Determine whether the underlined number describes a population parameter or a sample statistic. Explain your reasoning. Modifying Sixty minus five with underline of the 97 passengers aboard an airship survived an explosion.
Answers
Answer:
Step-by-step explanation:
Related Questions
What is (-7)^3 / (-7)^4 simplified? Can you walk me through the steps?
Answers
Answer:
(-7)∧-1
Step-by-step explanation:
(-7)^3 / (-7)^4
taking each and simplifing it
-7³ = -7 x -7 x -7
(-7)∧4 = -7 x -7 x -7 x -7
(-7)^3 / (-7)^4 = (-7 x -7 x -7 ) / ( -7 x -7 x -7 x -7) = 1/-7
1/-7 ( 1/ means raise to power -1)
1/-7 = (-7)∧-1
The rodriguez brother buys f boxes of frozen burger meat, each containing m slices of meat. Every week, the family eats b burgers. Write an equation in terms of f, m,, and b that represents the number of remaining burger meat,r, after 5 weeks
Answers
Answer:
[tex]r=f\times m-5b[/tex]
Step-by-step explanation:
Given:
Number of boxes of burger meat = [tex]f[/tex]
Number of slices of meat in each box = [tex]m[/tex]
Number of burgers the family eats each week = [tex]b[/tex]
Number of burger meat remaining = [tex]r[/tex]
To write: An equation in terms of [tex]f, m,\ and\ b[/tex] that represents the number of remaining burger meat, [tex]r[/tex], after 5 weeks.
Now, since each box contain 'm' slices.
Therefore, by unitary method, number of slices of meat in 'f' boxes is given as:
[tex]Total\ number\ of\ slices=f\times m[/tex]
Now, each week burger consumption = 'b'
So, 'b' slices of meat are eaten each week. Again by unitary method, the number of slices eaten in 5 weeks is given as:
[tex]\textrm{Number of slices eaten in 5 weeks}=5b[/tex]
Now, Slices remaining = Total number of slices - Number of slices eaten in 5 weeks.
Therefore, [tex]r=f\times m-5b[/tex]
Hence, the equation that represents the number of slices of burger meat remaining in terms of 'f', 'm', and 'b' is given as:
[tex]r=f\times m-5b[/tex]
Daisy is going 12 mph and Sally is going 8 mph if they where 60 miles apart how many hours would it take for them to meet up
Answers
Answer:
3 hours
Step-by-step explanation:
we know that
The speed is equal to divide the distance by the time
Let
s ----> the speed in mph
d -----> the distance in miles
t ----> the time in hours
x ----> distance traveled by Daisy to the meeting point
60-x ----> distance traveled by Sally to the meeting point
so
[tex]s=\frac{d}{t}[/tex]
Solve for d
[tex]d=st[/tex]
Distance traveled by Daisy to the meeting point
[tex]d=st[/tex]
we have
[tex]d=x\ mi\\s=12\ mph[/tex]
substitute
[tex]x=12t[/tex] ----> equation A
Distance traveled by Sally to the meeting point
[tex]d=st[/tex]
we have
[tex]d=(60-x)\ mi\\s=8\ mph[/tex]
substitute
[tex]60-x=8t[/tex] ----> equation B
substitute equation A in equation B
[tex]60-12t=8t[/tex]
solve for t
[tex]12t+8t=60\\20t=60\\t=3\ hours[/tex]
A pilot knows she descended 1,000 feet and traveled a diagonal distance of 18,000 feet.
What was the horizontal distance covered by the pilot?
A-17.9722 ft
B-18027.8 ft
C-16.000 ft
D-15.457 8 ft
Answers
The horizontal distance covered by pilot is 17,972.2 feet.
Step-by-step explanation:
Given,
Distance covered descending = 1000 feet
Diagonal distance = 18,000 feet
The horizontal distance will form a right triangle, therefore, we can find the horizontal distance by using pythagoras theorem.
Here,
a = 1000
b = horizontal distance
c = 18000
[tex]a^2+b^2=c^2\\(1000)^2+b^2=(18000)^2\\1000000+b^2=324000000\\b^2 = 324000000-1000000\\b^2=323000000[/tex]
Taking square root on both sides
[tex]\sqrt{b^2}=\sqrt{323000000}\\b=17972.2[/tex]
The horizontal distance covered by pilot is 17,972.2 feet.
