Find the average rate of exchange for the function. x=-6 and x=0
[tex]f(x)= \frac{1}{x-1} [/tex]

Answers

Answer 1
[tex]\dfrac{\frac1{0-1}-\frac1{-6-1}}{0-(-6)}=\dfrac{-1+\dfrac17}6=-\dfrac17[/tex]

Related Questions

Solve the equation.
17=5k-2

Answers

k=14 i think thats right im not sure
Answer:
k would equal 3.8

how much water does it take to completely fill a pool that is 50 m long 25 meters wide and 2 meters deep

Answers

Greetings!

The question is essentially asking you to figure out the volume of the pool.
The formula for the volume a rectangular prism is: [tex]l*w*h[/tex]

Input the information we know into the formula:
[tex]=50*25*2[/tex]
Simplify.
[tex]=1250*2[/tex]
[tex]=1250*2[/tex]
The Answer Is:
[tex]=2500[/tex]

The volume of the pool is 2500 meters³.

Hope this helps.
-Benjamin
Hello There!

You need to figure out the volume.
Use the formula:
v = l x w x h
Substitute the numbers in:
v = 50 x 25 x 2
Solve:
v = 2500.

The answer is 2500m³

Hope This Helps You!
Good Luck :) 

- Hannah ❤ 

Four sisters buy a total of 3 1/2 feet of ribbon. The sisters want to share the ribbon equally. How many feet of ribbon will each sister receive

Answers

divide 3 1/2 by 4

3 1/2 = 7/2

7/2 / 4 = 7/8 foot each

Answer:

[tex]\frac{7}{8}[/tex] feet.

Step-by-step explanation:

Four sister bought a total of ribbon = [tex]3\frac{1}{2}[/tex] feet

                                                           = [tex]\frac{7}{2}[/tex] feet

The sisters want to share the ribbon equally.

So we will divide the total length of the ribbon by 4.

= [tex]\frac{7}{2}[/tex] ÷ 4

= [tex]\frac{7}{2}[/tex] × [tex]\frac{1}{4}[/tex]

= [tex]\frac{7}{8}[/tex] feet.

Each sister will receive [tex]\frac{7}{8}[/tex] feet of ribbon.

Use
A=P(1+rn)nt
A=P(1+rn)nt where:
A = the amortized amount (total loan/investment amount over the life of the loan/investment)
P = the initial amount of the loan/investment
r = the annual rate of interest
n = the number of times interest is compounded each year
t = the time in years

Find how long it takes a $2,200.00 investment to earn $210.00 in interest if it is invested at 10% compounded monthly.

It will take ___ years. (Round answer to 3 decimal places.)

Answers

same here, the interest earned is 210, the principal is 2200, so the accumulated amount is 2410.

[tex]\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\to &\$2410\\ P=\textit{original amount deposited}\to &\$2200\\ r=rate\to 10\%\to \frac{10}{100}\to &0.10\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\to &12\\ t=years \end{cases}[/tex]

[tex]\bf 2410=2200\left(1+\frac{0.1}{12}\right)^{12t}\implies \cfrac{2410}{2200}=\left(1+\frac{1}{120} \right)^{12t} \\\\\\ \cfrac{241}{220}=\left(\cfrac{121}{120} \right)^{12t}\implies log\left( \frac{241}{220} \right)=log\left[ \left(\frac{121}{120} \right)^{12t} \right]\\\\\\ log\left( \frac{241}{220} \right)=12t\cdot log\left(\frac{121}{120} \right)\implies \cfrac{log\left( \frac{241}{220} \right)}{12 log\left(\frac{121}{120} \right)}=t\implies 0.915 \approx t[/tex]

so, about 10 months and 27 days.
Final answer:

It will take approximately 1.459 years for a $2,200.00 investment to earn $210.00 in interest if it is invested at 10% compounded monthly.

Explanation:

To find how long it takes a $2,200.00 investment to earn $210.00 in interest if it is invested at 10% compounded monthly, we can use the formula A = P(1+rn)^(nt). Plug in the values: A = 2200 + 210 = 2410, P = 2200, r = 0.10 (10%), n = 12 (compounded monthly), and t = ?

