Consider the quadratic equation x2 = 4x - 5. How many solutions does the equation have?

Answer:

D. c+14≤24

Step-by-step explanation:

A. c+14<24 is c<10 (subtract 14)

B. c+18≥24 is c≥6 (subtract 18)

C. c+18>24 is c>6 (subtract 18)

D. c+14≤24 is c≤10 (subtract 14)

The set is {5, 6, 8, 9, 10}, so it should include each one of those numbers. C and A don't include 6 and 10 respectively, so they can't be the answer. B contains all numbers 6 and above, which doesn't include 5. The remaining letter is D, so that's the final answer.

Answer:

2000*24%=680\

Step-by-step explanation:

Answer:

27 dollars

Step-by-step explanation:

On one side he had 175

One the other side he has 6 books and 13 dollars

175 = 6b+13

Subtract 13 from each side

175 -13 = 6b+13-13

162 = 6b

Divide each side by 6

162/6 = 6b/6

27 = b

Each book is 27 dollars

Answer:

888

Step-by-step explanation:

Im pretty sure this is the answer, if helpful please mark me as brainiest :>

Answer:

(1) 240-8Q=0240−8Q=0  (2) 225 (3) it is very necessary that the direct elasticity of demand for a product at a price from several buyers be different significantly;  so that customers are easily known, that further goods resale by buyers is not possible

Step-by-step explanation:

Solution

Given that:

(1) TR=∫MR=250Q−4Q  

Pr=TR-TC=250Q-4Q² - 10Q=240Q−4Q²  

Thus,

Pr   =240−8Q

240-8Q=0240−8Q=0

(2) Q=30

Now,

p=250-4 * 30=130

p=100

so.

100=250−4Q

Q=37.5

Pr=240×37.5−4×37.5²

=3375

Hence,

ΔPr=3600−3375=225

(3) For the execution of price discrimination by a monopolist, it is very important that the direct elasticity of demand for a product at a price from different buyers be remarkably different; so that  customers are easily known, that further goods resale by buyers is not done.

Answer:

There is a 11/14 chance that the result is a multiple of 3 or a multiple of 2.

Step-by-step explanation:

Since the spinner is from 1 to 14, find all of the multiples of 3 and multiples of 2.

There are 4/14 multiples of 3 and 7/14 multiples of 2.

Add both of these numbers together 4/14 + 7/14 = 11/14

If this answer is correct, please make me Brainliest!

The probability of landing on a multiple of 2 or 3 when spinning a spinner numbered 1 through 14 is 4/7.

The student asked about the probability of getting a multiple of 3 or a multiple of 2 when spinning a spinner numbered 1 through 14. To determine this, we first list the multiples of 3 and 2 within the range of numbers on the spinner.

Multiples of 3: 3, 6, 9, 12
Multiples of 2: 2, 4, 6, 8, 10, 12, 14
Note that 6 and 12 are multiples of both 2 and 3, so we should not count them twice.

The total number of distinct multiples of 2 or 3 is 3 (multiples of 3) + 7 (multiples of 2) - 2 (common multiples) = 8 unique numbers. Since there are 14 possible outcomes on the spinner, the probability of landing on a multiple of 3 or 2 is 8 (favorable outcomes) divided by 14 (total possible outcomes).

The probability calculation is: 8/14, which simplifies to 4/7.

Answer:

(3) 82%

Step-by-step explanation:

.62/.76=.8157894737 which when rounded is 82%.

If 76 percent of freshmen take Statistics, the percentage of freshmen who take English is 82 percent. Option B is correct.

The quantity of anything is stated as though it were a fraction of a hundred. A fraction of 100 can be used to express the ratio.

The percent of freshmen taking Statistics are taking English if 76% of freshmen are taking Statistics is found as;

The percent of freshmen taking Statistics are taking English if 76% of freshmen are taking Statistics is found as;

[tex]\rm \% S=\frac{.62}{.76} \times 100 \\\\ \% S=82\%[/tex][tex]% STATICS = \frac{.62}{.76} \times 100 \\\\ % STATICS = 81.5 \%[/tex]

Sixty-two percent of all freshmen at a nearby community college take both Statistics and English. If 76 percent of freshmen take Statistics,

Hence, the percentage of freshmen who take English is 82 percent.