Keywords: pyathoras theorem, square root
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Jennifer made 5 Liters of punch for her party. Her brother made another 750 milliliters if they combine the two batches how many 180 milliliters servings would they have would there be any punch left over if so how much
Answers
Answer:
Step-by-step explanation:
The total amount of punch that Jennifer made for her party is 5 Liters. Her brother made another 750 milliliters.
1000 milliliters = 1 liter
750 milliliters = 750/1000 = 0.75Liter
if they combine the two batches, the total amount made would be
5 + 0.75 = 5.75Liter
= 5.75 × 1000 = 5750 milliliters
The number of 180 milliliters servings would be
5750/180 = 31 servings
There would be leftovers of 170 milliliters
A box with a square base and open top must have a volume of 32,000cm^3. How do you find the dimensions of the box that minimize the amount of material used?
Answers
Answer:
Side of 40 and height of 20
Step-by-step explanation:
Let s be the side of the square base and h be the height of the box. Since the box volume is restricted to 32000 cubic centimeters we have the following equation:
[tex]V = hs^2 = 32000[/tex]
[tex]h = 32000/ s^2[/tex]
Assume that we cannot change the thickness, we can minimize the weight by minimizing the surface area of the tank
Base area with open top [tex]s^2[/tex]
Side area 4hs
Total surface area [tex]A = s^2 + 4hs[/tex]
We can substitute [tex]h = 32000/ s^2[/tex]
[tex]A = s^2 + 4s\frac{32000}{s^2}[/tex]
[tex]A = s^2 + 128000/s[/tex]
To find the minimum of this function, we can take the first derivative, and set it to 0
[tex]A' = 2s - 128000/s^2 = 0[/tex]
[tex]2s = 128000/s^2[/tex]
[tex]s^3 = 64000[/tex]
[tex]s = \sqrt[3]{64000} = 40[/tex]
[tex]h = 32000/ s^2 = 32000/ 40^2 = 20[/tex]
Suppose that the number of worker-hours required to distribute new telephone books to x% of the households in a certain rural community is given by the function W(x)=250x/(400−x). (a) What is the domain of the function W? (Give the domain in interval notation. If the answer includes more than one interval write the intervals separated by the "union" symbol, U.) (b) For what values of x does W(x) have a practical interpretation in this context? (c) How many worker-hours were required to distribute new telephone books to the first 70% of the households? (d) How many worker-hours were required to distribute new telephone books to the entire community? (e) What percentage of the households in the community had received new telephone books by the time 3 worker-hours had been expended?
Answers
Answer:
a) Domain = [tex](-\infty,400)\cup (400,\infty)[/tex]
b) [tex]x \in [0,100][/tex]
c) 53.03 worker hours
d) 83.33 worker hours
e) 83.33 worker hours
Step-by-step explanation:
We are given the following in the question:
[tex]W(x) = \dfrac{250x}{(400-x)}[/tex]
where W(x) is the number of worker-hours required to distribute new telephone books to x% of the households in a certain rural community.
a) Domain of function.
The domain is the all the possible values of x that the function can take.
Domain = [tex](-\infty,400)\cup (400,\infty)[/tex]
b) Values of x
Since x is a percentage in reference to context, it can only take value upto 100. Also it cannot take any negative value.
So domain n reference to context will be
[tex]x \in [0,100][/tex]
c) worker-hours were required to distribute new telephone books to the first 70% of the households
[tex]W(70) = \dfrac{250(70)}{(400-70)} = 53.03[/tex]
53.03 worker hours were required to distribute new telephone books to the first 70% of the households.
d) Worker hour for entire community
For entire community, x = 100
[tex]W(100) = \dfrac{250(100)}{(400-100)} = 83.33[/tex]
83.33 worker hours were required to distribute new telephone books to the entire households.
e) Percentage of the households in the community for 3 worker hours
[tex]3 = \dfrac{250x}{(400-x)}\\\\1200-3x = 250x\\253x = 1200\\\\x = \dfrac{1200}{253} = 4.74\%[/tex]
Thus, 4.74% of the households in the community had received new telephone books by the time 3 worker-hours had been expended.
Final answer:
The domain of the function W(x) is (-∞, 400) U (400, +∞). The values of x that have a practical interpretation in this context are in the interval [0, 100]. Approximately 53.03 worker-hours were required to distribute new telephone books to the first 70% of households, and approximately 83.33 worker-hours were required to distribute to the entire community. After 3 worker-hours, approximately 4.73% of the households had received new telephone books.
