Explain the differences among sand, silt, and clay, both in their physical characteristics and their behavior in relation to building foundations.

Answer:

The largest distance between corners in a 3-D cube = a root 3

Explanation : The detailed and step by step explanation is given in the attached file below.

Answer:

15.99 ft/s

Explanation:

From Newton's equation of motion, we have

v = u + at

v = Final speed

u = initial speed

a = acceleration

t = time

now

for the points A and C

v = 17.6 ft/s

u = 13.2 ft/s

t = 3 s

thus,

17.6 = 13.2 + a(3)

or

3a = 17.6 - 13.2

3a = 4.4

or

a = 1.467 m/s²

Thus,

For Points A and B

v = speed at B i.e v'

u = 13.2 ft/s

a = 1.467 ft/s²

t = 1.90 s

therefore,

v' = 13.2 + (1.467 × 1.90 )

v' = 13.2  + 2.7867

v' = 15.9867 ≈ 15.99 ft/s

Answer:

Yes, it is possible to maintain a pressure of 10 kPa in a condenser that is being cooled by river water that is entering at 20 °C because this temperature (20 °C) of the external cooling water is less than the saturation temperature of steam which is which is 45.81 °C, and heated by a boiler; as a result of this condition, coupled with the assumption that the turbine, pump, and interconnecting tube are adiabatic, and the condenser exchanges its heat with the external cooling river water, it possible to maintain a pressure of 10 kPa.

90 inches

Explanation:

According to OSHA requirement, the distance around safety showers and eyewash should be between 82-96 inches off the flow. This will allow for maximum diameter of spray.

Learn More

Safety distance around safety showers:https://brainly.com/question/11123362

Keywords: distance, fire sprinkler head, safety showers, eyewash units,heating and cooling units

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Answer:

Apparent Specific Gravity = 2.88

bulk specific gravity = 2.76

Bulk Specific Gravity SSD  = 2.80

absorption = 1.44%

bulk volume  = 373.3

Explanation:

given data

oven dry weight A  = 1034.0 g

moisture content = 4.0 %

saturated surface dry weight B = 1048.9 g

weight of the aggregate in water C = 675.6 g

solution

we get here Apparent Specific Gravity that is express as

Apparent Specific Gravity = [tex]\frac{A}{A-C}[/tex]   ..........1

put here value

Apparent Specific Gravity = [tex]\frac{1034}{1034-675.6}[/tex]

Apparent Specific Gravity = 2.88

and

now we get bulk specific gravity that is

bulk specific gravity = [tex]\frac{A}{B-C}[/tex]   ...................2

put here value

bulk specific gravity = [tex]\frac{1034}{1048.9-675.6}[/tex]

bulk specific gravity = 2.76

and

now we get Bulk Specific Gravity SSD

Bulk Specific Gravity SSD = [tex]\frac{B}{B-C}[/tex]    ............3

Bulk Specific Gravity SSD = [tex]\frac{1048.9}{1048.9-675.6}[/tex]

Bulk Specific Gravity SSD  = 2.80

and

now absorption will be here as

absorption = [tex]\frac{B-A}{A}[/tex] × 100%    ................4

absorption = [tex]\frac{1048.9-1034}{1034}[/tex] × 100%

absorption = 1.44%

and

last we get bulk volume that is

bulk volume = [tex]\frac{weight\ displce\ water}{density\ water }[/tex]

bulk volume = [tex]\frac{1048.9-675.6}{1}[/tex]

bulk volume  = 373.3

Answer:

Vb.Net

msgbox ("Press "q" twice to quit", msgboxstyle.information)

if char.q = keypress and keypress.count = 2 then

End

End if

Explanation:

Hi, you haven't provided the programing language in which you need the code, I'll just explain how to do it using Python, and you can apply the same method for any programming language, pseudocode or flowchart.  

