Find the limit of the function algebraically. limit as x approaches negative nine of quantity x squared minus eighty one divided by quantity x plus nine.

In this question , it is given that

A right triangle ABC is shown. Leg AC has length 24, leg BC has length 32, and hypotenuse AB has length 40.

And we have to find the values of sin A and cos A .

[tex]sin A  = \frac{opposite}{hypotenuse} = \frac{32}{40}[/tex]

[tex]sin A = \frac{4}{5}[/tex]

And

[tex]cos A = \frac{adjacent}{hypotenuse} = \frac{24}{40}[/tex]

[tex]cos A = \frac{3}{5}[/tex]

And these are the required values of sin A and cos A .

The solution to the equation 8(x-1) - 2x = -(x + 50) is x = -6.

To solve the equation 8(x-1) - 2x = -(x + 50).

First, distribute the 8 to the terms inside the parentheses:

8x - 8 - 2x = -(x + 50)

Simplify the left side of the equation:

6x - 8 = -(x + 50)

Distribute the negative sign to the terms inside the parentheses:

6x - 8 = -x - 50

Isolate the x terms on one side and the constant terms on the other side:

6x + x = -50 + 8

Combine like terms:

7x = -42

Divide both sides of the equation by 7:

7x / 7 = -42 / 7

x = -6

Therefore, the solution to the equation 8(x-1) - 2x = -(x + 50) is x = -6.

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Answer:

The equation of given graph is f(x)=[x]-6

C is correct

Step-by-step explanation:

We are given a graph and to find the equation of graph.

It is a graph of greatest integer function or floor function.

Parent function of greatest integer function:

[tex]f(x)=[x][/tex]

For x = 0 to x= 1 , f(x)=0

For x =1 to x=2 , f(x)=1

We are given a function,

For x = 0 to x= 1 , f(x)=-6

For x = 1 to x= 2, f(x) = -5

If we shift 6 unit down the parent function. We will get original function.

[tex]f(x)=[x]-6[/tex]

Hence, The equation of given graph is f(x)=[x]-6

The value of x makes the denominator of the function equal zero is 10

An equation is a mathematical expression that contains an equals symbol. Equations often contain algebra.

Given that:

y = [tex]\frac{6}{4x-40}[/tex]

Now the denominator is: 4x - 40

So, 4x =40

      x =40/4

      x =10

So, make the denominator 0, put x= 10.

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Answer: it’s D $325

Step-by-step explanation:

the fee the school should charge to maximize their revenue is $325

Answer:

the radius is perpendicular to the chord.

Step-by-step explanation:

The geometry is drawn in the image shown below in which AB is the chorh and O is the centre of the circle. Om is the radius which bisects the chord.(Given) So, AN = NB

From the image, considering ΔAON and ΔBON,

AO = BO (radius of circle)

AN = NB (given)

ON = ON (common)

So,

ΔAON ≅ ΔBON

Hence, ∠ANO = ∠BNO

Also, ∠ANO + ∠BNO = 180° (Linear Pair)

So,

∠ANO = ∠BNO = 90°

Hence, it is perpendicular to the chord.

Answer:

The answer above is correct! The answer is option D.

Step-by-step explanation:

Hope this helped clarify :D

Translating vertex A to vertex D, and then rotate △ABC around

point A to align the sides and angles will bring about a rigid

transformation.

This is the transformation which preserves the Euclidean

distance between every pair of points. This could be as a result

of the following:

Option D when done will preserve the distance between the

points when vertex A is translated to vertex D as they contain

the same angle with other sides and angles being made to

align.

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Answer:

[tex]\frac{60 - 10\sqrt10-6\sqrt3+\sqrt30}{97}[/tex]

Step-by-step explanation:

Hello!

To rationalize the denominator, we have to remove any root operations from the denominator.

We can do that by multiplying the numerator and denominator by the conjugate of the denominator. The conjugate simply means the same terms with different operations.

The answer is [tex]\frac{60 - 10\sqrt10-6\sqrt3+\sqrt30}{97}[/tex].

Answer: 35

Step-by-step explanation:

The rate of change of a graph is given by :-

[tex]k=\dfrac{\text{Change in y avlues}}{\text{Change in x values}}[/tex]

For points : (1, 35) and (2, 70)

The rate of change for the relationship in the graph is given by :-

[tex]k=\dfrac{70-35}{2-1}=35[/tex]

Hence, the rate of change for the relationship represented in the graph = 35.

The rate of change of the relationship shown in the graph is 35 miles per hour.

Linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the y intercept.

Let y represent the elevator height after x seconds.

