.

The chemical reaction has been differentiated as the endothermic and exothermic reaction based on the energy absorbed or release by the system.

The chemical compounds have been consisted of the conserved energy that has been released by the chemical when they break the bond. The energy has been absorbed by the bonds for the formation of new bonds.

The endothermic reaction has been given as the reaction that has been absorbed the energy from the surrounding for the breaking of bonds.

In the endothermic reaction, the energy for breaking bonds has been higher than the energy required to form new bonds in the products.

Thus, the system absorbs the energy from the surrounding and result in the rise in temperature of the system.

Thus, the statement for, "endothermic reaction has high energy for breaking bonds" has been true.

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Answer:

True

Explanation:

Got it right on the quiz

Answer:

A. CaCO₃(s) → CaO(s) + CO₂(g).

B. Decomposition reaction.

C. 29.46 g.

D. 93.94%

Explanation:

A. Write the balanced the reaction

CaCO₃(s) → CaO(s) + CO₂(g),

1.0 mol of CaCO₃ is decomposed to produce 1.0 mol of CaO and 1.0 mol of CO₂.

B. Identify the reaction type (single replacement, double replacement, synthesis, decomposition or combustion).

A decomposition reaction is a type of chemical reaction in which a single compound breaks down into two or more elements or new compounds.

Herein, CaCO₃ is decomposed to produce CaO and CO₂.

C. What is the theoretical yield of carbon dioxide gas (in grams)?

n = mass/molar mass = (67.0 g)/(100.08 g/mol) = 0.6695 mol.

Using cross-multiplication:

1.0 mol of CaCO₃ produces → 1.0 mol of CO₂, from stichiometry.

∴ 0.6695 mol of CaCO₃ produces → 0.6695 mol of CO₂.

∴ The theoretical yield of carbon dioxide gas = n*molar mass = (0.6695 mol)(44.0 g/mol) = 29.46 g.

D. What is the percent yield if 27.67 grams of carbon dioxide gas are actually produced?

∵ the percent yield = (actual yield/theoretical yield)*100.

actual yield = 27.67 g, theoretical yield = 29.46 g.

∴ the percent yield = (27.67 g/29.46 g)*100 = 93.94%.

Answer:

Explanation:

1) Word equation (given):

• Dinitrogen gas + dihydrogen gas → gaseous ammonia.

2) Chemical equation:

• N₂ (g) + 3H₂ (g) → 2NH₃ (g)

3) Mole ratios:

• 1 mole N₂ (g) : 3 mole H₂ (g) : 2 mole NH₃ (g)

4) Reaction rates:

• Rate of dinitrogen consumption: r₁ = n₁ / t (moles/s)

• Rate of ammonia production: r₂ = n₂ / t (moles/s)

• Due to the stoichiometric ratios: r₂ = 2 × r₁

5) Calculate r₁:

• 284 liter / s

• PV = nRT ⇒ n = PV / (RT)

• Divide by time, t: n/t = P (V/t) / (RT)

• Substitute V/t = 284 liter/s, P = 0.75 atm, and T = 196 +273.15K = 469.15K

r₁ = n₁ / t = (0.75 atm) (284 liter/s) / [ (0.08206 atm-liter/K-mol) (469.15k) ]

= 5.53 moles/s

6) Calcualte r₂

7) Convert rate in mole/s to rate in kg/s

When the reaction is run at 196.°C and 0.75atm, the rate at which ammonia is being produced is 0.19 kg/s.

To calculate the rate:

Firstly mole ratios:

1 mole N₂ (g) : 3 mole H₂ (g) : 2 mole NH₃ (g)

The rate of dinitrogen consumption:

Rate of ammonia production: r₂ = n₂ / t (moles/s)

The stoichiometric ratios: r₂ = 2 × r₁

To calculate r₁:

284 liter / s

PV = nRT

n = PV / (RT)

t: n/t = P (V/t) / (RT)

V/t = 284 liter/s,

P = 0.75 atm,

T = 196 +273.15K = 469.15K

r₁ = n₁ / t = (0.75 atm) (284 liter/s) / [ (0.08206 atm-liter/K-mol) (469.15k) ]

= 5.53 moles/s

Find r₂

r₂ = 2 × r₁

= 2 × 5.53 mole/s

= 11.06 mole/s

7) Change rate in mole/s to rate in kg/s

mass in grams = molar mass × number of moles

molar mass of NH₃ = 17.03 g/mol

mass = 17.03 g/mol × 11.06 /s

= 188.4 g/s

Convert 188.4 g/s into kg/s: 0.1884 kg/s

The significant digits is 0.19 kg/s.