Answer:

1 userInput = input("Please enter 'userInput':\n")

2 if "darn" in userInput.lower():

3      print("Censored")

4 else:

5      print(userInput\n)

Explanation line by line:

Answer:

a) Etath = 48.2 %

b) P2 = 1.195 MPa

c) wnet = 1749.14 KJ/kg

Explanation:

Given:

T1 = T2 = 50 , TL = 50 + 273 = 323 K

T3 = T4 = 350 , TH = 350 + 273 = 623 K

x3 =0.891

x4 = 0.1

Part a

Thermal efficiency (Etath) of carnot cycle is:

Etath = 1 - (TL / TH )

Etath = 1 - (323) / (623) = 48.2 %

Part b

Note:

From A - 4 Table

T1 = 50 C @sat

sf = 0.7038 KJ/kg.K

sfg = 7.3710 KJ/Kg.K

s2 = s3 = sf + x3 * (sfg)

s2 = s3 = 0.7038 + 0.891*7.3710 = 7.271361 KJ/kg.K

Thus,

@ T2 = 350 C  ; sg = 5.2114 KJ/kg.K

s2 = 7.271361 KJ/kg.K

s2 > sg@T = 350 C, hence super-heated region.

Use Table A-6

T2 = 350 C

s2 = 7.271361 KJ/kg.K

P2 = 1.195 MPa (using interpolation)

part c

wnet can be calculated by finding the enclosed area on a T-s diagram:

s4= sf + x4*sfg =  0.7038 + 0.1*7.3710 = 1.4409 KJ/kg.K

wnet = (TH - TL)*(s3 - s4)

wnet = (623 - 223) * (7.271361 - 1.4409) = 1749.14 KJ/kg

Answer: 144kpa

Explanation:

pressure density =p

The Gage pressure (P1)=48kpa

The height (h1)=3m

The Gage pressure (P2)=?

The height (h2)=9m

P=p * g * h

P1/P2=p * g * h1/p * g * h2

Cancelling out similar terms:

Therefore, P1/P2=h1/h2

P2=P1*h2/h1

Hence, P2=48*9/3=144kpa.

Answer:

Packet switching

Explanation:

Packet switching - it is referred to as the transmission process which involved sending of packets through communication path and last reassembling them again.

The sending of packets is done by broken the digital message into required pieces for efficient transfer.  

in this process, every individual parcel is sent separately.

Answer:

Explanation:

Implementing strategic system requires extensive organizational change coupled with a period of changing from one stage of socio-technical level to another. This changes are known as strategic transitions and are not easily achieved.

It must be noted that not all strategic systems are rewarding and can be very expensive to put together. It is easier to copy most information systems from other firms because strategic advantage can be most times unsustainable.

Answer:

Answer is explained below

Explanation:

Part A -:

Error statement -:

/*

prog.cpp: In function ‘void p(const int*, int)’:

prog.cpp:7:15: error: assignment of read-only location ‘* list’

list[0] = 100;

*/

There is one error in the code in following part

void p( const int list[], int arraySize)

{

list[0] = 100;

}

you are passing list as constant but changing it inside the function that is not allowed. if you pass any argument as const then you can't change it inside the function. so remove const from function argument solve the error.

Part B -:

change made

void p( int list[], int arraySize)

{

list[0] = 100;

}

Executable fully commented code -:

#include <iostream> // importing the iostream library

using namespace std;

void m(int, int []); // Function declearation of m

void p( int list[], int arraySize) // definition of Function p

{

list[0] = 100; // making value of first element of list as 100

}

int main()

{

int x = 1; // initilizing x with 1

int y[10]; // y is a array of 10 elements

y[0] = 1; // first element of y array is 1

m(x, y); // call m function

// printing the desired result

cout << "x is " << x << endl;

cout << "y[0] is " << y[0] << endl;

return 0;

}

void m(int number, int numbers[]) // Function definition of m

{

number = 1001; // value of number is 1001 locally

numbers[0] = 5555; // making value of first element of numbers array 5555

}

Part C :-

In program we initilize x with value 1 and create an array y of 10 elements.

we initilize the y[0] with 1\

then we call function m. In function m ,first argument is value of x and second argument is the pointer to the first element of array y.

so value of x is changed locally in function m and change is not reflected in main function.

but value of y[0] is changed to 5555 because of pass by refrence.

