During a chemical reaction

The diameter of  the pool is 4

Explanation:

To calculate the diameter we must write the values given in the question, here

The circumference of the pool is given as C=12.56 feet.

To calculate the diameter of the pool,

If radius is given, Multiply the radius by 2

If Circumference is given divide the circumference by Pi (π)

the constant value for  Pi (π)=3.14

Diameter(D)= C/π

12.56/3.14

=4

The diameter for the plastic wading pool is 4

Answer:

[tex]K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)[/tex]

Explanation:

The products of this reaction are given by:

[tex]K_2Cr_2O_7 (aq) + SnCl_2 (aq) + HCl (aq)\rightarrow KCl (aq) + SnCl_4 (aq) + CrCl_3 (aq) + H_2O (l)[/tex]

Firstly, dichromate anion becomes chromium(III) cation, let's write this change:

[tex]Cr_2O_7^{2-} (aq)\rightarrow Cr^{3+} (aq)[/tex]

The following steps should be taken:

[tex]Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq)[/tex]

[tex]Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)[/tex]

[tex]Cr_2O_7^{2-} (aq) + 14 H^+ (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)[/tex]

[tex]Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)[/tex]

Similarly, tin(II) cation becomes tin(IV) cation:

[tex]Sn^{2+} (aq)\rightarrow Sn^{4+} (aq) + 2e^-[/tex]

Now that we have the two half-equations, multiply the second one by 3, so that it also has 6 electrons that will be cancelled out upon addition of the two half-equations:

[tex]Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)[/tex]

[tex]3 Sn^{2+} (aq)\rightarrow 3 Sn^{4+} (aq) + 6e^-[/tex]

Add them together:

[tex]Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 3 Sn^{2+} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l) + 3 Sn^{4+} (aq)[/tex]

Adding the ions spectators:

[tex]K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)[/tex]

Explanation:

The van der Waals' forces are the forces that exist between the millions of separate water molecules, and not between the hydrogen and oxygen atoms in the case of water. Dipole-Dipole forces are one of van der Waals' three forces. ... For example, HCl comprised of the atom Hydrogen and Chlorine is polar.

Answer:

They are jogging side by side at 5 m/s

Let's distinguish between the concepts of speed and velocity:

The first condition we have here is the fact that two people have the same speed, this means they are moving at the same rate of change of distance. The second condition must be met as well, if we wish them to have the same velocity, this means they should be moving in the same direction, let's say, along the positive or negative x-axis, but not in opposite directions.

Answer:

In polar Covalent bonds, the electrons which are in bonded shifts towards an atom which has more valance electrons.

Explanation:

We know if an atom takes the electron it acquires a negative charge whereas if it gives an electron it acquires a positive charge in the ionic bond. But here we are talking about covalent bonds. Covalent bonds are those in which atoms share the electron instead of completely giving off the electron. If the atoms are identical in case of covalent bond that is 2 hydrogen atoms then this type of bonding is called pure covalent bonds but if the atoms linked in covalent bonds are different then it is called polar covalent bonds.

In this, the bonding electrons will shift towards an atom which has more valence electron thereby acquiring the partial negative charges and the other atom will acquire a partial positive charge. For example, HCl. In this the Chlorine atom is having more valence electron than hydrogen atom, and hence Chlorine atom has a partial negative charge and Hydrogen atom has a partial positive charge.

In polar Covalent bonds, the electrons that are in bonded shifts towards an atom that has more valance electrons.

The following information should be considered:

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Answer:

The mathematical formula expressing Newton's Second Law of Motion is :

F = ma

Explanation:

Second Law of Motion : It states that external unbalanced force is directly proportional to rate of change of momentum.

Its formula becomes : F = ma

[tex]F = \frac{m(v-u)}{t}[/tex]

Put,

[tex]\frac{(v-u)}{t} = a[/tex]

F = ma

Answer:

F = ma

Explanation:

Answer:

potassium 3-ethylpentanoate

or

potassium 3-ethylpentanoic acid

Explanation:

This is an organic compound.

This is a salt of carboxylic acid

This compound have 5 carbon main chain

There is an ethyl group is attached on carbon 3

K (Potassium) substituted the H (hydrogen) of pentanoic acid and form salt of it.

This compound shown in ionic form as salt solution written in ionic form.

