Find the derivative of the function y = sin(tan 4x)

Answers

Answer 1
[tex]\bf y=sin[tan(4x)]\implies \cfrac{dy}{dx}=\stackrel{chain~rule}{cos[tan(4x)]\cdot sec^2(4x)\cdot 4} \\\\\\ \cfrac{dy}{dx}=4cos[tan(4x)]sec^2(4x)[/tex]

Related Questions

Write 171 miles in 3 hours as a unit rate

Answers

mph is what you are going for

so 171/3 = 57

57mph is your answer

hope this helps

round 23.84 to 1 decimal point

Answers

23.8 is that all you need 

What is 0.2 repeated as a fraction?

Answers

0.2 in fraction form is 1/5

A given line has the equation 10x + 2y = −2.

What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12)?

Answers

10x + 2y = -2

2y = -10x -2

y = -5x - 1 (slope is -5 and a parallel line will have the same slope)


y = mx + b

slope(m) = -5

12 = -5(0) + b

12 = 0 + b

12 = b

so the parallel line is y = -5x + 12

hope this helps, God bless!

look at the figure if tan x=3/y and cos x =y/z what is the value of sin x?

Answers

Recall:

The tan of the measure of an angle is the ratio of the opposite side to the adjacent side to that angle, that is :

[tex]\displaystyle{ \tan x^{\circ}= \frac{opposite\ side}{adjacent \ side} [/tex]. 

Since this ratio is 3/y, we denote the opposite side, and adjacent side respectively by 3 and y. 

(Technically we should write 3t and yt, but we try our luck as we see y in the second ratio too!)


Similarly, [tex]\displaystyle{\cos x^{\circ}= \frac{adjacent\ side}{hypothenuse} [/tex].


The adjacent side is already denoted by y, so we denote the length of the hypotenuse by z.



Now the sides of the right triangle are complete. 

[tex]\displaystyle{ \sin x^{\circ}= \frac{opposite\ side}{hypotenuse}= \frac{3}{z} [/tex]


Answer: A

Answer: sin x° = 3/z( answer

Because tan is opposite/adjacent,

Cos is adjacent/hypotenuse and sin is opposite/hypotenuse the information to find sin is given. You simply take the opposite (3) and put it over the hypotenuse (z)

sin x°= 3/z

We want to build a box whose base is square, has no top and will enclose 100 m^3. determine the dimensions of the box that will minimize the amount of material needed to construct the box.

Answers

The dimensions of the box that minimizes material usage, enclosing 100 m³ with no top, are approximately 5.848 meters for the square base side length and 2.682 meters for the height.

Let's denote the side length of the square base as x meters and the height of the box as h meters. Since the box has no top, the volume (V) of the box is given by the product of the area of the square base and the height:

[tex]\[ V = x^2 \cdot h \][/tex]

Given that [tex]\(V = 100 \, \text{m}^3\)[/tex], we have the equation:

[tex]\[ 100 = x^2 \cdot h \][/tex]

Now, we want to minimize the amount of material needed to construct the box, which is the surface area (A) of the box. The surface area is the sum of the area of the square base and the areas of the four sides:

[tex]\[ A = x^2 + 4xh \][/tex]

To minimize A, we can express h in terms of x from the volume equation and substitute it into the surface area equation:

[tex]\[ h = \frac{100}{x^2} \]\[ A(x) = x^2 + 4x\left(\frac{100}{x^2}\right) \]\[ A(x) = x^2 + \frac{400}{x} \][/tex]

Now, to find the minimum amount of material, we take the derivative of A with respect to x and set it equal to zero:

[tex]\[ \frac{dA}{dx} = 2x - \frac{400}{x^2} = 0 \][/tex]

Multiply through by x^2 to get rid of the fraction:

[tex]\[ 2x^3 - 400 = 0 \][/tex]

Solve for x:

[tex]\[ x^3 = 200 \]\[ x = \sqrt[3]{200} \][/tex]

Now that we have x, we can find h using the volume equation:

[tex]\[ h = \frac{100}{x^2} \]\[ h = \frac{100}{(\sqrt[3]{200})^2} \]\[ h = \frac{100}{\sqrt[3]{400}} \][/tex]

The dimensions of the box that will minimize the amount of material needed are approximately [tex]\(x \approx 5.848\)[/tex] meters and [tex]\(h \approx 2.682\)[/tex] meters.

