Do the number of atoms you start with affect the outcome of half life

Answers

Answer 1
No half life is independent of the the number of atoms in a sample. Half life is dependent only on the isotope in question.

Related Questions

If the mass of a particular atom is exactly 5 times the mass of an atom of carbon-12, what is its mass

Answers

The mass is 60 grams.

Please answer question #1

Answers

Freezing occurs when the temperature drops enough a gas turns into a solid
I believe the answer is C I hope u get this right :)

Name two animals that are omnivores. Give an example of a plant and an animal that each one might eat.

Answers

Two animals that are omnivores are: 
Bears and Badgers
Bears eat clover and other plants, and they eat salmon and other animals.
Badgers eat plants such as different fruits like pears and plums, and Badgers eat earthworms, insects, amphibians (such as frogs) reptiles and birds.

Humans are omnivores. We eat both meat and plants. We eat green beans, peas, carrots, and corn. we also eat chicken, fish, pork, hamburger, salmon, and shrimp . Dogs are omnivores. In some dog food there is vegetables and there is also meat. For example, the meats would be chicken, pork, and salmon. The plants would be green beans, peas, and corn. Plants would basically be considered "vegetables." 
Now you try and think of some more!
Hope this helps you! 

Barium sulfate is a compound used to assist in diagnosing medical problems through x-ray analysis and is 58.8% barium. what mass of barium is present in a 620 mg tablet of barium sulfate?

Answers

Final answer:

To find the mass of barium in a 620 mg tablet of barium sulfate, multiply the tablet's mass by the percentage of barium (58.8%). The calculation yields approximately 364.56 mg of barium in the tablet.

Explanation:

The question is asking to calculate the mass of barium present in a 620 mg tablet of barium sulfate, a compound known for its use in medical imaging. Given that barium sulfate is 58.8% barium by mass, we can calculate the mass of barium in the tablet by multiplying the total mass of the tablet by the percentage of barium.

To find the amount of barium, we use the following calculation:

Mass of barium = (mass of barium sulfate tablet) x (percentage of barium) / 100%

Mass of barium = (620 mg) x (58.8%) / 100

Mass of barium = 620 mg x 0.588

Mass of barium ≈ 364.56 mg

Therefore, a 620 mg tablet of barium sulfate contains approximately 364.56 mg of barium.

List at least one reason for not touching the magnesium metal with bare hands. 3. list two reasons for using crucible tongs to handle the crucible and lid after their initial firing in the experimental procedure.

Answers

The magnesium metal is highly reactive and can ignite in contact with moisture or even air. The skin is usually covering in moisture, so the contact with it may cause a reaction that can produce irritation, lesions and even burns.

Crucible tongs are mandatory to handle hot crucibles to avoid skin burns and accidents during experimental procedures. Crucible tongs work with the crucible; their shape was designed to firmly hold it to avoid spills.

Touching the magnesium metal can actually contaminate it and bring with it impurities which may not be removed by heating. So this leads to error in weighing.

 

There are two reasons not to touch the crucible tong with bare hands:

1. The crucible tong is used during firing so it is extremely hot and may burn your hands

2. Any impurities in your hand may contaminate the tong hence leading to error just like the case for the magnesium metal

Show that the speed of an electron in the nth bohr orbit of hydrogen is αc/n, where α is the fine structure constant. what would be the speed in a hydrogen-like atom with a nuclear charge of ze?

Answers

Final answer:

The speed of an electron in the nth Bohr orbit of hydrogen is shown to be αc/n by equating the centripetal force to the Coulomb force. This principle extends to hydrogen-like atoms, where the speed becomes Zαc/n for a nucleus with charge Ze.

Explanation:

To demonstrate that the speed of an electron in the nth Bohr orbit of hydrogen is αc/n, where α is the fine structure constant, we start from the principle that the centripetal force required for an electron to move in a circular orbit is provided by the Coulomb force. For a hydrogen-like atom with a nucleus of charge Ze, the centripetal force is given by mev²/rn and the Coulomb force by k(Ze)(e)/rn². By setting these two forces equal, mev²/rn = k(Ze)(e)/rn², we can cancel rn and one charge e to find an expression for v, the electron speed.

