David wishes to accumulate $1 million by the end of 20 years by making equal annual end-of-year deposits over the next 20 years. if david can earn 10 percent on his investments, how much must he deposit at the end of each year? $50,000 $17,460 $14,900 $117,453

Answers

Answer 1
The formula of the future value of an annuity ordinary is
Fv=pmt [(1+r)^(n)-1)÷r]
Fv accumulated amount 1000000
PMT annual payment ?
R interest rate. 0.1
N time 20 years
Solve the formula for PMT
PMT=FV÷[(1+r)^(n)-1)÷r]
PMT=1,000,000÷(((1+0.1)^(20)−1)÷(0.1))
PMT=17,459.62 round your answer
PMT=17460
Answer 2

David must deposit approximately $16,150.01 at the end of each year to accumulate $1 million by the end of 20 years at a 10 percent interest rate.

To calculate the equal annual end-of-year deposits that David must make to accumulate $1 million in 20 years at a 10 percent interest rate, we can use the formula for the future value of an ordinary annuity.

The formula for the future value of an ordinary annuity is given by:

[tex]FV = P * ((1 + r)^n - 1) / r[/tex]

where:

FV is the future value of the annuity (the desired $1 million in this case)

P is the annual deposit (what we need to find)

r is the annual interest rate (10% or 0.10 as a decimal)

n is the number of years (20 years in this case)

Substituting the known values:

[tex]$1,000,000 = P * ((1 + 0.10)^{20} - 1) / 0.10[/tex]

Now, we can solve for P:

$1,000,000 = P * (6.1917364224) / 0.10

$1,000,000 = P * 61.917364224

P = $1,000,000 / 61.917364224

P ≈ $16,150.01

So, David must deposit approximately $16,150.01 at the end of each year to accumulate $1 million by the end of 20 years at a 10 percent interest rate.

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Related Questions

Write the quadratic function in the form g(x)= a (x-h)^2 +k . Then, give the vertex of its graph. g(x)=3x^2+30x+72
Writing in the form specified: g(x)= ___
Vertex:___

Answers

so hmmm as you may know by now...   [tex]\bf \begin{array}{cccccllllll} {{ a}}^2& + &2{{ a}}{{ b}}&+&{{ b}}^2\\ \downarrow && &&\downarrow \\ {{ a}}&& &&{{ b}}\\ &\to &({{ a}} + {{ b}})^2&\leftarrow \end{array}\qquad % perfect square trinomial, negative middle term \begin{array}{cccccllllll} {{ a}}^2& - &2{{ a}}{{ b}}&+&{{ b}}^2\\ \downarrow && &&\downarrow \\ {{ a}}&& &&{{ b}}\\ &\to &({{ a}} - {{ b}})^2&\leftarrow \end{array}[/tex]

is a perfect square trinomial

now, let's take a closer look at the middle guy
is just 2 * guy on the left * guy on the right
so the middle term is just the product of the  two terms of the binomial, without the exponent, or square rooted, and 2

alrite... that said.... now let's do some grouping

[tex]\bf g(x)=3x^2+30x+72\implies g(x)=(3x^2+30x)+72 \\\\\\ g(x)=3(x^2+10x)+72\implies g(x)=3(x^2+10x+\boxed{?}^2)+72[/tex]

so hmm we're missing the guy on the right there... who may that be?

well, we know the middle term is 10x, wait a minute, 10x is just 2 * 5 * x

so, if the guy on the left is "x", the other guy must be "5", 2*5*x = 10x

now, what we do is, we add 5²

however, bear in mind that, all we're doing is, borrowing from our very good friend Mr Zero, 0

so, if we add 5², we also have to subtract 5², so +5² - 5²

let's do so

[tex]\bf g(x)=3(x^2+10x)+72\implies g(x)=3(x^2+10x\boxed{+5^2-5^2})+72 \\\\\\ \textit{let's take out the negative from the group} \\\\\\ g(x)=3(x^2+10x+5^2)+\boxed{3(-5^2)}+72 \\\\\\ g(x)=3(x^2+10x+5^2)-75+72\implies g(x)=3(x+5)^2-3 \\\\\\ g(x)=3[x-(-5)]^2-3[/tex]

[tex]\bf \qquad \textit{parabola vertex form}\\\\ \begin{array}{llll} y=a(x-{{ h}})^2+{{ k}} \end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\ -------------------------------\\\\ \begin{array}{lcclll} g(x)=3[x-&(-5)]^2&-3\\ &\uparrow &\uparrow \\ &h&k \end{array}[/tex]

An object is dropped off a building that us 144 feet tall. After how many seconds does the object hit the ground? (s= 16t^2)

Answers

Given 
s=16t^2 
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release

Here we're given
s=144 feet
=>
s=144=16t^2 
=> 
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.

