elena lists the ages of all of the Family members who live in our house below what is the mean absolute deviation of all their ages?

9514 1404 393

Answer:

  9 days

Step-by-step explanation:

Divide quantity by rate to find time.

  (3 cups)(1/3 cup/day) = 3/(1/3) days = 3(3/1) days = 9 days

Answer:

35

Step-by-step explanation:

Answer:

35

Step-by-step explanation:

To find the sum in simplest form of 4 1/2 and 1 3/5, you convert each to an improper fraction, adding the fractions and convert back to a mixed number. The sum is 6 1/10.

The sum in simplest form of the two numbers 4 1/2 and 1 3/5 can be calculated as follows:

So, the sum in the simplest form of 4 1/2 and 1 3/5 is 6 1/10.

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The photosphere is approximately 5.62 times brighter per unit area than the sunspot.

Stefan-Boltzmann Law: We'll use the Stefan-Boltzmann Law, which states that the radiant emittance (power emitted per unit area) of a black body is proportional to the fourth power of its absolute temperature (T). Mathematically, this can be expressed as:

M = σ * T^4

Where:

M is the radiant emittance (W/m²)

σ is the Stefan-Boltzmann constant (5.670374 x 10^-8 W m^-2 K^-4)

T is the absolute temperature (Kelvin)

Radiant Emittance: Calculate the radiant emittance of the sunspot and the photosphere using their respective temperatures:

Sunspot: M_sunspot = σ * T_sunspot^4 = 5.670374e-8 * 3900^4 ≈ 83.32 x 10^12 W/m²

Photosphere: M_photosphere = σ * T_photosphere^4 = 5.670374e-8 * 5760^4 ≈ 468.37 x 10^12 W/m²

Brightness Ratio: Calculate the ratio of the photosphere's radiant emittance to the sunspot's radiant emittance to determine how much brighter the photosphere is per unit area:

Brightness Ratio = M_photosphere / M_sunspot ≈ 468.37 x 10^12 W/m² / 83.32 x 10^12 W/m² ≈ 5.62

Therefore, the photosphere is approximately 5.62 times brighter per unit area than the sunspot.

Answer:

  $27,318.18

Step-by-step explanation:

The build cost is multiplied by 1.03 each year. After 3 years, it will be multiplied by 1.03^3, so will be ...

  $25,000×1.03^3 ≈ $27,318.18

Answer:

y = -3x + 5

Step-by-step explanation:

Usually by drawing a simple graph, you can tell what the equation is, even if the graph isn't 100% accurate. From the points alone, you can tell that the slope is negative, since as you increase in x you decrease in y (which is a negative relationship). You can tell that it's +5 rather than -5 because the graph sketched shows that the line goes above 0 (indicating a positive number), rather than below (a negative number).

The slope of the line through points (2, -1) and (5,-10) is -3. With y-intercept +5, the line's equation in slope-intercept form is y = -3x + 5.

The subject of your question is in the field of Mathematics, specifically algebra.

You are looking for the equation of the line in slope-intercept form, which is y = mx + b where m is the slope and b is the y -intercept. We first calculate the slope using the formula (y2 - y1) / (x2 - x1). Plugging in the values we get, m = (-10 - (-1)) / (5 - 2) = -9 / 3 = -3. Thus, m = -3. Then, to find the y-intercept, we use the point-slope form of a line equation y - y1 = m(x - x1), and plug in one of the points (2, -1) and the slope value, and then solve for b. The equation in slope-intercept form will be y = -3x + 5.

So the answer to your question is y = -3x + 5.

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Answer:

48- Teddy will need 48 gallons of ice.

Step-by-step explanation:

2.5 ÷ 4 = 1.6

1.6 x 30 = 48!

Teddy will need 48 gallons of ice.

Hope i helped ^^

Answer:

The Exact answer is 287740837743404332336.

The Decimal Answer is 2.87740837  ⋅  10 ^20.

Answer:

[tex]\chi^2 =\frac{50-1}{0.2025} 0.3844 =93.015[/tex]

The degrees of freedom are given by:

[tex] df = n-1= 50-1=49[/tex]

And the p value is given by:

[tex]p_v =P(\chi^2 >93.015)=0.00015[/tex]

Since the p value is very low compared to the significance level provided we have enough evidence to conclude that the true deviation is higher than 0.45

Step-by-step explanation:

Information given

[tex]\alpha=0.05[/tex] represent the confidence level  

[tex]s^2 =0.62^2 =0.3844 [/tex] represent the sample variance obtained

[tex]\sigma^2_0 =0.45^2 =0.2025[/tex] represent the value that we want to test

System of hypothesis

On this case we want to check if the true deviation is higher than 0.45, so then we can create the following system of hypothesis:

Null Hypothesis: [tex]\sigma^2 \leq 0.2025[/tex]