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The predicted percentage of games won for a team with these statistics is approximately 60.025%.

To address the given questions, we'll use the provided estimated regression equation:

[tex]\[ \hat{y} = 60.5 + 0.319x_1 - 0.241x_2 \][/tex]

where:

- [tex]\( \hat{y} \)[/tex] is the predicted percentage of games won,

- [tex]\( x_1 \)[/tex] is the average number of passing yards obtained per game on offense,

- [tex]\( x_2 \)[/tex] is the average number of yards given up per game on defense.

a. To predict the percentage of games won for a team that averages 225 passing yards per game on offense [tex](\( x_1 = 225 \))[/tex] and gives up an average of 300 yards per game on defense [tex](\( x_2 = 300 \))[/tex], we'll substitute these values into the regression equation:

[tex]\[ \hat{y} = 60.5 + 0.319(225) - 0.241(300) \][/tex]

[tex]\[ \hat{y} = 60.5 + 71.775 - 72.3 \][/tex]

[tex]\[ \hat{y} = 60.5 - 0.525 \][/tex]

[tex]\[ \hat{y} = 60.025 \][/tex]

Therefore, the predicted percentage of games won for a team with these statistics is approximately 60.025%.

Complete question:

In exercise 24, an estimated regression equation was developed relating the percentage of games won by a team in the National Football League for the 2011 season (y) given the average number of passing yards obtained per game on offense (x1) and the average number of yards given up per game on defense (x2). The estimated regression equation was y = 60.5 + 0.319x1 - 0.241x2.

Predict the percentage of games won for a particular team that averages 225 passing yards per game on offense and gives up an average of 300 yards per game on defense.

Answer:

See Explanation

Step-by-step explanation:

To determine the number of prime cards needed to build a composite number, we simply express the number as a product of its prime factors.

These are:

4=2X2

6=2X3

8=2X2X2

9=3X3

10=2X5

12=2X2X3

14=2X7

15=3X5

16=2X2X2X2

18=2X3X3

20=2X2X5

21=3X7

22=2X11

24=2X2X2X3

26=2X13

27=3X3X3

28=2X2X7

30=2X3X5

32=2X2X2X2X2

33=3X11

34=2X17

35=5X7

36=2X2X3X3

38=2X19

39=3X13

40=2X2X2X5

42=2X3X7

44=2X2X11

45=3X3X5

46=2X2X13

48=2X2X2X2X3

49=7X7

50=2X5X5

Therefore for each of the numbers, those are the prime number cards to be used.

Answer: B

Step-by-step explanation:

Firstly, we identify the number of people that can use the slide per minute, which is 6. Using this, we find that for 1 minute it's 6 people, for 2 minutes it's 12 people and for 4 minutes it's 24 people.

The question provides us that 18 people can go down the water slide in 3 minutes. This suggests that every minute, 18 ÷ 3 = 6 people can go down the slide. So, for the double number line, we would show:

This 'per minute' basis helps in understanding and calculating the number of people going down the slide at different time intervals.

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Answer:

x intercept (3/7, 0) or (0.429, 0)

y intercept (0, -3)

Step-by-step explanation:

Answer:

C. The divergence of F is StartFraction 1 Over StartAbsoluteValue Bold r EndAbsoluteValue squared EndFraction

∇•F = 1/|r|²

Step-by-step explanation:

The position vector r = (x, y, z)

r = xi+yj+zk

|r| = √x²+y²+z²

|r|² = x²+y²+z²

Given the radial field F = r/|r|²

Divergence of the radial field is expressed as:

∇•F = {δ/δx i+ δ/δy j + δ/δy k} • {(r/|r|²)

∇•F = {δ/δx i+ δ/δy j + δ/δy k} • {xi/|r|² + yj/|r|² + zk/|r|²}

∇•F = δ/δx(x/|r|²) + δ/δy(y/|r|²)+δ/δz(z/|r|²)

Check the attachment for the complete solution.

revenge! hope that helps! thank you for my points back!