So,

the name will be

Potassium 3-ethylpentanoate

it is also named as potassium 3-ethylpentanoic acid

Note: you can write any one of them both are right

the structure and name is given in attachment

Answer:

S orbital:spherical

P orbital:dumbbell

D orbital:double dumbbell

F orbital:complex

Explanation:

Answer:

ls most commonly viewed as a metals

Answer:

When observing the image inside a spoon, the image seems to be bent or cut, because the rays of light deviate with a  certain angle of incidence, since they travel slower when passing from the air, where there are less particles, to the liquid, where there are more particles .

When turning the spoon a specular reflection is observed, it is when the surfaces are polished, the light rays are reflected with and angle of reflection in only one direction and in an orderly manner. This is why images are formed that look like copies of objects.

Explanation:

Reflection and refraction of waves are two phenomena that occur when a wave that propagates in a certain medium meets a separation surface with another medium.

Reflection is the change in direction that a wave experiences when it comes into contact with the surface that separates two media while returning to the point where it originated. Refraction is the change of direction and speed that a wave undergoes obliquely on a surface that separates two media with different refractive indices.

Looking at your reflection in a shiny soup spoon is a result of light reflection. The angle of incidence and angle of reflection are equal, resulting in an upright and undistorted image. The back of the spoon is concave, causing an upside down and distorted reflection.

When you look at your reflection in the side of a shiny soup spoon, you will see an upright and undistorted image. This is because of the reflection of light. The angle at which light hits the spoon, known as the angle of incidence, is equal to the angle at which it reflects off the spoon, known as the angle of reflection. The back of the spoon is concave, so when you look at your reflection in it, the image will be upside down and distorted.

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Answer:

a) 0.25 g b) 0.01542 g

Explanation:

Half life of Po-218 = 3.04 minutes

initial mass = 1 g

after 3.04 minutes it will remain 0.5 g

after another 3.04 minutes it will remain 0.25 g

After 6 minutes it will remain approx 0.25 g

B) after another 3.04 minutes it will remain 0.125 g

after another 3.04 minutes it will remain 0.0625 g

after another 3.04 minutes it will remain 0.03125 g

after another 3.04 minutes it will remain 0.015625 g

After 18 minutes it will remain approx 0.01542 g

Answer:

The [tex]K_{sp}[/tex] remains the same

Explanation:

Let's look at what actually happens in this scenario. Before we dive into the explanation, remember the principle of Le Chatelier: for a system at equilibrium, a specific disturbance in molarity/volume/pressure of any species in equilibrium would cause the equilibrium to shift towards the side that minimizes such a disturbance.

To begin with, we have a saturated water solution of lead(II) chloride. A saturated solution means that at the given temperature we have a maximum amount of lead(II) chloride that could dissolve in the given volume of water.

Since lead(II) chloride is not highly soluble, we have an equilibrium between the precipitate and the dissociated ions:

[tex]PbCl_2(s)[/tex]⇄[tex]Pb^{2+}(aq)+2Cl^-(aq)[/tex]

Now we're adding NaCl to this solution. Sodium chloride is a sparingly soluble salt which readily dissociates into sodium and chloride ions:

[tex]NaCl(aq)\rightarrow Na^+ (aq)+Cl^- (aq)[/tex]

Notice that sodium chloride increases the concentration of chloride ions in the solution, so the equilibrium between the precipitate and its ions is disturbed.

According to the principle of Le Chatelier, due to an increase in chloride ions, the equilibrium would be disturbed and the system would tend to decrease it in order to restore the equilibrium. Hence, the equilibrium shifts towards the precipitate forming more of the precipitate and decreasing the amount of lead(II) cation, as well as the excess of chloride ions. This is also called the common ion effect: the common ion decreases the solubility of a salt.

However, it only decreases the solubility of the salt but not the solubility product constant defined as:

[tex]K_{sp}=[Pb^{2+}][Cl^-]^2[/tex]

A decrease in lead(II) concentration is compensated by the excess of chloride. The solubility product is only temperature-dependent, just as any other equilibrium constant, so it doesn't depend on the molarity of chloride or lead(II) ions.

Solubility, on the other hand, is equal to:

[tex]S=[Pb^{2+}]=\frac{K_{sp}}{[Cl^-]^2}[/tex]

And, as you can see, it decreases, as K is kept constant and we have an increase in chloride.

Answer:

The answer is the Ksp remains the same.

Explanation:

I got this answer right on an assignment.

Answer:

The precipitate will form.