Answer:

After 3 seconds the object hit the ground.

Step-by-step explanation:

An object is dropped off a building that us 144 feet tall. After how many seconds does the object hit the ground.

Given that displacement, s = 16t²

To reach ground displacement should be 144 feet.

That is

            s = 16t² = 144

                      t² = 9

                       t = 3 seconds.

After 3 seconds the object hit the ground.

What is the inverse of the function below? F(x) = x - 6

Answers

To compute the inverse function of F(x) you simply have to get how argument x depends of value F(x).
F(x)=x-6
Inverse function:
x = F(x)+6
To show that there are different mathematical objects just use e.g F(y)
F(y)=y+6 

Answer:

f(x)=x+6

Step-by-step explanation:

its the exact opposite of the answer, so if it was x-6 then the inverse would be x+6

How do I answer this question?

Answers

see attached picture for steps and answer

Can someone please solve this ASAP?

Answers

surface area = 5ab +5bh

a = 4

b=7

h=18

5*4*7 = 140

5*7*18 = 630

630+140 = 770 square meters


If using spss, what is the exact likelihood of obtaining a t-test value at least as extreme or as close to the one that was actually observed, assuming that the null hypothesis is true

Answers

Supposing that the null hypothesis is true, the precise possibility of obtaining a t-test value at least as extreme or as ear to the one that was actually observed was 0.1%. This value can be found in the “Independent Samples t-test” table in the SPSS output, where the exact p value is reported as 0.001. If the null hypothesis is assumed to be true, then statistically noteworthy result should be highly improbable. The rejection of the null hypothesis implies that the correct hypothesis lies in the logical complement of the null hypothesis.

To add, used for non-batched and logical batched statistical analysis, SPSS Statistics was a software package for that specific purpose.

Based on the historical record what is the empirical probability that the city will be hit by a tornado

Answers

25.875% Chance of the city being hit by a tornado.

2^-1 ∙ 2^-4 is what?

Answers

1/2 . 1/16 = 1/32

When the power is minus just flip the number and make it denominator and make the power positive
The rule for multiplying similar bases with exponents...

(a^b)(a^c)=a^(b+c)

In this case:

(2^-1)(2^-4)  

2^(-1-4)

2^-5  which is equal to:

1/(2^5)

1/32

Which of the following is a polynomial with roots negative square root of 5, square root of 5, and −3?
x^3 − 2x^2 − 3x + 6
x^3 + 2x^2 − 3x − 6
x^3 − 3x^2 − 5x + 15
x^3 + 3x^2 − 5x − 15

Answers

If the roots are -sqrt(5), sqrt(5), and -3, then the three factors of the polynomial are: (x + sqrt(5)), (x - sqrt(5)), and (x+3) Let's multiply the first two factors together. (x + sqrt(5)) * (x - sqrt(5)) = x^2 - 5 Let's multiply this by the third factor (x+3). (x^2 - 5) * (x+3) = x^3 + 3x^2 -5x - 15 The correct answer is the last polynomial in the list of choices above.

Can segments with lengths of 36, 48, and 60 form a triangle? If so, would the triangle be acute, right, or obtuse?

Answers

Yes, because by the triangle inequality, a triangle can be formed from three segments of which the sum of the lengths of the two shorter ones exceed the longest segment.

Here we have 36+48=84 > 60, so the three segments form a triangle.

Since the ratio of the sides are 36 : 48 : 60 form the ratio of 3:4:5, which is exactly the ratio of a right triangle, we conclude that the triangle is a right triangle.
Final answer:

Segments with lengths of 36,48 and 60 can form a triangle. By employing the Pythagorean Theorem, we find that this is a right triangle as the lengths adhere to the theorem.