To find the speed of an electron in a hydrogen-like atom with nuclear charge Ze, the same process is followed, but with Z = 1 replaced by the actual Z value. Noting that α = ke²/(hc) and rearranging the terms, we determine that the electron speed v = αc/n for a hydrogen atom (Z=1). For a hydrogen-like atom with a nuclear charge of Ze, the speed would be v = Zαc/n.

One year ago, you sold a put option on 100,000 euros with an expiration date of 1 year. you received a premium on the put option of $0.04 per unit. the exercise price was $1.22. assume that 1 year ago the spot rate of the euro was $1.20, the 1-year forward rate exhibited a discount of 2 percent, and the 1-year futures price was the same as the 1-year forward rate. from 1 year ago to today, the euro depreciated against the dollar by 4 percent. today the put option will be exercised (if it is feasible for the buyer to do so).

Answers

There are two problems for this question:1. What is the total dollar amount of your profit and loss:
Put option premium is equal to 0.04 per unit.
The exercise price is 1.22
One option contract is 100,000
Selling price is 1.20
-Purchase prise is - 1.22
-Premium paid is +0.04
Net profit is = 0.02 x 100,000 = 2,000 – 80 = 1,920

2. Now undertake that as an alternative of taking a position in the put option one year ago, you sold a future's contract on 100,000 euros with a payment date of one year.
Find the total dollar amount of your profit or loss.
Solution: Contract to buy: $1.20 x 100,000 = 120,000 at payment date.
Contract to sell: $1.22 x 100,000 = 122,000 at settlement date
Settle contracts: -2,000 - 80 = -$2,080

which statement best describes the properties of ionic compounds????

Answers

Hello.

The answer is that these properties are brittle, solid at room temperature, and have a high melting point.

The molecular formula of a compound is always ________ the empirical formula. the molecular formula of a compound is always ________ the empirical formula. the same as simpler than an integral multiple of more complex than different from

Answers

molecular formula is an integral multiple of the empirical formula

Answer:

A whole number.

Explanation:

Hello,

Empirical formula is the smallest representation of a chemical formula and the molecular formula is the actual formula of a given compound. For instance, glucose has the following molecular formula:

[tex]C_6H_{12}O_6[/tex]

But its empirical formula is:

[tex]CH_2O[/tex]

So they are relation by the 6 as a whole number.

Best regards.

According to the lewis definition, a base is a(n):
a. proton donor.
b. hydroxide ion donor.
c. hydrogen ion donor.
d. electron pair donor.
e. electron pair acceptor.

Answers

a base is an hydroxide ion donor

What precautions must be taken when you introduce a mixture of compounds to be separated onto a liquid chromatography column?

Answers

Final answer:

Precautions must be considered when introducing a mixture of compounds onto a liquid chromatography column to ensure accurate separation.

Explanation:

When introducing a mixture of compounds onto a liquid chromatography column, there are several precautions that must be taken to ensure accurate separation. First, the sample should be introduced as a narrow band at the top of the column. This helps to maintain the initial concentration profile and prevent broadening of the bands. Second, the solvents used in the mobile phase should be compatible with the stationary phase and solutes to avoid any interactions that could affect separation. Finally, the column should be equilibrated with the mobile phase before introducing the sample to ensure consistent separation.

HNO3 Express your answers as ions separated by a comma.

Answers

In this item, it is assumed that we are to express the given compound in their ionic form. To be able to determine as to what ions this compound will dissociate into, we have the chemical reaction.

                     HNO3 --> H⁺  + NO₃⁻

Hence, the ions are H⁺, NO₃⁻. 

Describe how you could determine the specific heat of a sample of a solid substance. You may assume that the substance does not react with water. In your answer, make sure to include a description of what equipment you would use and how you would interpret the data you collected.