Explanation:

Let's write the equilibrium expression for the solubility product of calcium sulfate:

[tex]CaSO_4(s)[/tex] ⇄ [tex]Ca^{2+}(aq)+SO_4^{2-}(aq)[/tex]

The solubility product is defined as the product of the free ions raised to the power of their coefficients, in this case:

[tex]K_{sp}=[Ca^{2+}][SO_4^{2-}]=10^{-4.5}[/tex]

Our idea is to find the solubility quotient, Q, and compare it to the K value. A precipitate will only form if Q > K. If Q < K, the precipitate won't form. In this case:

[tex]Q_{sp}=[Ca^{2+}][SO_4^{2-}]=5.00\cdot10^{-2} M\cdot7.00\cdot10^{-3} M=3.5\cdot10^{-4}[/tex]

Now given the K value of:

[tex]K_{sp}=10^{-4.5}=3.2\cdot10^{-5}[/tex]

Notice that:

[tex]Q_{sp}>K_{sp}[/tex]

This means the precipitate will form, as we have an excess of free ions and the equilibrium will shift towards the formation of a precipitate to decrease the amount of free ions.

Answer:

32

Explanation:

The maximum number of electrons can be calculated by using the expression 2n2

when n = 4

substitute n for 4

2(4)2

2(16) = 32

Answer:

32

Explanation:

Answer:

The half life of element XY is 12 days

Explanation:

Given:

Time taken for  1024 grams to decay into 32 grams  = 60 days

To Find:

The half life of element XY = ?

Solution:

The Half life is calculated by

[tex]N = N_0 (\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}[/tex]

[tex]t_{\frac{1}{2}}[/tex] =[tex]\frac{t}{log_{\frac{1}{2}}( \frac{N(t)}{N_0})}}[/tex]

Substituting the values,

[tex]t_{\frac{1}{2}}[/tex] =[tex]\frac{60}{log_{\frac{1}{2}}( \frac{32}{1024})}}[/tex]

[tex]t_{\frac{1}{2}}[/tex] =[tex]\frac{60}{log_{\frac{1}{2}}(0.03125)}}[/tex]

[tex]t_{\frac{1}{2}}[/tex] =[tex]\frac{60}{5}[/tex]

[tex]t_{\frac{1}{2}}[/tex] = 12

Answer:

Substances used to make the bomb

The area it was placed

Which people were in that area

How the bomb was set off

Explanation:

Examining the residues left at the scene by the bomb could tell forensics what the bomb was made out of, and the police could investigate possible leads about people who purchased (or have access to) such materials.

The area should give clues because security cameras could be used to trace who was there that should not be. There would be a possible suspect.

If it is a public place, then we can see if there is anyone of importance (to the suspect) that was there at that time.

If a remote detonator was used to set off the bomb, then the suspect would have to be relatively close to the bomb.

Answer:

Substances used to make the bomb

The area it was placed

Which people were in that area

How the bomb was set off

The pair of elements Phosphorus and Bromine is most likely to form a covalent bond. Covalent bonds typically occur between nonmetals, as they share electrons to reach stability. Other given pairs, involving metals and nonmetals, are more likely to form ionic bonds.

Among the pairs of elements provided, the pair that is most likely to form a covalent bond is Phosphorus and Bromine. A covalent bond typically forms when two nonmetals, like phosphorus and bromine, share electrons. In contrast, sodium and magnesium are metals which usually form ionic bonds when they combine with nonmetals (like chlorine for sodium and oxygen for magnesium). Copper can also form ionic bonds with nonmetals like oxygen.

As an example, consider a molecule like oxygen gas (O=O). Each oxygen atom has six electrons in its valence shell and needs two more to reach stability. This stability is achieved when the two oxygen atoms share two pairs of electrons, forming a double covalent bond.

In contrast, consider the formation of sodium chloride (table salt). Sodium readily donates its single valence electron to chlorine, which needs only one more electron to be stable. This results in the formation of a sodium cation and a chloride anion, which are held together by an ionic bond.

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The number of neutrons that would equal a mass of one gram is approximately 6 x 10^23, which is also known as Avogadro's number.

To find the number of neutrons that would equal a mass of one gram, you would need to divide the desired mass (1 gram) by the mass of a single neutron, which is 1.67 x 10^-24 g. So, the calculation would be 1 g / 1.67 x 10^-24 g = approximately 6 x 10^23 neutrons. This number is also known as Avogadro's number, a familiar concept in chemistry and physics.