From the graph using points (0, 0) and (4, 140):

m = (140 - 0)/(4 - 0) = 35

The rate of change of the relationship shown in the graph is 35 miles per hour.

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False, The measure of Arc AC is not 65 degree if angle ABC is equal to 78 degree.

What is Circle?

The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.

Given that;

The statement is,

The measure of Arc AC is 65 degree if angle ABC is equal to 78 degree.

Now,

Since, Sum of Measure of arc AC and angle ABC is equal to 360 degree.

So, In angle ABC is 78 degree.

Then, Measure of arc AC = 360 - 78

                                       = 282 degree.

Thus, The measure of Arc AC is not 65 degree if angle ABC is equal to 78 degree.

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Final answer:

The x- and y-components of the given vector are calculated using trigonometric functions, resulting in -5.16 km along the x-axis and 7.37 km along the y-axis, considering the direction of the vector relative to the axes.

Explanation:

The question asks to find the x- and y-components of the vector d⟷ = (9.0 km, 35° left of +y-axis). To solve this, we use trigonometric functions, specifically sine and cosine, because the vector makes an angle with the axis.

Given the vector makes a 35° angle to the left of the +y-axis, this effectively means it is 35° above the -x-axis (or equivalently, 55° from the +x-axis in the second quadrant). We can calculate the components as follows:

The negative sign in the x-component indicates that the direction is towards the negative x-axis. Therefore, the x- and y-components of the vector are -5.16 km and 7.37 km, respectively.

1. [tex]\(\mathf{d}\): \(d_x = -3.8 \text{ km}, d_y = 8.2 \text{ km}\)[/tex]

2. [tex]\(\mathf{v}\): \(v_x = -4.0 \text{ cm/s}, v_y = 0\)[/tex]

3. [tex]\(\mathf{a}\): \(a_x = 10.3 \text{ m/s}^2, a_y = -14.7 \text{ m/s}^2\)[/tex]

To find the [tex]\( x \)[/tex]- and [tex]\( y \)[/tex]-components of vectors given in terms of magnitude and direction, we need to decompose the vectors using trigonometric functions. Let's go through each problem step by step.

1. Find the [tex]\( x \)[/tex]- and [tex]\( y \)[/tex]-components of the vector [tex]\( \mathf{d} = (9.0 \text{ km}, 25^\circ \text{ left of } +\mathbf{y}\text{-axis}) \)[/tex].

First, understand that "25° left of +[tex]\( y \)[/tex]-axis" means the vector is rotated 25° counterclockwise from the [tex]\( y \)[/tex]-axis.

Decomposition:

- Magnitude, [tex]\( d = 9.0 \text{ km} \)[/tex]

- Angle from the [tex]\( y \)-axis, \( \theta = 25^\circ \)[/tex]

To find the components:

- [tex]\( d_x = d \sin(\theta) \)[/tex]

- [tex]\( d_y = d \cos(\theta) \)[/tex]

However, since the angle is counterclockwise from the [tex]\( y \)-axis[/tex] and to the left, the [tex]\( x \)[/tex]-component is negative.

Therefore:

- [tex]\( d_x = -9.0 \sin(25^\circ) \)[/tex]

- [tex]\( d_y = 9.0 \cos(25^\circ) \)[/tex]

Calculating these:

- [tex]\( d_x \approx -9.0 \times 0.4226 \approx -3.8 \text{ km} \)[/tex]

- [tex]\( d_y \approx 9.0 \times 0.9063 \approx 8.2 \text{ km} \)[/tex]

So, the components are:

- [tex]\( d_x \approx -3.8 \text{ km} \)[/tex]

- [tex]\( d_y \approx 8.2 \text{ km} \)[/tex]

2. Find the [tex]\( x \)[/tex]- and [tex]\( y \)[/tex]-components of the vector [tex]\( \mathf{v} = (4.0 \text{ cm/s}, -x \text{-direction}) \).[/tex]

Since the vector is given in the [tex]\(-x\)[/tex]-direction, it means the entire magnitude is in the [tex]\( x \)[/tex]-direction and negative.

Decomposition:

- Magnitude, [tex]\( v = 4.0 \text{ cm/s} \)[/tex]

- Direction: [tex]\(-x\)[/tex]

Therefore:

- [tex]\( v_x = -4.0 \text{ cm/s} \)[/tex]

- [tex]\( v_y = 0 \text{ cm/s} \)[/tex]

So, the components are:

- [tex]\( v_x = -4.0 \text{ cm/s} \)[/tex]

- [tex]\( v_y = 0 \text{ cm/s} \)[/tex]

3. Find the [tex]\( x \)[/tex]- and [tex]\( y \)[/tex]-components of the vector [tex]\( \mathbf{a} = (18 \text{ m/s}^2, 35^\circ \text{ left of } -y \text{-axis}) \)[/tex].