Explanation:
(a) The domain of the function W is the set of all possible values of x that make the function defined and meaningful. In this case, the function W(x) is defined except when the denominator 400-x is equal to zero. So, we need to find the values of x that make the denominator zero.
To do that, we solve the equation 400-x = 0, which gives x = 400.
Therefore, the domain of the function W is the set of all real numbers except x = 400. We can express this in interval notation as (-∞, 400) U (400, +∞).
(b) In this context, the function W(x) represents the number of worker-hours required to distribute new telephone books to x% of the households in the rural community. A practical interpretation is only meaningful when x represents a valid percentage, meaning that it is between 0% and 100%, inclusive. So, the values of x that have a practical interpretation in this context are in the interval [0, 100].
(c) To find the worker-hours required to distribute new telephone books to the first 70% of households, we substitute x = 70 into the function W(x). Evaluating the expression, we get: W(70) = 250(70) / (400 - 70) = 17500 / 330 = 53.03.
Therefore, approximately 53.03 worker-hours were required to distribute new telephone books to the first 70% of households.
(d) To find the worker-hours required to distribute new telephone books to the entire community, we substitute x = 100 into the function W(x). Evaluating the expression, we get: W(100) = 250(100) / (400 - 100) = 25000 / 300 = 83.33.
Therefore, approximately 83.33 worker-hours were required to distribute new telephone books to the entire community.
(e) To find the percentage of households that had received new telephone books after 3 worker-hours, we rearrange the function W(x) to solve for x. We have:
W(x) = 250x / (400 - x)
3 = 250x / (400 - x)
3(400 - x) = 250x
1200 - 3x = 250x
1200 = 253x
x = 1200 / 253 ≈ 4.73
Therefore, approximately 4.73% of the households in the community had received new telephone books after 3 worker-hours.
A junk box in your room contains a dozen old batteries, five of which are totally dead. You start picking batteries one at a time and testing them. Find the probability of each outcome.
Answers
Answer:
7/12 of a chance
Step-by-step explanation:
If you have 12 batteries and 5 are dead, 12 - 5 is 7, so there's going to be 7/12 of a chance.
Evaluate the expression x^3 - (3 + x)^2x 3 −(3+x) 2 x, cubed, minus, left parenthesis, 3, plus, x, right parenthesis, squared for x=4x=4x, equals, 4.
Answers
Answer:
15
Step-by-step explanation:
Put the given value of x where x is in the expression and do the arithmetic.
4^3 -(3 +4)^2 = 64 -49 = 15
The value of the expression for x=4 is 15.
Final answer:
The expression x³ - (3 + x)² for x = 4 simplifies to 64 - 49, resulting in a final answer of 15.
Explanation:
The student has asked to evaluate the expression x³ - (3 + x)² for x = 4. To do this, we will substitute x with 4 and simplify the expression step by step. First, calculate the value inside the parentheses: (3 + 4) = 7. Then, we square this value to get 7² = 49. After that, subtract the squared value from 4³ (which is 64), to get the final answer.
The final answer is 15
Shane's neighbor pledged $1.25 for every 0.5 miles that Shane swims and the charity swim-a-thon. If Shane swims 3 miles how much money would his neighbors donate
Answers
Answer:
7.5
Step-by-step explanation:
1.25/ (.5) = 2.5
2.5 x 3 = 7.5
Three red balls, 4 white balls, and 1 green ball are in a bag. A ball is drawn without replacement. What is the probability that 3 balls can be drawn without drawing the green ball?
Answers
Answer:
[tex]\frac{5}{8}[/tex]
Step-by-step explanation:
Three red balls, 4 white balls, and 1 green ball are in a bag. A ball is drawn without replacement.
total balls = 3 red + 4 white + 1 green = 8 balls
the number of balls that are not green is 7
pick 3 balls from 7 balls that are not green
[tex]nCr= \frac{n!}{r!(n-r)!}[/tex]
[tex]P(not \ green)=\frac{7C3}{8C3}[/tex]
[tex]7C3= \frac{7!}{3!(7-3)!}=35[/tex]
[tex]8C3= \frac{8!}{3!(8-3)!} =56[/tex]
[tex]P(3 \ balls \ drawn)=\frac{35}{56} =\frac{5}{8}[/tex]
Tell which measure of central tendency best describes the data. Time spent on Internet (min/day): 75 38 43 120 65 48 52 A. Mean B. Median C. Mode
Answers
Answer:
B. Median
Step-by-step explanation:
We have been given data about time spent on Internet (min/day). We are asked to determine the best measure of central tendency for the given data.