Answers

I would measure the mass of the solid substance. I would prepare a known mass of room temperature water large enough to submerge the solid substance in question. I would place the water in an insulated container. Then I would heat the solid substance to a known temperature. I would measure the temperature of the heated sample and the water. Then I would submerge the sample in the water and allow the sample and the water to reach the same temperature. I would measure this equilibrium temperature. I would interpret the difference in temperature between the heated sample and the equilibrium temperature as the change in temperature in the sample. Given the known mass, the beginning temperature of the water, and the equilibrium temperature I can determine how much energy was transferred from the heated sample to the water. Now the mass of the sample, a change in temperature in the solid substance, and the amount of energy transferred to create the temperature is known. This is sufficient to determine the specific heat of the solid substance

Answer:

I would use calorimetry to determine the specific heat.

I would measure the mass of a sample of the substance.

I would heat the substance to a known temperature.

I would place the heated substance into a coffee-cup calorimeter containing a known mass of water with a known initial temperature. I would wait for the temperature to equilibrate, then calculate temperature change. I would use the temperature change of water to determine the amount of energy absorbed. I would use the amount of energy lost by substance, mass, and temperature change to calculate specific heat.

Explanation:

Answer on Edg 21'

80 grams of iron (III) oxide and 54 grams of aluminum react to form an elemental iron and aluminum oxide. In the lab you only manage to get 75% yield.
a. How many grams of the non limiting reagent remains?
b. How many grams of the limiting reagent remains?
c. How many in grams of an elemental iron is formed?

Answers

a) 34 grams Al remains b) 20 grams Fe2O3 remains c) 42 grams Fe produced Iron(III) oxide is Fe2O3, so the balanced reaction is Fe2O3 + 2Al ==> Al2O3 + 2Fe Now, calculate the molar masses of the involved elements and compounds Atomic weight iron = 55.845 g/mol Atomic weight Aluminum = 26.981539 g/mol Atomic weight oxygen = 15.999 g/mol Molar mass Fe2O3 = 2 * 55.845 + 3 * 15.999 = 159.687 g/mol Now determine how many moles of each reactant you have. Moles Fe2O3 = 80 g / 159.687 g/mol = 0.500980042 mol Moles Al = 54 g / 26.981539 g/mol = 2.001368417 mol Since you need only 2 moles of Al per mole of Fe2O3, the limiting reactant is Fe2O3. So for every mole of Fe2O3 used, we get 2 moles of iron, so the mass of iron produced with 100% yield is double the moles of Fe2O3 multiplied by the atomic weight of iron, so: 0.500980042 mol * 2 * 55.845 g/mol = 55.95446089 g Additionally, for every mole of Fe2O3 consumed, 2 moles of Al are consumed. So the mass of consumed Al is 0.500980042 mol * 2 * 26.981539 g/mol = 27.03442508 g a. Since we only had 75% yield, only 75% of the calculated aluminum is consumed, so 54 g - 0.75 * 27.034425 = 33.72418125 Rounded to 2 significant figures gives 34g b. Since we only had 75% yield, we're left with 25% of the Fe2O3 which is 0.25 * 80 g = 20 g c. And we only get 75% of the iron, so 55.95446089 g * 0.75 = 41.96584567, rounded to 2 figures gives 42 grams

The temperature at which a liquid turns to a gas is called the boiling point.

If true write true.
If false change the word to make the statement true.

Answers

The answer is true.

What is the value of the bond angles in bf3? enter the bond angle of the molecule?

Answers

Final answer:

The BF3 molecule forms a trigonal planar configuration because boron, the central atom, is surrounded by three fluorine atoms. As a result, the bond angles in this molecule are exactly 120 degrees.

Explanation:

The bond angles in a BF3 molecule, or boron trifluoride, are determined by its molecular structure. This molecule is arranged in a trigonal planar configuration, and hence the bond angles are exactly 120 degrees.

Let's dive a bit deeper - in geometry any three points in a plane can form an equilateral triangle if they are equidistant from each other. Similarly, in BF3 molecule, the boron atom is at the center and the three fluorine atoms are located at the corners of an equilateral triangle.

Since all angles in an equilateral triangle are 60 degrees and the bond angle is the angle between two consecutive sides, it is twice as much, or 120 degrees.