Answer:

Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 1,100 square feet

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 1,100 square feet

Step-by-step explanation:

We are given that the mean area of several thousand apartments in a new development is advertised to be 1,100 square feet.

A consumer advocate has received numerous complaints that the apartments are smaller than advertised.

Let [tex]\mu[/tex] = mean area of several apartments.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 1,100 square feet

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 1,100 square feet

Here, null hypothesis states that the mean area of apartments are same as advertised.

On the other hand, alternate hypothesis states that the mean area of apartments are smaller than advertised.

So, this would be the appropriate null and the alternative hypothesis to test this claim.

Answer:

Similie

Step-by-step explanation:

A similie is a comparison using like or as

An idiom however is a group of words established by usage as having a meaning not deducible from those of the individual words

reading this statement, its saying "Her eyes shone as bright as the sun"

the caparison is between her eyes and the bright sun

therefore making this a similie

Hope this helps

stay safe:))))

brainliest is appreciated :))

Based on the information given, the expression is a simile.

In this case, "Her eyes shone as bright as the sun" is an example of a simile. The eyes were compared to the sun.

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The formula is (4*pi/3)*r^3, so 256*pi/3 cubic units = 268.08  cubic units. {whatever units r is in}

Answer:

(256/3)pi

Step-by-step explanation:

(4/3)(pi)(r^3) =

(4/3)(pi)(4^3) =

(4/3)(pi)(64) =

(256/3)pi

Answer:

for AAS triangles or SSA

Step-by-step explanation:

Answer:

ny triangle whose two sides and 1 angle is known or 2 angles are known and 1 side is known

Step-by-step explanation:

Answer:

  -3

Step-by-step explanation:

Put 4 where x is, and do the arithmetic.

  (4^2 -4)/(4 -8) = (16 -4)/(-4) = 12/-4 = -3

The value of the expression is -3 for x=4.

Answer:

Step-by-step explanation:

The nth term of a geometric sequence is expressed as Tn = [tex]ar^{n-1}[/tex] where;

a is the first term

r is the common ratio

n is the number of terms

Since we are to insert three geometric means between 2 and 81/8, the total number of terms in the sequence will be 5 terms as shown;

2, a, b, c, 81/8

a, b, and c are the 3 geometric mean to be inserted

T1 = [tex]ar^{1-1}[/tex] = 2

T1 = a = 2....(1)

T5= [tex]ar^{5-1}[/tex]

T5 = [tex]ar^{4}[/tex] = 81/8... (2)

Dividing equation 1 by 2 we have;

[tex]\frac{ar^{4} }{a}= \frac{\frac{81}{8} }{2}[/tex]

[tex]r^{4} = \frac{81}{16}\\\\r = \sqrt[4]{\frac{81}{16} } \\r = 3/2[/tex]

Given a =2 and r = 3/2;

[tex]T2=ar\\T2 = 2*3/2\\T2 = 3\\\\T3 = ar^{2} \\T3 = 2*\frac{3}{2} ^{2} \\T3 = 2*9/4\\T3 = 9/2\\\\T4 = ar^{3}\\T4 = 2*\frac{3}{2} ^{3} \\T4 = 2*27/8\\T4 = 27/4\\[/tex]

Therefore the three geometric means are 3, 9/2 and 27/4

In a geometric sequence where three terms lie between 2 and 81/8, the three geometric terms are:

[tex]\mathbf{T_2 =3 }[/tex]

[tex]\mathbf{T_3 =\frac{9}{2} }[/tex]

[tex]\mathbf{T_4 =\frac{27}{4} }[/tex]

Recall:

Given a geometric sequence, 2 . . . 81/8, with three other terms in the middle, first, find the value of r.

Thus:

First Term:

Fifth Term:

[tex]T_5 = ar^{n - 1}[/tex]

a = 2

n = 5

r = ?