A sphere with a diameter of 16mm has the same surface area as the total surface area of a right cylinder with the base diameter equal to the sphere diameter. How high is the cylinder?

Answers

Final answer:

The height of the cylinder is 8mm.

Explanation:

To find the height of the cylinder, we need to first find the surface area of the sphere. The surface area of a sphere is given by the formula: 4πr^2. Since the diameter of the sphere is 16mm, the radius is half of that, which is 8mm. Plugging the value of the radius into the formula, we get: 4π(8^2) = 256π mm^2.

Next, we need to find the surface area of the cylinder. The base diameter of the cylinder is equal to the diameter of the sphere, which is 16mm. Therefore, the radius of the cylinder is also 8mm. The surface area of the cylinder is given by the formula: 2πrh + 2πr^2. Since the height is unknown, we'll use a variable 'h'.

Since the surface area of the sphere is equal to the surface area of the cylinder, we can set up an equation: 256π = 2πrh + 2πr^2. Plugging in the values, we get: 256π = 2π(8)(h) + 2π(8^2).

Cancelling out the common factor of 2π, we have the equation: 128 = 8h + 64. Subtracting 64 from both sides of the equation, we get: 64 = 8h. Dividing both sides by 8, we find that the height of the cylinder is: h = 8mm.

what does proportional mean?

Answers

In mathematics, two variables are proportional if a change in one is always accompanied by a change in the other, and if the changes are always related by use of a constant multiplier. The constant is called the coefficient of proportionality or proportionality constant.

corresponding in size or amount to something else

HELP ME! *EMERGENCY*
A survey by the state health department found that the average person ate 208 pounds of vegetables last year and 125 5/8 pounds of fruit. What fraction of the total pounds of fruit and vegetables do the pounds of fruits represent?

Answers

hello
answer is 333 5\8
~hope i help~

Answer : The fraction of pounds of fruits over the total pounds of fruit and vegetables is, [tex]\frac{1005}{2669}[/tex]

Step-by-step explanation :

As we are given that:

Total amount of vegetables = 208 pounds

Total amount of fruits = [tex]125\frac{5}{8}\text{ pounds}=\frac{1005}{8}\text{ pounds}[/tex]

Thus, the total amount of fruits and vegetables will be:

[tex]208+125\frac{5}{8}\\\\=208+\frac{1005}{8}\\\\=\frac{1664+1005}{8}\\\\=\frac{2669}{8}[/tex]

Now we have to calculate the fraction of pounds of fruits over the total pounds of fruit and vegetables :

[tex]\frac{\text{Pounds of fruits }}{\text{ total pounds of fruits and vegetables}}\\\\=\frac{(\frac{1005}{8})}{(\frac{2669}{8})}\\\\=\frac{1005}{8}\times \frac{8}{2669}\\\\=\frac{1005}{2669}[/tex]

Thus, the fraction of pounds of fruits over the total pounds of fruit and vegetables is, [tex]\frac{1005}{2669}[/tex]

0.2(v-5) = -1 solve equations

Answers

Your answer should be v=0
Reorder the terms in parentheses
+(+0.2v-1)=-1
Remove unnecessary parentheses
+ 0.2v-1=-1
We move all terms containing v to left and all other terms to the right
+ 0.2v+=-1+1
We simplify left and right side of the equation 
+ 0.2v=0
We divided both sides of the equation by 0.2 to get v
v=0

The results of an independent-measures research study are reported as "t(22) = 2.12, p < .05, two tails." for this study, what t values formed the boundaries for the critical region?