"35° left of -[tex]\( y \)[/tex]-axis" means the vector is rotated 35° counterclockwise from the negative [tex]\( y \)[/tex]-axis.

Decomposition:

- Magnitude, [tex]\( a = 18 \text{ m/s}^2 \)[/tex]

- Angle from the [tex]\(-y \)[/tex]-axis, [tex]\( \theta = 35^\circ \)[/tex]

To find the components:

- [tex]\( a_x = a \sin(\theta) \)[/tex]

- [tex]\( a_y = -a \cos(\theta) \)[/tex]

However, since the angle is counterclockwise from the [tex]\(-y \)[/tex]-axis and to the left, the [tex]\( x \)[/tex]-component is positive.

Therefore:

- [tex]\( a_x = 18 \sin(35^\circ) \)[/tex]

- [tex]\( a_y = -18 \cos(35^\circ) \)[/tex]

Calculating these:

- [tex]\( a_x \approx 18 \times 0.5736 \approx 10.3 \text{ m/s}^2 \)[/tex]

- [tex]\( a_y \approx -18 \times 0.8192 \approx -14.7 \text{ m/s}^2 \)[/tex]

So, the components are:

- [tex]\( a_x \approx 10.3 \text{ m/s}^2 \)[/tex]

- [tex]\( a_y \approx -14.7 \text{ m/s}^2 \)[/tex]

The correct question is:

1. Find the [tex]$x$[/tex] - and [tex]$y$[/tex]-components of the vector [tex]$d \boxtimes=(9.0 \mathrm{~km}, 25 \boxtimes$[/tex] left of [tex]$+\mathrm{y}$[/tex]-axis).

2. Find the [tex]$\mathrm{x}$[/tex] - and [tex]$\mathrm{y}$[/tex]-components of the vector [tex]$\mathrm{v} \boxtimes=(4.0 \mathrm{~cm} / \mathrm{s},-\mathrm{x}$[/tex]-direction [tex]$)$[/tex].

3. Find the [tex]$x$[/tex] - and [tex]$y$[/tex]-components of the vector [tex]$a \boxtimes=(18 \mathrm{~m} / \mathrm{s} 2,35 \boxtimes$[/tex] left of [tex]$-y$[/tex]-axis [tex]$)$[/tex].

The true statements about functions f(x) and g(x) are:

The function f(x) is given as:

f(x) = 4^x

From the table of values, we can see that the function g(x) is 1 less than the function f(x).

This means that:

g(x) = f(x) - 1

This can be rewritten as:

g(x) = 4^x - 1

In transformation, it means that the function f(x) is translated 1 units down to get the function g(x)

Hence, the true statements are: b and d

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Answer:

B.

Step-by-step explanation:

Answer: b. 23 cm

Step-by-step explanation:

We know that area of a triangle is given by :-

[tex]\text{Area}=\dfrac{1}{2}bh[/tex], where b is the base of triangle and h is the height of the triangle.

Given : The area of a triangle is [tex]92\ cm^2[/tex]

The base of the triangle = 8 cm

Let h be the height of the triangle , then we have

[tex]92=\dfrac{1}{2}(8)h\\\\\Rightarrow\ h=\dfrac{92}{4}\\\\\Rightarrow\ h = 23[/tex]

Hence, the height of the triangle = 23 cm

Answer:

Step-by-step explanation:

Alright, lets get started.

The given increase is 25 %.

Which means in terms : [tex]25*\frac{1}{100}[/tex]

That will be equal to : [tex]0.25[/tex]

So, the growth of 0.25 means the complete term will be :

[tex]1+0.25=1.25[/tex]

Hence the growth factor of 25 % will be equal to 1.25    :    Answer

Hope it will help :)

Answer: 13 units

Step-by-step explanation:

The distance formula to calculate distance between two points (a,b) and (c,d) is given by :-

[tex]d=\sqrt{(d-b)^2+(c-a)^2}[/tex]

Given points : (13, 20) and (18, 8)

Now, the distance between the points (13, 20) and (18, 8)is given by ;-

[tex]d=\sqrt{(8-20)^2+(18-13)^2}\\\\\Rightarrow\ d=\sqrt{(-12)^2+(5)^2}\\\\\Rightarrow\ d=\sqrt{144+25}\\\\\Rightarrow\ d=\sqrt{169}\\\\\Rightarrow\ d=13\text{units}[/tex]

Hence, the distance between the points (13, 20) and (18, 8) is 13 units.