Alternative hypothesis: [tex]\sigma^2 >0.2025[/tex]

The statistic for this case is given by:

[tex]\chi^2 =\frac{n-1}{\sigma^2_0} s^2[/tex]

Replacing we got

[tex]\chi^2 =\frac{50-1}{0.2025} 0.3844 =93.015[/tex]

The degrees of freedom are given by:

[tex] df = n-1= 50-1=49[/tex]

And the p value is given by:

[tex]p_v =P(\chi^2 >93.015)=0.00015[/tex]

Since the p value is very low compared to the significance level provided we have enough evidence to conclude that the true deviation is higher than 0.45

The value of 'd' such that the specifications cover 95% of the measurements can be determined using the z-score corresponding to a 95% confidence interval, and is found to be 0.392 by multiplying with the known standard deviation.

In this case, you're looking to find the value for d such that specifications cover 95% of the measurements. We know that the measurements follow a normal distribution, with a mean of 1.5 and a standard deviation of 0.2.

According to the Empirical Rule (for a bell-shaped, symmetric distribution), approximately 95 percent of the data is within two standard deviations of the mean. Here, however, we want to find the distance d from the mean that encapsulates 95% of the data. We already know that d falls within a 95% confidence interval, which splits the excluded 5% evenly between the upper and lower tails of the distribution.

So, we will use a z-score corresponding to 95% of the measurements. The z-score corresponding to 95% is approximately 1.96 (covering 2.5% in each tail). Multiply this z-score by the standard deviation to get the value of d (1.96 * 0.2 = 0.392). Thus, d = 0.392 should be the value that ensures the specifications cover 95% of the measurements.

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Answer:

c is correct

Step-by-step explanation:

edge

the arc length of the following segment of a circle is c. 18.6.

Arc length formula is used to calculate the measure of the distance along the curved line making up the arc (a segment of a circle). In simple words, the distance that runs through the curved line of the circle making up the arc is known as the arc length.

here, we have,

given that,

the following segment of a circle.

angle=97°

radius=11

so, the arc length= 18.6

hence, the arc length of the following segment of a circle is c. 18.6.

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Answer:

490

Step-by-step explanation:

The Median is the middle number in the set. In this case, it is 490.

~

Answer:

490

Step-by-step explanation:

the median is simply the middle number, and if there are two, you would add them together then divide whatever the total of those two numbers are by two, like this (4+5)/2

Answer:

on the no. line the negative no.s are to the left of zero. -5 is less than 4 because -5 lies to the left of 4 on the no. line -1 is greater than -3 because -1 lies to the right of -3 on the no. line . for less than you can use the sign <- sign

Step-by-step explanation:

-2>-9

7x^2 > -2x^2

6 > -8

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thanks.

Answer:

A) 9.49 ft

Step-by-step explanation:

The area of the rectangle is:

[tex]A = (18\,ft)\cdot (5\,ft)[/tex]

[tex]A = 90\,ft^{2}[/tex]

The length of the square is:

[tex]l = \sqrt{90\,ft^{2}}[/tex]

[tex]l \approx 9.487\,ft[/tex]

Answer:

$[tex]74.37[/tex]

Step-by-step explanation:

To figure out how much is left in his checking account, simply subtract the amount he took out.

[tex]124 -13.96 = 110.04[/tex]

[tex]110.04 - 21.67 =88.37[/tex]

[tex]88.37 - 14= 74.37[/tex]

$[tex]74.37[/tex] is left in his checking account.

Answer:

$102.37

Step-by-step explanation:

Todd has $124 to begin with

He writes two checks (subtract) $13.96 & $21.67

Then he removes $14.00 from his savings & places it into his Checking. (Adding) it to his checking account balance

$124-13.96-21.67+14 = $102.37

Answer:

proportional

Step-by-step explanation:

Answer:

(a) The median of both plots is same, 120 pounds is the median weight of Anatolian Shepherd and the Black Russian Terrier breed.

The range of both plots is also same that is 75 pounds.

The box plot of Anatolian Shepherd is skewed towards left therefore, it is considered to be positively distributed.

The box plot of Black Russian Terrier is skewed towards right therefore, it is considered to be negatively

(b) Any data point which is greater than 155 or smaller than 80 will be considered an outlier.

Step-by-step explanation:

A box plot is a graph which shows five statistical characteristics of a data set.

1. Maximum value

2. Minimum value

3. Median

4. Upper Interquartile

5. Lower interquartile

(a) Compare the distributions of weights for the two dog breeds

Please refer to the attached diagram of the question.

The median of both plots is same, 120 pounds is the median weight of Anatolian Shepherd and the Black Russian Terrier breed.

The range of Anatolian Shepherd is,

Range = Maximum value - Minimum value

Range = 175 - 100 = 75 pounds

The range of Black Russian Terrier is,

Range = Maximum value - Minimum value

Range = 155 - 80 = 75 pounds

Therefore, the range of both plots is also same that is 75 pounds.