So we are getting the following result :-

x is 1

y[0] is 5555

Answer:

current through the inductor  = 0.24 A

Explanation:

given data

inductor = 100mh

resistor = 100 ohm

voltage = 30 vac

frequancy = 200 Hz

to find out

current through the inductor

solution

current through the inductor will be when inductor is place parallel with resistor

across resistor

XL = i2πl

XL = i2π×200×100×[tex]10^{-3}[/tex] = i126.66

so

current through the inductor = [tex]\frac{voltage}{XL}[/tex]

current through the inductor = [tex]\frac{30}{125.66}[/tex]

current through the inductor  = 0.24 A

Answer:

time = 5.22 hr

Explanation:

Given data:

Energy of battery = 9400 J

Power consumed by three led bulb is 0.5 watt

we know Power is give as

[tex]Power = \frac{ energy}{time}[/tex]

plugging all value and solve for time

[tex]time = \frac{energy}{power}[/tex]

[tex]time = \frac{9400}{0.5}[/tex]

time = 18,800 sec

in hour

1 hour = 3600 sec

therefore in 18,800 sec

[tex]time = \frac{18800}{3600} = 5.22 hr[/tex]

Answer:

The weakest link is the people of the organization

The employees should be oriented and educated on the need to be security and safety conscious

Explanation:

Security professional had shown that negligence among the employees for security practices is a serious threat to end point security.

Answer:

Plane shell which is option b

Explanation:

The temperature in the case of a steady one-dimensional heat conduction through a plane wall is always a linear function of the thickness. for steady state dT/dt = 0

in such case, the temperature gradient dT/dx, the thermal conductivity are all linear function of x.

For a plane wall, the inner temperature is always less than the outside temperature.

To form the string 'ant bat cod', you can concatenate the strings s1, s2, and s3 using the + operator or repeat each string based on the desired repetition using the * operator.

Python expressions using s1, s2, and s3 and operators and * that evaluate to: (a) 'ant bat cod'.

Answer:

a) 0.813

b) 4.38 KW

c) COP = 5.13

d) 3.91 KW , COP = 6.17

Explanation:

Data obtained A-13 tables for R-134a:

[tex]h_{1} = 247.88 \frac{KJ}{kg} \\s_{1} = 0.9575 \frac{KJ}{kgK}\\h_{2s} = 279.45 \frac{KJ}{kg}\\h_{2} = 286.71 \frac{KJ}{kg}\\h_{3} = 87.83 \frac{KJ}{kg}[/tex]

The isentropic efficiency of the compressor is determined by :

[tex]n_{C} = \frac{h_{2s} - h_{1} }{h_{2} - h_{1} }\\= \frac{279.45 - 247.88 }{286.71 - 247.88}\\= 0.813[/tex]

The rate of heat supplied to the room is determined by heat balance:

[tex]Q = m(flow) * (h_{2} -h_{3})\\= (0.022)*(286.71 - 87.83)\\\\= 4.38KW[/tex]

Calculating COP

[tex]COP = \frac{Q_{H} }{W} \\COP = \frac{Q_{H} }{m(flow) * (h_{2} - h_{1}) }\\\\COP = \frac{4.38}{(0.022)*(286.71-246.88)}\\\\COP = 5.13[/tex]

Part D

Data Obtained:

[tex]h_{1} = 244.5 \frac{KJ}{kg} \\s_{1} = 0.93788 \frac{KJ}{kgK}\\h_{2} = 273.31 \frac{KJ}{kg}\\h_{3} = 95.48 \frac{KJ}{kg}[/tex]

The rate of heat supplied to the room is determined by heat balance:

[tex]Q = m(flow) * (h_{2} -h_{3})\\= (0.022)*(273.31 - 95.48)\\\\= 3.91KW[/tex]

Calculating COP

[tex]COP = \frac{Q_{H} }{W} \\COP = \frac{Q_{H} }{m(flow) * (h_{2} - h_{1}) }\\\\COP = \frac{4.38}{(0.022)*(273.31-244.5)}\\\\COP = 6.17[/tex]

Answer:

Electrical failure can lead to _hardware__failure, which in turn can lead to software failure

Answer:

Explanation:

Sample output:

BANK ACCOUT PROGRAM!

----------------------------------

Enter the old balance: 1234.50

Enter the transactions now.

Enter an F for the transaction type when you are finished.

Transaction Type (D=deposit, W=withdrawal, F=finished): D

Amount: 568.34

Transaction Type (D=deposit, W=withdrawal, F=finished): W

Amount: 25.68

Transaction Type (D=deposit, W=withdrawal, F=finished): W

Amount: 167.40

Transaction Type (D=deposit, W=withdrawal, F=finished): F

Your ending balance is $1609.76

Program is ending

Code to copy:

// include the necessary header files.