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Answer:

D

Explanation:

What an interesting amusing question.

The formula for KE = 1/2 m v^2.

v implies that there is motion.

The answer you are looking for is the body of water that has 0 for v.

A cloud moves, so it is not the answer.

A hailstone moves until it hits the ground. I'm assuming it's either on it's way down or it is caught in some sort of updraft in a cumulonimbus cloud. So it has motion.

Same comment for a raindrop. It has a v until it hits the ground so I'm assuming it is not the answer.

I've never seen a puddle of water move. It can only evaporate. So of all your choices, this one (D) is likely the right answer.

Answer:

[tex]\boxed{\text{n + A $\longrightarrow$ B + C + n}}[/tex]

Explanation:

When a neutron hits the nucleus of a heavy atom, the nucleus splits into two fragments of roughly equal mass and emits two or three neutrons.

A model that fits the process is

[tex]\boxed{\textbf{n + A $\longrightarrow$ B + C + n}}[/tex]

Answer : The correct option is, [tex]A\rightarrow B+C+n[/tex]

Explanation :

Nuclear fusion : It is a process where the two small nuclei converted to form a heavy nuclei and release some energy.

Nuclear fission : It is a process where a heavier nuclei (unstable nuclei) converted into two or more small (stable nuclei) and release some energy.

From the given reactions, we conclude that the reaction that shows the nuclear fission reaction is:

[tex]A\rightarrow B+C+n[/tex]

Hence, the nuclear fission reaction is, [tex]A\rightarrow B+C+n[/tex]

Answer:

I will work only one of the listed equations ... you follow the given example for the remaining reactions. Thank you :-)

Rxn 1: Pt°(s) + Fe⁺²(aq) ⇄ Pt⁺²(aq) + Fe°(s)

a) E(Pt⁺²/Fe°) = - 1.668v

b) Process is Non-spontaneous if E(cell) < 0

Explanation:

Pt°(s) + Fe⁺²(aq) ⇄ Pt⁺²(aq) + Fe°(s) ⇔

Pt°(s)|Pt⁺²[0.057M]║Fe⁺²[0.006M]|Fe°(s)

As written, Pt° is shown undergoing oxidation with Fe⁺² undergoing reduction. Applying the reduction potentials to the analytical equations for E(cell) and ΔG(cell) gives E(Pt/Fe⁺²) < 0 and ΔG(Pt/Fe⁺²) > 0 which indicate a non-spontaneous process. The following supports this conclusion.

E°(Fe⁺²) = -0.44v

E°(Pt⁺²) = +1.20v

E°(Pt/Fe⁺²) =E°(Redn) - E°(Oxidn) =E°(Fe⁺²) - E°(Pt⁺²)

= -0.44v - (+1.20v) = - 1.64v

[Fe⁺²] = 0.0066M

[Pt⁺²] = 0.057M

n = electrons transferred = 2

E(nonstd) = E°(std) - (0.0592/n)logQ);

Q = [Pt⁺²]/[Fe⁺²]

= -1.64v - (0.0592/2)log[0.057M]/[0.006M]v = -1.668v

Also, if ΔG(cell) > 0 => indicates non-spontaneous process

ΔG(Pt/Fe⁺²) = - nFE = -(2)(96,500Coulombs)((-1.664v) > 0 Kj => nonspontaneous rxn. (1 Coulomb-volt = 1 Kilojoule)

The Nernst equation is used to obtain the cell potential under standard conditions from the cell potential under nonstandard conditions.