2410 = 2200(1 + 0.10/12)^(12t). Divide both sides by 2200 to isolate the expression:

1.095 = (1 + 0.10/12)^(12t). Take the natural logarithm of both sides to remove the exponent:

ln(1.095) = 12t * ln(1 + 0.10/12). Solve for t:

t = ln(1.095) / (12 * ln(1 + 0.10/12)). Use a calculator to find the value of t, which is approximately 1.459 years when rounded to 3 decimal places.

If x=2 calculate the value of x squared +2x

Answers

Firstly, I substituted the x for 2 in the equation [tex]2^2+2(2)[/tex]. 
Secondly, simplify 2(2) to 4 so [tex]2^2+4[/tex]
Thirdly, simplify 2^2​​ to 4 so 4+4.Fourth, 4+4 is 8.

Help me asap!


please help

Answers

cross multiply:

21*9 = 189

7*q = 7q

so you have 189/7q

 divide 189 by 7 to get q

189 / 7 =27

q = 27

there are 2 more than 3 times as many parrots as finches at the pet store, if there's a total of 18 parrots and finches, how many are parrots and how many are finches

Answers

Final answer:

To solve this problem, you can set up a system of equations. There are 4 finches and 14 parrots.

Explanation:

To solve this problem, we can set up a system of equations based on the given information. Let's assume that the number of finches is 'x'. According to the problem, there are 2 more than 3 times as many parrots as finches. This can be written as:

Parrots = 3x + 2

Since the total number of parrots and finches is 18, we can set up another equation:

Parrots + Finches = 18

Substituting the first equation into the second equation, we get:

(3x + 2) + x = 18

Combining like terms, we have:

4x + 2 = 18

Subtracting 2 from both sides, we get:

4x = 16

Dividing both sides by 4, we find that:

x = 4

So, there are 4 finches and 3(4) + 2 = 14 parrots.

Find the largest number δ such that if |x − 1| < δ, then |5x − 5| < ε, where ε = 0.1. δ ≤ repeat and determine δ with ε = 0.01.

Answers

[tex]|5x-5|=5|x-1|<\varepsilon\implies|x-1|<\dfrac\varepsilon5=\delta[/tex]

So for [tex]\varepsilon=0.1[/tex], we get [tex]\delta=50[/tex]; for [tex]\varepsilon=0.01[/tex], we get [tex]\delta=500[/tex].

Hi, here we want to "finish" a delta-epsilon proof.

We will find that the maximum delta is: δ = 0.02

We just want to find the value of δ such that:

[tex]|x - 1| < \delta[/tex]

Implies that:

[tex]|5x - 5| < \epsilon[/tex]

Well, let's start with the second expression:

[tex]|5x - 5| < \epsilon[/tex]

We can take the 5 out of the absolute value:

[tex]5*|x - 1| < \epsilon[/tex]

Now we can divide both sides by 5:

[tex]|x - 1| < \epsilon/5[/tex]

Now, if you look at the above expression, in the left side we have the same thing as in the delta inequality.

So for now we have:

[tex]|x - 1| < \epsilon/5[/tex]

[tex]|x - 1| < \delta[/tex]

From this is easy to conclude that the maximum value that delta can take is:

δ = ε/5

And we know that ε = 0.1, then we have:

δ = 0.1/5 = 0.02

δ = 0.02

The maximum value that delta can take is 0.02

Then we need to repeat it for ε = 0.01, so we get:

δ = 0.01/5 = 0.002

δ = 0.002

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The elimination of paper-based documents between organizatins is made possible by

Answers

email
document sharing via computer, e. g., with Adobe pdf documents

PLEASE HELP! DUE IN 5 DAYS

Answers

m<3 = 47
m<5 = m<3 = 47 (Alternate interior angles)

answer 
m<5 = 47

since angle 3 = 47, then angle 1 also = 47

this would mean that both angles 5 & 7 are also 47

so angle 5 = 47 degrees

Mr. James wants to build a walkway around his school garden. The width of his garden is one-third the length. The perimeter of the school garden is 32 feet. What is the length and width of his garden?