#include<stdio.h>

// Definition of the function

float withdraw(float account_balance, float withdraw_amount)

{

// Calculate the balace amount.

float balance_amount = account_balance - withdraw_amount;

// Check whether the withdraw amount

// is greater than 0 or not.

if (withdraw_amount > 0 && balance_amount >= 0)

{

// Assign value.

account_balance = balance_amount;

}

// return account_balance

return account_balance;

}

// Definition of the function deposit.

float deposit(float account_balance, float deposit_amount)

{

// Check whether the deposit amount is greater than zero

if (deposit_amount > 0)

{

// Update account balance.

account_balance = account_balance + deposit_amount;

}

// return account balance.

return account_balance;

}

int main()

{

// Declare the variables.

float account_balance;

float deposit_amount;

float withdrawl_amount;

char input;

// display the statement on console.

printf("BANK ACCOUT PROGRAM!\n");

printf("----------------------------------\n");

// prompt the user to enter the old balance.

printf("Enter the old balance: ");

// Input balance

scanf("%f", &account_balance);

// Display the statement on console.

printf("Enter the transactions now.\n");

printf("Enter an F for the transaction type when you are finished.\n");

// Start the do while loop

do

{

// prompt the user to enter transaction type.

printf("Transaction Type (D=deposit, W=withdrawal, F=finished): ");

// Input type.

scanf(" %c", &input);

// Check if the input is D

if (input == 'D')

{

// Prompt the user to input amount.

printf("Amount: ");

// input amount.

scanf("%f", &deposit_amount);

// Call to the function.

account_balance=deposit(account_balance,deposit_amount);

}

// Check if the input is W

if (input == 'W')

{

printf("Amount: ");

scanf("%f", &withdrawl_amount);

// Call to the function.

account_balance = withdraw(account_balance,withdrawl_amount);

}

// Check if the input is F

if (input == 'F')

{

// Dispplay the amount.

printf("Your ending balance is $%.2f\n", account_balance);

printf("Program is ending\n");

}

// End the while loop

} while(input != 'F');

return 0;

}

the picture uploaded below shows the program screenshot.

cheers, i hope this helps.

Answer:

Three operations possible in a quack is QUACKPUSH, QUACKPOP and QUACKPULL.

Explanation:

A quack is a data structure combining properties of both stacks and queues. It can be viewed as a list of elements written left to right such that three operations are possible, these include:

Elements in the quack are stored in stacks. The component stacks can be accessed only through the standard stack functions PUSH and POP.

Answer:

View Image

Explanation:

The question is basically asking you to build a 2-bit asynchronous counter.

What the counter does is it increase it's value by 01₂ every clock pulse. So at 0₂, nothing happens, but at 1₂ it'll count up by 1. It then reset to 00₂ when it overflows.

The design for it is pretty much universal so I kinda did this from memory.

a.) A count-up counter (from 00-11) is simply made by connecting Q' to D, and the output of the previous DFF to the clock of the next one.

b.) A count-down counter (from 11-00) is simply made by using the same circuit as the count-up counter, but you connect Q' to the clock instead of Q.

Answer:

1.505

Explanation:

cylindrical part of diameter d is loaded by an axial force P. This causes a stress of P/A, where A = πd2/4. If the load is known with an uncertainty of ±11 percent, the diameter is known within ±4 percent (tolerances), and the stress that causes failure (strength) is known within ±20 percent, determine the minimum design factor that will guarantee that the part will not fail.

stress is force per unit area

stress=P/A

A = πd^2/4.

uncertainty of axial force P= +/-.11

s=+/-.20, strength

d=+/-.04 diameter

fail load/max allowed

minimum design=fail load/max allowed

minimum design =s/(P/A)

sA/P

A=([tex]\pi[/tex].96d^2)/4, so Amin=

[tex]0.96^{2}[/tex] (because the diameter  at minimum is (1-0.04=0.96)

minimum design=Pmax/(sminxAmin)

1.11/(.80*.96^2)=

1.505

Answer:

The program is given below with appropriate comments for better understanding

Explanation:

#Program

# foot stride = 2.5 feet

# 1 mile = 5280 feet

no_stride_first_min = int(input('Enter the number strides made durng the first minute of jogging: '))

no_stride_last_min = int(input('Enter the number strides made durng the last minute of jogging: '))

avg_stride_one_min = (no_stride_first_min + no_stride_last_min)/2 # calculates the average stride per minute

jogging_duration = float(input('Enter the total time spent jogging in hours and minute: '))

jogging_duration_hours = int(jogging_duration) # gets the hour

jogging_duration_min = jogging_duration - int(jogging_duration) # gets the minute

tot_jogging_duration_min = jogging_duration_hours*60 + jogging_duration_min # calculates total time in minutes

dist_feet = (avg_stride_one_min*2.5)*tot_jogging_duration_min # calculates the total distance in feet

dist_miles = dist_feet/5280 # calculates the total distance in mile

print('Distance traveled in miles = {0:.2f} miles'.format(dist_miles))

Answer:p=ML^-1T^-2

b)PV=MT^-3

c)P/PV^2=T^2L^-2

Explanation:In dimensions,Mass in kg is represented by M

Length is represented by L in meters.

T represent Time in seconds,s.

Pressure=hpg,h=height or depth In m,a=density=kg/m^3

g=acceleration due to gravity,m/s^2

P=hag=mxkg/m^3 xm/s^2=m^2×kg/m^2×s^2=kgm^-1 s^-2=ML^-1T^-2

B)PV=pressure xvelocity

=ML^-1T^-2×distance/time

ML^-1T^-2×L/T=MT^-3

C)p/pv^2=1/V^2=(time/distance)^2=(T/L)^2=T^2L^-2

The  equation that represents the expression for the bonding energy [tex](E_0\))[/tex] in terms of the parameters A, B, and n is: [tex]\[ E_0 = -\frac{A^{\frac{n-1}{n}}}{(nB)^{\frac{1}{n}}} + \frac{1}{n} \][/tex].

Step 1: Differentiate EN with Respect to r

Given:

[tex]\[ E_N = -\frac{A}{r} + \frac{B}{r^n} \][/tex]

Differentiate [tex]\(E_N\)[/tex] with respect to r:

[tex]\[ \frac{dE_N}{dr} = \frac{A}{r^2} - \frac{nB}{r^{n+1}} \][/tex]

Set the derivative equal to zero to find the minimum (equilibrium) point:

[tex]\[ \frac{A}{r^2} - \frac{nB}{r^{n+1}} = 0 \][/tex]

Solve for r as

[tex]\[ \frac{A}{r^2} = \frac{nB}{r^{n+1}} \][/tex]

[tex]\[ r^n = \frac{nB}{A} \][/tex]

[tex]\[ r = \left(\frac{nB}{A}\right)^{\frac{1}{n}} \][/tex]

Step 2: Solve for r in terms of A, B, and n

The equilibrium interionic spacing [tex]\(r_0\)[/tex] is the value of r at the minimum point,

[tex]\[ r_0 = \left(\frac{nB}{A}\right)^{\frac{1}{n}} \][/tex]

Step 3: Determine the Expression for E0

Substitute [tex]\(r_0\)[/tex] into the expression for [tex]\(E_N\):[/tex]

[tex]\[ E_0 = -\frac{A}{r_0} + \frac{B}{r_0^n} \][/tex]

[tex]\[ E_0 = -\frac{A}{\left(\frac{nB}{A}\right)^{\frac{1}{n}}} + \frac{B}{\left(\frac{nB}{A}\right)^{\frac{n}{n}}} \][/tex]

Simplify:

[tex]\[ E_0 = -\frac{A^{\frac{n-1}{n}}}{(nB)^{\frac{1}{n}}} + \frac{B}{(nB)^{\frac{n}{n}}} \][/tex]

[tex]\[ E_0 = -\frac{A^{\frac{n-1}{n}}}{(nB)^{\frac{1}{n}}} + \frac{B}{nB} \][/tex]

[tex]\[ E_0 = -\frac{A^{\frac{n-1}{n}}}{(nB)^{\frac{1}{n}}} + \frac{1}{n} \][/tex]

Combine the terms:

[tex]\[ E_0 = -\frac{A^{\frac{n-1}{n}}}{(nB)^{\frac{1}{n}}} + \frac{1}{n} \][/tex]

So, the equation is [tex]\[ E_0 = -\frac{A^{\frac{n-1}{n}}}{(nB)^{\frac{1}{n}}} + \frac{1}{n} \][/tex].