Data: 75, 38, 43, 120, 65, 48, 52,
We can see that our given data has a very large value outlier (120), so it will increase the mean.
There is no mode for the given data set as no value repeats.
We know that median is best measure for data set with large valued outliers because median is not affected by outliers.
Therefore, option B is the correct choice.
The measure of central tendency that best describes the data is B. Median.
Which measure of central tendency best describes the data on time spent on the Internet?Mean:
= (75 + 38 + 43 + 120 + 65 + 48 + 52) / 7
= 69.86
Median:
We arrange data in ascending order: 38, 43, 48, 52, 65, 75, 120. Since there are seven values, the median is the middle value: 52
Mode: There is no value that appears more than once in the data set.
Therefore, the measure of central tendency that best describes the data is B. Median.
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what is the value of x? pls help!
Answers
Answer:The procedure to use the find the value of x calculator is as follows:
Step 1: Enter the values in the divisor and the product field
Step 2: Now click the button “Solve” to get the output
Step 3: The dividend or the x value will be displayed in the output field
Step-by-step explanation: In algebra, it is easy to find the third value when two values are given. Generally, the algebraic expression should be any one of the forms such as addition, subtraction, multiplication, and division. To find the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to find the result.
Jacob and Ali want to run from one corner of a football field to the opposite corner. The rectangular football field is 50 yards wide and 120 yards long. Jacob runs around the perimeter of the field, while Ali runs in a straight line through the middle of the field. How many more yards does Jacob run than Ali?
Answers
Answer:
Jacob ran 40 yards more than Ali.
Step-by-step explanation:
Football field is in the shape of a rectangle having dimensions 120 yards × 50 yards
Since Jacob runs around the perimeter of the field from one corner to other corner, therefore, distance run by Jacob = [tex](\text{Length+width})[/tex]
Distance run by Jacob = 50 + 120 = 170 yards
Ali runs through the middle of the field diagonally on a straight line.
Therefore, distance covered by Ali = [tex]\sqrt{\text{length}^{2}+\text{width}^{2}}[/tex]
= [tex]\sqrt{(50)^{2}+(120)^{2}}[/tex]
= [tex]\sqrt{2500+14400}[/tex]
= [tex]\sqrt{16900}[/tex]
= 130 yards
Now difference between the distance covered by Jacob and Ali
= 170 - 130
= 40 yards
Therefore, Jacob ran 40 yards more than Ali.
A wheel on carmen's bike is 1.1 m in diameter. Carmen races the bicycle for 93m. How many times dose the wheel turn as the bicycle travels this distance
Answers
93÷1.1= 84.545454545
Answer:approximately 30 times
Step-by-step explanation:
The wheel on Carmen's bike circular in shape and has a diameter of 1.1 meter.
Radius = diameter/2 = 1.1/2 = 0.55 meter.
When the wheel completes one revolution, the distance covered is equal to the circumference of the wheel.
The formula for determining the circumference of the wheel is expressed as
Circumference = 2πr
Where π is a constant whose value is 3.14
Circumference = 2 × 3.14 × 0.55 = 3.454 metres.
Carmen races the bicycle for 93m. Therefore, the number of times that the wheel of the bicycle turns as it travels this distance would be
93 / 3.454 = 26.9 times
The number of question on a math test is represented (3x+1). The number of questions on the spelling test is represented by (x+12). Write an expression to find how many more questions were on the math test. Then evaluate the expression if the value x is 8
Answers
Answer:
Step-by-step explanation:
The number of questions on a math test is represented (3x+1). The number of questions on the spelling test is represented by (x+12).
An expression to find how many more questions were on the math test would be
= 3x + 1 - (x + 12)
= 3x + 1 - x - 12
= 3x - x + 1 - 12
= 2x - 11
When the value of x = 8, then the expression becomes
2× 8 - 11 = 16 - 11 = 5
Final answer:
To find how many more questions are on the math test compared to the spelling test, you subtract the spelling test expression from the math test expression. Simplifying this gives 2x - 11. Evaluating this expression for x = 8 shows there are 5 more questions on the math test.
Explanation:
The question asks you to write an expression to find out how many more questions are on the math test compared to the spelling test, and then evaluate this expression for x = 8.