Answers

L=3W

2(3W+W)=32 feet

8W=32 feet

W=4 feet

L=3W

L=3* 4 feet

L=12 feet

The width is 4 feet, the length is 12 feet.

A scientist studying bacteria begins with 20 cells. The bacteria population doubles every hour. Complete the table below to determine after how many hours there will be more than 500 bacteria cells. Time (hours) Number of bacteria cells 0 20 1 40 2 80 3 4 5 6 Write an exponential function to model this situation. Predict the bacteria population after 11 hours.

Answers

The bacteria population will be 40,960 in 11 hours

Answer:

1)

t=5 hours.

2)

40960 cells.

Step-by-step explanation:

A scientist studying bacteria begins with 20 cells.

The bacteria population doubles every hour.

Let P(t) determines the population of the bacteria in 't' hours.

Hence, by the given information our function P(t) is modeled as:

[tex]P(t)=20\times 2^t[/tex]

Now, we have to find the value of 't' such that:

P(t)>500

i.e.

[tex]20\times 2^t>500\\\\\\2^t>\dfrac{500}{20}\\\\2^t>25[/tex]

on taking logarithmic function on both side we get:

[tex]t\log 2>\log 25\\\\t>\dfrac{\log 25}{\log 2}\\\\t>4.64[/tex]

i.e. after 5 hours the population of the bacteria will exceed 500.

Now we have to find the value of function P(t) when t=11.

i.e.

[tex]P(11)=20\times 2^{11}\\\\P(11)=20\times 2048\\\\P(11)=40960[/tex]

Hence , the population of bacteria after 11 hours is:

40960 cells.

On Saturday, a local hamburger shop sold a combined total of 392 hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold. How many hamburgers were sold on Saturday?

Answers

hamburgers = x
cheeseburgers = 3x

x + 3x = 492
4x = 492
x = 123

Hope this helps!

Using the equation, 98 hamburgers were sold on Saturday.

What is an equation?

An equation is an equality relationship between two expressions written on both sides of the equal to sign.

Let the number of hamburgers sold be h and number of cheeseburgers sold be c.

Then we can formulate an equation

c = 3h

c + h = 392

3h + h = 392

4h = 392

h = 98

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on one of the day you went to the gym,the ratio of men to women was 3:2.if 120 men used the gym,how many women were there?

Answers

120-3/5
x-2/5
cross multiply the values
therefore:120×3/5=48
48=2/5x
48÷2/5=2/5÷2/5x
80=x

Answer:

80 women

Step-by-step explanation:

A ratio of men to women of 3:2 means that for 3 men that use the gym 2 women use the gym, so using a rule of three we can determinate how many women were on the gym that day if 120 men were there, like this:

  3 men   ------ 2 women

120 men  ------       X

[tex]X = \frac{(120men)(2women)}{3men}=80 women[/tex]

Then, there were 80 women for the 120 men that were in the gym.

An investment firm recommends that a client invest in bonds rated AAA, A, and B. The average yield on AAA bonds is 4%, on A bonds 6%, and on B bonds 11%. The client wants to invest twice as much in AAA bonds as in B bonds. How much should be invested in each type of bond under the following conditions?
A.  The total investment is $26,000, and the investor wants an annual return of $1,620 on the three investments.
B.  The values in part A are changed to $38,000 and $2,360, respectively
A.  The client should invest $(?) in AAA bonds, $(?)in A bonds, and $(?)in B bonds.

Answers

Part A.

1) Variables:

X: amount invested in AAA bonds

Y: amount invested in A bonds

Z: amount invested in B bonds.

2) Return:

4%* X + 6% * Y + 11% * Z = 1620

3) Investment:

 X + Y + Z = 26,000

4) Ratio between AAA and B bonds.