Pt(s) + Fe^2+(aq) -------> Pt^2+ (aq) + Fe(s)

We have the following information from the question;

[Fe2+] = 0.0066M,   [Pt2+] = 0.057M

The standard reaction potential is; 1.18 V - (-0.44V) = 1.62 V

Using Nernst equation;

Ecell = E°cell - 0.0592/n log Q

Where;

Q = [Pt2+] /[Fe2+] =  0.057M/ 0.0066M = 8.636

Ecell = 1.62 V - 0.0592/2 log(8.636)

Ecell = 1.59 V

Cu(s) + 2Ag+(aq) -------> Cu2+(aq) + 2Ag(s)

The standard reaction potential is; 0.80 V - 0.34 V = 0.46 V

Q = [Cu2+]/[Ag+]^2 = 0.013/0.013^2 = 76.92

Ecell =  0.46 V - 0.0592/2 log(76.92)

Ecell = 0.40 V

Co2+(aq) + Ti3+(aq) -------> Co3+(aq) + Ti2+(aq)

The standard reaction potential of the reaction is; 1.92 V  - (-0.37) = 2.29 V

Q = [Ti2+] [Co3+]/[Co2+] [Ti3+] = [0.0110] [0.030]/[0.050] [0.0055] = 0.00033/0.000275 = 1.2

Ecell = 2.29 V - 0.0592/1 log(1.2)

Ecell = 2.28 V

Mg(s) + Sn2+(aq) --------> Mg2+(aq) + Sn(s)

The standard reaction potential of the reaction is; (-0.14 V) - (-2.37 V) = 2.23 V

Q = [Mg^2+]/[Sn^2+] = [0.796 M]/[0.0170 M] = 46.8

Ecell = 2.23 V - 0.0592/2 log(46.8)

Ecell = 2.18 V

Each of the cell is spontaneous as written since Ecell in each case is positive.

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Answer:

Option B is correct

Explanation:

The ideal gas formula can be used to find the Pressure of Nitrogen gas.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]

Here P is pressure, V is volume and T is temperature.

In the given question:

P₁ = 1.7 kPa

T₁ = -10°C Changing to Kelvin:  273.15 -10°C = 263.15 K

V₁ = 7.5 m^3

V₂ = 3.8 m^3

T₂ = 200 K

P₂ =?

Putting values in the formula

[tex]\frac{1.7 *7.5 }{263.15}=\frac{P_{2*3.8}}{200}\\\frac{12.75}{263.15}=\frac{P_{2}*3.8}{200} \\0.048 = \frac{P_{2}*3.8}{200}\\=> P_{2} = \frac{0.04845*200}{3.8}\\P_{2} = 2.55 \,\,kPa\\[/tex]

So, Option B is correct.

Answer:

B.) 2.55 kPa

Explanation:

I got it correct on founders edtell

Answer:

Si: 1s²2s²2p⁶3s²3p2

Explanation:

Other electron configuration summaries include ...

Si:[Ne]3s²3p2; [Ne] = electron configuration of noble gas Neon (1s²2s²2p⁶)

Si:[Ne]3s²2p₋₁¹p₀¹p₊₁⁰ <=> e⁻ configuration with orbital orientations

Si:[Ne]3s(↑↓)3p₋₁(↑)p₀(↑) <=> Orbital Diagram

Final answer:

The ground-state electron configuration for silicon (Si) is determined by the Aufbau principle, which gives us Si: 1s²2s²2p¶3s²3p².

Explanation:

The ground-state electron configuration for silicon (Si), which has an atomic number of 14, is determined using the Aufbau principle. Starting with the lowest energy subshell, we continue to fill each subshell according to the prescribed order until all 14 electrons have been placed. Thus, following the order: 1s, 2s, 2p, 3s, 3p, the electron configuration for silicon will be:

Si: 1s²2s²2p¶3s²3p².

Here, each number represents the principal quantum number corresponding to the shell, while the letter indicates the subshell type. The superscript denotes the number of electrons in that particular subshell.

Answer:

2.453.

Explanation:

∵ pH = - log[H₃O⁺]

[H₃O⁺] = 0.00352 M.

∴ pH = - log[H₃O⁺] = - log(0.00352) = 2.453.