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Final answer:

The bond angles in BF3 are 120°; the molecule's geometry is trigonal planar and highly symmetrical, resulting in a dipole moment of zero. BF3 also tends to bond with a fluoride ion to form BF4-, which is more stable.

Explanation:

The value of the bond angles in BF3 is 120°, which corresponds to the molecular geometry known as trigonal planar. Each fluorine atom is positioned at the vertices of an equilateral triangle around the central boron atom, and all bonds are equal in length, and the molecule is highly symmetrical.

Additionally, BF3 has a net dipole moment of zero due to this symmetry. However, BF3 often forms a bond with a fluoride ion, resulting in the formation of BF4−, which completes boron's octet and is more stable.

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Why do elements that make positive ions occur on the left side of the periodic table while those that make negative ions occur on the right?

Answers

Metals tend to lose electrons in order to attain an e-configuration isoelectronic with a noble gas; or gain stability in the form of a half or full outer subshell. Non metals gain electrons to gain an isoelcetronic noble gas structure.
Because on the right they want and gain electron while on left they give

Under which class of substitution reaction does this reaction appear to fall

Answers

This reaction is most likely to fall under SN2 because the thing called carbonication does not occur in SN1. The carbon forms a partial bond with the nucleophile during the intermediate phase and the leaving group. So for this question the reaction will fall under SN2.

Substitution reactions are characterized by the replacement of one or more hydrogen atoms in an alkane with different atoms or groups, without breaking carbon-carbon bonds. These reactions can demonstrate first order behavior and can also be involved in the process of preparing insoluble salts from soluble ones.

The subject of this discussion is a type of chemical reaction known as a substitution reaction. In this type of reaction, one or more of an alkane's hydrogen atoms are replaced by a differing atom or group of atoms, without altering any carbon-carbon bonds. An example of this can be found in the reaction between ethane and molecular chlorine.

The stoichiometry of a homogeneous reaction like this outlines the rates for the consumption of reactants and the formation of products. This process could potentially represent a unimolecular elementary reaction. Interestingly, the rate law derived from this compares to the rate law derived experimentally for the overall reaction, which exhibits first-order behavior.

Substitution reactions can also involve soluble salts to prepare insoluble salts. An example of this is seen with the covalent oxides of the transition elements reacting with hydroxides to form salts containing oxyanions of the transition elements.

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Which radioactive isotope is commonly used to date wooden artifacts?

Answers

Carbon 14 because it has an approximate half life of 5000 years. 

You're writing the instruction manual for a power saw, and you have to specify the maximum permissible length for an extension cord made from 18-gauge copper wire (diameter 1.0 mm). the saw draws 9.0 a and needs a minimum of 115 v across its motor when the outlet supplies 120 v.

Answers

12.7 meters You want a maximum voltage drop of 5 volts while carrying a load of 9.0 amperes. So using ohms law I=V/R and solving for R, gives R=V/I. So R = 5/9 = 0.5556 ohms. The formula for the resistance of a conductor is R = pL/A where p = resistivity 1.72x10^-8 L = length A = cross sectional area Since the wire has a diameter of 1.0 mm, its radius is 0.5 mm. So the cross section is pi r^2 = pi 0.5^2 = pi 0.25 = 0.785398163 mm^2 We need to convert that cross section to square meters, so we divide by 1 million, giving a result of 7.85398163x10^-7 m^2 The resistivity of copper is 1.72x10^-8 Now substitute the known values into the formula and solve for L R = pL/A 0.5556 = 1.72x10^-8 * L / 7.85398163 x 10^-7 0.5556 * 7.85398163 x 10^-7 = 1.72x10^-8 * L 0.5556 * 7.85398163 x 10^-7 / 1.72x10^-8 = L 25.4 = L So the longest length of 18 gauge wire you can use is 25.4 meters. But you need to take into account that the current is flowing to the saw and back from the saw through the extension cord, so you need to divide that length by 2, giving 12.7 meters.

Final answer:

To find the maximum permissible length for an 18-gauge extension cord for use with a power saw, one must calculate the voltage drop the cord can tolerate (5 V) and use the ohmic resistance per length unit of an 18-gauge wire to maintain at least 115 V for the saw's operation. This involves applying Ohm's Law and wire resistance specifications.