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Answer:

-21 kJ·mol⁻¹  

Explanation:

Data:

                    H₃O⁺ +  OH⁻ ⟶ 2H₂O

       V/mL:    50         50  

c/mol·dm⁻³:   1.0         1.0

ΔT = 4.5 °C  

       C = 4.184 J·°C⁻¹g⁻¹

C_cal = 50 J·°C⁻¹

Calculations:

(a) Moles of acid

[tex]\text{Moles of acid} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}\\\\\text{Moles of base} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}[/tex]

So, we have 0.050 mol of reaction

(b) Volume of solution

V = 50 dm³ + 50 dm³ = 100 dm³

(c) Mass of solution

[tex]\text{Mass of solution} = \text{100 dm}^{3} \times \dfrac{\text{1.00 g}}{\text{1 dm}^{3}} = \text{100 g}[/tex]

(d) Calorimetry

There are three energy flows in this reaction.

q₁ = heat from reaction

q₂ = heat to warm the water

q₃ = heat to warm the calorimeter

q₁ + q₂ + q₃ = 0

     nΔH   +         mCΔT       + C_calΔT = 0

0.050ΔH + 100×4.184×4.5 +   50×4.5  = 0

0.050ΔH +          1883        +      225    = 0

                                  0.050ΔH + 2108 = 0

                                              0.050ΔH = -2108

                                                        ΔH = -2108/0.0500

                                                              = -42 000 J/mol

                                                              = -42 kJ/mol

This is the heat of reaction for the formation of 2 mol of water

The heat of reaction for the formation of mol of water is -21 kJ·mol⁻¹.

Answer:

a. [tex]2.69 pm[/tex]

b. [tex]4.42\cdot 10^{-34} m[/tex]

Explanation:

The de Broglie wavelength can be found by the following equation:

[tex]\lambda_{dB} = \frac{h}{mv}[/tex]

Here:

[tex]\lambda_{dB}[/tex] is the de Broglie wavelength (in m);

[tex]h[/tex] is the Planck's constant, [tex]h = 6.626\cdot 10^{-34} J\cdot s[/tex];

[tex]m[/tex] is mass (in kg);

[tex]v[tex] is velocity (in m/s).

a. We need to know the mass of an electron here:

[tex]m_e=9.11\cdot10^{-31} kg[/tex]

And the speed of light:

[tex]c = 3.00\cdot 10^8 m/s[/tex]

The fraction of the speed of light is:

[tex]\omega = 0.90[/tex]

Substituting into the equation:

[tex]\lambda_{dB} = \frac{h}{\omega c m_e}=\frac{6.626\cdot10^{-34} J\cdot s}{0.90\cdot 9.11\cdot 10^{-31} kg\cdot 3.00\cdot 10^8 m/s} = 2.69\cdot 10^{-12} m = 2.69 pm[/tex]

b. Similarly, here we have:

[tex]m_b=150 g = 0.150 kg[/tex]

And the velocity of:

[tex]v = 10 m/s[/tex]

We obtain:

[tex]\lambda_{dB}={6.626\cdot 10^{-34} J\cdot s}{0.150 kg\cdot 10 m/s} = 4.42\cdot 10^{-34} m[/tex]

Notice that the wavelength of a large object is smaller by a fraction of:

[tex]\frac{2.69\cdot 10^{-12} m}{4.42\cdot 10^{-34} m} = 6\cdot 10^{21}[/tex]

This means the de Broglie wavelength of a macroscopic object is negligible compared to the wavelength of a microscopic object.

Answer: D the rate that varies more with temperature

Explanation: reaction with greater activation energy is not feasible ordinarily as the reacting molecules have little or no energy to overcome the activation energy. But as the temperature of the reaction is increased, the reacting molecules gains more energy to overcome the energy barriers(activation energy) hence proceeding to form products. In this case, the rate of the reaction depends on the temperature. So an increase in temperature will increase the kinetic energy of the molecules thereby increasing the rate of the reaction and a decrease in temperature will leads to a decrease in the rate of the reaction.

Final answer:

In comparing two chemical reactions, the reaction with the greater activation energy typically has the slower rate. This is due to fewer molecules being able to overcome the higher energy barrier to react. The correct answer to the question is (A) the slower rate.

Explanation:

In comparing two reactions, if one has a greater activation energy, it generally has the slower rate. Activation energy is the energy required to initiate a reaction, and it plays a critical role in determining the rate of a chemical reaction. A higher activation energy means that fewer molecules possess the necessary energy to overcome the barrier and react at a given temperature. Thus, the reaction with a higher Ea will have a slower rate.