X = 2*Z

5) Solution of the system of equations:

Replace X with 2Z in the two first equations:

2Z * 4% + Y * 6% + Z * 11% = 1620

=> 0.08Z + 0.06Y + 0.11Z = 1620

=> 0.19Z + 0.06Y = 1620

2Z + Y + Z = 26,000

=> 3Z + Y = 26,000 => Y = 26,000 - 3Z

Replace Y with 26,000 - 3Z

0.19Z + 0.06(26,000 - 3Z) = 1620

0.19Z + 1560 - 0.18Z = 1620

0.01Z = 1620 - 1560

0.01Z = 60

Z = 60 / 0.01 = 6000

=> X = 2*6000 = 12,000

=> Y = 26,000 - 12,000 - 6,000 = 8,000

Answer: 12,000 in bonds AAA, 8,000 in bonds A, and 6000 in bonds B.

Part B.

2) Return:

0.04X + 0.06 Y + 0.11Z = 2360

3) Investment:

 X + Y + Z = 38,000

4) Ratio between AAA and B bonds.

X = 2Z

5) Solution of the system of equations:

Replace X with 2Z in the two first equations:

=> 0.08Z + 0.06Y + 0.11Z = 2360

=> 0.19Z + 0.06Y = 2360

2Z + Y + Z = 38,000

=> 3Z + Y = 38,000 => Y = 38,000 - 3Z

Replace Y with 38,000 - 3Z

0.19Z + 0.06(38,000 - 3Z) = 2360

0.19Z + 2280 - 0.18Z = 2360

0.01Z = 2360 - 2280

0.01Z = 80

Z = 80 / 0.01 = 8000

=> X = 2*8000 = 16,000

=> Y = 38,000 - 16,000 - 8000 = 14,000

Answer: 16,000 in AAA bonds, 14,000 in A bonds, and 8,000 in B  bonds.

Shan's dumpling house can produce 100 dumplings using one worker and 175 dumplings using two workers. what is the marginal product of the second worker?
a.25 dumplings
b.75 dumplings
c.175 dumplings
d.275 dumplings

Answers

Marginal product is defined as the incremental change in output that occurs due to a change in the input signals.

It is calculated on two steps:
1- Find the change that occurred to the outputs
2- Divide this change by the additional inputs

For the problem we have here:
Step 1:
old output = 100 dumplings
new output = 175 dumplings
change that occurred = 175 - 100 = 75
Step 2:
This change occurred as a result of adding 1 worker
Therefore:
marginal product = 75/1 = 75

Answer: (b)

The marginal product of the second worker is b. 75 dumplings.

To find the marginal product of the second worker, we need to determine how many additional dumplings the second worker is able to produce compared to the first worker. The marginal product (MP) of a worker is calculated as follows

[tex]\[ MP = \text{Total production with two workers} - \text{Total production with one worker} \][/tex]

Given:

[tex]\[\]\[ \text{Total production with one worker} = 100 \text{ dumplings} \]\[ \text{Total production with two workers} = 175 \text{ dumplings} \][/tex]

Substitute the given values into the formula:

[tex]\[\]\[ MP = 175 \text{ dumplings} - 100 \text{ dumplings} \]\[ MP = 75 \text{ dumplings} \][/tex]

m−14.6=9.74 4.86 23.34 24.34 25.34 wich one 

Answers

The answer would be 24.34
m - 14.6 = 9.74
m - 14.6 (+14.6) = 9.74 (+ 14.6)
m = 24.34

hope this helps

Nails cost $.13 per pound and screws cost $.21 per pound. Michelle bought 1.5 pounds of nails and 3.4 pounds of screws. How much did she pay for the nails and screws?

Answers

1.5(0.13) + 3.4(0.21) =
0.195 + 0.714 =
0.909 rounds to 0.91 <== he paid 91 cents
Attached the solution and work.

if the smaller of two consecutive intergers is subtracted from two times the larger then the result is 17 . find the intergers

Answers

Two consecutive integers (x) and (x+1)
2 (x+1) - (x) = 17
2x + 2 - x = 17
x + 2= 17
x + 2 - 2 = 17 - 2
x=15
and x + 1 = 15 + 1 = 16

15, 16 are your numbers.



A painting crew bought 30 gal of paint for a job. The crew members used 3 gal of paint per hour until they used all the paint.

Which sketch represents this situation?