Answer:

See below  

Explanation:

a) Adding HCl

HBTB is yellow in acid solution.

b) Adding NaOH

HBTB is blue in basic solution.

c) Explanation

HBTB is a weak acid in which the undissociated and ionized forms have different colours.

[tex]\underbrace{\hbox{\text{HBTB }}}_{\hbox{\text{yellow}}} + \text{{ H$_{2}$O}}\rightleftharpoons \text{H$_{3}$O$^{+}$} +\underbrace{\hbox{\text{ BTB$^{-}$}}}_{\hbox{\text{blue}}}[/tex]

Around pH 7 , the indicator consists of roughly equal amounts of the yellow and blue forms, so it appears green

According to Le Châtelier's Principle, if you apply a stress to a system at equilibrium, it will respond in a way that will relieve the stress.

When you added HCl, you increased the concentration of H₃O⁺. The system responded in a way that would decrease the H₃O⁺. That is, the position of equilibrium shifted to the left and produced more of the yellow form.

When you added NaOH, the base removed some of the H₃O⁺. The system responded in a way that would increase the H₃O⁺. That is, the position of equilibrium shifted to the right and produced more of the blue form

Answer:

D

Explanation:

Any change of temperature will subsequent in a change of the equilibrium position. With reference to Le Chaterlier's principle, this equilibrium shift will occur in a manner as to neutralize the change that the system has undergone.

In this case, the temperature is seen to have decreased. To neutralize this effect, the equilibrium position will shift in a manner as to increase the temperature back to its previous state.

This equilibrium shift will occur by favoring the reaction the reaction which results in the release of heat -which is the formation of dinitrogen tetrahydroxide.

This will result in the presence of more dinitrogren tetrahydroxide relative to the amount of nitrogen dioxide in the system.

Answer:

The equilibrium will shift so that there is more dinitrogen tetroxide.

Explanation:

Answer for Educere/ Founder's Education

B. 6.0 grams of Cl2 are consumed to produce 12.0 g of KCl.

Potassium chloride is a major remixing option for the food industry to reduce sodium in foods. Simple Facts About Potassium Chloride: Potassium Chloride (KCl) is a naturally occurring potassium salt that is usually extracted from the ground or the sea.

KCL is currently Europe's largest medical learning center, with three teaching hospitals and more than 27,000 students (including about 10,500 graduate students) from 150 countries, including law and humanities. We also utilize the strengths of science and the humanities. advantage.

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I think A is correct:

deltaH=(Enthalpie of reactents)-(Enthalpie of products)=110.525+285.5-393.5=2.525~2.825

Answer:

A. The enthalpy change for the reaction is 2.825 kJ

Explanation:

The given reaction is:

CO + H2O → H2 + CO2

The enthalpy change for a reaction is given as:

[tex]\Delta H = \sum n(p)\Delta H_{f}^{0}(products)-\sum n(r)\Delta H_{f}^{0}(reactants)[/tex]

where np and nr are the number of moles of products and reactants

ΔH⁰f are the standard enthalpies of formation of the respective reactants and products

[tex]\Delta H = [1\Delta H_{f}^{0}(H2)+1\Delta H_{f}^{0}(CO2)]-[1\Delta H_{f}^{0}(CO)+1\Delta H_{f}^{0}(H2O)][/tex]

Substituting the given enthalpy data:

ΔH = [1(0) + 1(-393.5)] - [1(-110.525) + 1(-285.8)] = 2.825 kJ

What are the choices?

A proton is changed over into a neutron by the emanation of a positron with a neutrino.

In atomic material science, beta decomposition (β-rot) is a sort of radioactive rot wherein a beta molecule (quick lively electron or positron) is transmitted from a nuclear core, changing the first nuclide to its isobar.

For instance, beta rot of a neutron changes it into a proton by the discharge of an electron joined by an antineutrino; or, then again a proton is changed over into a neutron by the emanation of a positron with a neutrino in supposed positron outflow.  

IR spectrum shows characteristic peaks for each functional groups. The band arise in the region, 3000-3100  corresponds to the OH group and the band in the range of 2850-2660 cm⁻¹corresponds to the C-H  stretching and the band at 1650 cm⁻¹ indicates the presence of C=C stretching.