Explanation:

Finding the Maximum Permissible Length for an 18-Gauge Extension Cord:

To determine the maximum permissible length for an 18-gauge (1.0 mm diameter) copper wire extension cord for a power saw that draws 9.0 A and requires a minimum of 115 V to operate efficiently when the outlet supplies 120 V, we need to calculate the allowable voltage drop and then translate that into a length given the specific characteristics of the wire.

Voltage Drop Calculation:

The power saw can tolerate a voltage drop of 5 V (from 120 V to 115 V). Using Ohm's Law (V = IR), where V is the voltage, I is the current, and R is the resistance, we can determine the maximum resistance of the cord allowed to ensure the voltage at the saw does not drop below 115 V. First, we calculate the maximum allowable voltage drop per meter (or foot) of wire using the resistance per length unit for an 18-gauge copper wire.

Since an 18-gauge wire has specific resistance (often found in tables or the manufacturer's specifications), that value can be applied to determine how the calculated voltage drop correlates to a length. For example, if the resistance of an 18-gauge copper wire is 6.385 ohms per kilometer (0.006385 ohms per meter), and the power saw draws 9.0 A, the maximum permissible voltage drop of 5 V could be distributed across a specific length of wire without exceeding the minimum requirement of 115 V at the tool.

Conclusion:

Using the calculated resistance, the homeowner or electrician can then calculate the exact permissible length, ensuring the power saw operates within safe electrical parameters. It's essential to consult up-to-date tables for wire resistance to ensure accuracy.

How many molecules of n2 are in a 300.0 ml container at 780 mmhg and 135°c?

Answers

To solve for the number of molecules, we need to first find the number of moles. Assuming ideal gas, we use the formula:

n = PV / RT

where P is pressure = 780 mmHg, V is volume = 300 mL = 0.3 L, T is temperature = 135°C = 408.15 K, R is gas constant = 62.36367 L mmHg / mol K

n = (780 mmHg) (0.3 L) / (62.36367 L mmHg / mol K) (408.15 K)

n = 9.19 x 10^-3 mol

 

Using Avogadros number, we calculate the number of molecules.

molecules = 9.19 x 10^-3 mol * 6.022 x 10^23 molecules / mol

molecules = 5.54 x 10^21 molecules

[tex]\boxed{{5{.4 \times 1}}{{\text{0}}^{{\text{21}}}}\;{\text{molecules}}}[/tex] of nitrogen are present in a 300 mL container at 780 mm Hg and [tex]135\;^\circ{\text{C}}[/tex].

Further Explanation:

An ideal gas contains a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is just a theoretical concept and practically no such gas exists. But gases tend to behave almost ideally at a higher temperature and lower pressure.

Ideal gas law is considered as the equation of state for any hypothetical gas. Here, we assume nitrogen to be an ideal gas. So the expression for the ideal gas equation of nitrogen is as follows:

[tex]{\text{PV}} = {\text{nRT}}[/tex]                                    ......(1)

Here, P is the pressure of nitrogen.

V is the volume of nitrogen.

T is the absolute temperature of nitrogen.

n is the number of moles of nitrogen.

R is the universal gas constant.

Rearrange equation (1) to calculate the number of moles of nitrogen.

[tex]{\text{n}} = \frac{{{\text{PV}}}}{{{\text{RT}}}}[/tex]        ......(2)

Firstly, the temperature is to be converted into K. The conversion factor for this is,

[tex]{\text{0 }}^\circ {\text{C}} = {\text{273 K}}[/tex]

So the temperature of nitrogen is calculated as follows:

[tex]\begin{aligned}{\text{Temperature}}\left( {\text{K}}\right)&=\left({135 + 273} \right)\;{\text{K}}\\&=408\;{\text{K}}\\\end{aligned}[/tex]

Also, the volume is to be converted into L. The conversion factor for this is,

[tex]{\text{1 mL}}={\text{1}}{{\text{0}}^{ - 3}}{\text{ L}}[/tex]

So the volume of nitrogen is calculated as follows:

[tex]\begin{aligned}{\text{Volume}}\left({\text{L}}\right)&=\left({{\text{300 mL}}} \right)\left({\frac{{{{10}^{ - 3}}{\text{L}}}}{{{\text{1 mL}}}}}\right)\\&=0.3\;{\text{L}}\\\end{aligned}[/tex]

The pressure of nitrogen is 780 mm Hg.