A) A graph in the first quadrant containing a line segment. The x axis is labeled Hours and the y axis is labeled Gallons remaining. The endpoints of the line segment are begin ordered pair 0 comma 3 end ordered pair and begin ordered pair 30 comma 0 end ordered pair.


B) A graph in the first quadrant containing a line segment. The x axis is labeled Hours and the y axis is labeled Gallons remaining. The endpoints of the line segment are begin ordered pair 0 comma 30 end ordered pair and begin ordered pair 10 comma 0 end ordered pair.


C) A graph in the first quadrant containing a line segment. The x axis is labeled Hours and the y axis is labeled Gallons remaining. The endpoints of the line segment are begin ordered pair 0 comma 10 end ordered pair and begin ordered pair 30 comma 0 end ordered pair.


D)A graph in the first quadrant containing a line segment. The x axis is labeled Hours and the y axis is labeled Gallons remaining. The endpoints of the line segment are begin ordered pair 0 comma 30 end ordered pair and begin ordered pair 3 comma 0 end ordered pair.

Answers

The answer to this question is A.)

Answer:

Step-by-step explanation:

They have 30 gallons of paint and for each hour that passes, they use 3 gallons of paint. Therefore, we can express that as a function:

y = -3x + 30

where y = gallons left

and x = hours passed

Therefore, the end points are (0, 30) and (10, 0)

Using our function when 0 hours has passed:

y = -3(0) + 30

y = 30

Therefore one endpoint is when x = 0 y = 30 or (0,30)

Using our function when 10 hours has passed:

y = -3(10) + 30

y = -30 + 30

y = 0

Therefore one endpoint is when x = 10 y = 0 or (10, 0)

The graph can be seen in the picture below.

The remainder when aa is divided by 77 is 22 and the remainder when bb is divided by 77 is 55. (so a mod 7=2a mod 7=2, b mod 7=5b mod 7=5) find: (a+a) mod 7(a+a) mod 7 equation editor equation editor (a+b) mod 7(a+b) mod 7 equation editor equation editor (3a) mod 7(3a) mod 7 equation editorequation editor (2b) mod 7(2b) mod 7

Answers

[tex]a\equiv2\pmod7[/tex]
[tex]b\equiv5\pmod7[/tex]

[tex]a+a\equiv2+2\equiv4\pmod7[/tex]

[tex]a+b\equiv2+5\equiv7\equiv0\pmod7[/tex]

[tex]3a\equiv6\pmod7[/tex]

[tex]2b\equiv10\equiv3\pmod7[/tex]
Final answer:

The modulo of the expressions are computed as follows: (a+a) mod 7 = 4, (a+b) mod 7 = 0, (3a) mod 7 = 6, and (2b) mod 7 = 3.

Explanation:

I'm sorry, but I'm afraid there might have been some confusion in your input. If you wanted the remainders of different expressions when divided by 7, here are the steps:

Given that a mod 7 = 2 and b mod 7 = 5, you can use modular arithmetic to compute the modulo of expressions including a and b:

(a+a) mod 7 = 2a mod 7. Since a mod 7 = 2, then 2a mod 7 = 4 mod 7.(a+b) mod 7 = 2+5 mod 7 = 7 mod 7 = 0.(3a) mod 7 = 6 mod 7.(2b) mod 7 = 10 mod 7 = 3.

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Angle XYZ is rotated 270 degrees counterclockwise about the origin to form angle X’Y’Z’. Which statement shows the measure of angle X’Y’Z’?
m∠X’Y’Z’ = m∠XYZ
m∠X’Y’Z’ = 180 degrees
m∠X’Y’Z’ = 270 degrees
m∠X’Y’Z’ = 2 × m∠XYZ

Answers

It is fine that you did not include the measure of angle XYZ in your posting.

This question is testing your knowledge of the four types of transformations.
1) Translations - an item is "slid" to a new location.
2) Reflections - an item is "flipped" (usually over the x-axis or y-axis)
3) Rotations - an item is rotated, usually around the origin (the point (0,0) is the center of most rotations, especially in high school math).
4) Dilations - an item is enlarged or reduced by a certain ratio.