Step 1: Write the expression
To find how many more questions are on the math test, you subtract the number of questions on the spelling test from the number of questions on the math test. Therefore, the expression is:
(3x + 1) - (x + 12)
Step 2: Simplify the expression
First, distribute the negative sign: 3x + 1 - x - 12. Simplify by combining like terms: 2x - 11. This simplified expression represents how many more questions are on the math test compared to the spelling test.
Step 3: Evaluate the expression for x = 8
Plug in x = 8 into the simplification, 2x - 11. So, you get: 2(8) - 11 = 16 - 11 = 5.
Therefore, there are 5 more questions on the math test than on the spelling test when x = 8.
help in anyway in this ixl
Answers
Answer:
Step-by-step explanation:
Triangle ABC is a right angle triangle.
From the given right angle triangle shown,
AB represents the hypotenuse of the right angle triangle.
With 45 degrees as the reference angle,
AC represents the adjacent side of the right angle triangle.
BC represents the opposite side of the right angle triangle.
To determine QR, we would apply trigonometric ratio
Sin θ = opposite side/hypotenuse side. Therefore,
Sin 45 = BC/6√2
√2/2 = BC/6√2
BC = √2/2 × 6√2
BC = 6
If radio station call letters must begin with either K or W and must include either two or three additional letters, how many different possibilities are there? There are different possibilities. (Simplify your answer.)
Answers
Answer:
Step-by-step explanation:
In a school, 3/4 of the students study a language. Of those who study a language, 3/5 study French. Find the ratio of students who study French to students who do not study French. Give your answer in its simplest form.
Answers
Answer: 9:11
Step-by-step explanation:
Let x be the total number of students.
If 3/4 of students study a language That mean 3x/4 students study a language.
Number of students that don't study a language becomes
x - 3x/4 = x/4.
and 3/5 of those who study language study French, that means 3x/4 * 3/5 of students study French.
This gives 3x/4 * 3/5 = 9x/20 Studying French.
Number of students that study language but do not study French becomes
3x/4 - 9x/20 = 6x/20
Total number of students that do not study French becomes
[total number of students not studying any language] + [total number of students studying a language but do not study French ]
Which becomes
x/4 + 6x/20 = 11x/20
Hence ratio of those that study French to those that do not study French Becomes
9x/20 : 11x/20
9:11.
Adrienne's annual take-home pay is $57,000. What is the maximum amount that she can spend per month paying off credit cards and loans and not be in danger of credit overload?
A. $950.00
B. $1187.50
C. $4750.00
D. $3800.00
Answers
Answer:
Option C. is correct.
Step-by-step explanation:
Given:
Adrienne's annual take-home pay = $57,000
To find:
The maximum amount that she can spend per month on paying off credit cards and loans and not be in danger of credit overload.
Solution:
Number of months in a year = 12
So, amount she can spend per month =
Annual pay of Adrienne / Number of months in a year = [tex]\frac{57000}{12} =\frac{28500}{6}=\frac{14250}{3}=4750[/tex]
So, option C. is correct.
Answer:
A. $950.00
Step-by-step explanation:
A p e x
. Solve the equation. 3/7x + 5 = 8 1 2/7 7 7 2/7 –7
Answers
Answer:
x= −5621/201
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
3 /7x+5 = 812/7772/7-7
3 /7x+5= 1/67+−7
3 /7x+5=( 1/67+-7)(Combine Like Terms)
3 /7x+5= −468 /67
3 /7x+5= −468/67
Step 2: Subtract 5 from both sides.
3 /7x+5−5=−468/67−5
3 /7x=−803/67
Step 3: Multiply both sides by 7/3.
( 7/3)*(3/7x)=(7/3)*(−803/67)
x= −5621/201
A salesperson at a car dealership has a salary of 900 dollars per week plus 3% commission on sales if a salesperson has sales of 72000$ in one week what was the salesperson paid that week
Answers
Answer:
Step-by-step explanation:
A salesperson at a car dealership has a salary of 900 dollars per week plus 3% commission on sales if a salesperson has sales of $72000 in one week, it means that the amount of commission that was received by the salesperson would be
3/100 × 72000 = 0.03 × 72000 = $2160
Therefore, the total amount of pay that the salesperson would receive for the week would be
900 + 2160 = $3060
11. A(-2,1), B(2,5), C(5,1) (round answers to the nearest tenth)
Perimeter___________
Area_______________
Answers
See the attached picture:
Players in any sport who are having great seasons, turning in performances that are much better than anyone might haveanticipated, often are pictured on the cover of Sports Illustrated. Frequently, their performances then faltersomewhat, leading some athletes to believe in a "Sports Illustrated jinx." Similarly, it is common for phenomenal rookies to have less stellar second seasons, the so-called "sophomore slump." While fans, athletes, and analysts have proposed many theories about what leads to such declines, a statistician might offer a simpler(statistical) explanation. Explain.