The volume of nitrogen is 0.3 L.

The temperature of nitrogen is 408 K.

The universal gas constant is 62.36367 L mmHg/mol K.

Substitute these values in equation (2).

[tex]\begin{aligned}{\text{n}}&=\frac{{\left({{\text{780 mm Hg}}}\right)\left({{\text{0}}{\text{.3 L}}} \right)}}{{\left({{\text{62}}{\text{.3637 L mm Hg/K mol}}}\right)\left( {{\text{408 K}}}\right)}}\\&={\text{0}}{\text{.009196 mol}}\\&\approx {\text{0}}{\text{.009 mol}}\\\end{aligned}[/tex]

According to Avogadro law, one mole of any substance contains  [tex]{\text{6}}{\text{.022}}\times{\text{1}}{{\text{0}}^{{\text{23}}}}[/tex] molecules.

So the number of molecules of nitrogen is calculated as follows:

[tex]\begin{aligned}\text{Number of molecules of nitrogen}&=\left(0.009\text{ mol}\right)\left(\dfrac{6.022\times 10^{23}\text{molecules}}{1\text{mol}}\right)\\&=5.4198\times 10^{21}\text{ molecules}\\&\bf \approx5.4\times 10^{21}\text{\bf molecules} \end{aligned}[/tex]

Learn more:

1. Which statement is true for Boyle’s law: https://brainly.com/question/1158880

2. Calculation of volume of gas: https://brainly.com/question/3636135

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: ideal gas, pressure, volume, absolute temperature, equation of state, hypothetical, universal gas constant, moles of nitrogen, 780 mm Hg, pressure of nitrogen, 780 mm Hg, volume of nitrogen, 0.3 L, temperature of nitrogen, 408 K, universal gas constant, 62.36367 L mmHg/mol K.

how do the characteristics of electron microscopes make them studying cells

Answers

Electron microscopes allow scientists to magnify the cells further than with a normal microscope, and the glass is thinner, making it a lot more clear and easy to study.

If 2.32 g of ethanol reacts with 10.6 g of oxygen, how many moles of water are produced?

Answers

0.151 moles Ethanol is C2H6O, and the balanced reaction is C2H6O + 3O2 ==> 2CO2 + 3H2O Now calculate the molar mass of C2H6O. Start with the atomic weights. Atomic weight carbon = 12.0107 Atomic weight hydrogen = 1.00794 Atomic weight oxygen = 15.999 Molar mass C2H6O = 2 * 12.0107 + 6 * 1.00794 + 15.999 = 46.06804 g/mol Molar mass O2 = 2 * 15.999 = 31.998 g/mol Determine how many moles of each reactant is available. Moles C2H6O = 2.32 g / 46.06804 g/mol = 0.050360293 mol Moles O2 = 10.6 g / 31.998 g/mol = 0.331270704 mol Looking at the balanced equation and the number of moles of each reactant, it's obvious that the limiting reactant is C2H6O, and since each mole of C2H6O will produce 3 moles of H2O, then we just need to multiply the number of moles of C2H6O we have by 3, giving 0.050360293 mol * 3 = 0.151080879 moles And of course, round to 3 significant figures, giving 0.151 moles.

What is the ph of
a.35 m solution of sodium azide? the ka value for hydrazoic acid is 1.9?

Answers

Final answer:

Given the Ka value for hydrazoic acid and the concentration of sodium azide, calculating the precise pH would typically involve understanding the dissociation degree or specific details about the ionization in the solution to apply the proper formulas. Without complete data, an exact pH calculation isn't directly attainable.