Answers

As the level of significance here is 0.05 because we are comparing the p-value with 0.05. Therefore the critical region boundaries here would be given as:

For 5 degrees of freedom, we get: ( from the t-distribution tables )

P(t_5 < 2.571) = 0.975

Therefore due to symmetry, we get:

P(-2.571 < t_5 < 2.571) = 0.95

Therefore the critical region here would be given as: +2.571 and -2.571

Final answer:

The critical values for the t-distribution are used to define the boundaries for the critical region in a hypothesis test. In this case, the boundaries are t < -2.073 or t > 2.073.

Explanation:

The critical values for the t-distribution are used to define the boundaries for the critical region in a hypothesis test. In this case, the results of the study are reported as t(22) = 2.12, p < .05, two tails. To find the boundaries for the critical region, we need to look up the critical value for a two-tailed test with 22 degrees of freedom and a significance level of 0.05.

Using a t-distribution table or a calculator, we find that the critical value is approximately 2.073. Therefore, the boundaries for the critical region in this study are t < -2.073 or t > 2.073.

Any calculated t-value that falls outside of these boundaries would lead to rejecting the null hypothesis and concluding that the variables are significantly correlated.

Write an absolute value for all real numbers at least 3 units from -2

Answers

{xi,...}|3|≥xsomething like this

If f (x)=2x^2+1 and g (x)=3x-2 what is the value of f (g (-2))?

Answers

[tex]\bf \begin{cases} f(x)=2x^2+1\\ g(x)=3x-2\\ \end{cases}\qquad g(-2)=3(-2)-2\implies \boxed{g(-2)=-8} \\\\\\ f(~~g(-2)~~)\implies f\left( \boxed{-8} \right)\implies f(-8)=2(-8)^2+1 \\\\\\ f(-8)=2(64)+1\implies f(-8)=129[/tex]

I need some extra detailed steps please

Answers

check the picture below.

as far as the maximum and minimum, and the zeros, you can get them right off the grid.

On a game show, a contestant randomly chooses a chip from a bag that contains numbers and strikes. The theoretical probability of choosing a strike is 3/10. The bag contains 9 strikes. How many chips are in the bag?

Answers

This question rests on the proportion 3/10, and how that might scale up to a larger bag. It says the probability of choosing a strike is 3/10; we can take that to mean that, in a bag of 10 chips, there are 3 strikes. Now, we're dealing with an unknown number of chips, but we are given the number of strikes it contains: 9. What are we multiplying - or scaling - the 3 by to get 9? We'll have to use that same scaling factor to scale up our 10. As an equation, this translates to:

[tex] \frac{3}{10}= \frac{9}{x}[/tex]

Where x is the number of chips in the larger bag.

8. Based upon a long period of record keeping the following represents the probability distribution of the number of times the John Jay wifi network is slow during a week. We call the random variable x.

x 0 1 2 3 4 5 6
p(x) .08 .17 .21 k .21 k .13

a. What is the value of k?

b. Calculate the expected value of x.

c. Calculate the expected value of x^2
.

d. Calculate the variance of x.

e. Calculate the standard deviation of x

f. Calculate the variance of 3x.

g. Suppose that network slowness is independent from week to week. What is the probability that if we look at 5 separate weeks, the network has no more than 4 slow times in any of those weeks?

h. Calculate the variance of the random variable x^2

Answers

Given a table representing the probability distribution of the number of times the John Jay wifi network is slow during a week. We call the random variable x.

[tex]\begin{tabular} {|c|c|c|c|c|c|c|c|} x&0&1&2&3&4&5&6\\[1ex] p(x)&.08&.17& .21& k& .21& k& .13 \end{tabular}[/tex]
 


Part A:

The total value of p(x) = 1.

Thus,

.08 + .17 + .21 + k + .21 + k + .13 = 1

0.8 + 2k = 1

2k = 1 - 0.8 = 0.2

k = 0.2 / 2 = 0.1

Therefore, the value of k is 0.1



Part B:

The expected value of x is given by

[tex]E(x)=\Sigma xp(x) \\ \\ =0(0.08)+1(0.17)+2(0.21)+3(0.1)+4(0.21)+5(0.1)+6(0.13) \\ \\ =0+0.17+0.42+0.3+0.84+0.5+0.78=3.01[/tex]

Therefore, the expected value of x is 3.01



Part C:

The expected value of [tex]x^2[/tex] is given by

[tex]E(x^2)=\Sigma x^2p(x) \\ \\ =0^2(0.08)+1^2(0.17)+2^2(0.21)+3^2(0.1)+4^2(0.21)+5^2(0.1)+6^2(0.13) \\ \\ =0(0.08)+1(0.17)+4(0.21)+9(0.1)+16(0.21)+25(0.1)+36(0.13) \\ \\ =0+0.17+0.84+0.9+3.36+2.5+4.68=12.45[/tex]

Therefore, the expected value of [tex]\bold{x^2} [/tex] is 12.45



Part D:

The variance of x is given by

[tex]Var(x)=E(x^2)-(E(x))^2 \\ \\ =12.45 - (3.01)^2=12.45-9.06 \\ \\ =3.39[/tex]

Therefore, the variance of x is 3.39.



Part E

The standard deviation of x is given by

[tex] \sqrt{Var(x)} = \sqrt{3.39} =1.84[/tex]

Therefore, the standard deviation of x is 1.84.



Part F:

The variance of ax, where a is a constant is given by

[tex]Var(aX)=a^2Var(X)[/tex]

Thus, the variance of 3x is given by

[tex]Var(3X)=3^2Var(X)=9(3.39)=30.51[/tex]

Therefore, the variance of 3x is 30.51.



Part G:

The probability that the network has no more that 4 slow times in one week is given by

[tex]P(x\leq4)=P(0)+P(1)+P(2)+P(3)+P(4) \\ \\ =0.08+0.17+0.21+0.1+0.21=0.77[/tex]

Since, the network slowness is independent from week to week, the probability that if we look at 5 separate weeks, the network has no more than 4 slow times in any of those weeks is given by

[tex](0.77)^5=0.27[/tex]

Therefore, the probability that if we look at 5 separate weeks, the network has no more than 4 slow times in any of those weeks is 0.27



Part H:

The variance of x^2 is given by

[tex]Var(x^2)=E((x^2)^2)-(E(x^2))^2=E(x^4)-(E(x^2))^2[/tex]

[tex]E(x^4)=\Sigma x^4p(x) \\ \\ =0^4(0.08)+1^4(0.17)+2^4(0.21)+3^4(0.1)+4^4(0.21)+5^4(0.1) \\ +6^4(0.13) \\ \\ =0(0.08)+1(0.17)+16(0.21)+81(0.1)+256(0.21)+625(0.1)\\+1,296(0.13) \\ \\ =0+0.17+3.36+8.1+53.76+62.5+168.48=296.37[/tex]

Thus,

[tex]Var(x^2)=296.37-(12.45)^2=296.37-155.00=141.37[/tex]

Therefore, the variance of the random variable [tex]\bold{x^2}[/tex] is 141.37

Answer:k=2

Step-by-step explanation:

Kate has a serving account that contains $230. She decides to deposit $5 each month from her monthly earnings for baby-sitting after school. Write an expression to find how much money Mata will have in her savings account after x months. Let x represent the number of months. Then find out how much she will have in her account after 1 year.

Answers

y=5x+230

after 1 year she will have $290
Take 5 multiply it by 12 you should get 60. Take 60 and add it with 230. If you do it right you should get 290

20. Find the measure of each interior angle and each exterior angles of the following regular polygons. Show your work.

Answers

Where are the polygons?

Trigonometric Identities
Simplify each expression.
(1−cos⁡(−t))(1+cos⁡(t)) =
(1+sin(t))(1+sin(-t))=
csc⁡(t)tan⁡(t)+sec⁡(−t) =
Thank you for your help

Answers

[tex]\bf \textit{symmetry identities}\\\\ sin(-\theta )\implies -sin(\theta )\qquad \qquad cos(-\theta )\implies cos(\theta ) \\\\\\also~recall\\\\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta) \\\\\\ sin^2(\theta)=1-cos^2(\theta) \\\\ -------------------------------\\\\\ [1-cos(-t)][1+cos(t)]\implies [1-cos(t)][1+cos(t)][/tex]