Explanation:

The question asks if segments with lengths of 36, 48, and 60 can form a triangle, and if so, the type of the triangle. Yes, these segments can form a triangle. To classify the triangle as obtuse, right or acute, we use the Pythagorean Theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. This can be written as c^2 = a^2 + b^2. Substituting our values: 60^2 equals to 36^2+48^2 (3600 = 1296+2304). Since both sides of the equation are equal, we get the conclusion that this is a right triangle.

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G study find the exact value of each of the remaining trigonometric functions cos theta=4/5 270< theta

Answers

This will be a 4th quadrant 3,4,5 triangle.
Sin = -3/5
Tan = -3/4
Final answer:

Given that cos theta is 4/5 within the 270 to 360-degree range, sin(theta) is -3/5, tan(theta) is -3/4, sec(theta) is 5/4, csc(theta) is -5/3, and cot(theta) is -4/3.

Explanation:

The question indicates that we are dealing with trigonometry and specifically asks for the remaining trigonometric functions given that cos theta = 4/5 and theta is in the range of 270o to 360o.

This implies that theta is in the fourth quadrant where cosine is positive, and the other trigonometric functions can have different signs.

Since we have the cosine of theta, we can use the Pythagorean identity to find the sine of theta. The identity states that in2(theta) + cos2(theta) = 1.

Plugging in the given cosine value, we have:

sin2(theta) + (4/5)2 = 1
sin2(theta) = 1 - 16/25
sin2(theta) = 9/25
sin(theta) = ±√(9/25) = ±3/5

However, since theta is in the fourth quadrant, the sine is negative, and therefore we find:

sin(theta) = -3/5

For the tangent of theta, we use the definition tan(theta) = sin(theta)/cos(theta), which yields:

tan(theta) = (-3/5) / (4/5) = -3/4

The values of the other three trigonometric functions (secant, cosecant, and cotangent) are the reciprocals of the three we just calculated:

sec(theta) = 1/cos(theta) = 5/4
csc(theta) = 1/sin(theta) = -5/3
cot(theta) = 1/tan(theta) = -4/3

A boat takes 4 hours to go 20 miles upstream.It can go 32 miles downstream in same time.Find the rate of the current and the rate of the boat in still water.

Answers

recall your d = rt, distance = rate * time.

now, if the boat has a speed of say "b", and the current has a speed of say "c", when the boat is going upstream, is not really going "b" fast, is going " b - c " fast, because the current is eroding speed from it, going upwards.

And when the boat is going downstream, is not going "b" fast either, because the current is now adding to speed to it, so is really going " b + c " fast.

The time it took one way, is the same time it took back, 4 hours each way.

thus

[tex]\bf \begin{array}{lccclll} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{t}\\ &------&------&------\\ Upstream&20&b-c&4\\ Downstream&32&b+c&4 \end{array} \\\\\\ \begin{cases} 20=4(b-c)\implies \frac{20}{4}=b-c\implies 5+c=\boxed{b}\\ 32=4(b+c)\implies \frac{32}{4}=b+c\implies 8=b+c\\ --------------------\\ 8=\left(\boxed{5+c} \right)+c \end{cases} \\\\\\ 8=5+2c\implies 3=2c\implies \cfrac{3}{2}=c\implies 1\frac{1}{2}=c[/tex]

what's the speed of the boat?  well, 5 + c = b.

a culture started with 6,000 bacteria. After 4 hours, it grew to 6,600 bacteria. Predict how many bacteria will be present after 10 hours. round your answer to the nearest whole number.

Answers

P = 6,600  

A = 6,000  

t = 4  

k = ?  


6600 = 6000e^(4k)  

6600/6000 = e^(4k)  

1.1 = e^(4k)  


Take the natural log of both sides.  


ln 1.1 = 4k ln e (remember that ln e = 1)  

ln 1.1 = 4k  

(ln 1.1) / 4 = k  

k = 0.0238  


Bacteria after 10 hours.  

P = 6000e^(0.0238*10)  

= 6000e^0.238  

= 7612  


Therefore, the bacteria will grow to 7612 after 10 hours.

ΔABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C?