What would be a better explanation for the decrease in performance of the Sports Illustrated cover athlete?
A. People on the cover are usually there for outstanding performances. Because they are so far from the mean, the performance in the next year is likely to be closer to the mean.
B. The slope of the linear regression, predicting performance from years in the sport, must be negative because an athlete's performance always decreases over time. No matter how well an athlete performed one year, they must perform worse the next year.
C. People on the cover are usually considered the best of theyear, so naturally they reached the maximum level of athletic performance that year and it is impossible to improve upon that.
D. Once an athlete has made the cover of Sports Illustrated, they have reached their ultimate goal as an athlete and lack motivation to try the following year.
Answers
Answer:
I pick the reasoning of option A
Step-by-step explanation:
I like the reasoning given in B, however, there are many cases of Athletes that, after reaching the top, maintain supremacy and improve over the years, adapting to their old age. Usually speed and physical resistance are replaced by technique and experience in the case of the top athletes.
I dont like C and D argument too much because being the best in a sport doesnt mean either that you reach the maximum level possible (in many cases you can keep growing) or that you dont have more motivations. Many athletes are super competitive people and they try to improve themselves all the time to reach, and stay, in the top.
I choose option A as answer because people on the cover doesnt neccesarily mean that they are the absolute best. Their performance was way better than their usual performance, and that may be due to either real skill growth, heavy training or a lucky streak. If it is a lucky streak, it is natural for that player's performance to go down into more terrenal levels for him. On the other hand, If he trained heavily, then he might have big injuries on later seasons and his performance wont be able to keep up for long. Thats why 'surprises' (that also sell better due to be a novelty) tend to go downhill after they reach the cover of sports illustrated.
The decrease in performance after an athlete's phenomenal season could be due to a statistical phenomenon called regression to the mean. This principle suggests that if a variable (e.g., athletic performance) is extreme on its first measurement, it will tend to be closer to the average on its subsequent measurement, which could explain why some athletes have less stunning seasons after achieving outstanding performances.
Explanation:A better explanation for the decrease in performance of the Sports Illustrated cover athlete could be option A. People on the cover are usually highlighted for their outstanding performances, which are far from the mean. Due to a phenomenon called regression to the mean, it is likely that their performance in the next season would be closer to the mean (average).
Regression to the mean is a statistical concept that suggests that if a variable is extreme on its first measurement, it will tend to be closer to the average on its second measurement, and vice-versa.
This has nothing to do with a jinx, but rather with the statistical principle that performances, both good and bad, tend to cluster around the mean over time. So, outstanding performance is often followed by less exceptional performance, not necessarily because the player got worse, but because the original performance was likely above their true average.
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AHHHH HELP I WILL GIVE BRAINLY NO CAP NO CAP
Answers
Answer:
The answer to your question is letter A
Step-by-step explanation:
From the graph, we conclude that it is a vertical ellipse with center (0, 0).
Also from the graph, we calculate a and b
a = 11, a is the distance from the center to the vertical vertex
b= 9, b is the distance from the center to the horizontal vertex
Equation
[tex]\frac{x^{2}}{9^{2}} + \frac{y^{2}}{11^{2}} = 1[/tex]
Simplification
[tex]\frac{x^{2}}{81} + \frac{y^{2}}{111} = 1[/tex]
What is the 4-day SMA for the following closing prices: $56, $61, $50, $57, $60, $58, and $57.
Group of answer choices
$56, $61, $50, $57
$56, $57, $56.25
Answers
Answer:
In order to find the correct answer you must use finances and use algebraic equations . You may also have to use precalculus. There is a group of answer choices, its really difficult to find the answer without more instructions. I don't understand what answer your looking for. You may be able to find the answer using finances and other detailed measures. Try using graph paper and write down finances I'm trying my best to help you.
Step-by-step explanation:
finances Algebra Precalculus
$56, $57, $56.25 is the 4-day SMA for the following closing prices: $56, $61, $50, $57, $60, $58, and $57
What is Statistics?Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.