[tex]\bf 1^2-cos^2(t)\implies 1-cos^2(t)\implies sin^2(t)\\\\ -------------------------------\\\\\ %Simplify each expression. (1−cos⁡(−t))(1+cos⁡(t)) = (1+sin(t))(1+sin(-t))= csc⁡(t)tan⁡(t)+sec⁡(−t) = [1+sin(t)][1+sin(-t)]\implies [1+sin(t)][1-sin(t)] \\\\\\ 1^2-sin^2(t)\implies 1-sin^2(t)\implies cos^2(t)\\\\ -------------------------------\\\\[/tex]

[tex]\bf csc(t)tan(t)+sec(-t)\implies \cfrac{1}{\underline{sin(t)}}\cdot \cfrac{\underline{sin(t)}}{cos(t)}+\cfrac{1}{cos(-t)} \\\\\\ \cfrac{1}{cos(t)}+\cfrac{1}{cos(-t)}\implies \cfrac{1}{cos(t)}+\cfrac{1}{cos(t)}\implies \cfrac{2}{cos(t)} \\\\\\ 2\cdot \cfrac{1}{cos(t)}\implies 2sec(t)[/tex]

There are four families attending a concert together. each family consists of 1 male and 2 females. in how many ways can they be seated in a row of twelve seats i

Answers

Final answer:

The four families consisting of 12 distinct individuals can be seated in 12! (479,001,600) ways. There are no seating restrictions, so each person can occupy any of the twelve seats.

Explanation:

The subject of this question is combinatorics, a branch of mathematics. In this problem, you have four families, each consisting of 1 male and 2 females, and you want to know in how many ways they can be seated in a row of twelve seats.

Given there is no restriction about the seating pattern, each member can occupy any seat. So, consider each family member as a distinct person; you then have 12 people to be seated in 12 different ways. This can be done in 12 factorial (12!) ways. Factorial implies the product of all positive integers up to that number. A simple way to calculate 12 factorial is: 12*11*10*9*8*7*6*5*4*3*2*1, which equals 479,001,600.

So, the four families can be seated in a row of twelve seats in 479,001,600 ways. This principle of arrangements is a key part of combinatorics and discrete mathematics.

Learn more about Combinatorics here:

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Final answer:

Considering each family as a single unit, the total number of ways they can be seated in a row of twelve seats is given by the formula: 12! divided by (2!) to the power of 4.

Explanation:

This is actually a problem that is solved using the principles of permutations and combinations in mathematics. Given we have 4 families each with 1 male and 2 females, we have a total of 12 people. Now, if we are to arrange these 12 people in a row of twelve seats, we have 12! (factorial) ways to do it. However, each family group is to be considered as a single unit and within each unit, arrangements don't count, so we must divide by the number of ways to arrange the 2 females within each family of 4, which is 2!. Hence, the total number of ways to seat the group is given by (12! / (2!)^4).

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Destiny works on commission as an office supply saleswoman. She sold a computer that cost $700 and received a $126 commission.

What percent of her sale is Destiny's commission?

Answers

Hello,

If you want to find the percentage of anything, simply divide how much of the total number by the total number. 126 ÷ 700, which is 0.18.

To turn the decimal into a percentage, simply move the decimal place two places to the right, and it is now 18%.

In conclusion, she earned 18% of her sale.
Hope this helps! =)

the total cost of 4 pens and 7 mechanical pencils is $13.25 the cost of each pencil is $0.75 write an equation that could be used to find the cost of a pen

Answers

4x+7y=$13.25
4x+ 7($0.75)

A negative number is raised to an odd exponent. The result is _____. zero one positive negative

Answers

The answer is a negative number

A negative number is raised to an odd exponent. The result is always negative.

What is mean by Odd exponent?

An odd power of a number is a number of the form for the integer and a positive odd integer.

The first few odd powers are 1, 3, 5, 7, .........

Given that;

The expression is;

A negative number is raised to an odd exponent.

Now, To prove this statement that ''A negative number is raised to an odd exponent. The result is always negative.''

Let an example for an odd exponent as;

f (x) = (- 4)³

Here the power is 3 which is odd.