Answers

41*41 = 1681
40*40 = 1600
9* 9 = 81
so a^2 = b^2 + c^2
1681 = 1600 + 81
1681 = 1681 ...it's right triangle

CA = 41 = Hypo.
cosC = Adj / Hypo
cosC = BC / CA = 40/41

answer
cosC = 40/41

Answer:

The correct answer is

C 40/41

Step-by-step explanation:

What are the spherical coordinates of the point whose rectangular coordinates are (4,1,4)?

Answers

Final answer:

The spherical coordinates for the given rectangular coordinates (4,1,4) can be calculated using formulas for the transformation. They approximately yield (sqrt(33), 0.505, 1.540).

Explanation:

In mathematics, we can convert rectangular coordinates to spherical coordinates using given formulas. Here, we have the rectangular coordinates (4,1,4). The transformation from rectangular to spherical involves three-step calculations:

First, calculate the radial coordinate, r, which is the distance from the origin to the point. It is given by r = sqrt(x^2 + y^2 + z^2).Second, find the polar angle, theta, measured relative to the vertical z-axis. It is given by cos(theta) = z/r.Lastly, find the azimuthal angle, phi, measured relative to the x-axis. It is given by cos(phi) = x/(r*sin(theta)).

Applying the formulas, we get: r = sqrt(4^2 + 1^2 + 4^2) = sqrt(33), theta = cos^-1(4/sqrt(33)) which is approximately 0.505, and phi = cos^-1(4/sqrt(33)*sin(0.505)) which is approximately 1.540.

So, the spherical coordinates of the point whose rectangular coordinates are (4,1,4) are approximately (sqrt(33), 0.505, 1.540).

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In a glide reflection, what comes first and what comes second?
first the glide, and second another glide
first the glide, and second a reflection
first the reflection, and second another reflection
first the reflection, and second a glide

Answers

First the glide, and second a reflection
Final answer:

In a glide reflection, the reflection comes first and the glide comes second.

Explanation:

In a glide reflection, first the reflection is applied, and second a glide is performed. The reflection is a transformation that flips the shape across a line of reflection, while the glide is a transformation that slides the shape along a vector. The combination of the reflection and glide creates a glide reflection.

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a star is 3.4 light years from earth. if 1 light years is 5.87×10^12 mi, how many miles from earth is the star?

Answers

You just multiply these two.

3.4 * 5.87х10^12 miles

In a case whereby a star is 3.4 light years from earth. if 1 light years is 5.87×10^12 mi, the number of miles from earth the star is can be expressed as [tex]3.4 * 5.87 * 10^12 miles[/tex]

How can the number of miles be calculated?

Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation.

Given that  star=3.4 light years from earth

1 light years= [tex]5.87*10x^{12} miles[/tex]

The number of miles from earth is

[tex]3.4 * 5.87 *10^{12} miles\\\\=3.4 * 5.87 * 10^12 miles[/tex]

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how do write an equation to represent a real world situation?

Answers

You can write about cars. Like for example, Cydney wants to buy a car but doesnt know which one to buy. One of them costs ... and the other costs... or you can write about houses. You can write about anything if you think about, you just need to make sure it looks and sounds real.

If there are 400 cubic centimeters of a chemical in 1 liter of solution, how many cubic centimeters of water must be added to dilute it to a 25% solution?

Answers

keeping in mind that, in 1 liter, there are 1000 cm³, and that the concentration amount of the chemical for say 25% will be 0.25 of whatever the quantity is, so... we convert the percentage amounts to decimal formats.

[tex]\bf \begin{array}{lccclll} &\stackrel{cm^3}{amount}&\stackrel{\textit{\% of chemical}}{concentration}&\stackrel{total~amount}{concentration}\\ &------&------&------\\ solution&1000&0.4&400\\ water&x&0&0x\\ ------&------&------&------\\ mixture&y&0.25&0.25y \end{array}[/tex]

so.. whatever "x" and "y" are, we know that 1000 + x = y.

and that 400 + 0x = 0.25y.

thus then

[tex]\bf \begin{cases} 1000+x=\boxed{y}\\ 400+0x=0.25y\\ 400=0.25y\\ ----------\\ 400=0.25\left( \boxed{1000+x} \right) \end{cases} \\\\\\ 400=250+0.25x\implies 150=0.25x\implies \cfrac{150}{0.25}=x\implies 600=x[/tex]

Peter decides to mix grades of gasoline in his truck. He puts in 11 gallons of regular and 7 gallons of premium for a total cost of $76.99. If premium gasoline costs $0.25 more per gallon than regular, what was the price of each grade of gasoline?