T5 = 81/8

[tex]\frac{81}{8} = 2r^{5 - 1}\\\\\frac{81}{8} = 2r^4\\\\[/tex]

[tex]\frac{81}{8} \times 8 = 2r^4 \times 8\\\\81 = 16r^4\\\\[/tex]

[tex]\frac{81}{16} = \frac{16r^4}{16} \\\\\frac{81}{16} = r^4\\\\[/tex]

[tex]\sqrt[4]{\frac{81}{16}} = r\\\\\frac{3}{2} = r\\\\\mathbf{r = \frac{3}{2}}[/tex]

Find the three geometric means [tex]T_2, T_3, $ and $ T_4[/tex] between 2 and 81/8.

[tex]\mathbf{T_n = ar^{n - 1}}[/tex]

a = 2

r = 3/2

[tex]T_2 = 2 \times (\frac{3}{2}) ^{2 - 1}\\\\T_2 = 2 \times (\frac{3}{2}) ^{1}\\\\\mathbf{T_2 = 3}[/tex]

[tex]T_3 = 2 \times \frac{3}{2} ^{3 - 1}\\\\T_3 = 2 \times (\frac{3}{2}) ^{2}\\\\T_3 = 2 \times \frac{9}{4}\\\\\mathbf{T_3 =\frac{9}{2} }[/tex]

[tex]T_4 = 2 \times \frac{3}{2} ^{4 - 1}\\\\T_4 = 2 \times (\frac{3}{2}) ^{3}\\\\T_4 = 2 \times \frac{27}{8}\\\\\mathbf{T_4 =\frac{27}{4} }[/tex]

Therefore, in a geometric sequence where three terms lie between 2 and 81/8, the three geometric terms are:

[tex]\mathbf{T_2 =3 }[/tex]

[tex]\mathbf{T_3 =\frac{9}{2} }[/tex]

[tex]\mathbf{T_4 =\frac{27}{4} }[/tex]

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Answer:

[tex]z=\frac{0.565 -0.58}{\sqrt{\frac{0.58(1-0.58)}{600}}}=-0.744[/tex]  

Since is a bilateral test the p value would be given by:  

[tex]p_v =2*P(z<-0.744)=0.4569[/tex]  

And since the p value is higher than the significance level we have enough evidence to conclude that the true proportion is not significantly different from 0.58

Step-by-step explanation:

Information given

n=600 represent the random sample selcted

X=339 represent the number of females aged 15 and older that living alone

[tex]\hat p=\frac{339}{600}=0.565[/tex] estimated proportion of females aged 15 and older that living alone

[tex]p_o=0.58[/tex] is the value that we want to check

[tex]\alpha=0.01[/tex] represent the significance level

z would represent the statistic

[tex]p_[/tex] represent the p value

Sytem of hypothesis

We want to check if the true proportion females aged 15 and older that living alone is significantly different from 0.58.:  

Null hypothesis:[tex]p=0.58[/tex]  

Alternative hypothesis:[tex]p \neq 0.58[/tex]  

The statistic is given by:

[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)  

Replacing the info given we got:

[tex]z=\frac{0.565 -0.58}{\sqrt{\frac{0.58(1-0.58)}{600}}}=-0.744[/tex]  

Since is a bilateral test the p value would be given by:  

[tex]p_v =2*P(z<-0.744)=0.4569[/tex]  

And since the p value is higher than the significance level we have enough evidence to conclude that the true proportion is not significantly different from 0.58

Answer:

Dale says the ratios 3:5 and 2:10 are equivalent.

He is wrong.

Let's compare the two ratios by converting them into the new forms which have the same denominator.

3/5 = 6/10

2/10 = 2/10

6/10 > 2/10 => 3/5 > 2/10

Hope this helps!

:)

Answer:

V≈14,137.17m³ or 4500π

Step-by-step explanation:

Formula: V=(1 /6)πd³

V=(1/6)π(30³)= 14137.16694115406957308189522475776297888726229718797619438.....