Explanation:

The question asks about the pH of a 0.35 M solution of sodium azide. Sodium azide (NaN3) dissociates in water to produce azide ions (N3-) and sodium ions (Na+). The azide ions then react with water to generate hydrazoic acid (HN3) and hydroxide ions (OH-), which affects the pH of the solution.

Given the Ka (acid dissociation constant) value for hydrazoic acid (HN3) is 1.9, and the concentration of sodium azide is 0.35 M, we can calculate the pH by first determining the pKa using the formula pKa = -log(Ka), then using the Henderson-Hasselbalch equation to find the pH, which is used for buffer solutions or weak acid/conjugate base systems.

However, since the concentration of sodium azide is directly given and it's a base forming solution, direct use of the pKa and Ka values without the concentrations of the conjugate pairs in a specific equation elucidating hydroxide ion concentration followed by pH calculation might be needed. Yet, a complete calculation would require the dissociation degree or further specific context about the system to accurately determine the pH, which isn't directly provided.

Refer to the first three rows of the periodic table, what element has properties most similar to carbon?

Answers

silicone is most similar to carbon.
 hope this helps; and good luck.

Suppose a lab group reports a percent yield of sand of 105%. Is it really possible to collect more sand than was originally present? What is a possible explanation for the “extra” product? Do not consider calculation mistakes; think about the procedure used.

Answers

The maximum percent of yield should be 100%, so It wasn't possible to make a higher than 100% yield like 105% in this problem. If that happens, it will contradict the law of conservation of energy as you can't create mass.

The increased mass might be produced by impurities. One of the examples would be if you rinse the container and left some water. The water is not calculated as a substrate but will increase the results weight. 
There also possibilities that some gas in the air react and produce a solid/liquid material. If you don't weight the gas it would seem that the mass increased.

What would be the shape of a molecule with triple bond?

A) bent
B) linear
C) pyramidal
D) tetrahedral

Answers

The measured bond angles of these compounds (H2O 104.5º & NH3 107.3º) show that they are closer to being tetrahedral than trigonal or linear. Of course, it is the configuration of atoms (not electrons) that defines the the shape of a molecule, and in this sense ammonia is said to be pyramidal (not tetrahedral).

The triple bond is present in hydrocarbons alkyne.The shape of a molecule with triple bond is linear shape. Therefore, option B is correct.

What is triple bond ?

The triple bond contain three covalent bond. A covalent bond of bond order is 3, it is consisting of six electrons. Therefore, one pair in a sigma bond and the other pairs in pi bonds present in it.

Alkynes are hydrocarbons in which carbon-carbon triple bonds are present. Their general formula is CnH2n-2 for molecules with one triple bond. Atoms form triple bonds with one another by sharing three pairs of electrons.

Triple-bonded carbons are sp-hybridized, and they have linear shapes. And its bond angle is 180° to each other.

Thus, The shape of a molecule with triple bond is linear shape, option B is correct.

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if 4.1 L of gas at 22 degrees celsius is heated to 52 degrees celsius, what would the final volume be?

Answers

You can calculate the approximate final volume using the ideal gas law at constant pressure.

This is the reknown Law of Charles:

V / T = constant.

=> V1 / T1 = V2 / T2

Where V is the volume and T is the absolute temperature (Kelvin).

V2 = (V1 / T1) * T2

V1 = 4.1 liter
T1 = 22 + 273.15 K = 295.15K
T2 = 52 + 273.15 K = 325.15K

V2 = (4.1 liter / 295.15K)*325.15K = 4.6 liter

Answer: 4.6 liter


Which statement best describes the difference between a physical change and a chemical change?

A. A chemical change results in a new element being formed, and a physical change results in a new compound being formed.

B. A physical change is a change from one state of matter to another; a chemical change results in a new substance formed.
C. A physical change produces a new element, and a chemical change results in a bond breaking between atoms.

D. A chemical change does not result in a new substance being formed, whereas a physical change does.

Answers

The answer is A :) :) :) :) :) :)

The answer is A, hope it helps :P

The structure of methyl acrylate is shown here. indicate the type of hybridization for each numbered atom.

Answers

The structure of methyl acrylate is


Other Questions
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