Answers

11r + 7p = 76.99
p = r + 0.25

11r + 7(r + 0.25) = 76.99
11r + 7r + 1.75 = 76.99
18r = 76.99 - 1.75
18r = 75.24
r = 75.24/18
r = 4.18 <=== regular : $ 4.18 per gallon

p = r + 0.25
p = 4.18 + 0.25
p = 4.43 <=== premium : $ 4.43 per gallon

Final answer:

Peter bought regular and premium gasoline at $4.18 and $4.43 per gallon respectively, after solving a system of equations based on the total gallons and cost.

Explanation:

We are given a problem where Peter mixes two grades of gasoline—regular and premium—with premium costing $0.25 more than regular. To solve this, we can set up a system of equations representing the cost of each type of gasoline and the total cost.

Let the cost per gallon of regular gasoline be r, and thus premium will be r + $0.25 as it is $0.25 more expensive. Peter buys 11 gallons of regular and 7 gallons of premium, spending a total of $76.99. So, we have two equations:

11r + 7(r + $0.25) = $76.99r = regualar gasoline price per gallon

Simplifying the first equation:

11r + 7r + $1.75 = $76.99

18r + $1.75 = $76.99

18r = $76.99 - $1.75

18r = $75.24

r = $75.24 / 18

r = $4.18

So the regular gasoline price per gallon is $4.18 and the premium gasoline price per gallon is $4.18 + $0.25 = $4.43.

What is the area of a parallelogram with a base of 20 inches and an altitude of 8 inches?

Answers

140 i think think think or 160

The area of a parallelogram with a base of 20inches and an altitude of 8 inches is 160 inches square.

What is a parallelogram in math?

A parallelogram is a quadrilateral with opposite sides parallel (and therefore opposite angles identical). A quadrilateral with equal sides is called a rhombus, and a parallelogram whose angles are all right angles is referred to as a rectangle.

Conclusion: The opposite sides are equal in length and the opposite angles are identical in degree. To find the area, multiply the base by the height. The formula is: A = B * H where B is the base, H is the height, and * means multiply.

A = base * altitude

A = 20 * 8

A = 160 inches square.

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Raphael paid 636 for camera during a 60% off sale with the cameras regular price

Answers

Your question needs some rewording.  How does this sound?  "Raphael paid $636 for camera during a 60% off sale.  The camera's regular price is x.  Find this price."

If the price is 60% lower than usual, Raphael is paying only (100% - 60%), or 40%, for the camera.

Thus, 0.40x = $636.  Divide both sides of this eq'n by 0.40 to find the original price of the camera.

x = $636/0.40 = ?

Two pairs of shoes and four pairs of socks cost $131, and three pairs of shoes and five pairs of socks cost $190. Find the cost of a pair of socks.

Answers

s = shoes
x = socks

 3( 2s + 4x = 131) ------>  6s + 12x = 393
-2( 3s + 5x = 190) ------>-6s - 10x = -380

(2x = 13)/ 2

x = 6.5

A pair of socks is equal to $6. 50

Hope this helps :)
Please give brainliest

The cost of a pair of socks would be $6.50

A $28,000 car loan is used to purchase a new car. The loan is for 6 years and has a 5.75% APR. Use the amortization formula to determine the amount of the monthly payments.

Answers

[tex]\bf \qquad \qquad \textit{Amortized Loan Value} \\\\ pymt=P\left[ \cfrac{\frac{r}{n}}{1-\left( 1+ \frac{r}{n}\right)^{-nt}} \right][/tex]

[tex]\bf \qquad \begin{cases} P= \begin{array}{llll} \textit{original amount}\\ \end{array}\to & \begin{array}{llll} 28,000 \end{array}\\ pymt=\textit{periodic payments}\\ r=rate\to 5.75\%\to \frac{5.75}{100}\to &0.0575\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{payments are monthly, thus} \end{array}\to &12\\ t=years\to &6 \end{cases} \\\\\\ pymt=28000\left[ \cfrac{\frac{0.0575}{12}}{1-\left( 1+ \frac{0.0575}{12}\right)^{-12\cdot 6}} \right][/tex]

“the sum of eight and twice w”

Answers

8+2w
Sum is +
twice w=2w
Sum of 8 and 2w
8+2w
hope this helps:)
please mark thanks and brainliest:)

Answer:

the expression is [tex]8+2w[/tex]

Step-by-step explanation:

WE need to write the expression for the given statement

“the sum of eight and twice w”

Expression represents the terms that contains variables and operations. the variable we use for the expression is 'w'

Difference represents the subtraction operation.

