Find the area. ABCD∼EFGHABCD∼EFGH The area of rectangle ABCD is 72 inches2 and a diagonal is 12 inches. The diagonal of rectangle EFGH is 22 inches. Find the area of rectangle EFGH. Round to the nearest inch2 if necessary.

Final answer:

Using the half-life formula, it would take 24 hours for the amount of carprofen to reduce from an initial dose of 80 milligrams to 10 milligrams.

Explanation:

To calculate the time it will take for the amount of carprofen to decrease from 80 milligrams to 10 milligrams in a dog, given the half-life of 8 hours, the exponential decay formula can be used. The half-life formula is:

[tex]C = C0 \times (1/2)^{(t/T)[/tex]

Let's set up the equation using the given values:

[tex]10 mg = 80 mg \times (1/2)^{(t/8 hours)[/tex]

Now, we solve for t:

[tex]10/80 = (1/2)^{(t/8)[/tex]

[tex]1/8 = (1/2)^{(t/8)[/tex]

To find the exponent t/8 that makes this equation true, we can use logarithms:

log2(1/8) = t/8

-3 = t/8

t = -3 * 8

t = -24 hours

The negative result is due to the fact that we are finding a factor by which the concentration is reduced. To get the actual time elapsed, we take the absolute value:

t = 24 hours

Therefore, it would take 24 hours for the amount of carprofen to reduce to 10 milligrams.

Answer:

the answer is A

Step-by-step explanation:

ttm

The probability that z lies between 0 and 3.01 P(0<z<3.01) = 0.4987.

The Z-score quantifies the discrepancy between a given value and the standard deviation. The Z-score, also known as the standard score, indicates how many standard deviations a specific data point deviates from the mean. In essence, standard deviation represents the degree of variability present in a given data collection.

Given:

Probability between z = 0 and z = 3.01 is given by

As, P(0<z<3.01)

= P(z<3.01) - P(z<0)

So, the z score values are

P(z<0) = 0.5

and, P(z<3.01) = 0.9987

Hence, the probability that z lies between 0 and 3.01 P(0<z<3.01) = 0.4987.

Learn more about z- score here:

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Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

[tex](4h^7k^2)^4[/tex]

We need to simplify this :

Here we go:

We will apply :

[tex](a^m)^n=a^{mn}[/tex]

[tex](4h^7k^2)^4\\\\=4^4\times (h^7)^4\times (k^2)^4\\\\=256h^{28}k^8[/tex]

Hence, option 'D' is correct.

Answer:

acceleration i think

Step-by-step explanation:

Answer:

Step-by-step explanation:

Givens

Now, remember that all coordinates with the form (a,0), represents points on the x-axis, because the y-coordinate is zero.

In this case, we have negative horizontal coordinates and a null vertical coordinate, like (-a,0).

This points is on the x-axis, because y-value is null. Actually, it's on the negative part of x-axis, because its horizontal coordinate is negative.

Therefore, the right answer is x-axis.

a. The perimeter of the triangle is 18 cm. b. The area of the triangle is 24 cm². c. Tiling the triangle at $7 per square centimeter would cost $168.

a. Perimeter:

Perimeter} = 5 + 5 + 8 = 18 cm

b. Area:

  Use Heron's formula since the sides are known:

[tex]\[ s = \frac{5 + 5 + 8}{2} = 9 \] \[ \text{Area} = \sqrt{s(s-5)(s-5)(s-8)} \] \[ \text{Area} = \sqrt{9 \times 4 \times 4 \times 1} = \sqrt{576} = 24 \, \text{cm}^2 \][/tex]

c. Cost to Tile:

  If the cost is $7 per square centimeter:

[tex]\[ \text{Cost} = \text{Area} \times \text{Cost per square centimeter} \] \[ \text{Cost} = 24 \times 7 = 168 \][/tex]

Therefore,

a. Perimeter = 18 cm

b. Area = 24 cm²

c. Cost to Tile = $168

For more questions on perimeter :

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The domain of y = sec(x) is all real numbers except for values where the cosine function is zero.

The domain of y = sec(x) is all real numbers except for values where the cosine function is equal to zero. Since the secant function is the reciprocal of cosine, it is undefined when cosine is zero.

So, the domain of y = sec(x) is all real numbers except for values of x where cos(x) = 0.