Therefore, the correct answer to the question is: (A) the slower rate. As temperature increases, reactions with high activation energies can speed up considerably, because the proportion of molecules with sufficient energy to overcome the Ea increases significantly. Conversely, reactions with lower activation energies are less sensitive to temperature changes since a high proportion of molecules already have enough energy, even at lower temperatures.

Answer:

[tex]K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}[/tex]

Explanation:

Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:

Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:

[tex]K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}[/tex]

Answer:

how does gravity affect something

Explanation:

they study  physics.

hope this helped

Florida experiences the first day of spring when Earth is in Position 3 with respect to the Sun. On or about March 21, known as the vernal equinox, neither hemisphere is favored, and the Sun crosses the celestial equator, marking the first day of spring.

Florida, which is located in the Northern Hemisphere, experiences the first day of spring when Earth is in Position 3 with respect to the Sun. On or about March 21, known as the vernal equinox, the Sun is on the celestial equator. This means that every place on Earth receives roughly 12 hours of sunshine and 12 hours of night. During this time, neither hemisphere is favored, and the Sun crosses the celestial equator, marking the first day of spring.

Answer: answer is D

Explanation:

Answer:

Look for predictable changes and patterns - Apex

Answer:

Look for predictable changes and patterns

Explanation:

Ap3x

The empirical formula of caproic acid is C3H6O.

The empirical formula of caproic acid can be determined by calculating the molar ratios of carbon, hydrogen, and oxygen in the compound. The masses of each element in the sample can be used to calculate the number of moles. From the molar ratios, we can determine the simplest whole number ratio of elements, which gives us the empirical formula.

Given that the sample contains 0.0930g of Carbon, 0.0156g of Hydrogen, and 0.0413g of Oxygen, we can calculate the number of moles:

Next, we divide the number of moles for each element by the smallest number of moles to get the simplest whole number ratio. In this case, the smallest number of moles is 0.002583moles:

Therefore, the empirical formula of caproic acid is C3H6O.

Final answer:

After converting the given masses of C, H, and O to moles and finding their mole ratio, we determine that the empirical formula for caproic acid is C3H6O.

Explanation:

To determine the empirical formula of caproic acid from the given masses of Carbon (C), Hydrogen (H), and Oxygen (O), we must first convert the masses to moles:

Carbon: 0.0930 g C × (1 mol C / 12.01 g C) = 0.007744 mol C

Hydrogen: 0.0156 g H × (1 mol H / 1.008 g H) = 0.015476 mol H

Oxygen: 0.0413 g O × (1 mol O / 16.00 g O) = 0.002581 mol O

Next, we find the ratio of moles of each element by dividing each by the smallest number of moles.

C: 0.007744 mol / 0.002581 mol = 3

H: 0.015476 mol / 0.002581 mol = 6

O: 0.002581 mol / 0.002581 mol = 1

Thus, the mole ratio of Carbon, Hydrogen, and Oxygen in caproic acid is 3:6:1, which simplifies to 1:2:1/3. However, we cannot have a fraction in an empirical formula, so we multiply by 3 to get whole numbers.

The empirical formula is therefore represented as C3H6O with the assumption that the molecule has the smallest number integers for carbon, hydrogen, and oxygen that maintain the ratio.

Answer:

[tex]2 NaOH (aq) + H_2SO_4 (aq)\rightarrow 2 H_2O (l) + Na_2SO_4 (aq)[/tex]

Explanation:

Let's correct and balance the given equation:

The equation becomes:

[tex]NaOH (aq) + H_2SO_4 (aq)\rightarrow H_2O (l) + Na_2SO_4 (aq)[/tex]

We require 2 NaOH in order to balance the two sodium cations on the right, this would yield a total of 4 hyrogens on the left, so we also need two water molecules to balance it fully:

[tex]2 NaOH (aq) + H_2SO_4 (aq)\rightarrow 2 H_2O (l) + Na_2SO_4 (aq)[/tex]

Answer:

The answer is A on edge

Explanation:

Our digestive has the steps of digestion and absorption associated with it. So all the compounds taken in as food are first broken down into simpler components before absorption.

ATP or Adenosine Triphosphate is a compound containing a molecule of adenine as nitrogen base, a ribose sugar and three molecules of phosphate attached with the adenine in a chain. Its unable to get absorbed into the system as ATP itself. In intestine, it will be broken down into Adenine, ribose, and phosphates and then absorbed individually into blood.

Thus even if we consume raw ATP, we can't bypass the process of ATP formation. So, there's no significance. And secondly, ATP is very expensive and not suitable for consumption itself.