A box-plot is considered to be normally distributed when the median is at the center of upper quartile and lower quartile.

The box plot of Anatolian Shepherd is skewed towards left therefore, it is considered to be positively distributed.

The box plot of Black Russian Terrier is skewed towards right therefore, it is considered to be negatively distributed.

(b) What weights would a Black Russian Terrier have to be to be considered an outlier?

An outlier is a data point in the data set that is very different from the other data points.

In this case, the maximum and minimum values in the Black Russian Terrier box-plot are

Maximum = 155

Minimum = 80

Therefore, any data point which is greater than 155 or smaller than 80 will be considered an outlier.

To compare the distributions of weights for the Anatolian Shepherd and Black Russian Terrier, we can look at the boxplots provided. If a Black Russian Terrier were to be considered an outlier, its weight would be significantly different from the other weights in the sample.

To compare the distributions of weights for the Anatolian Shepherd and Black Russian Terrier, we can look at the boxplots provided. The boxplot for each breed shows the minimum value, lower quartile (Q1), median (Q2), upper quartile (Q3), and maximum value. We can compare the positions of these measures to determine the differences between the two breeds.

If a Black Russian Terrier were to be considered an outlier, its weight would be significantly different from the other weights in the sample. An outlier is typically defined as a value that is more than 1.5 times the interquartile range (IQR) above the upper quartile (Q3) or below the lower quartile (Q1). To find the weight that would be considered an outlier for Black Russian Terriers, we need to calculate the IQR and use it to determine the threshold for outliers.

Answer:

(x + 1/2) ² = 289/4

Step-by-step explanation: I answered this correctly

The solutions to t[tex]x^2 + x = 72[/tex]he equation [tex]x^2 + x - 72[/tex] = 0 are x = 8 and x = -9.

To rewrite the quadratic equation[tex]x^2 + x - 72[/tex] = 0 by completing the square, we follow these steps:

Step 1: Move the constant term to the other side of the equation:

[tex]x^2 + x = 72[/tex]

Step 2: Take half of the coefficient of the x-term (which is 1) and square it. Add this value to both sides of the equation:

[tex]x^2 + x + (1/2)^2 = 72 + (1/2)^2\\x^2 + x + 1/4 = 72 + 1/4[/tex]

Step 3: Rewrite the left side as a perfect square:

[tex](x + 1/2)^2 = 289/4[/tex]

Step 4: Take the square root of both sides:

x + 1/2 = ± √(289/4)

Step 5: Solve for x:

x + 1/2 = ± 17/2

x = -1/2 ± 17/2

x = (-1 + 17)/2 or x = (-1 - 17)/2

x = 16/2 or x = -18/2

x = 8 or x = -9

The solutions to the equation [tex]x^2 + x - 72[/tex] = 0 are x = 8 and x = -9.

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Answer:

d. All of these.

Step-by-step explanation:

Analysis of variance (ANOVA) is used in statistics to determine the difference between the mean of two groups. A completely randomized design implies that samples are randomly assigned to either a treatment group or a placebo group during the experiment.  For example, if 40 people are selected to test the effect of an analgesic, four groups could be designed- Groups A, B, C, and D. Groups A, B, and C, can be given different amounts of the drug and Group D, given a placebo. This is an example of a randomized design because the participants were randomly assigned to the groups.

For an ANOVA test to exhibit complete randomized design, we assume that the sample populations are normally distributed, and also have the same variances. We also assume in this design, that samples are randomly and independently selected from their respective populations.

Answer:

[tex] \frac{61}{3} = 20 \frac{1}{3} [/tex]

Step-by-step explanation:

[tex]20 + \frac{2}{6} [/tex]

[tex] \frac{2}{6} = \frac{2 \div 2}{6 \div 2} = \frac{1}{3} [/tex]

[tex]20 + \frac{1}{3} = \frac{20}{1} + \frac{1}{3} = \frac{20 \times 3}{1 \times 3} + \frac{1}{3} [/tex]

[tex] \frac{60}{3} + \frac{1}{3} = \frac{60 + 1}{3} = \frac{61}{3} [/tex]

[tex] \boxed{\green{= \frac{61}{3} = 20 \frac{1}{3}}} [/tex]

Answer:

Step-by-step explanation:

We would set up the hypothesis test.

For the null hypothesis,

p = 0.35

For the alternative hypothesis,

p > 0.35

This is a right tailed test considering the > in the alternative hypothesis.