Learn more about Equilibrium here:

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Answer:

The Java code is given below with appropriate comments for better understanding

Explanation:

import java.util.Scanner;

public class ValidatePassword {

  public static void main(String[] args) {

      Scanner input = new Scanner(System.in);

          System.out.print("Enter a password: ");

          String password = input.nextLine();

          int count = chkPswd(password);

          if (count >= 3)

              System.out.println("Secure");

          else

              System.out.println("Not Secure");

  }

  public static int chkPswd(String pwd) {

      int count = 0;

      if (checkForSpecial(pwd))

          count++;

      if (checkForUpperCasae(pwd))

          count++;

      if (checkForLowerCasae(pwd))

          count++;

      if (checkForDigit(pwd))

          count++;

      return count;

  }

  // checks if password has 8 characters

  public static boolean checkCharCount(String pwd) {

      return pwd.length() >= 7;

  }

  // checks if password has checkForUpperCasae

  public static boolean checkForUpperCasae(String pwd) {

      for (int i = 0; i < pwd.length(); i++)

          if (Character.isLetter(pwd.charAt(i)) && Character.isUpperCase(pwd.charAt(i)))

              return true;

      return false;

  }

  public static boolean checkForLowerCasae(String pwd) {

      for (int i = 0; i < pwd.length(); i++)

          if (Character.isLetter(pwd.charAt(i)) && Character.isLowerCase(pwd.charAt(i)))

              return true;

      return false;

  }

  // checks if password contains digit

  public static boolean checkForDigit(String pwd) {

      for (int i = 0; i < pwd.length(); i++)

          if (Character.isDigit(pwd.charAt(i)))

              return true;

      return false;

  }

  // checks if password has special char

  public static boolean checkForSpecial(String pwd) {

      String spl = "!@#$%^&*(";

      for (int i = 0; i < pwd.length(); i++)

          if (spl.contains(pwd.charAt(i) + ""))

              return true;

      return false;

  }

}

Answer:

B. $5.18

Explanation:

Cost of electricity per kWh = $0.09

Power consumption of refrigerator = 320W = 320/1000 = 0.32kW

In a month (30 days) the refrigerator works 1/4 × 30 days = 7.5 days = 7.5 × 24 hours = 180 hours

Energy consumed in 180 hours = 0.32kW × 180h = 57.6kWh

Cost of electricity of 57.6kWh energy consumed by the refrigerator = 57.6 × $0.09 = $5.18

The electricity cost of the refrigerator per month is approximately $0.65. The correct answer is none of the given options.

To calculate the electricity cost of the refrigerator per month, we first need to find out how many kWh it consumes when it is running for one hour. We can do this by converting the power consumption of the refrigerator from watts to kilowatts:

320 W = 0.32 kW

Since the refrigerator runs only one quarter of the time, we can calculate the kWh consumed per month as follows:

0.32 kW * 1/4 * 24 hours/day * 30 days/month = 7.2 kWh/month

Now, we can calculate the cost of electricity using the unit cost of $0.09/kWh:

7.2 kWh/month * $0.09/kWh = $0.648/month

Therefore, the electricity cost of the refrigerator per month is approximately $0.65.

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The level of service of a highway is determined by the volume-to-capacity ratio. Using the provided traffic information, we can calculate the highway's capacity and determine its level of service, which ranges from A to F.

The level of service of a highway is determined by the volume-to-capacity ratio (V/C ratio).

Given peak-hour directional traffic flow, vehicle types, peak-hour factor, and free-flow speed, we can calculate the capacity of the highway and determine the level of service.

In this case, we would need to calculate the volume of traffic compared to the highway's capacity to determine the level of service, which can range from A to F.

Answer:

A)The sketches for the required planes were drawn in the first attachment.

B)The sketches for the required directions were drawn in the second attachment.

To draw a plane in a simple cubic lattice, you have to follow these instructions:

1- the cube has 3 main directions called "a", "b" and "c" (as shown in the first attachment)

2- The coordinates of that plane are written as: π:(1/a₀ 1/b₀ 1/c₀) (if one of the coordinates is 0, for example (1 1 0), c₀ is ∞, therefore that plane never cross the direction c).

3- Identify the points a₀, b₀, and c₀ at the plane that crosses this main directions and point them in the cubic cell.

4- Join the points.

To draw a direction in a simple cubic lattice, you have to follow these instructions:

1- Identify the points a₀, b₀, and c₀ in the cubic cell.

2- Draw the direction as a vector-like (a₀ b₀ c₀).