Infrared spectroscopy is analytical tool deal with the vibrational transition in molecules by the absorption of infrared radiation. Molecules which exhibit a change in dipole moment during vibration are IR active.

Ir spectroscopy is also called as vibrational spectroscopy, because the wavenumber corresponding to different modes of vibrations are measuring in this spectroscopic technique.

Each functional group have characteristic vibrational movements and corresponding bands in the IR spectrum . Hence, it is very useful for structural elucidation of molecules.

The bands in the region 3000-3100 cm⁻¹ corresponds to the stretching of OH group. Similarly the C-H stretching falls in the region of 2850-2660 cm⁻¹. A band at 1650 cm⁻¹ indicates the presence of C=C in the molecule.

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Final answer:

The infrared absorption spectrum indicates the presence of C-H stretching vibrations and a C=C double bond in the compound, classifying it as an alkene.

Explanation:

The infrared absorption spectrum of a C6 hydrocarbon shows key bands that allow us to deduce the functional groups present. The bands at 3000-3100 cm-1 (w), although weak, suggest the presence of C-H stretching vibrations in an alkane or alkene, since they fall within the range of 2850-2960 cm-1 (m) typical for sp3-hybridized carbons in alkanes. The band at 1650 cm-1 (w) is indicative of a C=C double bond suggestive of an alkene, as similar absorptions would be seen for carbonyl (C=O) stretching vibrations in ketones, aldehydes, or carboxylic acids, but those would typically have a stronger intensity and appear around 1715-1735 cm-1.

Thus, the evidence from the absorption spectrum suggests that this hydrocarbon belongs to the functional class of alkenes.

The empirical formula of the hydrocarbon is C1H3, calculated from the products of combustion. Using the molecular weight approximation of 132 amu, the molecular formula determined is C8H24.

To determine the empirical formula of the hydrocarbon, we analyze the products from its combustion. Since the sample produced 0.4931 g of CO2, we calculate the moles of carbon:

0.4931 g CO2 × (1 mol CO2/44.01 g CO2) = 0.01120 mol CO2
0.01120 mol CO2 corresponds to 0.01120 mol C (since there is 1 C in each CO2 molecule).

Similarly, given 0.2691 g of H2O:

0.2691 g H2O × (1 mol H2O/18.02 g H2O) = 0.01493 mol H2O
This gives us 0.02986 mol H (since there are 2 H in H2O).

The molar ratio of C to H can be simplified by dividing by the smaller number of moles:

Molar ratio C:H = 0.01120 mol C : 0.02986 mol H
We reduce this ratio to the simplest whole numbers to get the empirical formula:

(0.01120 / 0.01120) : (0.02986 / 0.01120) = 1:2.67
Approximating to whole numbers, we get C1H3 as the empirical formula.

To find the molecular formula, we use the given molecular weight (approximately 132 amu). Since the empirical formula weight of C1H3 is 12 (for C) + 3 (for H) = 15 amu, we calculate the multiplier:

Molecular weight / Empirical formula weight = 132 amu / 15 amu ≈ 8.8
This multiplier indicates the molecular formula is approximately 8 or 9 times the empirical formula. A whole number will result when using 8, thus we get the molecular formula C8H24.

Answer:

Explanation:

1) Chemical equation (unbalanced)

2) Balanced chemical equation:

3) Mole ratio:

4) Volume ratio:

Since the reaction is carried out at constant pressure and temperature, the volume ratios are equal to the mole ratios. Then:

Hence, 1.00 liter of CO gas produces 1.00 liter of CO₂

3) Mass of carbon dioxide:

a) Use ideal gas equation to convert 1.00 liter CO₂ produced to moles:

b) Convert moles to mass in grams

Answer:

1.00L

1.96G

0.500mol

0.750mol

16.8L

Explanation:

Answer:

D. Zn → Zn²⁺ + 2e⁻, 2H⁺ + 2e⁻ → H₂.

Explanation:

Oxidation reaction:

Zn losses 2 electrons and is oxidized to Zn²⁺:

Zn → Zn²⁺ + 2e⁻.