This gives;

f (x) = (- 4)³

f (x) = - 64

Which is negative function.

Hence, A negative number is raised to an odd exponent is always negative.

Therefore,

A negative number is raised to an odd exponent. The result is always negative.

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 Question Help A tourist asked a zookeeper how many birds and lions are in the zoo. The zookeeper replied there are 32 heads and 102 feet. Find the number of each.

Answers

let number of lions be l and number of birds be b.

l + b = 32
4l + 2b = 102....(1)
multiply first equation by 2
2l + 2b = 64.....(2)
Subtract   (1) - (2)i is
2l = 38
l = 19

b = 32-19 = 13

There are 19 lions and 13 birds.

Final answer:

By setting up and solving a system of equations, we find that there are 13 birds and 19 lions in the zoo.

Explanation:

To solve the problem of determining the number of birds and lions in the zoo given 32 heads and 102 feet, we can set up a system of equations. Birds have 2 feet, and lions have 4 feet. Let B represent the number of birds and L represent the number of lions.

Equations:

B + L = 32 (total heads)

2B + 4L = 102 (total feet)

Solving this system, we'll first multiply the first equation by 2 to facilitate elimination:

2B + 2L = 64

2B + 4L = 102

Subtracting the first modified equation from the second equation gives us 2L = 38, so L=19. Substituting L=19 into the first equation, we find B = 32 - 19 = 13.

Therefore, there are 13 birds and 19 lions in the zoo.


Round 227,985 to the nearest thousand.

:227,000
:228,000
:227,900
:230,000

Answers

228,000 would be the answer
the 7 is in the thousands place, the hundreds place is a 9 so you would round up so to the nearest thousand would be 228,000

If EF = 4x − 16, FG = 3x − 6, and EG = 27, find the values of x, EF, and FG.

Answers

The summation of the lengths of Ef and FG would give us the length of EG.
This means that:
EF + FG = EG
4x - 16 + 3x - 6 = 27
7x = 27 + 16 + 6
7x = 49
x = 49/7 = 7

Therefore:
EF = 4(7) - 16 = 12 unit length
FG = 3(7) - 6 = 15 unit length

Using symbols. There are 3 shelves. Each shelf has 21 books. How many books are there in all?

Answers

To find the total amount of books:
21 * 3 = 63      
There are 63 books in all.

The stem-and-leaf plot shows the ages of customers who were interviewed in a survey by a store.

How many customers were older than 45?

HELP ASAP please

Answers

11 because it asks for people older than 45 so it’s not 12. You just need to count how many number are after 45.

Answer:

Customers older than 45 years are 11 in number.

Step-by-step explanation:The age of store customers is represented by the stem ad leaf plot.The stem represents the tens digit while leaf denotes the unit digit.The question is asking us to find the number of customers who are older than 45 so 45 is not considered.

The age of customers more than 45 are:

48,50,50,51,55,56,62,64,65,65,73.There are 11 customers in all .

Liam has 9/10 gallon of paint for painting the birdhouse he sells at the craft fair. Each birdhouse requires 1/20 gallon of paint.how many birdhouse can Liam paint? Show your work.

Answers

First get common denominators of 20.

9/10 gallons of paint ·2/2= 18/20

(Gallons of paint available)/(Paint required per house)= # of total houses.
(18/20)/(1/20)= 
Dividing by a fraction can be multiplied by reciprocal.

(18/20)x(20/1)=18 birdhouses
In this question, each birdhouse requires 1/20 gallon of paint. From this description you can get this equation:

1 birdhouse= 1/20 gallon of paint

Then 9/10 gallon of paint would equal to: 
9/10 gallon of paint / (1/20 gallon of paint/1 birdhouse)=
9/10 gallon of paint *20 birdhouse / 1 gallon of paint=
180/10 * birdhouse= 18 birdhouse

Select "Rational" or "Irrational" to classify each number. 0.25 Sq. Rt. 0.25 Sq. Rt. 0.33

Answers

0.25: Rational
√0.25: Rational (=0.5)
√0.33: Irrational
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