Answer:

14137.17 meters cubed

Step-by-step explanation:

volume = 14137.17 meters cubed

Answer:

  1353 ft

Step-by-step explanation:

The cliff height and the distance from its base to the boat form the legs of a right triangle. The cliff height is the leg opposite the elevation angle, and the distance to the boat is the leg adjacent. Given these two legs of the triangle, the tangent relation seems useful:

  Tan = Opposite/Adjacent

We want to find the cliff height (opposite), so we can multiply this equation by Adjacent:

  Opposite = Adjacent×Tan

  cliff height = (2994 ft)(tan(24°19')) ≈ 1353 ft

The cliff is about 1353 feet high.

Clarissa's grade-point average for the semester is 1.

We have,

To calculate Clarissa's grade point average (GPA) for the semester, we need to assign points to each grade and calculate the weighted average.

Given the grade scale: A = 4 points, B = 3 points, C = 2 points, D = 1 point, and F = 0 points.

Clarissa earned the following grades:

Linear Algebra (4 hours): Upper D (D) = 1 point

Sociology (5 hours): Upper D (D) = 1 point

Engineering (2 hours): Upper D (D) = 1 point

Philosophy (3 hours): Upper D (D) = 1 point

To calculate the weighted average, we need to multiply each grade by the number of credit hours for the course and sum them up.

Then, we divide the total by the sum of the credit hours.

Total points = (1 * 4) + (1 * 5) + (1 * 2) + (1 * 3) = 4 + 5 + 2 + 3 = 14

Total credit hours = 4 + 5 + 2 + 3 = 14

GPA = Total points / Total credit hours = 14 / 14 = 1

Therefore,

Clarissa's grade-point average for the semester is 1.

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Answer:15/13

Step-by-step explanation:

Answer:

do you know what x or dx =

Step-by-step explanation:

Answer:

The correct answer to the following question will be "0.0367".

Step-by-step explanation:

The given values are:

[tex]p1=p2=0.06[/tex]

[tex]q1=q2=1-p1=0.94[/tex]

[tex]n1=n2=400[/tex]

As we know,

[tex]E(p1-p2)=p1-p2=0\\[/tex]

[tex]SE(p1-p2)=\sqrt{\frac{p1q1}{n1}+\frac{p2q2}{n2}}[/tex]

On putting the given values in the above expression, we get

                   [tex]= \sqrt{p1q1(\frac{1}{400}+\frac{1}{400})}[/tex]

                   [tex]=0.0168[/tex]

Now, consider

[tex]P(p1-p2>0.03)=P[\frac{(p1-p2)-E(p1-p2)}{SE(p1-p2)}>\frac{0.03-0}{0.0168}][/tex]

                            [tex]=P(Z>1.7857)[/tex]

                            [tex]=P(Z>1-79)[/tex]

                            [tex]=0.036727[/tex]

Therefore, "0.0367" is the right answer.

Calculating the probability of the difference between two sample proportions being more than 0.03 involves executing a hypothesis test via a z-test due to our large sample size. We formulate and employ a formula to get the z-score and then determine the associated p-value using a statistical tool.

This question falls within the area of statistics, particularly dealing with hypothesis testing and comparison of two independent population proportions. Given that 0.06 of each population possess a certain characteristic and samples of size 400 are drawn from each, we are required to calculate the probability that the difference between the sample proportions exceeds 0.03.

First, we establish the null hypothesis (H0) and alternative hypothesis (Ha) for the test. H0: P1 = P2 and Ha: P1 ≠ P2. Here, P1 and P2 represent the populations respectively. Given a sufficiently large sample size (n > 30), we use a z-test for comparing the proportions.

In computing the z-score, we use the following formula: z = (P1 - P2) / √ ((P*(1 - P*) / n1) + (P*(1 - P*) / n2)). Here, P* = (x1 + x2) / (n1 + n2), where x is the number of successes in each sample (0.06*400 = 24 per population logistically).

The p-value associated with the calculated z-score, which represents the probability that the difference between the first sample proportion and the second sample proportion being more than 0.03, can be found using a statistical calculator or statistical software. The precise numerical value for p will depend on the computed z-score.

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