Reduction reaction:

H⁺ gains 1 electron and is reduced to H:

2H⁺ + 2e⁻ → H₂.

So, the right choice is: D. Zn → Zn²⁺ + 2e⁻, 2H⁺ + 2e⁻ → H₂.

Answer:

D. Zn → Zn²⁺ + 2e⁻, 2H⁺ + 2e⁻ → H₂.

Explanation:

Answer via Educere/ Founder's Education

When ln K is negative, it means the equilibrium constant K is less than one, which results in a positive Gibbs free energy (ΔGrxn), indicating that the reaction is spontaneous in the reverse direction.

If ln K is negative, this indicates that the equilibrium constant, K, is less than one. According to thermodynamic principles, this means that the Gibbs free energy (ΔGrxn) for the reaction under standard conditions is positive, and therefore, the reaction is spontaneous in the reverse direction.

This is because the natural logarithm of a number less than one yields a negative value, and since ΔG° is related to ln K by the negative product with the gas constant (R) and temperature (T), ΔG° becomes positive when ln K is negative. So, the correct statement is 'ΔGrxn is positive and the reaction is spontaneous in the reverse direction.' A negative ΔGrxn would indicate a reaction that is spontaneous in the forward direction. If ΔGrxn were zero, the system would be at equilibrium and K would equal one.

Answer:

number 2 is correct

Explanation:

Among the options you provided, the correct answer for the cause of tornadoes is option 1: cool, dry air meeting warm, moist air.

Tornadoes typically form in severe thunderstorms where there is a significant clash between different air masses. The interaction of cool, dry air and warm, moist air sets up the conditions necessary for tornado development. This collision can create instability in the atmosphere, leading to the formation of a rotating column of air that extends from the base of a thunderstorm cloud to the ground.

Among the options you provided, the correct answer for the cause of tornadoes is option 1: cool, dry air meeting warm, moist air.

The correct option is 1.

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Answer:

Explanation:

The number of half-lives elapsed, n, is calculated dividing the time by the half-life time:

a. A sample of Ce-141 with a half-life of 32.5 days after 32.5 days

b. A sample of F-18 with a half-life of 110 min after 330 min

c. A sample of Au-198 with a half-life of 2.7 days after 5.4 days

Explanation:

Since, aluminium chloride is an eye and skin irritant. Therefore, it is better to follow safety measures while dealing with such a chemical.

Hence, it is good to wear a lab coat while working in a laboratory and wear chemical resistant gloves so that our skin does not come in contact with the chemical.

Also, safety glasses will prevent the eyes if there is spurting of chemical.

Thus, we can conclude that chemical-resistant gloves, a lab coat, and safety glasses will prevent you from coming into contact with the given hazard.

Answer: chemical-resistant gloves, a lab coat, and safety glasses

Answer:

I think it is B.

Explanation:

Hope my answer has helped you!

Answer:

The reaction will move to the left.

Explanation:

Ba(OH)₂ = Ba²⁺ + 2OH⁻,

Ba(OH)₂ is dissociated to Ba²⁺ and 2OH⁻.

H⁺ will combine with OH⁻ to form water.

So, the concentration of OH⁻ will decrease and the equilibrium is disturbed.

According to Le Châtelier's principle: when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.

So, the right choice is: the reaction will move to the left, is the choice that will not happen to the equilibrium.

Answer:

D.) The reaction will move to the left.

Explanation:

Answer:

the answer is c :) hope this helps buddy:))

Answer:

C. Fe in Fe₂O₃

Explanation:

The sum of the oxidations states times the atomicity is equal to the charge of the molecule.

A.

2.H + 1.P + 4.O = -1

2.(1+) + 1.P + 4.(2-) = -1

P = +5

B.

2.Cr + 7.O = -2

2.Cr + 7.(-2) = -2

2.Cr = 12

Cr = +6

C.

2.Fe + 3.O = 0

2.Fe + 3.(-2) = 0

2.Fe = 6

Fe = +3

Fe has the lowest oxidation state (+3).