To calculate the 4-day SMA (Simple Moving Average)
We need to add up the closing prices for the last 4 days and divide the sum by 4.
We then move the window one day forward and repeat the process.
Using the given closing prices, we can calculate the 4-day SMA as follows:
Day 1: (56 + 61 + 50 + 57) / 4 = 56
Day 2: (61 + 50 + 57 + 60) / 4 = 57
Day 3: (50 + 57 + 60 + 58) / 4 = 56.25
Day 4: (57 + 60 + 58 + 57) / 4 = 58
The 4-day SMA for the given closing prices is: $56, $57, $56.25, $58.
Hence, $56, $57, $56.25 is the 4-day SMA for the following closing prices: $56, $61, $50, $57, $60, $58, and $57.
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A stadium has 10500 seats and 8 VIP boxes. The stadium is divided into 12 equal sections: 2 premium sections and 10 standard sections. A seat at the premium section costs $48 per game. A seat at the standard section costs $27 per game.
Answers
Answer:
1). 875 seats
2). 25 rows in each section
3). $8400
4). Saving of $360
5). 2105 tickets remained unsold
6). x = 16
Step-by-step explanation:
This question is incomplete; here is the complete question.
A stadium has 10,500 seats and 8 VIP boxes. The stadium is divided into 12 equal sections: 2 premium sections and 10 standard sections. A seat at the premium section costs $48 per game. A seat at the standard section costs $27 per game.
1. How many seats are there in each section?
2. If there are 35 seats in each row, how many rows are in each section?
3. If all the seats in the premium section are sold out for a game, how much will the stadium get from those ticket sales?
4. There are 50 games in each season. A season pass costs $2,040. A season pass holder can go to all the games and have a seat in the premium section. How much can a fan save by buying the season pass?
5. For the night game on Tuesday, 8,395 tickets were sold. How many tickets were left?
6. Write an equation using “x” and then solve the equation. Each VIP boxes can seat X people. If all the seats and VIP boxes are filled up, there are 10,628 audience in the stadium.
1). Number of seats in the stadium = 10500
Number of sections = 2 premium + 10 standard = 12
Number of seats in each section = [tex]\frac{10500}{12}=875[/tex]
2). If the number of seats in each row = 35
Then number of rows in each section = [tex]\frac{875}{35}=25[/tex]
3). Number of seats in 2 premium sections = 2×875 = 1750
Cost of 1750 seats at the rate of $48 per game = 1750 × 48 = $84000
4). Cost of one ticket in premium section = $48 per game
If the games planned in one season = 50
Then cost of the tickets = 48×50 = $2400
Cost of the season ticket = $2040
Saving on the purchase of one season ticket = 2400 - 2040 = $360
5). For a night game number of tickets sold = 8395
Total number of seats in the stadium = 10500
Tickets remained unsold = 10500 - 8395 = 2105
6). Number of seats in each VIP box = x
Number of VIP boxes = 8
Number of seats in 8 VIP boxes = 8x
Total number of tickets sold = 10500 + 8x
Total number of audience in the stadium = 10628
Then the equation will be
8x + 10500 = 10628
8x = 10628 - 10500
x = [tex]\frac{128}{8}=16[/tex]
The subject of this question is Mathematics, specifically dealing with seating capacity and pricing in a stadium. To determine the maximum seating capacity of the stadium, add up the number of seats in each section. To calculate the total revenue from a single game, multiply the number of seats in each section by the corresponding ticket price, and then sum up the results.
Explanation:The subject of this question is Mathematics, specifically dealing with the concepts of seating capacity and pricing in a stadium.
To determine the maximum seating capacity of the stadium, we add up the number of seats in each section: 2 premium sections with 48 seats each, 10 standard sections with 900 seats each, and 8 VIP boxes with a capacity of 12 seats each. This gives us a total of 1116 seats.
To calculate the total revenue from a single game, we multiply the number of seats in each section by the corresponding ticket price, and then sum up the results. For the premium sections, the revenue is $48 per seat multiplied by 96 seats, and for the standard sections, the revenue is $27 per seat multiplied by 900 seats. Adding up these two amounts gives us the total revenue from a single game.
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Part A: In what way is the algorithmic process the same for integers and polynomials?
Part B: In what way is the algorithmic process different for integers and polynomials?
Select one answer for Part A and one answer for Part B.
A: Polynomial long division and integer division are not the same at all.