It the first three, the image after the transformation is congruent to the pre-image.  It has the same size and shape.  It is simply flipped, rotated, slid...

But... in the fourth, dilation, the image now has a different size.  It is still, however the same shape.

In geometry terms, after the first three transformations, the image is still "congruent" to the pre-image.  After dilation, the image is "similar" but not "congruent."

So... all that to say that when you rotate an angle around the origin, the measure of the angle doesn't change.

So the first choice is correct.  The measure of the image of the angle is the same as the measure of the angle.
m∠X’Y’Z’ = m∠XYZ

Answer:m∠X’Y’Z’ = m∠XYZ

Step-by-step explanation:

What are the next three terms of the geometric sequence 32, -16, 8, …?
a.
2, 1, 1/2
c.
-8, 16, -32
b.
4, 2, 1
d.
-4, 2, -1

Answers

to find the common ratio, divide the 2nd term by the first term
-16 / 32 = -0.5....this means u multiply each number by -0.5 to find the next number

8 * -0.5 = -4 <==
-4 * - 0.5 = 2 <==
2 * -0.5 = -1 <==

answer D

Which planets diameter is approximately 1/200 of the sun's diameter?explain

Answers

Mercury is much smaller still, only 1/200 the diameter of the sun as seen during the transit, only 10 arc-seconds across. This is like viewing that same quarter from 3-1/2 miles away!

Answer:

Mars

Step-by-step explanation:

Sun is the brightest object in the sky of the Earth. It is a giant spherical star, composed of hot plasma that is located at the center of the Solar System. The diameter of the Sun is about 1.391 million km.

Mars, also known as the Red Planet, is one of the four terrestrial planets. It is the fourth planet of the Solar System. It is the second-smallest planet having diameter of about 6,779 km.

Now, diameter of Mars ÷ diameter of the Sun ≈ 6,779 km ÷ 1391000 km ≈ 1 ÷ 200

⇒ diameter of Mars ≈ (1 ÷ 200) × diameter of the Sun

Therefore, the diameter of Mars is approximately 1/200 of the diameter of the Sun.

what percent is equivalent to 8/40

Answers

divide:

8/40 = 0.2

0.2 = 20%

Rose and Dennis each open a savings account at the same time. Rose invests $2,600 in an account yielding 4.1% simple interest, and Dennis invests $2200 in an account yielding 5.7% simple interest. After nine years, who has the greater total amount of money, and how much greater is it?

Answers

The formula is
A=p (1+rt)
A future value
P present value
R interest rate
T time in years

Rose investment
A=2,600×(1+0.041×9)
A=3,559.4

Dennis investment
A=2,200×(1+0.057×9)
A=3,328.6

So Rose investment is greater than Dennis investment by
3,559.4−3,328.6=230.8

Hope it helps!

Debra is on the swim team. Each day she swims 850m. How many kilometers does she swim each day?

Answers

the answer is 0.85 kilometers hope i helped

Debra swims 0.85 km each day.

27 students in all 4:5 packed lunch. how many students packed lunch

Answers

[tex]\bf \stackrel{total}{27}\qquad 4:5\qquad \cfrac{4}{5}\implies \cfrac{4\cdot \frac{27}{4+5}}{5\cdot \frac{27}{4+5}}\implies \cfrac{4\cdot 3}{5\cdot 3}\implies \cfrac{\stackrel{packed~lunch}{12}}{\stackrel{did~not~pack~lunch}{15}}[/tex]

marta took 48 pictures of flowers and 64 pictures of beautiful scenery. She wants to display the pictures so there is the same number of each kind of picture in each display. what is the greatest number of displays she can make?

Answers

She can make 48 displays with one picture of each

Create two whole number division problems that have a quotient of 9 and a remainder of 5. Justify which is greater using decimal division

Answers

59 ÷ 6 = 9 R 5
86 ÷ 9 = 9 R 5.

Because division can also be expressed as a decimal:

59/6 = 9.833
86/8 = 9.556

So, 59 ÷ 6 is greater.
Other Questions
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