For example, if we consider the unit circle, the cosine function is equal to zero at π/2 and 3π/2. Therefore, the domain of y = sec(x) would exclude these values.

The domain of [tex]\( y = \sec(x) \)[/tex] is all real numbers except [tex]\( x = \frac{\pi}{2} + \pi \cdot n \)[/tex], [tex]\( n \)[/tex] integer.

Let's find the domain of [tex]\( y = \sec(x) \)[/tex].

The secant function, [tex]\( \sec(x) \)[/tex], is defined as the reciprocal of the cosine function, [tex]\( \cos(x) \)[/tex]. So, [tex]\( \sec(x) = \frac{1}{\cos(x)} \).[/tex]

The cosine function is defined for all real numbers, except where the denominator becomes zero, because division by zero is undefined.

So, to find the domain of [tex]\( \sec(x) \)[/tex], we need to find where [tex]\( \cos(x) \)[/tex] is not zero.

The cosine function has a range between -1 and 1. It equals zero at [tex]\( x = \frac{\pi}{2} + \pi \cdot n \)[/tex] and [tex]\( x = -\frac{\pi}{2} + \pi \cdot n \)[/tex], where [tex]\( n \)[/tex] is an integer.

So, the domain of [tex]\( \sec(x) \)[/tex] is all real numbers except where [tex]\( \cos(x) = 0 \)[/tex]. Therefore, the domain of [tex]\( \sec(x) \)[/tex] is [tex]\( x \neq \frac{\pi}{2} + \pi \cdot n \)[/tex] and [tex]\( x \neq -\frac{\pi}{2} + \pi \cdot n \)[/tex], where [tex]\( n \)[/tex] is an integer.

In interval notation, the domain of [tex]\( \sec(x) \)[/tex] is:

[tex]\[ (-\infty, -\frac{\pi}{2}) \cup (-\frac{\pi}{2}, \frac{\pi}{2}) \cup (\frac{\pi}{2}, \infty) \][/tex]

Answer with explanation:

The two points on the number line are

  x = -4

  y=3

The distance is a positive Quantity.

So, Distance between x and y can be written as:

  =|x-y| or |y-x|

 =|3-(-4)| or |-4-3|

 =|3+4| or |-7|

 =|7| or |-7|

 =7 Units

The expression will be : =|x-y| or |y-x|

 =|3-(-4)| or |-4-3|

Answer:

in other words that guy said E

Step-by-step explanation:

The conjugate of the given complex number is:

                        [tex]2+8i[/tex]

We know that any complex number is written in the form of:

            [tex]z=a+ib[/tex]

where a and b are real numbers.

The conjugate of the complex number is given by:

              [tex]\bar z=\bar {a+ib}\\\\i.e.\\\\\bar z=a-ib[/tex]

Here we are given that:

We have a complex number such that the  real part of a complex number is 2 and it's imaginary part is -8.

i.e.

a=2 and b= -8

i.e. the complex number is:

[tex]z=2+(-8)i[/tex]

Hence, the conjugate of this number is:

[tex]\bar z=2-(-8)i\\\\i.e.\\\\\bar z=2+8i[/tex]

perimeter = 20 +20 +24 = 64 feet

 area = 12^2 + x^2 = 20^2

144 + x^2 = 400

x^2 = 256

x = sqrt(256) = 16 feet

area = 1/2 x 16 x 24 = 192 square feet

 cost = 192 x $2 = $384

Answer:

16 50 min

Step-by-step explanation:

Final answer:

In this question, the arrangements of characters sitting together and the options for hamburger toppings are explored using permutations and combinations in Mathematics for High School.

Explanation:

(1) When the elf and the dwarf insist on sitting next to each other, treat them as one entity. Then, there are 4 entities: {elf & dwarf}, hobbit, wizard, man. This gives 4! ways to arrange them, and the elf and dwarf can be arranged within their entity in 2! ways.

So, the total ways are 4! x 2! = 48 ways.

(2) For the hamburger order, since you can choose to include/exclude each topping independently, there are 2 options for each topping (with or without).

Hence, the total ways to order the hamburger are 2⁵ = 32 ways.

for the length of the side that is not given:

look at it as part of a triangle with the legs being 4m tall by 6 m wide

 so 4^2 + 6^2 = X62

16+36 = 52^2

square root(52) = 7.211 m

 does it as to round of to nearest whole number? nearest tenth?

round off answer as needed