A: When using polynomial long division, the same process of divide, multiply, and bring down applies, just like when dividing integers.
A: When using polynomial long division, the multiply, subtract, and bring down portion applies just like when dividing integers.
B: When using polynomial long division, polynomial terms are added, not subtracted like in integer division.
A: When using polynomial long division, the same process of divide, multiply, subtract, bring down applies, just like when dividing integers.
B: Polynomial long division uses powers of variables instead of place values used when dividing integers, and only the first term of the divisor is considered in the divide step.
B: Polynomial long division treats remainders differently than they are treated in integer long division.
B: Polynomial long division and integer division are completely the same.
Answers
Answer:
A: When using polynomial long division, the multiply, subtract, and bring down portion applies just like when dividing integers
B: Polynomial long division uses powers of variables instead of place values used when dividing integers, and only the first term of the divisor is considered in the divide step
Step-by-step explanation:
The above answers are pretty self-explanatory.
I find polynomial division easier, because the "trial division" step uses only the highest-degree terms, so always gives the exact result you need for the quotient. (There's no "guess and check" as with integer long division.) Powers of the variable take the place of powers of 10 (or whatever number base you're using) in integer long division.
__
For integer long division, the steps are ...
Divide the leading portion of the dividend by the divisor to determine the quotient digit.Multiply the divisor by the quotient digit and subtract the result from the dividend, paying attention to place value. If the quotient digit is too large (the difference is negative), choose a smaller value and repeat.Append the next succeeding digit of the dividend to the difference from the above step to form the new dividend and repeat from the first step until the desired quotient precision is achieved.If all given digits of the dividend have been exhausted, append zero to form the new dividend.Any remainder can be expressed as a fraction with the divisor as its denominator. (That fraction is added to the rest of the quotient.)For polynomial long division, the steps are similar.
Divide the highest degree term of the dividend by the highest-degree term of the divisor to form the next term of the quotient.Multiply the quotient term just found by the divisor and subtract the result from the dividend to obtain the new dividend.Repeat from the first step until the degree of the dividend is less than that of the divisor. If this remainder is non-zero, it can be expressed as a fraction with the divisor as its denominator. (That fraction is added to the rest of the quotient.)_____
Examples of each are shown in the attachments.
In a mid-size company, the distribution of the number of phone calls answered each day by each of the 12 receptionists is bell-shaped and has a mean of 37 and a standard deviation of 9. Using the empirical rule (as presented in the book), what is the approximate percentage of daily phone calls numbering between 28 and 46?
Answers
Answer:
0.6826
Step-by-step explanation:
Mean(μ) = 37
Standard deviation (σ) = 9
P(28 < x < 46) = ???
Using normal distribution
Z = (x - μ)/σ
For x = 28
Z = (28 - 37)/9
Z = -9/9
Z = -1
For x = 46
Z = (46 - 37)/9
Z = 9/9
Z = 1
We now have
P(-1 < Z < 1)
= P(Z < 1) - P(Z < -1)
From the table, Z = 1 = 0.3413
φ(Z) = 0.3413
Recall that
When Z is positive, P(x<a) = 0.5 +φ(Z)
P(Z<1)= 0.5 + 0.3413
= 0.8413
When Z is negative, P(x<a) = 0.5 - φ(Z)
P(Z< -1)= 0.5 - 0.3413
= 0.1587
We now have
0.8413 - 0.1587
= 0.6826
Kevin invested $8,000 for one year at a simple annual interest rate of 6 percent and invested $10,000 for one year at an annual interest rate of 8 percent compounded semiannually. What is the total amount of interest that Kevin earned on the two investments?A. $880
B. $1,088
C. $1,253
D. $1,280
E. $1,296
Answers
Answer:
Total interest =$1296
Step-by-step explanation:
Kevin invested $8,000 for one year at a simple annual interest rate of 6 percent
Simple interest = [tex]\frac{Pnr}{100}[/tex]
P=8000, n=1 year and r=6
interest = [tex]\frac{8000(1)(6)}{100}[/tex]
Interest = 480 dollars
[tex]compound \ interest =P(1+\frac{r}{n} )^{nt}-p[/tex]
P= 10000, t=1, r=8%=0.08, n=2 for semiannually
[tex]compound \ interest =10000(1+\frac{0.08}{2} )^{2(1)}-10000[/tex]
Interest = 10816- 10000=816
Total interest = [tex]480+816=1296[/tex]