Considering the population proportion, probability of success, p = 0.35

q = probability of failure = 1 - p

q = 1 - 0.35 = 0.65

Considering the sample,

Sample proportion, P = x/n

Where

x = number of success = 42

n = number of samples = 100

P = 42/120 = 0.42

We would determine the test statistic which is the z score

z = (P - p)/√pq/n

z = (0.42 - 0.35)/√(0.35 × 0.65)/100 z = 1.48

The test statistic for the hypothesis test, given a sample proportion of 0.42, hypothesized population proportion of 0.35, and sample size of 100 students, is calculated to be 1.47.

To calculate the test statistic for the hypothesis test, we use the formula for testing a proportion:

Using the given numbers, we have:

Now we calculate the standard error:

SE = \(\sqrt{\frac{0.35(1-0.35)}{100}}\) = \(\sqrt{\frac{0.35(0.65)}{100}}\) = \(\sqrt{\frac{0.2275}{100}}\) = 0.0477.

Then we calculate the z-score:

z = \(\frac{0.42 - 0.35}{0.0477}\) = \(\frac{0.07}{0.0477}\) = 1.47.

The value of the test statistic for this hypothesis test is 1.47.

Answer:

look below im smart and im just a seventh grader O w O

Step-by-step explanation:

2f(1.6m)

X=24

X=2*24/1.6

X=2*15

X= 30 m

Answer:

so first you cross multiply the first fractions' numerator by the other fractions denominator.

and then you do the same for the other one

then you multiply both denominators

the answer u got from cross multiplying, you get those numbers and subtract

them. the denominator doesn't need anything done to it.

Step-by-step explanation:

hope it helps (pls brainliest if u can)

Answer:

2/ 21

Step-by-step explanation:

2/3 ÷ 7

Copy dot flip

2/3 * 1/7

2/ 21

Answer: 9pi

Step-by-step explanation:

Answer:

  448.69 in^3

Step-by-step explanation:

The volume of a sphere is given by the formula ...

  V = (4/3)πr^3

We want to use diameter, so we can substitute r = d/2 into the formula:

  V = (4/3)π(d/2)^3 = (4/(3·8))πd^3

  V = (π/6)d^3

For the given numbers, ...

  V = (3.14/6)(9.5^3) ≈ 448.69 in^3 . . . . volume of a basketball

Using the formula

[tex]a^2-b^2=(a+b)(a-b)[/tex]

We can write

[tex](4^2)^2-1 = 16^2-1 = (16+1)(16-1)=17\cdot 15[/tex]

Since 17 is prime and the factors of 15 are 3 and 5, the three prime factors of this number are 3, 5 and 17.

The required prime factors of the given expressions are given as 3, 5, and 17.

A number or algebraic expression that evenly divides another number or expression—i.e., leaves no remainder—is referred to as a factor.

Here,
Given expression,
=[4²]² -1
= 16² - 1

Since (a² - b²) = (a + b)(a - b)
= (16 + 1)(16 - 1)
= 17 × 15

= 17 × 3 × 5

Thus, the required prime factors of the given expressions are given as 3, 5, and 17.

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Answer:

B

Step-by-step explanation:

Because since they are increasing $8.50 by 10% you got to divide by 10 to get the answer. Because 10% is equal as multiplying .10 or dividing by 10. So when you divide by 10 you get 0.85. So B is the answer to the question.

Answer:

e. No, the p-value is greater than 0.01, so there is insufficient evidence at the 0.01 level to conclude that pain levels are lower after hypnotism.

Step-by-step explanation:

Hello!

The study's objective is to test if hypnotism reduces pain.

A sample of n=8 subjects was taken and the pain level was recorded in each subject before and after being hypnotized.

The variable of interest was determined by calculating the difference of pain level after - before hypnosis. This is a paired sample test and the variable can be determined as:

Xd: Difference between pain level felt after hypnosis and pain level felt before hypnosis of a subject.

The sample average and standard deviation obtained were:

Xd= -3

Sd= 3

And the variable is presumed to be approximately normal.

An approximately normal distribution is enough to conduct a paired sample t-test.

If the claim is that hypnosis reduces pain, then the average pain level after hypnosis should be less than the average pain level before hypnosis, then the average difference is expected to be negative, symbolically: μd < 0

The test will be one-tailed and so will be the p-value.

Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

So first step is to calculate the value of the statistic under the null hypothesis and then you can calculate the p-value.

H₀: μd ≥ 0

H₁: μd < 0

[tex]t_{H_0}= \frac{X_d-Mu_{d}}{\frac{S_d}{n} }= \frac{-0-0}{\frac{3}{\sqrt{8} } } = -2.828= -2.83[/tex]

The DF of the t-test are n-1= 7

Then you can calculate the p-value as:

P(t₇≤-2.83)= 0.0127

The level of the test is α: 0.01

The decision rule is:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The p-value > α the decision is to not reject the null hypothesis.

Correct option: e. No, the p-value is greater than 0.01, so there is insufficient evidence at the 0.01 level to conclude that pain levels are lower after hypnotism.

I hope this helps!