Sum represents the addition operation.

twice 'w' means 2 times w that is 2w

the sum of 8 and 2w

For sum we use '+'

so ,the expression becomes [tex]8+2w[/tex]

A pilot can travel 540 miles with the wind in the same amount of time as 380 miles against the wind. Find the speed of the wind if the pilots speed in still air is 230 miles per hour.

Answers

t=d/v

540/(230+w)=380/(230-w)

540(230-w)=380(230+w)

124200-540w=87400+380w

124200-920w=87400

-920w=-36800

w=40

So the wind speed is 40 miles per hour.

A road crew spread 1 1/3 tons of gravel evenly over 8 feet of road.how many tons of gravel did they spread on each foot of road?

Answers

[tex]\bf 1\frac{1}{3}\div 8\implies \cfrac{1\frac{1}{3}}{8}\implies \cfrac{\frac{1\cdot 3+1}{3}}{\frac{8}{1}}\implies \cfrac{\frac{4}{3}}{\frac{8}{1}}\implies \cfrac{4}{3}\cdot \cfrac{1}{8}\implies \cfrac{4}{24}\implies \cfrac{1}{6}[/tex]

What are the counting numbers in base 6

Answers

In the base 6 number system, we would only use numerals from 0 to 5. The idea of base 6 is just like the normal base 10 system, however instead of using the numerals from 0 to 9, we use numerals from 0 to 5. And instead of having a ones digit, a tens digit, a hundreds digit and so on, we use a ones digit, a sixes digit, a thirty-sixes digit, and so on. Therefore in base 6, the number 321 means 1  one plus 2 sixes plus 3 thirty-sixes, or 121. So to count until 15 for example, we  would need:

 

Base 6                                                                   Base 10

 

1                                                                                  1   

2                                                                                  2

3                                                                                  3

4                                                                                  4

5                                                                                  5

10  (1 six plus 0 ones)                                                 6

11  (1 six plus 1 one)                                                   7

12  (1 six plus 2 ones)                                                 8

13                                                                                9

14                                                                              10

15                                                                              11

20  (2 sixes plus 0 ones)                                           12

21  (2 sixes plus 1 one)                                             13

22                                                                              14

23                                                                              15

Final answer:

The counting numbers in base 6 are represented using the digits 0 to 5, where each digit position represents a power of six. The sequence starts at 0, followed by 1, 2, 3, 4, 5, and then continues with 10 (which is 6 in decimal), 11 (7 in decimal), etc.

Explanation:

The counting numbers in base 6, also known as base-6 or hexadecimal numbers, consist of the digits 0, 1, 2, 3, 4, and 5. Just like in the decimal system (base 10) where the digits go from 0 to 9, in base 6 we only use the digits 0 to 5 for each place value, and each place is six times greater than the place to its right. After reaching 5, the next number in the sequence would be represented as 10 (base 6), which is equal to 6 in base 10. The sequence continues with 11 (base 6 equals 7 in base 10), 12 (base 6 equals 8 in base 10), and so on.

The concept of base systems is an important aspect of number theory in mathematics. In everyday life, we use the base 10 numbering system, mainly because humans have ten fingers. However, in computing and other scientific fields, different base systems like base 2 (binary) or base 16 (hexadecimal) are often used.

Which if the following is the smallest value 0.79, 2.40, 3.00007, 0.424, or 100?

Answers

0.424 is the smallest value 
hope this helps

Hi there!


The smallest value is 0.424

-----------------------------------------------------------------------------

You might think that 0.79 is the smallest one but it also has 0 which is not written. 0.790 is bigger than 0.424


I hope that helps!

In a circle of radius 25 inches, a central angle of 35 degrees will intersect the circle forming an arc of length ____

Answers

arc length = (central angle/360) x 2 x PI x r

= (35/360) x 2 x 3.14 x 25

=15.2638

round answer as needed, you don't say how to round it.

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